amples of coarse aggregate from a stockpile are brought to the laboratory for the determination of specific gravities. the following weights are found:
The aggregate bulk dry specific gravity, the aggregate apparent specific gravity, the moisture content of stockpile aggregate and absorption are respectively,
A. 2.7
B. 2.72
C. 1.6%
D. 0.21%
A) The formula for the aggregate bulk dry specific gravity is:
Aggregate bulk dry specific gravity = Mass of oven dried aggregate /( Mass of saturated surface dry aggregates - Submerged mass of aggregate)
Placing the values from the data we have,
Aggregate bulk dry specific gravity = 5216/ (5227 - 3295) = 2.7
B) Formula for aggregate apparent specific gravity is
Mass of oven dried aggregate/ ( Mass of oven dried aggregate - Submerged mass of aggregate) = 5216/ (5216 - 3295) = 2.7
C) The moisture content of the stockpile aggregate is
m = (weight of moist aggregate - mass of oven dried aggregate) / (mass of oven dried aggregate* 100%)
m = (5298 - 5216)/ (5216* 100%) = 1.6 %
D) Absorption is calculated as A = (5227 - 5216) / (5216) * 100% = 0.21 %
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which of the following happens when the frequency of electromagnetic radiation decreases? explain your reasoning.
As the electrical field corresponds to amplitude; so when the frequency decreases, waves broaden and the extent of the change decreases.
What happens when frequency of electromagnetic radiation decreases?When the frequency decreases, then the wavelength gets longer. There are two types of waves: mechanical and electromagnetic. Mechanical waves like sound, ocean, seismic, or earthquake travel through a solid, liquid, or gas medium whereas electromagnetic waves travel through a medium or a vacuum.
The energy equation is given as, E = hν, where E represents energy, h is Planck's constant whose value is 6.626 x 10 -34 J.s and v represents frequency. The energy equation is direct relationship between frequency and energy. As frequency increases, energy. also increases.
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a car drives around a 75 m radius curve at a constant speed of 18 m/s. a car freshener hangs by a string from the rearview mirror. determine the angle between the string and the vertical as the car rounds the curve.
The angle between the string and the car is 23.79° When the car drives around a 75 m radius curve with a constant speed of 18m.s.
Radius of the curve = r = 75m
Speed of the car = v = 18 m/s
To calculate centripetal acceleration,
Centripetal acceleration is the acceleration experienced by the car when in constant motion around the curve.
Centripetal Acceleration = Cₐ =
= v² / r
= 18² / 75
= 4.35 m/s²
Gravitational acceleration = g = 9.8 m/s²
To find the angle between the string and the car= θ =
= θ = tan (Cₐ /g)
= θ = tan (4.35 / 9.8)
= θ =23.79°
Thus, the string attached to the car moving at the constant force is at an angle of 23.79 degrees.
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a fluid enters a pipe and at the end of the pipe is a diverging nozzle. the diverging nozzle exhausts to the atmosphere. the fluid has properties of c p
The Bernoulli Principle causes pressure to fall in a converging nozzle.
the properties of the fluid was changed to the following conditions they are the change in density, energy, mass.
what was nozzle mean ?
A nozzle is a spout on the end of a hose or pipe that is used to regulate the flow of a fluid such as water or air. A convergent nozzle is one that begins large and gradually becomes smaller, resulting in a decrease in cross-sectional area. Due to mass conservation, a fluid must accelerate as it enters the smaller cross-section. The fluid must travel quicker to keep a consistent amount of fluid passing through the limited part of the nozzle.
The energy required to accelerate this fluid must originate from someplace. Some energy is included in the random motion of molecules, which we perceive as pressure. This random motion's energy.
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A 3.1 x 1023 kg object and a 7.3 x 105 kg object are orbiting each other in deep space. If these two objects are 4.3 x 1010 meters apart, what is the magnitude of their gravitational force?
The gravitational force on the object of masses 3.1×10²³ kg and 7.3×10⁵ kg respectively is 8.16×10⁻³ N.
What is gravitational force?Gravitational force is the most prevalent force in the universe, pulling together on any two objects with mass in the universe.
To calculate the magnitude of the gravitational force, we use the formula below.
Formula:
F = GmM/r²............... Equation 1Where:
F = Gravitational forcem = Mass of the first objectM = Mass of the second objectr = Distance between the objectsG = Universal constant.From the question,
Given:
m = 3.1×10²³ kgM = 7.3×10⁵ kgG = 6.67×10⁻¹¹ Nm²/kg²r = 4.3×10¹⁰ mSubstitute these values into equation 1
F = (3.1×10²³× 7.3×10⁵×6.67×10⁻¹¹)/(4.3×10¹⁰ )²F = 8.16×10⁻³ NHence, the gravitational force is 8.16×10⁻³ N.
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A cedar raft is 2. 4 m wide, 0. 30 m high, and 3. 0 m long. What is the maximum load (in newtons) the raft can support? Assume the density of cedar to be 598 kg/m^3 and ignore the volume of the load
The maximum load (in newtons) the raft can support is 7830kg.
What is buoyancy force?
A fully or partially submerged object is subject to an upward force known as the buoyant force. Upthrust is another name for this thrust upward. A body that is partially or completely submerged in a fluid gives the impression of losing weight because of the buoyant force, or that it is lighter.
What is density?
Density Symbol: D or Formula for Density: D = m/V, where D stands for density, m for mass, and V for volume.
Buoyancy is the upward force that an object feels from the water and when compared to the weight of the object.
Buoyancy force can be calculated with the equation
Fb=Vs×D×g
where F b is the buoyancy force, V s is the submerged volume, D is the density of the fluid the object is submerged in, and g is the force of gravity.
It can also be given as the sum of the weight of the raft and the weight of the load. That is,
W raft +W load = Fb=Vs×D×g.
The weight of the raft
W raft=V raft Draft g.
At maximum load, Volume of water displaced is equal to volume of the raft.
max(W load )=(D water −D raft )Vraft g.
=(1020kg/m 3 −150kg/m 3 )(3m×3m×1m)g
=7830kg.
Hence, the maximum load the raft can carry sea water so that the plank just floats in water is 7830kg.
Therefore, the maximum load (in newtons) the raft can support is 7830kg.
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f the planet were orbiting a star twice as massive as our sun but still taking 3.862 years to orbit, how far would it be from its host star?
Distance-Related Data the distance between us and Proxima Centauri, the star closest to us, is still 40,208,000,000,000 km. Or around 268,770 AU.
Explain about the planet were orbiting a star?Exoplanets are planets that revolve around other stars. In our solar system, every planet revolves around the Sun. Exoplanets are extremely difficult to directly observe using telescopes.
One particular planetary system a star with planets surrounding it—is our solar system. Although there are more than 3,200 other stars in our galaxy with planets around them, our solar system is the only one that is formally referred to as a "solar system."
Surprisingly, our simulations reveal that a planet does not rapidly disintegrate inside of a red giant star or even modify its orbit—in certain situations, a planet continues to circle below a red giant star's photosphere for thousands or even millions of years.
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if we connect two diodes in series pointing in opposite direction, we can still get the output of the circuit.
When two diodes are connected in opposing directions, both of them will constantly be in the reverse bias state and won't conduct until they break down.
How does a diode function? What is it?A diode is a semiconductor component that only allows one way for electricity to flow. These are the fundamental parts of semiconductors and are referred to as "active components." They are capable of keeping a steady voltage and control the flow of power.
Why are diodes necessary?Due to its capacity to limit electrical current flow to only one direction, diodes are utilized in circuit protection. This quality is advantageous since several electrical devices and components will break down or become damaged if current travels in the different path.
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Part Description Answer The two main categories of pipes we examine for our physics of sound study are Save 1. straight pipes with red waves and straight pipes with blue waves a pipe with both ends open, and a pipe with one end closed a pipe with pressure and a pipe with displacement a pipe with no openings and pipe with many openings 5.56 pts. 100% 10% try penalty Hints: Q,0 You have an open pipe and closed pipe of the same length: Which will have the higher (fundamental frequency 5.56 pts.100% 33% try penalty 1. open pipe 2. closed pipe 3. they will have the same frequency Hints: 0,0 What is the harmonic n = 3 of an open-open pipe 9 m in length? (include units with answer) 5.56 pts.100% Format Check 2% try penalty Bonus hint Hints: 1,0 What is the harmonic n = 3 of an closed-open pipe 9 m in (length? (include units with answer) 5.56 pts. 100% Format Check 2% try penalty Bonus hint Hints: 0,0
Examining the types of Organ Pipes, we evaluate,
A) 2) A pipe with both ends open, and a pipe with one end closed
The first pipe is called an open pipe and the second pipe is called a closed pipe
B) 1) open pipe
If L is the length of the pipes,
fundamental frequency of open pipe, f(open)= v/(2*L)
fundamental frequency of closed pipe, f(closed)= v/(4*L)
clearly, f(open) = 2*f(closed)
C) 5th harmonic of open pipe, f5 = 5*v/(2*L) = 5*343/(2*2) = 429 Hz
D) 5th harmonic of closed pipe, f5 = 5*v/(4*L) = 5*343/(4*2) = 214 Hz
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what will happen if the s and c inputs on an active high s-c flip-flop are both high at the same time?
Consider a lamina occupying the region R and having the density function rho: R is the rectangular region with vertices (0, 0), (0, 3), (8, 3). rho(x, y) = ((xy)^(1/2)).
a) Find the moments of inertia Ix, Iy, and I0 about the x-axis, y-axis, and origin, respectively.
b) Find the radii of gyration with respect to the x-axis, y-axis, and origin, respectively.
There are specified boundary conditions.y = root of x – 1 – y = 3 – x – y = 0, and y = 0 when x is subtracted from the answer.
Find the moments of inertia ?
We must determine how much the area of rwill be now that we have the figure. Using integration, we will obtain the d l of r, whose area is equal to the integration of the 122 root of our x minus 1 dx plus the integration of limit 2233 minus x Dx. From here, we can write that 2 divided by 3 multiply x, minus 1 whole to the power 3 divided by 2 limit 1 to 2 plus 3 x minus x, squared y = root of x – 1 – y = 3 – x – y = 0, and y = 0 when x is subtracted from the answer.To learn more about boundary conditions refer
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a helium-neon laser emits laser light at a wavelength of 632.8 nm and a power of 2.3 mw. at what rate are photons emitted by this device?
These photons are emitted by this devices at rate 73.2 x 10¹⁴
The rate of photons emittedPhotons can be absorbed or emitted from atoms if the electrons in the atom transition from a state expressed in quantum numbers. The movement of electrons from a lower quantum state to a higher quantum state requires photons.
To determine the rate of the emitted photon, find the energy of each photon first.
Use formula:
E = hc/λ
h is Planck's constant and c is the speed of light.
h = (6.628) (10⁻³⁴) Js
c = (2.998) (10⁸) m/s
So,
E = hc/λ
= (6.626 × 10⁻³⁴) (2.9 × 10⁸) / (632.8 x 10⁻⁹)
= 3.14 x 10⁻¹⁹ J
Hence the energy emitted = 2.3 x 10⁻³
So, the rate:
= 2.3 x 10⁻³ / 3.14 x 10⁻¹⁹
= 73.2 x 10¹⁴
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What is the bug's speed at the end of this displacement? assume that the speed is due entirely to the wind.
The work done by the wind is 90 × [tex] {10}^{-2} [/tex] Joules and the bug's speed at the end of this displacement is 6.32 m/s.
The bug's speed can be calculated by the formula -
Work = Force × displacement
Keep the values in formula to find the work done -
W = (4i - 6j) × [tex] {10}^{-2} [/tex] × (9i - 9j)
Performing multiplication on Right Hand Side of the equation -
W = (36 + 54) × [tex] {10}^{-2} [/tex]
Performing addition on Right Hand Side of the equation
W = 90 × [tex] {10}^{-2} [/tex] Joules
The bug's speed at the end is -
W = 1/2mv²
As 1000 gram = 1 kg
So, 45 gram = 45 × [tex] {10}^{-3} [/tex] grams
90 × [tex] {10}^{-2} [/tex] = 1/2 × 45 × [tex] {10}^{-3} [/tex] × v³
v² = (2 × 90 × [tex] {10}^{-2} [/tex]) ÷ (45 × [tex] {10}^{-3} [/tex])
v² = (180 × 10) ÷ 45
v² = 1800/45
v² = 40
v = ✓40
v = 6.32 m/s.
Hence, the work done is 90 × [tex] {10}^{-2} [/tex] Joules and bug's speed is 6.32 m/s.
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The complete question is -
A 45 gram bug is hovering in the air. A gust of wind exerts a force (4i - 6j) × [tex] {10}^{-2} [/tex] N on the bug. How much work is done by the wind as the bug undergoes displacement 9i - 9j. What is the bug's speed at the end of this displacement? assume that the speed is due entirely to the wind.
A cubical block of mass m and side 'a' is moving horizontally on a smooth horizontal surface with a velocity v 0
. The block collides with a ridge P and starts rotating about P. Find the minimum value of v 0
needed to overcome the ridge.
A cubical block of mass m and side a is moving horizontally on a smooth horizontal surface with a velocity v₀. The minimum value of v₀ is 4aω/3.
Consider the initial angular momentum of the block,
Li = Mv × x
Angular momentum of the block after it hits a certain point O is
Lf = Ic *ω
where, Ic is the moment of inertia
ω is angular velocity
From the parallel axis theorem, we have
Io = Ic + M * OC² = 1/6 M a² + M ( AC² + AO² ) = 1/6 M a² + 1/2 M a² = 2/3 M a²
Using the law of conservation of angular momentum, we have
1/2 M v = 2/3 M a² ω
v = (4a ω)/3
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shown following are several times in the history of the universe. imagine that you were able to watch a single photon that has been part of the cosmic microwave background since it first became present in the universe. rank these times from left to right based on the wavelength this photon would have at each time, from shortest to longest. 100 million years after the Big Bang
1.5 billion years after the Big Bang
1 million years after the Big Bang
500,000 years after the Big Bang
today
The rank of these times from left to right based on the wavelength of this photon would have at each time, from shortest to longest are:
500,000 years after the Big Bang. 1 million years after the Big Bang.100 million years after the Big Bang. 1.5 billion years after the Big Bang. Today.What are photon wavelength and frequency?There is a wavelength and a frequency for every photon. The distance between two electric field peaks with the same vector is known as the wavelength. The number of wavelengths a photon travels through each second is what is known as its frequency. A photon cannot truly have a color, unlike an EM wave.
Therefore, In the standard model of particle physics, the photon is a fundamental particle. It has no discernible wavelength. The table describes it as a point particle with mass 0 and spin 1.
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A corgi dog has a mass of 10 kg and is running at you with a velocity of 5 m/s. What is the momentum of the dog?.
The momentum of the dog will be 50Kgm/s.
What is Momentum?Momentum is the product of the mass of a body and its velocity. Momentum is a vector quantity meaning it has both magnitude and direction.
From Isaac Newton’s second law of motion which states that the time rate of change of momentum is equal to the force acting on the body.
Also, according to Newton’s third law, when a force is applied on a body there is an equal and opposite reaction, so any change in the momentum of one body is balanced by an equal and opposite change of the momentum of another body. So, in the absence of any external force acting on a collection of bodies, their total momentum never changes; this is the law of conservation of momentum.
Momentum, p = mass (m) x velocity (v)
where m = 10kg
v = 5m/s
p = 10 x 5
p = 50kgm/s.
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car b is rounding the curve with a constant speed of 54 km/h, and car a is approaching car b in the intersection with a constant speed of 72 km/h. determine the velocity which car a appears to have to an observer riding in and turning with car b. the x-y axes are attached to car b. is this apparent velocity the negative of the velocity which b appears to have to a non-rotating observer in car a? the distance separating the two cars at the instant depicted is 40 m.
The velocity of car A relative to the observer of car B when the car B is not rotating is, V = ( 20i - 15j ) m/s
Velocity of car B with which it is rounding is: Vb = 54km/hr = 15m/s
velocity of car A with which it is approaching car B: Va = 72km/hr = 20m/s
Distance between the two cars, d = 40m
velocity is car A is
Va = Vb + Vb/r × d + V ( V is the velocity of car A relative to the observer of car B)
20i = 15j + 15/100k × ( -40i ) + V
20i = 15j - 6j + V
V = ( 20i - 9j ) m/s
Thus the velocity of car A relative to the observer of car B = ( 20i - 9j ) m/s
The velocity of car A relative to the observer of car B when the car B is not rotating, V = ( 20i - 15j ) m/s
As this velocity is not negative relative to the previously calculated velocity.
Thus, this apparent velocity is not negative.
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how fast, in rpm , would a 5.8 kg , 20- cm -diameter bowling ball have to spin to have an angular momentum of 0.26 kgm2/s ?
Angular speed is the speed of the object which determines how fast any object can rotate. It has both direction and magnitude and so is the vector quantity.
Given that:
Angular momentum (L) = 0.26
Diameter = 20cm = 0.2 cm
Radius, r = (d/2) = 0.1m
Mass = 5.8 kg
Moment of inertia (I) = 2mr² / 5
I = (2 * 5.8 * 0.1^2) / 5
= 0.116
= 0.116 / 5
= 0.023 kgm²
Angular speed (w) ;
w = L / I
w = 0.26 / 0.023
= 11.30
= 11.3 rad/s
w = (11.3 * 60/2π)
w = 1064.9
Angular speed = 1064.9 rpm
= 1065 rpm
Therefore the angular speed is 1065 rpm.
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an object has a weight of 8.50 n when in air. however, it apparantley weighs 4.40 n when completely submerged in water
the density of the object is 0.0041 g/vol
How does density change in water and air?Water has a density of about 1 gram per milliliter, however this might vary depending on temperature or the things that are dissolved in it. Because ice is less thick than liquid water, ice cubes float in glasses of water.
Compared to a unit volume of liquid water, air has fewer molecules per volume, making it lighter.
Given two weights = 8.5 N and 4.4 N
the formula v₀ = wₐ - wₓ/ pₓg
here wₐ = weight in air
and wₓ = weight in water
Thus on substituting the value of the above mentioned dimensions we get
v₀ = 8.5 - 4.4 / 1000
v₀ = 0.0041
Thus the density of the object is 0.0041 g/vol
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TRUE/FALSE. founders' shares, a type of classified stock owned by the firm's founders, generally have more votes per share than the other classes of common stock.
A sort of categorized stock known as founders' shares is owned by the company's founders and typically has more voting rights per share than other classes of common stock.
What is founders' shares ?This is accurate since founders typically hold the earliest shares of a company, giving them a greater number of voting rights per share than other classes of common stock.The founders of the company own founders' shares, a sort of categorized stock that often has higher voting power per share than other classes of common stock.The shares given to a company's founders are referred to as founders stock.Up until a dividend is due to the holders of common stock, the stock frequently doesn't generate any income.When the shares in founders stock become exercisable is determined by the vesting schedule.To learn more about founders' shares refer
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when charges mutually repel and distribute themselves on the surface of conductors, what becomes of the electric field inside the conductor?
The charges align themselves so that the conductor's internal field is zero.
What occurs if a charged surface is in close proximity to a conducting surface?Induced charges are created on the conductor when a charge is brought close to it. The internal free charges of the conductor, however, are gathered throughout its surface because the electric field inside the conductor must be zero in order to defeat the electric field of induced charges.
What takes place within a conductor?A substance that has a lot of free electrons accessible for the flow of current is said to be a conductor. Since there are numerous electrons, a powerful force of repulsion exists between them as well. As a result, the electrons move to lessen their attraction for one another.
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What percentage of the final current I0 flows through an inductor L in series with a resistor R , three time constants after the circuit is completed?
The required percentage of the final current that flows is 95 %.
The percentage of the final current flows through an inductor Using the decay of current in the RL circuit,
[tex]I = I_{0} ( 1 - e^{\frac{-l}{r} } )[/tex]
It is given that an inductor L in series with a resistor R
So, l = 3r
Then,
[tex]I = I_{0} ( 1 - e^{\frac{-3r}{r} } )\\\\I = I_{0} ( 1 - e^{-3 } )[/tex]
Now,
[tex]I = I_{0} ( 1 - e^{-3 } )\\\\ I = I_{0} ( 1 - 0.04978 } )\\\\I =I_{0} *0.95[/tex]
So,
[tex]\frac{I}{I_{0} }*100 = 95 %[/tex]
Hence, The required percentage of the final current that flows is 95 %.
A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.
The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field.
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Humans can produce an output power as great as 20 W/kg during extreme exercise. Sloths are not so energetic. At its maximum speed, a 4.0 kg sloth can climb a height of 6.0 m in 2.0 min.What's the specific power for this climb?Express your answer in watts per kilogram.
Answer:
below
Explanation:
Work = force x distance = PE gain = mgh = 4 kg * 9.81 m/s^2 * 6 = 235.44 j
Power = work / time ( time is in seconds)
= 235.44 / (2*60) = 1.962 watts
SPECIFIC power = 1.962 w / 4 kg = .49 w/kg
a cube of side length 10.0 cm and made of unknown material floats at the surface between water and oil. the oil has a density of 810 kg/m3. If the cube floats so that it is 71 % in the water and 29 % in the oil, what is the mass of the cube?What is the buoyant force of the cube?
The buoyant force of the cube is 23 / 12 gcm^-3. Upthrust, often known as buoyancy, is an upward force applied by a fluid against the weight of an object that is partially or completely submerged.
What is buoyant force ?Upthrust, often known as buoyancy, is an upward force applied by a fluid against the weight of an object that is partially or completely submerged. The weight of the fluid on top causes pressure in a fluid column to rise with depth.
Any object in water experiences a buoyant force that works against gravity, causing it to shed some of its weight. The buoyant force acting on the object will be equal to gravity and it will float if it displaces an amount of water equal to its own weight.
Let the side of metal be L.
So the of base is A = L²
Now the weight of 144 g weight will be balanced by the buoyancy force due to 1/2cm length of metal cube (p = 2gcm^-3)
So buoyancy force is F = A x L1pg=L^2 x 1/2 x 2x10
L = 12cm
This force is equal to weight of 144gm.
so, L² x 1/2 x 2 x 10 = 144 x 10
L = 12 cm
when no weight was placed the 1/2 cm was above the liquid.
so total length under weight was L - 1/2 = 23/ 2 cm
weight of block = buoyancy force
pmetal x L³ x g = p x L² x 23/2 x g
pmetal = 23 / 12 gcm^-3
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54(a) Define the capacitance of a capacitor
(b) State:
three factors on which the capacitance
a parallel plate capacitor depends.
(ii) two uses of capacitors.
(c) The plates of a parallel - plate capacitor
are 5mm apart and 2m² in area. The plates
are in vacuum. A potential difference of 1kv
is applied across the capacitor.
Calculate the:
(i)
Capacitance
(ii) charge on each plate
ii) electric intensity in the space between them
iv) energy stored in the capacitor
[NECO,2000] [Permitivity of free space.
Do=8.85x10-¹² Nm²C²1
a) The ratio of the electric charge on each conductor to the potential difference (i.e., voltage) between them is used to express capacitance.
b) The area of the plates, the spacing between them, and the type of insulating material or dielectric between them are the three variables that have an impact on a parallel-plate capacitor's capacitance.
c) The area of each plate, the dielectric material separating the plates, and the distance between the plates all affect the capacitance of a parallel plate capacitor.
What is Capacitor?An electrostatic field of energy is stored in a capacitor, a passive electrical component. A capacitor is made up of two conducting plates and an insulating substance called the dielectric in its most basic form.Farads (F), which bear the name of English physicist Michael Faraday, are the units used to measure the capacitance of a capacitor (1791–1867). There is a lot of capacitance in a farad.a capacitor is an electrical energy storage device that consists of two conductors that are isolated from one another and placed near to one another. A straightforward illustration of such a storage system is the parallel-plate capacitor.A dielectric material and two metal plates serve as the building blocks of a capacitor.To learn more about Capacitor refer to:
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solar photovoltaic energy is highly versatile and can be used in a variety of dispersed settings. which of the following would not be a good location to harness large amounts of this form of energy?
The location that is not good for photovoltaic cells is the farm.
What is a photovoltaic cell?In the recent years, there have been a lot of clamor for the return to clean energy and the first port of call have been the consideration of the use of renewable energy sources as a power source for the future. This has engendered the return to the solar energy.
In the harvesting of the solar energy, solar cells are displayed in such a place that they can be able to absorb the energy from the sun and this is converted to electrical energy.
Unfortunately, if we are to harness the use of the photovoltaic cells, we need a large expanse of land that can be used to mount the cells and these lands would cease to be available for use in agriculture.
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Missing parts;
Solar photovoltaic energy is highly versatile and can be used in a variety of dispersed settings. Which of the following would NOT be a good location to harness large amounts of this form of energy?Roof tops of commercial buildings Base-load Power Facilities Airports Agricultural Fields Residential Neighborhoods
a battery was charged. when the charging began, it was 232323 percent full. after 303030 minutes of charging, the battery was 898989 percent full.
According to the provided statement, a power supply was charged after 2.2 minutes of charging.
What would you say is charge?Charge, also referred to as electric charge, electrostatic attraction, or electrostatic interactions and denoted by the symbol q, is a property of a unit of matter that indicates how many more or fewer particles than protons it contains.
Charge, in brief: what is it?The physical characteristic of matter that leads it to feel a force when exposed to an electromagnetic field is called electric charge. The two types of electric charges that protons and electrons most frequently carry are positive and negative charges. Charge movement is what produces energy.
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for the composite bar of prob. 2.111, determine the residual stresses in the tempered-steel bars if p is gradually increased from zero to 98 kips and then decreased back to zero.
The load in the column has an eccentricity of 13.13 mm.
The column has a maximum stress of 78.72 MPa.
a)
P = 310 kN is the axial load that is applied to the column.
At the middle of the column, there is a ym = 9 mm deflection.
The column has an elasticity modulus of E = 200 GPA.
The column measures L= 6.5 m in length.
Consult the textbook's Appendix C, "Properties of Rolled-Steel Shapes."
Rolled-steel form for W25058;
7,420 mm2 is the cross-sectional area.
I = Iy = 18.7106 mm4 is the smallest moment of inertia on the y-axis.
R = ry = 50.3 mm is the smallest radius of gyration on the y-axis.
S = Sy = 185103 mm3 is the section's section modulus.
The column's length (L) and its effective length (Le) are equal (L).
Le = L= 6.5 m
Using the equation, determine the critical load (Pcr).
Pcr = π2EI(Le)2
The elastic modulus in this instance is E.
Change E to 200 GPa, I to 18.7 106 mm4, and Le to 6.5 m.
Pcr=π2 * 200 GPa * 109 N/m21 GPa * 18.7 * 106 mm4 * (1 m1,000 mm)
4(6.5)
2 = 873,665 N * 1 kN1,000 N = 873.665 kN
Using the equation, ascertain the load's eccentricity (e).
ym=e[sec(π2PPcr)−1]
The column's deflection in this instance is ym.
Change ym to 9 mm, P to 310 kN, and Pcr to 873.665 kN.
9 = e * [sec(π2310873.665) − 1]
e = 13.13 mm
As a result, the load's eccentricity within the column is 13.13 mm.
b)
P = 37 kN is the axial load applied to the rod.
P = 310 kN is the axial load that is applied to the column.
At the middle of the column, there is a ym = 9 mm deflection.
The column has an elasticity modulus of E = 200 GPA.
The column measures L= 6.5 m in length.
Consult the textbook's Appendix C, "Properties of Rolled-Steel Shapes."
Rolled-steel form for W25058;
7,420 mm2 is the cross-sectional area.
I = Iy = 18.7106 mm4 is the smallest moment of inertia on the y-axis.
R = ry = 50.3 mm is the smallest radius of gyration on the y-axis.
S = Sy = 185103 mm3 is the section's section modulus.
c)
The section's section modulus in this case is S.
Change I to 18.7106 mm4 and S to 185103 mm3.
c = 18.7 × 106185 × 103 = 101.08 mm
Using the equation, determine the highest tension in the column (max).
σmax = PA(1+ecr2sec(π2PPcr))
Replace P with 310 kN, A with 7,420 mm2, E with 13, C with 101.08 mm, R with 50.3 mm, and Pcr with 873.665 kN.
σmax = 310 kN×1,000 N1 kN7,420 mm2×(1 m1,000 mm)2(1+13.13×101.0850.32sec(π2310873.665))
=78.72×106 Pa×1 MPa106 Pa=78.72 MPa
Consequently, the column's maximum stress is 78.72 MPa.
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Frequently, attention in an equilibrium situation is confined to a plane. An example would be a ladder leaning against a wall, which is in danger of slipping only in the plane perpendicular to the ground and wall. By orienting a Cartesian coordinate system so that the x and y axes are in this plane, choose which of the following sets of quantities must be zero to maintain static equilibrium in this plane.
\sum F_x and \sum \tau_z and \sum F_y
\sum F_z and \sum \tau_x and \sum \tau_y
\sum \tau_x and \sum F_x and \sum \tau_y and \sum F_y
\sum \tau_x and \sum F_x and \sum \tau_y and \sum F_y and \sum \tau_z
To preserve static equilibrium in this plane, the following sets of quantities must all be zero: ∑Fx and ∑τz and ∑Fy
We can see from the question that we must demonstrate the collection of values that must be zero in order to maintain static equilibrium on the provided plane.
As a result, we can see that the set of variables that must equal zero in order to maintain static equilibrium in the given plane is composed of Fx, Fy, and τz
This is due to the fact that a system must have all of its components' forces added together to equal zero in order for it to remain in equilibrium.
Thus, To preserve static equilibrium in this plane, the following sets of quantities must all be zero: ∑Fx and ∑τz and ∑Fy
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if the 36.0- n force continues, the box accelerates at 0.38 m/s2 . what is the coefficient of kinetic friction?
The coefficient of kinetic friction is 0.54
Kinetic friction is characterized as a force that acts between moving surfaces. A body moving on the surface encounters a force in the opposite direction of its movement. The magnitude of the force will depend on the coefficient of kinetic friction between the two materials. Here we are given the information of a force of 36.0 N required to a 6.0-kg box moving across a horizontal concrete floor and the acceleration is at 0.60 m/s2.The formula we can refer to in order to the calculate the kinetic friction is : F- u[tex]_{k}[/tex](mg)=ma
=>36-u[tex]_{k}[/tex](mg)= 6* 0.60
=> u[tex]_{k}[/tex](mg) = 36 -(3.6)
=> u[tex]_{k}[/tex]= 32.4/mg
=>u[tex]_{k}[/tex]= 32.4/6*10 = 0.54
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A force of 36.0 n is required to start a 6.0-kg box moving across a horizontal concrete floor. if the 36.0-n force continues, the box accelerates at 0.60 m/s2 . What is the coefficient of kinetic friction?
