hich of the following is not needed to compute a t statistic? hint: why did we need to switch from a ztest to a t-test? a. a hypothesized value for the population mean b. the value of the population variance or standard deviation c. the value of the sample mean d. the value of the sample variance or standard deviation

About the circle relation C on the set of real numbers:

To determine if circle (C) is reflexive, we need to examine if for every real number x, x C x holds true. By definition of C, this means that for every real number x, x^2 + x^2 = 1.

Now, let's simplify this equation: x^2 + x^2 = 2x^2, so we get 2x^2 = 1. To satisfy this equation, x^2 must equal 1/2. However, there is no real number x for which x^2 = 1/2.

As we cannot find an example of x such that (x, x^2 + x^2) = (x, 1), we conclude that since this does not equal 1, C is not reflexive.

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To find the acceleration when the velocity equals zero, we need to differentiate the velocity function with respect to time, t.

For the first piece of the velocity function where st<2, the derivative of mt is simply m since t is not a variable in this expression. For the second piece of the velocity function where t>2, we need to use the chain rule to differentiate the natural logarithmic function. The derivative of ln(t-1) with respect to t is 1/(t-1).
Therefore, the derivative of v(t) with respect to t is:
a(t) = m - 2St for st<2
a(t) = 1/(t-1) for t>2
To find the acceleration when the velocity equals zero, we need to set v(t) equal to zero and solve for t.
For the first piece of the velocity function where st<2, we have:
0 = mt - St2 - 4
St2 = mt - 4
t = sqrt((m-4)/S)

For the second piece of the velocity function where t>2, we have:
0 = 14 ln(t-1)
t = e+ 1
Now, we can substitute these values of t into the acceleration function to find the acceleration when the velocity equals zero:
For the first piece of the velocity function where st<2, we have:
a(sqrt((m-4)/S)) = m - 2S(sqrt((m-4)/S))
For the second piece of the velocity function where t>2, we have:
a(e+1) = 1/(e-1)

Therefore, the acceleration when the velocity equals zero depends on the values of m, S, and e.
To find the acceleration for the piecewise defined velocity function when the velocity equals zero, we first need to identify when v(t) = 0 within the given function. The function is defined as follows:
v(t) = { mt - St^2 - 4, for 0 ≤ t < 2
        14 ln(t - 1), for t > 2
1. For the first part of the function (0 ≤ t < 2), set v(t) = 0 and solve for t:
  mt - St^2 - 4 = 0
2. For the second par of the function (t > 2), set v(t) = 0 and solve for t:
  14 ln(t - 1) = 0
After finding the values of t when the velocity is zero, you can then calculate the acceleration for each case. Acceleration is the derivative of the velocity function with respect to time (a(t) = dv(t)/dt). Compute the derivatives for both parts of the piecewise function and evaluate them at the values of t where the velocity is zero.

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To find the equation of the curve whose tangent line has a slope of f'(x) = 2x^(-8/9) and given that the point (-1, -6) is on the curve, follow these steps: Integrate the derivative to find the original function: f(x) = ∫(2x^(-8/9))dx.Apply the power rule for integration: f(x) = (2/(1 - (-8/9)))x^(1 - (-8/9)) + C = (2/(17/9))x^(17/9) + C = (18/17)x^(17/9) + C.

Use the given point (-1, -6) to find the value of C: -6 = (18/17)(-1)^(17/9) + C. Solve for C: C = -6 - (18/17)(-1) = -6 + (18/17) = (-104 + 18)/17 = -86/17.Write the equation of the curve with the value of C: f(x) = (18/17)x^(17/9) - 86/17. We know that the slope of the tangent line at any point on the curve is equal to the value of the derivative of the curve at that point. So, we can use the given derivative to find the equation of the curve.f'(x) = 2x^(-8/9).Integrating both sides with respect to x, we get:f(x) = ∫2x^(-8/9) dxf(x) = -9x^(1/9) + C (where C is the constant of integration)Now, we can use the given point (-1,-6) to find the value of C:f(-1) = -9(-1)^(1/9) + C = -6C = -6 + 9(1)^(1/9) = -6 + 9 = 3Therefore, the equation of the curve is:f(x) = -9x^(1/9) + 3.

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Answer:

375 females

Step-by-step explanation:

150/200 = 75%

375/500 = 75%

The probability of 2 people out of 10 chosen at random favoring the new building project: P(X = k) = (n choose k) * p^k * (1 - p)^(n - k), where n = 10, p = 0.7, and k = 2. The resulting probability is approximately 0.00005349 or 0.005%.

To solve this problem, we need to use the binomial distribution formula: P(X = k) = (n choose k) * p^k * (1 - p)^(n - k)

where P(X = k) is the probability of getting exactly k successes (people who favor the new building project),

n is the total number of trials (people chosen at random),

p is the probability of success in each trial (proportion of people in favor of the project), and

(n choose k) is the binomial coefficient, which represents the number of ways to choose k items from a set of n items.

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Answer:

[tex]\large\boxed{\textsf{See Below.}}[/tex]

Step-by-step explanation:

[tex]\textsf{We are asked to solve for the values of x, given values to select from.}[/tex]

[tex]\textsf{Instead of using the FOIL Method, we can simply substitute in the given options}[/tex]

[tex]\textsf{then identify if the two expressions are actually equal to each other. This is}[/tex]

[tex]\textsf{the \underline{Substitution Property of Equality}.}[/tex]

[tex]\large\underline{\textsf{What is the Substitution Property of Equality?}}[/tex]

[tex]\textsf{The Substitution Property of Equality is a property that allows us to substitute in}[/tex]

[tex]\textsf{a known value for a placeholder, or an unknown variables and the equation will}[/tex]

[tex]\textsf{still remain equal. However for our problem we are given the value of x, but we're}[/tex]

[tex]\textsf{not certain that the value will make the equation true. That's why we should}[/tex]

[tex]\textsf{check every option provided.}[/tex]

[tex]\large\underline{\textsf{Use the Substitution Property of Equality;}}[/tex]

[tex]\textsf{Our first option given is -46. Substitute that value in for x.}[/tex]

[tex]\tt (-46 - 3)^{2} = 49[/tex]

[tex]\textsf{Follow Order of Operations (PEMDAS), and simplify inside the parentheses first.}[/tex]

[tex]\tt (-46 -3)^{2}=(-49)^{2}=(-49 \times -49)=2401.[/tex]

[tex]\tt 2401 \neq 49.[/tex]

[tex]\textsf{-46 is not a value of x.}[/tex]

---------------------------------------------------

[tex]\textsf{Our second option given is -4. Substitute that value in for x.}[/tex]

[tex]\tt (-4 - 3)^{2} = 49[/tex]

[tex]\textsf{Follow Order of Operations (PEMDAS), and simplify inside the parentheses first.}[/tex]

[tex]\tt (-4 -3)^{2}=(-7)^{2}=(-7 \times -7)=49.[/tex]

[tex]\tt 49 = 49. \large\checkmark[/tex]

[tex]\large\boxed{\textsf{-46 is a value of x.}}[/tex]

---------------------------------------------------

[tex]\textsf{Our third option given is 10. Substitute that value in for x.}[/tex]

[tex]\tt (10 - 3)^{2} = 49[/tex]

[tex]\textsf{Follow Order of Operations (PEMDAS), and simplify inside the parentheses first.}[/tex]

[tex]\tt (10 -3)^{2}=(7)^{2}=(7 \times 7)=49.[/tex]

[tex]\tt 49 = 49. \large\checkmark[/tex]

[tex]\large\boxed{\textsf{10 is a value of x.}}[/tex]

---------------------------------------------------

[tex]\textsf{Our last option given is 52. Substitute that value in for x.}[/tex]

[tex]\tt (52 - 3)^{2} = 49[/tex]

[tex]\textsf{Follow Order of Operations (PEMDAS), and simplify inside the parentheses first.}[/tex]

[tex]\tt (52 -3)^{2}=(49)^{2}=(49 \times 49)=2401.[/tex]

[tex]\tt 2401 \neq 49.[/tex]

[tex]\textsf{52 is not a value of x.}[/tex]

There is a 2/3 or 0.67 probability of rolling a divisor of 80 on a 6-sided die.

To find the probability of rolling a number on a 6-sided die that is a divisor of 80, follow these steps:
List the divisors of 80: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80.

Identify which of these divisors can appear on a 6-sided die: 1, 2, 4, 5
Count the number of valid divisors: 4
Count the total number of sides on the die: 6

Calculate the probability:

P(divisor of 80) = (number of valid divisors) / (total number of sides)
So, the probability of rolling a divisor of 80 on a 6-sided die is:
P(divisor of 80) = 4/6 = 2/3 ≈ 0.67.

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According to given information, the value of cos θ is (3sqrt(5))/7.

What is cos?

In trigonometry, cos (short for cosine) is a mathematical function that relates the angle of a right triangle to the ratio of the length of its adjacent side to its hypotenuse.

We can start by using the Pythagorean identity:

[tex]sin^2[/tex] θ + [tex]cos^2[/tex] θ = 1

Since we know sin θ, we can solve for cos θ:

[tex]cos^2[/tex] θ = 1 - [tex]sin^2[/tex] θ

[tex]cos^2[/tex] θ = 1 - [tex](2/7)^2[/tex]

[tex]cos^2[/tex] θ = 1 - 4/49

[tex]cos^2[/tex] θ = 45/49

Taking the square root of both sides, we get:

cos θ = ±[tex]\sqrt{(45/49)[/tex]

Since we know that tan θ is positive, we can deduce that cos θ must be positive as well. Therefore:

cos θ = [tex]\sqrt{(45/49)[/tex] = [tex](3\sqrt{(5)})/7[/tex]

So the value of cos θ is (3sqrt(5))/7.

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To determine the equations of the lines tangent to the curve at x = 0, we need to follow these steps:

Step 1: Find the slope of the tangent line at x = 0.

To find the slope of the tangent line at x = 0, we need to take the derivative of the curve with respect to x and evaluate it at x = 0. Let's first rewrite the given equation of the curve in standard form:

9[tex]x^2[/tex]- 18x + 4[tex]y^2[/tex]+ 16y = 11

Now, we can take the derivative of both sides of the equation with respect to x:

18x - 18 + 8y(dy/dx) + 16(dy/dx) = 0

Simplifying, we get:

(24dy/dx) = 18 - 18x

Now, we can evaluate this equation at x = 0 to find the slope of the tangent line at x = 0:

(24dy/dx)|_(x=0) = 18

So, the slope of the tangent line at x = 0 is 18/24 or 3/4.

Step 2: Write the equation of the tangent line.

Using the point-slope form of a linear equation, we can write the equation of the tangent line at x = 0:

y - y1 = m(x - x1)

where m is the slope of the tangent line at x = 0, and (x1, y1) is a point on the curve where the tangent line touches.

Plugging in the values, we get:

y - y1 = (3/4)(x - 0)

Simplifying, we get:

y - y1 = 3x/4

This is the equation of one of the tangent lines to the curve at x = 0.

Step 3: Find the point of intersection.

To find the point of intersection of the two tangent lines, we need to find the value of y1, which is the y-coordinate of the point on the curve where the tangent line touches.

Plugging in x = 0 into the original equation of the curve:

9[tex](0)^2[/tex] - 18(0) + 4[tex]y^2[/tex] + 16y = 11

Simplifying, we get:

4[tex]y^2[/tex] + 16y - 11 = 0

We can solve this quadratic equation to find the values of y1. Once we have the values of y1, we can plug them into the equation of the tangent line to find the corresponding x-coordinates and determine the point of intersection of the two tangent lines.

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The demand function for good y is y* = -(p2/p1) * (x*/2)

To find the demand for good y, we can set the MRS (marginal rate of substitution) from part 1 equal to the price ratio at an interior optimal bundle.

Let's call the optimal bundle (x*, y*) and the prices of goods x and y as px and py, respectively. Then the condition for optimal consumption is given by:

MRS = -px / py = p1 / p2 (assuming a two-good model)

where p1 and p2 are the prices of goods x and y, respectively, and px/py is the price ratio.

Solving this equation for y, we get:

y* = -(p2/p1) * (x*/2)

This gives us the demand function for good y in terms of its price (p2) and the price of good x (p1) and the optimal quantity of good x (x*).

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If 3n + 2 is an odd integer, then n must be odd.

The proof starts by assuming that n is even, which means it can be expressed as 2k for some integer k.

Substituting this value in the expression 3n + 2, we get:

3n + 2 = 3(2k) + 2 = 6k + 2

Simplifying further, we can factor out 2 from the expression:

3n + 2 = 2(3k + 1)

Since 3k + 1 is an integer, we can see that 3n + 2 is even, which contradicts our original assumption that it is odd. Therefore, our initial assumption that n is even is false, and we conclude that n must be odd.

This proof follows the method of proof by contradiction, where we assume the opposite of what we want to prove and show that it leads to a contradiction, hence proving the original statement.

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The percentage of ball that hit into the outfield would be represented by the equation = 15/8 = X/100. That is A.

The total number of balls that that where present at the battling practice by Alexis = 15.

The number of balls that hit into the outfield = 8

The number of balls that hit outside the outfield = 15-8= 7

The percentage (x) of the balls that are outside the outfield;

X = 8/15 × 100/1

x ×15 = 8 × 100

15/8 = X/100.

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The equation of the line with a slope of 3/4 passing through the point (2,1) is y = (3/4)x - 1/2.

In mathematics, slope refers to the measure of steepness or incline of a line, usually denoted by the letter m.It is the ratio of the vertical change in position of two points on a line to their horizontal change.

The equation of a line with a slope of 3/4 passing through the point (2,1) can be found using the point-slope form of the equation of a line:

y - y₁ = m(x - x₁)

where m is the slope of the line, and (x₁,y₁) are the coordinates of the given point on the line.

Substituting the given values, we get:

y - 1 = (3/4)(x - 2)

Multiplying both sides by 4 to eliminate the fraction, we get:

4y - 4 = 3(x - 2)

Expanding the right-hand side, we get:

4y - 4 = 3x - 6

Adding 4 to both sides, we get:

4y = 3x - 2

Dividing both sides by 4, we get the final equation in slope-intercept form:

y = (3/4)x - 1/2

Therefore, the equation of the line with a slope of 3/4 passing through the point (2,1) is y = (3/4)x - 1/2.

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The relative minimum is at (0, 0) and the relative maximum is at (1/ln2, -1/ln2).

To find the relative extrema of the function, we first find the first and second derivatives:

y' = 2x log2 x + x(1/ln2)

y'' = 2 log2 x + 2/ln2

To find the critical points, we set y' equal to zero and solve for x:

2x log2 x + x(1/ln2) = 0

x log2 x + x/ln2 = 0

x(log2 x + 1/ln2) = 0

x = 0 or x = 1/ln2

Next, we use the second derivative test to classify the critical points:

For x = 0, y'' = 2/ln2 > 0, so the function has a relative minimum at (0, 0).

For x = 1/ln2, y'' = 2 log2 (1/ln2) + 2/ln2 < 0, so the function has a relative maximum at (1/ln2, -1/ln2).

Therefore, the relative minimum is at (0, 0) and the relative maximum is at (1/ln2, -1/ln2).

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since it has a diameter of 9, that means its radius is half that, or 4.5.

[tex]\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=4.5\\ h=7 \end{cases}\implies V=\cfrac{\pi (4.5)^2(7)}{3}\implies V=47.25\pi[/tex]

Answer:

Step-by-step explanation:

r= the radius of base

h=height

volume of cone=1/3*r^2*pi*h

1/3*(4.5)^2*pi*7

=1/3*81/4*7*pi

=567/12 pi

To determine which sets are bases for R3, we need to check if they are linearly independent and if they span R3. The set {0, 2 038 0; 0, 0, 5; -77, 17, 37; -37, 27, 17} is a basis for R3.

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We can find the compositions f o g, g o g, and f o g by plugging the function expressions into each other and simplifying.

f o g(n) = f(g(n)) = f(3n - 1) = 2(3n - 1) + 1 = 6n - 1

g o g(n) = g(g(n)) = g(3n - 1) = 3(3n - 1) - 1 = 8n - 4

f o g(n) = f(g(n)) = f(3n - 1) = 2(3n - 1) + 1 = 6n - 1

g o f(n) = g(f(n)) = g(2n + 1) = 3(2n + 1) - 1 = 6n + 2

Therefore, the compositions are:

f o g(n) = 6n - 1

g o g(n) = 8n - 4

f o g(n) = 6n - 1

g o f(n) = 6n + 2

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An arithmetic sequence is a sequence of numbers in which each term after the first is obtained by adding a fixed number to the previous term

The first term of an arithmetic sequence is denoted by 'a₁', the second term by 'a₂', and so on.

Given that;

Un = a + (n - 1)d

U50 = 4 + (50 - 1) 2

U50 = 102

Then;

Un = ar^n-1

U10 = 1000(1/2)^9

U10 = 1.95

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Length of arc(DAB) is 83.98.

A quadrilateral is a four-sided polygon, which is a two-dimensional geometric figure with four straight sides and four angles. Quadrilaterals are classified based on their properties and characteristics, such as the length of their sides, the size of their angles, and the presence of parallel sides or right angles. Some common types of quadrilaterals include squares, rectangles, rhombuses, trapezoids, and parallelograms.

In the given circle;

∠DAB=97°

Radius of circle=29

We know, sum of opposite angle of quadrilateral inscribed in the circle is 180°

∠DAB+∠DCB=180°

∠DCB=180°-97°

∠DCB=83°

∠DPB=2×∠DCB

∠DPB=2×83

=166°

Length of arc(DAB)=∠DPB/360°×2πr

=166/360×2×π×29

=83.98.

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A researcher will pose all of these related to sampling. So, the correct answer is all of the questions

The first question is related to the applicability of the findings of study which are typically beyond the data sources that are selected for study

The second question is related to the fact that sample of participants selected for the study reflects the diversity of the actual population to which extent

The third question relates to identifying the individuals which will be available for the study and it will consider different factors such as their experiences

The fourth question is not that much relevant as it as related with depth and the precision of the findings of the study

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The reason for including control variables in multiple regressions is to c. make the variables of interest no longer correlated with the error term.

In multiple regressions, control variables are used to ensure that, after holding the control factors constant, the variables of interest are no longer linked with the error term. This makes it easier to separate the effects of the interesting factors on the result variable. The effects of additional factors that could be connected to both outcome variables and variables of interest can be mitigated by including control variables in multiple regression.

When two or more predictor variables in multiple regression are closely associated, imperfect multicollinearity can be reduced by including control variables. However, including control variables is not primarily done to reduce imperfect multicollinearity.

Complete Question:

The reason for including control variables in multiple regressions is to: a. increase the regression r-squared.

b. reduce imperfect multicollinearity.

c. make the variables of interest no longer correlated with the error term,

d. reduce heteroskedasticity in the error term.

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To solve the given differential equation (6x+1)y^2 dy/dx + 4x^2 + 2y^3 = 0, we can rearrange the terms to make it an explicit equation for dy/dx: dy/dx = -(4x^2 + 2y^3) / ((6x+1)y^2)

Now, separate the variables by moving all the x terms to one side and y terms to the other side: (dy / (y^2 - 2y^3)) = - (4x dx / (6x + 1))

Next, integrate both sides of the equation: (dy / (y^2 - 2y^3)) = -∫(4x dx / (6x + 1))

To solve the given differential equation (6x+1) y^2 dy/dx + 4x^2 + 2y^3 = 0, we can rearrange the terms to get:

(6x+1) y^2 dy = - (4x^2 + 2y^3) dx

Now, we can integrate both sides:

∫ (6x+1) y^2 dy = - ∫ (4x^2 + 2y^3) dx

Integrating the left-hand side with respect to y and the right-hand side with respect to x, we get:

2y^3 (3x + 1) = - (4/3)x^3 - y^4 + C

where C is the constant of integration.

To solve for y, we can isolate y^4 on one side of the equation and take the fourth root:

y^4 = (4/3)x^3 - 2y^3 (3x + 1) + C

y^4 + 6y^3 x + (4/3)x^3 - C = 0

This is a quartic equation in y^4, which can be difficult to solve. However, if we substitute z = y^3, we can rewrite the equation as:

z^2 + 6xz + (4/3)x^3 - C = 0

This is a quadratic equation in z, which can be solved using the quadratic formula:

z = (-6x ± sqrt(36x^2 - 4(4/3)x^3 + 4C)) / 2

Simplifying and substituting back for y, we get:

y = (z)^(1/3)

y = [(-6x ± sqrt(36x^2 - 4(4/3)x^3 + 4C)) / 2]^(1/3)

This is the general solution to the given differential equation. To find a particular solution, we need to know the initial condition, such as y(0) = 1.

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Answer: C: 36

Step-by-step explanation: 3 x 4 x 3 = 36

Times how many beverages, meats, and vegetables to get your answer.

Answer:

2) x=11

Step-by-step explanation:

1) u got the first one right x=90°

2)

2x-1+69=90

2x-1=21

2x=22

x=11

Answer:

C. y = x/3 -2

Step-by-step explanation:

A linear function is a function of x.

A. is a function of x^2

B. is a function of 1/ x^2

C. is a function of x

D is a function of 1/x

The only linear function is C.

The probability of picking strawberry chocolate as the third chocolate is 6/10 or 3/5. So the overall probability of picking and eating three chocolates in the order nut, nut, strawberry is (1/2) x (5/11) x (3/5) which equals 15/110 or approximately 0.136 or 13.6%.

To find the probability of picking and eating three chocolates in the order of nut, nut, and strawberry, we'll use the concept of probability.

The probability of picking nut chocolate from the box is 6/12 or 1/2. Once a nut chocolate has been chosen and eaten, there are now 5 left in the box out of which 5/11 or approximately 0.45 are nut chocolates. So the probability of picking another nut chocolate is 5/11. Finally, once the second nut chocolate has been eaten, there are 4 left in the box out of which 6/10 or 0.6 are strawberry chocolates.

There are 12 chocolates in total: 6 with nuts and 6 with strawberries.

1. Probability of picking a nut on the first attempt: 6/12 (6 nuts out of 12 chocolates)
2. Probability of picking a nut in the second attempt: 5/11 (5 nuts out of 11 remaining chocolates)
3. Probability of picking a strawberry on the third attempt: 6/10 (6 strawberries out of 10 remaining chocolates)

To find the overall probability, multiply the individual probabilities:

Probability = (6/12) * (5/11) * (6/10) = 1/2 * 5/11 * 3/5 = 3/22

So, the probability of picking and eating three chocolates in the order of nut, nut, and strawberry is 3/22.

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Answer:

3500

Step-by-step explanation:

9 rounds up the number 4 to 5

3500

Answer:

3,500

Step-by-step explanation:

because 9 is greater than 5 so u would round upward and that 495 would become a 500 but theres also the 3,000 so add the two together and you would get 3,500

b.) No, f is not differentiable at x=4. This is because the left and right limits of the function at x = 4 are not equal, and hence the function has a sharp corner or cusp at that point.

To demonstrate this, determine the left and right derivatives of f(x) at x = 4. The limit of (f(4 - h) - f(4)) / h as h approaches 0 from the left can be used to calculate the left derivative. We receive the following results after plugging in the values from the first portion of the function:

lim h→0- [(-4 - (4 - h)) - (-4)] / h
= lim h→0- [-h / h]
= -1

Similarly, finding the right derivative is as simple as taking the limit of (f(4 + h) - f(4)) / h as h approaches 0 from the right. We receive the following results after plugging in the values from the second portion of the function:

lim h→0+ [(4 + h)^2 - 8(4 + h) + 8 - (4^2 - 8(4) + 8)] / h
= lim h→0+ [(h^2 + 16h) / h]
= 16

Since the left and right derivatives are not equal (i.e., -1 ≠ 16), the function is not differentiable at x = 4.

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