How does the value of the digit 2 in 2000 compare with the value of the digit 2 in 200

Answer:

Adding two positive integers gets a positive sum

now when adding two negative integers gets a negative sum.

Step-by-step explanation:

hope that helps>3

Step-by-step explanation:

0.000000358 written as scientific notation is

[tex]3.58 \times {10}^{ - 7} [/tex]

Answer:

12x – 4

Step-by-step explanation:

The sum of 5 times a number and - 4, added to 7 times the number =

(5x + -4) + 7x →

(5x + -4 + 7x) →

(5x + 7x + -4) →

(5x + 7x) + -4 →

12x + -4 →

12x – 4

Answer:

24

Step-by-step explanation:

the two times the cut into one

Answer:

When estimating area, count the squares that cover the shape. When estimating perimeter, count the unit lengths that are around the shape

Step-by-step explanation:

9514 1404 393

Answer:

  C)  x = 1/2 cm

Step-by-step explanation:

Apparently, we're to assume the units of x are centimeters. The volume of the cube is the product of its dimensions:

  V = x³ = 1/8

Then the value of x is ...

  x = ∛(1/8) = 1/∛8

  x = 1/2

_____

Additional comment

It can be useful to memorize the squares and cubes of small integers. The cubes you see most often are ...

  1³ = 1; 2³ = 8; 3³ = 27; 4³ = 64; 5³ = 125; 6³ = 216; 7³ = 343

Answer:

No it is not possible, cuz 35 students would need 4.6 teachers, it is not a whole number

Step-by-step explanation:

STUDENT : TEACHER

15 : 2

35 : 4.66

So according to the ratio, if we had 35 students, we would need 4.66 Teachers, but that is not possible, cuz i mean, u obviously can't cut the human into pieces and call that 0.66

The correct magnitude of the vector times the appropriate unit vector of given vectors are given as follows:

a. <0.708, 0, -0.708> [tex]*4.66*10^{-3}[/tex]

b. <0, -1, 0>*676

c. [tex]\overrightarrow{C} = <0.707, 0, -0.707>*4.47*10^2[/tex]

The general vector can be represented as:

[tex]\underset{A}{\rightarrow}[/tex] = (a, b, c) ......1

the magnitude [tex]| \right\underset{A}{\rightarrow} |[/tex] can be obtained as :

[tex]| \right\underset{A}{\rightarrow} | = \sqrt{a^{2}+ b^{2} +c^{2} }[/tex] .....2

and unit vector would be:

[tex]\hat{u}_A=\dfrac{\overrightarrow{A}}{|\overrightarrow{A}|}[/tex].......3

Solution:

a) ( 0.00330, 0, -0.00330)

here,

[tex]\underset{A}{\rightarrow} = ( 0.00330, 0, -0.00330)[/tex]

applying this magnitude to equation two:

[tex]| \right\underset{A}{\rightarrow} | = \sqrt{0.00330^{2}+ 0^{2} +(-0.00330)^{2} }[/tex] = [tex]4.66*10^{-3}[/tex]

the unit vector would be:

[tex]\hat{u}_A=\dfrac{\overrightarrow{A}}{|\overrightarrow{A}|}[/tex]

[tex]\hat{u}_A= < \frac{0.00330}{4.66*10^{-3}}, \frac{0}{4.66*10^{-3}}, \frac{-0.00330}{4.66*10^{-3}}>[/tex]

[tex]\hat{u}_A= <708, 0, -708>[/tex]

Thus, the vector [tex]{\overrightarrow{A}[/tex] would be - <0.708, 0, -0.708> [tex]*4.66*10^{-3}[/tex]

B) (0, -676, 0)

Solving simailarly like A),

Vector [tex]| \right\underset{B}{\rightarrow} | = \sqrt{0^{2}+ -676^{2} +0^{2} }[/tex] = 676

the unit vector would be:

[tex]\hat{u}_B=\dfrac{\overrightarrow{B}}{|\overrightarrow{B}|}\\\hat{u}_B= < \frac{0}{676}, \frac{-676}{676}, \frac{0}{676}>[/tex]

Thus,  the vector [tex]\overrightarrow{B}[/tex] = <0, -1, 0>*676

C) (0.00316, 0, -0.00316)

Attempting the third vector similarly we will get magnitude:

[tex]| \right\underset{C}{\rightarrow} | = \sqrt{0.00316^{2}+ 0^{2} +(-0.00316)^{2} }[/tex] = [tex]*4.47*10^{-3}[/tex]

Then,

[tex]\hat{u}_C=\dfrac{\overrightarrow{C}}{|\overrightarrow{C}|}\\\hat{u}_C= < \frac{0.00316}{4.47*10^2}, \frac{0}{4.47*10^2}, \frac{0.00316}{4.47*10^2}>[/tex]

The vector [tex]\overrightarrow{C} = <0.707, 0, -0.707>*4.47*10^2[/tex]

Learn more about vector unit:

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Answer:

perimiter if not add cause your doing inside so perimiter

Step-by-step explanation:

Answer:

8i + 5j - 3i - 2j

5i + 3j

I don’t know what i or j are because you didn’t say in your question, but you use the expression above and plug in the numbers to get your answer.

Step-by-step explanation:

Yes maybe

hope it helps

Answer:

Answer is the second circle will explain later but the second circle the middle one

[tex]\begin{array}{l}\sum _{n=1}^{6}\frac{n}{2n+1} =\frac{1}{2\cdotp 1+1} +\frac{2}{2\cdotp 2+1} +\frac{3}{2\cdotp 3+1} +\frac{4}{2\cdotp 4+1} +\frac{5}{2\cdotp 5+1} +\frac{6}{2\cdotp 6+1}\\\\\sum _{n=1}^{6}\frac{n}{2n+1} =\frac{1}{3} +\frac{2}{5} +\frac{3}{7} +\frac{4}{9} +\frac{5}{11} +\frac{6}{13}\end{array}[/tex]

Answer:

⚪ (4 • 3) + (4 • 8)

Step-by-step explanation:

[tex]4•(3 + 8)[/tex]

by distributing 4 in the bracket:

[tex] = \{(4•3) + (4•8) \}[/tex]

Answer: 5.25, 3/2, the square root of 6, 5

Step-by-step explanation:

Step-by-step explanation:

a refuse regular function tries to calculate a y value for a given x (input) value.

the inverse function turns this around and tries to calculate the x (input) value for a given y functional value.

e.g. when we know f(x) = 8, then what was the x value leading to this 8 fungible value ?

in order to turn this around, we solve the same functional equation for x instead of for y.

in our example here

f(x) = y = 3x -6

y + 6 = 3x

x = y/3 + 2

and now, to write the inverse function as normal function, we simply exchange the x and y names :

y = x/3 + 2

Answer: 399÷28= 14.25

Step-by-step explanation:

Divide 399 by 28 = 14.25

Answer:

72

Step-by-step explanation:

let the number be n then the quotient of the number and 6 is [tex]\frac{n}{6}[/tex] , then

[tex]\frac{n}{6}[/tex] = 12 ( multiply both sides by 12 )

n = 12 × 6 = 72

The number is 72

Answer:

72

Step-by-step explanation:

n/6=12

72/6=12/1

12/1=12

Answer: Lines [tex]\frac{}{BC}[/tex] and [tex]\frac{}{EF}[/tex] are different lengths.

Step-by-step explanation:

The distance formula is [tex]\sqrt{(x_1-x_2) ^{2}+(y_1-y_2) ^{2} }[/tex], and you can use this formula to solve for the lengths of both lines [tex]\frac{}{BC}[/tex] and [tex]\frac{}{EF}[/tex].

For line [tex]\frac{}{BC}[/tex], let [tex]x_{1}[/tex] = the x at point B, or 1, and let [tex]x_{2}[/tex] = the x at point C, or 2.

Now, let [tex]y_{1}[/tex] = the y at point B, or 4, and let [tex]y_{2}[/tex] = the y at point C, or -1.

Now, solve the formula to find the length [tex]\frac{}{BC}[/tex] = [tex]\sqrt{(x_1-x_2) ^{2}+(y_1-y_2) ^{2} }\\[/tex].

[tex]\frac{}{BC}[/tex] = [tex]\sqrt{(1-2)^{2} +(4-(-1))^2[/tex]

[tex]\frac{}{BC}[/tex] = [tex]\sqrt{(-1)^{2} +(4+1)^2[/tex]

[tex]\frac{}{BC}[/tex] = [tex]\sqrt{1 +5^2[/tex]

[tex]\frac{}{BC}[/tex] = [tex]\sqrt{(1+25)[/tex]

[tex]\frac{}{BC}[/tex] = [tex]\sqrt{26} \\[/tex]

Now, for line [tex]\frac{}{EF}[/tex], let [tex]x_{1}[/tex] = the x at point E, or -4, and let [tex]x_{2}[/tex] = the x at point F, or -1.

Let [tex]y_{1}[/tex] = the y at point E, or -3, and let [tex]y_{2}[/tex] = the y at point F, or 1.

Now, solve the formula to find the length [tex]\frac{}{EF}[/tex] = [tex]\sqrt{(x_1-x_2) ^{2}+(y_1-y_2) ^{2} }\\[/tex].

[tex]\frac{}{EF}[/tex] = [tex]\sqrt{(-4-(-1))^{2} +(-3-1)^2[/tex]

[tex]\frac{}{EF}[/tex] = [tex]\sqrt{(-4+1)^{2} +(-4)^2[/tex]

[tex]\frac{}{EF}[/tex] = [tex]\sqrt{(-3)^2+16[/tex]

[tex]\frac{}{EF}[/tex] = [tex]\sqrt{(9+16)[/tex]

[tex]\frac{}{EF}[/tex] = [tex]\sqrt{25}[/tex]

[tex]\frac{}{EF}[/tex] = 5

Now, look back at [tex]\frac{}{BC}[/tex]. The two lines have different lengths, so you have now justified the fact that they are not the same.

Questions 13 and 14 would be solved in much the same way- but please let me know if you want me to show the work for those as well!

Answer:

13

Step-by-step explanation:

3x^2-5y

3(4)^2-5(7)

3(16)-35

48-35

13

9514 1404 393

Answer:

  no

Step-by-step explanation:

The graph of this equation on an x-y plane is a vertical line. The input value x=15 maps to an infinite number of outputs (y-values). For a relation to be a function, each input can only map to one output.

  x = 15 is not a function

Step-by-step explanation:

1 hours = 60

1 m = 60 sec

so 2 × 60 × 60 = 7200 sec

1 km = 1000m

8 km= 8000m

Answer:

2 hours into seconds is 7200 seconds.

8 kilometers into meters is 8000 meters.

Step-by-step explanation:

To convert hours into seconds, multiply the number of hours by 3600.

To convert kilometers into meters, multiply the number of kilometers by 1000.

Answer:

-51

Step-by-step explanation:

30 - (3 + (-12))^2

30 - (-9)^2

30 - 81

-51

Answer:

Step-by-step explanation:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

Step-by-step explanation:

1) 4 terms

2) - 6

3) Coefficient = 4x³ + x - 3y

Step-by-step explanation:

I hope it was helpful

9514 1404 393

Answer:

  (f/g)(x) = 1/(2x)

  x ≠ 1/2

Step-by-step explanation:

  [tex](f/g)(x)=\dfrac{f(x)}{g(x)}=\dfrac{6x-3}{12x^2-6x}=\dfrac{6x-3}{2x(6x-3)}\\\\\boxed{(f/g)(x)=\dfrac{1}{2x}}\quad x\ne\dfrac{1}{2}[/tex]

The domain restriction x ≠ 1/2 comes from the requirement to prevent the denominator factor 6x-3 from being zero.

Answer:

a

Step-by-step explanation:

First identify which number represent the given letters

in the first question a)2 represents a, while 5 represents b.Then substitute 2 for a and 5 for b in the given expression.Do this for the second question.

Answer:

a) 52/126

B)55/126

C)40/126

Answer:

a. 52/126 i.e ratio of total coffee and total people

b. 55/126 i.e ratio of total females and total people

c. 40/126 i.e ratio of total male preferring tea and total people

Step-by-step explanation:

simplify the fraction if it is required.

The 10 hypothetical numbers which meets the conditions given on the question may include :

1, 2, 3, 5, 6, 6, 7, 10, 10, 12

The five number summary include the maximum, minimum, lower quartile, Median and upper quartile of a distribution.

The five number summary of the hypothetical data are:

Median: 6

Minimum: 1

Maximum: 12

Lower quartile: 2.75

Upper quartile: 10

Comparing the 5 - number summary of the hypothetical data with that of the given boxplot.

From the given  boxplot shown :

Minimum value = 1

Maximum value = 12

Median = 6

LOWER QUARTILE, Q1 = 4

UPPER QUARTILE, Q3 = 8

IQR = (Q3 - Q1) = 8 - 4 = 4

THE 10 made up numbers :

1, 2, 3, 5, 6, 6, 7, 10, 10, 12

The five number summary for the made up data :

Median = 1/2(n+1)th term = 5.5th term = (6+6)/2 = 6

Minimum: 1

Maximum: 12

First quartile = 1/4(n+1)th = 2.75th term = (2+3)/2 = 2.5

Third quartile: 3/4(n+1)th term = 8.25 = (10+10)/2 = 10

Interquartile Range: (10 - 2.5) = 7.5

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