An ice skater with a mass of 80 kg pushes off against a second skater with a mass of 32 kg. Both skaters are initially at rest. (a) What is the total momentum of the system after they push off? (b) If the larger skater moves off with a speed of 3 m/s, what is the corresponding speed of the smaller skater
A. The total momentum of the system after they push off is zero.
B. m1v1=m2v2
v2=m1v1/m2
v2=80*3.0/32
v2=7.5 m/s
in fact
m1v1=80*3= 240 kgm/s
m2v2= 32*7.5= 240 kgm/s.
A penny board is a type of skateboard characterized by a short, narrow deck made of plastic. If you're on the short side, consider choosing a smaller deck. Smaller decks are easier to operate and control, lighter, and more portable. If you are taller, you should choose a larger deck.
The larger deck gives more stability and power when skating. A big part of being a skater girl is looking like that which means wearing skate-branded shoes and clothes. Other skaters tend to wear these clothes cut to allow the skater's movement. Good skatesHer brands include Vans DC Nike especially basketball lines and Etnies I have.
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What is the speed of light in Crown glass? answer:______m/s
ANSWER
197,368,421.1 m/s ≈ 1.97 x 10⁸ m/s
EXPLANATION
The speed of light in a medium with an index of refraction n is given by,
[tex]v=\frac{c}{n}[/tex]Where c is the speed of light in a vacuum, which is 3 x 10⁸ m/s.
In this case, we have to find the speed of light in Crown glass, whose index of refraction is 1.52 at 20°C. So, the speed of light in this medium is,
[tex]v=\frac{3\cdot10^8m/s}{1.52}=197,368,421.1m/s\approx1.97\cdot10^8m/s[/tex]Hence, the speed of light in Crown glass is 197,368,421.1 m/s ≈ 1.97 x 10⁸ m/s.
If the tire of a car rotates at a constant speed of 552 times in one minute, how many times will the tire rotate in half-an-hour?
Given:
The car tire rotates 552 times in a minute.
Required:
The number of times the tire rotates in half an hour.
Explanation:
The tire rotates 552 times in a minute.
There are 30 minutes in half an hour.
The number of times the tire rotates in half an hour will be
[tex]\begin{gathered} 552\times30 \\ =16560 \end{gathered}[/tex]Final Answer: The tire rotates 16560 times in half an hour.
How much current does a 75-W light bulb draw when connected to 120 V?
We will determine the current as follows:
First, we recall that:
[tex]I=\frac{P}{V}[/tex]So:
[tex]I=\frac{75W}{120V}\Rightarrow I=\frac{5}{8}A\Rightarrow I=0.625A[/tex]So, the current that a 75-W light bulb draws when connected to 120 V is 0.625 Amps.
Imagine you want to watch a show, and an ad comes on beforehand. The ad is from Chic Shampoo. The voiceover says, “Shampoo Chic—we're unique!”
In this scenario, you are the:
Responses
message
stereotype
receiver
sender
In this scenario, you are the Receiver.
One possible scenario is moving to a city. The most likely scenario is he returns to school in the fall. In the best-case scenario, I'll finish the work by tomorrow. They looked at each other and weighed the situation. the sequence of events. chain of events. the course of the event. series of expansions. Your scenario is very similar to your situation, but it hasn't happened yet, and it may not happen at all.
The real world is where you actually have to live and the situations you actually have to deal with. Real-world examples are the life you are living now and the life you want to live someday. Almost any situation in which an unknown quantity exists can be described by a linear equation. To look at income over time, calculate mileage rates, and forecast profits. Many people use linear equations on a daily basis, even if they don't draw line graphs and do the calculations in their heads.
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Answer:
Receiver.
Explanation:
I need to find wfg,wnet,the acceleration of the car and how long will it take Tyler to get to the gas station
The free body diagram representing this scenario is shown below
From the information given.
mass of car = 1200kg
Recall,
weight = mg
where
m = mass
g = acceleration due to gravity = 9.8 m/s^2
Thus,
weight of car = 1200 x 9.8 = 11760 N
Normal reaction, N has same magnitude with the weight but the direction is opposite. thus,
N = 11760 N
Frictional force = N x coefficient of friction
From the information given,
coefficient of friction = 0.67
Thus,
Frictional force = 11760 x 0.67 = 7879.2 N
Net force of the car = applied force - frictional force
applied force = 1.3 x 10^4 N = 13000 N
Thus,
Net force = 13000 - 7879.2 = 5120.8N
Recall,
net force = mass x acceleration
acceleration = net force/mass = 5120.8/1200 = 4.27 m/s^2
We want to calculate the time it will take Tyler to get to the gas station. We would apply one of Newton's equation of motion which is expressed as
s = ut + 1/2at^2
where
s = distance covered
t = time
a = acceleration
u = initial velocity
From the information given,
s = 15
a = 4.27
u = 0 because the car was at rest(Since it was broken down)
By substituting these values into the equation, we have
15 = 0 x t + 1/2 x 4.27 x t^2
15 = 0 + 2.135t^2
15 = 2.135t^2
Dividing both sides of the equation by 2.135, we have
15/2.135 = 2.135t^2
t^2 = 7.026
t = square root of 7.026
t = 2.65
The time required is 2.65 s
Daisy throws her love-lock's key horizontally with a speed of 11.0 m/s from a bridge. It falls 2.94 s before reaching the water below. What was the total speed just before hitting the water?
Daisy throws her love-lock's key horizontally with a speed of 11.0 m/s from a bridge. It falls 2.94 s before reaching the water below. the total speed just before hitting the water was 17.836 m/s.
given that :
initial velocity u = 11.0 m/s
final velocity v = 0 m/s
using the formula :
v = u + at
0 = 11 - 9.8 t
t = 1.12 sec
time taken to hit the water = 2.94 sec
bow, time taken to reach water :
t' = 2.94 - 1.12
t' = 1.82 sec
therefore , speed just before hitting the water :
v = u + at'
v = 0 + 9.8 × 1.82
v = 17.836 m/s
Thus, Daisy throws her love-lock's key horizontally with a speed of 11.0 m/s from a bridge. It falls 2.94 s before reaching the water below. the total speed just before hitting the water was 17.836 m/s.
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Calculate the x-component and the y-component (in m) of the vector with magnitude 26.0 m and direction 45.0°.x = m y = m
The components can be found as:
[tex]\begin{gathered} V_x=V\cdot\cos (45)=26\cdot\cos (45) \\ V_x=13\sqrt[]{2} \\ V_x\approx18.38m \\ ----------------------- \\ V_y=V\cdot\sin (45)=26\cdot\sin (45) \\ V_y=13\sqrt[]{2} \\ V_y\approx18.38m \end{gathered}[/tex]
When you drop a 0.37 kg apple, Earth exerts
a force on it that accelerates it at 9.8 m/s² to-
ward the earth's surface. According to New-
ton's third law, the apple must exert an equal
but opposite force on Earth.
If the mass of the earth 5.98 x 10²4 kg, what
is the magnitude of the earth's acceleration
toward the apple?
Answer in units of m/s².
The earth is accelerating toward the apple at a rate of 6.2 × 1025 m/s2.
How is this acceleration determined?The apple weighs m = 0.37 kg.
The apple's speed when it approaches the earth's surface is 9.8 meters per second.
Earth's mass, M, is 5.98 × 1024 kg.
Using Newton's Second Law of Motion, we may now:
The strength of the force exerted by Earth on the apple is,
F = ma
⇒ F = 0.37 × 9.8
⇒ F = 3.626 N
We are informed that the apple must exert an equal but opposite force on Earth in accordance with Newton's third law of motion.
Therefore, the force exerted by the apple on Earth will be of the following magnitude:
F = 3.626 N
Let "A" be the acceleration of the earth relative to the apple in m/s2.
Thus,
The following will be used to determine how quickly the earth is moving toward the apple:
F = MA
⇒ 3.626 = [5.98 × 10²⁴] × A
⇒ A = 3.626 / [5.98 × 10²⁴]
⇒ A = 0.606 × 10⁻²⁴
⇒ A = 6.06 × 10⁻²⁵ m/s²
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Question A student conducts an experiment to determine how the temperature of water affects the time for sugar to dissolve. In each trial, the student uses a different amount of water and a different temperature of water. What is wrong with this experimental design? Responses The student needs to perform more trials. The student needs to perform more trials. The student changed more than one independent variable. The student changed more than one independent variable. The student does not have a dependent variable. The student does not have a dependent variable. The student did not change enough independent variables.
The student changed more than one independent variable.
A dependent variable is a variable that changes as a result of the manipulation of the independent variable. It's the result you want to measure and it depends on the independent variable. In statistics, the dependent variable is also called the response variable it responds to changes in another variable.
In other words, the two characteristics of the experimental design we've talked about so far are that the experiment must have at least two comparable conditions, and the researcher must match the participants to the conditions, not the participants themselves. That's it. The independent and dependent variables are those when you run the experiment. The independent variable is the one that changes and the dependent variable is the one that changes.
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A toy car of mass 8 kg initially moves with a speed of 5 m/s. How much work must be done on the car to increase its speed to 10 m/s?
ANSWER:
300 J
STEP-BY-STEP EXPLANATION:
To know the work required, we must calculate the work in both cases, the difference would be the amount of work necessary for the speed to increase. The work done is the same as the amount of energy increase. The formula for kinetic energy is:
[tex]\frac{1}{2}m\cdot v^2[/tex]We calculate in each case:
[tex]\begin{gathered} \frac{1}{2}\cdot8\cdot10^2=400\text{ J} \\ \frac{1}{2}\cdot8\cdot5^2=100\text{ J} \end{gathered}[/tex]We calculate the difference between the two to find out the work required:
[tex]400-100=300\text{ J}[/tex]The work required is 300 J
a cylinder of gas is at room temperature (20 °C) the air conditioner breaks down and the temperature rises to 40°C what is the new pressure of gas relative to its initial pressure
Given,
The initial temperature of the room, T₁=20 °C=293.15 K
The final temperature, T₂=40 °C=313.15 K
Let the initial temperature of the room be P₁, and the final temperature be P₂
From Gay-Lussac's law,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]On substituting the known values in the above equation,
[tex]\frac{P_1}{293.15}=\frac{P_2}{313.15}[/tex]Therefore P₂ is given by,
[tex]P_2=\frac{P_1\times313.15}{293.15}=1.07P_1[/tex]Therefore, the new pressure relative to the initial pressure is 1.07 times the initial pressure, i.e., 1.07P₁
velocity differs from speed in that velocity indicates a particle's __________ of motion.
velocity differs from speed in that velocity indicates a particle's Direction of motion.
For the majority of us, speed and velocity can be a little puzzling. Speed and velocity are different in that speed just gives us an indication of how quickly an object is going, whereas velocity not only tells us an object's speed but also the direction in which it is travelling. In contrast to velocity, which is defined as a function of displacement, speed can be defined as a function of the distance travelled. A body's instantaneous velocity is its speed right now. Average velocity is defined as total displacement divided by total time and is provided by the formula v = x/t, where x is the body's total displacement and t is the time. Average speed is never greater than average velocity, and vice versa.
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Draw a supply graph for pizzas. Show what would happen to the supply of pizzas if two more pizzerias open up in town. Identify the determinant of supply that caused the shift.
The supply curve will move to the correct, demonstrating an increment within the add-up to the amount of pizza as of now on the advertisement, in case two or more pizzerias open within the community.
To encourage data on the important picture, see the subtle elements underneath and the attachment.
The add up to several items and administrations that businesses in a country's economy point to offer inside a particular time outline is known as total supply, too known as residential last supply in economics.
It is the overall number of merchandise and administrations that businesses in an economy are arranged and able to offer for sale at a particular cost point.
A alter in supply is characterized as a move to the cleared out or right within the general price-quantity relationship that shapes a supply shift. A alter in supply is characterized as a move to the cleared out or right within the general price-quantity relationship that shapes a supply bend.
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A satellite is 100 miles above the earth, it has a mass of 100kg. If the mass of the satellite were doubled the force of gravity of the satellite on the earth would ?
Given:
Distance of satellite from Earth = 100 miles
Mass of satellite = 100 kg
If the mass of the satellite were doubled, let's find what would happen to the force of gravity of the satellite on earth.
Apply the gravitational force formula:
[tex]F=\frac{Gm_1m_2}{r^2}[/tex]Where:
F is the force of gravity
m is the mass.
From the formula above, we can see the force of gravity (F), is directly proportional to the mass.
Since they are directly proportional to each other, if the mass is doubled, the force of gravity will also be doubled.
Therefore, if the mass of the satellite is doubled, the force of gravity of the satellite on the earth will also be doubled.
ANSWER:
Force of gravity will be doubled when the mass of the satellite is doubled.
19:46 Thu 20 Oct
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Value
isaacphysics.org
Q1. Calculate the weight of the following masses, which are at the Earth's surface.
(a) For a mass of 1.5 kg, what is its weight?
Private
?
Units
Check my answer
N/kg
Calculate the weight of the following masses, which are at the Earth's surface. For a mass of 1.5 kg, its weight is (W)=14.7N
What is weight?Weight is a physical term that means that how much force of attraction is applied on the mass of the object. It can be measured in Newton and Dyne.
How can we calculate the weight?To calculate the weight we are using the formula here is,
W= mg
Here we are given,
m= mass of the object on earth. = 1.5 kg
g= The force of acceleration of the object. = 9.8m/s²
We have to calculate the value of the weight = W N.
Now we put the values in the above equation, we get
W=mg
Or, W=1.5*9.8
Or, W=14.7 N
From the calculation we can say that, For a mass of 1.5 kg, its weight is (W)=14.7N
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Find the measure of the indicated angle to the nearest degree.
Sin θ
The measure of the indicated angle to the nearest degree is Sin 42°.
An angle is formed when two immediate traces or rays meet at a not-unusual endpoint.
The names of primary angles are Acute angle, Obtuse perspective, proper attitude, straight attitude, reflex angle, and full rotation. A perspective is a geometrical form shaped by using joining rays at their endpoints. An angle is normally measured in stages. there are various varieties of angles in geometry.
A right triangle or proper-angled triangle, or greater officially an orthogonal triangle, formerly called a rectangle triangle, is a triangle wherein one angle is a proper angle or facets are perpendicular. The relation among the perimeters and different angles of the proper triangle is the premise for trigonometry.
calculation:-
perpendicular = 43
hypoteneuse = 64.4
Sin θ = perpendicular / hypoteneuse
= 43 / 64.4
Sin θ = 0.66770
Sin θ = 41.889
Sin θ = 42° ( nearest degree)
Sin α = 90 - 42
= 48°
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A father demonstrates projectile motion to his children by placing a pea on his fork's handle and rapidly depressing the curved tines, launching the pea to heights above the dining room table. Suppose the pea is launched at 7.47 m/s at an angle of 81.0° above the table. With what speed (in m/s) does the pea strike the ceiling 2.10 m above the table?
Given
Initial velocity is u=7.47 m/s
The angle is
[tex]\theta=81^0[/tex]The vertical height travelled, h=2.10 m
To find
The final speed of the pea.
Explanation
Along the vertical direction,
The final speed is given by the equation of kinematic
[tex]v_y^2=u_y^2+2ah[/tex]Putting the values
[tex]\begin{gathered} v_y^2=(7.47sin81^o)^2+2(-9.81)\times2.1 \\ \Rightarrow v_y=3.63\text{ m/s} \end{gathered}[/tex]Along the horizontal direction,
the speed is constant throughout the projectile
Thus,
[tex]v_x=7.47cos81^0=1.168\text{ m/s}[/tex]So the final velocity of the pea is
[tex]\begin{gathered} v=\sqrt{(3.63)^2+(1.168)^2} \\ \Rightarrow v=3.81\text{ m/s} \end{gathered}[/tex]Conclusion
The final velocity is 3.81 m/s
A 9,900-kg truck runs into the rear of a 1,000-kg car that was stationary. The truck and car are locked together after the collision and move with speed 5 m/s. Compute how much kinetic energy was "lost" in this inelastic collision.
answer in J
Kinetic energy was "lost" in this inelastic collision is 151 J
The momentum is given as :
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
The truck and car are locked together after the collision. The truck has same final velocity :
u = (( m₁ + m₂ ) v) / m₁
u = ( (9900 + 1000 ) × 3 ) / 9900
u = 3.30 m/s
now, the change in kinetic energy is given by :
ΔK.E = 1/2 ( m₁ + m₂) v² - 1/2 m₁ u²
ΔK.E = 1/2 ( 1211.11 ) - 1/2 ( 909.09)
ΔK.E = 605.55 - 454.54
ΔK.E = 151 J
Thus, A 9,900-kg truck runs into the rear of a 1,000-kg car that was stationary. The truck and car are locked together after the collision and move with speed 5 m/s. kinetic energy was "lost" in this inelastic collision is 151 J
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The first human-made satellite, Sputnik I, had a mass of 83.4 kg and a momentum with a magnitude of 660,730 kg·m/s. What was the satellite’s speed? Round your answer to the nearest whole number.
The satellite’s speed is 7922.4 m / s if the Sputnik I, had a mass of 83.4 kg and a momentum with a magnitude of 660,730 kg·m/s.
p = m v
p = Momentum
m = Mass
v = Velocity
m = 83.4 kg
p = 660730 kg m / s
v = p / m
v = 660730 / 83.4
v = 7922.4 m / s
Momentum can be described as a mass in motion. It is the product of the object's mass and its velocity. It can also be described as the power held by a moving body that it can exert on another body.
Therefore, the satellite’s speed is 7922.4 m / s
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Which thinker belongs at the beginning of Raj’s timeline?
The thinker belonging at the beginning of Raj’s timeline is Ptolemy.
Who is Ptolemy?
Claudius Ptolemy was a mathematician, astronomer, astrologer, geographer, and music theorist, who wrote about a dozen scientific treatises, three of which were of importance to later Byzantine, Islamic, and Western European science.
Ptolemy made his observations using nak-ed eyes. In his opinion, the Universe is ''a set of nested, transparent spheres, with Earth in the center. Ptolemy argued that the Moon, Mercury, Venus, and the Sun were all revolving around around Earth.
Although Ptolemy made significant contributions in Astronomy but he was wrong in his argument that the earth did not move at all.
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How long is the runway? And what is the planes take off speed
These relationships are referred to as the equation of motion.
s = ut + ½at². and v = u + at.
length of the Run way = 1350m
Take of speed of the plane is 90 m/s.
How many formulas of motion are there?We will learn how to relate quantities such as velocity, time, acceleration, and displacement as long as the acceleration is constant. These relationships are referred to as the equation of motion.The three equations of motion are as follows:
v = u + a t is the first equation of motion.s = u t + 1 /2 a t^2 is the second equation of motion. Third Element of Motion: v 2 = u 2 + 2 a sfrom equation of motion
s = ut + ½at².
here u =0 a =3 m/s^2 t= 30s
put these values on the above equation
s= 1/2x 3x 30x30= 1350 m
length of the Run way = 1350m
from equation of motion ,
v = u + at.
= 0+ 3x 30 = 90m/s.
Take of speed of the plane is 90 m/s.
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Distance = 1350m, speed = 90m/s
Given:
Initially the Aero plane is at rest. Therefore, initial velocity:
u = 0m/s
Acceleration = 3m/[tex]s^{2}[/tex]
Time taken = 30 seconds
So according to question, we have to find distance & speed
How to find distance?we know that
s = ut + 1/2a[tex]t^{2}[/tex]
Putting all the values, we get S = 1350 m
Now to find speed, we know,
[tex]v^{2} = u^{2} + 2aS[/tex]
Putting all the values,
v = [tex]\sqrt{8100}[/tex]
v = 90m/s
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A cat is thrown straight up at 24.9 m/s What is the cat's velocity 4.3 seconds later?
Answer:
-17.3 m/s
Explanation:
a = -9.81 mm/s^2 vo = 24.9 m/s
vf = vo - at
= 24.9 - 9.81 ( 4.3) = -17.3 m/s ( cat is already coming back down)
which of the following is correct equation for finding the wavelengths of a wave? physics
Answer:
Option C may be the anawer for it
What is the term to describe the time that a force is applied to an object?
a) Inertia
b) Momentum
c) Impulse
d) Weight
Answer:
c)impulse
Explanation:
.............
A 3.00-kg object is initially moving northward at 15.0 m/s. Then a force of 15.0 N, toward the east, acts on it for 2.70 s.
A) At the end of the 2.70 s, what is the magnitude of the object’s final velocity?
B) What is the direction of the final velocity? Enter the angle in degrees where positive indicates north of east and negative indicates south of east.
C) What is the change in momentum during the 2.70 s? Take +y to be north and +x to be east. Enter a positive answer if the change in momentum is toward the east and a negative answer if the change in momentum is toward the west.
The magnitude of the object’s final velocity, the direction of the final velocity and the change in momentum during the 2.70 s
V=0.1 m/s[tex]\theta[/tex]=48.0^0 + from east-4.5kgm/s toward westThis is further explained below.
What is the magnitude of the object’s final velocity?F_x=m a_x=15N
f is force
m is mass
a is acceleration
[tex]&a_x=\frac{15}{3} \\\\ m s^2=5 m_{s^{-2}} \\[/tex]
v_x=0+5 * 2.7
v_x=13.5
v_y=15
[tex]V=\sqrt{v_x^2+v_{y^2}}\\[/tex]
V=0.1 m/s
b)
[tex]\tan \theta=\frac{V_y}{V_x} \\\\ =\frac{18}{13.5} \\\\[/tex]
=1.11
[tex]\theta[/tex]=48.0^0 + from east
c)
Initial momentum,
p_{i x}=0, p_{i y}=m v_y=45 kgmg
final momentum,
P_{f x}=13.5 *3
=40.5kgm
P_{f y}=45Kgm/s
In conclusion, D P_x=P_{1 \text { In }}-P_{i x}=-4.5kgm/s toward west
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Explain how the Earth, Moon, and Sun all cause the moon phases.
Answer:The sun provides the light to see the moon, while the earth casts a shadow on the moon but on full moons there is no shadow from the earth on the moon, and the moon is the thing affected by all of this
Explanation:
A train car with a mass of 1 kg is stuck to another train car with a mass of 2 kg. An Explosion pushes the two carts away from each other. After the recoil, the 1 kg train car is now moving at -2 m/s and we need to find the Velocity of the 2 kg train car.
We know that the momentum is conserved on the system this will mean that:
[tex]p_i=p_f[/tex]where:
[tex]p=mv[/tex]At the beginning the cars are stuck together and we can assume they are at rest; we know that after the explosion the velocity of the 1 kg car is -2 m/s; then we have:
[tex]\begin{gathered} (1+2)(0)=(1)(-2)+2v \\ 0=-2+2v \\ 2v=2 \\ v=\frac{2}{2} \\ v=1 \end{gathered}[/tex]Therefore, the velocity of the 2 kg car is 1 m/s.
Optics 1. An object 2 cm high is placed 30 cm from a concave mirror with a radius of curvature of 10 cm. Find the position and size of the image.
Size of the image 0.4cm
Distance u =−30cm
Height h = 2cm
Radius of curvature R = 10cm
We know that,
-f = R/2 = 10/2 = -5 cm
Now, using the mirror’s formula
1/f = (1/v) + (1/u)
-1/5 = (1/v) - (1/30)
v = 6cm
Now, the magnification is
m = -v /u = -6 / -30 = 0.2
We know that,
m = h`/h
0.2 = h`/2
he = 0.4 cm
What is optics?Optics is the branch of physics that studies the behaviour and properties of light, including its interaction with matter and the structure of instruments that use or detect it. Optics typically describes the behaviour of visible, ultraviolet and infrared light.
Three main branches of optical science
Geometrical optics, the study of light as rays. Physical optics, the study of light as waves. Quantum optics, the study of light as particleTo learn more about optics, visit;
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Car A moving in a straight line and a constant speed of 20 m/s is initially 200 m behind car b moving in the same straight line at a constant speed of 15 m/s how far must car a travel from this initial position before it catches up with car bb
The distance travelled by the car A from the initial position before it catches up with car B is 800 m.
v = d / t
v = Velocity
d = Distance
t = Time
Let x be the distance travelled by car B before car A catches up.
For car A,
v = 20 m / s
d = ( 200 + x ) m
t = d / v
t = ( 200 + x ) / 20
For car B,
v = 15 m / s
d = x m
t = x / 15
The time taken by both car A and car B before they meet up is the same.
( 200 + x ) / 20 = x / 15
3000 + 15 x = 20 x
5 x = 3000
x = 600 m
Distance travelled by the car A = 200 + x
Distance travelled by the car A = 200 + 600
Distance travelled by the car A = 800 m
Therefore, the distance travelled by the car A from the initial position before it catches up with car B is 800 m.
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