Chemistry College

How do you balance this equation
2h2s+3o2+so2

Answers

Answer 1

The balanced equation is: 4 [tex]H_2S[/tex]+ 3 [tex]O_2[/tex]→ 4 [tex]SO_2[/tex]+ 8 [tex]H_2O[/tex]

The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.

The unbalanced equation is:

2 [tex]H_2S[/tex]+ 3 [tex]O_2[/tex]→ [tex]SO_2[/tex]

Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the [tex]SO_2[/tex]:

2 [tex]H_2S[/tex]+ 3 [tex]O_2[/tex]→ 2 [tex]SO_2[/tex]

Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each [tex]H_2S[/tex]) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:

2 [tex]H_2S[/tex]+ 3 [tex]O_2[/tex]→ 2 [tex]SO_2[/tex]+ 4 [tex]H_2O[/tex]

Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from [tex]O_2[/tex]and 3 from 2 [tex]SO_2[/tex]) and three on the left side (2 from [tex]H_2S[/tex]). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:

2 [tex]H_2S[/tex]+ (3/2) [tex]O_2[/tex]→ 2 [tex]SO_2[/tex]+ 4 [tex]H_2O[/tex]

To remove the fractional coefficient, we can multiply all coefficients by 2:

4 [tex]H_2S[/tex]+ 3 [tex]O_2[/tex]→ 4 [tex]SO_2[/tex]+ 8 [tex]H_2O[/tex]

Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:

4 [tex]H_2S[/tex]+ 3 [tex]O_2[/tex]→ 4 [tex]SO_2[/tex] + 8 [tex]H_2O[/tex]

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