Answer: 14.41*10^2 m/s
Explanation:
let, V be the escape velocity of the moon.
M be the mass of the earth.
r be the distance between the moon and the earth.
G be the universal gravitational constant.
And G = 6.67428*10^-11 m^3kg^-1 s^-2
here, given in the question that
The earth has a mass of 5.98*10^24 kg.
so, M = 5.98*10^24 kg.
And the distance from the earth to the moon is 3.84*10^8 m.
so, r = 3.84*10^8 m.
now, we know,
V = √2GM/r
V = √(2 * 6.67428*10^-11* 5.98 * 10^24 )/ 3.84*10^8
V = √79.82*10^13/3.84*10^8
V = √20.78*10^5
V = 14.41*10^2 m/s
what happens to the reflection when it hits the triangular prisms? the reflection is from air to glass. critical angle=42° please help me i need it right now:(
Answer: TIR (total internal reflection) occurs
Explanation: TIR occurs because the angle of refraction reaches a 90-degree angle before the angle of incidence reaches a 90-degree angle. The only way for the angle of refraction to be greater than the angle of incidence is for light to bend away from the normal. Since light only bends away from the normal when passing from a more dense medium into a less dense medium, then this would be a necessary condition for total internal reflection.
What is the gravitational force acting on a 70.0 kg object standing on the Earth’s surface?
The radius of the earth is 6.371 x 106 m and the mass is 5.972 x 1024 kg.
The gravitational force acting on a 70.0 kg object standing on the Earth’s surface is 687.37N
What is gravitational force ?
A mass attracts a mass; the amount of the gravitational force is directly proportional to the masses of the two items and inversely proportional to the square of the distance between the two objects. Gravitational force is an attractive force that exists between all objects with mass.
The square of the distance between two things has an inverse relationship with the force of gravity, which depends directly on the masses of the two items. Accordingly, the force of gravity increases with mass but decreases as object distance increases.
F = G (M*m) /r2
F = 6.674×10−11 * 5.972*10^24*70/ (6.371*10^6)^2
= 687.37N
F = gravitational force
G = gravitational constant
m = mass of the body
M = mass of the earth
r = distance between them
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does the current stays the same throughout in a parallel circuit
Answer:
When the current splits, the current in each branch after the split adds up to the same as the current just before the split.
No, the current is not constant across the entire parallel circuit.
The circuit is known to be divided into branches by the parallel connection. Consequently, those branches are formed from the total current.
A parallel circuit may have one or more branches. The total current splits into its corresponding branches as soon as it enters one. Less current flows through the branches than across the entire system. The branch resistance affects the branch current values. In parallel circuits, the current is therefore different. All components in a parallel arrangement share the same voltage.
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Does Monera move?
20 points
Answer:
Prokaryotic Bacteria
Explanation:
Find the resultant force of 16N and the force of 25N acting at the same point on an object if the Force at : (1) In the same direction in the same line. (11) In the opposite direction but in the same straight line. (111) At right angles to each other.
1 ) Resultant force if the forces act in the same direction = 41 N
2 ) Resultant force if the forces act in the opposite direction = 9 N
3 ) Resultant force if the forces act at right angles to each other = 29.68 N
F1 = 16 N
F2 = 25 N
1 ) If the forces act in the same direction,
F = F1 + F2
F = 16 + 25
F = 41 N
2 ) If the forces act in the opposite direction,
F = F2 - F1
F = 25 - 16
F = 9 N
3 ) If the forces act at right angles to each other,
F² = F1² + F2²
F² = 16² + 25²
F² = 256 + 625
F² = 881
F = 29.68 N
Therefore,
1 ) F = 41 N
2 ) F = 9 N
3 ) F = 29.68 N
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What role does fiction play in sport of your choice? Collect one picture of that sport in action where friction either supporting it or opposing it
1.- A car travels 10.0 km due north, then 8.00 km due east in 30.0 minutes. Find the
car's
Distance.
Displacement (indicate the angle too)
Average speed
Average velocity
(a)The displacement of the car is 12.8m
(b)The average speed is 10.0 m/s.
(c)The average velocity is 7.11 m/s.
What is displacement and distance?Distance is the real distance an object has traveled. The shortest distance between an object's initial and final positions is called displacement. It has a scalar value. A vector quantity, that is. An body can never travel a distance of zero.
Briefing:a. The vector sum of the different displacements yields the overall displacement. The Pythagorean theorem provides the vector sum since these displacements are perpendicular.
x2 = (10.0 km)² + (8.00 km)²
x = 12.8 km.
The angle is found using
tan q = (10.0 km/8.00 km)
q = 51.3° N of E.
b. Avg. Speed = Distance/Time = (18.0 km/30.0 min)(1000 m/1 km)(1 min/60 s) = 10.0 m/s.
c. Avg. Velocity = Displacement/Time = (12.8 km/30.0 min)(1000 m/1 km)(1 min/60 s) = 7.11 m/s.
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The complete question is -
A car travels 10.0 km due north, then 8.00 km due east, the total trip taking 30.0 minutes. Find (a) the displacement of the car, (b) the average speed (in m/s), and (c) the average velocity (in m/s).
A car is initially moving at 10.5 m/s and accelerates uniformly to reach a speed of 21.7 m/s in 4.34 s. How far did the car move during this
acceleration?
The care travelled a distance of 69.87 m.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. SI unit of acceleration is meter/second² (m/s²).
Given parameters:
Initial velocity of the car; u = 10.5 m/s.
Final velocity of the car; v = 21.7 m/s.
Time; t = 4.34 s.
The acceleration of the moving car; a = (Final velocity of the car - Initial velocity of the car)/time
= ( 21.7 m/s - 10.5 m/s)/4.34 s.
= 2.58 m/s².
Hence, the car move a distance during this acceleration; s = ut +1/2 at²
= 10.5×4.34 + 1/2 × 2.58×4.34² m.
= 69.87 m.
Hence, the car move a distance of 69.87 m during this acceleration.
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A plane is flying to Minnesota with a velocity of 373.52 km/h, N. The plane encounters a crosswind with a velocity of 64.90 km/h, W. What is the magnitude of the resultant velocity of the plane?
Answer:
379.12 km/h N 9.86° W
Explanation:
You want to know the resultant velocity when a plane's velocity of 373.52 km/h N is modified by a crosswind at 64.90 km/h W.
Vector sumIn (N, E) coordinates, the sum of the velocities is ...
(373.52, 0) +(0, -64.90) = (373.52, -64.90)
The magnitude of this vector is ...
|v| = √(373.52² +64.90²) ≈ 379.12 . . . . km/h
The direction will be west of north by the angle ...
θ = arctan(-64.90/373.52) ≈ -9.86° . . . . . . N = 0°, + = clockwise
The resultant velocity is 379.12 km/h N 9.86° W.
A hiker walks due East for a distance of 6 km
from her base camp. On the 2nd day, she covered
8km, North. On the 3rd day she walks for 4 km
South and found a cave. Determine her resultant
displacement between the base camp and the
cave.
Resultant displacement between the base camp and the cave will be 7.211 km
Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.
Her resultant displacement can be calculated using Pythagoras theorem
[tex]H^{2} = P^{2} + B^{2}[/tex]
= [tex]4^{2} + 6^{2}[/tex]
= 52
H = [tex]\sqrt{52}[/tex] = 7.211 km
Resultant displacement between the base camp and the cave will be 7.211 km
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A soccer coach is working with a device that measures the velocity of a soccer ball after it has
been kicked.
Which units should the coach use for velocity?
Choose 1 answer:
meters per second
kilograms
meters
meters per second
What is Velocity?
The pace at which an object's position changes in relation to a frame of reference and time is what is meant by velocity. Although it may appear sophisticated, velocity is just the act of moving quickly in one direction. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction. Its SI equivalent is the meter per second (ms-1). A body is considered to be accelerating if the magnitude or direction of its velocity changes.
Therefore, it will measured in meters per second.
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Interpret information to make judgment.
The teacher is showing the class an experiment using a radioactive source. She insists on these safety precautions
a) No students may sit in the front row
b) The radioactive source is kept in a lead box when not in use.
Explain why each of these precautions is important.
These precautions are important to avoid radiation effects. Lead is powerful in shielding nuclear substances because of its physical residence.
It is dense and difficult, which means it is able to block x-rays and gamma rays from penetrating thru the cloth. whilst these radioactive waves touch the steel, they collide with the lead atoms and get dispersed
Lock radioactive stock materials and sealed assets in a secured box or a secured storage vicinity when not in use. A stock fabric is a radioactive material as provided by using the vendor and does no longer include material withdrawn from the original inventory for experimental use.
You must generally hold radioactive resources, along with any radioactive waste that's in the garage, in suitable boxes internal an appropriate store to defend against unintended harm or loss and to guard employees and the majority.
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If you are told an image has been made by a single optic that has a positive focal length, which is true?
If you are told an image has been made by a single optic that has a positive focal length, The options that are true are:
The image is real. (Option A)
The image is virtual. (Option B)
The image has a positive image distance. (Option C)
The image has a negative image distance. (Option D)
The image is inverted. (Option E)
The image is upright.(Option F)
The image was made with a converging optic. (Option G)
The image was made with a diverging optic. (Option H)
If the optic is a lens, it is convex. (Option I)
If the optic is a mirror, it is convex. (Option K)
What is Focal Lenght?The focal length of an optical system is the inverse of the system's optical power; it measures how strongly the system converges or diverges light.
A system with a positive focus length converges light, whereas a system with a negative focal length diverges light.
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Full Question:
If you are told an image has been made by a single optic that has a positive focal length, which is true?
a. The image is real.
b. The image is virtual.
c. The image has a positive image distance.
d. The image has a negative image distance.
e. The image is inverted.
f. The image is upright.
g. The image was made with a converging optic.
h. The image was made with a diverging optic.
i. If the optic is a lens, it is convex.
j. If the optic is a lens, it is concave.
k. If the optic is a mirror, it is convex.
l. If the optic is a mirror, it is concave.
A 0.056 kg sample of an unknown substance is heated to 89.6 °C in a hot water tube. It is then quickly removed and placed into an insulated jar holding 188 ml of water initially at 132.8° F. The final equilibrium temperature of the system is 67° C. What is the specific heat of this unknown substance?
The specific heat of the unknown substance is 6.84 J/gºC
How do I determine the specific heat capacity?First, we shall convert 132.8° F to ° C. Thisis illustrated below:
Temperature (° F) = 132.8 ° FTemperature (° C) =?°C = (°F − 32) × 5/9
°C = (132.8 − 32) × 5/9
°C = 56 °C
Next, we shall determine the heat absorbed by the water. This is illustrated below:
Volume of water (V) = 188 mLDensity of water (d) = 1 g/mLMass of water (M) = dV = 1 × 188 = 188 gInitial temperature (T₁) = 56 °CFinal temperature (T₂) = 67 °CChange in temperature (ΔT) = 67 - 56 = 11 °CSpecific heat capacity of copper (C) = 4.184 J/gºC Heat absorbed (Q) =?Q = MCΔT
Q = 188 × 4.184 × 11
Q = 8652.512 J
Finally, we shall determine the specific heat capacity of the unknown metal. This can be obtained as follow:
Heat absorbed (Q) = 8652.512 JHeat released (Q) = -8652.512 JMass of unknown substance (M) = 0.056 kg = 56 gInitial temperature (T₁) = 89.6 °CFinal temperature (T₂) = 67 °CChange in temperature (ΔT) = 67 - 89.6 = -22.6 °CSpecific heat capacity of unknown substance (C) = ?Q = MCΔT
-8652.512 = 56 × C × -22.6
-8652.512 = C × -1265.6
Divide both sides by -1265.6
C = -8652.512 / -1265.6
C = 6.84 J/gºC
Thus, the specific heat capacity is 6.84 J/gºC
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a spiral spring loaded with a piece of metal extends by 9.4cm. when the metal is fully immersed in water, the spring extends by 3.5cm. assuming Hooke's law is obeyed, calculate the relative density of the metal
The relative density of the metal that is on a spiral spring which extends 9.4 cm in air and 3.5 cm in water is 1.59
RD = Weight of body in air / Upthrust
RD = Relative density
F = - k x
F = Spring force
k = Spring constant
x = Displacement
RD = - k ( 9.4 ) / - k ( 9.4 - 3.5 )
RD = 9.4 / 5.9
RD = 1.59
Relative density is the ratio of density of the substance to the density of the reference material. Density is the ratio of mass to volume. The unit of density is kg / m³. Relative density has no unit since it is density divided by density.
Therefore, the relative density of the metal is 1.59
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An object with a mass of 33g and a volume of 39cm^3 is placed in a liquid with a density of 1.25 g/cm^3. Find the volume of the part of the object that is NOT submerged in the liquid. Give your answer in cm^3 and with 3 significant figures.
Answer:
V₂ = 12.6 cm³ - volume of the NOT immersed part:
Explanation:
Given:
m = 33 g
V = 39 cm³
ρ = 1.25 g/cm³
____________
V₂ - ?
Gravity:
F = m·g
Strength of Archimedes:
Fa = ρ·g·V₁
V1 - the volume of the submerged
The object is floating, so:
F = Fa
m·g = ρ·g·V₁
m = ρ·V₁
V₁ = m / ρ = 33 / 1.25 ≈ 26,4 cm³
V₂ - volume of the NOT immersed part:
V₂ = V - V₁ = 39 - 26.4 = 12.6 cm³
16) What is the acceleration of the ball on its way up?
a) 0m/s
b) 8m/s
c) -9.81m/s^2
d) +9.81m/s
The acceleration of the ball on it way up is -9.81m/s².
The correct option is C)
What is acceleration?
This is the rate of change of velocity with respect to time. The speed and direction of the accelerating object are also very important. It unit is meters per second square, m/s².
What is Gravity?
This is the force that pulls a body toward the center of the earth. This force causes objects to fall freely. This free-falling object has an acceleration of 9.8m/s downward the earth. This is called acceleration gravity.
What is velocity?
This refers to the speed at which an object moves in a given direction. It unit is meters per second, m/s.
Recall that the direction of motion is assumed to be the positive direction. Other parameters depend on the direction of motion. Hence for upward acceleration, the direction of motion is positive but the acceleration due to gravity is negative because the direction is downwards.
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A 50.0-kilogram cheetah has a kinetic energy of 18000J How fast is the cheetah running ? ( Hint : Rearrange the equation to solve for v .)
I found that people say it’s 36 but there is no explanation for it
Answer:
Explanation:
here take kinetic energy =1/2×m×v²
m=50.0-kilogram (given)
kinetic energy=18000J (given)
now by taking the given values we get v²=(2×18000)/50
⇒v²=720
⇒v=26.8328m/s
done!
If is the angle between and the perpendicular is 90 then the lines of forces are O a. Not sure O b. Zero O C. Maximum O d. None of the above.
If the angle between displacement and force is 90° then the lines of force are zero. The correct option to this question is B.
The work completed is zero if there is a 90 degree angle between the force and the displacement.A scalar quantity, such as work, has simply magnitude and no direction.W= F×s or W= F×scosФ, which stands for "done," is the scalar product of force and displacement.Since cos90° has a value of 0, everything multiplied by 0 also has a value of 0.Because of this, when the angle between the force and the displacement is 90, we say that work is complete. For more information on scalar quantity kindly visit to
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function of a transformer in electrical circuits
Explanation:
There two types of transformers which are mainly stepup and step down transformers
the former is used for increasing voltage while the latter is used for reducing voltage
A tank with a flat bottom is filled with water to a height of 7.5 meters. What's the pressure at any point at the bottom of the tank?
A tank with a flat bottom is filled with water to a height of 7.5 meters. The pressure at any point at the bottom of the tank will be 174825 Pascal
Pressure at the flat bottom will be = Po + P(h)
Po = atmospheric pressure
P(h) = Pressure due to water
density of water = rho = 1000 kg / [tex]m^{3}[/tex]
Pressure at the flat bottom will be = 101325 Pa + 1000 * 9.8 * 7.5 = 174825 Pascal
The pressure at any point at the bottom of the tank will be 174825 Pascal
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I'm stuck on b(i), because I don't understand what equation to use with what values.
Answer:
Apparently, it takes 3 * 5E-3 sec to travel from D to G
The distance is given as .68 m
V = S / t = .68 m / (3 * 5E-3 s) = 45 m/s
Pls draw me what a velocity time graph would look like : moving at a positive constant speed to then at rest? Thank you!!!
Answer:
See below
Explanation:
Here are a couple of options..... one where the object slows to a rest and the other where the object stops to a rest instantaneously
a sample of cube X is shown above. If it’s mass is 244.4 mg, what is its density in g/cm^3
The density of the cube is 1.1 g/cm³
What is density?Density is described as the substance's mass per unit of volume. Mathematically, density is defined as mass divided by volume: density (rho) =mass/ Volume where ρ is the density, m is the mass, and V is the volume.
mass of cube= 244.4mg
volume of cube = 222.2 cm³
density = mass/ volume
density = 244.4/ 222.2 cm³
density = 1.1 g/cm³
Density is essentially a measurement of how tightly matter is packed together. density is a unique physical property of a particular object.
In conclusion, the principle of density was discovered by the Greek scientist Archimedes.
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A car of mass 500 kg is moving at a speed of 1.2m/s. A man pushes the car increasing the speed to 2 m/s. How much work did the man do
Answer:
Work:
A = 640 J
Explanation:
Given:
m = 500 kg
V₁ = 1.2 m/s
V₂ = 2.0 m/s
____________
A - ?
The work is equal to the change in the kinetic energy of the car:
A = Δ Wk
A = m·V₂² / 2 - m·V₁² / 2
A = (m/2)·(V₂² - V₁²)
A = (500/2)·(2² - 1.2²) = 640 J
A child throws a piece of candy corn directly up with an initial velocity of 3.8 m/s. If the starting height of the candy was 2.2 meters, what will be the height of the candy after 0.3 seconds? Use a = -9.8m/s/s
Three masses are connected as shown on a smooth horizontal surface.
(Take acceleration due to gravity as 9.8ms^-2)
a)Calculate the acceleration of the mass M3.
b)Calculate the tension in each string.
c)If the surface was not smooth describe how:
1.the acceleration of the system would be affected.
2.the tension in each string would be affected.
a) The acceleration of the mass M3 is 14.42 m/s².
b) The tension in each string. is : T₁ = 5119 N.
T₂= 7714 N.
And T₃ . = 12833 N.
c) If the surface was not smooth, there will be a frictional force which lessen both tension and acceleration of the system.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Let the acceleration of the system = a.
And the tension in each string is T₁ , T₂ and T₃ respectively.
Then for M₁ mass;
tension in string T₁ = M₁a
For M₂ mass:
tension in string T₂ = M₂ a
For M₃ mass:
tension in string T₃ - M₃g = M₃ a.
⇒T₃ = M₃g + M₃ a.
And T₃ = T₁ + T₂.
⇒M₃g + M₃ a. = M₂ a + M₁a
⇒ a = M₃g/( M₁ +M₂ -M₃)
= 530× 9.8/ (355+535-530)
= 14.42 m/s².
Then, the tension in each string is T₁ = 355 * 14.42 N = 5119 N.
T₂ = 535×9.8 N = 7714 N.
And T₃ = T₁ + T₂ = 5119 N +7714 N. = 12833 N.
If the surface was not smooth, there will be a frictional force which lessen both tension and acceleration of the system.
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A falling object with a mass of 2.55 kg encounters 4.0 N of air resistance. What is the acceleration of the object? (Choose up to be the positive direction, and remember the definition of weight).
Question 9 options:
a)
-21 N
b)
-241.0 m/s2
c)
-21.0 m/s2
d)
-8.2 m/s2
e)
8.2 m/s2
The acceleration of the falling obeject of mass 2.55 kg is -8.2 m/s². And the right option is d) -8.2 m/s².
What is acceleration?This can be defined as the rate of change of velocity.
To calculate the acceleration of the object, we use the formula below.
Formula:
a = (R-mg)/m............. Equation 1Where:
a = Acceleration of the objectm = Mass of the objectR = Air resistanceg = Acceleration due to gravity.Note: Taking forces acting upward to be positve and downward force to be negatove,
From the question,
Given:
R = 4 Nm = 2.55 kgg = 9.8 m/s²Substitute these values into equation 2
a = [4-(2.55×9.8)]/2.55a = -20.99/2.55a = -8.2 m/s²Hence, The acceleration of the object is -8.2 m/s².
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Which of the following courses might a mechanical engineer take in college?
Agriculture Operations
Organic Chemistry
Ethics in Sustainable Agriculture
Molecular Biology
The course to be likely taken by a mechanical engineer in college is agriculture operations (option A).
What is engineering?Engineering is application of mathematics and the physical sciences to the needs of humanity and the development of technology.
Mechanical engineering is a subfield of engineering concerned with designing and building machines and mechanical systems.
A mechanical engineer is an individual who specialises in the field of mechanical engineering. This means that a mechanical engineer is expected to be vast in the knowledge of designing and building machines for operations in other fields.
One of those fields that a mechanical engineer can build or design machine for is agriculture. Therefore, agriculture operations is the most likely course to be taken by a mechanical engineer in college.
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Answer: The correct answer is Agriculture Operations
Explanation: This answer has been confirmed correct.
Mechanical engineers work with equipment and automation, in areas such as agricultural operations. In contrast, they do not typically work with chemistry, ethics, or molecular biology.
In Graph C above, which line(s) shows an object that has a constant
velocity?
Answer:
it's D that has a constant velocity
