Ionization energy regularly fluctuates over a population, rising and falling with time. Effective nuclear charge rises with time, whereas electron shielding stays constant.
This ionization energy rule is what?
Ionization energy exhibits periodicity on the periodic table. The typical tendency for electron affinity would be upward from left to right during the duration of an element period. During a period, the atomic radius moves from left to right, increasing the pull of electrons toward the (near) nucleus.
Why does the energy of ionization rise?
The very first ionization energy normally moves across a period of the periodic table from left to right. The outermost electron as well as the nucleus have a stronger connection as a result of the higher nuclear charge.
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When converted to inches of mercury the air pressure reading of 1,017 millibars at letter c is equal to?
the nuclear mass of 141ba is 140.883 amu. calculate the binding energy per nucleon for 141ba.
The binding energy per nucleon for the atom, 141-Ba is 8.326 MeV per nucleon.
What is nuclear binding energy?Nuclear binding energy is the minimum energy required to separate the nucleus of an atom into its constituent protons and neutrons.
The protons and neutrons in the nucleus of an atom are collectively called nucleons.
The binding energy per nucleon for the atom, 141-Ba is given below:
The atom, 141-Ba has 56 protons and 85 neutrons.
The total mass of the 141-Ba nucleus is obtained from;
(56 * 1.007277) + (85 * 1.008665)
The total mass of the Li nucleus = 142.144 amu
The actual mass of 141-Ba = 140.883 amu
Mass defect = (142.144 - 140.883) amu
Mass defect = 1.261 amu
The total binding energy per nucleon in MeV is calculated as follows;
Total binding energy = 1.261 amu × 931 MeV
Total binding energy = 1173.991 MeV
The binding energy per nucleon in MeV per nucleon = 1173.991 MeV/141
The binding energy per nucleon in MeV per nucleon = 8.326 MeV per nucleon
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calculate the number of grams of aluminum required to prepare 125.0 g of chromium metal by the first reaction.
The number of grams of aluminum required to prepare 125.0 g of chromium metal by the first reaction is approximately 32.4 g.
To calculate the number of grams of aluminum required to prepare 125.0 g of chromium metal, you need to balance the chemical equation for the reaction between aluminum and chromium oxide to determine the stoichiometry of the reaction.
Here is the balanced chemical equation for the reaction:
Al + Cr2O3 -> 2 Cr + Al2O3
From the balanced equation, we can see that for every mole of aluminum that reacts, 2 moles of chromium are produced. We can use the molar masses of aluminum and chromium to determine the mass of aluminum required to produce a given mass of chromium.
The molar mass of aluminum is 26.98 g/mol, and the molar mass of chromium is 52.00 g/mol. Using these values, we can calculate the mass of aluminum required to produce 125.0 g of chromium as follows:
125.0 g Cr / 52.00 g/mol = 2.40 moles Cr
2.40 moles Cr * (1 mole Al / 2 moles Cr) = 1.20 moles Al
1.20 moles Al * 26.98 g/mol = 32.4 g Al
Therefore, the number of grams of aluminum required to prepare 125.0 g of chromium metal by the first reaction is approximately 32.4 g.
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what are the percentage dissociations of h (g), o (g),and i (g) at 2000 k and a total pressure of 1 bar?
The percentage dissociation of H₂ is 0.0814%.
The percentage dissociation of O₂ is 0.0335%.
The percentage dissociation of I₂ is 94.6%.
The balanced chemical equation:
H₂(g)⇄2H(g)
ΔG0=2(106,760 J/mol)
-RT lnK=2*106,760 J/mol
-(8.3145 J/K/mol)(200 K) ln K=2*106,760 J/mol
Solving for K,
K=2.65*10^-6
On calculation, the percentage dissociation of H₂ is 0.0814%.
The balanced chemical equation:
O₂(g)⇄2O(g)
ΔG0=2(121552 J/mol)
-RT lnK=2*121552 J/mol
-(8.3145 J/K/mol)(200 K) ln K=2*121552 J/mol
Solving for K,
K=4.48*10^-7
On calculation, the percentage dissociation of O₂ is 0.0335%.
The balanced chemical equation:
I₂(g)⇄2I(g)
ΔG0=2(-29410 J/mol)
-RT lnK=2*-29410 J/mol
-(8.3145 J/K/mol)(200 K) ln K=2*(-29410) J/mol
Solving for K,
K=34.37
On calculation, the percentage dissociation of I₂ is 94.6%.
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Classify the compounds as acids, bases, or salts. Acid Base Salt 2 HF HF Ca(OH)2 | NH4Cl NaF CaCl2 H2C204 RbOH H2SO3
We know that,
Acid is a compound, molecule or the entity that can donate a proton or accept an electron pair in reactions.
Base is a compound, molecule or the entity that can donate an electron pair in reactions.
In water, base solution is slippery to the touch, tastes bitter, changes the color of indicators.
Salts are chemical compounds that are consisting of an ionic assembly of positively charged cations and negatively charged anions.
Salts are produced by the reaction of an acid with a base and the reaction between an acid and a base is called a neutralization reaction.
HF is a acid
[tex]Ca(OH)_{2}[/tex] is a base
[tex]NH_{4}Cl[/tex] is a salt
NaF is a base
[tex]CaCl_{2}[/tex] is a salt
[tex]H_{2} C_{2} O_{4}[/tex], oxalic acid is an acid
RbOH is a base
[tex]H_{2} SO_{3}[/tex] is an acid
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4. Antibiotics are effective on
____________________________________cells.
This means they would not work on which two
infections from question #1?
________________________________________
and ____________________________________.
(use the photo for question one)
Antibiotics are effective on bacterial cells. This means they would not work on which two infections from question 1? Common cold and influenza ("flu").
Why won't it be effective on those infections?Antibiotics are a type of medication that will fight bacterial infections by killing the bacteria and preventing their growth. It will then affect living microorganisms.
It will then not be effective in viral infections since viruses are not living beings, which will not do anything to them and what will generate is that in the individual who is taking the antibiotics, the bacteria generate antibiotic resistance making it more difficult to eradicate them when it is generated by a bacterial infection.
Therefore, we can confirm that in a common cold and influenza the use of antibiotics is not going to be effective because they are caused by viral agents that will not be eradicated.
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if the reaction begins with 95.00 grams of cr2o3 and 183.0 grams of silicon, how many grams of the excess reactant will be used?
The limiting reactant is the one that is used up first and sets a limit on the quantity of product(s) that can be produced. Calculate the moles of each reactant present and contrast this ratio with the mole ratio of the reactants in the balanced chemical equation to determine the limiting reactant.
When a chemical reaction is complete, the limiting reagent—also known as the limiting reactant or limiting agent—is the reactant that has been completely consumed. Since the reaction cannot proceed without this reagent, the amount of product that can be produced is constrained. Excess reagents or excess reactants are any reagents that are present in amounts greater than those necessary to cause a reaction with the limiting reagent (sometimes abbreviated as "xs"). Since the amount of product produced when the limiting reagent interacts entirely is defined as the theoretical yield, the limiting reagent must be identified in order to calculate the percentage yield of a reaction. There are various equivalent techniques to determine the limiting reagent and assess the excess amounts of other reagents given the balanced chemical equation that describes the reaction.
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color in a unit cell of this two-dimensional lattice:
The color in a unit cell of a two-dimensional lattice is determined by the arrangement of atoms within the lattice structure. A unit cell is the smallest repeating unit within the lattice, and it contains all of the atoms within the lattice.
The atoms are arranged in a regular pattern, which can be described as a crystal lattice.The color in a unit cell is determined by the type of bonds that exist between the atoms in the lattice. Different types of bonds will produce different colors. For example, ionic bonds are strong and result in a bright, vivid color, while covalent bonds are weaker and produce a more muted color. Metals, on the other hand, have metallic bonds, which produce a metallic sheen.
The color of a unit cell can also be affected by the properties of the atoms themselves. For example, if the atoms have a large difference in electronegativity, the unit cell may appear to have a strong color contrast. Additionally, the color can vary depending on the angle at which it is viewed.In summary, the color in a unit cell of a two-dimensional lattice is determined by the type of bonds that exist between the atoms, as well as the properties of the atoms themselves. These factors will determine the overall appearance of the unit cell.
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7. During titration, a stopcock is used to O clamp and secure the titrator O measure exactly 5 mL of titrant O release one drop at a time from the titrator O add NaOH to the titrator 8. The volume of titrant used during a titration will always be the exact same throughout three trials. O True O False 9. The concentration of acetic acid in vinegar is represented by the units O mL/mol O mol/L O mL O mol
The answers include the following;
During titration, a stopcock is used to release one drop at a time from the titrator.The volume of titrant used during a titration will always be the exact same throughout three trials is referred to as a false statement.The concentration of acetic acid in vinegar is represented by the units is mL.What is Titration?This is referred to as a technique done in the laboratory where a solution of known concentration is used to determine the concentration of an unknown solution.
It involves the use of a burette, pipette etc in whic the stopcock is used to release one drop at a time from the titrator for an accurate result.
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what volume of carbon dioxide, measured at 25 °c and 741 torr, can be obtained by the reaction of 50.0 g of caco3 with 750 ml of 2.00m hcl solution? CaCO3(s) + HCL(aq) => CaCl2(aq) + CO2(g) + H2O (unbalanced)
a. 11.2 L
b. 12.5 L
c. 18.8 L
d. 9.4 L
e. 6.25 L
The volume of the carbon dioxide that is produced in the reaction is 12.5 L. Option B
What is the volume of carbon dioxide?We know that a chemical reaction is said to occur when there is a combination of one or more reactants. We have to first obtain the limiting reactant in this case.
Number of moles of calcium carbonate = 50.0 g/100 g/mol
= 0.5 moles
Number of moles of HCl = 750/1000 * 2 = 1.5 moles
If 1 moles of carbonate reacts with 2 moles of HCl
0.5 moles of carbonate reacts with 0.5 moles * 2 moles/1
= 1 mole
The limiting reactant is the carbonate
If 2 moles of carbonate produces 1 moles of carbon dioxide
0.5 moles of carbonate produces 0.5 * 1/2
= 0.5 moles of carbon dioxide
Using PV =nRT
P = pressure
V = volume
n = Number of moles
R = gas constant
T = temperature
V = nRT/P
V = 0.5 * 0.082 * 298/0.975
V = 12.5 L
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4. Consider the following data: Metal Mass (9 Cu Specilic Heat_Wg % Temperature, 0,900 0.285 these two metals are placed in contact, which of the following will take place? Heat will flow from Al to Cu because Al has Heat will flow larger from specific heat. Cu to Al because Cu has Heat will flow from Cu Io larger heat capacity cause Cu is at a higher temperature. Heat will flow from Cu lo Al because Cu has No heat will Ilow In elther larger mass, direction Calculate the amount of heat liberated "C lo 11.8*C The specific heat (In kJ) from 262 of Cu Is 0.385 Jl 9 %C of copper when cools from 87.0oC to 11,8oC. The specific heat of Cu is 0.365 J/g oC
The heat will flow from copper to aluminum because Cu is at higher temperature. The heat liberated is -7.60kJ
When two metals at different temperatures are kept in contact, heat flows from hotter metal to colder metal until thermal equilibrium is reached.
Here Copper is at a temperature of 60 degree Celsius and aluminum is at 40 degree Celsius. Thus, heat will flow from Cu to Al.
In order to calculate the amount of heat liberated following calculations are required.
m1=262 g
T1=87 oC
Cp=0.385 J/g oC
T2=11.8 oC
The heat liberated can be expressed as follows:
Q=mCp(T2-T1)
Q=262 g*0.385 J/goC(11.8-87)oC
Q=-7585 J
=-7.60kJ
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at the end of glycolysis, in what molecule(s) can one find the energy that was contained in the chemical bonds of glucose? select all that apply.
At the end of glycolysis, one can find the energy that was contained in the chemical bonds of glucose in ATP, NADH and pyruvate molecule.
The process of glycolysis takes place in the cytosol of a cell. It can be broken down into two phases viz. energy requiring phase and energy releasing phase.
Energy requiring phase: The starting molecule i.e glucose is at first rearranged and two phosphate groups are attatched to it, which comes from ATP. The phosphate groups form the sugar- fructose-1,6-biphosphate. This splits into three-carbon sugars
Energy releasing phase: The three carbon-sugars are converted into three-carbon molecules i.e two ATP molecules and one NADH molecule and pyruvate.
Thus, in ATP, NADH and pyruvate we can find the energy contained in chemical bonds of glucose.
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How many lone pairs are in the Lewis structure of hydrazine H2NNH2 ? 4 12 : 8
a molecular geometry with triangular pyramids.The presence of two lone pair of electrons and an electrostatic number of four further indicate the tetrahedral electronic structure of the hydrazine molecule.
In N2H2, how so many lone pair are there?Atoms of nitrogen form a single connection with hydrogen and a double bind with one another.In this molecule, there are two pairs od lone electrons and four pairs with bonding electrons.
Is there a lone pair in NH2NH2?While N2 lacks lone pairs of electrons, NH3 and NH2NH2 do.C.Every nitrogen in NH2NH2 has an oxidation number of +2.
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classify each statement about electromagnetic radiation as true or false.
Classification of each statement about electromagnetic radiation:
True statement:
(2) The product of the frequency and wavelength of electromagnetic radiation is constant.
(3) The light from the sun includes multiple types of electromagnetic radiation.
(4) X-ray radiation has shorter wavelengths than microwave radiation.
False statement:
(1) Visible light has a lower frequency than infrared radiation.
(5) X-ray radiation has more energy than gamma radiation.
(6) The speed of electromagnetic radiation varies with frequency
What is electromagnetic radiation?Waves-based radiation that has an electric and magnetic field. It derives from both natural and artificial sources. From low energy to high energy, electromagnetic radiation can have different intensities. It consists of x-rays, gamma rays, infrared, visible, and ultraviolet light as well as radio waves and microwaves.
Radio waves, microwaves, infrared, ultraviolet, gamma, and x-rays are all types of EM radiation. Cosmological sources (such as the sun and stars), radioactive substances, and man-made gadgets are some examples of sources of EM radiation. The dual wave and particle character of EM are evident.
True Statements:
The product of the frequency and wavelength of electromagnetic radiation is constant and equal to speed of light.The light from the sun includes multiple types of electromagnetic radiation which are radio waves, micro waves, infrared waves, visible light, x rays and gamma rays.X-ray radiation has shorter wavelength than microwave radiation.False Statements:
Visible light has lower frequency than infrared radiation.The speed of electromagnetic radiation varies with frequency.X-ray radiation has more energy than gamma radiation.To know more about electromagnetic radiation refer to:
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The complete question is as follows:
Classify each statement about electromagnetic radiation as true or false: Visible light has a lower frequency than infrared radiation The product of the frequency and wavelength of electromagnetic radiation is constant, The light from the sun includes multiple types of electromagnetic radiation X-ray radiation has shorter wavelengths than microwave radiation, X-ray radiation has more energy than gamma radiation The speed of electromagnetic radiation varies with frequency
Question 22 19 . Give the formula for magnesium hydrogen sulfate A) MgHSO3 b, B) Mg2( HSO4)2 C) MgzHSO3 d, D) Mg(HSO412 E) MgSO4
b.Mg2( HSO4)2 .Magnesium hydrogensulfate [Mg(HSO4)2], as a heterogeneous solid acid catalyst, has been used for the mild formation of trimethylsilyl (TMS).
Mg(HSO4)2 from various primary, secondary, and tertiary aliphatic alcohols; aromatic alcohols; and oximes using hexamethyldisilazane (HMDS) under ambient conditions. Hexamethyldisilazane (HMDS) has been utilized as a heterogeneous solid acid catalyst to moderately produce trimethylsilyl (TMS) ethers from a variety of primary, secondary, and tertiary aliphatic alcohols, aromatic alcohols, and oximes under ambient conditions. Additionally, under solvent-free conditions and with short reaction durations and high to exceptional yields, 14-aryl-14H-dibenzoxanthenes and 1,8-dioxo-octahydroxanthene derivatives were produced in the presence of Mg(HSO4)2. The balanced chemical equation is therefore Mg (s) Magnesium + H 2 SO 4 (aq) Sulphuric acid MgSO 4 for the reaction of magnesium solid with sulfuric acid to produce hydrogen gas and magnesium sulfate ( aq ) Hydrogen (g) with magnesium sulfate.
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When the friction slider was increased to about ¼, the skater completed ___ loops before failing?
When the friction slider was increased to about ¼, the skater completed less loops before failing?
What is friction?We can define the friction that is acting on the object as the kind of force that is acting on an object so as to reduce the speed of the object. As such, we can see that we have a situation whereby we have an object that is in motion.
If an object is in motion, we know that the force that tries to slow down the object is the force of the friction that is acting on the object that is in question. The skater is also under the action of the force of friction and this is the force that is attempting to slow the skater down as described above.
The loops would decrease when the friction is increased as such the skater can not be able to do as much loops as before.
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Draw the Lewis Structure for TeO3 and determine the electron domain geometry. Draw the Lewis Structure for TeO3 and determine the number of lone pair(s) on the central atom. Draw the Lewis Structure for TeO3 and determine the name of the molecular geometry. Draw the Lewis Structure for TeO3 and predict the polarity. Draw the Lewis Structure for TeO3 and predict the predominant intermolecular force. Draw the Lewis Structure for TeO3 and determine the hybridization on Te.
The Lewis Structure for TeO3 is attached in the image given below, and the electron domain geometry is Tetrahedral.
Lewis structures, often referred to as Lewis dot formulas, Lewis dot structures, electron dot structures, or Lewis electron dot structures (LEDS), are diagrams that depict the interactions of atoms inside molecules as well as any lone pairs of electrons that may be present. Any molecule with a covalent link, as well as coordination compounds, can have a Lewis structure. Gilbert N. Lewis, who first described it in his 1916 article The Atom and the Molecule, gave the Lewis structure its name. Lewis structures add lines between atoms to represent shared pairs in a chemical bond, extending the idea of the electron dot diagram. Each atom's position within a molecule is indicated by its chemical symbol in Lewis structures. Lines divide atoms that are linked together. Pairs of dots are displayed next to the atoms to represent the additional electrons that form lone pairs. While main group elements of the second period and beyond frequently respond by gaining, shedding, or sharing electrons until they have attained a valence shell electron configuration with a full octet of (8) electrons, hydrogen (H) can only form bonds that share two electrons.
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when you change the number of __ you change the element: (5 points) electrons neutrons protons
That element transforms because when atomic number has been modified. The three fundamental types of components that comprise an atom are proton, neutrons, and nuclei.
What does an atomic number mean?The number of neutrons corresponds to the quantity more protons in the nucleus of the atom. No mater how many neutrons are present, an element's identity is determined by its number of protons; for example, an element with six atoms is a carbon atom. The count of protons in the nucleus is the atomic number.
Why does atomic number matter more?The electron count in an element is indicated by the atomic number. The majority of an element's chemical properties are determined by the electrons in their valency shell, which is their outer energy shell.
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Answer:
c. protons
Explanation:
got it right on the flexpoint test
29) The molecular geometry of the PF4+ ion is octahedral B) tetrahedral trigonal pyramidal D) trigonal planar E) trigonal bipyramidal '
The lewis structure shape of PF4+ is tetrahedral with the positive charge on phosphorus atom.
A Lewis Structure is a greatly condensed illustration of a molecule's valence shell electrons. It is used to display how the electrons are positioned around particular molecules' atoms. When two atoms are bonded together, electrons are depicted as "dots" or as a line. The tetrahedral that describes how atoms share electrons so that each atom has eight electrons in its outer shell. This idea is the foundation of a Lewis structure. An oxygen atom, as an illustration, has six electrons in its outer shell. The removal of one electron from its valence shell causes it to become positively charged. tetrahedral has four covalent connections, the central phosphorus atom is joined to four fluorine atoms. Therefore, Lewis Structure if we examine the phosphorous There are five valence electrons in phosphorus. It has four bonds at this place. There is no electron lone pair on the phosphorus atom in the PH+4 ion. It has a tetrahedral structure with a 10928′ bond angle. PH4+ assumes tetrahedral geometry with a bond angle of 109° 28' since there is no lone pair-bond pair repulsion and there are four identical bond pair-bond pair interactions.
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What is the formula for copper (II) nitrite? CuzNz Cu(NOz)2 Cuz(NO3h2 Cuz(NO2)2
CuN2O4 | Copper Nitrite | PubChem CuNO2 | Copper Nitrite | ChemSpider Please contact your local healthcare facility or the World Health Organization for medical information on Covid-19.
Copper (II) Nitrate's chemical name is Cu
2. Similar to that, this anhydrous salt's structure is made up of 2 anions, NO3-, and 1 cation, Cu2+. The substance manifests up to 5 distinct hydrate forms. Cu is trihydrated as Cu(NO3)2, and it is pentahydrated as Cu. 2.
The reaction you were provided explains the thermal breakdown of copper(II) nitrate, Cu
2 . Decomposition reactions often have one reactant and several products, which makes them easy to spot.
An oxidation process occurs when copper reacts with oxygen to generate copper oxide.
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enter your answer in the provided box. use the following information to calculate the δh o lattice of mgf2:
Since magnesium ions have a charge that is two times greater than that of lithium and sodium ions, MgF2 has a higher lattice energy than LiF and NaCl. As ion charge rises, lattice energy rises as well.
What is mgf2?An inorganic substance with the chemical formula MgF2 is magnesium fluoride. The substance is transparent over a wide spectrum of wavelengths and is a white crystalline salt with industrial uses in optics and space telescopes. Ionic compounds, which are formed of a cation and an anion, include magnesium fluoride as an example.
What is MgF2 used for?The hydrogen Lyman-alpha line (121 nm) and beyond are well-transmitted by magnesium fluoride in the VUV range. Magnesium fluoride is ideal for Excimer laser applications and is mostly employed in UV optics.
Fluorine is an electronegative element, whereas magnesium is an electropositive element. Magnesium fluoride is the result of the reaction between these two, which produces an ionic product.
Briefing:Lattice energy: MgF2(s) → Mg2+(g) + 2 F– (g)
Use Hess’s law: ∆Hº
Mg(s) → Mg(g) 148 kJ
F2(g) → 2F(g) 159 kJ
Mg(g) → Mg+ (g) + e– 738 kJ
Mg+(g) → Mg2+(g) + e – 1450 kJ
2F(g) + 2e–→ 2F– (g) 2(–328) = – 656 kJ
MgF2(s) → Mg(s) + F2 (g) 1123 kJ (Reaction is reversed and the sign of ∆Hº changed.)
MgF2(s) → Mg2+(g) + 2F– (g) 2962 kJ
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how many coulombs of positive charge are contained in the atomic nuclei of this gas?
The total positive charge in the nucleus of any gas is the total number of protons times the total charge contained by one proton. The total number of protons depends on the type of gas, for example, hydrogen, oxygen, chlorine, etc. Each gas has a different number of protons in its nuclei.
To calculate the total positive charge in the atomic nuclei of any gas, find the total number of atoms in the gas. It can be calculated by multiplying Avogadro’s Number with the total amount of gas in moles. If the gas is available in molecules like , then it needs to be multiplied by 2 to calculate the correct number of atoms in the gas. The total number of protons needs to be calculated, which can be done by multiplying the atomic number of gas with the total number of atoms calculated before. Now we can calculate the charge by multiplying the charge on one proton by the total number of protons. A body that has more protons than electrons is said to have a positive charge. We are aware that electrons are negatively charged and protons are positively charged. Consequently, positively charged objects have more protons than electrons.
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Balance the following redox reaction under acidic aqueous conditions using the smallest whole-number coefficients possible. On which side does H (aq) appear, and what is its coefficient? 79. MnO4(aq)+(aą) 1(aq) +Mn2 (aq) a. left, 16 b. right, 16 c. left, 8 d. right, 8 e. right, 4
H+ appear on left hand side and the coefficient is 16 in the balanced redox reaction under acidic aqueous conditions.
What is redox reaction?
Redox reactions, also referred to as oxidation-reduction processes, are reactions in which electrons are transferred from one species to another. An oxidized species is one that has lost electrons, whereas a reduced species has gained electrons.
The balanced redox reaction under acidic aqueous conditions using the smallest whole-number coefficients is written as
[tex]2MnO+16H^{+} +10I^{-}[/tex] → [tex]2Mn2^{+} + 8H_{2} O + 5I^{2}[/tex]
Therefore, the H+ is present on left side with a coefficient of 16 in the balanced redox reaction under acidic aqueous conditions.
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Draw a Lewis structure for the urea molecule, CO(NH2)2CO(NH2)2. Draw the Lewis dot structure for urea. Include all lone pairs of electrons. SubmitPrevious Answers Part B Predict its geometric shape around C atom with the VSEPR theory. Predict its geometric shape around atom with the VSEPR theory. tetrahedral trigonal pyramidal bent trigonal planar SubmitRequest Answer Part C Predict its geometric shape around N atom with the VSEPR theory. Predict its geometric shape around atom with the VSEPR theory. tetrahedral trigonal pyramidal bent trigonal planar
Part B- The geometric shape is trigonal planar and hybridization is sp2. Part C- The geometric shape is tetrahedral and hybridization is sp3.
A Lewis Structure is a completely simplified illustration of the valence shell electrons in a molecule. It is used to expose how the electrons are organized round character atoms in a molecule. Electrons are proven as "dots" or for bonding electrons as a line among the 2 atoms.
The Lewis structure of urea is attached in the image given below.
The carbon atom surrounded by three regions of electron density. Therefore, it is trigonal planar.
The electron pair geometry is sp2 hybridization.
The nitrogen atoms are surrounded by four regions of electron density. Thus, it is arranged in a tetrahedral geometry. and the hybridization is sp3.
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consider the chlorite anion. what is the central atom? enter its chemical symbol. how many lone pairs are around the central atom? what is the ideal angle between the chlorine-oxygen bonds? compared to the ideal angle, you would expect the actual angle between the chlorine-oxygen bonds to be ...
The actual angle between chlorine-oxygen bonds may differ slightly from the ideal angle due to various factors such as electron-electron repulsion and bond length
The central atom of the chlorite anion (ClO2^-) is chlorine and its chemical symbol is Cl.
There are two lone pairs of electrons around the central chlorine atom. The ideal angle between the chlorine-oxygen bond of the chlorite anion is about 120 degrees.
This is because the molecular structure of the chlorite ion is curved, with a chlorine atom bonded to two oxygen atoms. The actual angle between chlorine-oxygen bonds may differ slightly from the ideal angle due to various factors such as electron-electron repulsion and bond length. However, it is generally expected that the actual angles between chlorine-oxygen bonds are close to the ideal angles.
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stable atoms have ____ paid of valence electrons
Answer: 8 electrons
Explanation:
Answer: 8 valence electrons
Explanation: This is because the maximum electron an energy level can hold is 8 making it a stable atom
Name each compound. (Refer to the nomenclature flowchart found in the Key Concepts section of the Chapter in Review.) a. B2Cl2 b. BaCl2 c. CrCl3
According to the rules of nomenclature,
B2Cl2 - DiBoron Dichloride
BaCl2 - BariumChloride
Crcl3 - ChromiumChloride
What are rules of Nomenclature?Write the name for both elements.Change the ending of the second element to ide.Place prefixes in front of each element based on the number of atoms present.The prefix 'mono' is only used on the second non-metal in the chemical formula.There shouldn't be two vowels in a row. For example, when you have 'mono' in front of 'oxide' it is written 'monoxide', not 'monoxide'.According to the rules of nomenclature,
B2Cl2 - DiBoron Dichloride
BaCl2 - BariumChloride
Crcl3 - ChromiumChloride
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g what is the equilibrium constant at 298 k for the spontaneous reaction that occurs when a cu2 1cu half-cell is connected to a ag iag half-cell? 0.34 0.80
The standard electrode potential of the connected cell is 0.46. Thus, the equilibrium constant for the spontaneous redox reaction is 1.0.
What is electrode potential?The standard electrode potential of an electrochemical cell is the potential difference occurred between two electrodes. The redox reaction involving oxidation of one species and reduction of another species is taking place at corresponding standard electrode potential of each metal electrodes.
Here, copper metal undergoes oxidation at an electrode potential of 0.34 V and silver metal reduces at 0.80 V. The standard electrode potential of the cell is:
E⁰ cell = E⁰ cathode - E⁰ anode
= 0.80 - 0.34 = 0.46 V.
The relation between E⁰ cell and equilibrium constant K is written as follows:
E⁰ cell = - RT ln K.
thus, at 298 K the equilibrium constant is calculated as follows:
K = ln⁻¹ (0.46 V/ (8.315 × 298 K))
= 1.0
Therefore, the equilibrium constant for the redox reaction is 1.
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Draw the Lewis dot structure for the cyanide ion (CN-) and identify the hybridization state of the carbon and nitrogen atoms. Also identify the sigma and pi bonds present in the structure and any non-bonding electrons in the molecule.
1) The Lewis dot structure of the cyanide ion (CN-) is as follows:
Cyanide ion (CN-):
C: N:
2) Electron configuration:
C: [He] 2s2 2p2
N: [He] 2s2 2p3
The hybridization state of the carbon and nitrogen atoms in the cyanide ion is sp.
3) In the cyanide ion, the sigma bonds are the single bonds between the carbon and nitrogen atoms, and the pi bonds are the double bonds between the carbon and nitrogen atoms. There are no non-bonding electrons in the molecule.
The cyanide ion has a total of 10 valence electrons, which are used to form bonds between the carbon and nitrogen atoms. The carbon atom forms a single bond with the nitrogen atom by sharing one of its 2p electrons, and the nitrogen atom forms a triple bond with the carbon atom by sharing three of its 2p electrons. This results in a linear molecule with a carbon atom bonded to a nitrogen atom, with both atoms having a single bond and a double bond.
The hybridization state of the carbon and nitrogen atoms in the cyanide ion is sp. This is because the carbon atom has two unpaired electrons in its 2p orbitals, and the nitrogen atom has three unpaired electrons in its 2p orbitals. These unpaired electrons form sigma bonds with each other, resulting in an sp hybridization state.
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How many molecules are in 0.400 moles of N2O5?
Answer:2.41 molecules
Explanation:
Answer:
2.41 molecules.
Explanation:
0.400 mol N2O5 contains 2.41 molecules N2O5.
1mole N2O5=6.022 × 1023molecules N2O5.
