How many solutions can be found for the equation 12x 8 = 12x 8? zero one two infinitely many

Answer:

C

Step-by-step explanation:

[tex]-15x+60\leq 105 \\ \\ -15x \leq 45 \\ \\ x \geq -3[/tex]

[tex]14x+11 \leq -31 \\ \\ 14x \leq -42 \\ \\ x \leq -3[/tex]

The intersection is x = 3.

∑ k = 1 88 2.5 ⁢ ( 1.2 ) k  is this series written in sigma notation.

What is the series written in sigma notation?

Given:

2.5 + 2.5(1.2) + 2.5(1.2)2 + ⋯ + 2.5(1.2)87

If we look at the power it is always one less the term i.e., for first term the value of k=0.

So, the series in the form of summation can be written as

∑ k = 1 88 2.5 ⁢ ( 1.2 ) k

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Answer:

Step-by-step explanation:

Congruent parts of congruent triangles are congruent, so we can easily demonstrate BD ≅ DF ≅ BF.

AB ≅ BC ≅ CD≅ DE≅ EF ≅ FA . . . . definition of regular hexagon

∠A ≅ ∠C ≅ ∠E . . . . definition of regular hexagon

ΔFAB ≅ ΔBCD ≅ ΔDEF . . . . SAS congruence

FB ≅ BD ≅ DF . . . . CPCTC

ΔBDF is equilateral . . . . definition of equilateral triangle

The area is 97.211 sq units.

This part of the plane is a triangle. We can Call it δ. We can find the intercepts by setting two variables to 0 simultaneously; we'd find, for instance, that y=z=0 means 3x=15 i.e., x=3 , so that (3, 0, 0) is one vertex of the triangle. Similarly, we'd find that (0, 5, 0) and (0, 0, 15) are the other two vertices.

Next, we can parameterize the surface by

s(u,v)=[tex]\int\limits^a_b {3(1-u)(1-v),5u(1-v),15v} \, dx[/tex]

so surface element is

dS= IIsu*svII =15[tex]\sqrt{42}[/tex](1-v)dudv

Then the area of  is given by the surface integral

[tex]\int\limits^a_b {} \, \int\limits^a_b {dS} \, dx = 15\sqrt[n]{42} \int\limits^a_b {x} \, dx \int\limits^a_b {1-v} \, dudv[/tex]=97.211

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Each element in the range of g(x) is 3 less than the corresponding element in the range of f(x).

Answer:

See below.

In short, by having vertical shift will affect range from -1 ≤ y ≤ 1 to -1 + a ≤ y ≤ 1 + a

Step-by-step explanation:

Generally, a cosine function without vertical shift will always have range equal to -1 ≤ y ≤ 1

If there is given vertical shift, our range will change to -1 + a ≤ y ≤ 1 + a

An example is if we are given the function of cos(x), this always has range of -1 ≤ y ≤ 1 because there is no vertical shift.

But if we have cos(x) + 1, we have vertical shift which is 1. Then the range will be -1+1 ≤ y ≤ 1+1 which equals to 0 ≤ y ≤ 2.

Hence, the function of -5cos(2x) has only range of -1 ≤ y ≤ 1 but the function of -5cos(2x) - 3 will have range of -1-3 ≤ y ≤ 1-3 which equals to -4 ≤ y ≤ -2

The theorems or postulates for the given pair of angles are as follows:

2. ∠2 ≅ ∠8 → Alternate exterior angles are congruent;

3. ∠2 ≅ ∠4 → Vertically opposite angles are congruent;

4. ∠3 ≅ ∠5 → Alternate interior angles are congruent;

5. ∠3 is supplementary to ∠6 → Consecutive interior angles are supplementary;

6. ∠4 ≅ ∠8 → Corresponding angles are congruent;

Consider two lines m and n are parallel. A transversal t is intersecting the lines m and n.

So, it forms 8 angles with the lines m and n. They are ∠1, ∠2, ∠3, ∠4, ∠5, ∠6, ∠7, and ∠8.

Based on their position, they are paired into different categories. Such as:

Interior angles: ∠3, ∠4, ∠5, ∠6

Exterior angles: ∠1, ∠2, ∠7, ∠8

Classifying the given pair of angles and their corresponding theorems:

2. ∠2 ≅ ∠8 → These angles belong to pair of Alternate exterior angles.

Theorem - "The alternate exterior angles are congruent"

3. ∠2 ≅ ∠4 → These belong to pair of vertically opposite angles.

Theorem - "The verticle angles are congruent"

4. ∠3 ≅ ∠5 → These belong to pair of alternate interior angles.

Theorem - "The alternate interior angles are congruent"

5. ∠3 is supplementary to ∠6 → These angles belong to pair of consecutive interior angles. Thus, they are supplementary.

Theorem - " The supplementary angles add up to 180°"

6. ∠4 ≅ ∠8 → These angles belong to pair of corresponding angles.

Theorem - " The corresponding angles are congruent".

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Eduro's mistake of solving the inequality -4x > 120 is adding 4 to both sides instead of dividing both sides by -4

minus four x greater than 120

-4x > 120

x < 120/-4

There is a change in the inequality sign from greater than to less than because the inequality is been divided by -4

x < -30

Check:

-4x > 120

-4(-30) > 120

120 > 120

Therefore, Eduro's mistake of solving the inequality -4x > 120 is adding 4 to both sides instead of dividing both sides by -4

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Answer: 0.032, 18, 4224, 7.58

Step-by-step explanation:

5. 5 L = 5000 mL = 5000 [tex]cm^{3}[/tex]

5000/(6*6*6) = 23 r 32 so 5 L of water can fill up 23 cubic tanks length 6 cm and is left with 0.032 L

6. There is (13 - 11) x 20 x 10 = 400 [tex]cm^{3}[/tex] left unoccupied in the box

400/23 = 17.4 so it takes 18 balls to overflow the water

7. 1 mL = 1 [tex]cm^{3}[/tex]

(a) 22 x 12 x 16 = 4224 [tex]cm^{3}[/tex] = 4224 mL

(b) 2 L = 2000 mL = 2000 [tex]cm^{3}[/tex]

22 x 12 = 264

2000/264 = 7.58 cm

Answer:

x = 7

Step-by-step explanation:

since the points all lie on the same line then the slopes of adjacent points will have the same slope.

calculate the slope using R and S then equate to slope using R and T or S and T

calculate slope using slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = R (- 5, - 3 ) and (x₂, y₂ ) = S (- 1, - 1 )

[tex]m_{RS}[/tex] = [tex]\frac{-1-(-3)}{-1-(-5)}[/tex] = [tex]\frac{-1+3}{-1+5}[/tex] = [tex]\frac{2}{4}[/tex] = [tex]\frac{1}{2}[/tex]

Repeat with (x₁, y₁ ) = R (- 5, - 3 ) and (x₂, y₂ ) = T (x, 3 )

[tex]m_{RT}[/tex] = [tex]\frac{3-(-3)}{x-(-5)}[/tex] = [tex]\frac{3+3}{x+5}[/tex] = [tex]\frac{6}{x+5 }[/tex]

equating [tex]m_{RS}[/tex] and [tex]m_{RT}[/tex]

[tex]\frac{6}{x+5}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )

x + 5 = 12 ( subtract 5 from both sides )

x = 7

The inverse of function f(x) = 9x+7 is f-1(x) = x/9 - 7/9

The function is given as:

f(x) = 9x + 7

Express f(x) as y

y = 9x + 7

Swap the positions of x and y in the above equation

x = 9y + 7

Subtract 7 from both sides

9y = x - 7

Divide through by 9

y = x/9 - 7/9

Express as an inverse function

f-1(x) = x/9 - 7/9

Hence, the inverse of function f(x) = 9x+7 is f-1(x) = x/9 - 7/9

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Answer:

  no solution

Step-by-step explanation:

The Law of Sines tells you the relationship between sides and angles of a triangle.

The Law of Sines tells you ...

  sin(A)/a = sin(B)/b = sin(C)/c

Using the given information, this would tell us ...

  sin(55°)/12 = sin(B)/b = sin(C)/27

Then angle C would be ...

  sin(C) = (27/12)sin(55°) ≈ 1.843

There is no angle whose sine is greater than 1. The triangle we seek does not exist. (Side BC is too short relative to side AB.)

Answer:

Step-by-step Explanation:

The correct option is C.

The algebraic expression for "seven more than the product of three and some number = 3x + 7 = 0

An algebraic expression is one that is composed of variables, integer constants, and algebraic operations. An algebraic expression is, for instance, 3x² 2xy + c.

we can search for the product of 3 and "some number",

Let the number be x.

So, the product of x is 3 times = 3x

And now

7 more then the Product .

we add the 7 to the product .

3x + 7 = 0

So the equation will be 3x + 7 = 0

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I understand that question you are looking for is:

Which of these is the algebraic expression for "seven more than the product of three and some number?"

A. 7 + 3 + x

B. 3 + 10 ÷ x

C. 3x + 7

D. 3 + 7x

Answer:

14m

Step-by-step explanation:

Please refer to the attached figure
B is the position where John is standing, His eyes are at point A, 2 meters from the ground

D is the base of the cliff and E is the top of the cliff

∠EAC is the angle at which John looks up to the cliff and is given as 45°

BD is the distance from the cliff given as 12m

So AC is also 12m

∠ACE is 90°

Therefore ∠AEC is 180-(45+90) = 45° since AEC forms a triangle and sum of angles in a triangle = 180°

In the ΔAEC, by the law of sines
12/sin(45) = EC/sin(45) . This means EC = 12 since the denominators cancel out

Since point C is 2 meters above ground(the base of the cliff) add 2 and we get the height of the cliff as 12+2 = 14m

Answer:

First:

5x + 9 < 2

x= 9/5= 1,8 < 2

Second:

x + 6 < 12

x= 12/6= 2 < 12

Answer:

t ≥ 36

Step-by-step explanation:

took a while but i had to try a lot of the numbers. hope it helped, mark me brainleist.

The inequality to represent the times when the phone would have at least as much battery charge as the tablet is t ≥ 36.

We know that t is the time,  in minutes, since Marcel plugged in the phone and the tablet.

For phone:-

Initial battery charge = 13%.

Rate of charging = 2% points in 3 minutes = 2/3 % in 1 minute.

Thus, the total charge on the phone after t minutes = 13% + t(2/3)%.

For tablet:-

Initial battery charge = 25%.

Rate of charging = 1% points in 3 minutes = 1/3 % in 1 minute.

Thus, the total charge on the tablet after t minutes = 25% + t(1/3)%.

We are asked to complete the inequality to represent the times when the phone would have at least as much battery charge as the tablet.

Since the phone is required to have at least as much battery charge as the tablet, we can show this as:

The total charge on the phone after t minutes ≥ The total charge on the tablet after t minutes,

or, 13% + t(2/3)% ≥ 25% + t(1/3)%,

or, t(2/3)% - t(1/3)% ≥ 25% - 13%,

or, t(1/3)% ≥ 12%,

or, t ≥ 12%/(1/3)%,

or, t ≥ 36.

Thus, the inequality to represent the times when the phone would have at least as much battery charge as the tablet is t ≥ 36.

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The descriptive statistics for the above data is given as follows:
X = 12.5

A set of concise descriptive coefficients that describe a particular data set indicative of a whole or sample population is known as descriptive statistics.

For X (mean) = [tex]{\displaystyle X={\frac {1}{n}}\sum _{i=1}^{n}X_{i}[/tex]

= 300/24

= 12.5

For sample variance = [tex]s^2 = \frac{1}{n-1}\biggl[\, \sum_{i=1}^n X_i^2 - \frac{\Bigl(\,\sum\limits_{i=1}^n X_i\Bigr)^{\!2}}{n} \biggr][/tex]

= (1/(24-1) (4,900 - (300²/24)

= 50

Standard deviation s = √s²

= √50

= 7.0711

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The area of the resulting surface of this infinite curve is π units.

In this question,

The infinite curve is y = e^−2x, x ≥ 0.

The curve is rotated about x-axis.

Since x ≥ 0, the limits will be 0 to ∞.

Then the area of the resulting surface is,

[tex]A= 2\pi \lim_{b\to \infty} (\int\limits^\infty_0{e^{-2x} } \, dx )[/tex]

Now substitute,

u = -2x

⇒ du = -2dx

⇒ dx = [tex]-\frac{1}{2} du[/tex]

Then,

[tex]\int\limits{-\frac{1}{2}e^{u} } \, du =-\frac{1}{2}\int\limits{e^{u} } \, du[/tex]

Now substitute u and du, we get

⇒ [tex]-\frac{1}{2} \int\limits {e^{-2x} }(-2) \, dx[/tex]

⇒ [tex]-\frac{-2}{2} \int\limits {e^{-2x} } \, dx[/tex]

⇒ [tex](1) \int\limits {e^{-2x} } \, dx[/tex]

⇒ [tex]\int\limits {e^{-2x} } \, dx[/tex]

Thus the area of the resulting surface is

[tex]A= 2\pi \int\limits^\infty_0{e^{-2x} } \, dx[/tex]

⇒ [tex]A= 2\pi [{e^{-2x}(\frac{1}{-2} ) } \,]\limits^\infty_0[/tex]

⇒ [tex]A= \frac{2\pi}{-2} [{e^{-2(\infty)}-e^{-2(0)} } \,]\\[/tex]

⇒ [tex]A= -\pi [0-1} \,]\\[/tex]

⇒ [tex]A= \pi[/tex]

Hence we can conclude that the area of the resulting surface is π units.

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Step-by-step explanation:

Yes, an positive average rate of change means that our endpoint of the interval is greater than the initial point of our interval. By definition, a function, f is increasing over an interval [a,b], if f(b)> f(a)

Yes, a positive average rate of change means that our endpoint of the interval is greater than the initial point of our interval.

It is the average amount by which the function changed per unit throughout that time period. It is calculated using the slope of the line linking the interval's ends on the graph of the function.

Yes, a positive average rate of change indicates that the endpoint of our period is higher than the interval's starting point. A function f is rising over the range [a,b] by definition if f(b)> f. (a)

Therefore, the positive average rate of change over an interval must be increasing over that interval.

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Answer:

give it a try

Step-by-step explanation:

Okay. I'm gonna flip five coins, but I'm told the first coin is Tell there's no choice there at all. It is certain the first coin shows a tail and then I want to have four heads in a row. Okay, so one for tell which means certain getting ahead is a half chance. Again a half chance again a half and again a half So that you work out and it's 1/16. That's the answer. There's no choice about the foreheads. It just has to be head every time I said.

The solutions for the given system are (3,2), (3,-2), (-3,2) and (-3,-2).

The quadratic function can represent a quadratic equation in the Standard form: ax²+bx+c=0 where: a, b and c are your respective coefficients. In the quadratic function the coefficient "a" must be different than zero (a≠0) and the degree of the function must be equal to 2.

The solution of these equations represents the points at which the parabolas intersect.

2x²+8y²=50 (1)

x²  + y²= 13 (2)

Multiplying the equation 2 by -2, you have:

2x²+8y²=50 (1)

-2x² -2 y²= -26(2)

Sum both equations, you have: 6y²= 24. Now, you can find y.

6y²= 24

y²=4

y=±2

If y=2, from equation 2, you have

x²  + y²= 13

x²  + 2²= 13

x²  + 4= 13

x² =13-4

x² =9

x=±3

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Answer: d. 40 pounds

Step-by-step explanation: let e equal the number of pounds weigh on Earth and m equal the number of pounds weighs on Mars.

so

72m=180e

1m= 72m/72

e= 180/72 = 2.5

1m=2.5e

16m=1 x16

e= 16 x 2.5

e= 40

so therefore, 16m=40e

I hope this helps

Answer:

10830.87 mm³

Step-by-step explanation:

Hello!

Volume of a cylinder: [tex]V = \pi r^2(h)[/tex]

The radius for this cylinder is 9.525, after dividing 19.05 by 2.

Plug it into the volume formula to solve for the volume.

The volume is approximately 10830.87 cubic millimeters.

Answer:

7

Step-by-step explanation:

You take the corresponding side that you know which is 10.5 and you multiply that by your scale factor of 2/3.

Another name for 10.5 is 10 [tex]\frac{1}{2}[/tex]  and that can be changed to [tex]\frac{21}{2}[/tex]

([tex]\frac{21}{2}[/tex])([tex]\frac{2}{3}[/tex])  The two's cancel out and we are left with [tex]\frac{21}{3}[/tex]  Which is the same as 7.

The ratio of the volume of pipe a to the volume of pipe b is 27:1  .

A cylinder is a three-dimensional shape consisting of two parallel circular bases, joined by a curved surface. The center of the circular bases overlaps each other to form a right cylinder.

Given that,

Radius of pipe a is 6 cm, and the radius of pipe b is 2 cm.

We know that the volume of cylinder is :- [tex]\pi r^{2}h[/tex]

where r is radius and h is height of the cylinder.

If two figures are similar then ratio of volume is equal to the cube of any dimension.

The ratio of the volume of Pipe a to the volume of Pipe b  :-

[tex]\frac{V(a)}{V(b)}=\frac{6^{3} }{2^{3} }[/tex]

       = [tex]\frac{27}{1}[/tex]

Hence, The ratio of the volume of pipe a to the volume of pipe b is 27:1 .

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28. 1.45l ÷ 0.32l = 4.53125

so approximately 5 glasses to leave the bottle empty

29. 5.6kg + 2.5kg = 8.1kg

8.1kg ÷ 0.48 = 16.875

he can make 16 complete doughs

there will be 0.875kg of flour left

The second tree is 56.4 ft tall.

Triangles with the same shape but different sizes are said to be similar triangles. Squares with any side length and all equilateral triangles are examples of related objects. In other words, if two triangles are identical, their respective sides are equal in number and their corresponding angles are congruent.

Let the length of the tall tree be x. Thus by similarity of triangles we get,

Length of small tree/ Shadow Length of small tree =

Length of  Tall tree/ Shadow Length of tall tree

Substituting the values we get,

5.6/4.2 = x/42.3

x = 56.4

Thus the second tree is 56.4 ft tall.

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The solution to the given differential equation is yp=−14xcos(2x)

The characteristic equation for this differential equation is:

P(s)=s2+4

The roots of the characteristic equation are:

s=±2i

Therefore, the homogeneous solution is:

yh=c1sin(2x)+c2cos(2x)

Notice that the forcing function has the same angular frequency as the homogeneous solution. In this case, we have resonance. The particular solution will have the form:

yp=Axsin(2x)+Bxcos(2x)

If you take the second derivative of the equation above for  yp , and then substitute that result,  y′′p , along with equation for  yp  above, into the left-hand side of the original differential equation, and then simultaneously solve for the values of A and B that make the left-hand side of the differential equation equal to the forcing function on the right-hand side,  sin(2x) , you will find:

A=0

B=−14

Therefore,

yp=−14xcos(2x)

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The double integral. 7x cos(y) da, d is bounded by y = 0, y = x2, x = 7 d is given as

[tex]\int _D 7xcosydA =7/2(-cos49+1)[/tex]

Generally, the equation for is  mathematically given as

The area denoted by the letter D that is bordered by y=0, y=x2, and x=7

The equation for the X-axis is y=0.

y=x² ---> (y-0) = (x-0)²

Therefore, the equation of a parabola is y = x2, and the vertex of the parabola is located at the point (0,0), and the axis of the parabola is parallel to the Y axis.

The equation for a straight line that is parallel to the Y-axis and passes through the point (7,0) is x=7.

[tex]\int _D 7xcosydA\\\\\int^7_0 \int^x^2 _0 7xcosydA[/tex]

Integrating we have

[tex]7/2 \int^7_0 (2xsinx^2)dx[/tex]

If x equals zero, then we know that u equals zero as well.

When x equals seven, we know that u=72=49.

Therefore, by changing x2=u into our integral, it becomes from

 [tex]7/2 \int^7_0 (2xsinx^2)dx[/tex]

[tex]7/2 \int^49_0 sin u dx[/tex]

Hence

=7/2(-cos49+1)

In conclusion,

[tex]\int _D 7xcosydA =7/2(-cos49+1)[/tex]

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