How many diagonals does a regular n-gon have? ( An n-gon is a regular polygon with n sides)

Two different integers are the same numbers, which have different signs.

An integer is a number that includes negative and positive numbers, including zero. It does not include any decimal or fractional part. A few examples of integers are: -5, 0, 1, 5, 8, 97.

Given that,

x, y, and z are three integers. They follow the one condition: x-y-z = 0.

Any number in the number system that has only two signs, either + or -, So we consider that the third integer is 0 because 0 is a whole number that has neither a positive nor a negative sign.

The remaining two integers are the same numbers, but they have different signs to follow the given condition.

x-y-z = 0

x = y+z

Let y,z are the same numbers, They have different signs and x = 0.

Note: The value of x is always negative and y's value is always positive.

Example:

x = 0,  y = +6,  z = -6

x-y-z = 0

x = y+z

0 = +6-6

0 = 0

Hence, two different integers are the same numbers, which have different signs.

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By the use of the completing the square method, the maximum height of the path of the water 3 ±√29/4 + 9 m.

What is called distance?

h = -4x² +24x -29

Now we have;

0 = -4x² +24x -29

-4x² +24x -29= 0

x² - 6x = -29/4

(x - 3)² = -29/4 + 3²

(x - 3)² =  -29/4 + 9

x = 3 ±√29/4 + 9 m

Therefore, the maximum height of the path of the water  x = 3 ±√29/4 + 9 m

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Answer:
the answer to the question is answer C

Answer:

Step-by-step explanation:

B is your answer

Answer:

2

Step-by-step explanation:

Your slope is your change in y over your change in x.  The ordered pair is in the form of (x,y), so you subtract the y's and put that in your numerator (top)and subtract your x's and put that in your denominators (bottom).

2 - (-4) would be your top number.  To subtract a negative number is the same as adding a positive, so 2 - (-4) is the same as 2 +4, so your top number is 6.  

Now, to find the bottom number, you subtract the x's.

5-2 which is 3.

We now have the top and the bottom number

6/3 which is the same as 2.

Check the picture below.

well, let's take a peek at the distances of each side.

[tex]~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad B(\stackrel{x_2}{4}~,~\stackrel{y_2}{3}) ~\hfill AB=\sqrt{[ 4- 0]^2 + [ 3- 0]^2} \\\\\\ ~\hfill AB=\sqrt{25}\implies \boxed{AB=5} \\\\\\ B(\stackrel{x_1}{4}~,~\stackrel{y_1}{3})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-3}) ~\hfill BC=\sqrt{[ 4- 4]^2 + [ -3- 3]^2} \\\\\\ ~\hfill BC=\sqrt{36}\implies \boxed{BC=6}[/tex]

[tex]C(\stackrel{x_1}{4}~,~\stackrel{y_1}{-3})\qquad A(\stackrel{x_2}{0}~,~\stackrel{y_2}{0}) ~\hfill CA=\sqrt{[ 0- 4]^2 + [ 0- (-3)]^2} \\\\\\ ~\hfill CA=\sqrt{25}\implies \boxed{CA=5} \\\\\\ \textit{so it's an \underline{isosceles triangle}}[/tex]

89% of pebbles weigh more than 2.1 grams.

What is a percentage?

Given,

         Mean = 2.6

           SD = 0.4

As we have to find the percentage of pebbles weighing more than 2.1, we have to find the z-score for 2.1 first.

             [tex]z = \frac{x- mean}{SD}[/tex]

             [tex]z = \frac{2.1 - 2.6}{0.4}[/tex]

             [tex]z = -1.25[/tex]

Now we have to use the z-score table to find the percentage of pebbles weighing less than 2.1

So,

   [tex]P ( x < 1.25 ) = 0.10565[/tex]

This gives us the probability of P(z<-1.25) or P(x<2.1)

To find the probability of pebbles weighing more than 2.1

[tex]P ( x > 2.1 ) = 1 - P( x < 2.1 ) = 1 - 0.10565 = 0.89435[/tex]

Converting into percentage

0.89435 × 100 = 89.435 %

Rounding off to nearest percent   =89%

Therefore, 89% of pebbles weigh more than 2.1 grams.

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Answer:

484 Students

Step-by-step explanation:

This is simple probability. Assuming 22/80 students walk to school within a small population, and there are 1760 students at the school, there should be (22/80)*1760 students that walk to school in total. (This is just theoretical). This is 484 students.

The secant of circle D is the 'line GH'. Where the line segment EF is the diameter of the circle, line segment DC is the radius, and the ray AB is the tangent of the given circle.

The line that passes through the circle and touches the circle at two points is said to be a secant line of the circle.

The given circle D has a center at D.

The radius of the circle is given by the line segment CD

The diameter (or) the longest chord of the circle is given by the line segment EF

The ray AB passes touches the circle at point B, which is called the tangent of the circle.

Where the line GH passes through the circle and touches at two points. So, this line GH is said to be the secant of the circle.

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Disclaimer: The given question is incomplete(needs a diagram). Here is the required diagram attached.

Question: In circle D, which is a secant?

a) EF

b) DC

c) Line segment AB

d) Line GH

Answer:

ray ab

Step-by-step explanation:

Yes. [tex]f(x)[/tex] is a PDF if

• [tex]f(x) \ge 0[/tex] for all [tex]x[/tex] in the support; this is true, since [tex]e^{-x}>0[/tex] for all [tex]x[/tex], and multiplying a positive number [tex]x[/tex] doesn't change this fact;

• the integral of [tex]f(x)[/tex] over its support is 1; this is also true, since

[tex]\displaystyle \int_{-\infty}^\infty f(x) \, dx = \int_0^\infty xe^{-x} \, dx = 1[/tex]

which can be computed by parts.

The solution to the given differential equation [tex]\frac{dy}{dx} = e^{4x+5y}[/tex] is , [tex]\frac{e^{-5y}}{-5}=\frac{e^{4x}}{4} +c[/tex], where c is constant of integration.

For given question,

We have been given a differential equation [tex]\frac{dy}{dx} = e^{4x+5y}[/tex]

We know that for any real number a, m, n,

[tex]a^{m + n} = a^m \times a^n[/tex]

⇒ dy/dx = [tex]e^{4x}[/tex] × [tex]e^{5y}[/tex]

Separating the variables (x and its differential in one side and y and its differential in another side )

⇒ [tex]\frac{1}{e^{5y}}[/tex] dy = [tex]e^{4x}[/tex] dx

⇒ [tex]e^{-5y}[/tex] dy = [tex]e^{4x}[/tex] dx

Integrating on both the sides,

⇒ [tex]\int e^{-5y}[/tex] dy = [tex]\int e^{4x}[/tex] dx

We know that, [tex]\int e^{ax}\, dx=\frac{e^{ax}}{a} +C[/tex]

⇒ [tex]\int e^{4x}\, dx=\frac{e^{4x}}{4} +C[/tex]

and [tex]\int e^{-5y}\, dy=\frac{e^{-5y}}{-5} +C[/tex]

So the solution is, [tex]\frac{e^{-5y}}{-5}=\frac{e^{4x}}{4} +c[/tex], where c is constant of integration.

Therefore, the solution to the given differential equation [tex]\frac{dy}{dx} = e^{4x+5y}[/tex] is , [tex]\frac{e^{-5y}}{-5}=\frac{e^{4x}}{4} +c[/tex], where c is constant of integration.

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Based on the given tast content; the ratio of green cars to white cars is 1 : 2 and it can be said that there are twice as many white cars as green cars.

Ratio of green cars to white cars = 24 : 48

= 24 / 48

= 1 / 2

Ratio of green cars to white cars = 1 : 2

Therefore, the ratio of green cars to white cars is 1 : 2 and it can be said that there are twice as many white cars as green cars

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On a number line, an absolute value equation that has the given solution set is |m - 4| = 2.

By critically observing the given question, we can infer and logically deduce that the solution sets for this absolute value equation is given by:

m = {2, 6}

Next, we would calculate the mean of the solution sets as follows:

m₁ = (2 + 6)/2

m₁ = 8/2

m₁ = 4.

Also, we would calculate the difference in the solution sets as follows:

m₂ = (6 - 2)/2

m₂ = 4/2

m₂ = 2.

Mathematically, the absolute value equation is given by:

|m - m₁| - m₂ = 0

|m - 4| - 2 = 0

|m - 4| = 2.

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Answer:

11÷7=[tex]\frac{11}{7}[/tex]

v= 11/7

The probability that a class of 50 has an average midterm mark that is less than 75 is value=0

Average is the mathematics mean, and is calculated by means of adding a group of numbers and then dividing with the aid of the count of these numbers. for instance, the average of 2, three, three, five, 7, and 10 is 30 divided with the aid of 6, that is five.

The common is described as the implied value that is identical to the ratio of the sum of the number of a given set of values to the whole wide variety of values gift within the set.

There are three primary sorts of common: imply, median, and mode. each of those techniques works slightly differently and frequency effects in barely specific regular values. The suggestion is the maximum normally used average. To get the suggested fee, you add up all of the values and divide this total by using the number of values.

The probability that a class of 50 has an average midterm mark that is less than 75

n = 50

P(<75)=P(Z<75)

P(Z<75−786√50)

P(Z<−3.5355)

We will look for the value in the StandardNormal able. We will get the value=0

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Step-by-step explanation:

there are some formulas to know about this.

I am sure you discussed this in class.

when 2 lines (originating from the same point) cut through the same circle creating some circle segments (such lines are also called Secants), then there is a relationship in the lengths of the different parts of the lines among themselves.

the outer portion of such a line multiplied with the length of the whole line to the second point it intersects the circle is the same for every secant from the same point through the same circle.

that means in our case :

7(x - 6) = 6(x - 3)

7x - 42 = 6x - 18

x = 24

and so,

EG = (x - 3) + 6 = (24 - 3) + 6 = 21 + 6 = 27

The complete questions is:

The ice cream shop needs 5 pounds of strawberries for every gallon of strawberry ice cream. the shop chooses to produce 4 gallons of chocolate ice cream. how many pounds of strawberries should the shop purchase?

Pounds of strawberry ice cream needed to be bought by the shop exists 20 pounds.

The ice cream shop requires 5 pounds of strawberries for every gallon of strawberry ice cream and the shop chooses to make 4 gallons of ice cream,

Quantity of chocolate ice cream created in the shop = 4 gallons

Quantity of strawberries needed for each gallon of ice cream = 5 pounds

Pounds of strawberries needed to be bought by the shop = Quantity of chocolate ice cream created by the shop [tex]*[/tex] Quantity of strawberries needed for each gallon of ice cream

[tex]$= 4 * 5[/tex]

= 20 pounds.

Pounds of strawberries needed to be bought by the shop exists 20 pounds.

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Answer:

12

Step-by-step explanation:

The amount in the ira's account s = $187,159.62.

How do you interest rate?

Future Value of an Ordinary Annuity

[tex]s = R(( 1 + i)^{n} - 1 ) / i[/tex]

where

S = the future value;

R = the periodic payment;

i = the interest rate per period;

n = the number of periods.

[tex]s = 5000 ( 1 + 0.032)^{25} - 1)/ 0.032[/tex]

[tex]s = 5000((1.032)^{25} - 1 )/0.032[/tex]

[tex]s = 5000( 2.19782157471 - 1)/0.032[/tex]

[tex]s = 5000(1.19782157471)/0.032[/tex]

[tex]s = 5000 * 37.4319242096[/tex]

s = $187,159.62

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The general equation for a circle is [tex](x-h)^2+(y-k)^2=r^2[/tex], where [tex](h,k)[/tex] is the centre of the circle and [tex]r[/tex] is the radius.

First, we can determine the centre of the circle.

( _ , _ )

The point directly on top is (4,7). Because it lies on the same vertical line as the centre, they have the same x-coordinate.

(4, _ )

The point directly to the right of it is (7,4). Because it lies on the same horizontal line as the centre, they have the same y-coordinate.

(4,4)

Therefore, the centre of the circle is (4,4). Plug this into the general equation:

[tex](x-h)^2+(y-k)^2=r^2\\(x-4)^2+(y-4)^2=r^2[/tex]

Now, we can determine the radius of the circle.

To do this, we can calculate the distance between the centre of the circle and one of the given points that lie on the circumference.

The centre is (4,4), and one of the points is (4,7). Because they only have a difference of 3 units in the y-direction (and none in the x-direction), this means that the radius is 3 units. Plug this into the general equation:

[tex](x-4)^2+(y-4)^2=r^2\\(x-4)^2+(y-4)^2=3^2\\(x-4)^2+(y-4)^2=9[/tex]

[tex](x-4)^2+(y-4)^2=9[/tex]

Answer:

160

Step-by-step explanation:

I multiplied the amount of each item to get to the answer:

- 8 shirts

- 4 pairs of pants

- 5 pairs of shoes

8 x 4 x 5 = 32 x 5

32 x 5 = 160

hope this helps!

Answer:

D

Step-by-step explanation:

I did the assignment

hope this helps :)

The solution to given expression tan(2θ) is 22.615°

For given question,

We have been given an expression tan(2θ)

Given that cos(θ) = 5/13, and θ is in quadrant 1.

We know that the trigonometric identity

sin²θ + cos²θ = 1

⇒ cos²θ = (5/13)²

⇒ sin²θ = 1 - 25/169

⇒ sin²θ = 169 - (25/169)

⇒ sin²θ = 144/169

⇒ sin(θ) = 12/13

We know that the identity cos(2x) = cos²x - sin²x

⇒ cos(2θ) = cos²θ - sin²θ

⇒ cos(2θ) = 25/169 - 144/169

⇒ cos(2θ) = -119/169

And sin(2x) = 2sin(x)cos(x)

⇒ sin(2θ) = 2sin(θ)cos(θ)

⇒ sin(2θ) = 2 × 12/13 × 5/13

⇒ sin(2θ) = 120/169

We know that, tan(x) = sin(x)/cos(x)

⇒ tan(2θ) = sin(2θ)/cos(2θ)

⇒ tan(2θ) = (120/169) / (-119/169)

⇒ tan(2θ) = 120 / (-119)

⇒ tan(2θ) = -1.008

Since θ is in quadrant 1, tan(2θ) = 1.008

⇒ 2θ = arctan(1.008)

⇒ 2θ = 45.23

⇒ θ = 22.615°

Therefore, the solution to given expression tan(2θ) is 22.615°

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Answer:

35.56

Step-by-step explanation:

The arrangement of the fractions given from the lowest to the highest is illustrated

a. 1/2, 3/4, 5/10, 9/20.

We can change this to percentages.

1/2 = 1/2 × 100 = 50%

3/4 = 3/4 × 100 = 75%

5/10 = 5/10 × 100 = 50%

9/20 = 9/20 × 100 = 45%

Therefore, the arrangement will be 9/20, 5/10, 1/2, and 3/4.

b. 3/8, 1/15, 3/20, 9/10

3/8 = 37.5%

1/15 = 6.67%

3/20 = 15%

9/10 = 90%

The arrangement will be 1/15, 3/20, 3/8, and 9/10.

c. 7/9, 1/3, 5/6, 3/4

7/9 = 77.7%

1/3 = 33.3%

5/6 = 82%

3/4 = 75%

The arrangement will be 1/3, 3/4, 7/9, and 5/6.

d.3/12, 1/5 7/15 1/20

3/12 = 25%

1/5 = 20%

7/15 = 48%

1/20 = 5%

The arrangement will be 1/20, 1/5, 3/12, and 7/15.

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We can comment that the maximum value of the given data is 0.2, maximum value is 42. The interquartile range is 15 to 37, first and third quartile values are 15 and 37 respectively. It can also be inferred from the box plot that there are no outliers. The median of the given data, as shown in the box plot, is 28.

What is a box plot?

A box and whisker plot, often known as a box plot, shows a data set's five-number summary. A box is drawn from the first quartile to the third quartile in a box plot. At the median, a vertical line passes through the box. The five-number summary of a box plot includes the following:

It also tells if there are any outliers in the data.

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Answer:

Step-by-step explanation:

0= x2 – 2x – 3

a = 1, b = -2 and c = -3.

Answer:

A on edge

Step-by-step explanation:

Give me the brainiest please

Answer: Anna got 30

Step-by-step explanation: 2x+3y=25

15+10=25

Answer:

6

Step-by-step explanation:

The growth factor is the same as the base of the exponential factor.

The value of the function [tex]$f(x)=(1/3)(6)^x[/tex] growth factor exists 6.

function [tex]$f(x)=(1/3)(6)^x[/tex]?

Given: [tex]$f(x)=(1/3)(6)^x[/tex]

For any equation [tex]$ f(x)=ab^x[/tex]

Let, 'a' exists the initial value

b exists the growth or decay factor.

When the value of b exists greater than 1 then its growth factor

when the value of b exists between 0 and 1 then it exists a decay factor

Let x exists the number of years

Given function, [tex]$ f(x)=(1/3)(6)^x[/tex]

The value of b exists 6.

So the growth factor exists 6.

Therefore, the correct answer is option c. 6.

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Answer:

x = 4

Step-by-step explanation:

These triangles are similar by the AA Similarity Postulate.

12 + 4 = 16

(5x - 2)/12 = 6x/16 (3x/8)

Cross multiply: 8(5x - 2) = 12(3x)

40x - 16 = 36x

4x - 16 = 0

4x = 16

x = 4

Small numbers that are added to avoid unfair scoring of low-probability outcomes are called pseudocodes

From the statement, we have the following highlights:

The term for the statements in the above highlight is pseudocodes

This is because pseudocodes are false codes or small numbers

Hence, the small numbers that are added to avoid unfair scoring of low-probability outcomes are called pseudocodes

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Answer:1/2 of the teapot

Step-by-step explanation: Since 1/3 of the teapot is equal to 2/3 of the container, 1/3 of the container is equal to half of 1/3 of the teapot. We know that 1/3 divided by 2 equals 1/6, so 1/6 of the teapot is equal to 1/3 of the container. There are 3-thirds in a whole so we have to multiply 1/6 by 3. This equals 3/6 or 1/2.