Electrons that are located in the outermost orbit in the Bohr model of a boron atom will be 3.
A nucleus with six neutrons and five protons makes up the Bohr model of boron. The K-shell and L-shell electron shells around the nucleus The valence electrons, which make up three of the electrons in the outermost shell of the Bohr diagram, are also present. The orbits of the electrons around the small nucleus are described by the Bohr model of boron.
It utilizes a number of different electron shells, including K, L, M, and N. The number of electrons that each shell can hold varies, with the shell closest to the nucleus having the least energy. The energy levels increase as the shell recedes more. According to the Bohr model, the electrons in an atom may be seen to orbit the nucleus in a variety of orbits with differing energies.
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what effect does the amplitude setting on the function generator have on oscope display of the voltage in the small coil?
As the amplitude increases from the wave generator, the Voltages passing through the inductor will be higher. and consequently, the current passing through the inductor will also be higher Remember that when a voltage is applied across the inductor, the current is driven in the inductor due to the applied voltage.
When the applied voltage is sinusoidal it creates a sinusoidal current in the inductor with the same frequency as the applied voltage. As this current increases, it creates an induced potential difference proportional to the rate of change of current, and hence there is a sinusoidal induced voltage in the Inductor.
The function generator's amplitude control changes the voltage difference between the output signal's high and low voltage. Its direct current offset control changes the signal's average voltage with regard to the ground. A function generator is equipment to generate input functions for your circuit. It can generate sinewaves, square waves, triangular waves, modulated signals, and so on. An oscilloscope is equipment to display the signals in the circuit.
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an athlete runs with velocity 12 km/h12 km/h for 55 minutes, 14 km/h14 km/h for the next 22 minutes, and 19 km/h19 km/h for other 66 minutes. compute the total distance traveled. (use decimal notation. give your answer to two decimal places.)
Total distance travelled by the athlete is 37.03km as it is calculated by the expression of distance in terms of speed and time.
Velocity is the distance travelled by a moving body per unit time . Distance travelled is the speed unit time.here an athlete runs with velocity 12 km/hr in 55 min, 14 km/hr in next 22 min and 19 km/hr for the next 66 min.
55min= 55/60hr ,
22min=22/60hr ,
66 min= 66/60 hr.
Distance= speed . time
Putting these in the expression
Total speed= 55/60 hr..12 km +22/60 hr. .14 km/hr + 66/60hr . 19 km/hr.
= 37.03 km
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4. how can we change the speed of waves in a string? a) by changing the supplied frequency b) by changing the string tension. c) by changing the size (gauge) of the string d) either b) or c) will do
We change the speed of waves in a string option a. by changing the supplied frequency.
Increasing the tension on a string increases the rate of a wave, which increases the frequency (for a given length). Urgent the finger at exceptional places adjustments the period of string, which changes the wavelength of the status wave, affecting the frequency.
The speed of a wave on a string depends on the rectangular root of the anxiety divided through the mass per length, the linear density. In standard, the velocity of a wave via a medium relies upon the elastic assets of the medium and the inertial assets of the medium.
While the length of a string is modified, it'll vibrate with a one-of-a-kind frequency. Shorter strings have better frequency and therefore better pitch.
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nazi made the biggest gun, schwerer gustav. it weighed 1500 metric ton. when it shot out a projectile of 5 metric ton, it recoiled with 2.6 m/s. find the projectile speed.
the speed of the projectile is 780m/s.
given in this question,
mass of the gun m₁ =1500metric tun
as we know 1ton= 1000kg
so m₁=1,500,000kg
mass of projectile m₂= 5ton =5000kg
for solving this problem we will use the concept of conservation of momentum.
which is [tex]P_{initial}[/tex]=[tex]P_{final}[/tex]
[tex]P_{initial}[/tex]=0
and [tex]P_{final}[/tex]=m₁v₁+m₂v₂
∵v₁=2.6m/s
now by the conservation of momentum
[tex]P_{i}[/tex]=[tex]P_{f}[/tex]
0=1,500,000×2.6+5000×v₂
v₂=-1500000×2.6/5000
v₂= -780m/s
hence the value of the velocity negative is not possible
negative sign is showing direction of projectile.
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Body systems work together to perform all the functions necessary for the survival of
An organism
C. Explain why the failure of one organ or organ
system can affect the function of other body
systems in an organism.
Explanation:
Body systems work together to perform all the functions necessary for the survival of
An organism
C. Explain why the failure of one organ or organ
system can affect the function of other body
systems in an organism.
you are moving toward a stationary observer in your spaceship at 0.5c while shining a light toward the stationary observer. at what speed does the stationary observer measure the light from your spaceship?
The stationary bystander measures the light coming from your spaceship at the speed of light.
What it refers to is speed. the rate at which the position of an object shifts in any direction. Speed is defined as the rate of the distance traveled to the time needed to cover that distance. Speed is a scalar volume since it just has a direction and no magnitude.
Light is a type of electromagnetic radiation that helps the mortal eye see or makes effects visible. The term" radiation that's visible to the mortal eye" can also be used to describe it. Photons, which are bitsy energy packets, are present in light.
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if sarah applies a force of 17.0 n to the end of a 35 cm lever at an angle of 25 degrees, what will be the torque exerted on the lever?
The torque that will be exerted on the lever is 2.49 N-m.
The torque on the rod is given by,
T = F x a
Where,
T is the torque,
F is the applied force,
a is the perpendicular distance from the end of the rod.
T = F.s.sinA
The force that Sarah applied is 17 N and s is the distance from one end of the lever is 0.35 m,
The angle at which the force is applied is 25 degrees.
Putting the values,
T = 17 x 35 x sin(25)
T = 2.49 N-m
So, yes, there will be a torque of magnitude 2.49 N-m.
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an automobile with a mass of 1325 kg has 3.02 m between the front and rear axles. its center of gravity is located 1.78 m behind the front axle. the automobile is on level ground. (a) determine the magnitude of the force from the ground on each front wheel (assuming equal forces on the front wheels). 2665.79 correct: your answer is correct. n (b) determine the magnitude of the force from the ground on each rear wheel (assuming equal forces on the rear wheels).
The magnitude of the force from the ground on each front wheel is 2775N.
Let us call the force on the front axle F and the force on the rear axle R.
We know that
⇒ F + R= total weight of vehicle = 1360 * 9.80 = 13328 Newtons
And using torques, you know that force on the front axle * distance to the center of mass = force on the rear axle * distance to the center
of mass
or F *1.78 = R * (3.05 - 1.78)
So
1.4016F = R
Then.
F + 1.4016 F = 13328
F = 5550 N and R = 13328 - 5550 = 7778N
So the force on each front tire is 5550 /2 = 2775N
And the force on each rear tire is 7778 /2 = 3889N
Force is a push or pulls upon an item because of the object's interaction with some other object. Pressure is a power that can exchange the motion of an object. A force can reason an object with mass to alternate its speed, i.e., to boost up. pressure also can be described intuitively as a push or a pull. A force has each significance and course, making it a vector amount.
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what is one major difference between federal and unitary governments
Answer:
In a unit government, all the powers of government are moved around in the central government where in turn in a federal government, the powers of government are divided between the center and the units.
Explanation:
I hope this helps.
a satellite of mass 1000 kg is in a circular orbit around a planet. the centripetal acceleration of the satellite in its orbit is 5 ms2. what is the gravitational force exerted on the satellite by the planet?
The gravitational force exerted on the satellite of mass 1000 kg moving in a circular orbit with a centripetal acceleration of 5 m/s² by the planet is 5000 N (option C). The, the force acting on the satellite is: Therefore, the gravitational force exerted on the satellite by the planet is 5000 N (option C).
f
An influence that can alter an object's motion is called a force. A mass-containing object's velocity can change, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction. The rate at which an object's velocity with respect to time changes is called its acceleration. Vector quantities include accelerations. The direction of the net force acting on an object provides information about its acceleration.
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A plane starting at rest at the south end of a runway undergoes a uniform acceleration of 1.60 m/s to the north. At takeoff, the plane's velocity is 72.0 m/s to the north. How far does the plane travel across the runway
The distance travelled by the plane across the runway is determined as 1,620 m.
What is the distance travelled by the plane across the runway?The distance travelled by the plane across the runway is calculated by applying the following equation.
v² = u² + 2as
where;
v is the final velocity of the planeu is the initial velocity of the planea is the acceleration of the planes is the distance travelled by the planeThe initial velocity of the plane, u = 0, since it started from rest.
v² = 0 + 2as
s = v²/2a
The given parameters;
acceleration of the plane, a = 1.6 m/s²final velocity of the plane = 72 m/ss = (72²)/(2 x 1.6)
s = 1,620 m
Thus, the distance travelled by the plane along or across the runway depends on the final velocity of the plane and the acceleration of the plane.
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ima rilla saari rushes to her car in order to hurry home and get dressed for work. failing to realize the dangers of driving under slick and icy conditions, she collides her 940-kg mazda miata into the rear of a 2460-kg pick-up truck which was at rest at the light on lake avenue. ima's pre-collision speed was 12.5 m/s. determine the post-collision speed of the two entangled cars as they slide across the ice.
The two intertwined autos are sliding on the ice at a 3.46 m/s post-collision speed.
What is conservation of momentum?The principle of momentum conservation argues that within a given problem domain, momentum is never created nor destroyed but only modified by the action of forces as they are represented by Newton's laws of motion.
According to the rule of conservation of momentum, absent an external force, the combined momentum of two or more bodies operating upon one another in an isolated system remains constant. As a result, momentum cannot be gained or lost.
The speed of the Mazda before the accident multiplied by the mass of the Mazda must match the speed after the collision multiplied by the mass of both cars, according to the property of conservation of momentum:
m1v1 = m1 + m2 *v2
940*12.5 = 940 +2460 *v2
v2 = 3.46 m/s
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determine what fraction of the kinetic energy of the ball before collision is lost during teh collsion. what happens to it?
1/2 m₁v₁²(m₁ / m₁+ m₂ ) is the fraction of Kinetic energy lost during an inelastic collision.
From the concept of law of conservation of energy, In an elastic collision when two objects collide with a particular velocity then the kinetic energy before the collision will be the same after the collision as well but that's not the case in an Inelastic collision where there's always loss of kinetic energy.
In case of inelastic collision,
pi = pf
here p = momentum
m₁v₁ = (m₁ + m₂)v₂
v₂= m₁v₁ / (m₁ + m₂) ------- equation 1
Ki = Kf
1/2m₁v₁² = 1/2 (m₁+m₂) v₂²
Put the value of v₂ from equation 1
1/2mv² = 1/2 (m₁ + m₂) [m₁v₁ / m₁+m₂]²
=> 1/2 (m₁v₁)² / ( m₁+m₂ )
∴ Fraction of Kinetic energy lost
= 1/2 m₁v₁² - 1/2 (m₁v₁)² / (m₁+m₂)
=> 1/2 m₁v₁²( m₁ / m₁ + m₂ )
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a 200 g mass is placed on the meter stick 20 cm from the fulcrum. a 170 g mass is used tobalance the system. how far will it have to be located from the fulcrum to keep the systeminbalance?
200 g mass is placed on meter stick 20 cm from fulcrum. a 170 g mass is used to balance the system and placed the meter stick at 23.52cm.
What is equilibrium?A dynamic or static equilibrium between opposing forces or actions, such as when forces are acting on a body and the resultant is zero (as in a reversible chemical reaction when rates of reaction in both the directions are equal)
The word "equilibrium" derives from the Latin word "libra," which means "weight" or "balance." As a constellation, astrological sign, and representation of the zodiac, Libra is sometimes shown as a set of balance scales, frequently held by the blindfolded goddess of justice, which stands for justice, fairness, and equality. Biology, chemistry, physics, and economics all have different definitions of equilibrium, yet they all refer to the harmony of opposing forces.
F₁d₁ = F₂d₂
m₁gd₁ = m₂gd₂
m₁d₁ = m₂d₂
here,
m₁ is mass of known object = 200 g
m₂ is mass of unknown object = 170 g
d₁ is distance from fulcrum of known object = 20 cm
d₂ is distance from fulcrum of unknown object = ?
∴ 200 × 20 = 170 × d₂
4000 = 170 × d₂
4000/170 = d₂
d₂ = 23.52 cm
170 g mass is placed at the distance of 23.52 cm.
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a wheel and axle on a bicycle are designed with an axle radius of 0.125 meters and a wheel radius of 0.5 meters. if a force of 800 newtons is applied to the axle, what is the maximum output force of the bike wheel?(1 point)
The maximum output force of the bike wheel is equal to 40000 newtons.
The maximum output force of the bike wheel is calculated by using the equation:
F = R^2 * P, where F is the force exerted by the wheel on the axle, R is the radius of the axle, and P is the applied force. So we have: 800 N = (0.125 m)^2 * (800 N)
Rearranging gives us: 2 * R^2 = 800 N
Solving for R gives us: 0.5 m = 40000 N/m^2
This means that we must have a radius of 0.5 meters to produce an output force of 40000 newtons.
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What is the name of the object to which the electric current flows from the battery toward (and then back to)?
Answer: Electrical Conductors
Explanation: Electrical conductors allow electric current to flow easily because of the make up of their atoms. In a conductor, the outer electrons of the atom are loosely bound and can freely move through the material when an electric charge is applied. In general, the best electrical conductors are metals.
a nearsighted man has a far point of 300 cm. what kind of corrective lens should be prescribed for him?
The diverging lens/concave lens is used as a corrective lens is used for a nearsighted person
Nearsightedness is also known as myopia where the person with myopia will be able to see the near object but far objects will look blurry.
Myopia is corrected with lenses called "minus power lenses". They are concave in shape and help the eye to focus light properly. Myopia causes distant objects to appear blurry. Prescription glasses or contact lenses can usually correct this blurry distance vision. Myopic eyes have a stronger ability to focus than normal eyes. Focus in front of the retina, not on the retina. Lenses used to correct nearsightedness work by reducing the eye's ability to focus.
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Which of the following graphs represent an object at rest? (There could be more than one correct cho 0' 0' 0 0 graph a graph b graph c graph d
Graph A, because distance-time graph is a straight line parallel to the time-axis because the position of the object does not change when it is at rest.
Distance is the length between two points or items, and it is directionless. Since distance is a scalar attribute, it only takes into account the overall magnitude and ignores the start and end locations. Being a scalar attribute, distance may only be positive or zero; it cannot be the opposite.
Although kilometers (km) and centimeters (cm) or millimeters (mm) can also be used to express shorter distances, the meter (m) is the most used unit of measurement for distance (mm). When calculating distance, the letter D is usually used to denote the distance traveled.
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enceladus is an icy moon of saturn experiencing tidal forces because of an elliptical orbit due to an orbital resonance with another moon dione. what are the consequences of tidal heating of enceladus because of this elliptical orbit?
The main consequence of tidal heating on Enceladus because of this elliptical orbit is that it occasionally brings the moon closer to Saturn and occasionally farther away.
When Dione, a bigger moon, orbits Saturn once, Enceladus orbits twice. Enceladus' orbit is made elliptical by Dione's gravity. This causes tidal heating inside the moon, and the following effects also:
The extremely hot geysers on the Enceladus moon, which shoot water into space, are caused by this.The "tiger stripes" in Enceladus' south pole, which are active fissures, are where the particles are released.The presence of salt in the plumes suggests that the frozen shell may be hiding an ocean of liquid water.But the ultimate cause of the geological activity on this moon had remained a mystery. Instead of a circular orbit, Enceladus orbits Saturn in an elliptical distortion. Saturn's gravity pulls and squeezes the moon as a result, heating its innards and allowing geological activity on the frozen moon.
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when the top 2 waves are added together, the result is the bottom wave. the bottom wave is an example of
When two waves collide while moving across the same medium, wave interference is the result.
What happens when 2 waves meet?When two waves collide, they cause each other's displacement to change, creating a totally new wave in the process. The amplitude of the resulting wave at each point is determined by adding the amplitudes of each wave, according to the principle of superposition.Sound waves interact when they share a space with one another.The waves pass through each other instead than off of one another. Depending on how the waves align, a wave will result.The two waves will combine into a temporary, larger wave with an amplitude equal to the sum of their individual amplitudes if their crests and troughs completely line up. Constructive interference is what this is.To Learn more About wave interference refer to :
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a plane electromagnetic wave, with wavelength 3.0 m, travels in vacuum in the positive direction of an x axis. the electric field, of amplitude 300 v/m, oscillates parallel to the y axis. what are the (a) frequency, (b) angular frequency, and (c) angular wave number of the wave? (d) what is the amplitude of the magnetic field component? (e) parallel to which axis does the magnetic field oscillate? (f) what is the time-averaged rate of energy flow in watts per square meter associated with this wave? the wave uniformly illuminates a surface of area 2.0 m2. if the surface totally absorbs the wave, what are (g) the rate at which momentum is transferred to the surface and (h) the radiation pressure on the surface?
Since, we know that magnetic field is always perpendicular to the z axis or electric field.
Calculation:-
lambda = 2.8m
v = 3*10^8m/s
v = f(lambda)
(a) f = 1.07*10^8hz
(b)angular frequency = 2pif
= 6.72*10^8rad/s
(c) wave number = 2pi/lambda
= 2.24
(d) B=E/c
= 300/(3*10^8)
=10^-6Tesla
(e) Magnetic discipline is perpendicular to wave propagation and electric powered subject
The magnetic discipline is perpendicular to the z-axis.
Electromagnetic waves are non-mechanical waves. Electromagnetic waves do no longer require a medium to propagate and may without problems pass via a vacuum. Electromagnetic waves propagate in all guidelines from the source of interference. The wave will keep transferring till something interrupts it. Electromagnetic waves vary from mechanical waves in that they do no longer require a medium for propagation.
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q2: if a system contains 2 objects, is there a possibility that the momentum of one object is not conserved?
Yes, there a possibility that the momentum of one object is not conserved.
In a two-body collision, is momentum always conserved?Newton's third law suggests that momentum is always conserved in collisions between two isolated objects. In collisions, it is believed that the interaction between the colliding items lasts for a brief period of time, making the impulse caused by outside forces insignificant.
For the momentum to be conserved, a system must satisfy two conditions:
Throughout the interaction, the system's mass must remain constant.
The system must be subject to zero net external force.
Momentum does not always change and is not conserved because the collision is automatically conserved when the kinetic energy is. The amount of momentum needed when there is a change in speed during a collision remains constant.
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which person below discovered that the orbits of planets are ellipses? which person below discovered that the orbits of planets are ellipses? copernicus ptolemy tycho brahe kepler galileo
The scientist that discovered that the orbit of planets are ellipses is johannes Kepler. That is option E.
What is elliptical planet?Elliptical planets are those planets that are not round in shape but are ellipses which is the shape of a circle that has been stretched in one direction as seen with oval shape.
The scientist johannes Kepler, who is also a mathematician discovered that orbits of planets are elliptic in shape through his work on planet orbits.
He successfully proved this through his three laws of planetary motion that include the following:
The first law: The planets move in elliptical orbits with the Sun at one focus.The second law: The time necessary to traverse any arc of a planetary orbit is proportional to the area of the sector between the central body and that arcThe third law: There is an exact relationship between the squares of the planets’ periodic times and the cubes of their mean distances from the Sun.Learn more about planets here:
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the base of an aluminum block, which is fixed in place, measures 90 x 90 cm. the height of the block is 60cm. a force, applied to the upper force and parallel to it, produces a shear strain of 0.0060. the shear modulus of aluminum is 3.0 x 10^10 pa. what is the displacement
The displacement of an aluminum block, which is fixed in place, measures 90 x 90 cm with a height of 60 cm is 0.36 cm
S = Shear ε / Shear γ
S = Shear Modulus
ε = Stress
γ = Strain
S = 3 * [tex]10^{10}[/tex] Pa
Shear γ = 0.006
Shear ε = S * Shear γ
Shear ε = 3 * [tex]10^{10}[/tex] * 0.006
Shear ε = 1.8 * [tex]10^{8}[/tex]
Shear ε = 180 MPa
Displacement = Shear ε * l
l = Length = 60 cm
Displacement = 0.006 * 60
Displacement = 0.36 cm
Therefore, the displacement of the upper phase aluminum block is 0.36 cm in the direction of applied force.
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3. (a) calculate the work done on a 1500-kg elevator car by its cable to lift it 40.0 m at constant speed, assuming friction averages 100 n. (b) what is the work done on the elevator car by the gravitational force in this process? (c) what is the total work done on the elevator car?
(a) Work done on the car by its cable will be 5.92 * [tex]10^{5}[/tex] J.
(b) Work done on the car by the gravitational force will be -5.92 * [tex]10^{5}[/tex] J.
(c) Total work done on the car will be 0 J.
Work done is the product of force and displacement.
Mathematically, Work-done = W = Force * DistanceMass of the car = m = 1500 kg
Distance lifted by the cable = d = 40 m
Frictional force experienced by the car = Fs = 100 N
(a) According to the Newton's second law of motion
F = Fcable - mg - Fs = ma
Fcable = mg + Fs
Work done by the same force = W1
W1 = Fcable * d
W1 = (mg + Fs) * d
W1 = (1500*9.8 + 100) * 40
W1 = 592600
W1 = 5.92 * [tex]10^{5}[/tex] J
(b) Work done by the gravitational force = W2 = mg * d
W2 = 1500*(-9.8)*40
Since the acceleration is acting downwards 'g' will be considered with a negative sign.
W2 = -5.88 * [tex]10^{5}[/tex] J
(c) The total work done on the lift is the work done by the net force exerted on the car during this process:
W3 = Fnet * d
Fnet = -5.88 * [tex]10^{5}[/tex] J + 5.92 * [tex]10^{5}[/tex] J
Fnet = 0
W3 = 0 * 40
W3 = 0 J
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for an elastic collision, why do the carts start interacting even though they never physically touch?
An example of a collision without physical contact is a charged particle being deflected by another charged particle as they travel by one another.
Another illustration is a gravitational slingshot, in which a light object moves around a much heavier object to accelerate. A collision does not require the objects to actually touch; for instance, an asteroid passing by the earth is seen as one since its course is altered by the gravitational pull of the planet. The conservation of momentum and energy can still be used to assess the collision. Yes, even without direct touch, an accident may still occur.
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a 1.92 kg object on a frictionless horizontal track is attached to the end of a horizontal spring whose force constant is 4.77 n/m. the object is displaced 5.31 m to the right from its equilibrium position and then released, which initiates simple harmonic motion. what is the magnitude of the force acting on the object 3.72 s after it is released? answer in units of n.
The magnitude of the force acting on the object of mass 1.92 kg, 3.72 s after it is released is 23.414 N in negative direction.
ω = √ ( k / m )
ω = Angular frequency
k = Force constant
m = Mass
k = 4.77 N / m
m = 1.92 kg
ω = √ 4.77 / 1.92
ω = √ 2.48
ω = 1.58 rad / s
F ( t ) = - m d ω² cos ω t
F ( t ) = Force wrt time
d = Displacement
t = Time
t = 3.72 s
d = 5.31 m
F ( 3.72 ) = - 1.92 * 5.31 * 1.58² cos ( 1.58 * 3.72 )
F ( 3.72 ) = - 25.45 cos 5.88
F ( 3.72 ) = - 23.414 N
Therefore, the magnitude of the force acting on the object is 23.414 N in negative direction.
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100 POINTS!! 1. Calculate the current flowing when:
(A) 75 mC pass a point in I min;
(B) 0.5 GC pass a point in 2 hours;
(C) 2.0 MC pass a point in 1000 hours.
2. Calculate the charge flow when the current flow is:
(A) 6.0 A for 5 min;
(B) 250 mA for 4 hours;
(C) 2.5 KA for 50 s.
3. How long does it take for the following to pass a point in the circuit?
(A) 25 MC at a current of 25 mA;
(B) 48 C at a current of 12 A;
(C) 360 C at a current of 4.0 A.
4. A current of 10 cA flows through a resistor of resistance 4.0 ohms
Find the:
(a) P.d across the resistor;
(b) Total charge flow in 3 minutes;
Current ( I ) = charge(Q) * time(t)
(A) I = 75/1000 * 1*60 = 4.5A
(B) I = 0.5*10^9 * 2*60*60 = 3.6*10^12 A
(C) I = 2*10^-6*1000*60*60 =0.55 A
2) Q = I/t
( A) Q = 6/5*60 = 0.02 C
( B) Q = 250*1000/ 4*60*60 = 17.36 C
( C) Q = 2.5/1000*50 = 5*10^-5 C
3 ) t = I/C
(A) t =25*1000/ 25*10^-6 = 1*10^9 s
(B) t = 12/48 = 0.25 s
(C) t = 4/360 = 0.011 s
4 )
( A) P . d = current * resistance = 10/100 * 4= 0.4V
( B) charge = 10*10^-2/3*60 = 5.55*10^-4 C
What is charge ?
Charge, also known as electric charge, electrical charge, or electrostatic charge and denoted by the symbol q, is a property of a unit of matter that indicates how many more or fewer electrons than protons it contains.
The physical characteristic of matter that causes it to feel a force when exposed to an electromagnetic field is called electric charge. The two types of electric charges that protons and electrons most frequently carry are positive and negative charges.
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A mass on a spring undergoes shm. When the mass is at its maximum displacement from equilibrium, its instantaneous velocity?.
When the spring undergoes simple harmonic motion and its mass is at maximum displacement then its instantaneous velocity is zero.
Simple Harmonic Motion:
Simple harmonic motion is a periodic motion in which the acceleration of the object undergoing the simple harmonic motion is directly proportional to the distance of the object from its equilibrium position and is always directed toward the mean position.
At the maximum displacement, the spring is under its greatest tension, which forces the mass upward. At the maximum displacement, the spring reaches its greatest compression, which forces the mass back downward again.
Therefore we get that when mass is at its maximum displacement from equilibrium its instantaneous velocity is zero.
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What single color of light illuminating a ripe banana will make it appear black?.
The single color of light illuminating a ripe banana will make it appear black will be blue light.
When lit with blue light, ripe bananas appear black. Yellow is a combination of red and green, so if blue light is flashed onto a yellow banana, the fruit will absorb the blue light, leaving nothing for the banana to reflect. The banana seems black to the eyes because there is nothing for them to reflect back to them. So, when viewed with blue light, a ripe banana appears black.
A red shirt would seem black if only blue light were shined on it because no red light would be there to reflect the blue light, which would otherwise absorb it. Ripe bananas adhere to the same standard and also white objects, which seem white because they reflect all colors.
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