how does a crowbar used to remove the top of a box change the direction of the force?

Quantum mechanics is the study of atoms and incredibly tiny particles that are even smaller.

In quantum mechanics, another branch of physics, atomic and subatomic particles are investigated. The primary field of science that deals with the study of atoms and molecules is chemistry. By utilizing their knowledge of atoms, chemists create molecules that resemble drugs. A distinction is established between atomic physics, which studies the atom as a system made up of a nucleus and electrons, and nuclear physics, which explores nuclear reactions and special properties of atomic nuclei. Three subatomic particles make up matter: protons, neutrons, and electrons. The only subatomic particles that have electrical charges are protons and electrons, with protons having a positive charge and electrons having a negative charge.

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The use of different concentrations of aqueous isopropanol in a step gradient separation is often done to achieve a better separation of molecules or compounds in a sample.

The use of different concentrations of aqueous isopropanol in a step gradient separation is often done to achieve a better separation of molecules or compounds in a sample.

In step gradient separation, a series of solutions with increasing or decreasing concentrations of a solvent is used to separate molecules based on their different affinities for the solvent. By gradually changing the solvent composition, molecules with different properties (such as size, polarity, or charge) can be separated from each other.

In the case of aqueous isopropanol, changing the concentration of isopropanol in the solution can change the polarity of the solvent system. This can be useful for separating molecules that have different polarities, as they will have different affinities for the solvent at different concentrations.

For example, in a mixture of polar and nonpolar compounds, a low concentration of isopropanol may be more effective at eluting the polar compounds, while a higher concentration may be needed to elute the nonpolar compounds. By using a series of solutions with different isopropanol concentrations, a step gradient separation can be achieved that separates the different compounds in the mixture.

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We can use the radioactive decay formula to determine how much of the 24-gram sample of potassium-40 will remain after 3.75 billion years:

[tex]N = N0 * (1/2)^(t/T)[/tex]

where: N0 is the initial amount of the radioactive substance

N is the final amount of the radioactive substance

t is the time that has passed

T is the half-life of the radioactive substance

Plugging in the given values, we get:

[tex]N = 24 g * (1/2)^(3.75)[/tex])billion years / 1.25 billion years)

[tex]N = 24 g * (1/2)^3[/tex]

[tex]N = 24 g * 0.125[/tex]

[tex]N = 3 g[/tex]

Therefore, after 3.75 billion years, only 3 grams of the 24-gram sample of potassium-40 will remain.

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Answer:

To determine the formula of the hydrate, you need to calculate the ratio of water to the salt (CaCl2) in the hydrate. You can do this by dividing the mass of water by the mass of the salt and then determining the simplest whole number ratio that represents this value.

1.081 g H2O / 1.110 g CaCl2 = 0.970

Since the ratio is close to 1:1, we can assume that the formula of the hydrate is CaCl2 * H2O, with one mole of water for every mole of CaCl2. So the formula of the hydrate would be CaCl2.H2O.

Answer:

Explanation:

To determine the formula of a hydrate, we need to calculate the number of moles of calcium chloride and water in the sample, and then use the mole ratios to determine the empirical formula of the hydrate.

First, we'll calculate the number of moles of calcium chloride:

1.110 g CaCl2 / (110.98 g/mol) = 0.01 moles CaCl2

Next, we'll calculate the number of moles of water:

1.081 g H2O / (18.015 g/mol) = 0.06 moles H2O

Now that we have the number of moles of each component, we can determine the mole ratio of calcium chloride to water:

0.01 moles CaCl2 / 0.06 moles H2O = 1/6

This means that for every 6 moles of water, there is 1 mole of calcium chloride. Based on this information, the empirical formula of the hydrate can be written as CaCl2 · 6H2O.

Note that the empirical formula represents the simplest whole-number ratio of atoms in a compound and does not necessarily represent the true molecular formula, which may be a multiple of the empirical formula. To determine the true molecular formula, we would need additional information, such as the molecular weight of the compound.

One of the key features of enzymes is that they are not consumed in chemical reactions and can be used again.

Enzymes are biological catalysts that accelerate chemical reactions by lowering the activation energy required for the reaction to occur. They are typically large, complex proteins that have a specific three-dimensional structure that allows them to interact with specific substrates, or reactants, in a particular chemical reaction.

Enzymes remain unchanged after a reaction, and can be used to catalyze the same reaction many times over. However, enzymes can be affected by changes in pH, temperature, or other environmental factors, which can alter their structure and affect their ability to catalyze reactions.

Enzymes are critical to many biological processes, including metabolism, digestion, and DNA replication. Without enzymes, many of these processes would occur too slowly to sustain life. Scientists have also developed ways to use enzymes in industrial processes, such as the production of biofuels and pharmaceuticals. The ability to use enzymes repeatedly in these applications makes them a valuable tool in the development of sustainable and efficient technologies.

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(b) Water. The liquid is most likely Water.

The density of a liquid can be determined by dividing its mass by its volume. In this case, the mass of the graduated cylinder with liquid is 145 grams and the volume of liquid is 100 ml. Therefore, the density of the liquid is 1.45 g/ml. Water has a density of 1 g/ml, which is closest to the given density of 1.45 g/ml.

The cylinder has a 100 ml capacity.

Moreover, the liquid-filled cylinder weighs 145 g.

The weight of the cylinder when empty is 45 g.

Now,

Fluid mass is 145 - 45 g.

= 100 g

The liquid's density is  

=[tex]\frac{mass of liquid}{volume of liquid}[/tex]

=[tex]\frac{100g}{100ml} =\frac{1g}{1ml}[/tex]

= 1 gm/ml

Knowing that 1 ml equals 1

Density equals 1 g/cc. Therefore, the liquid is most likely water.

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complete question:A graduated cylinder contains 100ml of liquid the mass of the graduated cylinder with the liquid is 145 gram the mass of the graduated cylinder when empty is 45 grams the liquid is most likely

(a) Ethanol

(b) Water

(c) Corn oil

(d) Chloroform​

The correct answer is ATP Synthase uses the energy of a proton gradient to add a phosphate to ADP.

The mitochondrial enzyme ATP synthase, which is found in the inner membrane, transforms ADP and phosphate into ATP. The stream of protons is driven by the movement of electrons from the chemically positive to the negative side of the proton, which creates a gradient.The electron transport chain involves the downhill flow of electrons to the final electron acceptor through a chain of membrane-bound carriers in order to aid the uphill transfer of protons across a proton-impermeable membrane. In order to move protons (ions) via ATP synthase Fo particles and down the concentration gradient, it creates a proton gradient. The proton-motive force, which drives protons to move, provides the energy for ADP phosphorylation (ions).

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When you need to generate aggregate values (such a sum) and then use them in another query, a derived table can be helpful.

A table expression that appears in a query's FROM clause is referred to as a derived table. When using column aliases is not possible because another clause is being processed by the SQL translator before the alias name is available, you can use derived tables instead.

A sort of subquery known as a derived table is enclosed in parenthesis, given a name, and placed in the from clause of an outer select expression. A result set from a select statement is returned by the subquery.

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The law of conservation of mass states that mass cannot be created or destroyed in a chemical reaction, only rearranged. Therefore, the total mass of the reactants must equal the total mass of the products.

Starting with 0 g of calcium (Ca) and 1.9 g of fluorine (F2), we can calculate the total mass of the reactants:

Total mass of reactants = Mass of Ca + Mass of F2

Total mass of reactants = 0 g + 1.9 g

Total mass of reactants = 1.9 g

According to the problem statement, the reaction forms 3.9 g of calcium fluoride (CaF2). Therefore, the total mass of the products is:

Total mass of products = Mass of CaF2

Total mass of products = 3.9 g

Since the total mass of the reactants must equal the total mass of the products, we can set these two expressions equal to each other:

Total mass of reactants = Total mass of products

1.9 g = 3.9 g

This is a contradiction, as it is impossible for the mass of the reactants to be less than the mass of the products. Therefore, there must be an error in the problem statement or the given values.

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The inclination to lose/gain an electron is due to their electron configurations and the resulting stability, sodium tends to lose an electron to become a positively charged ion, while chlorine tends to gain an electron to become a negatively charged ion.

Sodium has an electron configuration of 1s2 2s2 2p6 3s1, meaning it has one valence electron in its outermost shell. It is energetically favorable for sodium to lose this electron and achieve a full valence shell, which would give it the electron configuration of a noble gas (neon), 1s2 2s2 2p6. This stable configuration is achieved by the loss of one electron, which forms a positively charged ion with a full outer shell.

On the other hand, chlorine has an electron configuration of 1s2 2s2 2p6 3s2 3p5, meaning it has seven valence electrons in its outermost shell. It is energetically favorable for chlorine to gain one electron to achieve a full valence shell, which would give it the electron configuration of a noble gas (argon), 1s2 2s2 2p6 3s2 3p6. This stable configuration is achieved by the gain of one electron, which forms a negatively charged ion with a full outer shell.

ThereforeThis process of electron transfer allows both atoms to achieve a stable electron configuration and become more energetically stable.

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The electronic configuration can be used to know the details of atom.

The question is incomplete so I will educate you generally about electronic configuration.

The electronic configuration of an atom refers to the arrangement of electrons in its energy levels or orbitals.

The electrons in an atom occupy specific energy levels, with the innermost energy level having the lowest energy and being occupied by the most electrons. Each energy level can contain a certain number of electrons, and electrons occupy the lowest energy level available to them.

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The correct IUPAC name for the molecule is option c) 4,6,7-tetramethylnonane.

To name the molecule, we start by identifying the longest continuous carbon chain, which in this case contains nine carbon atoms. We number the chain from the end that gives the substituents the lowest possible numbers, which gives us the numbering 1-2-3-4-5-6-7-8-9.

The molecule has three branches: a propyl group on carbon 5, an ethyl group on carbon 2, and a methyl group on carbon 3. We name these branches as substituents and indicate their positions with their respective numbers. Therefore the correct IUPAC name for the molecule is 4,6,7-tetramethylnonane.

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Gluconeogenesis...

[tex] \: \: \: [/tex]

Answer:

Gluconeogenesis is the answer...

Yes, interstitial fluid is included in the extracellular fluid.

Extracellular fluid refers to all the fluid that is outside of cells and includes both interstitial fluid and plasma. Interstitial fluid is the fluid that surrounds individual cells and fills the spaces between tissues. Plasma, on the other hand, is the fluid component of the blood that carries nutrients, hormones, waste products, and other substances throughout the body.

Together, interstitial fluid and plasma make up the extracellular fluid compartment, which is important for maintaining fluid balance and supporting the exchange of substances between cells and their environment. The extracellular fluid compartment is constantly in flux, with fluid moving in and out of it as needed to maintain homeostasis.

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The atomic radius of magnesium is approximately 1.736 Å. This can be calculated using the formula: Atomic Radius = (a / 2) * sqrt(3), where a is the lattice parameter for the hcp crystal structure.

To calculate the atomic radius of magnesium, we can use the following formula:

Density = (2 * Atomic Mass) / [(a²) * (c / a) * Na]

where:

Density is the density of magnesium
Atomic Mass is the atomic mass of magnesium
a is the lattice parameter for the hcp crystal structure
c/a is the ratio of the height of the unit cell to the base length of the unit cell
Na is Avogadro's number
We can rearrange this formula to solve for the atomic radius:

Atomic Radius = (a / 2) * sqrt(3)

where:

a is the lattice parameter for the hcp crystal structure
Now, let's plug in the values given in the problem:

Density = 1.74 g/cm3
c/a = 1.624
Na = 6.022 x 10²³ molecules/mol

The atomic mass of magnesium is 24.305 g/mol.

To find the lattice parameter, we can use the fact that the volume of the unit cell is given by:

Volume = a² * (c / a) * sqrt(3) / 2

The density is also related to the volume and the atomic mass by:

Density = Atomic Mass / Volume

We can combine these two equations and solve for a:

a = (4 * Atomic Mass / (sqrt(3) * Density * c))⁽¹/³⁾

Plugging in the values:

a = (4 * 24.305 g/mol / (sqrt(3) * 1.74 g/cm^3 * 1.624))⁽¹/³⁾
a = 3.209 Å

Now we can calculate the atomic radius:

Atomic Radius = (a / 2) * sqrt(3)

Atomic Radius = (3.209 Å / 2) * sqrt(3)

Atomic Radius = 1.736 Å (rounded to three significant figures)

Therefore, the atomic radius of magnesium is approximately 1.736 Å.

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Sigma bonds are formed by the end-on overlap of orbitals. A sigma bond ([tex]\sigma[/tex] bond) is a type of bond formed by the overlapping of orbitals in an end-to-end fashion.

There are two types of bonding. They are:

A pi bond ([tex]\pi[/tex] bond) is a type of bond formed by the overlapping of the orbitals in a side-by-side fashion. One pi bond and one sigma bond are present in an alkene. Two pi bonds and one sigma bond can be found in alkynes.

Both the structure and the reactivity are greatly impacted by this. The head-on intersection of two sp orbitals results in the formation of the sigma bond. The side-on overlapping of 2p orbitals results in the formation of pi bonds.

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The two rings that have approximately the same bond angle in their favored conformations are cyclopropane and cyclopropane. The rings that sacrifice bond angle to relieve torsional strain are cyclopropane and cyclobutane.

Bond angle strain is a type of steric interaction.

A cyclic ring is a closed chain of atoms, typically carbon, that forms a loop or ring structure. Cyclic rings are commonly found in organic molecules, and the properties and behavior of cyclic rings can vary depending on their size, shape, and composition.

Cyclic rings can be classified based on the number of atoms in the ring, with three-membered rings known as cyclopropanes, four-membered rings known as cyclobutanes, five-membered rings known as cyclopentanes, six-membered rings known as cyclohexanes, and so on. The stability and reactivity of cyclic rings can also be affected by the presence of functional groups and the stereochemistry of the ring.

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Clever is the characteristic that a  scientific experiment must have to be valid. Therefore, the correct option is option A.

An experiment, in its most basic form, is just the testing of a theory. In turn, a hypothesis is a suggested relationship or explanation for a phenomenon.

The experiment is the cornerstone of the scientific method, that is a methodical approach to learning about the world around you. Although some experiments are conducted in laboratories, an experiment can be conducted anywhere, at any time. Clever is the characteristic that a  scientific experiment must have to be valid.

Therefore, the correct option is option A.

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To prepare 100 mL of a 0.200 M acetate buffer, pH 5.00, you will need acetic acid, 3M HCl, 3 M NaOH, and a pH meter.

1. Calculate the amounts of acetic acid and sodium acetate needed to make the buffer.

To prepare 0.200 M acetate buffer, you will need 0.2 moles of acetic acid and 0.2 moles of sodium acetate.

Moles of acetic acid = 0.2 moles

Moles of sodium acetate = 0.2 moles

2. Calculate the volume of acetic acid and sodium acetate needed to make the buffer.

Volume of acetic acid = [tex]0.2 moles *(17.30 mL/mole) = 3.46 mL[/tex]

Volume of sodium acetate =[tex]0.2 moles * (22.06 mL/mole) = 4.41 mL[/tex]

3. Calculate the amount of HCl and NaOH needed to adjust the pH to 5.00.

First, the pKa of acetic acid needs to be calculated.

pKa of acetic acid = 4.76

Now, the amount of HCl and NaOH needed to adjust the pH of the buffer can be calculated using the Henderson-Hasselbalch equation.

Henderson-Hasselbalch equation:

pH =[tex]pKa + log\frac{[base]}{[acid]}[/tex]

Rearranging the equation to calculate [base],

[base] =[tex][acid] * 10^{(pH - pKa) }[/tex]

[NaOH] =[tex][HCl] * 10^{(pH - pKa) }[/tex]

[HCl] =[tex][NaOH] * 10^{(pKa - pH) }[/tex]

[HCl] =[tex]0.2 M * 10^{(4.76 - 5.00) }[/tex]

[HCl] = [tex]0.162 M[/tex]

[NaOH] =[tex]0.2 M* 10^{(5.00 - 4.76) }[/tex]

[NaOH] = [tex]0.238 M[/tex]

4. Calculate the volume of HCl and NaOH needed to adjust the pH to 5.00.

Volume of HCl = [tex]0.162 M * (17.30 mL/mole) = 2.79 mL[/tex]

Volume of NaOH = [tex]0.238 M *(22.06 mL/mole) = 5.25 mL[/tex]

5. Prepare the buffer.

To prepare the buffer, add 3.46 mL of acetic acid, 4.41 mL of sodium acetate, 2.79 mL of HCl, and 5.25 mL of NaOH to a volumetric flask, and make up to 100 mL with distilled water.

6. Measure the pH of the buffer and adjust as necessary.

Using a pH meter, measure the pH of the buffer and adjust with additional HCl or NaOH as necessary to reach a pH of 5.00.

Once the desired pH is reached, the buffer is ready to use.

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complete question:How do you prepare 100 mL of 0.200 M acetate buffer, pH 5.00, starting with pure liquid acetic acid and solutions containing 3 M HCl and 3 M NaOH furthermore 15 points?

Electrons that are in the outermost energy level of an atom are referred to as "valence electrons."

Valence electrons are the electrons that are involved in chemical reactions and bonding, and they play a crucial role in determining the chemical properties of an element.

In general, the number of valence electrons in an atom is related to the position of the element in the periodic table. Elements in the same group (vertical column) have the same number of valence electrons, and this number increases as you move from left to right across a period (horizontal row). The arrangement of valence electrons is important for understanding chemical reactivity, because it determines the way in which atoms bond with each other to form molecules.

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The functional groups which is shown above is most likely to gain a proton and become positively charged is The amino group.

The introductory nature of any functional group depends on the chances of the functional group getting protons associated with it. This means that the hydrogens ions in the system are associated with the introductory functional group. This way the functional groups can be charged. The association of hydrogen directly determines the acidic or introductory character of the functional group that remains associated with specific biomolecules.

The amino group is one of several nitrogen- containing functional groups set up in organic motes. What distinguishes the amino group is that the nitrogen snippet is connected by single bonds to either hydrogen or carbon.

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Answer:

Explanation:

In the case of NaCl

Formula units, also known as formula mass, are the simplest repeating unit in a chemical compound. For a salt like sodium chloride (NaCl), one formula unit would be one Na+ ion and one Cl- ion.

For sodium chloride, the formula mass is the sum of the atomic masses of the individual atoms in the formula unit, which is approximately 58.44 g/mol.

In the case of NaCl, 24 g would be equivalent to approximately 0.41 moles. Since one formula unit of NaCl weighs 58.44 g, then 0.41 moles of NaCl would be equal to approximately 0.41 moles * 6.022 x 10^23 formula units = 2.47 x 10^23 formula units.

Therefore, 24 g of NaCl would be equal to approximately 2.47 x 10^23 formula units.

The reason why volumetric flasks are used instead of beakers or graduated cylinders is that Volumetric flasks are calibrated to contain a precise volume of liquid at a particular temperature, making them more accurate than graduated cylinders.

Beakers and graduated cylinders are not as accurate or precise and are more suitable for approximate measurements. Additionally, volumetric flasks are designed to minimize evaporation and reduce errors due to meniscus formation, which can affect the accuracy of the final concentration of the standard solution. Therefore, volumetric flasks are the preferred choice for preparing standard solutions from solids.

Accuracy: Volumetric flasks are designed to deliver a precise volume of liquid at a specific temperature, making them more accurate than graduated cylinders.

Precision: Volumetric flasks are designed to minimize evaporation and errors due to meniscus formation, resulting in higher precision than graduated cylinders.

Consistency: Volumetric flasks deliver a consistent volume of liquid every time, while the volume of liquid delivered by graduated cylinders can vary depending on the user's technique.

Ease of use: Volumetric flasks are easy to use, with a simple and straightforward procedure for filling and measuring the liquid. Graduated cylinders require more technique and practice to use accurately.

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The attractive force between water molecules that results from hydrogen bonding is called hydrogen bonding.

Hydrogen bonding is a type of intermolecular force that arises when hydrogen atoms are covalently bonded to atoms of high electronegativity, such as oxygen, nitrogen, and fluorine. These hydrogen bonds form strong attractions between the molecules, giving water its high surface tension and other unique properties. These hydrogen bonds form strong attractions between the molecules, giving water its unique properties such as high surface tension, high boiling point, and low vapor pressure. Hydrogen bonding is responsible for the stability of many biological molecules such as DNA and proteins, and for the increased solubility of many compounds in water.

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The statement "all liquid and precipitate waste will be placed in a glass bottle waste container in the fume hood. However, Cu and Mg waste will be placed in the solid waste container" is generally true and reflects standard practices in laboratory waste disposal.

In the laboratory, it is important to properly dispose of any waste generated during experiments in order to minimize environmental impact and ensure safety. Liquid and precipitate waste is typically collected in glass bottles, which are more suitable for containing such materials and can be more easily recycled. Glass is also more chemically resistant and less likely to react with the waste materials compared to plastic containers. Furthermore, waste containers should be placed in the fume hood to prevent exposure to any harmful fumes and to minimize any risk of explosion or fire.

On the other hand, solid waste containers are typically used for the disposal of any solid waste materials generated during experiments, such as Cu and Mg waste. Copper (Cu) and magnesium (Mg) are metals that are often used in laboratory experiments and can produce solid waste materials. These solid waste materials can be safely disposed of in a solid waste container, which can be emptied and disposed of as general waste.

It is important to note that laboratory waste disposal practices may vary depending on the specific institution or laboratory. Some laboratories may have their own specific guidelines for waste disposal that should be followed. Additionally, some materials may require special handling or disposal procedures, such as hazardous or radioactive waste. In such cases, additional precautions may be necessary to ensure proper disposal and minimize potential risks to health and the environment.

In conclusion, proper disposal of laboratory waste is essential to maintain a safe and sustainable working environment. Collecting liquid and precipitate waste in glass bottles in the fume hood and solid waste in a designated container, such as Cu and Mg waste, are standard practices in laboratory waste disposal. Laboratories should establish clear guidelines for waste disposal and ensure that all personnel are trained and follow proper waste disposal procedures to ensure safety and environmental responsibility.

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A. The empirical formula of the compound is [tex]C_{3} H_{6} O[/tex].

B. The molecular formula of ethyl butyrate [tex]C_{6} H_{12} O_{2}[/tex]

The empirical formula of a chemical compound is defined as the  simplest whole number ratio of atoms present in a compound. The molecular formula shows the exact number of atoms of each element making up the compound. It may be similar to the molecular formula of the compound. In the combustion of 2.78 mg of ethyl butyrate produces 6.32 mg CO2 and 2.58 mg H2O. In the one millimole of carbon dioxide, there is 1 millimole of carbon. So, in 44.01 mg of carbon dioxide there is 12.01 mg of carbon. Likewise there is 2 mole of hydrogen in every mole of water. So, in 18.02 mg of water there is 2.02 mg of hydrogen since the molar mass of hydrogen is 1.01 mg/mole. The molecular formula of the compound can be written as C6H12O2.

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In reference to the given data concerning the separation of the mixture, the percent by mass of salt in the mixture is 73.9%.

To find the percent by mass of salt in the mixture, we need to divide the mass of salt by the total mass of the mixture and multiply by 100.

First, we need to calculate the mass of sand in the mixture:

Mass of sand = Total mass of mixture - Mass of salt

Mass of sand = 2.18 g - 1.61 g = 0.57 g

Now we can calculate the percent by mass of salt in the mixture:

Percent by mass of salt = (Mass of salt / Total mass of mixture) x 100%

Percent by mass of salt = (1.61 g / 2.18 g) x 100%

The percent by mass of salt = 73.9%

Therefore, the percent by mass of salt in the mixture is 73.9%.

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Balanced equation of the following are:Solid aluminium is put with aqueous magnesium nitrate:

Mg(NO3)2(aq) + Al(s) → Mg(s) + Al(NO3)3(aq)

2. Aqueous potassium sulphate is combined with aqueous barium hydroxide:

Ba(OH)2(aq) + K2SO4(aq) → BaSO4(s) + 2KOH(aq)

3. Solid barium oxide is heated:

BaO(s) → BaO2(s) + O2(g)

4 When calcium is added to nitrogen gas, a reaction occurs in which the calcium metal reacts with the nitrogen gas to form calcium nitride (Ca3N2). Solid calcium is added to nitrogen gas

Ca(s) + N₂(g) → Ca3N2(s)

5.  Solid lithium reacts with oxygen gas:

Li(s) + O2(g) → Li2O(s)

6.Balanced equation of Aqueous zinc chloride is added to solid sodium:ZnCl2(aq) + Na(s) → Zn(s) + 2NaCl(aq)

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The bar graph below shows the organic compounds found in an egg. The y-axis displays the amount of each organic compound in percentage, while the x-axis displays the type of organic compound.

Organic compounds are compounds composed of carbon, hydrogen, and other elements such as oxygen, nitrogen, sulfur, phosphorus, and other elements. Carbon and hydrogen are the two most abundant elements in organic compounds, making up about 90% of the compounds. Organic compounds can be divided into two categories, natural and synthetic. Natural organic compounds are those that are produced in or derived from living organisms, such as carbohydrates, proteins, and lipids. Synthetic organic compounds are those that are made by humans, such as plastics, dyes, and medicines.

The bar graph shows that the most abundant organic compound in an egg is water, making up approximately 75% of the egg's total mass. This is followed by proteins at approximately 13%, fat at approximately 11%, carbohydrates at approximately 1%, and other organic compounds making up approximately 0.2%.

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The density of the NH₃ sample is 0,82 gram/liter. The formula that can be used to calculate the density of a sample of NH₃ is D = [tex]\frac{M.P}{R.T}[/tex].

Density is the mass unit volume of a material substance. To find the density of NH₃ you can use the following steps:

Step 1: Convert temperature to kelvin and convert temperature to atm.

R = -9° C = (273,15  - 9 ) = 264,15 K

P = 793mmHg × 1/760 mmHg/atm = 1,043 atm

Step 2: Make a formula for calculating density with the ideal gas rules.

Ideal gas law ⇒ P × V = n × R × T

Density ⇒ D = mass ÷ V

P × V = n × R × T

P × V = [tex]\frac{mass . R . T}{M}[/tex]

P × M =  [tex]\frac{mass . R . T}{V}[/tex] ................. enter the formula to find the density

P × M = D × R × T

D × R × T = P × M

D  = [tex]\frac{M.P}{R.T}[/tex]

Step 3: Substitute the known data into the formula

D = [tex]\frac{M.P}{R.T}[/tex]

D = [tex]\frac{17,034 g/mol x 1,043 atm}{0,0821 Latm/mol.K x 264,15 K}[/tex]

D = 0,82 gram/liter

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