There are eight atoms present in a simple cubic unit cell but only a net single atom present in it.
The simple cubic unit cell is basically the simplest repeating unit present in a simple cubic structure. Each of the corners of this simple unit cell are defined by a particular lattice point at which a particular atom, ion, or molecule can be found in the given crystal.
Each of the eight corners present in the unit cell therefore contains an identical particle. The remaining particles would be present on the edges or on the faces of the unit cell, or we can say within the body of the unit cell. There are 8 atoms but each of them only contributes to one eight of the atom and so the net atom is only 1. (8 × 1/8 = 1)
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what is the oxidation number (oxidation state) for n in n2h62 ?
The oxidation number (or oxidation state) of nitrogen in N2H6 is+2. Oxidation numbers are assigned to atoms in a molecule to keep track of the total number of electrons that have been gained or lost by the atom.
The oxidation number (or oxidation state) of nitrogen in N2H6 is +2. This is because nitrogen has lost two electrons in the reaction, resulting in an oxidation number of +2. In general, oxidation numbers can be used to track the number of electrons gained or lost by an atom in a reaction. Oxidation numbers are assigned based on the number of bonds formed between atoms as well as the electronegativity of the atoms involved. For example, oxygen usually has an oxidation number of -2, nitrogen usually has an oxidation number of +2, and hydrogen usually has an oxidation number of +1.
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it is observed that the density of an ideal gas increases by 10 percent when compressed isothermally from 10 atm to 11 atm. determine the percent increase in density of the gas if it is compressed isothermally from 100 atm to 101 atm.
The percent increase in the density of the gas is 2 percent.
The percentage increase in the density of an ideal gas is proportional to the pressure change, according to Gay-Lussac's law. Since the increase in pressure is 10 percent from 10 atm to 11 atm, and the increase in density is also 10 percent, the pressure-density relationship can be expressed as:
(density increase) / (initial density) = (pressure increase) / (initial pressure)
Rearranging and substituting the known values, we can find the relationship between pressure and density:
(density increase) / (initial density) = 0.1
(pressure increase) / (initial pressure) = 0.1
Now, if the pressure increases from 992 atm to 1004 atm, the density increase can be calculated by substituting these values into the equation:
density increase = 0.1 * initial density
= 0.1 * (density at 992 atm)
pressure increase = 1004 atm - 992 atm = 12 atm
(density increase) / (initial density) = 0.1 * (pressure increase) / (initial pressure)
density increase = 0.1 * (12 atm) / (992 atm) * initial density
The increase in density is therefore 0.1 * 12 / 992 * initial density
= 0.02 * initial density.
So the percent increase in the density of the gas is 2 percent.
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The complete question is:
It is observed that the density of an ideal gas increases by 10 percent when compressed isothermally from 10 atm to 11 atm. Determine the percent increase in the density of the gas if it is compressed isothermally from 992 atm to 1004 atm. The increase in the density of the gas is 02%.
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what is flavor? describe how taste experience is affected if olfaction does not take place when tasting a substance.
Flavor refers to the taste and aroma sensation perceived when eating or drinking a substance.
The flavor is a combination of taste and smell, with the majority of the flavor experience being contributed by the sense of smell, also known as olfaction.
If olfaction does not take place when tasting a substance, the taste experience is greatly affected. The sense of smell plays a crucial role in flavor perception, as it can enhance or diminish the taste sensations perceived by the tongue.
Without the sense of smell, the taste experience is limited to basic tastes like sweet, sour, salty, bitter, and umami. The overall experience of flavor will be greatly reduced and the taste of the substance may seem bland or unappealing.
In conclusion, the sense of smell plays a crucial role in our taste experience, and without it, flavor perception is greatly reduced.
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if each reactant molecule in the above image represents 0.0800mol and the reaction yield is 77.%, how many grams of si-containing product form? round your answer to 2 significant figures. g
1.73 grams of Silicon-containing product forms.
To find the amount of product formed, we need to first find the number of moles of product produced by multiplying the number of moles of the reactant by the reaction yield (0.77). Then we can convert the number of moles to grams using the molar mass of the product.
0.0800 mol * 0.77 = 0.0616 mol product
The molar mass of silicon (Si) is 28.09 g/mol, so the mass of the product can be found as follows:
0.0616 mol * 28.09 g/mol = 1.73 g (rounded to 2 significant figures)
So, 1.73 grams of Si-containing product forms.
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Please answer my question.
The electronic configuration of antimony is Kr 4d¹⁰ 5s² 5p³. The placement of electrons in orbitals surrounding an atomic nucleus is known as electronic configuration.
What is electronic configuration?
The placement of electrons in orbitals surrounding an atomic nucleus is known as electronic configuration, also known as electronic structure and electron configuration.
The number of electrons within every orbital is denoted by a superscript, and the occupied orbitals are listed in order of filling to represent the electronic configuration of such an atom inside the quantum-mechanical model. The electronic configuration of antimony is Kr 4d¹⁰ 5s² 5p³.
Therefore, the electronic configuration of antimony is Kr 4d¹⁰ 5s² 5p³.
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mass of co2 collected was 2.40 g. how many moles of carbon were present in the original sample?
According to the question, the mass of CO2 collected is 2.40g. The number of moles of carbon present in the sample is 0.0546 mol.
The number of moles of carbon present in the original sample can be calculated by dividing the mass of CO2 collected (2.40 g) by the molar mass of CO2 (44.01 g/mol).
So, the number of moles of carbon = [tex]2.40 g / 44.01 g/mol[/tex] = 0.0546 mol.
Since CO2 contains one carbon atom and two oxygen atoms, the number of moles of carbon present in the original sample is equal to the number of moles of CO2 collected.
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If you have 2 moles of CO2 how many mile of carbon would you have? And how many moles of oxygen
Explanation:
So 2 moles of carbon reacts with 2 moles of oxygen to produce 2 moles of CO2.
A mole of CO2 molecules (we usually just say “a mole of CO2”) has one mole of carbon atoms and two moles of oxygen atoms. The atom ratio and the mole ratio of the elements are identical! 1-).
1 mole of CO2 = 1 × 12 + 2 × 16 = 44 g. 2 mole of CO2 = 2 × 44.0 = 88.0 g.
calculate the amount of naoh needed to prepare 300 ml of 0.1m solution. (hint: molecular weight of naoh
The amount of NaOH will be needed to prepare 300 ml of 0.1m solution is 1.2 gram.
Sodium hydroxide, also called as lye as well as caustic soda. It is an inorganic compound having chemical formula NaOH. It is a white solid ionic compound which is consisting of sodium cations Na+ and hydroxide anions OH−. Sodium hydroxide is a highly caustic base as well as alkali which decomposes proteins at ordinary ambient temperatures and may cause severe chemical burns. It is highly soluble in water, and it readily absorbs moisture as well as carbon dioxide from the air.
[tex]M_{eq}[/tex] NaOH = Volume × Molarity = 300 × 0.1 = 30
Now lets find how many g of NaOH will be needed to prepare 300 mL of 0.1 M solution.
W / 40 × 1000 = 30
W = 1.2 gram
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a biochemist studying breakdown of the insecticide ddt finds that it decomposes by a first-order reaction with a half-life of 12.0 yr. how long does it take ddt in a soil sample to decompose from 408 ppbm to 10.0 ppbm (parts per billion by mass)?
A biochemist studying breakdown of the insecticide DDT finds that it decomposes by a first-order reaction with a half-life of 12.0 yr. it takes 84.0 years for DDT in a soil sample to decompose from 408 ppb to 10.0 ppb.
The rate of a first-order reaction is proportional to the concentration of the reactant. The half-life (T1/2) of a first-order reaction is defined as the time it takes for the concentration of the reactant to decrease by a factor of 1/2.
We can use the following equation to calculate the time it takes for the concentration of DDT to decrease from 408 ppb to 10.0 ppb:
[A]t = [A]0 x (1/2)(t/T1/2)
where [A]t is the concentration of DDT at time t, [A]0 is the initial concentration of DDT, t is the time, and T1/2 is the half-life.
Setting [A]t = 10.0 ppb and [A]0 = 408 ppb, and solving for t, we get:
t = T1/2 x log( [A]0 / [A]t ) / log(1/2)
t = 12.0 yr x log( 408 ppb / 10.0 ppb ) / log(1/2)
t = 84.0 yr
Therefore, it takes 84.0 years for DDT in a soil sample to decompose from 408 ppb to 10.0 ppb.
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Which qualities are maintained during all chemical reactions? Select all that apply.
Question 2 options:
A. The identity of the atoms present in the reactants
B. The number of atoms present in the reactants
C. The arrangement of chemical bonds present in the reactants
D. The number of reactant molecules
The qualities that are maintained during all chemical reactions are as follows:
A. The identity of the atoms present in the reactants
B. The number of atoms present in the reactants
In chemical reactions, the law of conservation of mass states that the total amount of matter in a closed system remains constant. This means that certain qualities of the reactants must be maintained in order for this law to be upheld. The qualities that are maintained during all chemical reactions include:
A. The identity of the atoms present in the reactants: The atoms in the reactants are not destroyed or created during the reaction. They simply rearrange to form new compounds.
B. The number of atoms present in the reactants: The total number of atoms in the reactants must equal the total number of atoms in the products. This is because matter cannot be created or destroyed, only transformed from one form to another.
C. The arrangement of chemical bonds present in the reactants: The reactants are composed of chemical bonds that hold the atoms together. In a chemical reaction, the bonds are broken and new bonds are formed to create the products. However, the number of bonds present in the reactants must equal the number of bonds present in the products.
D. The number of reactant molecules: The number of reactant molecules must equal the number of product molecules, as the law of conservation of mass applies to individual molecules as well as to the total amount of matter in a closed system.
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What is the correct formula for calcium dihydrogen phosphate?
Calcium Dihydrogen Phosphate has the proper chemical formula Ca(H₂PO₄)₂.
The inorganic compound Ca(H₂PO₄)₂ is known as monocalcium phosphate. Ca(H2PO4)2H2O is frequently encountered as the monohydrate. Both salts are solids without color. They are mostly employed as superphosphate fertilizers, while they are also widely utilized as leaveners. Calcium Dihydrogen Phosphate hydrate is used in the production of glass, as a plastics stabilizer, and as a pH control reagent. When Calcium Hydroxide is neutralized with Phosphoric Acid, Phosphate Dihydrate precipitates as a solid, yielding Dicalcium Phosphate. The fact that dicalcium phosphate is safe for people is a very significant characteristic.
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if you start with 6.03 g of crude sulfanilamide and recrystallize it from ethanol to recover 4.82 g of pure sulfanilamide, what is the percent recovery?
If you start with 6.03 g of crude sulfanilamide and recrystallize it from ethanol to recover 4.82 g of pure sulfanilamide, the percent recovery is 80.1%.
Sulfanilamide, commonly known as sulfanilamide, is an antibacterial sulfonamide medication. It is an organic molecule made composed of an aniline that has been derivatized with a sulfonamide group.
To calculate the percent recovery, we'll divide the mass of pure sulfanilamide obtained (4.82 g) by the initial mass of crude sulfanilamide (6.03 g) and multiply by 100 to express the result as a percentage:
Percent recovery = (mass of pure sulfanilamide obtained / initial mass of crude sulfanilamide) x 100
= (4.82 g / 6.03 g) x 100
= 80.1%
So, the percent recovery in this case is 80.1%.
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In the Hydroxide ion, there are 10 electrons and 9 protons.
Where did the extra 1 electron come from?
Answer:
The extra electron in the hydroxide ion (OH-) comes from the gain of a single electron by the oxygen atom, giving it a net negative charge.
if we wanted to neutralize an acid to determine its concentration, should it be added to the anodic or cathodic compartment? why?
If we wanted to neutralize the acid to determine its concentration, it should be added to the cathodic compartment as the more concentrated electrolyte will lies on the cathode compartment.
The more the concentrated electrolyte in the concentration cell will be in the cathodic compartment. The cathode chamber will be reduced in the concentration cell, then the concentration of the electrolyte in the solution will be decreases. The anode chamber is oxidized on the concentration cell, the concentration of the electrolytes will increases in the solution.
Thus, in the cathodic compartment , the concentration of the acid can be determine.
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to convert 0.0257 mm2 to μm2, you must:
0.0257 mm2 is equivalent to 25700 μm2 when using the conversion formula of 1 mm2 = 1000000 μm2.
The conversion formula for converting mm2 to μm2 is:
1 mm2 = 1000000 μm2
Therefore, to convert 0.0257 mm2 to μm2, we must first multiply 0.0257 by 1000000. This results in 25700 μm2, which is the equivalent of 0.0257 mm2.
To illustrate how this works, the conversion can be expressed in the following equation: 0.0257 mm2 × 1000000 = 25700 μm2.
In summary, 0.0257 mm2 is equivalent to 25700 μm2 when using the conversion formula of 1 mm2 = 1000000 μm2. This formula can be used to quickly and accurately convert any mm2 value to its corresponding μm2 value.
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according to , equal volumes of h2 and o2 at the same t and p have moles.
The Ideal Gas Law states that equal volumes of hydrogen (H2) and oxygen (O2) have the same number of moles when they are at the same temperature and pressure.
According to the Ideal Gas Law, if the temperature is constant, the pressure, volume, and temperature of a gas are all exactly proportional to the number of moles of gas present.
So the number of moles of each gas will be identical if equal volumes of H₂ and O₂ are kept at the same temperature and pressure. This indicates that if the gases are ideal, then the number of molecules in each gas will also be equal (i.e. they follow the Ideal Gas Law). It is significant to remember that gases are frequently not perfect in real-world settings.
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Why is 1-methyl-3,4-diethylbenzene is an unsuitable name? Draw this compound and give the correct name.
The correct name would be 1,4-dimethyl-2-ethylbenzene.
The name "1-methyl-3,4-diethylbenzene" is not a systematic or commonly used name for a chemical compound. A more appropriate name for this compound would be 1,4-dimethyl-2-ethylbenzene. This name follows the International Union of Pure and Applied Chemistry (IUPAC) naming conventions, which provide a systematic and standardized way of naming chemical compounds. In this case, the name indicates that the compound is a benzene with a methyl group on the 1-carbon and two ethyl groups on the 3 and 4 carbons. The correct systematic name is preferred over the common name, as it helps to avoid ambiguity and confusion.
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what is the difference between closed reduction and open reduction? in what type of fracture would closed reduction most likely occur? in what type of fracture would open reduction most likely occur?
In general, closed reduction is used for simple fractures that can be reset without cutting through the skin. Open reduction is necessary for more severe fractures, such as compound fractures, where the broken bone has punctured the skin or the fracture is not amenable to resetting through closed reduction.
A fractured bone's shattered ends can be reset without surgery via closed reduction. The shattered ends of the bone must need surgery to be placed in their proper anatomical positions after open reduction. Closed reduction would probably be necessary for a partial fracture. Open reduction would be necessary for a complex fracture.
In a non-surgical procedure known as "closed reduction," the damaged bone is straightened without a skin incision. The procedure often includes pulling or manipulating the bone manually while under local or general anaesthesia.
On the other hand, open reduction requires surgery to correct the shattered bone. When closed reduction is not an option or the shattered bone is badly malpositioned, it is often carried out.
Simple fractures, when the shattered bone is still in alignment and may be moved with manual manipulation or traction, are most likely to result in closed reduction.
In complicated fractures, where the fractured bone has pierced the skin, or in severe fractures, where the broken bone is severely displaced and cannot be realigned with closed reduction, open reduction is more likely to take place.
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HELP ASAP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
When will a fossil be used in finding the absolute age of rocks?
A.if it existed for a limited period of time and in a small area
B.if it existed for a limited period of time and in a wide area
C.if it existed for a long period of time and in a wide area
D.if it existed for a long period of time and in a small area
in the 1950's the 'wonder drug' thalidomide was prescribed to pregnant women for the treatment of morning sickness, but was halted because [fill in the blank]
Your answer a.one enantiomer of the drug caused birth defects. b.one enantiomer of the drug caused brain damage. c. the US government redirected their attention to space exploration. d.both enantiomers of the drug caused brain damage.
Thalidomide was prescribed to pregnant women in the 1950s as a "wonder drug" to treat morning sickness, but it was halted because both enantiomers of the drug caused severe birth defects and brain damage in their babies. So the correct option is "d".
Thalidomide had two enantiomers, one of which was active and one of which was inactive. It was believed that the active enantiomer was responsible for the drug's therapeutic effects, but it was later discovered that both enantiomers caused the serious side effects. This led to the eventual halt of the drug in 1961, and it has since become a cautionary tale about the importance of testing drugs for safety before releasing them to the public.
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PLEASE HELP ASAPPPP
When the particles of a liquid experience a decrease in kinetic energy, which of the following is true?
( multiple answer) *
3 points
temperature increases
temperature decreases
intermolecular bonds become weaker
intermolecular bonds become strong
freezes
melts
molecules speed up
molecules slow down
When the particles of a liquid experience a decrease in kinetic energy, then the true statements are temperature increases, intermolecular bonds become weaker, freezes and molecules slow down.
What happens to a liquid when kinetic energy changes?Particle kinetic energy increases until the liquid reaches its boiling point. The potential energy of particles begins to increase at the boiling point. The particles move apart until the attractive forces hold them together no longer. The liquid has transformed into a gas at this point.
The mechanical energy of an object is the sum of its potential and kinetic energies. The potential energy of an object decreases as it falls, while the kinetic energy increases.
Thus, As the temperature drops, so does the vibration of the molecules, and thus the kinetic energy of the molecules.
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Drag the handle on the left and adjust the length of the box to 5 nm. (Because no other dimensions of the box change, its length can be used as a substitute for volume. ) Pump the pump handle once fully. This should add 40 to 50 gas molecules to the container. The pressure gauge will fluctuate a little bit, so watch it for a minute to estimate an average value. Record the pressure in the table.
In the Constant Parameter menu, select Temperature. Then drag the handle of the box to change its length to each of the other values in the data table. Record the pressure for each length
Gay-Law Lussac's explains how the molecules are related to one another. According to the legislation, the relationship between system's absolute temperature and pressure has always been direct.
The pressure rises as a result of gas molecule collisions. The system's pressure was between 7.2 and 8.2 atm as the temperature rose. The system's pressure ranged from 3.6 to 4.1 atm as the temperature dropped. Gay-Law Lussac's explains how the molecules are related to one another. The ideal gas equation for gaseous molecules provides the link between temperature and pressure. The temperature and the temperature have been directly proportionated. When a result, as pressure has increased, so has temperature and vice versa. The energy that raises temperature has been released as a result of the gas molecules' contact with the wall. The temperature rising reflects the pressure rise.
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A) Assuming the frequency factor and activation energy do not change as a function of temperature, calculate the rate constant for the reaction at 50 ∘C.B) If the activation energy for this reaction is 75 kJ/mol, at what temperature would the reaction rate be doubled?Express your answer as an integer and include the appropriate units.
[tex]Ae^(-75000/8.314*323)[/tex] = k0 is the rate constant for the reaction at 50 ∘C. If the frequency factor and activation energy do not change as a function of temperature.
A) The rate constant (k) of a reaction can be calculated using the Arrhenius equation:
k = [tex]Ae^(-Ea/RT)[/tex]
Where A is the frequency factor, Ea is the activation energy, R is the gas constant (8.314 J/mol*K), T is the temperature in Kelvin, and e is the natural logarithm base. Assuming the frequency factor and activation energy are constant, the rate constant can be calculated as follows:
T = 50 + 273 = 323 K
k = [tex]Ae^(-Ea/RT)[/tex] = [tex]Ae^(-75000/8.314*323) = k0[/tex]
Here, k0 is the rate constant at a reference temperature. To determine the rate constant at 50 ∘C, we need to know the value of k0, which is not provided.
B) The temperature at which the reaction rate would be doubled can be calculated using the Arrhenius equation as follows:
k1 = [tex]2k0 = 2Ae^(-Ea/RT)[/tex]
T1 = [tex](Ea/R) * ((-ln(2k0/A))^(-1))[/tex]
Here, k1 is the rate constant at the temperature T1, at which the reaction rate would be doubled. To calculate T1, we need to know the values of k0 and A, which are not provided.
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2
Use the information and chart to answer the following question.
A student is conducting a laboratory experiment with sulfur hexafluoride with a molar mass of 146.07 g/mol.
However, the student did not complete the required pre-laboratory notes.
Compound
SF6
Mass
235.7 g
Moles
Which selection would help the student complete the chart?
Particles
There are 1.6 moles and 9.7 * 10^23 molecules. Option D
What is the number of the moles?We must note that moles of the substance is something that we can be able to get when we look at the Avogardo's law. We know that the mole is the unit of the mount of the substance that is involved.
Now;
Number of moles = mass/molar mass
Number of moles = 235.7 g/146.1 g/mol
= 1.6 moles
If one mole contains 6.02 * 10^23 molecules
1.6 moles would contain; 1.6 * 6.02 * 10^23 /1
= 9.7 * 10^23 molecules
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calculate the number of grams of ammonium chloride that must be added to 2.00 l of a 0.500 m ammonia solution to obtain a buffer of ph
The number of grams of ammonium chloride that must be added to 2.00 l of a 0.500 m ammonia solution to obtain a buffer of pH 9.20 is 61.59 g.
Concentration of ammonia, [NH₃] = 0.500 M
Volume of solution = 2.00 L
pH of buffer = 9.20
Kb (NH₃) = 1.80x10⁻⁵
A basic buffer is NH₃/NH₄Cl, and the equivalent Henderson-Hasselbalch equation is;
pOH =pKb +log[BH⁺]/[B]
where kb = base dissociation constant
BH⁺ is conjugate acid = NH₄Cl
B is base = NH₃
from the question we know that pH = 9.20, therefore,
pOH= 14-pH = 14- 9.20 = 4.8
pKb = - log Kb = -log (1.80x10⁻⁵) = 4.74
[NH₄Cl] = 0.574 M
Moles NH₄Cl = molarity x volume
Moles NH₄Cl = 0.574 M x 2L = 1.15 moles
Mass NH₄Cl = moles x mass molar = 1.15 moles x 53.49 = 61.59 g
Your question is incomplete but most probably your full question was
Calculate the number of grams of ammonium chloride that must be added to 2.00 L of a 0.500 M ammonia solution to obtain a buffer of pH = 9.20. Assume the volume of the solution does not change as the solid is added. Kb for ammonia is 1.80×10−5.
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what are the rules for rounding off numbers ?
According to the rules of rounding off, if the number that we are rounding off if following by digits 5 below, we round the number up and if it the follow up digit is 5 or above, we round the number up.
Any particular number can be rounded to the nearest ten, to the nearest hundred, to the nearest thousand, and so on.
According to the rules of rounding off, if the number that we are rounding is followed by a digit that is equal to or greater than 5, that is, 5, 6, 7, 8, or 9, we round the number up. For example, 47 rounded off to nearest ten is 50.
And, if the number that we are are rounding is followed by a digit which is lower than 5, that is, 0, 1, 2, 3, or 4, then we round off the number down. For example, 22 rounded off to the nearest ten is 20.
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what makes an element stable or unstable. Explain the octet rule (do not copy the definition). Draw an illustration of any element (except the examples done in class) to illustrate the octet rule.
An electron should contain 8 electrons within its outer shell, according to the octet rule. Therefore, octet rule gives stability to an element.
What is octet rule?An electron should contain 8 electrons in its outer shell, according to the octet rule, which is a general chemical rule of thumb. Furthermore, it is observed that, with the exception of a few atoms from the p block identified as hydrogen, lithium, as well as helium, the majority of the elements from the s-block and p-block adhere to this norm.
For instance, the component carbon dioxide adheres to the "Octet Rule," which governs the binding of information. An electron should contain 8 electrons within its outer shell, according to the octet rule, a general chemical rule of thumb.
Therefore, octet rule gives stability to an element.
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For the frequency, 4.7 x 10^12 Hz, what is the wavelength?
What i the work aociated with decompoition of trinitrotoluene (TNT) upon detonation according to the following reaction at 320. 55 K
The work associated with the decomposition of trinitrotoluene (TNT) upon detonation according to the following reaction at 320. 55 KWork equals 17640 joules or 17.640 Kilojoules.
Remember the correct balanced chemical equation below:
C7H5N3O6(s) ----- >3/2N2(g)+5/2H2(g)+3O2(g)+7C(s)In the decomposition of TNT, the number of moles of gaseous molecules equals 7 moles of gases.
We are aware that only gaseous molecules will play a role in the TNT decomposition process. This is due to the phenomenon known as pressure-volume work, in which gases can alter the container's volume at constant pressure.
We can use the formula W= (PV) = PV, but PV can be equal to nRT (PV = nRT), so we can use W= (nRT) W= n RT. Here, n is the number of moles of gases, which is 7 mol, R is the gas constant, and T is the temperature, which is 303.10 K. Simply substitute the values that are already known for W = 7 mol 8.314 J.mol-1K-1
We can convert W to Kilojoules by using the equation 1 KJ = 1000 Joules, which yields work = 17.640 KJ.
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A medical technician needs to prepare a saline IV drip bag for a patient. Calculate and explain how they would prepare 500.00mL of a 0.154M saline solution, starting with water and solid NaCL.
The solution would be prepared by weighing 4.50 grams of NaCl and dissolving it in 500.00 mL of water.
Preparation of solutions500.00 mL saline solution of 0.154 M concentration is what the medical technician needs to prepare. We first need to know the amount of solid NaCl to be measured in order to arrive at the concentration.
Recall: mole = molarity x volume
Mole of 500.00 mL, 0.154 M solutions = 500/1000 x 0.154 = 0.077 moles.
Also recall: mass = mole x molar mass
The molar mass of NaCl is 58.44 g/mol
mass of 0.077 moles NaCl = 0.077 x 58.44 = 4.50 grams
In other words, 4.50 grams of NaCl will be weighed and dissolved in 500 mL of water in order to make 0.154 M, 500 mL saline solution.
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