Answer:
Step-by-step ex-plane
The zeros of a polynomial function can be used to determine how the graph behaves at those points. The multiplicity of a zero also plays an important role in shaping the graph of a polynomial function.
The graph of the seventh degree polynomial function with zeros 1, 2 (multiplicity of 3), 4, and 6 (multiplicity of 2) will cross the x-axis at 1 only. This is because the zero at 1 has a multiplicity of 1.
The graph will only touch (be tangent to) the x-axis at 2. This is because the zero at 2 has a multiplicity of 3.
At the zero of 2, the graph of the function will flatten out against the x-axis.
Therefore, the correct answers are:
- The graph of the function will cross through the x-axis at 1 only.
- The graph will only touch (be tangent to) the x-axis at 2.
- At the zero of 2, the graph of the function will flatten out against the x-axis.
Which describes the correct order of steps to construct an angle bisector of ZJKL using only a straightedge and compass?
Answer:
First you draw the lines zjkl and then you make an archs to bisect the line using a compass and a pencil first you go to each point and it's corresponding letter you arch then draw a straight line which passes through the arch
Probability of dice and frequency
Probabilities are:
Even number = 0.5
Odd Number = 0.5
Number 1 face up = 1/6
Number 2 face up = 1/6
Number 3 face up = 1/6
Number 4 face up = 1/6
Number 5 face up = 1/6
Number 6 face up = 1/6
Is x-6 a factor of f(x)? Use the Factor Theorem.
f(x)=x^4-32x²-144
Yes
No
By evaluating f(6) and confirming that it equals zero, we can determine that x - 6 is a factor of the polynomial f(x) = x^4 - 32x^2 - 144.
To determine if x - 6 is a factor of f(x) = x^4 - 32x^2 - 144 using the Factor Theorem, we need to check if f(6) equals zero. If f(6) is zero, then x - 6 is a factor of f(x); otherwise, it is not a factor.
Let's calculate f(6):
f(6) = (6)^4 - 32(6)^2 - 144
= 1296 - 32(36) - 144
= 1296 - 1152 - 144
= 0
Since f(6) equals zero, we can conclude that x - 6 is indeed a factor of f(x).
The Factor Theorem states that if f(c) equals zero, where c is a constant, then x - c is a factor of f(x). In this case, since f(6) is zero, x - 6 is a factor of f(x).
Therefore, the answer is: Yes, x - 6 is a factor of f(x).
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find a and b find a and b find a and b find a and b find a and b find a and b find a and b find a and b find a and b vfind a and b
Answer
a=93
b=74
Step-by-step explanation:
a=180-87=93 b=180-106=74
In x=5. Solve for the equation c
Answer:
What is the equation?
Step-by-step explanation:
Can't solve it without knowing where c is in the equation
Mrs.Li's classroom is 34 feet wide and 42 feet long.
How much area is taken up by the objects in the classroom? How much area is left for the student's desks? Write and solve equations to find the area.
Mrs.Li's desk is 8 sq ft, Fish tank 6 sq ft, Math Center 100 sq ft, Reading Center 120 sq ft
PLEASE HELP THIS IS REALLY IMPORTANT
Answer:
1428
Step-by-step explanation:
Area=L×B/W
34×42
=1428
Find the area of the shaded portion in the equilateral triangle with sides 6. Show all work for full credit.
(Hint: Assume that the central point of each arc is its corresponding vertex.)
The area of the shaded portion in the equilateral triangle with sides 6 is 9√3 - 36π.
To find the area of the shaded portion in the equilateral triangle, we need to determine the area of the three arcs and subtract it from the area of the equilateral triangle.
First, let's find the area of one arc. Each arc has a radius equal to the length of the side of the equilateral triangle, which is 6. The formula for the area of a sector is A = (θ/360)πr², where θ is the central angle in degrees.
In an equilateral triangle, each interior angle measures 60 degrees, so the central angle of the arc is 120 degrees (360 degrees divided by 3). Plugging these values into the formula, we get A_arc = (120/360)π(6)² = (1/3)π(6)² = 12π.
Since there are three identical arcs, the total area of the arcs is 3 times the area of one arc, which is 3(12π) = 36π.
Now, let's find the area of the equilateral triangle. The formula for the area of an equilateral triangle is A_triangle = (√3/4)s², where s is the length of a side.
Plugging in the value of the side length, we have A_triangle = (√3/4)(6)² = (√3/4)(36) = 9√3.
Finally, we subtract the area of the arcs from the area of the equilateral triangle to find the shaded portion's area: A_shaded = A_triangle - A_arc = 9√3 - 36π.
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You have found a store that is unique. All the shirts sell for a set price and all the pants are also priced the same in the entire store! You have purchased 3 shirts and 2 pants for $104.81 and your friend has purchased 2 shirts and one pant for $61.33. Set up and solve a system of linear equations. How much is one shirt?
Answer:
Step-by-step explanation:
Let x be 1 shirt price
Let y be 1 pant price
we have the following equation
3x+2y = 104.81$ (1)
2x+y = 61.33$ => multiply two sides by 2 => 4x + 2y = 122.66 (2)
=> (2) - (1) => x = 17.85$
So one shirt is 17.85$
12 is at most a number decrease by 7 write an inequality to solve.
Thank you
Answer:
Let x be the number we are looking for.
We know that 12 is at most a number decreased by 7, which can be written as:
x - 7 >= 12
To solve for x, we add 7 to both sides of the inequality:
x - 7 + 7 >= 12 + 7
Simplifying, we get:
x >= 19
Therefore, the solution to the inequality is x >= 19.
The answer is:
19 ≤ wWork/explanation:
Let w be the number. Now, let's write an inequality to solve for w.
Let's focus on the part that says "at most a number". At most means that the number can't be greater than something, it can only be less than. So the symbol for "at most" is ≤, which also means "less than".
Now, decreased by 7 means we subtract 7 from w.
With all this information, we are ready to write the inequality.
The inequality is:
[tex]\sf{12\leqslant w-7}[/tex]
Now, let's solve it for w.
_________________________
Add 7 on each side
[tex]\sf{12+7\leqslant w}[/tex]
[tex]\sf{19\leqslant w}[/tex]
Hence, the answer is 19 ≤ w.. A plastic marker buoy floating on the sea consisting of a cone attached to a hemispherica base is shown above. The radius of the hemispherical base is 0.95cm and height of the cone is 1.2m. Calculate the volume of the buoy.
Answer:
The volume of the buoy can be calculated by finding the volumes of the cone and hemisphere separately and then adding them together.
The volume of the cone is given by:
Vcone = (1/3)πr^2h
where r is the radius of the base of the cone and h is the height of the cone.
Substituting the given values, we get:
Vcone = (1/3)π(0.95)^2(1.2) = 1.08 m^3 (rounded to two decimal places)
The volume of the hemisphere is given by:
Vhemisphere = (2/3)πr^3
where r is the radius of the hemisphere.
Substituting the given value, we get:
Vhemisphere = (2/3)π(0.95)^3 = 1.05 × 10^-3 m^3 (rounded to two decimal places)
Therefore, the total volume of the buoy is:
Vbuoy = Vcone + Vhemisphere = 1.08 + 1.05 × 10^-3 = 1.08 m^3 (rounded to two decimal places)
Which is the standard equation of the parabola in the graph?
Graph of parabola opening to the right with vertex at 0 comma 4, focus at 4 comma 4, p equals 4, vertical dotted line going through negative 4 on x axis is labeled directrix, and horizontal dotted line going through 4 on y axis is labeled axis
x2 = 16(y – 4)
x2 = –16(y + 4)
(y – 4)2 = 16x
(y + 4)2 = –16x
The correct equation for the parabola is [tex]x^2 = 16(y - 4)[/tex].
The standard equation of the parabola in the graph can be determined based on its characteristics.
Given:
Vertex: (0, 4)
Focus: (4, 4)
P (the distance from the vertex to the focus or directrix): 4
We can conclude that the parabola opens to the right because the axis is horizontal.
The standard equation of a parabola with a horizontal axis and vertex (h, k) is given by:
[tex](x - h)^2 = 4p(y - k)[/tex]
In this case, the vertex is (0, 4), so the equation becomes:
[tex](x - 0)^2 = 4p(y - 4)[/tex]
Now, we need to determine the value of p. The distance from the vertex to the focus is p, which is 4 in this case.
Therefore, the standard equation of the parabola in the graph is:
[tex]x^2 = 4(4)(y - 4)\\x^2 = 16(y - 4)[/tex]
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The improper integral [tex]\int\limits^1_0 {arctan \sqrt{x/(1-x)} } \, dx[/tex] =
The value of the improper integral ∫[0 to 1] arctan(√(x/(1-x))) dx is π/4.
To evaluate the improper integral
∫[0 to 1] arctan(√(x/(1-x))) dx,
we can use a trigonometric substitution. Let's substitute x = sin²θ, which gives dx = 2sinθcosθ dθ and modifies the limits of integration as well.
When x = 0, sin²θ = 0, and when x = 1, sin²θ = 1. Therefore, the new limits of integration are θ = 0 to θ = π/2.
Now, let's substitute these expressions into the integral:
∫[0 to 1] arctan(√(x/(1-x))) dx
= ∫[0 to π/2] arctan(√(sin²θ/(1-sin²θ))) * 2sinθcosθ dθ
= 2∫[0 to π/2] arctan(√(sin²θ/cos²θ)) * sinθcosθ dθ.
Simplifying inside the arctan, we have:
√(sin²θ/cos²θ) = √tan²θ = tanθ.
Substituting this back into the integral, we get:
2∫[0 to π/2] arctan(tanθ) * sinθcosθ dθ.
Since arctan(tanθ) is equivalent to θ for 0 ≤ θ < π/2, the integral becomes:
2∫[0 to π/2] θ * sinθcosθ dθ.
We can rewrite sinθcosθ as (1/2)sin(2θ):
2∫[0 to π/2] θ * (1/2)sin(2θ) dθ
= ∫[0 to π/2] θ * sin(2θ) dθ.
Now, we can integrate by parts with u = θ and dv = sin(2θ) dθ:
∫ u dv = uv - ∫ v du.
Differentiating u = θ gives du = dθ, and integrating dv = sin(2θ) dθ gives v = -(1/2)cos(2θ).
Applying the formula for integration by parts:
∫[0 to π/2] θ * sin(2θ) dθ = [-(1/2)θ * cos(2θ)] from 0 to π/2 - ∫[0 to π/2] (-(1/2)cos(2θ)) dθ
= [-(1/2)(π/2) * cos(π)] - [-(1/2)(0) * cos(0)] - [-(1/2) ∫[0 to π/2] cos(2θ) dθ]
= [-(π/4)(-1)] - [0] - [-(1/2) ∫[0 to π/2] cos(2θ) dθ]
= π/4 + (1/4) ∫[0 to π/2] cos(2θ) dθ.
Now, let's integrate ∫[0 to π/2] cos(2θ) dθ:
∫ cos(2θ) dθ = (1/2)sin(2θ).
Evaluating this integral from 0 to π/2:
∫[0 to π/2] cos(2θ) dθ = (1/2)sin(π) - (1/2)sin(0)
= (1/2)(0) - (1/2)(0)
= 0.
Substituting this result back into the previous expression:
π/4 + (1/4) ∫[0 to π/2] cos(2θ) dθ = π/4 + (1/4)(0)
= π/4.
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The calculated value of the improper integral [tex]\int\limits^{1}_0 \arctan\sqrt{\frac{x}{1 - x}} \, dx[/tex] is 0.7853
How to evaluate the integralFrom the question, we have the following parameters that can be used in our computation:
[tex]\int\limits^{1}_0 \arctan\sqrt{\frac{x}{1 - x}} \, dx[/tex]
The above expression can be integrated using integration by parts method
When integrated, we have
[tex]\int\limits^{1}_0 \arctan\sqrt{\frac{x}{1 - x}} \, dx = \arctan\left(\frac{\sqrt{x}}{\sqrt{1-x}}\right)\,x+\frac{\sqrt{1-x}\sqrt{x}+\arctan\left(\frac{\sqrt{1-x}}{\sqrt{x}}\right)}{2}[/tex]
When simplified, we have
[tex]\int\limits^{1}_0 \arctan\sqrt{\frac{x}{1 - x}} \, dx = \frac{\left(2x-1\right)\arctan\left(\sqrt{\frac{x}{1-x}}\right)+\left(1-x\right)\sqrt{\frac{x}{1-x}}}{2}[/tex]
Recall that the x values are from 0 to 1
This means that
[tex]\int\limits^{1}_0 \arctan\sqrt{\frac{x}{1 - x}} \, dx = \frac{\left(2(1)-1\right)\arctan\left(\sqrt{\frac{1}{1-1}}\right)+\left(1-1\right)\sqrt{\frac{1}{1-1}}}{2}- \frac{\left(2(0)-1\right)\arctan\left(\sqrt{\frac{0}{1-0}}\right)+\left(1-0\right)\sqrt{\frac{0}{1-0}}}{2}[/tex]
When evaluated, we have
[tex]\int\limits^{1}_0 \arctan\sqrt{\frac{x}{1 - x}} \, dx = 0.7853[/tex]
Hence, the value of the integral is 0.7853
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A marketing firm is considering making up to three new hires. Given its specific needs, the management feels that there is a 60% chance of hiring at least two candidates. There is only a 7% chance that it will not make any hires and a 10% chance that it will make all three hires.
a. What is the probability that the firm will make at least one hire? (Round your answer to 2 decimal places.)
b. Find the expected value and the standard deviation of the number of hires. (Round intermediate calculations to at least 4 decimal places. Round your final answers to 2 decimal places.)
Evaluate the following sum.
To simplify the expression 12(3k-3)k^5, we can use the distributive property and simplify each term.First, let's apply the distributive property:
[tex]12 * 3k * k^5 - 12 * 3 * k^5[/tex]
This simplifies to:
[tex]36k * k^5 - 36 * k^5[/tex]
To combine like terms, we add the exponents when multiplying variables with the same base. In this case, both terms have k as the base:
36k * k^5 can be simplified to 36k^6.
Therefore, the expression becomes:
[tex]36k^6 - 36k^5[/tex]
This is the simplified form of the expression 12(3k-3)k^5.
It's important to note that if you have any specific values for k, you can substitute those values into the expression to get the numerical result. Without a specific value for k, we can't simplify it further.
Remember to always double-check the original expression and any specific instructions or context given to ensure you've applied the correct simplification techniques.
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I need help answering this, I don’t remember how to do this
Answer:
37.5
Step-by-step explanation:
the therom of a parallelogram is width*height
so 7.5*5
=37.5
If you found this helpful, please consider giving a brainliest!
Answer:
A = 37.5
Step-by-step explanation:
The area of a parallelogram is:
Area = base × height
In your picture the base is 7.5 and the height is 5.
So multiply 7.5×5 and you get 37.5.
The area is 37.5cm^2
Now, at the animal shelter 4/6 of the animals are cats. Of the cats ½ are male. What fraction of the animals at the shelter are male cats?
winta and lensa invest birr 21000 and 17500 respectively in a business.at the end of the year, they make profit birr 24600. what is the the share of winta in the profit?
Answer:
Step-by-step explanation:
To determine the share of Winta in the profit, we need to calculate the ratio of her initial investment to the total initial investment and then apply that ratio to the total profit.
Winta's initial investment: Birr 21,000
Lensa's initial investment: Birr 17,500
Total initial investment: Birr 21,000 + Birr 17,500 = Birr 38,500
To find the share of Winta in the profit, we calculate:
Winta's share = (Winta's initial investment / Total initial investment) * Total profit
Winta's share = (Birr 21,000 / Birr 38,500) * Birr 24,600
Simplifying the calculation:
Winta's share = (0.5455) * Birr 24,600
Winta's share ≈ Birr 13,414.55
Therefore, Winta's share in the profit is approximately Birr 13,414.55.
Find the quotient -7.3 1/2
Answer:
Step-by-step explanation: -3.655 hopefully that works
solve the equation…………….
Answer:
18
Step-by-step explanation:
[tex]\sqrt{x-2} =4\\x-2=16\\x=18[/tex]
Given equation :
[tex] \sqrt{x - 2} = 4[/tex]
Squaring both sides
[tex]( { \sqrt{x - 2} })^{2} = {(4)}^{2} [/tex]
[tex]x - 2 = 16[/tex]
Move all terms containing x to the left, all other terms to the right.
[tex]x = 16 + 2[/tex]
[tex]x = 18[/tex]
Verification:
Put value the x in the given equation.
[tex] \sqrt{x - 2} = 4[/tex]
[tex] \sqrt{18 - 2} = 4[/tex]
[tex] \sqrt {16} = 4[/tex]
[tex] \sqrt {4 \times 4 } = 4[/tex]
[tex]4 = 4[/tex]
Hence, The answer is 18.
27) Determine whether the graph can represent a normal curve. If it cannot, explain why.
A) The graph cannot represent a normal density function because it increases as x becomes very large
or very small.
B) The graph cannot represent a normal density function because it takes negative values for some
values of x.
C) The graph can represent a normal density function.
D) The graph cannot represent a normal density function because the area under the graph is greater
than 1.
The graph can represent a normal curve because it represent a normal density function. The Option C.
Can the graph represent a normal curve?The answer is yes. While these characteristics may deviate from the ideal properties of a normal distribution, they do not necessarily invalidate the possibility of the graph representing a normal density function.
A normal curve can have tails that extend indefinitely allowing for the graph to increase as x becomes very large or very small. Negative values can occur if the graph represents a standard normal distribution which is centered at zero.
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Esmerelda simplified a complex fraction. Her work is shown below.
Negative 5 and one-fourth divided by three-halves = negative StartFraction 21 over 4 EndFraction divided by three-halves = (Negative StartFraction 21 over 4 EndFraction) (Three-halves) = Negative StartFraction 24 over 6 EndFraction = negative 4
What errors did Esmerelda make? Select three options.
Esmerelda converted the mixed number to the wrong improper fraction.
Esmerelda added the numerators.
Esmerelda added the denominators.
Esmerelda did not divide –24 by 6 correctly.
Esmerelda did not use the reciprocal of the divisor
The correct options are:
Esmerelda converted the mixed number to the wrong improper fraction.
Esmerelda added the numerators.
Esmerelda did not divide –24 by 6 correctly.
The errors made by Esmerelda are as follows:
1. Esmerelda converted the mixed number to the wrong improper fraction.
2. Esmerelda added the numerators.
3. Esmerelda did not divide –24 by 6 correctly.
Let's go through each error:
1. Esmerelda converted the mixed number to the wrong improper fraction:
Esmerelda incorrectly converted "Negative 5 and one-fourth" to "Negative StartFraction 21 over 4 EndFraction." The correct conversion would be "Negative StartFraction 5 over 4 EndFraction" since the mixed number -5 1/4 can be expressed as -5 + 1/4 = -5 (1/4) = -5 (4/4) + (1/4) = -5 (4 + 1)/4 = -5 (5/4) = -5 (5 over 4).
2. Esmerelda added the numerators:
Esmerelda incorrectly added the numerators of the fractions, resulting in "Negative StartFraction 21 over 4 EndFraction" instead of the correct numerator of -5 * 4 = -20.
3. Esmerelda did not divide –24 by 6 correctly:
Esmerelda made an error in dividing -24 by 6, resulting in "StartFraction 24 over 6 EndFraction" instead of the correct value of -24 divided by 6, which is -4.
Therefore, the correct options are:
- Esmerelda converted the mixed number to the wrong improper fraction.
- Esmerelda added the numerators.
- Esmerelda did not divide –24 by 6 correctly.
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These tables of values represent continuous functions. In which table do the
values represent an exponential function?
The fourth table of values represents an exponential function (Correct choice: D).
Which table of value does represent an exponential function?
Herein we find four tables of values, three representing a linear function and one representing an exponential function. Each function is introduced below:
Linear equation:
n = m + r · n
Exponential function
n = m · rⁿ
Where:
m - Inputn - Outputr - Common rate.Common rate is the most appropriate criterion to distinguish linear equations of exponential equations. Now we proceed to summarize the results of each table of values:
Case A: Linear equation, r = 8.
Case B: Linear equation, r = 1.
Case C: Linear equation, r = 5.
Case D: Exponential equation: r = 2.
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A dairy farmer wants to mix a 75% protein supplement and a standard 25% protein ration to make 1100 pounds of a high-grade 55% protein ration how many pounds of each should he use?
The farmer should use 660 pounds of the 75% protein supplement and 440 pounds of the 25% protein ration to make 1100 pounds of a high-grade 55% protein ration.
Let 75% protein supplement be x and 25% protein ration be y
The total weight of the mixture is x + y = 1100
The second equation related to the protein in the mixture is 0.75x + 0.25y = 0.55 × 1100
= 0.75x + 0.25y = 605
By using the elimination method multiply the first equation by 0.25 to match the coefficients of y:
0.25x + 0.25y = 0.25 × 1100
0.25x + 0.25y = 275
by subtracting this equation from the second equation:
0.75 x + 0.25 y - {0.25 x + 0.25y} = 605 - 275
0.75 x - 0.25 x = 330
0.5x = 330
x = 660
by substituting this in the first equation:
660 + y = 1100
y = 440
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Two friends wash cars to make extra money. The profit P(x) of one friend after x days can be represented by the function P(x) = −x2 + 5x + 12. The second friend's profit can be determined by the function Q(x) = 6x. Solve the system of equations. What solution is a viable answer to the question, "After how many days will the two students earn the same profit?" and which solution is a nonviable answer? Show your work and justify your answer.
After 3 days, the two friends will earn the same profit.
To find the number of days after which the two friends will earn the same profit, we need to set the profit functions P(x) and Q(x) equal to each other and solve for x.
P(x) = Q(x)
−x^2 + 5x + 12 = 6x
Rearranging the equation:
−x^2 + 5x + 12 - 6x = 0
Combining like terms:
−x^2 - x + 12 = 0
To solve this quadratic equation, we can factor it or use the quadratic formula. In this case, let's factor the equation:
-(x - 3)(x + 4) = 0
Setting each factor equal to zero:
x - 3 = 0 or x + 4 = 0
Solving for x:
x = 3 or x = -4
Both x = 3 and x = -4 are solutions to the equation. However, we need to determine which one is a viable answer and which one is a nonviable answer.
The question asks for the number of days, which cannot be negative. Therefore, x = -4 is a nonviable answer since it represents a negative number of days. The viable answer is x = 3.
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Part B
Use the distance formula to find BC. Show your work.
Answer:
5 units------------------------
Use coordinates of endpoints, taken from the diagram, B(6, 2) and C(2, - 1) and the distance formula:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Substitute BC for d and given coordinates to find the radius:
[tex]BC=\sqrt{(2-6)^2+(-1-2)^2} =\sqrt{16+9} =\sqrt{25} =5[/tex]Hence the segment BC is 5 units long.
Shan scored 7 out of 10 for his maths test and 15 out of 20 for his science test. Which test did he achieve better results?
Shan performed better in his science test than in his math test based on the respective scores of 15 out of 20 and 7 out of 10.
To determine which test Shan achieved better results in, we need to compare the scores he obtained in both the math and science tests.
Shan scored 7 out of 10 in his math test, which can be written as a fraction 7/10. This fraction can also be converted to a decimal by dividing 7 by 10, resulting in 0.7.
Similarly, Shan scored 15 out of 20 in his science test, which can be written as a fraction 15/20. This fraction can also be simplified by dividing both the numerator and denominator by 5, resulting in 3/4. Converting this fraction to a decimal by dividing 3 by 4 yields 0.75.
Comparing the decimal values, we can see that 0.75 (science test) is greater than 0.7 (math test). Therefore, Shan achieved better results in his science test compared to his math test.
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1. Solve the differential equation
(4+t²)dy/dt + 2ty = 4t
2. Find the general solution of the differential equation dy/dt + (1/2)y = (1/2)e^t/3 .
3. Solve the initial value problem .
ty' + 2y = 4t² , where y(1) = 2.
Answer:
1. The solution to the differential equation is y = (4*t/3 + 2/3*t + C)/(t**2 + 4), where C is the constant of integration.
2. The general solution to the differential equation is y = (3/4)*exp(t/6) + C*exp(-t/2), where C is the constant of integration.
3. The solution to the initial value problem is y = t^2 + 4/3.
find the volume of the pyramid that has a square base.
picture provided down below.
PLEASE HELP THIS IS THE LAST DAY IM ABLE TO TURN THIS IN!!!!
Answer:
324 cm³
Step-by-step explanation:
Square based pyramid volume formula:
[tex]V=a^2\frac{h}{3}[/tex]
with a being the base length and h being the height
We can substitute in our values:
[tex]V=a^2\frac{h}{3} \\V=9^2\frac{12}{3}\\V=81(4)\\V=324[/tex]
So, the volume is 324 cm³.
Hope this helps! :)
Marie went golfing and tracked her golf cart's distance from the first hole over time. She stayed at the first hole for the first 30 minutes. Then she drove away from the first hole for the next 2 hours. She stopped to have lunch for 1 hour and then took 2 hours to drive back to the first hole.
Which of the following graphs could represent Marie's situation?
The graph that correctly represents Marie's situation is the graph B or the second graph.
How should the graph be?For the graph to correctly represent Marie's situation the followin elements are needed:
A step line that goes from 0 to 5 in the y-axis in the time of 2 hours, which represents her driving away for 2 hours.A horizontal line for 1 hour that represents Marie having lunch during that time.A negative step line that shows her driving back to the first hole, this line should go from 5 in the y-axis to 0.Note: This question is incomplete; below are the missing graphs:
Learn more about graphs in https://brainly.com/question/17267403
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AB is a radius of the circle. The circumference of the circle is 119.56. Find the
length of AB, rounding to the nearest tenth.
B
A
Answer:
19.0285
Step-by-step explanation:
For this, we have to work backwards.
First, the equation for the circumference of a circle is:
[tex]2\pi r[/tex]
We already know the circumference, so we can solve for r:
[tex]119.56=2\pi r[/tex]
divide both sides by 2
[tex]59.78=\pi r[/tex]
divide both sides by pi
[tex]19.0285...=r[/tex]
So, depending on the answer choices, the answer is 19.0285 rounded to the according decimal place.
Hope this helps! :)
