Answer:
4
Step-by-step explanation:
3a, 2b, (1)c, and 100 are all their own terms. None of them having the same variable making them each their own. (including whole numbers without a variable, the absence of a variable still means its a term)
X-3
If f(x) =
and g(x) = 5x - 4, what is the domain of (fog)(x)?
X
{x1x*}
use coordinate notation to write the rule that maps each preimage to its image. Then confirm that the transformation is not a rigid motion.Number 8
In geometry, transformation involves changing the position and/or size of a shape.
The coordinate notations are:
[tex](x,y) \to (\frac{1}{2}x,\frac{1}{2}y)[/tex]. [tex](x,y) \to (2x,y)[/tex].Both transformations are not rigid
[tex]7.\ \triangle ABC \to \triangle A'B'C'[/tex]
Using coordinates A and A', as a reference;
We have:
[tex]A = (6,6)[/tex]
[tex]A' = (3,3)[/tex]
Divide A' by A to get the scale ratio (k)
[tex]k = \frac{A'}{A}[/tex]
[tex]k = \frac{(3,3)}{(6,6)}[/tex]
Factorize
[tex]k = \frac{(3,3)}{2 \times (3,3)}[/tex]
[tex]k = \frac{1}{2}[/tex]
Hence, the coordinate notation is:
[tex](x,y) \to (\frac{1}{2}x,\frac{1}{2}y)[/tex]
Calculate distance AB and A'B' using:
[tex]d = \sqrt{(x_2 - x_1)^2 +(y_2 - y_1)^2}[/tex]
So, we have:
[tex]AB = \sqrt{(6 - 4)^2 +(6 - -2)^2} = \sqrt{68}[/tex]
[tex]A'B' = \sqrt{(3 - 2)^2 +(3 - -1)^2} = \sqrt{17}[/tex]
Because
[tex]AB \ne A'B'[/tex]
We've confirmed that the transformation is not rigid
[tex]8.\ \triangle FGH \to \triangle F'G'H'[/tex]
Using coordinates F and F';
We have:
[tex]F = (-1,1)[/tex]
[tex]F' = (-2,1)[/tex]
Divide the x-coordinate of F' by F to get the scale ratio (k) because the y-coordinates of the pre-image and the image are the same
[tex]k = \frac{F'}{F}[/tex]
[tex]k = \frac{-2}{-1}[/tex]
[tex]k = 2[/tex]
Hence, the coordinate notation is:
[tex](x,y) \to (2x,y)[/tex]
Calculate distance FG and F'G' using:
[tex]d = \sqrt{(x_2 - x_1)^2 +(y_2 - y_1)^2}[/tex]
So, we have:
[tex]FG = \sqrt{(-1 - 1)^2 +(1 - -1)^2} = \sqrt{8}[/tex]
[tex]F'G' = \sqrt{(-2 - 2)^2 +(1 - -1)^2} = \sqrt{20}[/tex]
Because
[tex]FG \ne F'G'[/tex]
We've confirmed that the transformation is not rigid
Read more about transformations at:
https://brainly.com/question/11709244
What is the common difference -30,70,170,270
select the correct answer
1.caul will be the measure of one of the legs of a right triangle, if its hypotenuse is 10 cm and leg b is 6 cm, what will be the measure of leg a?
a) 8 cm
b) 5 cm
c) 4 cm
d) 12 cm
please
Answer:
answer us a) 8cm
Step-by-step explanation:
a^2 + 6^2 = 10^ 2
a^2 + 36 = 100
subtract 36 from 100
a^2 = 64
square root of 64 is 8
What is the equation of the line that passes through the point (-7, 2) and has a
slope of -1
Answer:
y = -x - 5
Step-by-step explanation:
y = mx + b
slope = m = -1
y = -1x + b
y = -x + b
Plug in (-7, 2) for x and y, and solve for b.
2 = -(-7) + b
2 = 7 + b
b = -5
y = -x - 5
Plz help I need help now plz
Answer:
-840
Step-by-step explanation:
When we multiply two intergers with the same sign, the product will be positive. When we multiply intergers with different signs, the quotient will be negative
[tex]( - 5) \times ( - 3) = 15[/tex]
[tex]15 \times ( - 8) = - 120[/tex]
[tex] - 120 \times 7 = - 840[/tex]
Find all of the points of the form (x, −x) which are 7 units from the origin.
(x, y) =
(smaller x-value)
(x, y) =
(larger x-value)
Answer:
(-7, 0) and (7, 0)Step-by-step explanation:
All the points that are 7 units from the origin are on the circle:
x² + y² = 7²The maximum and minimum values of x obtained when y = 0:
x² = 7² √x² = √7²x = ± 7So
min x = -7 and max x = 7The points are:
(-7, 0) and (7, 0)The equation will be
[tex]\\ \sf\longmapsto \sqrt{x^2+y^2}=7[/tex]
[tex]\\ \sf\longmapsto x^2+y^2=7[/tex]
If y be 0[tex]\\ \sf\longmapsto x^2+0=7^2[/tex]
[tex]\\ \sf\longmapsto x^2=49[/tex]
[tex]\\ \sf\longmapsto x=\sqrt{49}[/tex]
[tex]\\ \sf\longmapsto x=\pm 7[/tex]
Now the points are
(7,0)(-7,0)Fill in the blank
30.030___30.03
Answer:
=
Step-by-step explanation:
A triangle has vertices A (0,0) B (2,6) and (0,4) Rotate it 180 clock wise about the origin followed by a dilation with a scale factor of 3 find the coordinates of the vertices of A’ B’ C’ and state whether the two triangles are congruent or similar
9514 1404 393
Answer:
A'(0, 0), B'(-6, -18), C'(0, -12)Step-by-step explanation:
Rotation 180° is the transformation ...
(x, y) ⇒ (-x, -y)
Dilation by a factor of 3 is the transformation ...
(x, y) ⇒ (3x, 3y)
The two transformations together can be described by ...
(x, y) ⇒ (-3x, -3y)
That is, the coordinates of A, B, C are each multiplied by -3. The image vertices are ...
A' = -3A = A'(0, 0) . . . . . . . . the center of rotation and dilation is invariant
B' = -3B = B'(-6, -18)
C' = -3C = C'(0, -12)
Any dilated figure will not be congruent to the original. The triangles are similar.
Which statement is true about the function?
A.
The function is negative on the interval .(n/2,n)
B.
The function is positive on the interval .(3n/4, 5n/4)
C.
The function is positive on the interval .(x/4, 3n/4)
D.
The function is negative on the interval .(5x/4, 7n/4)
Answer:
A
Step-by-step explanation:
During the Interval, pi/2 to pi, the function is below the x axis, so it is negative
Answer:
A. The function is negative on the interval .(n/2,n)
Step-by-step explanation:
edmentum
x=15 is this a function how do you do it
Answer:
Step-by-step explanation:
X-1=5x+3x-8
solve for x, step by step
Answer:
x=1
Step-by-step explanation:
X-1=5x+3x-8
X-5x-3x=-8+1
-7x=-7
-7x/-7=-7/-7
x=1
Please help now. I’m very confused and i don’t no how to do this. I don’t want just the answer but a great explanation.
Answer:
First option
Step-by-step explanation:
Hi there!
The "constant additive rate of change" means a constant slope.
The slope is [tex]\displaystyle\frac{change \hspace{4} in \hspace{4} y}{change \hspace{4} in \hspace{4} x}[/tex].
First of all, if the slope is constant, then we know immediately that it must be a linear function, a line. The change in y is forever the same according to the change in x. Knowing this, the second option is for-sure wrong (it's not a straight line).
Now, let's look at the first option. It is a linear function, which means it has a constant slope. However, we're given that the slope is [tex]-\displaystyle \frac{1}{4}[/tex]. This means that for a line, whenever it travels 4 units to the right, it travels 1 unit down (it travels down whenever the slope is negative and up whenever the slope is positive).
This is the exact case for the first option. Look at the point (-2,2) on the line. When we move 4 units to the right of that point, The line would have moved 1 unit down. We would reach the point (2,1).
Therefore, the correct answer would be the first option.
I hope this helps!
What shape is this? Plz help
Answer:
I think it is a triangle..
Answer:
A triangle
Step-by-step explanation:
Even if you split the shape in half it still maintains to have 3 sides making it a triangle.
Help fast! Round the measurement 1258 mL into three significant figures
Answer:
1000mL, 1300mL and 1260mL
Step-by-step explanation:
Find 10x+y when x= 10 and y = 3.
The answer is
Answer:
[tex]10x + y \\ 10(10) + 3 \\ 100 + 3 = 103[/tex]
I hope I helped you^_^
6 + 5y - 4y + 10 + 3x - X
Answer:
2 + + 1 6
Step-by-step explanation:
Add the numbers:
6 + 5y - 4y + 10 + 3x -x =
1 6 + 5 − 4 + 3 −
Combine like terms:
16 + 5y - 4y +3x - x
16+ 1y + 3x -x
Multiply by 1
16 + 1y + 3x - x
16 + y + 3x - x
Combine like terms:
16 + y + 3x - x
16 + y + 2x
Rearrange terms:
16 + y + 2x
2x + y + 16
Answer:
16 + y + 2x
Step-by-step explanation:
[tex]6 + 5y - 4y + 10 + 3x - x[/tex]
[tex]16 + 5y - 4y + 3x - x[/tex]
[tex]5y - 4y = (5 - 4)y = 1y = y[/tex]
[tex]16 + y + 3x - x[/tex]
[tex] = 16 + y + 2x[/tex]
Which irrational number is between 9 and 10?
Find the probability that a student earns a grade of A,B, or C
P=
Answer:
Step-by-step explanation:
Answer: 0.86
Step-by-step explanation:
please show work hahah I really suck with these equations f – 6 = -2f + 3(f – 2)
Step-by-step explanation:
I tried my best to answer this question I guess this would help
A box contains six red playing cards numbered one to six and also six black playing cards numbered one to six. What is the probability of picking a card that is black or has an even number?
A. 1
B. 1/2
C. 1/4
D. 3/4
If f(x)=5x-11 what is f(1)? f(3)?
Answer:
jhbgjbfvjbdfkvbdkbnxkhfb kxvnxkvbfvkbchbfcnccfkxkhvchjjj
Step-by-step explanation:
dywfrfvyetwfkfgffyffusofgsjfdgsdlcgslvgsivsfgfisfgisfdyfdic
Step-by-step explanation:
Hi there!
Given;
f(x) = 5x-1
Now; Simply keep the value of x in the given function.
f(1) = 5*1-11
= -6
Again;
f(3) = 5*3-11
= 15-11
= 4
Therefore, f(1) = -6 and f(3) = 4.
Hope it helps!
What is 25 x 34 in simplest form
Josef has $300 to spend. Which inequality could help him find the maximum number of gifts, x, he could buy if he needs $215 to fix his car and then wants to spend $15 on each gift?
Answer:
x = (300 - 215)/15
Step-by-step explanation:
x, the amount of gifts, is equal to the amount of money left over after he fixes his car, divided by the amount he's willing to spend on each gift.
josef could buy a maximum of 5 gifts! the answer is 5.6 but he can't buy half a gift, nor can he afford 6, so we round down to get 5 gifts :)
Answer:
Josef can buy 5 gifts for 75$
Solve
| 2x + 6 | = x
Answer:
1) soln,
or,2x+6=x
or,2x-x= -6
or,x= -6
•°•x= -6 Ans#
Use the diagram to find the measures of the lengths of the sides. The perimeter of the trapezoid on the right is 93
inches.
Answer:
Step-by-step explanation:
Answer:
wait- i think its this: 14, 14, 21, 47
Step-by-step explanation:
Find the values of the trigonometric functions of t from the given information. sec(t) = 2, terminal point of t is in Quadrant IV
Answer:
The values of the trigonometric functions of t
[tex]$\sin t=-\frac{\sqrt{3} }{2}[/tex]
[tex]\cos t=\frac{1}{2},[/tex]
[tex]\tan t=-\sqrt{3}[/tex]
[tex]$\csc t-\frac{2}{\sqrt{3} }[/tex]
[tex]\sec t=2[/tex]
[tex]\cot t=\frac{1}{\sqrt{3} }[/tex]
Step-by-step explanation:
Given:
[tex]\sec(t)=2[/tex]
The terminal point of [tex]t[/tex] is in Quadrant [tex]IV[/tex]
Step 1:
To find the values of trigonometric functions of t
[tex]\sec(t)=\frac{H}{A}[/tex]
[tex]=\frac{2}{1}[/tex]
Analyze the figure and find the value of O
[tex]t[/tex] ∈ [tex]IV[/tex]
[tex]O=\sqrt{2^{2}-1^{2} }[/tex]
[tex]=\sqrt{4-1}[/tex]
[tex]=\sqrt{3}[/tex]
Step 2:
[tex]$\sin t=-\frac{O}{H}[/tex]
[tex]=-\frac{\sqrt{3} }{2}[/tex]
[tex]\cos t=\frac{A}{H}[/tex]
[tex]=\frac{1}{2}[/tex]
[tex]\tan t=-\frac{O}{A}[/tex]
[tex]=-\sqrt{3}[/tex]
[tex]$\csc t=-\frac{H}{O}[/tex]
[tex]=-\frac{2}{\sqrt{3} }[/tex]
[tex]\sec t=\frac{H}{A}[/tex]
[tex]=\frac{2}{1}[/tex]
[tex]\cot t=-\frac{A}{O}[/tex]
[tex]=\frac{1}{\sqrt{3} }[/tex]
Learn more about trigonometry functions, refer:
https://brainly.com/question/16693162Jacob took a total of 4 quizzes over the course of 3 weeks.
How many weeks of school will Jacob have to attend this quarter before he will have taken 16 quizzes?
Answer:
The answer would be a total of 12 weeks .
Step-by-step explanation:
Because the first four test were in a total of three weeks
so in order to find out how many weeks for 16 quizzes just multiply
4 quizzes -3 weeks
8 quizzes -6 weeks
12 quizzes - 9 weeks
16 quizzes - 12 weeks
SO just multiply 4 by 4 and multiply 4 by 3
1.1.PS-8
Write 6.81 as a mixed number in simplest form.
6.81
Answer: when you simplify it you get 6 81/100 and you cant go any further because you will start to get into approximate values.
Step-by-step explanation:
The (minmum or maximum) value is __?
Can someone help me please, thank you
Answer:
-1 ,+1 i hope it helps mark me as brainliest
