how do you know if two line segments are perpendicular

There is only one solution for the equation 4z + 2(z -4) = 3z + 11 because the exponent for the power of z is 1.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

A solution is any value of a variable that makes the specified equation true.

According to the given information:

4z + 2(z-4)= 3z+11

Solve the equation,

4z+2z-8=3z+11

6z-3z=11+8

3z =19

z=

Hence,

Number of solution that can be found for the equation 4z + 2(z-4)= 3z+11 is option(2) one

To know more about Equations and Solutions visit:

https://brainly.com/question/545403

#SPJ4

Answer:

-8

Step-by-step explanation:

y=(1/3)x

4 = (1/3)12

y=(1/3)(-24)

y= -8

Answer:

OA=95

Step-by-step explanation:

JL = 19Z = OA = 4Z+75

19Z = 4Z+75

19Z-4Z=75

15Z=75

Z=75÷15

Z=5

OA=4(5)+75

OA=95

btw, u stan blackpink? i cant wait for their next comeback "BORN PINK"

The amount of heat (in KJ) released when 3.5 moles of CH₄ react is 3115 KJ

CH₄ + 2O₂ -> CO₂ + 2H₂O ΔH = 890 KJ

From the balanced equation above,

1 mole of CH₄ reacted to release 890 KJ of heat energy.

From the balanced equation above,

1 mole of CH₄ reacted to release 890 KJ of heat energy

Therefore,

3.5 moles of CH₄ will react ro release = 3.5 × 890 = 3115 KJ of heat energy

Thus, 3115 KJ of heat energy were released from the reaction

Learn more about enthalpy change:

https://brainly.com/question/11967318

#SPJ1

Answer:

3x + 16 + 30/x - 13

Step-by-step explanation:

Solving the quadratic equation we conclude that:

The height of the rocket is defined by the quadratic equation:

[tex]d = 90t - 5t^2[/tex]

The maximum height is what we get in the vertex of the quadratic equation, such that for this quadratic equation, the vertex is at:

[tex]t = -90/(2*-5) = 9[/tex]

So the maximum height is what we get when we evaluate in t = 9:

[tex]d = 90*9 - 5*9^2 = 45[/tex]

The maximum height is 45ft.

Now we need to solve the equation for the largest value of t:

[tex]d = 90*t - 5t^2 = 0[/tex]

Rewriting it, we get:

[tex]0 = 90*t - 5*t^2\\\\0 = t*(90 - t*5)[/tex]

The maximum solution is what we get when:

0 = 90 - t*5

t = 90/5 = 18

The rocket is 18 seconds in the air.

If you want to learn more about quadratic equations:

https://brainly.com/question/1214333

#SPJ1

Answer:

44°

Step-by-step explanation:

[tex]\frac{134-46}{2}=44[/tex]

.

Step-by-step explanation:

let's say one integer is X ....

so , Another one is (X -4).....

so , X × (X - 4) = 45

x² - 4x - 45 = 0

x² - 9x + 5x - 45 = 0

x(x - 9) +5(x - 9) = 0

(x-9) × (X+5) = 0

x-9 = 0 OR x+5 = 0

X= 9 X= -5

X is not a negative integer ......

so , X = 9

X-4 = 5 .......

From the two functions function 2 has the highest maximum value.

Given two functions,one is y=-[tex]x^{2} -2x-2[/tex] and f(-2)=1,f(-1)=6,f(0)=9,f(1)=10,f(2)=9,f(3)=6.

We ae required to choose a function which is having highest maximum possible value.

Function is like a relationship between two or more variables expressed in equal to form. Each value of x of a function has some value of y.

The highest value in the second function is 10 which is at x=1. Put the value of x=1 in y=-[tex]x^{2} -2x-2[/tex].

y=-1-2-2

y=-5

So it might not be highest value of this function.So the second function has highest maximum value of 10 at x=1.

Hence the second function has highest value.

Learn more about functions at https://brainly.com/question/10439235

#SPJ1

Answer:

one hour

Step-by-step explanation:

if they are going the same speed going differnet directions they will be 2 miles apart after one hour

Answer:

  68 miles

Step-by-step explanation:

The total distance can be determined from the fractions.

Let d represent the total distance of the race.

The distance running is 1/2d. The distance swimming is 1/4d. The remaining distance is 17 miles.

  Remaining = total distance - distance running - distance swimming

  17 mi = d -1/2d -1/4d = 1/4d . . . . . . . . use known fractions

  68 mi = d . . . . . . . multiply by 4

The total distance of the race is 68 miles.

__

Additional comment

This would be a very difficult race. A typical "iron man" race has a swimming distance under 2.5 miles, less than 1/10 of the distance running. The biking distance is typically about 4 times the running distance of "only" 26 miles. An iron man race can take about 17 hours to complete.

This race has a 17-mile swimming segment, which would take a fast swimmer on the order of 8 hours, by itself. (This is 2.7 times the length of a "marathon" swim.) Here, the running distance is 34 miles, about 30% longer than a marathon.

The average value of the given function is [tex]f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}[/tex].

According to the statement

we have given that the function f(x) and we have to find the average value of that function.

So, For this purpose, we know that the

The given function f(x) is

[tex]f(x) = -x^{2} + 2x +1[/tex]

And now integrate this function with the limit 0 to a then

[tex]f_{avg} = \frac{1}{b - a} \int\limits^a_0 {f(x)} \, dx = -x^{2} + 2x +1[/tex]

Now integrate this then

[tex]f_{avg} = \frac{1}{a} \int\limits^a_0 {-x^{2} + 2x +1} \, dx[/tex]

Then the value becomes according to the integration rules is:

[tex]f_{avg} = \frac{1}{a} \int\limits^a_0 {-\frac{x^{3} }{3} + \frac{2x^{2} }{2} +x} \,[/tex]

Now put the limits then answer will become as output is:

[tex]f_{avg} = \frac{1}{a} [ {-\frac{a^{3} }{3} + \frac{2a^{2} }{2} +a} \,][/tex]

Now solve this equation then

[tex]f_{avg} = [ {-\frac{a^{2} }{3} + \frac{2a }{2} +1} \,][/tex]

Now

[tex]f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}[/tex]

This is the value which represent the average of the given function in the statement.

So, The average value of the given function is [tex]f_{avg} = \frac{-2a^{2} + 6a + 6 }{6}[/tex].

Learn more about integration here

https://brainly.com/question/22008756

#SPJ4

The double reflection generates the following three points: A''(x, y) = (1, - 1), B''(x, y) = (2, 2) and C''(x, y) = (5, 2).

In this problem we must apply two rigid transformations to find three points. The formula for reflection over an axis parallel to the y-axis is defined below:

P'(x, y) = (x', k) - [P(x, y) - (x', k)]     (1)

Where:

If we know that A(x, y) = (1, - 5), k = - 1 and k' =  1, then the resulting points are:

Point A

A'(x, y) = (1, - 1) - [(1, - 5) - (1, - 1)]

A'(x, y) = (1, - 1) - (0, - 4)

A'(x, y) = (1, 3)

A''(x, y) = (1, 1) - [(1, 3) - (1, 1)]

A''(x, y) = (1, 1) - (0, 2)

A''(x, y) = (1, - 1)

Point B

B'(x, y) = (2, - 1) - [(2, - 2) - (2, - 1)]

B'(x, y) = (2, - 1) - (0, - 1)

B'(x, y) = (2, 0)

B''(x, y) = (2, 1) - [(2, 0) - (2, 1)]

B''(x, y) = (2, 1) - (0, - 1)

B''(x, y) = (2, 2)

Point C

C'(x, y) = (5, - 1) - [(5, - 2) - (5, - 1)]

C'(x, y) = (5, - 1) - (0, - 1)

C'(x, y) = (5, 0)

C''(x, y) = (5, 1) - [(5, 0) - (5, 1)]

C''(x, y) = (5, 1) - (0, - 1)

C''(x, y) = (5, 2)

The double reflection generates the following three points: A''(x, y) = (1, - 1), B''(x, y) = (2, 2) and C''(x, y) = (5, 2).

To learn more on rigid transformations: https://brainly.com/question/1761538

#SPJ1

Answer:

B

Step-by-step explanation:

because i said so

The scale factor is 2.875 miles per inch. Then the actual distance from the library to the park will be 2.875 miles.

Dilation is the process of increasing the size of an item without affecting its form. Depending on the scale factor, the object's size can be raised or lowered. There is no effect of dilation on the angle.

Micah drew a map of his neighborhood. The actual distance from his house to the school is 5.75 miles. Then the scale factor is given as,

Scale factor = 5.75 / 2

Scale factor = 2.875 miles per inch

Then the actual distance from the library to the park is given as,

D = 1 x 2.875

D = 2.875 miles

The scale factor is 2.875 miles per inch. Then the actual distance from the library to the park will be 2.875 miles.

More about the dilation link is given below.

https://brainly.com/question/2856466

#SPJ1

The missing diagram is given below.

Answer:

2.875 miles per inch

Step-by-step explanation:

The solutions to the questions are given below

a)

sample(n) word length sample mean

1                    5,4,4,2    3.75

2                    3,2,3,6     3.5

3                         5,6,3,3    4.25

b)R =0.75

c)

The table below shows sample means in the table.

sample(n) word length sample mean

1                    5,4,4,2    3.75

2                    3,2,3,6     3.5

3                         5,6,3,3    4.25

b)

Generally, the equation for is  mathematically given as

variation in the sample means

R =maximum -minimum

R=4.25-3.5

R =0.75

c)

In conclusion, In most cases, the mean of many samples will provide a more accurate estimate than the mean of a single sample.

They may have a higher level of confidence in their estimate if the range of the sample means is closer to 0 than it is now.

Read more about probability

https://brainly.com/question/795909

#SPJ1

The two possible positions of point P are:

(3, -5) and (0.6, 5.8)

We know that point P lies on the line:

y = 4 - 3*x

And that the distance between P and the origin is √34, then if the coordinates of point P are (x, y), we have that:

[tex]\sqrt{34} = \sqrt{x^2 + y^2}[/tex]

Now, we can replace "y" in the distance equation by the linear equation, and also remove the square roots:

[tex]34 = x^2 + (4 - 3x)^2[/tex]

Now we can solve the quadratic equation for x:

[tex]34 = x^2 + 9x^2 + 16 - 24x\\\\10x^2 - 24x - 18 = 0\\\\[/tex]

The solutions are:

[tex]x = \frac{24 \pm \sqrt{(-24)^2 - 4*10*(-18)} }{2*10} \\\\x = \frac{24 \pm36}{20}[/tex]

So the two solutions are:

x = (24 + 36)/20 = 3

x = (24 - 36)/20 = -0.6

To get the points, we need to evaluate y on these values:

y = 4 - 3*3 = -5   So we have P = (3, -5)

y = 4 - 3*(-0.6) = 2.2 So we have the point (0.6, 5.8)

There are the two possible positions of point P.

If you want to learn more about quadratic equations:

https://brainly.com/question/1214333

#SPJ1

The definition of the given piecewise function is:

A piecewise function is a function that has different definitions, depending on the input.

In this problem, for x until 2, the function is the cube function shifted down 3 units, hence the definition is:

[tex]y = x^3  - 3, x \leq 2[/tex]

For x greater than 2, the function is the square function shifted up 6 units, hence the definition is:

[tex]y = x^2 + 6, x > 2[/tex]

More can be learned about piecewise functions at https://brainly.com/question/27262465

#SPJ1

Answer:

a. triangle DEF's lines are all 3 times more than triangle ABC

b. triangle DEF's lines are all 3 times more than triangle ABC

c. 2.5 times 2 = 5

I hope u can elaborate a bit more :)

Answer:

Step-by-step explanation:

X-INTERCEPT

Plug y=0 into the equation and solve the resulting equation −6x=−7 for x.

The x-intercept:

[tex]\left(\frac{7}{6},0\right)\approx \left(1.16666666666667,0\right)[/tex]

Y-INTERCEPT

Plug x=0 into the equation and solve the resulting equation 3y=−7 for y.

The y-intercept:

[tex]\left(0, - \frac{7}{3}\right)\approx \left(0,-2.33333333333333\right)[/tex]

Answer:

[tex]x[/tex]-intercept = ([tex]-\frac{7}{6}[/tex]  , 0)

[tex]y[/tex]-intercept = (0 , [tex]-\frac{7}{3}[/tex])

Step-by-step explanation:

[tex]6x + 3y = -7[/tex]

• The x-intercept is the point at which the line crosses the x-axis, that is, where y = 0.

∴ [tex]6x + 3(0) = -7[/tex]

⇒ [tex]6x = -7[/tex]

⇒ [tex]x = \bf -\frac{7}{6}[/tex]

∴ The x-intercept is at the point ([tex]-\frac{7}{6}[/tex] , 0).

• Similarly, the y-intercept is the point at which the line crosses the y-axis, that is, where x = 0.

∴ [tex]6(0) + 3y = -7[/tex]

⇒ [tex]3y = -7[/tex]

⇒ [tex]y = \bf - \frac{7}{3}[/tex]

∴ The y-intercept is at the point (0 , [tex]-\frac{7}{3}[/tex]).

Answer:   C

Step-by-step explanation: We see that e is 6 for $2.70 and d is 12 for $6.00.  Half of 6 is 3 and 2.70 is less than 3 so the cheapest price can't be d. Then, we have 9 for 3.60. 3.60 divided by 9 is 0.40 per which is cheaper than a (0.42 per) so a and d can't be the cheapest. 3 for 1.38 means 0.46 per which is more expensive than a so it also cannot be b. Now we only have c and e left. We divide 2.70 by 6 and find out that the answer is 0.45 which is also more expensive than a. So, the answer is c.

Answer:

[tex]\Large\boxed{1)~6x+7}[/tex]

[tex]\Large\boxed{2)~-7x+5y+8}[/tex]

Step-by-step explanation:

Given expression

4x + 7 + 2x

Move like terms together

= 4x + 2x + 7

= (4x + 2x) + 7

Combine like terms

[tex]\Large\boxed{=6x+7}[/tex]

Given expression

-4x + 3y - 3x + 8 + 2y

Move like terms together

= -4x - 3x + 3y + 2y + 8

= (-4x - 3x) + (3y + 2y) + 8

Combine like terms

[tex]\Large\boxed{=-7x+5y+8}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

[tex]denote \: by \: s \: the \: cost \: of \: a \: sweatshirt \\ denote \: by \: t \: the \: cost \: of \: a \: t \: shirt[/tex]

[tex]3t + 7s = 240.5 \\ 6t + 5s = 220[/tex]

[tex] - 6t - 14s = - 481 \\ 6t + 5s = 220[/tex]

[tex] - 9s = - 261 \\ s = \frac{ - 261}{ - 9} = 29 \: dollars[/tex]

[tex]3t + 7(29) = 240.5 \\ [/tex]

3t + 203 = 240.5

3t = 37.5

t = 12.5 dollars

Answer:

25

Step-by-step explanation:

Cancel out 19^0, then exponentiate and simplify by multiplying exponents. Then simplify the terms. This leaves you with 2^-16*5^10*5^-8*2^16 which equals 5^2 which is 25

Let [tex]X(s)[/tex] and [tex]Y(s)[/tex] denote the Laplace transforms of [tex]x(t)[/tex] and [tex]y(t)[/tex].

Taking the Laplace transform of both sides of both equations, we have

[tex]\dfrac{dx}{dt} + 3x + \dfrac{dy}{dt} = 1 \implies \left(sX(s) - x(0)\right) + 3X(s) + \left(sY(s) - y(0)\right) = \dfrac1s \\\\ \implies (s+3) X(s) + s Y(s) = \dfrac1s[/tex]

[tex]\dfrac{dx}{dt} - x + \dfrac{dy}{dt} = e^t \implies \left(sX(s) - x(0)\right) - X(s) + \left(sY(s) - y(0)\right) = \dfrac1{s-1} \\\\ \implies (s-1) X(s) + s Y(s) = \dfrac1{s-1}[/tex]

Eliminating [tex]Y(s)[/tex], we get

[tex]\left((s+3) X(s) + s Y(s)\right) - \left((s-1) X(s) + s Y(s)\right) = \dfrac1s - \dfrac1{s-1} \\\\ \implies X(s) = \dfrac14 \left(\dfrac1s - \dfrac1{s-1}\right)[/tex]

Take the inverse transform of both sides to solve for [tex]x(t)[/tex].

[tex]\boxed{x(t) = \dfrac14 (1 - e^t)}[/tex]

Solve for [tex]Y(s)[/tex].

[tex](s - 1) X(s) + s Y(s) = \dfrac1{s-1} \implies -\dfrac1{4s} + s Y(s) = \dfrac1{s-1} \\\\ \implies s Y(s) = \dfrac1{s-1} + \dfrac1{4s} \\\\ \implies Y(s) = \dfrac1{s(s-1)} + \dfrac1{4s^2} \\\\ \implies Y(s) = \dfrac1{s-1} - \dfrac1s + \dfrac1{4s^2}[/tex]

Taking the inverse transform of both sides, we get

[tex]\boxed{y(t) = e^t - 1 + \dfrac14 t}[/tex]

Answer:

300

Step-by-step explanation:

375 divided by 5=75

Each “1”=75

4x75=300

There are 300 boys.

Hope this makes sense

Answer:

300 boys

Step-by-step explanation:

Let the number of boys = x

Girls: 375

boys : girls = 4 : 5

total in the ratio is 9

girls are 5/9 of total, and are 375

boys are 4/9 of total

5/9 x = 375

x = 375 × 9/5

x = 675

Boys are 4/9 of total.

4/9 × 675 = 300

[tex]\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}[/tex]

A linear function is an equation of the form:

[tex]\sf{y=mx+b}[/tex]

▪ [tex]\sf{m= \: slope}[/tex]

▪ [tex] \sf{b= \: y-intercept}[/tex]

First, pick any two pairs of points from the table.

[tex]\small\longrightarrow \sf{(x_1,y_1)(-1.13)}[/tex]

[tex]\small\longrightarrow \sf{(x_2,y_2)=(0,10)}[/tex]

Using these points, find the slope.

[tex]\small\longrightarrow \sf{m= \dfrac{y _{2 } - y_1}{x_2-y_1} }[/tex]

When x=0, y=10, therefore, the y-intercept, b=10.

[tex]\leadsto[/tex] Substitute m=-3 and b=10 into the slope-intercept form given above:

[tex]\small\longrightarrow \sf{m=m = \dfrac{10 - 13 }{0 -( - 1) } = - \dfrac{3}{1} = - 3}[/tex]

▪ [tex]\small\longrightarrow \sf{y= -3x+10}[/tex]

[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]

[tex]\large\boxed{\bm{y= -3x+10}}[/tex]

Answer:

[tex]\displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x=-4 \ln |x|+5 \ln|x-1|+\dfrac{3}{x-1}+\text{C}[/tex]

Step-by-step explanation:

Fundamental Theorem of Calculus

[tex]\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))[/tex]

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given integral:

[tex]\displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x[/tex]

Factor the denominator:

[tex]\begin{aligned}\implies x^3-2x^2+x & = x(x^2-2x+1)\\& = x(x^2-x-x+1)\\& = x(x(x-1)-1(x-1))\\ & = x((x-1)(x-1))\\& = x(x-1)^2\end{aligned}[/tex]

[tex]\implies \displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x=\displaystyle \int \dfrac{x^2-4}{x(x-1)^2}\:\:\text{d}x[/tex]

Take partial fractions of the given fraction by writing out the fraction as an identity:

[tex]\begin{aligned}\dfrac{x^2-4}{x(x-1)^2} & \equiv \dfrac{A}{x}+\dfrac{B}{(x-1)}+\dfrac{C}{(x-1)^2}\\\\ \implies \dfrac{x^2-4}{x(x-1)^2} & \equiv \dfrac{A(x-1)^2}{x(x-1)^2}+\dfrac{Bx(x-1)}{x(x-1)^2}+\dfrac{Cx}{x(x-1)^2}\\\\ \implies x^2-4 & \equiv A(x-1)^2+Bx(x-1)+Cx \end{aligned}[/tex]

Calculate the values of A and C using substitution:

[tex]\textsf{when }x=0 \implies -4=A(1)+B(0)+C(0) \implies A=-4[/tex]

[tex]\textsf{when }x=1 \implies -3=A(0)+B(0)+C(1) \implies C=-3[/tex]

Therefore:

[tex]\begin{aligned}\implies x^2-4 & \equiv -4(x-1)^2+Bx(x-1)-3x\\& \equiv -4(x^2-2x+1)+B(x^2-x)-3x\\& \equiv -4x^2+8x-4+Bx^2-Bx-3x\\& \equiv (B-4)x^2+(5-B)x-4\\\end{aligned}[/tex]

Compare constants to find B:

[tex]\implies 1=B-4 \implies B=5[/tex]

Substitute the found values of A, B and C:

[tex]\implies \displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x=\displaystyle \int -\dfrac{4}{x}+\dfrac{5}{(x-1)}-\dfrac{3}{(x-1)^2}\:\:\text{d}x[/tex]

[tex]\textsf{Apply exponent rule} \quad \dfrac{1}{a^n}=a^{-n}[/tex]

[tex]\implies \displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x=\displaystyle \int -\dfrac{4}{x}+\dfrac{5}{(x-1)}-3(x-1)^{-2}}\:\:\text{d}x[/tex]

[tex]\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int ax^n\:\text{d}x=a \int x^n \:\text{d}x$\end{minipage}}[/tex]

[tex]\boxed{\begin{minipage}{4 cm}\underline{Integrating} $\dfrac{1}{x}$\\\\$\displaystyle \int \dfrac{1}{x}\:\text{d}x=\ln |x|+\text{C}$\end{minipage}}[/tex]

[tex]\boxed{\begin{minipage}{4 cm}\underline{Integrating $ax^n$}\\\\$\displaystyle \int ax^n\:\text{d}x=\dfrac{ax^{n+1}}{n+1}+\text{C}$\end{minipage}}[/tex]

[tex]\begin{aligned}\implies \displaystyle \int \dfrac{x^2-4}{x^3-2x^2+x}\:\:\text{d}x & =\displaystyle \int -\dfrac{4}{x}+\dfrac{5}{(x-1)}-3(x-1)^{-2}}\:\:\text{d}x\\\\& = \displaystyle -4\int \dfrac{1}{x}\:\:\text{d}x+5\int \dfrac{1}{(x-1)}\:\:\text{d}x-3 \int (x-1)^{-2}}\:\:\text{d}x\\\\& = \displaystyle -4 \ln |x|+5 \ln|x-1|-3 \int (x-1)^{-2}}\:\:\text{d}x\end{aligned}[/tex]

Use Integration by Substitution:

[tex]\textsf{Let }u=(x-1) \implies \dfrac{\text{d}u}{\text{d}x}=1 \implies \text{d}x=\text{d}u}[/tex]

Therefore:

[tex]\implies \displaystyle -4 \ln |x|+5 \ln|x-1|-3 \int (x-1)^{-2}}\:\:\text{d}x[/tex]

[tex]\implies \displaystyle -4 \ln |x|+5 \ln|x-1|-3 \int u^{-2}}\:\:\text{d}u[/tex]

[tex]\implies -4 \ln |x|+5 \ln|x-1|-\dfrac{3}{-1}u^{-2+1}+\text{C}[/tex]

[tex]\implies -4 \ln |x|+5 \ln|x-1|+3u^{-1}+\text{C}[/tex]

[tex]\implies -4 \ln |x|+5 \ln|x-1|+\dfrac{3}{u}+\text{C}[/tex]

Substitute back in u = (x - 1):

[tex]\implies -4 \ln |x|+5 \ln|x-1|+\dfrac{3}{x-1}+\text{C}[/tex]

Learn more about integration here:

https://brainly.com/question/27988986

https://brainly.com/question/27805589

Answer:

1441.503 square inches

Step-by-step explanation:

155×60cm=9300square centimeter

9300 divide 6.452 to change to square inches.

Ans=1441.503

Answer:

64.58 sq.in

Step-by-step explanation:

Answer:

4x=90

X=90÷4

X=22.5

5x-27=90

5x=90+27

5x=117

X=117÷5

X=23.4

So 23.4 is a larger angle