There are 165600 coulombs passed through the solution if 11. 5 A of current was applied for 4. 00 h.
Calculation,
Formula used :
Q = It
Where Q = charge passing through the solution = ?
I = current passed through the solution = 11. 5 A
and , t = time = 4. 00 h
Putting the value of current , and time
Q = 11. 5×4. 00 h =11. 5× 46×3600 A×s = 165600 coulombs
The SI unit of charge is coulombs.
The SI unit of current is ampere.
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Which stage in the life cycle of a plant is represented in this picture?
Answer:
seed, sprout, small plant, and adult plant.
Explanation:
I didnt see the picture so I cant tell you what stage it represented but I told you all the stages of plants in life cycle.
The density of gold is 19.3 g/cm3. what is the volume in cubic centimeters of a piece of gold whose mass is 5.23 g?
If density of gold is 19.3g/cm3 amd mass is 5.23 g, then volume obtained is 0.27cm3.
Density is defined as how much a matter is packed in given area. It is represented by ρ.
ρ = m/ V
Given,
density of gold = 19.3 g/cm3
mass of gold = 5.23 g
As we know that,
density = mass/ volume
mass = density× volume
19.3 = 5.23 / volume
volume = 5.23/19.3
volume = 0.27 cm3.
Thus, if density and mass is given volume can be obtained.
Volume of gold is given as 0.27 cm3.
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Disadvantages of evaporation
Answer: The main disadvantages of evaporation are high capital, energy and maintenance costs; large size of apparatus; enhanced temperatures; corrosion problems; and scaling or foaming.
Explanation:
Potassium permanganate is a strong oxidizer that reacts explosively with easily oxidized materials. What is its formula?
Answer: KMnO4 (subscript 4)
What reagent is needed to convert 1-hexyne to 2-hexanone?
(a) o3 /zn/ h3o
(b) pcc (pyridinium chlorochromate)
(c) bh3 /h2o2 /oh-
(d) h2o/h
The reagent is needed to convert 1-hexyne to 2-hexanone is [tex]H_{2}O /H^{+}[/tex].
So , option D is correct one.
Ozonolysis is used to form aldehyde and ketone from alkene not alkyne .So option A is incorrect .
The reagent PCC is used as an oxidant and is used to convert primary and secondary alcohol into aldehyde and ketone.
The [tex]BH_{3} /H_{2} O_{2} /OH^{-}[/tex] is used to convert alkene into alcohol which is known as hydroboration reaction.
The addition of a hydroxyl group to an alkyne causes tautomerization which subsequently forms a carbonyl Markovnikov addition of a hydroxyl group to an alkyne forms a ketone. So, [tex]H_{2}O /H^{+}[/tex] is used to convert alkyne into ketone.This reagent is needed to convert 1-hexyne to 2-hexanone.
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How many amps are required to produce 75. 8 g of iron metal from a solution of aqueous iron(iii)chloride in 6. 75 hours?
The amount of current required to produce 75. 8 g of iron metal from a solution of aqueous iron (iii)chloride in 6. 75 hours is 168.4A.
The amount of Current required to deposit a metal can be find out by using The Law of Equivalence. It states that the number of gram equivalents of each reactant and product is equal in a given reaction.
It can be found using the formula,
m = Z I t
where, m = mass of metal deposited = 75.8g
Z = Equivalent mass / 96500 = 18.6 / 96500 = 0.0001
I is the current passed
t is the time taken = 75hour = 75 × 60 = 4500s
On subsituting in above formula,
75.8 = E I t / F
⇒ 75.8 = 0.0001 × I × 4500
⇒ I = 168.4 Ampere (A)
Hence, amount of current required to deposit a metal is 168.4A.
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A local plant nursery uses large sprinklers to water the plants twice a day. the water contains phosphorus, which is a fertilizer that helps plants grow. some of the water becomes runoff and ends up in nearby streams and lakes. this is an example of which type of short-term human-induced environmental change? eutrophication non-sustainable harvesting nonnative species introduction deforestation
Eutrophication
In an aged aquatic habitat like a lake, eutrophication is the progressive rise in the concentration of phosphorus, nitrogen, and other plant nutrients. As the volume of organic matter that can be converted into nutrients increases, the productivity or fertility of such an ecosystem also naturally rises.
What is Eutrophication ?Eutrophication may be caused by a number of things, including overuse of fertilisers, untreated sewage, the use of phosphorous-containing detergents, and industrial waste discharge.
Eutrophication naturally. Natural eutrophication is a process that develops in water resources over a very long period of time as a result of a slow buildup of nutrients and organic waste. Anthropogenic or cultural eutrophication.Learn more about Eutrophication here:
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Consider the gibbs energies at 25 ∘ c. substance δ∘f (kj·mol−1) ag (aq) 77. 1 cl−(aq) −131. 2 agcl(s) −109. 8 br−(aq) −104. 0 agbr(s) −96. 9 (a) calculate δ∘rxn for the dissolution of agcl(s)
The ∆G° for the dissolution of AgCl solid is 55.7 kJ/mol.
What is gibbs free energy?The gibbs free energy is termed as thermodynamic quantity which is equal to the enthalpy (of a system or process) subtracted by the product of the entropy and the absolute temperature.
The gibbs free energy of the reaction is given by:
∆G°(rxn) =sum of ([∆G°] products)- sum of ( [∆ G°] reactants)
Reaction can be given as:
AgCl(S) » Ag+ (aq) + Cl- (aq)
Gibbs free energy of silver ions = ∆G°f, (Ag+) = 77.1kJ/mol
Gibbs free energy of formation of chloride ions = ∆G°f, (Cl-)= -131. 2kJ/mol
Gibbs free energy of formation of silver chloride solid = ∆ G°f, (AgCl) = - 109.8kJ/mol
The gibbs free energy of the reaction of dissolution of AgCl) :∆ G°rxn:
∆G°rxn = (77.1kJ/mol) – (- 109.8kJ/mol)
55.7kJ/mol
Thus, we found that the ∆G° for the dissolution of AgCL solid is 55.7 kJ/mol.
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Why do you add hydroxide to your hexanediamine solution? what would occur if you did not add it?.
In the polymerization reaction, the lone pair electrons on the NH₂ groups of hexanediamine attack the C=O groups of the dicarboxylic acid in a nucleophilic substitution reaction as shown in the image.
Hydroxide is added to remove any H⁺ ions present and keep the hexanediamine in the deprotonated form, so that the NH₂ lone pair electrons are available for reaction.
What if you don't add it ?If hydroxide is not added, the NH₂ groups will get protonated by H⁺ ions present to give NH₃⁺ groups, which cannot react.
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How could you distinguish a compound from a mixture ? Give three characteristics for each case.
Answer:
compound(C) mixture(M)
Explanation:
COMPOUNDS MIXTURES
(C)In nature they are homogeneous. (M)They can be homogeneous as well as heterogeneous in nature.
(C)They have a definite melting and boiling point. (M)They do not have any definite melting or boiling point.
(C)Example: Baking soda, salt, etc.(M) Example: Salt and sand, sugar and water.
Which one of these molecules can be a reactant in a friedel-crafts reaction? a) aniline b) benzenesulfonic acid c) chloroethene d) bromobenzene e) p-bromonitrobenzen
The molecules can be a reactant in a Friedel-crafts reaction will be aniline .
The Lewis acid as well as the chlorine atom of such acid chloride form a complex during the Friedel-Crafts acylation reaction. Cleaving the complex's C-Cl link produces an acylium ion. The acylium ion undergoes resonance stabilized but also has a positive electrical charge upon that carbon atom.
The Friedel-Crafts alkylation reaction, an electrophilic aromatic substitution process, may add an alkyl to a benzene molecule. One illustration is the insertion of a methyl group into a benzene ring.
Therefore, the molecules can be a reactant in a Friedel-crafts reaction will be aniline .
Hence, the correct answer will be option (a)
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What is the product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes?
The product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes is ethyl 4- hydroxybutanoate .
Sodium borohydride is a relatively selective reducing agent Ethanolic solutions of Sodium borohydride reduces aldehyde , and ketone , in the presence of acid chloride , ester , epoxide , lactones , acids , nitriles , nitro groups.
The sodium borohydride does not reduce ester group because sodium borohydride is not strong enough and the electrophilicity at carbony carbon of ester is not more as compare toaldehyde , and ketone
The product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes is ethyl 4- hydroxybutanoate .
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(4) When the hydrocarbon was burned 0.20 mol of water were produced.
How many moles of hydrogen atoms are there in 0.20 mol of water?
Moles of hydrogen atoms
Answer:
.4 moles of hydrogen
Explanation:
Formula for water == H2 O
so you can see there are twice as many hydrogen moles as water moles
.2 * 2 = .4
When the hydrocarbon was burned 0.20 mol of water were produced. 0.40 moles of hydrogen atoms are there in 0.20 mol of water.
A mole is a unit used to measure the concentration of a chemical in chemistry. It is described as the quantity of a substance that includes exactly the same number of atoms as there are in exactly 12 grammes of carbon-12. This number can be an entity (such as an atom, molecule, ion, or other particle). The dozen, which represents 12 items, and the pair, which represents 2 items, are two more basic units of measurement that are comparable to the mole.
2 moles H / 1 mole H2O = x moles H / 0.20 moles H2O
2 moles H ×0.20 moles H2O = 1 mole H × x moles H2O
0.40 moles H = x moles H2O
So, there are 0.40 moles of hydrogen atoms in 0.20 moles of water.
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What can the presence of suffixes such as -ite,-ate,or -de in a chemical name indicate?
Answer: Most polyatomic ions are -ate, related ions that have 1 fewer oxygen atom are -ite (must have at least 1 oxygen tho) and nonmetals are ide.
Explanation:
Why do you add hydroxide to your hexanediamine solution? what would occur if you did not add it?.
In order to react with the hydrochloric acid (HCl) created when the hexanediamine combines with the adiptic acid, NaOH was added to the hexanediamine solution. By combining with the HCl to create NaCl and water, the NaOH preserves the pH of the solution. HCl is taken out of the solution and the reaction is pushed in the direction of the products.
Hexanediamine solutionA C6 alkane-alpha, omega-diamine is hexanediamine. It serves as a xenobiotic metabolite for humans. It comes from a hydride.
Weight in Formula: 116.21Indication: 1,6-NH2(CH2)6NH2Risk Information: CorrosiveDensity: 0.854 (g/mL).Heat of Boiling (°C): 205Temp. Freeze (°C): 39–42Water and Alcohol Are Both Slightly SolubilizedSynonyms include 1,6-diaminohexane and hexamethyleneediamine.Shelf Life: 36 monthsWhat is the purpose of hexanediamine?
Hexanediamine is mostly used to make adhesive resins, resins for paper manufacturing, resins for water treatment, and unaltered resins. Hexanediamine is only used in industrial products; it is unlikely that consumers will come into touch with it.learn more about hexanediamine solution here
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A gas sample occupies 10. 28 l at 8. 34 atm. its volume at 6. 98 atm (assuming constant temperature conditions) is:____.
a. 12. 28
b. 8. 60
c. 15. 61
d. 5. 66
12.28 L volume at 6.98atm in sample gas occupies 10. 28 l at 8. 34atm. Hence, option A is correct.
What is ideal gas?Ideal gas is a hypothetical gas whose molecules occupy negligible space and have no interactions, and which consequently obeys the gas laws exactly.
In the limit of low pressures and high temperatures, where the molecules of the gas move almost independently of one another, all gases obey an equation of state known as the ideal gas law:
PV = nRT,
P is pressure of gas (atm)T is temperature of gas (K)where n is the number of moles of the gas R is the universal gas constant, 8.3145 joules/K.When Temperature is constant so, it follow Boyle's law:
P1 V1 = P2 V2
P1 = 8.34atm, V1 = 10.28 L, P2 = 6.98atm
V2 = P1 V1 / P2
V2 = 8.34atm x 10.28 / 6.98atm
V2 = 12.28 L
12.28 L volume at 6.98atm in sample gas occupies 10. 28 l at 8. 34atm. Hence, option A is correct.
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Which acid or base (along with its corresponding salt) should be used to generate a buffer solution with ph around 3. 5?
Formic acid, Sodium formiate will generate a buffer solution with pH around 3. 5.
It must consider the acid whose pKa = pH in order to choose the base or acid that can produce a buffer solution with such a pH of about 3.5.
However, it also need to consider buffer capacity, which is a factor that can alter the pH of a solution by one unit in a liter.
The connection between the components' concentrations and their concentrations themselves affects buffer capacity in addition to their individual concentrations.
Therefore, Formic acid, Sodium formiate will generate a buffer solution with pH around 3. 5.
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When 1. 0 l of 0. 00010 m naoh and 1. 0 l of 0. 0014 m mgso4 are mixed, would a precipitate be formed? show work
When 1. 0 l of 0. 00010 m NaOH and 1. 0 l of 0. 0014 m mgso4 are mixed, there will be no precipitate formed.
What is a precipitate?The precipitate is the solid concentration of a substance that is collected over a solution.
First, we determine the concentration of magnesium and hydroxide
(Mg2+) = 7.00 × 10⁻⁴
(OH−) = 5.00 × 10⁻⁵
Now, we calculate the solubility quotient
Qc = (Mg2+) (OH−) ²
Qc = 7.00 × 10⁻⁴ x (5.00 × 10⁻⁵)²
Qc = 1.75 x 10⁻¹²
The solubility product of the magnesium hydroxide is 1.80 x 10⁻¹¹ which is more than the solubility quotient. Thus, there will be no precipitate form.
Thus, there will be no precipitate formed because the solubility quotient we calculated is less than the solubility product.
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Determine which choice is an example of an exothermic process. a. none of these b. freezing water c. melting ice d. baking bread
option (b) freezing water is the correct answer.
Freezing water is an example of an exothermic process.
What is an exothermic process?An exothermic reaction is one in which energy is given off as heat or light. In contrast to an endothermic process, which draws energy from its surroundings, an exothermic reaction transfers energy into the environment.Heat is released during an exothermic reaction, raising the temperature of the immediate environment. The environment is cooled through an endothermic process that absorbs heat.We can observe that melting of an ice is an example of endothermic process whereas, freezing of water is considered to be an example for exothermic process.
Water releases heat when it solidifies, warming the area around it. As a result, freezing is an exothermic process.
Some of the examples for exothermic process can be as follows:Making of an Ice Cube. Making an ice cube is a process of liquid changing its state to solidSnow Formation in CloudsBurning of a CandleRusting of Iron Burning of SugarFormation of Ion PairsIn the above given options,
In melting ice, it is an endothermic response because it releases heat, allowing a transition to take place. The procedure is endothermic since the ice cube requires heat to melt.In baking bread, the dough's ingredients, including the flour, yeast, and others, are heated. They absorb the heat, which triggers chemical processes.To learn more about exothermic process visit:
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Answer:
B.) Freezing water
Explanation:
I got it correct on founders edtell
The volume of a rock weighing 1. 705 kg is 334. 5 ml. What is the density of the rock?
The density of rock weighing 1.705 kg is 3.213 gm/ml.
Explanation:
Given;
Volume of rock = 334.5 ml
Weight of rock = 1.075 kg = 1075 gm
By the formula,
Density = Weight in gm/Volume in ml
= 1075/334.5 gm/ml = 3.2137 gm/ml
Therefore, density of rock is 3.213 gm/ml.
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A 45. 0 l gas cylinder contains 988 g he at 23 °c. what is the pressure inside the cylinder? (r = 0. 08206 l⋅atm/mol⋅k)
a. 10. 4 atm
b. 533 atm
c. 41. 4 atm
d. 133 atm
e. 101 atm
A 45. 0 L gas cylinder contains 988 g He at 23 °C then pressure inside the cylinder is 134.67 atm.
Calculation,
Formula used :The ideal gas equation is given as,
PV = nRT ....(i)
Where , P is pressure of the gas = ?
V = volume of the gas = 45. 0 L
R = universal gas constant = 0. 08206 L⋅atm/mol⋅K
T = Temperature = 23 °C = 23 + 273 = 299 K
n = number of moles = given mass/ molar mass = 988 g/4 = 247 moles
Putting the value of P , V , T , R and n in equation (i) we get
P×45. 0 L = 247 moles× 0. 08206 L⋅atm/mol⋅K×299 K
P = 247 moles× 0. 08206 L⋅atm/mol⋅K×299 K /45. 0 L = 134.67 atm
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Libr (s) → li (aq) br- (aq) δh = -48. 8 kj/mol in a coffee-cup calorimeter you dissolve 21. 4 g of this salt in 111 g of water at 25. 1 oc. what will be the final temperature of the solution formed?
Final temperature of the solution formed is 50.93ºC
As we know,
heat = mass x specific heat x change in temperature
q = mC∆T
where, m = 111 g water
C = 4.184 J/g/deg
∆T = ?
To find heat we need to first find moles Libr used in this reaction:
21.4 g Libr x 1 mole/86.84 g = 0.246 moles
Therefore,
q = 0.246 moles x (-48.8) kJ/mol = -12.00 kJ = -12000 J (since it is negative, this indicates an exothermic reaction, so temperature of solution will increase).
-12000 J = (111g)(4.184 J/g/deg)(∆T)
∆T = -25.83 degrees
Final temperature = 25.1º - (-25.83º) = 50.93ºC
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Calculate the average acceleration from the following data points: v1 = 150 m/s, v2 = 975 m/s, t1 = 15 s, t2 = 55 s
The average acceleration from the following data points is 20.625 m/s^2.
We know that average acceleration = change in speed / change in time
here,
change in speed = v2-v1
= 975-150
= 825 m/s
change in time = t2 - t1
= 55 - 15
= 40 s
now, putting all the values, average acceleration = 825 / 40
= 20.625 m/ s^2 .
what is acceleration?
The rate at which an entity's velocity with regard to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.
The SI unit of acceleration is metre per second square (m/s^2).
An average acceleration the speed at which velocity changes, the evolution of velocity through time, or the instantaneous acceleration ( acceleration at a given moment ) .
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Think critically...
Q7. Bridges are made from materials that contract and expand as the temperature changes, so
they cannot be fastened firmly to the bank of a river or lake. The photographs below show an
expansion joint at the end of a bridge in winter and in summer.
www
(A)
(B)
Which season is shown in each picture? Explain how you know?
The season that is shown in the picture attached is that:
For the red - summer For the black - winterWhat is the season about?Metals are known to often expand due to different factor. For example, the rails of a railway are known to often expand in summer and they tend to contract in winter. This tend to make the gaps kept to be between successive rails and it is one that allow for expansion.
Note also that in Summer the expansion joint will tend to have little space as the two sides of the bridge is said to expand because of the heat and in terms of winter, it contract and there are bigger space as they tend to contract in the cold.
Hence, The season that is shown in the picture attached is that:
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When hexan-1-ol is treated with conc. h2so4 at moderate temperatures, ________ is formed via a(n) ________ mechanism
When hexan-1-ol is treated with conc. H₂SO₄ at moderate temperatures, Di-n-hexyl ether is formed via SN₂ mechanism.
SN₂ Mechanism is mechanism involving the factors of steric hindrance following the order of 1° > 2° > 3°. It is a Nucleophilic substitution reaction.
Williamson Ether Synthesis is the synthesis of ether through SN₂ mechanism in which an ether is treated with conc. H₂SO₄ at moderate temperature.
When hexan-1-ol is treated with conc. H₂SO₄ at moderate temperatures, Di-n-hexyl ether is formed as below:
CH₃CH₂CH₂CH₂CH₂CH₂OH +Conc. H₂SO₄-->(CH₃CH₂CH₂CH₂CH₂CH₂)₂0
Hexan-1-ol Di-n-hexyl ether
Williamson Ether Synthesis is a reaction involving a alcohol that is deprotonated to form an ether.
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What atomic or hybrid orbitals make up the sigma bond between c1 and c2 in ethane, ch3ch3 ?
Atomic or hybrid orbitals make up the sigma bond between c1 and c2 in ethane, ch3ch3 are one s orbital and 2 p orbital
Sigma bonds are the most powerful type of covalent chemical link. They are generated by atomic orbitals overlapping head-on. For diatomic molecules, sigma bonding is most readily explained using the language and tools of symmetry groups.
Chemical covalent bonds are sigma bonds and pi bonds. The overlap of atomic orbitals creates sigma and pi bonds. Sigma bonds are produced by overlapping from end to end, whereas Pi bonds are created when the lobe of one atomic orbital overlaps another.
Sigma bonding can be seen in the link between two hydrogen atoms. Sigma bonds are also formed between the sp3 orbitals of hybridized carbon and the s orbitals of hydrogen in methane.
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I WILL MARK U BRAINLIEST IF U ANSWER THIS QUESITON
Answer:
c ) 16
Explanation:
C4 H10 O + 6 O2 =====> 4 CO2 + 5 H2O
1 + 6 + 4 + 5 = 16
Answer:
C.) 16
Explanation:
An equation is balanced when there are equal amounts of each element on both sides of the reaction. These values can be modified by adding coefficients.
The unbalanced equation:
C₄H₁₀O + O₂ -----> CO₂ + H₂O
Reactants: 4 carbon, 10 hydrogen, 3 oxygen
Products: 1 carbon, 2 hydrogen, 3 oxygen
The balanced equation:
1 C₄H₁₀O + 6 O₂ -----> 4 CO₂ + 5 H₂O
Reactants: 4 carbon, 10 hydrogen, 13 oxygen
Products: 4 carbon, 10 hydrogen, 13 oxygen
Now, you can add the coefficients:
1 + 6 + 4 + 5 = 16
Octanol is slightly soluble in water, and water is very soluble in octanol. why is it important to presaturate octanol with water and water with octanol when measuring ow?
N-Octanol and water are chosen because the connection between a substance's hydrophilicity and lipophilicity is measured by [tex]K_{OW}[/tex] (n-Octanol/Water partition coefficient). When a chemical is more dissolves in fat-like solvents like n-octanol, the value is more significant than one, when it's more dissolved in water, the value is lower.
What is the partition coefficient?
The partition coefficient for the two-phase network comprising n-octanol and water is known as the [tex]K_{OW}[/tex] value. N-Octanol-Water Partition Ratio is another name for it.The connection between a substance's hydrophilicity (its ability to dissolve in water) and lipophilicity (its ability to dissolve in fat) is measured by [tex]K_{OW}[/tex]. The value is bigger if a drug is more accessible in fat-like liquids like n-octanol and less if a compound seems more water-soluble.Owing to linkage or fragmentation, substances that are involved in the octanol-water combination as multiple synthetic entities are each given a unique [tex]K_{OW}[/tex] ratio.So, N-Octanol is chosen because it has a carbon/oxygen ratio that is comparable to that of lipids and because it shows both hydrophobic and hydrophilic properties. N-octanol, therefore, resembles the makeup and characteristics of cells and other living things.
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A membrane is impermeable to charged molecules and does not allow passage of ions because of?
A membrane is impermeable to charged molecules and does not allow the passage of ions because the charged molecules possess polarity and the membrane possesses hydrophobic interiors.
Hydrophobic ions:Charged hydrophilic molecules of all sizes, from small molecules to giant enzymes, can now be made more soluble via a technique called hydrophobic ion pairing. Hydrophobic molecules having hydrophilic moieties are ionically coupled with charged hydrophilic molecules, and the resulting uncharged complex is water-insoluble and will precipitate in aqueous conditions.
With polar solvents like water or alcohol, hydrophilic compounds can easily establish hydrogen bonds. Ionic (charged) groups with oxygen or nitrogen atoms make up the chemical structure of hydrophilic compounds. Typically, a substance's hydrophilicity is determined by its polarity. A molecule will be hydrophobic overall even if it has polar covalent bonds and these bonds are distributed symmetrically.
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What is the molality of a solution prepared by dissolving 3. 41 g of c6h12o6 in 85 ml of water:__________
When 3. 41 g of C6H12O6 is dissolved in 85 ml of water the molality is 2.2m.
What is molality?Molality is the amount of a substance dissolved in a certain mass of solvent.
Molality = moles of solute/ mass of solvent (kg)
Given,
Mass of solute = 3.14g
Molar mass of solute = 180 g
Mole of solute= given mass/molar mass
= 3.14/180
= 0.0189 mol.
Volume of solvent = 85 ml
Density of water = 1 g/cm3
Density = mass/ volume
mass = density × volume
= 1× 85
= 85g
Molality = (0.0189/ 85) × 1000
= 2.2m
Thus we find that the molality of given solution is 2.2m.
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