How many grams of NaOH are needed to make 100. mL of solution with a concentration of 1.5 M?

To name Type 2 ionic compounds such as AuCl₃, you need to use the Stock system or Roman numeral system to indicate the oxidation state of the cation. Some steps are; Identify the cation, Determine the charge, Write the name, and combine two names.

Here are the steps to name AuCl₃; Identify the cation and anion. In this case, the cation is Au³⁺ and the anion is Cl⁻.

Determine the charge on the cation by using the anion's charge and balancing the charges to zero. Since Cl⁻ has a charge of -1 and there are three Cl⁻ ions in the compound, the total negative charge is -3. Therefore, the Au³⁺ ion has a charge of +3.

Write the name of the cation first, followed by the name of the anion with an -ide ending. Since the cation is Au³⁺, we use the name "gold(III)" to indicate the oxidation state of +3. The anion is Cl⁻, so we add the -ide ending to get "chloride".

Combine the two names to get the compound's name: "gold(III) chloride".

Therefore, the name of the Type 2 ionic compound AuCl₃ is "gold(III) chloride".

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The energy associated with the formation of 2.55 g of 4He by the fusion of 3H and 1H is -2.982 x 10⁻¹⁰ J.

The given masses of the isotopes can be converted to kilograms using the conversion factor: 1 u = 1.661 x 10⁻²⁷ kg.

Mass of 4He = 2.55 g = 2.55 x 10⁻³ kg

Mass of 3H = 3.01605 u = 3.01605 x 1.661 x 10⁻²⁷ kg/u

= 5.0099 x 10⁻²⁷ kg

Mass of 1H = 1.00783 u = 1.00783 x 1.661 x 10⁻²⁷ kg/u

= 1.6737 x 10⁻²⁷ kg

The balanced equation for the fusion reaction is;

3H + 1H → 4He

The molar mass of 4He is 4.0026 g/mol, which can be converted to kg/mol using the conversion factor: 1 g/mol = 1 x 10⁻³ kg/mol.

Molar mass of 4He = 4.0026 g/mol = 4.0026 x 10⁻³ kg/mol

The number of moles of 4He formed can be calculated from its mass;

n(4He) = m(4He) / M(4He)

= 2.55 x 10⁻³ kg / 4.0026 x 10⁻³ kg/mol

= 0.638 mol

From the balanced equation, 3 moles of H atoms react with 1 mole of He atoms to form 1 mole of He atoms. Therefore, the number of moles of H atoms required for the reaction is;

n(H) = 3/4 x n(4He)

= 3/4 x 0.638 mol

= 0.479 mol

The energy released in the reaction can be calculated using the mass-energy equivalence equation;

E = Δm c²

where Δm is change in mass, c is the speed of light.

The change in mass is;

Δm = [3H + 1H - 4He] = [5.0099 x 10⁻²⁷ kg + 1.6737 x 10⁻²⁷kg - 4.0026 x 10⁻³ kg]

= -3.315 x 10⁻²⁷ kg (negative because mass is lost in the reaction)

The energy released is;

E = (-3.315 x 10⁻²⁷ kg) c²

= (-3.315 x 10⁻²⁷ kg) (2.998 x 10⁸ m/s)²

= -2.982 x 10⁻¹⁰ J

The negative sign indicates that energy is released in the reaction (exothermic reaction).

Therefore, the energy associated is -2.982 x 10⁻¹⁰ J.

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A vessel of 14.0 L would hold 1.78 moles of chlorine gas at 120.0 °C and 33.3 atm.

The ideal gas law relates the pressure (P), volume (V), temperature (T), and the number of moles (n) of a gas to a constant R known as the universal gas constant. In this equation, P, V, and T are directly proportional to n, which means that as the number of moles of gas increases, so does the pressure, volume, and temperature.

Using the ideal gas law, PV = nRT, we can solve for the number of moles of chlorine gas:

n = PV/RT

First, we need to convert the temperature to Kelvin by adding 273.15:

T = 120.0 + 273.15 = 393.15 K

Next, we can plug in the values we have:

n = (33.3 atm)(14.0 L)/(0.0821 L•atm/mol•K)(393.15 K)

n = 1.78 moles

Therefore, 1.78 moles of chlorine gas at 120.0 °C and 33.3 atm would occupy a vessel of 14.0 L.

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In the given reaction, the reactants are hydrochloride acid (HCI) and sodium hydroxide (NaOH). The products are sodium chloride (NaCl) and water.

The chemical equation provided represents a neutralization reaction between hydrochloric acid (HCI) and sodium hydroxide (NaOH) in aqueous solution.

A neutralization reaction is a type of double displacement reaction in which an acid and a base react to form salt and water.

The reactants in this equation are hydrochloric acid (HCI) and sodium hydroxide (NaOH). Hydrochloric acid is a strong acid that dissociates in water to form hydrogen ions (H+) and chloride ions (Cl-). Sodium hydroxide, on the other hand, is a strong base that dissociates in water to form sodium ions (Na+) and hydroxide ions (OH-).

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The crystal I chose is sodium chloride crystals and it is beneficial for man as it is used in the preservation of food as well as in seasoning of food.

A solid whose components are arranged in a highly ordered microscopic structure to form an all-pervasive crystal lattice is referred to as a crystal.

Sodium chloride also referred to as common salt is an ionic compound that has the chemical formula NaCl.

Sodium chloride is an essential nutrient employed in healthcare. It is employed as a spice to improve flavor and as a food preservative. Additionally, sodium chloride is employed in the production of plastics and other goods and is applied to de-ice sidewalks and roadways

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The molarity of the NaOH is  0.25 M

The total volume of the NaOH used is 3.8 mL

Total volume of the HCl used is 9.5 mL

Total volume of HCl = Final burette reading - Initial burette reading

= 25 mL - 15.5 mL = 9.5 mL

Total volume of NaOH used = 8.80 mL - 5.00 mL = 3.8 mL

Number of moles of the HCl = 9.5/1000 * 0.1 M

= 0.00095 moles

Since the reaction is 1:1

molarity of the NaOH = Number of moles /Volume

=  0.00095 moles * 1000/3.8

= 0.25 M

This is the molarity of the NaOH that is involved.

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1. The specific heat capacity of the metal is 0.102 J/gºC

2. The specific heat capacity of the metal is 0.432 J/gºC

3. The final temperature of water is 16.7 °C

First, we shall obtain the heat absorbed by the water. This is shown below:

Q = MCΔT

Q = 125 × 4.184 × 3.4

Q = 1778.2 J

Finally, we shall determine the specific heat capacity of the metal. This is shown below:

Q = MCΔT

-1778.2 = 2.36×10² × C × -74.1

-1778.2 = -17487.6 × C

Divide both sides by -17487.6

C = -1778.2 / -17487.6

Specific heat capacity of metal = 0.102 J/gºC

As discussed above, we shall first obtain the heat absorbed by the water. This is shown below:

Q = MCΔT

Q = 75.2 × 4.184 × 8.1

Q = 2548.56 J

Finally, we shall determine the specific heat capacity of the metal. This is shown below:

Q = MCΔT

-2548.56 = 95.3 × C × -61.9

-2548.56 = -5899.07 × C

Divide both sides by -5899.07

C = -2548.56 / -5899.07

Specific heat capacity of metal = 0.432 J/gºC

The final temperature is the same as the equilibrium temperature of the mixture. Thus, we shall obtain the equilibrium temperature. Details below:

Heat loss by warm water = Heat gain by cold

MᵥᵥC(Tᵥᵥ - Tₑ) = MC(Tₑ - T)

Cancel out C

Mᵥᵥ(Tᵥᵥ - Tₑ) = M(Tₑ - T)

100 × (50 - Tₑ) = 50 × (Tₑ - 20)

Clear bracket

1500 - 100Tₑ = 50Tₑ - 1000

Collect like terms

1500 + 1000 = 50Tₑ + 100Tₑ

2500 = 150ₑ

Divide both side by 150

Tₑ = 2500 / 150

Tₑ = 16.7 °C

The equilibrium temperature is 16.7 °C.

Thus, we can conclude that the final temperature of the water is 16.7 °C

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The total pressure of the gases in the container is 1.000 atm at RTP.

To calculate the total pressure of the gases in the container, we need to use the ideal gas law, which states:

PV = nRT

where P is the pressure of the gas, V is the volume of the container, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.

At RTP (standard temperature and pressure), the temperature is 273 K and the pressure is 1 atm. The volume of the container is not given, but since it is rigid, we can assume it is constant.

To find the total pressure, we need to first calculate the partial pressures of each gas using the mole fraction of each gas. The mole fraction is the fraction of the total moles of gas that are made up of each gas.

Let's assume that we have 100 moles of gas in the container. Then, we have:

20.0 moles of helium (20.0% of 100 moles)

20.0 moles of neon (20.0% of 100 moles)

60.0 moles of argon (60.0% of 100 moles)

The total moles of gas is then:

n = 20.0 moles + 20.0 moles + 60.0 moles = 100 moles

The mole fraction of helium is:

X(He) = n(He) / n = 20.0 moles / 100 moles = 0.200

The mole fraction of neon is:

X(Ne) = n(Ne) / n = 20.0 moles / 100 moles = 0.200

The mole fraction of argon is:

X(Ar) = n(Ar) / n = 60.0 moles / 100 moles = 0.600

The partial pressure of helium is:

P(He) = X(He) * P(total) = 0.200 * 1 atm = 0.200 atm

The partial pressure of neon is:

P(Ne) = X(Ne) * P(total) = 0.200 * 1 atm = 0.200 atm

The partial pressure of argon is:

P(Ar) = X(Ar) * P(total) = 0.600 * 1 atm = 0.600 atm

The total pressure is the sum of the partial pressures:

P(total) = P(He) + P(Ne) + P(Ar) = 0.200 atm + 0.200 atm + 0.600 atm = 1.000 atm

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The quantity of protons, neutrons, and electrons that each element has makes it unique.

Each chemical element's atoms has the same number of protons and electrons, which is important because neutrons' quantities are variable.

Isotopes are atoms with the same number of protons but differing numbers of neutrons.

They differ in mass, which affects their physical characteristics even if they have nearly identical chemical properties. There are unstable isotopes that emit radiation as well as stable isotopes that do not. These are referred to as radioisotopes.

Thus, The quantity of protons, neutrons, and electrons that each element has makes it unique.

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The diagram shows a picture of a compound.

A compound is a substance that is made up of two or more different elements that are chemically bonded together in a specific ratio.

This means that the elements are combined in a way that creates a new substance with different physical and chemical properties than the individual elements.

Compounds can be formed through a variety of chemical reactions, such as combining elements through a chemical bond or through a reaction between an acid and a base.

So for the given diagram, we can see that it represents two or more elements chemically combined.

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Answer: copper hydroxide

Explanation:

Copper(II) hydroxide is the hydroxide of copper with the chemical formula of Cu(OH)2. It is a pale greenish-blue or bluish-green solid. Some forms of copper(II) hydroxide are sold as "stabilized" copper(II) hydroxide, although they likely consist of a mixture of copper(II) carbonate and hydroxide.

Example:

2NaOH+CuSO4→Na2SO4+Cu(OH)2

Answer:

5l NO

2

at STP

No. of molecules=

22.4

5

mol=

22.4

5

×N

A

molecules

A) 5ℊ of H

2

(g)

No. of moles=

2

5

mol=

2

5

×N

A

molecules

B) 5l of CH

4

(g)

No. of moles of CH

4

=

22.4

5

mol=

22.4

5

N

A

molecules

C) 5 mol of O

2

=5N

A

O

2

molecules

D) 5×10

23

molecules of CO

2

(g)

Molecules of 5l NO

2

(g) at STP=5l of CH

4

(g) molecules at STP

Therefore, option B is correct.

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The climatic change in Earth's history that has resulted in glaciers is the cold climate.

During the last 2.6 million years, the Earth has experienced a series of ice ages, or periods of colder global climate, which have led to the growth of glaciers in regions with sufficient snowfall.

These colder periods are associated with changes in the Earth's orbit, tilt, and precession, which affect the amount and distribution of solar radiation received by the Earth. These climatic changes have had significant impacts on the Earth's surface and have influenced the evolution of life on our planet.

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Answer:

What is meant by activated complex?

The state of the particles that is in between the reactants and products is called the activated complex. An activated complex is an unstable arrangement of atoms that exists momentarily at the peak of the activation energy barrier.

source:Gogle

Answer is Answer

Explanation:

The three correct answers about the reactants they used for a successful reaction are:

The collision theory states that successful chemical reactions occur when reactant particles collide with each other with sufficient energy and proper orientation.

Based on the collision theory,  for a successful reaction to occur, the reactants must collide with each other with sufficient energy (activation energy) and in the correct orientation.

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Complete question:

For this question, choose THREE answers. A student adds two chemicals together in lab and observes a successful reaction. Which of the following can be assumed about the reactants they used?

They had the minimum activation energy.

They did not have the minimum activation energy.

They were not oriented in the correct direction.

They were oriented in the correct direction.

They did not successfully collide with each other.

They successfully collided with each other.

The synthesis of N-methyl-4-(p-tolyldiazenyl)aniline can be accomplished in a few steps, as outlined below:

Step 1: Nitration of toluene

Step 2: Reduction of p-nitrotoluene

Step 3: Diazotization of p-toluidine

Step 4: Coupling with N-methylaniline

Toluene is first nitrated to form p-nitrotoluene. This can be done by treating toluene with a mixture of nitric acid and sulfuric acid under controlled conditions. The reaction can be represented as follows:

Toluene + HNO3 → p-nitrotoluene + H2O

The p-nitrotoluene is then reduced to form p-toluidine, using a reducing agent such as iron and hydrochloric acid. The reaction can be represented as follows:

p-nitrotoluene + 6HCl + Fe → p-toluidine + 3H2O + FeCl3

The p-toluidine is then diazotized using nitrous acid to form the diazonium salt. The reaction can be represented as follows:

p-toluidine + HNO2 → p-tolyldiazonium chloride + H2O

The diazonium salt is then coupled with N-methylaniline to form N-methyl-4-(p-tolyldiazenyl)aniline. The reaction can be represented as follows:

p-tolyldiazonium chloride + N-methylaniline → N-methyl-4-(p-tolyldiazenyl)aniline + HCl

Overall reaction:

Toluene + HNO3 → p-nitrotoluene + H2O

p-nitrotoluene + 6HCl + Fe → p-toluidine + 3H2O + FeCl3

p-toluidine + HNO2 → p-tolyldiazonium chloride + H2O

p-tolyldiazonium chloride + N-methylaniline → N-methyl-4-(p-tolyldiazenyl)aniline + HCl

It is important to note that these reactions require careful handling and should only be attempted by individuals with proper training and experience in organic chemistry.

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The debate on what will provide secure and sustainable energy for the United States is of great concern to Americans, and the policies set by National and State Politicians play a crucial role in determining how the United States uses energy.

In this context, a letter can be written to a government official such as a governor, senator, or president, to clearly state the claim/conclusion about the best options for energy production.

Evidence from this activity, as well as additional research, can be used to persuade the reader of the claim.

Thus by doing so, it can be ensured that energy policies are developed with the best options for energy production in mind, leading to a more secure and sustainable future for the United States.

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The coordination number of [Co(NH3)6]3+ is 6, [Ca(EDTA)]2- is 8, Pt(NH3)4 2+ is 4, and Na[Au(CI)2] is 2.

a. [Co(NH3)6]3+: The coordination number of this complex is 6. Each ammonia molecule has a lone pair of electrons that can form a coordinate covalent bond with the cobalt ion. Therefore, the cobalt ion is surrounded by six ammonia molecules in an octahedral arrangement. b. [Ca(EDTA)]2- : The coordination number of this complex is 8. The EDTA molecule has four carboxylic acid groups and two amine groups that can form coordinate covalent bonds with the calcium ion. Therefore, the calcium ion is surrounded by eight atoms or groups in a square antiprismatic arrangement. c. Pt(NH3)4 2+ : The coordination number of this complex is 4. Each ammonia molecule has a lone pair of electrons that can form a coordinate covalent bond with the platinum ion. Therefore, the platinum ion is surrounded by four ammonia molecules in a square planar arrangement. d. Na[Au(CI)2] : The coordination number of this compound is 2. The gold ion is coordinated by two chloride ions in a linear arrangement. The sodium ion is not involved in the coordination sphere of the gold ion

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The law of conservation of mass states that in a chemical reaction, the total mass of the reactants is equal to the total mass of the products. To provide evidence for this law, we can perform an experiment in which calcium carbonate ([tex]CaCO_3[/tex]) is decomposed to produce calcium oxide (CaO) and carbon dioxide ([tex]CO_2[/tex] ), and then measure the masses of the reactants and products.

Method:

Weigh a sample of [tex]CaCO_3[/tex] using a balance.

Heat the [tex]CaCO_3[/tex] in a crucible until it decomposes to CaO and [tex]CO_2[/tex]. The [tex]CO_2[/tex] gas will escape, leaving only CaO in the crucible.

Allow the crucible to cool and then weigh it again to determine the mass of the CaO produced.

Collect the [tex]CO_2[/tex] gas that is released during the reaction in a gas syringe or other collection device. Measure the volume of [tex]CO_2[/tex] gas produced, and calculate its mass using its molecular weight.

Which measurements should be taken:

The following measurements should be taken:

The mass of the [tex]CaCO_3[/tex] used as a reactant.

The mass of the CaO produced as a product.

The volume of [tex]CO_2[/tex] gas produced during the reaction.

The temperature and pressure of the [tex]CO_2[/tex] gas to allow for the calculation of its mass.

How the student could show evidence for the conservation of mass:

To show evidence for the law of conservation of mass, the student can compare the mass of the [tex]CaCO_3[/tex] used as a reactant to the total mass of the products, which includes the mass of CaO produced and the mass of [tex]CO_2[/tex] gas released.

The sum of the masses of CaO and [tex]CO_2[/tex] should be equal to the mass of the [tex]CaCO_3[/tex] used as a reactant, within experimental error. This will provide evidence that the mass of the reactants is conserved and equals the mass of the products, as required by the law of conservation of mass.

Additionally, the student could calculate the theoretical yield of CaO and CO2 based on the balanced equation for the reaction, and compare this to the actual yield obtained from the experiment. Any difference between the theoretical and actual yields could be due to experimental error, but the comparison can still provide additional evidence for the conservation of mass.

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The freezing point of the solution containing 0.867 m glycerin is -1.61442 °C. Option C is correct

The mass of glucose in 505 mL of 10.5% glucose solution is 53.01 g or 5.30 x 10^2 g.

Option C is correct

To find the freezing point depression of the solution containing 0.867 m glycerin:

ΔTf = Kf * molality

ΔTf = (1.86°C/m) * 0.867 m

ΔTf = 1.61442 °C

The freezing point depression is 1.61442 °C.

The freezing point of the solution is:

Freezing point = 0.0 °C - ΔTf

Freezing point = 0.0 °C - 1.61442 °C

Freezing point = -1.61442 °C

To find the mass of glucose in 505 mL of 10.5% glucose solution:

Mass of glucose = Volume of solution * Density of solution * % mass

Mass of glucose = 505 mL * 1.04 g/mL * 10.5%

Mass of glucose = 53.01 g

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The vibrational modes and unique possible states for each mode are detailed in the table below.

A vibrational mode of a molecule refers to a specific way in which the atoms inside a molecule can move relative to each other. Molecules are made up of atoms that are connected to each other by chemical bonds, and these bonds act like springs that can vibrate.

When a molecule absorbs energy, it can cause the bonds to stretch, bend, or twist in specific ways, creating different vibrational modes. The vibrational modes of a molecule can provide important information about its structure and chemical properties.

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Cuso4 + NaoH -》cu(oH)2 +Na2So4

Cuso4 + 2NaoH -》cu(oH)2 +Na2So4

Explanation:

this is balanced equation

Answer:

C. polar nature

Explanation:

The polarity of water and its ability to hydrogen bonding contributes to it's unique properties

Answer:

Hydrogen H 3.330% Carbon C 26.450% Oxygen O 35.234%

Explanation:

Answer:

LiOH is soluble. Na2CO3 is soluble. Cu(OH)2 is insoluble.

Explanation:

LiOH is soluble. Na2CO3 is soluble. Cu(OH)2 is insoluble.

Answer:

increase concentration of reactants

Explanation:

I took the test

A sp² hybrid orbital on C-1 overlaps with a sp hybrid orbital on C-2 to form the sigma bond between C-1 and C-2. This statement regarding the skeletal structure of the organic molecule true. The correct option is option A.

In general, molecules containing carbon (C) are referred to as organic compounds. Carbon atoms serve as the primary structural framework for the enormous diversity of naturally occurring compounds. Organic substances play a critical role in the existence of all life forms on Earth (and perhaps elsewhere in the universe). A sp² hybrid orbital on C-1 overlaps with a sp hybrid orbital on C-2 to form the sigma bond between C-1 and C-2.

Therefore, the correct option is option A.

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Answer:

A

Explanation:

If Hydrogen is H₂  There will be two silver

and is Carbon is C There will only be one gray

and if Oxygen is O₃ There will be three red