Answer:
Explanation:
The use of nonrenewable energy resources, such as coal, oil, and natural gas, has changed significantly over the past 30 years. Some key changes include:
Increased use of natural gas: The use of natural gas as an energy source has increased significantly in recent years, due to the development of new technologies that have made it easier and more cost-effective to extract and transport natural gas. This has led to a decrease in the use of coal as an energy source, as natural gas is cleaner and more efficient.Increasing use of renewable energy sources: Over the past 30 years, there has been a growing focus on renewable energy sources, such as wind, solar, and hydro power, as a way to reduce the dependence on fossil fuels and lower greenhouse gas emissions. The growth of renewable energy sources has been supported by government policies, technological advances and decreasing costs.Increase in the use of electric cars: Electric cars are becoming increasingly popular in recent years and this is expected to continue as the technology improves and the cost of batteries decreases. Electric cars are more energy-efficient and have lower emissions than traditional gasoline cars.Changes in oil consumption: The consumption of oil for transportation has decreased over the past 30 years due to more efficient vehicles and more use of biofuels. However, oil consumption for electricity generation and industrial use has remained relatively constant.Overall, the past 30 years have seen a shift away from traditional fossil fuels towards cleaner and more sustainable energy sources, driven by concerns about climate change and environmental degradation.
Explain how to convert SI units by using the prefixes.
Use 1 for the prefixed component and the power of 10 in front of the base unit when establishing a conversion factor to or from that SI units.
Why does the SI prefix exist?The International System of Units, or SI, has a variety of prefixes for its units. These may refer to exceedingly little or extremely huge amounts. Though storage is not an official SI unit, they are most generally used in computing to represent to storage capacity, such as bytes.
What do physics prefixes mean?Prefixes are words that are used to describe very large or very small quantities and are added before the SI units. For particular, kilo is the prefix for 103. Prefix femto has a multiplier of 10^-15.
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6. A loaded 10 000 kg train freight car (ma) roll at 3 m. -1 to the right toward a
2 000 kg freight train car travelling at 4 m. –1 in the oppoite direction. On
colliion, the two car couple (lock together). A) What i the velocity of the two freight train car after the colliion? (4)
b) Calculate the impule exerted on each freight train car. (4)
c) If the colliion lat 0,7 , calculate the net force exerted on each freight
train car. (4)
d) Show that thi i an inelatic colliion
A) The velocity of the two freight car is 1.83 m/s, B) The impulse exerted on each freight train car is 22000 kg-m/s, C) The net force exerted on each freight train car is 31428.6 N.
Mass of the loaded freight car, m₁ = 10000 kg
Initial velocity of the loaded freight car, v₁ = 3 m/s
Mass of the empty freight car, m₂ = 2000 kg
Velocity of the empty freight car, v₂ = -4 m/s
Let the velocity of the coupled car after collision, = v
By the law of conservation of momentum,
m₁v₁ + m₂v₂ = (m₁+m₂)v
A) v = (10000×3 - 2000×4)/(10000+2000)
v = 1.83 m/s
B) Impulse = change in momentum(Δp)
Δp = 10000×3 - 2000×4 = 22000 kg-m/s
C) Net force, F = Impulse/time = 22000/0.7
F = 31428.6 N
D) The collision is inelastic as the final speed of both the car is less than their initial velocities.
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a 75 kg boy moves 4m of lawn the lawn mower weighs 250 N if he applies 15 N along the direction the lawn mower moves how much work has been done on the lawn mower?
3750N work has been done on the lawn mower, the work done is equal to 1 joule.
How are work hours determined?
Work = Force x Distance is an equation that can be used to determine work. The Newton meter (N m) or joule (J) is the SI unit for work. When an item is moved 1 N of force over a distance of 1 m, the work done is equal to 1 joule.The displacement and component of the applied force of the object in the direction of displacement are the two factors that make up the work done by a force. The body moves more quickly and task is completed when we push a block with some force.250N * 15N = 3750N.
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three equal point charges of 1.2 nc are placed at the corners of an equilateral triangle whose sides are 0.500 m long. a. what is the potential energy of the system? (take as zero the potential energy of the three charges when they are infinitely far apart.) b. what is the electric potential at the the center of the triangle?
The potential energy of the system is -1.44 × 10^-19 J. The electric potential at the center of the triangle is zero.
a. To calculate the potential energy of the system, we need to find the force between the three charges and then multiply it by the distance. Using Coulomb's Law, the force between two charges can be calculated as F = k * q1 * q2 / r^2, where k is the Coulomb constant, q1 and q2 are the charges and r is the distance between them.
In this case, the charges are equal and the distance between them is 0.500 m, so the force between two charges can be calculated as
F = 8.99 * 10^9 * 1.2 * 10^-9 * 1.2 * 10^-9 / (0.500 * 10^-3)^2 = 2.64 * 10^-9 N.
The potential energy can be calculated as U = -F * d = -2.64 * 10^-9 * 0.500 * 10^-3 = -1.44 * 10^-19 J.
b. To calculate the electric potential at the center of the triangle, we need to find the electric field at that point. The electric field is given by E = F / q, where F is the force and q is the charge.
In this case, the charge is 1.2 * 10^-9 C, so the electric field can be calculated as
E = 2.64 * 10^-9 / 1.2 * 10^-9 = 2.2 * 10^9 N/C.
Since the electric potential is given by V = E * d, we can calculate the electric potential at the center of the triangle as
V = 2.2 * 10^9 * 0.25 * 10^-3 = 0.55 V.
However, the potential energy of the system was taken as zero when the charges were infinitely far apart, so the electric potential at the center of the triangle is actually zero.
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How high up did the waitress lift the 21.96 N tray when she did 97.91 J of work on it for 3 s? Please help!! fast!
It will be like over 2.4353m
6 Newton's third law involves two quantities which are equal in size and opposite in direction. What is the unit for these two quantities? AJ B. m/s2 C - N D W ?
The unit of the two quantities used in the Newton's third law is Newton, which is denoted by N.
Newton's third law states that there is equal and opposite reaction for every action, In other words, There is an equal reaction for every force, but in the direction opposite to direction of the force. These forces are the quantities which are used in this law. The SI unit of reaction and force is Newton, which is equal to kg-m/s². It is denoted by N. It is formulated as: Force = mass × Acceleration.
F = m × a
Hence the correct option is C.
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express an osmotic pressure of 7 atm in units of dyne/cm2.
An osmotic pressure of 7 atm in units of [tex]\frac{dyne}{cm^{2} }[/tex] is [tex]7\times10^{6}\frac{dyne}{cm^{2} }[/tex].
Osmotic pressure and various other colligative properties of solutions are closely connected. These are induced by solutes dissolving in a solution and include the freezing point depression, boiling point elevation, and vapour pressure depression. Instead than using direct measurements of osmotic pressure, the osmolarity is frequently calculated from vapour pressure depression or freezing point depression. The concentration required to witness these phenomena is called osmolarity.
Albumin and other macromolecules inside the intravascular compartment exert an osmotic force known as colloid osmotic pressure (COP), also known as oncotic pressure, which balances the hydrostatic forces of the capillaries and venules to determine the net fluid flux across the endothelium.
Now, 1 atm=1.03bar
and 1.03 bar=[tex]10^{6}\frac{dyne}{cm^{2} }[/tex]
So, 7 atm=[tex]7\times10^{6}\frac{dyne}{cm^{2} }[/tex]
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your mass is 80 kg. the area of one of your shoes that is in contact with the ground is 0.012 . while standing stationary on your two feet, what is the pressure that you exert on the ground?
The required pressure exerted on the ground when mass and area are given is calculated to be 65.3 kPa.
Mass of the person is given as 80 kg.
Area of one of the shoes in contact with the ground is 0.012 m².
Force exerted is calculated as,
F = m a = 80 × 9.8 = 784 N
The pressure exerted on the ground is to be found out.
The expression for pressure is said to be known as,
P = F/A
where,
P is pressure
F is force
A is area
Putting the values into the above expression, we have,
P = F/A = 784/0.012 = 65333.3 Pa = 65.3 kPa
Thus, the pressure exerted on the ground is calculated to be 65.3 kPa.
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Students want to determine the impulse of an object. List the three ways the students can find the impulse.
2 have already been found: final momentum - initial momentum, and force x time.
Three ways the students can find the impulse are : a)Impulse = Force * time = force * Delta t. Delta t = t^final - t^initial b)Impulse = Delta p = p^final - p^initial c) J=Ft, or impulse (J) is equal to force (F) times time (t).
What is impulse?Impulse is an integral of force, F, over the time interval, t, for which it acts. As force is a vector quantity, impulse is also vector quantity. Impulse applied to an object produces equivalent vector change in its linear momentum and also in the resultant direction.
Impulse is a certain amount of force you apply for certain amount of time to cause a change in the momentum. For example, when you hit a ball with cricket bat, you apply force for a time to cause a change of momentum in the ball.
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what is the vapor pressure of solvent a at 25 °c? this solvent has a normal boiling point of 80.1 °c. the ∆hvap for solvent a is 30.5 kj/mol.
The vapor pressure of solvent A at 25 °C is approximately 2.93 atm, if this solvent has a normal boiling point of 80.1 °c. the ∆hvap for solvent a is 30.5 kj/mol.
The vapor pressure of a solvent can be estimated using the Clausius-Clapeyron equation, which relates the vapor pressure of a substance to its normal boiling point and enthalpy of vaporization. The equation is:
ln(P2/P1) = ΔHvap/R * (1/T1 - 1/T2)
Where P1 and P2 are the vapor pressures at two temperatures, T1 and T2, ΔHvap is the enthalpy of vaporization, and R is the gas constant. We can rearrange the equation to solve for the vapor pressure at a given temperature:
P = P1 * exp(ΔHvap/R * (1/T1 - 1/T2))
In this case, the normal boiling point of solvent A is 80.1 °C, so T1 can be taken as that temperature. The temperature we want to find the vapor pressure for is 25 °C, so T2 is 25 + 273.15 = 298.15 K. The enthalpy of vaporization of solvent A is given as ΔHvap = 30.5 kJ/mol.
Plugging in these values and using the ideal gas law to convert pressure units, we find:
P = 1 atm * exp(30.5 kJ/mol / (8.314 J/mol*K) * (1/371.15 K - 1/298.15 K))
P = 2.93 atm
So the vapor pressure of solvent A at 25 °C is approximately 2.93 atm.
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a 10 kg object is moving in a straight-line with an initial speed of 2 m/s. how long (in s) will it take for the speed of the object to increase to 10 m/s if its kinetic energy increases at a rate of 20 j/s? you may treat this as an isolated system. a 10 kg object is moving in a straight-line with an initial speed of 2 m/s. how long (in s) will it take for the speed of the object to increase to 10 m/s if its kinetic energy increases at a rate of 20 j/s? you may treat this as an isolated system.
10 kg object is moving in a straight line with an initial speed of 2 m/s.it will take 8 seconds for the speed of the object to increase to 10 m/s if its kinetic energy increases at a rate of 20 j/s.
In an isolated system, energy is conserved, meaning that the total energy of the system remains constant. In this case, the rate of energy increase is 20 J/s, meaning that 20 J of energy is added to the system each second. This energy is used to accelerate the object, increasing its kinetic energy and thus its speed.
The equation t = (KE2 - KE1)/P can be used to calculate the amount of time it takes for an object to accelerate from one speed to another given a rate of energy increase. In this case, the object is accelerating from an initial speed of 2 m/s to a final speed of 10 m/s, and the rate of energy increase is 20 J/s. Therefore, it will take 8 seconds for the object to reach its final speed.
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Shira is trying to decide between getting a debit card, a prepaid debit card, and a credit card.
Which statement is true?
(2 Points)
O All 3 cards are completely different
O Debit cards and prepaid debit cards are the same
O Debit cards and credit cards are the same
O All 3 cards are completely the same
Answer:
All 3 cards are completely different
what other structures have the similar characteristic as the parthenon?
The Parthenon is a famous ancient Greek temple known for its classical architecture, which was built in Athens between 447 and 432 BC.
Many other structures have been inspired by the Parthenon and have similar characteristics, including:
The Propylaea: A monumental gateway to the Acropolis in Athens, Greece, built during the same time period as the Parthenon.The Temple of Athena Nike: Another temple on the Acropolis in Athens, which also embodies the classic Greek architectural style.The Erechtheum: A temple on the Acropolis in Athens, which is known for its intricate and decorative carvings.The Temple of Olympian Zeus: A massive temple in Athens, Greece, dedicated to the god Zeus, and similar in design to the Parthenon.The Maison Carrée: A well-preserved Roman temple in Nîmes, France, which was built in the same classical architectural style as the Parthenon.The Pantheon: A temple in Rome dedicated to all the gods, and renowned for its iconic dome and classical columns, similar to the Parthenon.These structures, like the Parthenon, showcase the beauty and elegance of ancient Greek architecture and its influence on other cultures and time periods.
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what type of seismic movements destroy buildings the most?
Seismic movements that cause the most destruction to buildings are typically caused by waves known as "surface waves". These waves have the greatest amplitude (movement), and therefore the greatest potential for causing damage, especially to tall structures.
The two main types of surface waves are Love waves and Rayleigh waves. Love waves move horizontally, causing buildings to shake from side to side, while Rayleigh waves move both horizontally and vertically, leading to a rolling motion.
When these waves move through the ground, they can cause buildings to sway or vibrate, potentially leading to structural damage or even collapse. The specific type of surface wave that causes the most damage depends on the frequency of the wave and the size and type of building. For example, low-frequency waves can cause tall buildings to vibrate and potentially collapse, while high-frequency waves can cause smaller buildings to shake violently. The type of soil and rock beneath the building also play a role in how much damage is caused, as certain types of soil can amplify or dampen the waves as they move through the ground.
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a car goes from 0 to 60 mph in 7.0 seconds. if it could maintain this acceleration at higher speeds, how long would it take the car to go from 0 to 120 mph?
In 7.0 seconds, an automobile can accelerate from 0 to 60 mph. It would take the car about 14.0 seconds to accelerate from 0 to 120 mph if it could maintain this acceleration at higher speeds.
Acceleration is :-
a = (vf - vi) / t
= (60 mph - 0 mph) / 7 s
= 8.57 mph/s.
Now that we know the acceleration of the car, we can calculate the time it takes to reach 120 mph using the kinematic equation:
v = vi + at, where v is final velocity, vi is initial velocity and t is time.
Now, equation for t, is:
t = (v - vi) / a
= (120 mph - 0 mph) / 8.57 mph/s
= 13.99 s.
Therefore, it would take approximately 14.0 seconds for the car to go from 0 to 120 mph if it could maintain the acceleration of 8.57 mph/s.
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a car has a mass m, and a weight, w, on earth. what is the car’s mass and weight on a planet which has three times the mass of the earth and twice the radius of the earth?
The mass of the car will be same as m, and its weight will be 3w/4 on the planet which has three times the mass of the earth and twice the radius of the earth.
Mass is a constant quantity of an object which remains constant irrespective of the place, where the object is placed. So the mass will remains the same as m.
Acceleration due to gravity of earth is defined as, g = GM/R²
Where G is universal gravitational constant, M is the mass of the earth, and R is the radius of the earth.
Mass of the planet, = 3M
Radius of the planet, = 2R
Acceleration due to gravity of the planet, g₁ = G(3M)/(2R)²
g₁ = 3GM/4R²
g₁ = 3g/4
We know
weight on a planet = mass × acceleration due to gravity of that planet
w = mg
w₁ = mg₁
w₁ = m(3g)/4
w₁ = 3mg/4
w₁ = 3w/4
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what is the speed, in meters per second, of the jet 4.84 s after it leaves the deck of the carrier
A military aircraft can take off from an aircraft carrier at a speed of about 170 miles per hour.
They achieve this speed by combining the jet propulsion system of the aircraft with a catapult system installed on the aircraft carrier. Large commercial planes may travel between 550 and 580 miles per hour, but their takeoff and landing speeds can differ. Most commercial aircraft fly between 160 and 180 miles per hour, with landing speeds between 150 and 165 mph. Starting at rest, it moves at a speed of 72.7 m/s while rolling 86.4 m along the deck to the end of the runway. At that moment, the jet exits the deck and accelerates at a new rate of 5.19 m/s2 at a position of 32 degrees above the ground.
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Simplify the following expression in terms of the dimensions mass, length, and time given by [M], [L], and [T].
[M][L]^2/[t]^2 . [T]/[L] = ?
a. [M] [L]/[T]^2
b. [M] [L]/[T]
c. [T][L]/[M]
d. [M] [T]/[L]
e. [M][L]^2/[T]
The required solution of the dimensional formula is calculated to be [M][L]/[T]. Correct option is B.
Dimensional analysis is the practice of checking relations between physical quantities by identifying the dimensions of the physical quantities.
If Q is the unit of a derived quantity represented by Q = M^a L^b T^c, then M^a L^b T^c is called the dimensional formula and the exponents a, b, and c are called the dimensions.
The given expression is the multiplication of dimensional formulae of two different physical quantities.
We know that,
Mass m = [M]
Length l = [L]
Time t = [T]
The given expression to solve is,
[M][L]²/[T]² . [T]/[L] = [M][L]/[T]
Thus, the required solution of the given expression is [M][L]/[T].
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Consider S:M (i.e. surface area to mass ratio) of an object. What happens to the ratio when the density of an object decreases while the surface area and volume remain the same?Group of answer choices:it increasesthe outcome cannot be determinedit depends on the nature of the material in the objectit decreasesit remains the same
The ratio of surface area to mass when the density of an object decreases while the surface area and volume remain the same, increases. The correct option is A.
An object's surface area and volume don't change, but its density does. The formula for density
ρ = m ÷ V
V = m ÷ ρ
m = mass (kg)
V = volume (m³)
ρ = the density (kg/m³)
The density decreases
ρ₁ > ρ₂
The surface area remains the same
A₁ = A₂
The volume remains the same
V₁ = V₂
V₁ = V₂
m₁ ÷ ρ₁ = m₂ ÷ ρ₂
m₂ × ρ₁ = m₁ × ρ₂
m₂ = (m₁ × ρ₂) ÷ ρ₁
ρ₁ > ρ₂
m₂ < m₁
The density decreases, and the mass also decreases.
The quantity of surface area per unit mass of an object is known as the surface area to mass ratio.
S:M = A ÷ m
At initial (S:M)₁ = A₁ ÷ m₁
At final (S:M)₂ = A₂ ÷ m₂
A₁ = A₂
m₂ < m₁
(S:M)₂ > (S:M)₁
Thus, the surface area to mass ratio will increase.
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does the average mass of the object, based on the experimental trials, agree with the mass measured with a digital scale?
To determine if the average mass of the object, based on the experimental trials, agrees with the mass measured with a digital scale, you will need to compare the two values.
If the difference between the two values is small, then the average mass of the object based on the experimental trials is in agreement with the mass measured with the digital scale.
If the difference between the two values is large, then the average mass of the object based on the experimental trials is not in agreement with the mass measured with the digital scale.
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Two negative charges that are both -5.0 x 10^-5 C push each other apart with a force of 15 N. How
far apart are the two charges?
Contrary charges attract each other whereas like charges repel one another. Accordingly, two negative charges repel one another, but a positive charge pulls a negative charge toward it. Along the line between the two charges, attraction or repulsion occurs.
What are the interactions between two negative charges?Coulomb's law is a mathematical formula that describes the electric force that exists between charged things. It was developed by Charles-Augustin de Coulomb, a French physicist, and is comparable to Isaac Newton's law of gravity.Electric force and gravitational force both act along a line separating the two objects, and both forces diminish with the square of the distance between them. The electric charge of an object, as opposed to the mass of an object, determines the amount and sign of the electric force according to Coulomb's law. The effect of electromagnetic on the motion of charged objects is thus determined by charge. A basic characteristic of matter is charge. Each component of matter possesses an electric charge that can either be positive, negative, or zero.As an illustration, atomic nuclei have a positive charge while electrons have a negative charge. Due to the equal distribution of positive and negative charges in most bulk matter, it has zero net cha.Example :
15N = 9 * (10)9 NM²(-5.0 * (10) -5 C) (-5.0 * (10 )- 5 c) / c² (d)²
15N = 22.5 NM² / d²
d ² = 22.5 NM² / 15N
d² = 1.5m².
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does it always take the same amount of solid materials to saturate 50 millileters of water
No it does not take same amount of solid materials to saturate 50 milileter of water.
There are different amount of voids in different types of solids (for example: soil). When the volume of the voids with respect to the volume of the solid particles is called void ratio.
void ratio(N) = volume of voids(Vₙ)/volume of solids(Vₓ)
When the volume of void is completely filled with water and no air is present in the voids then this phenomena is know as saturation. But as we discussed earlier that different amount of solid contains different volume of voids, so it will take different amount of solids to be saturated by 50 ml of water.
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which is a possible unsafe consequence of using fin material that is too thin or weak for your rocket and the motor that you are using?
Using fin material that is too thin or weak for a rocket and its motor can result in fin failure, trajectory instability, motor damage, and loss of control.
Fin failure: Thin or weak fins may not be able to withstand the aerodynamic forces and stresses during launch, which can result in fin failure.
Trajectory instability: Weak or poorly designed fins can cause trajectory instability, making the rocket unpredictable and potentially dangerous.
Motor damage: In some cases, using weak or improperly designed fins can lead to excessive stress on the motor casing, causing damage and potentially leading to a motor failure.
Loss of control: If fins fail or the rocket becomes unstable, it may become uncontrollable and fall back to the ground, potentially causing damage or injury.
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why, when popped, does a fully inflated balloon make a louder noise than a partially inflated balloon? use energy considerations in your answer. type your answer
It happens due to the elasticity of balloon.Also, the pressure inside the balloon of air is higher than outside, which creates a difference between the surrounding air pressure and the pressure inside the balloon.
why, when popped, does a fully inflated balloon make a louder noise than a partially inflated balloon?
The fully inflated balloon has more elastic energy, therefore, more energy is converted to sound energy.When you pop a balloon, the air that was compressed (squeezed) inside of it rapidly expands, creating a shock wave through the air that sounds like a loud bang.A study, published in the Canadian Audiologist journal, found that when a balloon is tightly inflated to pop, the bursting balloon is louder than a shotgun going off next to someone's ear and nearly as intense as a 357 magnum pistol. Researchers found a balloon inflated to rupture peaks at 168 decibels (dB).The pressure inside the balloon is more than that of atmospheric pressure and it increases when we inflate a balloon. Balloon bursts when the pressure inside the balloon becomes higher than its wall capacity to hold.
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a moon orbits a planet with an elliptical orbit. at what point in the orbit is the kinetic energy of the moon the smallest?
In an elliptical orbit, the kinetic energy of an object is smallest at the point in the orbit where the object is at its farthest distance from the planet, also known as the apogee.
At this point, the object is moving the slowest and has the least kinetic energy. The gravitational potential energy of the object is at a maximum at this point, since the object is farthest from the planet and the gravitational pull is weakest. The total energy of the object remains constant as it moves along its elliptical orbit, but the distribution of energy between kinetic and potential energy changes as the object moves from perigee (the point of closest approach to the planet) to apogee and back.
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ancient astronomers knew about precession of the ____________, which means that as time passes, it points at a different ___________.ecliptic, planet north pole, planet north celestial pole, star celestial equator, star
"Ancient astronomers knew about precession of the celestial equator, which means that as time passes, it points at a different star." Correct option is D.
Right now, the north celestial pole is pointing just 1° from the star Polaris. Ancient astronomers also employed the celestial equator and the Earth's North Pole as points of reference for observing and measuring the stars.
The north celestial pole's direction progressively shifts over time as a result of the ecliptic's precession, which is a slow, ongoing change in the orientation of the Earth's axis of rotation. A combination of gravitational forces from the Sun, Moon, and other planets result in this phenomenon.
The two places in the sky where the axis of rotation of the Earth intersects the celestial sphere are known as the north and south celestial poles.
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a 2.00-cm-high object is placed 3.00 cm in front of a concave mirror. if the image is 5.00 cm high and virtual, what is the focal length of the mirror?
The focal length of the mirror is 10 cm
The focal length of an optical system is the inverse of the system's optical power; it measures how strongly the system converges or diverges light.
A system with a positive focus length converges light, whereas a system with a negative focal length diverges light.
The equation for a concave mirror is:
1/f = 1/p + 1/q,
where f is the focal length,
p is the object distance, and
q is the image distance.
In this case, p = 3.00 cm and q = -5.00 cm (negative because the image is virtual).
Thus,
1/f = 1/3 + 1/-5
f = -10 cm
The negative value of focal length indicates that the mirror is a concave mirror.
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a wave oscillates 5.0 times a second and has a speed of 5.0 m/s . what is the wavelength of this wave?
Answer:
Explanation:
v=wavelengths *frequency
5.0/5.0
But I think is wrong the question
Because if they ask you wavelength you need to have frequency and speed
a ferrous supperalloy (410) cable has 28 mm original diameter and 25 m original length. this cable is designed to pull an elevator up at a constant speed
To draw an elevator up at a consistent pace, a ferrous superalloy (410) cable with an original diameter of 28 mm and an original length of 25 m can be employed.
The mechanical strength of the cable will be determined by several elements, including the superalloy composition, the production process, and the operating circumstances (e.g. temperature, speed, and load). The maximum stress (tensile force per unit area) of the cable must be evaluated to guarantee that it can safely carry the weight of the elevator and any passengers. This may be computed using the following formula: Force / Area = Stress where Force is the tensile force applied to the cable and Area is the cable's cross-sectional area. The cable's cross-sectional area might be be calculated as follows: Area = π * (d/2)^2 where d is the cable's diameter. The maximum stress in the cable may be calculated by combining these formulae. If this stress exceeds the yield strength of the superalloy, the cable may deform or break, hence the cable's design and operation circumstances must be carefully considered to guarantee that it can safely hold the elevator and any passengers.
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a) describe the motion of the object modeled in the graph
b) describe the object's average velocity
c) write the mathematical model which describes the object's motion
d) determine the object's position at t=6.0s
a. Its a motion with constant movement. A liniear graph between time and distance shown the distance changes constantly over time.
b. The average velocity can be calculate by Δx / Δt = (35-5) / 4 = 7.5 m/s
c. [tex]\frac{y-y_{1} }{y_{2}-y_{1} } = \frac{x-x_{1} }{x_{2}-x_{1} }[/tex] = [tex]\frac{y-20}{35-20} = \frac{x-2}{4-2}[/tex] = [tex]2y-40=15x-30[/tex] = [tex]15x-2y=-10[/tex]
d. By using equation above, the objects position at t=6s, is
[tex]15x6-2y=-10[/tex]
[tex]y=50m[/tex]
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