how do i solve this

Answer:

The cost before rebates is: $69.95 + $49.95 = $119.90

The total rebate amount is: $20 + $30 = $50

The cost of two envelopes is: 2 x $0.20 = $0.40

The cost of two stamps is: 2 x $0.394 = $0.788

The total cost after rebates and including expenses is: $119.90 - $50 + $0.40 + $0.788 = $70.078

Rounding to two decimal places, the total cost after rebates and including expenses is $70.08

The actual rebate after expenses is: $50 - $0.40 - $0.788 = $48.812

Rounding to two decimal places, the actual rebate after expenses is $48.81

The perimeter and area of the given polygon are:

Perimeter = 22.325 units

Area = 25 square units

Using Pythagoras theorem, we can find the length of the sides of the polygon as:

a = √(1² + 3²)

a = √10

b = √(3² + 3²)

b = 2√9

c = √(3² + 3²)

c = 2√9

d = √(1² + 3²)

d = √10

e = 4

Thus:

Perimeter = 2√10 + 4√9 + 4

Perimeter = 22.325 units

Area = 2(¹/₂ * 1 * 3) + 2(¹/₂ * 3 * 3) + (4 * 3)

= 25 square units

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Answer:

Step-by-step explanation:

To find the difference in temperature between the day's high and low, we need to subtract the low temperature from the high temperature.

The high temperature is 18 degrees, and the low temperature is -6 degrees.

So, the difference in temperature between the day's high and low is:

18 degrees - (-6 degrees)

= 18 degrees + 6 degrees

= 24 degrees

Therefore, the difference in temperature between the day's high and low is 24 degrees.

Question: "Identify the correct description for the formula g'(x) ≈ g(x)/h – g(x – h)/h from the following options: FFD1: forward finite difference with stepsize h for the first derivative of g at a BFD1: backward finite difference with stepsize h for the first derivative of g at a CFD1: central finite difference with stepsize h for the first derivative of g at x CFD2: central finite difference with stepsize h for the second derivative of g at x None of the Above"

The correct description for the formula g'(x) ≈ g(x)/h – g(x – h)/h is BFD1: backward finite difference with stepsize h for the first derivative of g at a.

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Answer:

308

Step-by-step explanation:

The area of a rectangle is the length multiplied by the width.

14 x 22 = 308

Hope this helps!

0 (to four decimal places).

To find the probability that p is less than 0.9, we need to use the normal approximation to the binomial distribution, as n is large (n=255) and p is not too close to 0 or 1 (p=0.83).

The mean of the binomial distribution is given by μ = np = 255 × 0.83 = 211.65, and the standard deviation is given by σ = sqrt(np(1-p)) = sqrt(255 × 0.83 × 0.17) = 4.46 (rounded to two decimal places).

To use the normal distribution, we standardize the variable p using the formula z = (p - μ) / σ. Then, we find the probability that z is less than (0.9 - μ) / σ.

z = (0.9 - 211.65) / 4.46 = -35.43 (rounded to two decimal places)

Using a standard normal table or calculator, we find that the probability of a standard normal random variable being less than -35.43 is essentially 0 (to four decimal places). Therefore, the probability that p is less than 0.9 is also essentially 0 (to four decimal places).

Answer: 0 (to four decimal places).

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a) Samantha will have $20,359.68 in the account after the last $175 deposit is made in seven years.

b) Samantha makes 175-dollar deposits at the beginning of each month for seven years, she will have $21,372.77 in the account after the last deposit is made.

We can use the formula for the future value of an annuity with monthly compounding to solve this problem. The formula is:

FV = [tex]P * (((1 + r/n)^(n*t) - 1) / (r/n))[/tex]

Where:

FV is the future value of the annuity

P is the regular payment or deposit

r is the annual interest rate

n is the number of compounding periods per year (12 for monthly compounding)

t is the total number of years

a. If Samantha makes 175-dollar deposits at the end of each month for seven years, the total number of deposits she will make is:

7 years x 12 months/year = 84 deposits

The regular payment or deposit is P = $175, the annual interest rate is r = 5.4%, and the number of compounding periods per year is n = 12. The total number of years is t = 7.

Using the formula above, we can calculate the future value of the annuity:

FV = [tex]$175 *[/tex] [tex](((1 + 0.054/12)^(12*7) - 1) / (0.054/12))[/tex]

FV = [tex]$175 *[/tex] (((1.0045)[tex]^84 - 1[/tex]) / (0.0045))

FV =[tex]$175 * (116.2269)[/tex]

FV = $20,359.68

Therefore, Samantha will have $20,359.68 in the account after the last $175 deposit is made in seven years.

b. If Samantha makes 175-dollar deposits at the beginning of each month for seven years, we need to adjust the formula above to account for the timing of the deposits. One way to do this is to use the formula:

[tex]FV = P * (((1 + r/n)^(n*t) - 1) / (r/n)) * (1 + r/n)[/tex]

Where the additional factor (1 + r/n) accounts for the fact that the deposits are made at the beginning of each month.

Using this formula, we get:

FV = [tex]$175 * (((1 + 0.054/12)^(12*7)[/tex] - 1) / (0.054/12)) * (1 + 0.054/12)

FV = [tex]$175 * (((1.0045)^84 - 1)[/tex] / (0.0045)) * 1.0045

FV = $175 * (122.2837)

FV = $21,372.77

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the following points have been plotted on the cartesian plan:

(-3, 2) and

(-3, -2). The above represent coordinates.

A coordinate system in geometry is a system that employs one or more integers, or coordinates, to define the position of points or other geometric components on a manifold such as Euclidean space.

A coordinate system is a framework for specifying the relative positions of objects in a specific region, such as an area on the earth's surface or the whole earth's surface. A geographic coordinate system determines locations on the world by using a three-dimensional spherical surface.

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Part A) The best graphical representation to display the given data would be a histogram.

Part B) The illustration of the histogram is displayed below.

Part A:  A histogram is a type of bar graph that displays the frequency distribution of a set of continuous data. In this case, we have a set of grades, which are continuous data, and a histogram can display the frequency distribution of these grades. A histogram is an appropriate choice because it allows us to see the distribution of the grades and identify any patterns or outliers in the data.

Part B: To create a histogram for the given data, we need to follow these steps:

Determine the class intervals: Class intervals are ranges of data values that are used to group the data in a histogram.

Count the frequency of data in each class interval: We need to count how many data points fall in each class interval.

We draw the x-axis, which represents the class intervals, and the y-axis, which represents the frequency of data in each class interval. Then, we draw rectangles on the x-axis, each representing a class interval, with a height equal to the frequency of data in that interval.

Finally, we need to label the x-axis as "Grades" and the y-axis as "Frequency." If needed, we can also include a scale on the x-axis to indicate the range of grades being displayed.

By following these steps, we can create a histogram that effectively displays the distribution of grades in the given data set.

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Answer:

A, C, E

Step-by-step explanation:

remember to law of sine :

a/sin(A) = b/sin(B) = c/sin(C)

or the "upside-down" version :

sin(A)/a = sin(B)/b = sin(C)/c

with a, b, c being the sides of the triangle, and A, B, C being the corresponding opposite angles in the triangle.

so, as you can clearly see, we always need at least one angle and one side (in fact either 2 angles one side or 1 angle 2 sides) to use the law of sine to solve the rest of the triangle.

therefore, the answer options A, C, E are correct.

for SSS (all 3 sides are known) we need the law of cosine to solve the angles (at least one of them, and then we could continue with either law).

remember :

c² = a² + b² - 2ab×cos(C)

again, a,b,c are the sides, and C is the opposite angle of whatever side we define as "c".

that's why I always call this the extended Pythagoras.

for AAA (all 3 angles are known) we cannot solve the triangle, because dilated triangles all have the same angles. and therefore there are infinitely many triangles with the same angles.

The  p-value (0.031) is less than the significance level (0.05), we reject the null hypothesis.

To determine whether the automobile insurance company has an average insurance payout for all their customers that is greater than $500 per insurance claim, we can conduct a hypothesis test.

Let's define the following:

- Null hypothesis (H0): The average insurance payout per claim for all customers of the insurance company is $500 or less.
- Alternative hypothesis (Ha): The average insurance payout per claim for all customers of the insurance company is greater than $500.

We can set a significance level for the test, which is the probability of rejecting the null hypothesis when it is actually true. Let's set a significance level of 5% (0.05).

Next, we need to calculate the test statistic, which is the number of standard deviations that the sample mean is from the hypothesized population mean. The test statistic for a one-sample t-test is:

t = (XX  - μ) / (s / √n)

Where:
- X  is the sample mean ($579.80)
- μ is the hypothesized population mean ($500)
- s is the sample standard deviation ($751.30)
- n is the sample size (18)

Substituting the values, we get:

t = (579.80 - 500) / (751.30 / √18)
t = 2.02

We can then find the p-value, which is the probability of getting a test statistic as extreme as the one we calculated, assuming the null hypothesis is true. We can use a t-distribution table or a statistical software to find the p-value. For a one-tailed test with 17 degrees of freedom (n-1), the p-value is approximately 0.031.

Since the p-value (0.031) is less than the significance level (0.05), we reject the null hypothesis. We can conclude that there is sufficient evidence to suggest that the average insurance payout per claim for all customers of the insurance company is greater than $500.

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Jackson will have 112 cards in his collection after 7 years. The Option D is correct.

The difference between the number of cards in year 2 and year 3 is:

= 48 - 32

= 16

Note: Its covers a span of 3 - 2 = 1 year. Therefore, the average number of cards added per year between years 2 and 3 is 16/1 = 16.

Now we can estimate the number of cards Jackson will have in year 7 by stating the following formula:

= Number of cards in year 5 + (Average number of cards added per year) x (Number of years from year 5 to year 7)

= 80 + 16 x (7 - 5)

= 80 + 32

= 112 cards

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Answer:  16.8 feet

Note: your teacher may not want you to enter "feet" and instead may just want the number only.

===================================================

Work Shown:

tan(angle) = opposite/adjacent

tan(40) = h/20

20*tan(40) = h

h = 20*tan(40)

h = 16.7819926 which is approximate

h = 16.8

The streetlamp is approximately 16.8 ft tall.

When using your calculator, make sure it's in degree mode. One way to check is to compute something like tan(45) and you should get 1 as a result.

Step-by-step explanation:

The table should be completed with the components of the quadratic equation as follows;

In Mathematics and Geometry, the general form of a quadratic function can be modeled and represented by using the following quadratic equation;

y = ax² + bx + c

Where:

Axis of symmetry, Xmax = -b/2a

Axis of symmetry, Xmax = -(2)/2(1)

Axis of symmetry, Xmax = -2/2

Axis of symmetry, Xmax = -1

For the vertex, we have:

f(-1) = (-1)² + 2(-1) - 8 = -9.

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The student solved 12 problems correctly.

To find out how many problems the student solved correctly, we can use the given information and set up an equation using the terms "correct problems" and "incorrect problems."

Let x represent the number of correct problems and y represent the number of incorrect problems. We know the following:

1. The total number of problems completed is 33, so x + y = 33.
2. The teacher pays 70 cents for correct problems and takes 40 cents for incorrect problems, and neither owes anything to each other. So, 70x - 40y = 0.

Now, we'll solve this system of equations step-by-step:

Step 1: Solve the first equation for x: x = 33 - y.
Step 2: Substitute the expression for x in the second equation: 70(33 - y) - 40y = 0.
Step 3: Simplify and solve for y: 2310 - 70y - 40y = 0 => 2310 - 110y = 0 => y = 21.
Step 4: Substitute the value of y back into the equation for x: x = 33 - 21 => x = 12.

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The probabilities are:

(a) P(X = 0) ≈ 0.3139

(b) P(X ≥ 1) ≈ 0.6861

(c) P(X ≤ 1) ≈ 0.9862

We can model this situation using the hypergeometric distribution.

Let's define:

N = total number of manufacturing plants = 30

D = number of plants outside the country = 7

n = number of plants in the performance evaluation = 4

(a) Probability of including no plants outside the country:

We want to find P(X = 0), where X is the number of plants outside the country in the performance evaluation. This can be calculated using the hypergeometric distribution formula:

P(X = 0) = (C(23, 4) * C(7, 0)) / C(30, 4) = (23 choose 4) / (30 choose 4) ≈ 0.3139

(b) Probability of including at least 1 plant outside the country:

We want to find P(X ≥ 1). We can use the complement rule and find the probability of including no plants outside the country and subtract it from 1:

P(X ≥ 1) = 1 - P(X = 0) = 1 - (C(23, 4) * C(7, 0)) / C(30, 4) ≈ 0.6861

(c) Probability of including no more than 1 plant outside the country:

We want to find P(X ≤ 1). This can be calculated as the sum of P(X = 0) and P(X = 1):

P(X ≤ 1) = P(X = 0) + P(X = 1) = (C(23, 4) * C(7, 0)) / C(30, 4) + (C(23, 3) * C(7, 1)) / C(30, 4) ≈ 0.9862

Therefore, the probabilities are:

(a) P(X = 0) ≈ 0.3139

(b) P(X ≥ 1) ≈ 0.6861

(c) P(X ≤ 1) ≈ 0.9862

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To estimate a in a binomial distribution, you can use the maximum likelihood estimation (MLE) method. Here are the steps:

1. Define the terms:
  - a: The probability of success in a single trial
  - n: The number of observations (trials)
  - k: The number of successful events among the n trials

2. Write the binomial probability function:
  P(k events | a) = (nCk) * (a^k) * (1 - a)^(n - k)

3. Calculate the likelihood function, which is the product of the binomial probability functions for all observed data points (for k = 0, 1, 2, ..., n).

4. Differentiate the logarithm of the likelihood function with respect to a (using logarithmic properties to simplify the expression) to obtain the first-order condition.

5. Set the first-order condition equal to zero and solve for a, which will give you the maximum likelihood estimate of a.

By following these steps, you can estimate a in a binomial distribution based on the number of events among n observations using the maximum likelihood estimation method.

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The solution to the equation ex + x = 7 using Newton's method with an initial guess of Xo = 2 is approximately 1.4449.

(a) To determine the equation y = a + mx of the least square line that best fits the given data points (2,1), (1,1), (3,2), we first need to calculate the mean of x and y, and then calculate the slope m and y-intercept a of the line.

Mean of x: (2 + 1 + 3)/3 = 2

Mean of y: (1 + 1 + 2)/3 = 4/3

To calculate the slope m, we need to find the sum of (xi - x-bar)(yi - y-bar) and the sum of (xi - x-bar)^2 for each data point:

(2-2)(1-4/3) + (1-2)(1-4/3) + (3-2)(2-4/3) = -1/3

(2-2)^2 + (1-2)^2 + (3-2)^2 = 6

So, m = (-1/3) / 6 = -1/18

To calculate the y-intercept a, we can use the formula a = y-bar - m(x-bar):

a = (4/3) - (-1/18)(2) = 5/9

Therefore, the equation of the least square line is y = (5/9) - (1/18)x.

(b) We want to solve the equation ex + x = 7 using Newton's method with an initial guess of Xo = 2.

First, we need to find the derivative of the function f(x) = ex + x:

f'(x) = ex + 1

Then, we can use the formula for Newton's method:

Xn+1 = Xn - f(Xn) / f'(Xn)

Plugging in X0 = 2 and using four significant digits:

X1 = 2 - (e^2 + 2) / (e^2 + 1) = 1.574

X2 = 1.574 - (e^1.574 + 1.574) / (e^1.574 + 1) = 1.4633

X3 = 1.4633 - (e^1.4633 + 1.4633) / (e^1.4633 + 1) = 1.445

X4 = 1.445 - (e^1.445 + 1.445) / (e^1.445 + 1) = 1.4449

Therefore, the solution to the equation ex + x = 7 using Newton's method with an initial guess of Xo = 2 is approximately 1.4449.

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Continuous-compounding is a method of calculating interest where the interest is added to the principal continuously.

instead of being added at regular intervals (such as monthly or annually). This means that the interest is compounded an infinite number of times-over the year, resulting in a higher effective interest rate than other compounding methods.

In this scenario, the person has invested [tex]$479[/tex] in an account that earns an annual interest rate of [tex]8.2%[/tex] compounded continuously. This means that the interest is added to the account balance continuously throughout the year.

The formula for calculating the balance of an account with continuous compounding is:

[tex]V = Pe^(rt)[/tex]

where:

V = the balance after t years

P = the initial investment (or principal)

e = the mathematical constant approximately equal to [tex]2.71828[/tex]

r = the annual interest rate as a decimal

t = the number of years

Using this formula and substituting the given values, we get:

[tex]V = 479e^(0.08212)[/tex]

Simplifying this expression, we get:

[tex]V ≈ $1,204.70[/tex]

Therefore, the person's investment of [tex]$479[/tex] with an annual interest rate of [tex]8.2%[/tex]  compounded continuously, would grow to approximately after 12 years

The formula for calculating the value of the account after t years, with continuous compounding, is:

[tex]V = Pe^(rt)[/tex]

where V is the final value, P is the initial principal, r is the interest rate (expressed as a decimal), and t is the time in years.

Using this formula, we can calculate the value of the account after 12 years:

[tex]V = 479 * 2.6709[/tex]

[tex]V = 1280.74[/tex]

Final answer

Therefore, the amount of money in the account after [tex]12[/tex] years, to the nearest cent, is [tex]$1,280.74.[/tex]

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The complex fourth roots of 3−33i are: [tex]z_0[/tex] = 3.062[tex]e^{(-21.603)}[/tex], [tex]z_1[/tex] = 1.513[tex]e^{(22.247)}[/tex], [tex]z_2[/tex] = 0.3826[tex]e^{(22.247)}[/tex] and [tex]z_3[/tex] = 1.198[tex]e^{(76.247)}[/tex].

To find the complex fourth roots of 3-33i, we can use the polar form of the complex number:

3-33i = 33∠(-86.41)

Then, the nth roots of this complex number are given by:

[tex]z_k[/tex] = [tex]33^{(1/n)}[/tex] × ∠((-86.41 + 360k)/n) for k = 0, 1, 2, ..., n-1

For n = 4, we have:

[tex]z_0[/tex] = [tex]33^{(1/4)}[/tex] × ∠(-86.41/4) ≈ 3.062∠(-21.603°)

[tex]z_1[/tex] = [tex]33^{(1/4)}[/tex] × ∠(88.99/4) ≈ 1.513∠(22.247°)

[tex]z_2[/tex] = [tex]33^{(1/4)}[/tex] × ∠(196.99/4) ≈ 0.3826∠(49.247°)

[tex]z_3[/tex] = [tex]33^{(1/4)}[/tex] × ∠(304.99/4) ≈ 1.198∠(76.247)

So the complex fourth roots of 3-33i are approximate:

[tex]z_0[/tex] = 3.062[tex]e^{(-21.603)}[/tex]

[tex]z_1[/tex] = 1.513[tex]e^{(22.247)}[/tex]

[tex]z_2[/tex] = 0.3826[tex]e^{(22.247)}[/tex]

[tex]z_3[/tex] = 1.198[tex]e^{(76.247)}[/tex]

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When the popularity of grapefruits increases, it leads to a higher demand for them in the market. Consequently, the price of grapefruits rises due to this increased demand. In response to the price increase, several changes occur in the market for grapefruits.

Firstly, as the price of grapefruits increases, the quantity demanded by consumers will likely decrease, as some individuals might be deterred by the higher cost. This is in accordance with the law of demand, which states that as the price of a good increases, the quantity demanded decreases, and vice versa.

Secondly, the higher price of grapefruits may encourage producers to increase their supply to take advantage of the increased revenue potential. As a result, the quantity supplied in the market will likely rise, following the law of supply, which states that as the price of a good increases, the quantity supplied increases, and vice versa.

In the long run, the market will seek to achieve equilibrium, where the quantity demanded equals the quantity supplied. This process will involve adjustments in both supply and demand until a new equilibrium price and quantity are established. The ultimate outcome will depend on the elasticity of both supply and demand for grapefruits, which determine how responsive they are to price changes.

In conclusion, an increase in the popularity of grapefruits resulting in a higher price leads to changes in the market, including decreased quantity demanded, increased quantity supplied, and eventually, a new market equilibrium.

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The condition that must be imposed on k1 and k2 so that 22 6. +2,02 is an unbiased estimator of θ.

To prove that 22 6. +2,02 is an unbiased estimator of the parameter θ, we need to show that its expected value is equal to θ, i.e.,

E(22 6. +2,02) = θ.

Using the linearity of the expected value operator, we have:

E(22 6. +2,02) = E(k1Ô1 + k2Ô2)

= k1E(Ô1) + k2E(Ô2)

Since both Ô1 and Ô2 are unbiased estimators of θ, we have:

E(Ô1) = E(Ô2) = θ

Substituting these values in the above equation, we get:

E(22 6. +2,02) = k1θ + k2θ

= (k1 + k2)θ

For 22 6. +2,02 to be an unbiased estimator of θ, the above expression should be equal to θ. Therefore, we must have:

(k1 + k2) = 1

This implies that the constants k1 and k2 must satisfy the constraint:

k1 + k2 = 1

Hence, this is the condition that must be imposed on k1 and k2 so that 22 6. +2,02 is an unbiased estimator of θ.

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The mean of the sampling distribution of the sample means is equal to the population mean, which is 5.5 inches. The standard deviation of the sampling distribution of the sample means is equal to the population standard deviation divided by the square root of the sample size.

So, for a sample size of 11, the standard deviation of the sampling distribution is:

standard deviation = 1.4 / sqrt(11) = 0.42 inches

To find the probability that the mean length of the 11 items is less than 13.4 inches, we need to standardize this value using the formula:

z = (x - mu) / (sigma / sqrt(n))

where:

x = 13.4 (the mean length we're interested in)

mu = 5.5 (the population mean)

sigma = 1.4 (the population standard deviation)

n = 11 (the sample size)

Substituting the values, we get:

z = (13.4 - 5.5) / (1.4 / sqrt(11)) = 14.31

Using a standard normal distribution table, we can find that the probability of getting a z-score of 14.31 or more is practically zero.

Therefore, the probability that the mean length of the 11 items is less than 13.4 inches is practically 1 or 100%.

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There are 8 successful trials (trials 2, 4, 5, 7, 8, 10, 11, and 12).

The probability that exactly two kittens will be chocolate brown is 1/12.

The probability that at least two kittens will be chocolate brown is 7/12.

Priya can increase the accuracy of the simulation by increasing the number of trials.

We have,

To determine if a trial was a success, we need to count the number of chocolate brown kittens in each trial.

If a trial has at least two chocolate brown kittens, it is considered a success.

Now,

Using the table provided, we can count the number of chocolate brown kittens in each trial:

trial number outcome count of chocolate brown kittens

1 ggggg 0

2 gggwg 1

3 wgwgw 0

4 gwggg 1

5 gggwg 1

6 wwggg 0

7 gwggg 1

8 ggwgw 1

9 wwwgg 0

10 ggggw 2

11 wggwg 1

12 gggwg 1

So,

There are 8 successful trials (trials 2, 4, 5, 7, 8, 10, 11, and 12).

To estimate the probability that exactly two kittens will be chocolate brown, we need to count the number of trials where exactly two chocolate brown kittens were born and divide it by the total number of trials.

From the table, we can see that there is only one trial where exactly two chocolate brown kittens were born (trial 10).

The estimated probability.

=  1/12

= 0.0833.

To estimate the probability that at least two kittens will be chocolate brown, we need to count the number of trials where at least two chocolate brown kittens were born and divide it by the total number of trials.

From the table, we can see that there are 7 successful trials.

The estimated probability.

= 7/12

= 0.5833.

Another question Priya could answer using this simulation is:

Question:

What is the probability that all five kittens will be white?

Answer:

We need to count the number of trials where all five cubes drawn were white (trial 6 and trial 9) and divide it by the total number of trials.

The estimated probability.

= 2/12

= 0.1667.

To increase the accuracy of the simulation, Priya could increase the number of trials conducted.

The more trials conducted, the more accurate the estimated probabilities will be.

Thus,

There are 8 successful trials (trials 2, 4, 5, 7, 8, 10, 11, and 12).

The probability that exactly two kittens will be chocolate brown is 1/12.

The probability that at least two kittens will be chocolate brown is 7/12.

Priya can increase the accuracy of the simulation by increasing the number of trials.

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Answer:

Both are non-linear. The first equation is a rational function and the second is a quadratic.

Step-by-step explanation:

The inequality is 0.15x ≤ 5.00. If copies of a flyer at a store that charges $0.15 per copy, the maximum number of copies you can afford to make is 33.

The inequality that represents the number of copies you can make is:

0.15x ≤ 5.00

Here, x represents the number of copies you can make, and 0.15 is the cost per copy in dollars. The inequality states that the total cost of copies must be less than or equal to the amount of money you have.

To find the maximum number of copies you can afford to make, we need to solve for x:

0.15x ≤ 5.00

x ≤ 5.00/0.15

x ≤ 33.33

Since you cannot make a fraction of a copy, the actual number of copies you can make is 33 or less.

In conclusion, the inequality that represents the number of copies you can make is 0.15x ≤ 5.00, and the maximum number of copies you can afford to make is 33.

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You have $5.00 and you need to make copies of a flyer at a store that charges $0.15 per copy. Find the inequality that represents the number of copies you can make. Use x as the variable. What is the maximum number of copies you can afford to make?

The degree of the polynomial 2 + 2w⁶ + 15y²w + 64u² - uy⁶ is found to be 7 as the term with highest power is 7.

A degree of the polynomial is the highest power to which any of its term is expressed as. For finding the degree we have to find the term with the highest degree in the polynomial. The given polynomial is,

2 + 2w⁶ + 15y²w + 64u² - uy⁶,

The term with the highest degree is uy⁶, which has a degree of 7 (the sum of the exponents of u and y ). Therefore, the degree of the polynomial is 7.

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Complete question - Give the degree of the polynomial. 2 + 2w⁶ + 15y²w + 64u² - uy⁶.

B) Note that in the prompt above, you can use translation to map the line y= 2x -4 onto the line y = 2x + 4.

While you can use axial symmetry in the y -  axis to map the line  y = x onto the line y = -x.

Axial symmetry is symmetry around an axis; an item is axially symmetric if it retains its appearance when rotated around an axis.

A baseball bat with no brand or other design, or a plain white tea saucer, for example, looks the same when rotated by any angle around the line traveling longitudinally through its center, indicating that it is axially symmetric.

A transformation in which the coordinate system's origin is shifted but the orientation of each axis remains constant

So for B) you can use a translation to map the line y = 2x -4 onto the line y = 2x + 4 by shifting the first line 4 units upwards along the y - axis....

mathematically, that would be:

y = 2x - 4 + 4

y = 2x


For C) you can use axial symmetry on the y -  axis to achhieve the mapping of y = x onto y = -x by reflection.

The polar opoppsite of y = x  is y = -x.

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answer

56

explain

because I just don't

Answer: The probability of winning the jackpot is 1/4096, which corresponds to option A

Step-by-step explanation:

To find the probability of winning the jackpot, we need to find the probability of getting a wild symbol on the center line of each of the 4 reels.

Since there are 16 stops on each reel and 2 wild symbols on each reel, the probability of getting a wild symbol on the center line of a single reel is 2/16 or 1/8.

The probability of getting a wild symbol on the center line of all 4 reels is the product of the probabilities for each reel. Thus:

(1/8) * (1/8) * (1/8) * (1/8) = 1/4096