How many grams of sodium chloride are there in 550 ml of a 1. 90 m aqueous solution of sodium chloride?

Answer:

The low light eye sight depends on the rod cells of the eye,and the birds have more amount of rod cell in their eyes, that's why they have an extraordinary night vision

We know that,

acceleration (a) = final velocity(V)-initial velocity(U)/ Time taken(T)

Answer:

Explanation:

Warm lake vapor pressure is higher than cold lake vapor pressure because it evaporates more quickly. In other words, as the temperature of warm water increases, the kinetic energy of the warm water molecule also increases. As the kinetic energy of the warm water molecule increases, the number of molecules conversion into a vapor also increases, thereby increasing the vapor pressure of warm water.

Answer:

B.

Warm water evaporates more quickly.

Explanation:

i got it right on edmentum!!

In the polymerization reaction, the lone pair electrons on the NH₂ groups of hexanediamine attack the C=O groups of the dicarboxylic acid in a nucleophilic substitution reaction as shown in the image.

Hydroxide is added to remove any H⁺ ions present and keep the hexanediamine in the deprotonated form, so that the NH₂ lone pair electrons are available for reaction.

If hydroxide is not added, the NH₂ groups will get protonated by H⁺  ions present to give NH₃⁺ groups, which cannot react.

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The column count property can be used to create multiple columns of text within a single element.

Hydrogen bonding is generally an intermolecular force, and  covalent bonding is only an intramolecular attractive force.

When a hydrogen atom gets bound to a powerfully electronegative atom and is in close proximity to some other electronegative atom with such a single electron pairs, a hydrogen bond occurs as an intermolecular force (IMF).

The three types of intermolecular interactions include dipole-dipole, London dispersion, and hydrogen bonding forces. Metal bonds, ionic bonds, as well as covalent bonds are mostly the three types of intramolecular forces.

Therefore, Hydrogen bonding is generally an intermolecular force, and  covalent bonding is only an intramolecular attractive force.

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A student makes up 2 l of a 3. 0 m aqueous solution of HBr. to this solution she adds 1 l of a 4 m NaOH solution, then the pH of the resulting solution is 13.83.

Normality is defined as the ratio of equivalent mass of compound to the volume of solution in litre.

N1 is the normality of HBR = 3m

N2 is the normality of NaOH = 4m

V1 is the volume of the HBr = 2l

V2 is the volume of the NaOH = 1l

V is the total volume of solution = V1 + V2 = 2l +1l

= 3l

Normality of the solution = N

As we know that,

N1V1 - N2V2 = NV

3 × 2 – 4 × 1 = N × 3

6 – 4 = N – 3

N = 2/3 = 0.67 m

(OH-) = N = 0.67 m

Since normality of NaOH is greater than BR . Hence the resulting solution is alkaline.

pOH = -log[OH-]

POH = - log (0.67) = 0.17

As we know that,

PH + pOH = 14

pH = 14 – 0.17

= 13.83

Thus, we calculate that the pH of the resulting solution is 13.83.

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Mass of copper would be=92.46 g

I = Current = 19.5 A

t = 4 hours =4×60×60=14400 s

F = Faraday constant = 96485.33 C/mol

Molar mass of copper = 63.546 g/mol

A charge is given by

Q=19.5×14400=280880 C

Moles of electrons are given by Q/F=280880/96485.33=2.91 mol

Moles of copper is=1/2×2.91=1.455 mol

Mass of copper would be=1.455×63.546=92.46 g

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The mass of Copper electroplated is 68.76 g

The process of plating a metal onto another is known as electroplating.

It is often used to prevent corrosion of metal or for the decorative purposes

In this process, electric current is passed through an aqueous solution containing dissolved cations.

The dissolved cations are reduced developing a thin metal coating on the electrode.

At cathode,

[tex]Cu^{2+}(aq) + 2e^-\rightarrow Cu(s)[/tex]

Current, I = 14.5 A

Time, t = 4 hrs = 4×60×60 = 14400 sec

Charge, q = It = 14.5×14400= 208800 C

Copper metal deposited by 2×96487 C = 63.55 g

Copper metal deposited by 208800 C = [tex]\frac{63.55 \times208800}{2\times96487}[/tex]

                                                         = 68.76g

Hence, The mass of Copper electroplated is 68.76 g

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Markovnikov addition product from the addition of hi to 2-methyl-2-butene is 2-iodo-2-mehtylbutane.

What is Markonikov rule?

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The molar solubility is 7.4×[tex]10^{-3}[/tex] M and the solubility is  7.4×[tex]10^{-3}[/tex] g/L .

Calculation ,

The dissociation of silver bromide is given as ,

[tex]AgBr[/tex] → [tex]Ag ^{+}[/tex] + [tex]Br^{-}[/tex]

S  

 -          S        S        

Ksp =  [[tex]Ag ^{+}[/tex] ] [ [tex]Br^{-}[/tex] ]  =  [S] [ S ] = [tex]S^{2}[/tex]

S = √ Ksp = √ 5. 5×[tex]10^{-5}[/tex] = 7.4×[tex]10^{-3}[/tex]

The solubility =7.4×[tex]10^{-3}[/tex] g/L

The molar solubility is the solubility of one mole of the substance.

Since ,  one mole of [tex]AgBr[/tex] is dissociates and form one mole of each  [tex]Ag ^{+}[/tex] and [tex]Br^{-}[/tex] ion . So, solubility is equal to molar solubility but unit is different.

Molar solubility = 7.4×[tex]10^{-3}[/tex] mol/L = 7.4×[tex]10^{-3}[/tex] M

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Answer:

.24 mol / liters

Explanation:

38. 2 ml = .0382 liters

.0382 liters times ( 0. 163 m KOH/1 liter) times ( 1 mol H2SO4/  1 mol koh) =

.006/.025 liters = .24 mol / liters

chegg

Answer:

See below

Explanation:

Temperature is basically a measure of the average kinetic energy of the particles in the sample ....so as  temp goes up, kinetic energy increases

The concentration of HCl contained in the final solution is 0.95 M.

Here, we use the dilution formula, which is,

M (V₁ + V₂) = M₁V₁ + M₂V₂

where,

M = resultant concentration

M₁ = concentration of HCl

V₁ = volume of HCl

M₂ = concentration of NaOH

V₂ = volume of NaOH

Given,

M₁ = 1 M

V₁ = 90 cm³ = 90 mL

M₂ = 0.5 M

V₂ = 10 cm³ = 10 mL

To find,

M =?

Put the values in the above formula,

M (V₁ + V₂) = M₁V₁ + M₂V₂

M (90 + 10) = (1 × 90) + (0.5 × 10)

M × 100 = 90 + 5

M × 100 = 95

M = 95/100

M = 0.95 M

Therefore, the concentration of HCl contained in the final solution is 0.95 M.

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The rate of reaction of the value of KIS 3 and [A] and [B] are each 2M is: 24 (mol/L)/s (Option B)

In chemistry, the rate of reaction describes how quickly a chemical reaction develops.

It is frequently described in terms of either the concentration of a reactant that is spent in a unit of time or the concentration of a product that is generated in a unit of time (amount per unit volume).

Recall that the rate equation is:
Rate = K[A]²[B]

Hence:

Concentration of A = 2M

Concentration of B = 2M

K = 3

Taking the values and substituting them, we have:

Rate = 3 (mol/L)⁻³/s×[2]² ×[2]

Rate = 24 (mol/L)⁻³/s

The rate of reaction can be used as a valuable diagnostic tool. We may devise strategies to increase production by learning how quickly things are created and what slows down reactions.

This knowledge is necessary for the industrial production of various chemicals, such as:

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The treatment of tetrahydrofuran with excess HBr results in the formation of 1,4-dibromobutane as a major organic product .

THF which is  tetrahydrofuran is reated with excess of HBr at 373 K .The product is 1,4-dibromobutane as a major organic product .

In the mechanism proton having positive charge is attack on electron rich oxygen and protonated it then bromine anion attack at adjacent carbon and break carbon - protonated  oxygen bond and in he final step the hydroxyl group is protonated and remove as a water with attack at bromine anion .

Therefore , on treatment of tetrahydrofuran with excess HBr results in the formation of 1,4-dibromobutane as a major organic product .

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The answer choice which represents an aspect of the kinetic-molecular theory and can be used to explain compressibility of plasma is; Particles move independently of one another and are widely spaced.

The kinetic-molecular theory in discuss postulates about the states of matter.

Also, it is built upon the idea that matter is composed of tiny particles that are constantly in motion.

Hence, the theory is explanatory of the observable properties and behaviours of solids, liquids and gases and hence, explains the compressibility of plasma.

Remarks;

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One isomer is formed

1,1- Dichloroethane is the isomer.

If another hydrogen of c2h5cl is replaced by a chlorine atom to yield c2h4cl2, it would result in one isomer.

These are the three different categories of structural isomers.

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The Henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.

It is expressed as:

pH = pKa + log([A-]/[HA].

where,

[A-] is molar concentration of conjugate base and

[HA] is molar concentration of weak acid.

Given,

pH = 5.30

Substitute the value in the Henderson Hasselbalch equation

5.30 = 4.874 + log[A-]/ [HA]

log[A-]/[HA] = 5.30 - 4.874

[A-]/[HA] = 10^ 0.426

[A-]/[HA] = 2.7

Thus from the conclusion we can say that The henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.

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9ml will be given for the case of dosage calculation order: 3 mg available: 2 mg per 6 ml

Conversion factors are necessary for dosage calculation, such as when translating from pounds to kilograms or liters to milliliters. This approach, which is straightforward in design, enables physicians to deal with different units of measurement and convert factors to arrive at the solution.

dosage calculation techniques serve as a second or third check on the accuracy of the previous computation techniques. Dimensional Analysis, Ratio Proportion, and Formula or Desired Over Have Method are the three main approaches for dosage calculation. dosage calculations are frequently prescribed and labeled based on their weight or, for solutions, their strength, which is the amount of weight dissolved or suspended in a given volume.

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Answer:

A. 2.74g is the correct answer

Explanation:

[tex]average \: mass = \frac{(mass \: pre - 1982 \times abundance) + (mass \: post - 1982 \times abundance}{100 } \\ ave = \frac{ (3.1g \times 40.0) + (2.5g \times 60.0)}{100} \\ ave = \frac{124 + 150}{100} \\ ave = \frac{274}{10} = 2.74g[/tex]

where, the sum of abundance always have to be 100%

Thus, 40.0 +60.0= 100.0

The binding energy of the electron is 1.237 ×10^(-16) kj/ mol.

The given parameter

wavelength of photon,

                       λ = 0.999nm

                          = 0.999x10⁻⁹ m

K.E of emitted photon,

                    K.E = 940 ev

The binding energy of electron is calculated as follows:

From Einstein's mass defect equation=

                    ΔE = Δmc²

Also, from Einstein's photo electric equation=

                       E = Ф + K.E

Where;

          Ф is binding energy of electron on metal surface.

The energy of on mole of electron, the emitted is calculated as:

                       [tex]E = hf =h \frac{c}{λ} = (6.626×10^{-34} ) × \frac{{3×10^{8} }}{0.999×10^{-9} } \\\\E= 1.989×10^{-16}[/tex]

The K.E of emitted electron in Joules is

                 [tex]K.E = 940 × \frac{1}{2} ×1.602 ×\ 10^{-19} J\\\\ = 0.752 × 10^{-16} J[/tex]

The binding energy is electron is calculated as:

               [tex]Ф = E - K.E\\= (1.989 - 0.752) ×10^{-16}\\ =1.237 × 10^{-16} J[/tex]

Question: An X-ray photon of wavelength 0.999nm strikes a surface. The emitted electron has a kinetic energy of 940 eV. What isthe binding energy of the electron in kJ/mol? (KE=1/2mv2; 1 electron volt (eV) = 1.602 x10-19J)

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Answer:

Carbonyl

Explanation:

While the diagram is slightly unclear, the molecule most likely being shown is a carbonyl. A molecule is a carbonyl when there is a carbon double-bonded to an oxygen.

Atoms of particles are so small that they cannot be divided further by any physical means.

According to John Dalton, atoms are the smallest, indivisible particles of elements.

However, it was later found out that chemically, atoms consist of protons, neutrons, and electrons.

Thus, the indivisibility of atoms that John Dalton was referring to must be that of physical division.

In other words, the particles of atoms are so small that dividing them further using physical means is absolutely impossible.

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There is  200 milliosmolarity of a 0. 2 m glucose solution, assuming that the atoms in a glucose molecule are held together by covalent bonds .

Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution. Dilution is a process of decreasing the concentration of a solution by adding a number of solvents

Calculation ,

The molarity of the glucose = 0.2 M

the mili means [tex]10^{-3}[/tex] of any unit.

So , the 1mM =  1 × [tex]10^{-3}[/tex] M

So ,  0.2 M  =  0.2/ [tex]10^{-3}[/tex] M = 0.2 × [tex]10^{3}[/tex] = 200 mM

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Answer:

18016

Explanation:

(empirical formula)n=molar mass

Answer: C_6 H_12 O_6

Explanation: The molar mass of glucose is given as 180.16 gm/mol.

It is 40% carbon, so the weight of the carbon is 40% of 180.16 =72.06 gm. The molar weight of the carbon is 12.011 gm, so the total number of the moles of carbon are 72.06/12.011 = 6 moles.

It is 6.719% of hydrogen, so the weight of the hydrogen is 6.719% of 180.16 = 12.105 gm. The molar weight of the hydrogen is 1.008 gm, so the total number of the moles of hydrogen are 12.105/1.008 = 12 moles.

It is 53.27% of oxygen, so the weight of the oxygen is 53.27% of 180.16 = 95.97 gm. The molar weight of the oxygen is 16 gm, so the total number of the moles of oxygen are 95.97/16 = 6 moles.

The standard free energy change ΔG° at 600 K is equal to  1. 4×[tex]10^5[/tex]J/mol then the equilibrium constant at 600K is 0 .

Calculation ,

ΔG° = - RT㏑Kp

Where ΔG° = standard free energy change =  1. 4×[tex]10^5[/tex]J/mol

R = universal gas constant  = 8.3 J / K mol

T = temperature = 600K

Kp  = equilibrium constant

Now putting the value of all data in equation (i) we get ,

1. 4×[tex]10^5[/tex]J/mol = - 8.3 J / K mol × 600K ㏑Kp

- 1. 4×[tex]10^5[/tex]J/mol /8.3 J / K mol × 600K  = ㏑Kp

㏑Kp = - 6972×[tex]10^5[/tex]

Kp = 0

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There are 0. 650 moles of sodium bromide can be produced from the reaction of 1. 03 moles of bromine gas with 0. 650 moles of sodium .

Calculation ,

To find the number of moles of sodium bromide we have to write balanced chemical equation first .

[tex]2Na (s)+ Br_{2}(g)[/tex] → 2NaBr (s)

from the equation we can conclude that 2 moles sodium react with one mole of bromine to form 2 mole of sodium bromide .

But  1. 03 moles of bromine gas ( that is equal to the number of moles required in the equation) with 0. 650 moles of sodium ( that is half of required mole ) is given .

So, sodium is present as limiting reactant .

So , the number of sodium bromide formed is equal to the number of moles of sodium atom.

Hence ,  the number of sodium bromide formed =  0. 650 moles

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The molar mass of a protein if a 0. 30 l of solution containing 0. 45 g of the protein has an osmotic pressure of 0. 80 torr at 25∘c is 0.348 g/mol

Here we can apply the formula ∏ = iMRT, where ∏ = osmotic pressure = 0.80 - ( given ). This is only one part of the information we are given / can conclude in this case ....

i = van’t Hoff factor = 1 for a protein molecule,

R = gas constant = 62.36 L torr / K-mol,

T ( temperature in Kelvin ) = 25 + 273 - conversion factor C° + 273 = 298K

( Known initially ) ∏ = osmotic pressure = 0.80 torr

besides the part " M " in the formula, which we have no information on whatsoever, as we have to determine it's value.

_____

Substitute derived / known values to solve for M ( moles / liter ) -

∏ = iMRT

⇒ 0.80 = ( 1 )( M )( 62.36 )( 298 )

⇒ 0.80 = M( 18583.28 )

⇒ M = 0.80 / 18583.28 ≈ 4.3049 ....

_____

We know that M = moles / liter, so we can use this to solve for moles, and hence calculate the molar mass by the formula molar mass = g / mol -

M = mol / l

⇒ 4.3049 = 0.045 / 25 mL ( 0.030 L ),

0.045 / 0.030 = 1.5 g / L

⇒ 1.5 g = 4.3049 moles,

molar mass = 1.5 g = 4.3049 moles = 0.348 g / mol

Thus the concluded that the molar mass of protein is 0.348 g / mol.

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The mass of the piece of wood is 35.58 g.

Joule = M × T × C

Where, M = mass

T = change in temperature(42C-23C=19 C)

C = specific heat capacity = 1.716 joules/gram

Substituting the values in the equation,

1160 = M × 19 × 1.716

M = 1160/32.604 = 35.58 g

Therefore, the mass of the piece of wood = 35.58 g

A material's specific heat capacity, which is defined as its heat capacity divided by its mass, determines how much energy is required to increase a gram's temperature by one degree Celsius (or one Kelvin)

Mass is the quantity of matter in a physical body.

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