How do you think you results would be affected if using K2Cr2O7/H2SO4 as the oxidizing agent instead of KMnO4

Answers

Answer 1

Answer:

Due to weak oxidizing agent.

Explanation:

In my opinion the results would be affected if using K2Cr2O7/H2SO4 as the oxidizing agent instead of KMnO4 because K2Cr2O7/H2SO4 is weak oxidizing agent as compared to KMnO4. An oxidizing agent is a substance that has the ability to oxidize other substances means that accept their electrons so that's why the results of strong oxidizing agent is different than weak oxidizing agent.

Answer 2

The results of the reaction will be affected due to the difference in :

Oxidizing agent strength

The use of  K₂Cr₂O7 / H₂SO₄ which is weaker oxidizing agent in the reaction will produce a different result from the use of KmnO₄ which is a stronger oxidizing agent.

This is because stronger oxidizing agents in reaction readily accept electrons from reactants while weaker oxidizing agents do not readily accept electrons from substances reacting in the reaction.

Therefore we can conclude that The results of the reaction will be affected due to the difference in oxidizing agent strength

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Although your question is incomplete a general solution is provide within the scope of your question


Related Questions

How many liters of hydrogen can be produced at a pressure of 2 atm and a temperature of 298 K?

Answers

Answer: A volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.

Explanation:

Given: Mass of Mg = 2.3 g

Pressure = 2 atm

Temperature = 298 K

The reaction equation is as follows.

[tex]Mg + 2HCl \rightarrow MgCl_{2} + H_{2}[/tex]

This shows that 1 mole of Mg gives 1 mole of [tex]H_{2}[/tex].

Hence, moles of Mg for the given mass is calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{2.3 g}{24.30 g/mol}\\= 0.095 mol[/tex]

Hence, 0.095 moles of Mg will give 0.095 moles of [tex]H_{2}[/tex].

Formula used to calculate volume is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into the above formula as follows.

[tex]PV = nRT\\2 atm \times V = 0.095 mol \times 0.0821 L atm/mol K \times 298 K\\V = \frac{0.095 mol \times 0.0821 L atm/mol K \times 298 K}{2 atm}\\= 1.16 L[/tex]

Thus, we can conclude that a volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.

How many oxygen (O) atoms would a carbon (C) atom need to bond with to form a stable compound?
A.3
B.4
C.1
D.2

Answers

D. 2
good luck! hope this helped
Answer: 2

The first stable compound of these atoms is CO2

determine the number of oxygen in 1.60 moles of sodium hydrogen phosphate

Answers

Answer:

6.40 is the answer to your question

The number of moles of oxygen in 1.60 moles of sodium hydrogen phosphate is 6.4 moles

Let's represent the chemical formula of the compound. The chemical formula of sodium hydrogen phosphate is as follows:

Chemical formula

The chemical formula of a compound is a symbolic expression use to signify the number of atoms present in a molecular substance. Therefore,

sodium hydrogen phosphate  = Na₃PO₄

Therefore,

1 mole of Na₃PO₄ = 4 moles of oxygen

1.60 moles of Na₃PO₄  = ? moles of oxygen

cross multiply

number of moles of oxygen = 1.60 × 4

number of moles of oxygen = 6.4 moles

learn more on moles here: https://brainly.com/question/18395277

A piece of solid tin is submerged in silver nitrate solution. A reaction occurs producing tin (iv) nitrate solution and solid silver. Write the word equation, write the skeletal equation and balanced chemical equation for the reaction.

Answers

Answer: For the given reaction-

The word equation is Tin + silver nitrate = tin (IV) nitrate + silverThe skeletal equation is [tex]Sn + AgNO_{3} \rightarrow N_{4}O_{12}Sn + Ag[/tex]The balanced chemical equation is  [tex]Sn(s) + 4AgNO_{3}(aq) \rightarrow N_{4}O_{12}Sn(aq) + 4Ag(s)[/tex]

Explanation:

When names of chemicals or species involved in a chemical reaction are represented in the form of an equation then it is known as a word equation.

For example, Tin + silver nitrate = tin (IV) nitrate + silver

The 'equal to' symbol denotes a forward arrow.

A skeletal equation contains only the chemical formula of species involved in a chemical reaction.

For example, [tex]Sn + AgNO_{3} \rightarrow N_{4}O_{12}Sn + Ag[/tex]

A chemical equation which contains same number of atoms on both reactant and product side along with states of species is called a balanced chemical equation.

 [tex]Sn(s) + 4AgNO_{3}(aq) \rightarrow N_{4}O_{12}Sn(aq) + 4Ag(s)[/tex]

The carbonyl carbon in a ketone is attacked primarily by the peroxy oxygen bonded to hydrogen as opposed to the peroxy oxygen bonded to carbon because:

Answers

Answer:

This is because peroxy oxygen bonded to hydrogen can easily undergo nucleophilic protonation with the carbonyl carbon to form an alcohol

Explanation:

A ketone is a functional group that contains a carbonyl group (carbon-oxygen double bond ( R1R2-C=O).

The carbonyl carbon doubly bonded to the oxygen is electron deficient as a result of difference in electronegativity between carbon and oxygen, hence is susceptible to nucleophilic attacks

R1R2 - C = O

where R1 and R2 are organic substituents.

The peroxy oxygen that is bonded to hydrogen (H -O-O-R) is the electron-rich centre and easily attacks electron-deficient centres like the carbonyl carbon in ketones to form an alcohol.

The bond between the hydrogen attached to the peroxy oxygen is broken and the resultant hydrogen ion undergoes protonation with the oxygen of the carbonyl group to form an alcohol

R1R2 - C = O + H - O-O - R =>

R1R2- CH - OH + R - O-O-R1

Define fermentation and how alcohol is produced. Describe distillation, the process used in forming " spirits".

Answers

Answer:

Fermentation is where all alcohol is created, distillation is where the alcohol is separated and removed. In order for fermentation to occur, two things are needed: a raw material in liquid form that contains sugar, followed by the addition of yeast.

How many bonds can a carbon atom form?
O A. 1
B. 2
C. 4
O D. 3

Answers

It’s C/4 have a good day

Complete the sentence

The Earth’s earliest atmosphere contained large amounts of carbon dioxide. The percentage of carbon dioxide in the Earth’s atmosphere today is ___

A) Less than 1%
B) 5%
C) 21%
D) 78%

Answers

Answer:

A) Less than 1%

Explanation:

The answer is approximately 0.04%

The maximum number of electrons that can be present in an SHELL is

a) [tex]2 {n}^{2} [/tex]
b) [tex]2 {n}^{2} + 1[/tex]
c) 2n
d) none of these.​

Answers

[tex]\huge\boxed{\fcolorbox{red}{blue}{ QUESTION }}[/tex]

The maximum number of electrons that can be present in an shell is

[tex] \orange{\underline{\huge{\bold{\textit{\green{\bf{OPTIONS}}}}}}} [/tex]

a) [tex]2 {n}^{2} [/tex]

b) [tex]2 {n}^{2} + 1[/tex]

c) 2n

d) none of these.

[tex] \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}[/tex]

OPTION (a)

[tex]2 {n}^{2} [/tex]

[tex] \bold { \red{ \star{ \blue{EXAMPLES}}}}[/tex]

In First shell only 2 electron can be placed .

[tex]2 {n}^{2} \\ n = 1 \: (bez \: \: no \: \: shell \: = 1) \\ so \\ 2 { n}^{2} = 2 \times {1}^{2} = 2 \: electrons[/tex]

In second shell 8 electrons can be placed

[tex]2 {n}^{2} \\ n = 1(bez \: \: no\: \: shell \: = 2) \\ 2 {n}^{2} = 2 \times {2}^{2} = 2 \times 4 = 8 \: electrons[/tex]

Cuál es el cruce para un niño donde su padre tiene el pelo rizo RR y su madre pelo lacio rr

Answers

Answer:

Rr

Explanation:

The electrolysis of water forms H2 and O2. 2H2O Right arrow. 2H2 O2 What is the percent yield of O2 if 10.2 g of O2 is produced from the decomposition of 17.0 g of H2O

Answers

Answer:

67.5%

Explanation:

Step 1: Write the balanced equation for the electrolysis of water

2 H₂O ⇒ 2 H₂ + O₂

Step 2: Calculate the theoretical yield of O₂ from 17.0 g of H₂O

According to the balanced equation, the mass ratio of H₂O to O₂ is 36.04:32.00.

17.0 g H₂O × 32.00 g O₂/36.04 g H₂O = 15.1 g O₂

Step 3: Calculate the percent yield of O₂

Given the experimental yield of O₂ is 10.2 g, we can calculate its percent yield using the following expression.

%yield = (exp yield / theoret yield) × 100%

%yield = (10.2 g / 15.1 g) × 100% = 67.5%

How many moles of sodium carbonate in 18.06x10 to the power 22

Answers

Answer:

[tex] moles = \frac{ number \: of \: particles}{6.02 \times {10}^{23} } [/tex]

=1.806×10^22/6.02×10^23

=0.03 moles

hope this helps :)

Answer 1.354
Explanation none

True or false
The atomic number of an element is always more than the mass number of that elemenT

Answers

False, the mass number can never be smaller than the atomic number

When naming acids such as HCl, HBr, and HI, the prefix "hydro-" is added and the "ine" of the element is replaced with which of the following suffixes before the word "acid" is added?
Select one:
a. "-ic"
b. "-ate"
c. "-ite"
d. "-ide"

Answers

Answer:

a. "-ic"

Explanation:

The correct answer is a. "-ic".

For example:

For HCl, the name is Hydrochloric acid. As you can see, the suffix "-ine" of the element (originally chlorine) is changed to "-ic".

Following the same logic, the name for HBr is Hydrobromic acid; and the name for HI is Hydroiodic acid.

Determine the excluded volume per mole and the volume actually occupied by a mole for a gas consisting of molecules with radius 167 pm. [Note: To obtain the volume in liters, we must express the radius in decimeters (dm).] Enter your answers in scientific notation.

Answers

Answer:

Explanation:

Volume of one mole of a gas = 22.4 litre.

No of molecules in one mole of gas = 6.02 x 10²³ .

Volume of one molecule = 4/3 π R³

= 4/3 x 3.14 x ( 167 x 10⁻¹² m )³

= 19.5 x 10⁶ x 10⁻³⁶ m³

=19.5 x 10⁻³⁰ m³

= 19.5 x 10⁻³⁰ x 10³ litre .

=  19.5 x 10⁻²⁷ litre .

So volume occupied by molecules in one mole of gas

= 19.5 x 10⁻²⁷ x 6.02 x 10²³  litre

117.4 x 10⁻⁴ litre

= .01174 litre.

Excluded volume

= ( 22.4 -  .01174  ) litre .

= 22.388 litre.

I am so lost Helppp! step by step would be great and any links would help!

Answers

Answer: i dont know

Explanation:


(Please Help)

1.What is the most common isotope for element X

2.Calculate the average atomic mass or element X

Answers

Answer:

1. Isotope 2 occurs most commonly

2. 39.02amu

Explanation:

1. Isotope 2 has a relative abundance of 78.68% i.e. 78.68 out of 100, hence, it is the isotope that occurs most commonly.

2. Isotope 1 = 9.67%, mass no: 38

Isotope 2 = 78.68%, mass no: 39

Isotope 3 = 11.34%, mass no: 40

Isotope 4 = 0.31%, mass no: 41

To find the average atomic mass of element X, we multiply each isotopes' relative abundance by its mass no and find the sum as follows:

We convert each percentage to decimal abundance:

Isotope 1 = 9.67% = 0.0967

Isotope 2 = 78.68% = 0.7868

Isotope 3 = 11.34% = 0.1134

Isotope 4 = 0.31% = 0.0031

(0.0967 × 38) + (0.7868 × 39) + (0.1134 × 40) + (0.0031 × 41)

3.6746 + 30.6852 + 4.536 + 0.1271

Average atomic mass = 39.02amu

calculate the final pressure of a gas that is expanded from 725cm³ at 30C and 1.19 atm to 1.12cm³ at 43C​

Answers

Answer:

Final pressure, P2 = 1088.89 atm

Explanation:

Given the following data;

Initial volume, V1 = 725 cm³

Initial temperature, T1 = 30°C

Initial pressure, P1 = 1.19 atm

Final volume, V2 = 1.12 cm³

Final temperature, T2 = 43°C

To find the final pressure (P2), we would use the combined gas law.

Mathematically, the combined gas law is given by the formula;

[tex] \frac {PV}{T} = k [/tex]

[tex] \frac {P_{1}V_{1}}{T_{1}} = \frac {P_{2}V_{2}}{T_{2}} [/tex]

Substituting into the formula, we have;

[tex] \frac {1.19*715}{30} = \frac {P_{2}*1.12}{43} [/tex]

[tex] \frac {850.85}{30} = \frac {P_{2}*1.12}{43} [/tex]

[tex] 28.3617 = \frac {P_{2}*1.12}{43} [/tex]

Cross-multiplying, we have;

[tex] 28.3617 * 43 = 1.12P_{2} [/tex]

[tex] 1219.5531 = 1.12P_{2} [/tex]

[tex] P_{2} = \frac {1219.5531}{1.12} [/tex]

Final pressure, P2 = 1088.89 atm

I am having trouble converting :(

Answers

Answer:

For the first question, to determine the total number of molecules of nitrogen dioxide, first make use of the molar mass of the nonpolar compound and then use that to find the total number of moles and then subsequently after make use of the ratio for the Avogadro's number to determine the total number of molecules of this compound.

For the final question, do the inverse, where we make use of the molecules of the compound and then use Avogadro's number to determine the moles of the compound and then use the same molar mass of the compound to determine the grams of the Nitrogen Dioxide.

some one help please ​

Answers

oxnzle ...............

Answer: oxnzle

Explanation:

 Help ASAP only right answers only no spam don’t answer if you don’t know

















Answers

Answer:

NO. 10.

performed experiments

NO. 11.

Inference

Explanation:

No 10.

in order to prove that Mary Mellon was in fact infected by typhoid proper experiments needs to be carried out.

No. 11

inference means an assumption due to the situation.

Calculate the average atomic mass for element X.
(Please HELP)

Answers

Where is the image can you please attached the image

HELPPPPPPPP i accidentally pressed on c

Answers

Answer:

a

Explanation:

I'm not completely sure tho veary sorry if it's wrong

Answer:

the answer is C

Explanation:

as the yeast feeds on sugar and yields the ATP per glucose molecule and Carbon dioxide

Write a Lewis structure that obeys the octet rule for each molecule or ion. Include resonance structures if necessary and assign formal charges to each atom.

Answers

Answer:

A structure that obeys the octet rule for each molecule or ion is [tex]XeO_4[/tex]  

Explanation:

Here in [tex]XeO_4[/tex]   , Xenon  has  8 valence electrons and each oxygen atom has 6 valence electrons  

Lewis structure for [tex]XeO_4[/tex] is shown below :

Here , all atoms are having their complete octet .

All the atoms in this Lewis structure is having their complete octet .

Resonance structure is not required as all atoms are same that is oxygen .

Calculate the average atomic mass for element X(please help)

Answers

Answer:

Wt Avg At Mass = 39.0229 amu

Explanation:

The Weight Average Atomic Mass in atomic mass units (amu) is the sum of the Weight Average Mass contributions of each isotopic mass. That is,

Wt. Avg. At. Mass (amu) = ∑ Wt. Avg. Contributions of each isotopic mass

Wt. Avg. Contribution = fractional abundance x isotopic mass(amu)

For this problem data:

Isotope   %Abundance     fractional         Isotopic             Wt Avg Isotopic

                                        abundance      mass(amu)        Contribution (amu)

   1                  9.67%           0.0967               38                      3.6746 amu

   2               78.68%           0.7868               39                    30.6852 amu

   3                 11.34%           0.1134                 40                      4.5360 amu

   4                  0.31%           0.0031                41                       0.1271  amu

________________________________________________________

Wt. Avg. Atomic Mass (amu) = ∑ Wt. Avg. Contributions  =  39.0229 amu

please provide is matter about us pure all NCERT questions and answers

Answers

Answer:

I hope that's what u were lookong for :))

Explanation:

which states of matter can flow from one place to another​

Answers

Answer:

Liquid

Explanation:

Quite an easy question!

Answer:

Liquid

Explanation:

I was passing by lol

write a short note on detection of nitrogen in the organic compound​

Answers

ajdhrhahdjdjdndoxhdebdixhxb dbds ebenej


Wood is made mostly of cellulose and has a chemical formula of C.H.00. Which of the following equations
represents the cellulose combustion reaction?

Answers

Answer:

Option B.

C₆H₁₀O₅ + 6O₂ —> 6CO₂ + 5H₂O

Explanation:

To know which option is correct, we shall write the balanced equation for the combustion of cellulose. This is illustrated below:

C₆H₁₀O₅ + O₂ —> CO₂ + H₂O

There are 6 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 6 before CO₂ as shown below:

C₆H₁₀O₅ + O₂ —> 6CO₂ + H₂O

There are 10 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 5 before H₂O as shown below:

C₆H₁₀O₅ + O₂ —> 6CO₂ + 5H₂O

There are a total of 7 atoms of O on the left side and a total of 17 atoms on the right side. It can be balance by writing 6 before O₂ as shown below:

C₆H₁₀O₅ + 6O₂ —> 6CO₂ + 5H₂O

Now, the equation is balanced.

Thus, option B gives the correct answer to the question.

A student determines the calcium content of a solution by first precipitating it as calcium hydroxide, and then decomposing the hydroxide to calcium oxide by heating. How many grams of calcium oxide should the student obtain if his solution contains 55.0 mL of 0.458 M calcium nitrate?

Answers

Answer:

1.41g

Explanation:

all work is shown in the attached image :-)

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