Answer:
When a body is describing a uniform circular motion , the speed of the body remains the same but the direction of motion of the body changes continuously with time . Since velocity is a vector quantity , the continuous change in the direction of motion of the body means the continuous change in velocity of the body with time . As the rate of change of velocity isacceleration , so a uniform circular motion is an accelerated motion .
Answer:
Explanation:
Uniform circular motion is accelerated because the velocity changes due to continuous change in the direction of motion. So, even when the body moves ta a constant speed, its velocity is not constant. Thus, for a body moving in a circular path at a constant speed, its velocity changes continuously
An m = 7.25 kg mass is suspended on a string which is pulled upward by a force of F = 76.7 N as shown in the figure. If the upward velocity of the mass is 2.25 m/s right now, then what is the velocity 3.50 s later?
The velocity after 30s would be 38. 99 m/s
How to calculate the velocityUsing the formula
F = m Δ V/ t
Where, F = force = 76. 7N
m = mass = 7. 25kg
Δv = change in velocity= V2 - V1 and V1 = 2. 25 m/s
t = time = 3. 50s
76. 7 = 7. 25 × (v2 - 2. 25) / 3. 50
76. 7 = 2. 07 × (v2 - 2. 25)
make v2 subject of formula
v2 - 2. 25 = 76. 07 ÷ 2. 07
v2 = 36. 74 + 2. 25
v2 = 38. 99 m/s
Thus, the velocity after 3. 50s would be 38. 99 m/s
Learn more about change in velocity here:
https://brainly.com/question/10962624
#SPJ1
A T-shirt cannon can shoot a 0.085 kg T-shirt at nearly 30 m/s. The T-shirt cannon has a mass of 33 kg. If the initial net momentum is at 0 then what is the velocity of the recoil of the T-shirt cannon?
Answer:
Approximately [tex]0.077\; {\rm m\cdot s^{-1}}[/tex] (assuming that external forces on the cannon are negligible.)
Explanation:
If an object of mass [tex]m[/tex] is moving at a velocity of [tex]v[/tex], the momentum [tex]p[/tex] of that object would be [tex]p = m\, v[/tex].
Momentum of the t-shirt:
[tex]\begin{aligned} p(\text{t-shirt}) &= m(\text{t-shirt}) \, v(\text{t-shirt}) \\ &= 0.085\; {\rm kg} \times 30\; {\rm m \cdot s^{-1}} \\ &= 2.55 \; {\rm kg \cdot m \cdot s^{-1}} \end{aligned}[/tex].
If there is no external force (gravity, friction, etc.) on this cannon, the total momentum of this system should be conserved. In other words, if [tex]p(\text{cannon})[/tex] denote the momentum of this cannon:
[tex]p(\text{t-shirt}) + p(\text{cannon}) = 0[/tex].
[tex]p(\text{cannon}) = -p(\text{t-shirt}) = -2.55\; {\rm kg \cdot m \cdot s^{-1}}[/tex].
Rewrite [tex]p = m\, v[/tex] to obtain [tex]v = (p / m)[/tex]. Since the mass of this cannon is [tex]m(\text{cannon}) = 33\; {\rm kg}[/tex], the velocity of this cannon would be:
[tex]\begin{aligned} v(\text{cannon}) &= \frac{p(\text{cannon})}{m(\text{cannon})} \\ &= \frac{-2.55\; {\rm kg \cdot m \cdot s^{-1}}}{33\; {\rm kg}} \\ &\approx 0.077\; {\rm m \cdot s^{-1}}\end{aligned}[/tex].
In science I have to make a project that can solve any real world problems [Grade 6]
When lights are wired such that if one bulb fails, the entire string of lights
goes out, they are said to be wired in ______
Answer:
series
Explanation:
In a series circuit all the components are attached to one branch, so that if one component fails, all the others stop working. In a parallel circuit, however, the components are wired in separate branches, so that even if one branch fails, the rest are not disrupted.
At what angle two forces P + Q and (P - Q) act so that their resultant is :
(i) [tex] \sf \sqrt{3 {p}^{2} + {q}^{2} } [/tex]
(ii) [tex] \sf \sqrt{2( {p}^{2} + {q}^{2} )} [/tex]
(iii) [tex] \sf \sqrt{ {p}^{2} + {q}^{2} } [/tex]
[tex] \underline{ \rule{888pt}{3pt}}[/tex]
(hint : use law of cosin will be used)
please help especially in (iii) part I have been trying to solve it for hours ^^"
ty in advance!
Use resultant formula
[tex]\boxed{\sf R=\sqrt{A^2+B^2+2ABcos\theta}}[/tex]
So
#1
A be p+q and B be p-q
[tex]\\ \rm\Rrightarrow R=\sqrt{3p^2+q^2}[/tex]
[tex]\\ \rm\Rrightarrow \sqrt{(p+q)^2+(p-q)^2+2(p+q)(p-q)cos\alpha}=\sqrt{3p^2+q^2}[/tex]
[tex]\\ \rm\Rrightarrow 2p^2+2q^2+2(p^2-q^2)cos\alpha=3p^2+q^2[/tex]
[tex]\\ \rm\Rrightarrow 2cos\alpha=1[/tex]
[tex]\\ \rm\Rrightarrow cos\alpha=\dfrac{1}{2}[/tex]
[tex]\\ \rm\Rrightarrow \alpha=\dfrac{\pi}{3}[/tex]
#2
[tex]\\ \rm\Rrightarrow 2(p^2+q^2)+2(p^2-q^2)cos\beta=2(p^2+q^2)[/tex]
[tex]\\ \rm\Rrightarrow 2cos\beta=0[/tex]
[tex]\\ \rm\Rrightarrow cos\beta=0[/tex]
[tex]\\ \rm\Rrightarrow \beta=\dfrac{\pi}{2}[/tex]
#3
[tex]\\ \rm\Rrightarrow 2(p^2+q^2)+2(p^2-q^2)cos\gamma=p^2+q^2[/tex]
[tex]\\ \rm\Rrightarrow 2(p^2-q^2)cos\gamma=-(p^2+q^2)[/tex]
[tex]\\ \rm\Rrightarrow cos\gamma =\dfrac{q^2-p^2}{2(p^2-q^2)}[/tex]
[tex]\\ \rm\Rrightarrow \gamma=cos^{-1}\left(\dfrac{q^2-p^2}{2(p^2+q^2)}\right)[/tex]
Answer:
See below ~
Explanation:
Here, let's apply the resultant vector formula :
[tex]R = \sqrt{A^{2} + B^{2} + 2ABcos\theta}[/tex]
Part (i) :
√3P² + Q² = √(P + Q)² + (P - Q)² + 2(P + Q)(P - Q)cosθ
3P² + Q² = P² + Q² + 2PQ + P² + Q² - 2PQ + 2(P² - Q²)cosθ
2(P² - Q²)cosθ = P² - Q²
cosθ = 1/2
θ = π/3 or 60°
Part (ii) :
√2(P² + Q²) = √(P + Q)² + (P - Q)² + 2(P + Q)(P - Q)cosθ
2(P² + Q²) = P² + Q² + 2PQ + P² + Q² - 2PQ + 2(P² - Q²)cosθ
2(P² - Q²)cosθ = 0
cosθ = 0
θ = π/2 or 90°
Part (iii) :
√P² + Q² = √(P + Q)² + (P - Q)² + 2(P + Q)(P - Q)cosθ
P² + Q² = P² + Q² + 2PQ + P² + Q² - 2PQ + 2(P² - Q²)cosθ
2(P² - Q²)cosθ = -P² - Q²
cosθ = [tex]\frac{-(P^{2}+ Q^{2}) }{2(P^{2}-Q^{2}) }[/tex]
[tex]\theta = cos^{-1} \frac{-(P^{2}+ Q^{2}) }{2(P^{2}-Q^{2}) }[/tex]
A block of mass 5 kg slides down an inclined plane that has an angle of 10. If the inclined plane has no friction and the block starts at a height of 0.8 m, how much kinetic energy does the block have when it reaches the bottom? Acceleration due to gravity is g = 9.8 m/s2
The kinetic energy of the block when it reaches the bottom is 39.2 J.
Kinetic energy of the block at the bottom
Apply the principle of conservation of energy.
K.E(bottom) = P.E(top)
P.E(top) = mgh
where;
m is mass of the blockg is acceleration due to gravityh is the vertical height of fallP.E(top) = 5 x 9.8 x 0.8
P.E(top) = K.E(bottom) = 39.2 J
Learn more about kinetic energy here: https://brainly.com/question/25959744
#SPJ1
Consider the three inclines shown in the figure. The vertical line is an incline with a 90° angle. (Inclines with 90° angles do exist!) All three inclines are frictionless. Three small identical objects are released from the top of the inclines. What can we tell about their travel times and final speeds?
(Options are: greater than, less than, equal to)
The final speed of C is ... that of B.
The travel time of A is ... that of B.
The final speed of B is ... that of A.
The travel time of C is ... that of B.
The final speed of A is ... that of C.
The travel time of C is ... that of A.
The final speed of C is equal to that of B.
The travel time of A is less than that of B.
The final speed of B is equal to that of A.
The travel time of C is greater than that of B.
The final speed of A is equal to that of C.
The travel time of C is greater than that of A.
What is speed?The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.
Consider the three inclines shown in the figure (attached below). The vertical line is an incline with a 90° angle. All three inclines are frictionless. Three small identical objects are released from the top of the inclines.
When the objects are at the same height, they travel with the same height. The travel time is directly proportional to the incline.
Thus, all the statements are completed.
Learn more about speed.
brainly.com/question/7359669
#SPJ1
The following equation shows the position of a particle in time t, x=at²i + btj where t is in second and x is in meter. A=2m/s², b=1m/s. Find
A, the average velocity of the particle in the time interval t₁=2sec and t₂=3sec
B, the velocity and acceleration at any time t.
C, the average acceleration in the time interval given in part (a)
The average velocity is 4i m/sec , the average acceleration is 4i
What is a Vector ?A vector is an object that has both magnitude and direction.
It is given that
x=at²i + btj
where t is in second and x is in meter.
The average velocity is given by dx/dt
dx/dt = 2at i + b j
dx/dt = 2 * 2 * t i +1 j
dx/dt = 4t i +j
dx/dt in the time interval of 2 to 3 sec is
at 2 sec,
dx/dt = 4 * 2 i +j = 8i +j
at 3 sec ,
dx/dt = 4 * 3 i + j = 12i+j
Therefore the average velocity is
(12i +j - 8i -j)/ (3-2) = 4i
The velocity at any given time is dx/dt = 4t i +j
The acceleration at any given time is d²x/dt²
d²x/dt² = 4 i
the average acceleration in the time interval t₁=2sec and t₂=3sec
Average Acceleration = 4i
To know more about Vector
https://brainly.com/question/24256726
#SPJ1
When vectors B+A=5i-j and B-A=i-7j, what is the magnitude and direction of vector A?
Answer:
2i-j, if b+a = 5i-j then b-a -b+a will give you a
An object of the same mass has three different weights at different times.
Answer:
See below
Explanation:
Possible.....mass is the amount of matter an object has ....weight is the result of gravity on an object.... different gravity ( Earth , Moon or Mars etc)
results in different weights .
How is overgrazing threatening the livelihood of pastoral communities in the savanna in Africa
Answer:
Overgrazing, which refers to the overutilization of grazing resources, by livestock promotes the increase in undesirable herbaceous plant species and bush encroachment, which are all indicators of rangeland degradation
A girl throws a marshmallow that lands in her friend’s mouth 2 m away. The girl threw the marshmallow at an angle of 30 degrees. How hard did she throw the marshmallow?
She threw the marshmallow at a speed of around 4.76 m/s.The formula for the horizontal range gives the velocity.
What is projectile motion?The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.
The item is known as a projectile, and the course it takes is known as a trajectory. Falling object motion is a simple one-dimensional kind of projectile motion with no horizontal movement.
Given data;
The marshmallow was thrown at a distance of 2 meters
Range,R = 3 m
Initial velocity,u
The angle at which the marshmallow was thrown,θ = 30°
The acceleration due to gravity,g = 9.81 m/s²
The projectile's motion is divided into two parts: horizontal and vertical motion.
[tex]\rm R = \frac{u^2sin2 \theta }{g} \\\\ \rm R = \frac{u^2sin2 \times (30) }{9.81} \\\\ u^2=\frac{2 \times 9.81 }{sin 60^0} \\\\ u^2=22.66 \\\\ u=4.76 \ m/sec[/tex]
Hence, she throws the marshmallow at a speed of 4.76 m/sec.
To learn more about the projectile motion refer to the link;
https://brainly.com/question/11049671
#SPJ1
8- A 20 KVA, 440/220 single-phase transformer has winding resistance as 0.090 and
0.0220. the total resistance referred to HV side isk
a) 0.0455 0
b) 0.0955
c) 0.112
d)0.1752
The total resistance referred to the HV side will be 0.36 ohm.
What is resistance?Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.
The total resistance referred to HV side is;
[tex]\rm \frac{R_H}{R_L} =(\frac{V_P}{V_S})^2 \\\\ R_H=R_L(\frac{V_P}{V_S})^2\\\\ R_H=0.090 \times (\frac{440}{220})^2\\\\ R_H=4 \times 0.090 \\\\ R_H= 0.36 \ ohm[/tex]
Hence, the total resistance referred to the HV side will be 0.36 ohm.
To learn more about the resistance refer to the link;
https://brainly.com/question/20708652
#SPJ1
A gas is contained in a cylinder with a frictionless moveable piston at a pressure of 3.50 × 105 pascals and a volume of 0.02 cubic meters. What is the work done by the gaseous system if the volume is increased to 0.15 cubic meters?
W=PΔV
W=3.5 x 10⁵ x (0.15-0.02)
W=4.55 x 10⁴ J
Water has a specific heat of 4.186J/gC how much heat is required to increase 10.0g of water from 25.0C to 30.0C
Answer:
Heat = 209.3 J
Explanation:
Givens
Specific Heat 4.186 J/g °C10 gramsdelta t = 30 - 25 delta t = 5°CDelta H = ?Formula
Heat = m c delta t
Solution and Answer
Heat = 10 grams * 4.186 * 5
Heat = 209.3 J
A train whistle is 580 Hz when stationary. It is moving away from you at 18.8 m/s. What frequency do you hear?
(Speed of sound = 343 m/s) (Unit = Hz)
Answer
613.63Hz
Explanation:
Fobs = (V/V-Vsource)Force
V=speed of sound
Fobs= (343/343-18.8)580
Fobs= 613.63Hz
Fobs = frequency observed
https://brainly.com/question/15339151
the answer is 550 Hz on Acellus
Nuclear Energy
The element carbon has three natural isotopes: C-12, C-13, and C-14.
Use the periodic table to find the number of protons in a carbon atom.
Then make a drawing to show the nuclei of the three carbon isotopes.
Your drawing should convey the number of protons and neutrons in each of the three different nuclei.
Carbon-12 and Carbon-13 are stable, whereas Carbon-14 is unstable.
Which isotope of carbon is most likely to undergo natural radioactive decay?
Which one would be called a radioisotope?
Explain the three processes of nuclear change and what is produced during as a result of that change.
Why is U-235 the most common nuclear fuel instead of the more abundant U-238? State a clear topic sentence and support it with evidence.
Create a flow chart to show how uranium is processed for use in a nuclear reactor.
Answer:
When uranium is mined, it consists of approximately 99.3% uranium-238 (U238), 0.7% uranium-235 (U235), and < 0.01% uranium-234 (U234). These are the different uranium isotopes. Isotopes of uranium contain 92 protons in the atom's center or nucleus. (The number of protons in the nucleus is what makes the atoms "uranium.") The U238 atoms contain 146 neutrons, the U235 atoms contain 143 neutrons, and the U234 atoms contain only 142 neutrons. The total number of protons plus neutrons gives the atomic mass of each isotope — that is 238, 235, or 234, respectively. On an atomic level, the size and weight of these isotopes are slightly different. This implies that with the right equipment and under the right conditions, the isotopes can be separated.
Explanation:
Please answer the following question.
The earthquake measure scale that is quantitative is the Richter scale.
The earthquake measure scale that is qualitative is the Mercalli Intensity scale
What is an Earthquake?This refers to the tremor of the earth that is caused by various factors such as movement within the earth's crust.
Hence, we can see that the more reasonable scale is the Richter scale as it measures the magnitude of an earthquake through the use of a seismograph that helps to show how strong an earthquake is.
The statement that all earthquakes occur along a plate boundary is FALSE.
This is because some earthquakes do not occur in places that have a large concentration of fault.
The statement that the epicenter is where the break occurs near the fault causing the earthquake is FALSE.
This is because the epicenter is the place where an earthquake occurs, but the hypocenter is the place where earthquake occurs below the surface.
Read more about earthquakes here:
https://brainly.com/question/248561
#SPJ1
A block with a weight of 620 N is pulled up at a constant speed on a very smooth ramp by a constant force. The angle of the ramp with respect to the horizontal is θ = 23.5° and the length of the ramp is l = 14.1 m.
Calculate the work done by the force in pulling the block all the way to the top of the ramp. (Neglect friction.)
The work done by the force in pulling the block all the way to the top of the ramp is 3.486 kJ.
What is work done?Work done is equal to product of force applied and distance moved.
Work = Force x Distance
Given is a block with a weight of 620 N is pulled up at a constant speed on a very smooth ramp by a constant force. The angle of the ramp with respect to the horizontal is θ = 23.5° and the length of the ramp is l = 14.1 m.
From the Newton's law of motion,
ma =F-mg sinθ =0
So, the force F = mg sinθ
Plug the values, we get
F = 620N x sin 23.5°
F = 247.224 N
Work done by motor is W= F x d
The force is equal to the weight F = mg
So, W = 247.224 x 14.1
W = 3.486 kJ
Thus, the work done by the force in pulling the block all the way to the top of the ramp is 3.486 kJ.
Learn more about Work done
brainly.com/question/13662169
#SPJ1
what is the magnitude of the vector described below
"75mph to the north"
A. North
B. Hours
C. 75mph
D. Miles per hour
Answer:
D. Miles per hour
Explanation:
Have a Good Day
Assuming the same current is running through two separate coils, why is it easier to thrust a magnet into a wire coil with one loop than one with four loops?
it is easier to thrust a magnet into a wire coil with one loop than one with four loops Because with four loops it becomes more difficult to push the magnet in.
What is a magnetic field?It is the type of field where the magnetic force is obtained. The magnetic force is obtained it is the field felt around a moving electric charge.
The quantity of turns or loops in a coil directly relates to the intensity of the magnetic field within the coil.
As a result, the magnetic field strength has increased fourfold when there are four loops instead of one, making it more difficult to push the magnet in.
A single-looped wire coil is simpler to insert a magnet into than one with four loops. because inserting the magnet gets more challenging when there are four loops.
To learn more about the magnetic field refer to the link;
https://brainly.com/question/19542022
#SPJ1
the deepest point in the sea is 100m below sea level .what arr the water pressure at this depth and the total pressure due to water and atmosphere ?
The water pressure at this depth and the total pressure due to water and atmosphere are 10.3 x 10⁵ Pa and 11.31× 10⁵ Pa.
What is pressure?The pressure is the amount of force applied per unit area.
Atmospheric pressure, Patm =1.01×10⁵ Pa
Density of water, ρ=1030 kg/m³
Depth, h=100 m
Pressure =ρgh
P = 1030×10×100
P = 10.3 x 10⁵ Pa.
Total pressure, P=Po +ρgh
P=1.01×10⁵ + 1030×10×100
P=11.31× 10⁵ Pa
Hence, total pressure is 11.31× 10⁵ Pa.
Learn more about pressure.
https://brainly.com/question/12971272
#SPJ1
A+B A=3i+4j-k B=5i+6j+2k
[tex]\text{Given that,}\\\\\vec A =3 \hat i + 4 \hat j - \hat k ~ \text{and}~ \vec B = 5\hat i + 6 \hat j +2 \hat k \\ \\\text{Now,}\\\\\vec A + \vec B = 3 \hat i +4 \hat j - \hat k + 5 \hat i + 6 \hat j + 2 \hat k\\\\~~~~~~~~~~=8 \hat i +10 \hat i + \hat k[/tex]
What is the gravitational acceleration I’d experience? How does it compare to Earth’s (for reference, Earth’s gravitational acceleration is 9.81 m/s2)?
Answer:
free-falling object is an object that is falling under the sole influence of gravity. A free-falling object has an acceleration of 9.8 m/s/s, downward (on Earth). This numerical value for the acceleration of a free-falling object is such an important value that it is given a special name. It is known as the acceleration of gravity - the acceleration for any object moving under the sole influence of gravity. A matter of fact, this quantity known as the acceleration of gravity is such an important quantity that physicists have a special symbol to denote it - the symbol g. The numerical value for the acceleration of gravity is most accurately known as 9.8 m/s/s. There are slight variations in this numerical value (to the second decimal place) that are dependent primarily upon on altitude. We will occasionally use the approximated value of 10 m/s/s in The Physics Classroom Tutorial in order to reduce the complexity of the many mathematical tasks that we will perform with this number. By so doing, we will be able to better focus on the conceptual nature of physics without too much of a sacrifice in numerical accuracy.
g = 9.8 m/s/s, downward
( ~ 10 m/s/s, downward)
Explanation:
Look It Up!
Even on the surface of the Earth, there are local variations in the value of the acceleration of gravity (g). These variations are due to latitude, altitude and the local geological structure of the region. Use the Gravitational Fields widget below to investigate how location affects the value of g.
1. (a) What must the charge (sign and magnitude) of a particle of mass 1.43 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 660 N/C? (b) What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight? 1. ( a ) What must the charge ( sign and magnitude ) of a particle of mass 1.43 g be for it to remain stationary when placed in a downward - directed electric field of magnitude 660 N / C ? ( b ) What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight ?
(a) The charge (sign and magnitude) of a particle of mass 1.43 g be for it to remain stationary is 2.12 x 10⁻⁵ C.
(b)The magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight is 10.24 x 10⁻⁸ N/C.
What is electric field?The field developed when a charge is moved. In this field, a charge experiences an electrostatic force of attraction or repulsion depending on the nature of charge.
Given is a particle of mass 1.43 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 660 N/C.
The electric field and force is related as
F = qE
mg = qE
Substitute the given values in the question, we have
1.43 x 10⁻³ x 9.81 = q x 660
q = 2.12 x 10⁻⁵ C
Thus, the charge of particle is 2.12 x 10⁻⁵ C.
(b)
Given is the electric force on a proton is equal in magnitude to its weight.
Force on proton = mass of proton x acceleration due to gravity
F = 1.67 x 10⁻²⁷ kg x 9.81
F = 16.38 x 10⁻²⁷ N
Charge on proton = 1.6 x 10⁻¹⁹ C
E = F/q
E = 16.38 x 10⁻²⁷ / 1.6 x 10⁻¹⁹
E = 10.24 x 10⁻⁸ N/C
Thus, the magnitude of electric field is 10.24 x 10⁻⁸ N/C.
Learn more about electric field.
https://brainly.com/question/15800304
#SPJ1
How are stationary waves formed in closed pipes ? Explain the various modes of vibration and obtain relations for their frequencies.
Answer:
By the reflection and the superimposition of the incident sound waves.
Explanation:
what current is transfered if 0.24 coublombs is to be transfered in 15ms
Answer:
I=0.016A
Explanation:
I=Q/tI=(0.24)/(15)I=0.016AA particle of weight W is placed on a rough plane which is inclined at an angle y to the horizontal. The coefficient of friction between the particle and the plane is where < tan . Show that the magnitude of the least horizontal force tan - W μ 9 F needed to maintain the particle in equilibrium is F=;
[tex] \frac{tan \beta - \alpha }{?} w \div 1 + \beta tan \alpha [/tex]
Answer:
45x+65b=67csseekoolmanbejk
Question 12 (10 points)
4) Listen
Ď (10,0 m)
25.00
Answer
53.0
B (15.0 m)
30,00
X
č (12.0 m)
X (8.00m)
For the vectors shown in the figure above
A+B+B. What is the
magnitude of
Note: Your answer is assumed to be reduced to the highest power possible.
Your Answer:
x10
units
Answer:
d jjh hhv g 7655 ijv 77_* uyfgj 3&88 huih
2- An instrument has resistance of 7 Ohms. its moving coil gives full deflection with 25 mA If a resistance of 0.7 Ohms is connected in parallel with the instrument, the instrument will be capable of reading up to A- 0.275 A B- 0.280 A R= V- 17- r C- 0.295 A 크 0175 25X163 7 D- 0.297 A I -0.179
From the calculation, the instrument will have a full scale deflation at 0.225A.
What is a shunt?We can convert a galvanometer to an ammeter by connecting a shunt resistance in parallel.
The current that flows across the shunt = I
Thus;
0.70I = 0.025 * 7
I = 0.25 A
0.25 A - 0.025 A =0.225A
Learn more about galvanometer:https://brainly.com/question/17247518
#SPJ1
