Titanium phosphide (TiP) is a kind of chemical compound made of titanium and phosphorus. It is a metal compound that has a very high melting point, so it is often found in the form of a gray powder.
Titanium(III) phosphide is metallic. When it comes in contact with water or stomach acid, it breaks down into phosphine gas. Phosphine is a colorless, flammable, and explosive gas.
Titanium phosphide is a type of phosphide that contains more metal atoms than other types of phosphides. This makes it more resistant to breaking down into its parts, which makes it a good choice for things like jewelry.
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order the following choices to trace the synthesis and post-translational processing of a protein.
1. The nucleus contains the gene that codes for the protein. This gene is translated into mRNA, which leaves the nucleus through pores.
2. On ribosomes found on the surface of the rough endoplasmic reticulum, the protein is built as the mRNA is translated.
3. The rough endoplasmic reticulum is able to modify proteins and store them for short periods of time.
4. From the endoplasmic reticulum to the Golgi apparatus, the protein is transported by transitional vesicles.
What is protein?
A macronutrient called protein is necessary for gaining muscle growth. Although it can also be found in other sources like nuts and legumes, it is more frequently found in animal products. Amino acids, which are organic molecules formed of carbon, hydrogen, nitrogen, oxygen, or sulfur, are the chemical building blocks of protein.
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how do i read the lignes in between numbers on a beaker
The curve is called a meniscus
If the line is in the middle of two lines you add a .5 decimal
Explanation:
what is the significance of finding archean ""redbeds"" or banded iron formations (bifs) during the evolution of the atmosphere?
This significant change in the Earth's atmosphere is marked by the emergence of redbeds, sediments that contain oxidised iron.
The release of oxygen into the atmosphere led to the formation of minerals on land (continental redbeds). Since the created oxygen was absorbed by rocks for a very long time, as seen in Banded Iron Formations (BIFs) and continental red beds, it did not accumulate in the atmosphere for very long. The majority of the oxygen created over time is still preserved in the historic "banded rock" and "red bed" formations. The growth of oxygen may have been significantly influenced by the oxidation of the mantle rocks. It has been suggested that the shift from subaerial to mostly submerged volcanoes may also have resulted in a decline in volcanic emission of decreased gases.
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a new benzene/toluene solution is prepared, but with different proportions, this time, the mole fraction for benzene is 0.9. what are the mole fractions for each substance in the vapor phase
The mole fraction of each substance in the vapor phase depends on its vapor benzene pressure. The vapor pressure of a substance in a mixture is proportional to its mole fraction in the liquid phase, and the total pressure in the system is the sum of the vapor pressures of the individual components. Therefore, the mole fraction of each substance in the vapor phase can be calculated using the following equation:
X_i = P_i / (P_benzene + P_toluene)where X_i is the mole fraction of substance i in the vapor phase, P_i is its vapor pressure, and P_benzene and P_toluene are the vapor pressures of benzene and toluene, respectively. To determine the values of P_benzene and P_toluene, the Antoine equation or other vapor pressure models can be used.
Note that this calculation assumes that the vapor phase is in equilibrium with the liquid phase, which may not always be the case depending on the conditions of the system.
About BenzeneBenzene, also known by the chemical formulas C6H6, PhH, and benzol, is an organic chemical compound that is a colorless, flammable liquid with a sweet odour. Benzene consists of 6 carbon atoms forming a ring, with 1 hydrogen atom bonded to every 1 carbon atom. Benzene is a type of cyclic aromatic hydrocarbon with a fixed pi bond. Benzene is a component of petroleum, and is one of the most basic petrochemicals and an important solvent in the world's industry. Because it has a high octane number, benzene is also an important ingredient in gasoline. Benzene is also a basic ingredient in the production of pharmaceuticals, plastics, gasoline, artificial rubber, and dyes. In addition, benzene is a natural ingredient in petroleum, but is usually obtained from other compounds found in petroleum. Because it is carcinogenic, its use other than non-industrial fields is very limited.
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When calcium compounds are introduced into a gas flame, a red colour is seen; sodium compounds give a yellow flame. Outline the source of the colours and why they're different
promoted electrons fall back into their lower energy level
energy between the levels are different
The color of a flame in a fire test is determined by the element being burned, with calcium producing a red flame and sodium producing a yellow flame. The color is caused by the emission of light from excited atoms in the flame.
When a substance burns in a flame, it reacts with the oxygen in the air to produce heat and light. The light produced is called emission light and is made up of different wavelengths, or colors. Each element has a unique set of emission lines, or specific colors that it produces when it is burned.
In the case of calcium, the red color is produced by excited calcium atoms emitting light at a specific wavelength, which our eyes perceive as red. Similarly, when sodium is burned in a flame, it produces a yellow color because the excited sodium atoms emit light at a different, specific wavelength that we perceive as yellow.
The difference in the color of the flame is due to differences in the energy levels of the electrons in the excited atoms of each element. Calcium has a higher energy level than sodium, so it produces a more intense red light, while sodium has a lower energy level and produces a less intense yellow light.
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what will produce if soap reaction with fecl3
Soap reacts with FeCl3 to produce iron soap and a salt.
Soap is made up of long chain molecules of fatty acids that have a polar, or charged, end and a non-polar, or non-charged, end. When soap is added to a solution of iron(III) chloride (FeCl3), the polar ends of the soap molecules are attracted to the charged iron ions in the solution, while the non-polar ends are repelled. This creates a complex between the soap and the iron ions, called iron soap.
The salt that is produced in the reaction is chloride ions that have been separated from the iron ions in the FeCl3. Chloride ions are negatively charged, so they will not form a complex with the soap. Instead, they will remain in solution as separate ions.
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The unit cell of an oxide of uranium consists of cubic closest-packed uranium ions with oxide ions in all the tetrahedral holes. What is the formula of the oxide?
The formula of the oxide is UO_2 since the ratio of uranium to oxygen is 8:4, which equals 2:1. This can be written as U:O = 2:1 or UO_2.
The formula of the oxide can be calculated as follows: The unit cell of the oxide consists of 8 uranium ions with a total atomic weight of 238, and 4 oxide ions with a total atomic weight of 32. The formula of the oxide is UO_2 since the ratio of uranium to oxygen is 8:4, which equals 2:1. This can be written as U:O = 2:1 or UO_2.
The cubic closest-packed structure of the uranium ions with oxide ions in the tetrahedral holes is known as the NaCl structure, or the face-centered cubic structure. This means that the uranium ions are located at the corners and faces of the cube, while the oxide ions are located in the center of the tetrahedral holes. This structure is important for the formation of the uranium oxide, as the ions must be arranged in a specific way in order to form a stable compound.
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If the [A-]/[HA] ratio of a buffer solution changes from 0.2 to 5 upon addition of a strong base solution, by how many units does the pH change?
0.9
1.2
1.4
1.1
Option C is correct. The right response is 1.4. The Henderson-Hasselbalch equation is written as pH=pKa +log([A][HA])
A weak base will react with the H+ from a strong acid to create the weak acid HA when a strong acid is put to a buffer: H+ + A- HA. The pH only minimally changes because the H+ is absorbed by the A- rather than forming H3O+ (H+) by interacting with water. pH is calculated as follows: pH = pKa + log [Salt] / [Acid]. Any acidic buffer solution will always have a pH below 7, while any basic buffer solution will always have a pH above 7. Option C is correct.
The right response is 1.4.
The Henderson-Hasselbalch equation is written as pH=pKa+log([A][HA])
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100.0 ml of 0.500 m cabr2 and 50.0 ml of 1.00 m nabr are mixed. what is the concentration of bromide ion in the resulting solution?
Answer:
To find the concentration of bromide ion in the resulting solution, we need to calculate the total moles of bromide ion in the final solution and divide by the total volume of the solution.
First, we can find the number of moles of bromide ion in the initial solution of cabr2 by multiplying the volume of the solution (100.0 mL) by the concentration (0.500 M):
moles = (100.0 mL) * (0.500 M) = 50.0 moles
And also in Nabr by multiplying the volume of the solution (50.0 mL) by the concentration (1.00 M)
moles = (50.0 mL) * (1.00 M) = 50.0 moles
Next, we add the total moles of bromide ion of the two solutions, which would be 50.0 moles + 50.0 moles = 100.0 moles
The final volume of the solution is 150.0 ml
Then, we divide the total number of moles by the total volume of the solution to find the concentration:
concentration = moles / volume = 100.0 moles / 150.0 mL = 0.667 M
So the concentration of bromide ion in the resulting solution is 0.667 M (in units of Molarity)
After weighing a powder on a weigh boat and transferring it to a beaker, it is important to
a) Rinse any residue from the weigh boat into the beaker.
b) Allow the powder several minutes to rest before use.
c) Remove any clumps in the powder by stirring with a glass rod.
d) Heat the contents of the beaker to evaporate any water absorbed.
After weighing a powder on a weigh boat and transferring it to a beaker, it is important to, the correct option is, (c) Remove any clumps in the powder by stirring with a glass rod.
In order to ensure accurate measurement of the powder, it is important to remove any clumps that may have formed during transfer from the weigh boat to the beaker. Stirring the powder with a glass rod helps to break up any clumps, leading to a more uniform and representative sample. This step is especially important when the powder is being used in an experiment or reaction, as clumps can affect the accuracy and reproducibility of the results. Heating the contents of the beaker can also lead to degradation or loss of the powder, so it is generally not recommended.
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Draw a structure for (E)-2-hydroxy-4-hexen-3-one. Show stereochemistry only if given in the name. You do not have to explicitly draw H atoms. If a group is achiral, do not use wedged or based bonds on it.
The structure for (E)-2-hydroxy-4-hexen-3-one is given below. Stereochemistry is is a trans-configurated molecule with the hydroxyl group (OH) located on the stereogenic center.
This means that the higher priority groups, as determined by the Cahn-Ingold-Prelog system, are on opposite sides of the double bond. The "-" signs in the structure indicate the location of the double bond. the higher priority groups (double bond and carbonyl group) in the trans orientation. This molecule has a chiral center and can exist as two stereoisomers, but it is specifically the (e) isomer. Stereoisomers are molecules with the same chemical formula and atomic arrangement but with a different spatial arrangement of their atoms. Enantiomers and diastereomers are the two primary categories of stereoisomers. Stereoisomers known as enantiomers are mirror images of one another and cannot be overlaid.
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approximately how many joules of heat required to raise the temperature of 20 g of water from thirty degrees celsius to 40 degrees celsius
To raise the temperature of 20 grams of water from 30 degrees Celsius to 40 degrees Celsius requires approximately 8.4 joules of heat.
This can be calculated using the equation Q = mcΔT, where m is the mass of the water (20 grams), c is the specific heat capacity of water (4.184 J/g°C), and ΔT is the change in temperature (10°C). Therefore, the required heat is 8.4 J.
The equation can be used to calculate the amount of energy required to raise the temperature of a given mass of a substance from one temperature to another. For example, if we wanted to calculate the amount of energy required to raise the temperature of 20 grams of water from 30 degrees Celsius to 40 degrees Celsius, we would use the following equation: Q = (20 grams)(4.184 J/g°C)(10°C) = 8.4 J.
This means that 8.4 joules of energy are required to raise the temperature of 20 grams of water from 30°C to 40°C.
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When a drop of ink is added to a beaker of water, the ink molecules become randomly dispersed throughout the water. This is an example of an increase in...?
A. Complexity
B. Matter
C. usable energy
D. potential energy
E. entropy
When a drop of ink is added to a beaker of water, the ink molecules become randomly dispersed throughout the water. This is an example of an increase in entropy by diffusion process.
Ink flows around the water and gradually mixes with it due to the motion of the ink molecules in the water. Overall, a diffusion process occurs between the water and ink particle populations.
Entropy is the measurement of the amount of thermal energy per unit of temperature in a system that cannot be used for productive work. Entropy is a measure of a system's molecular disorder or unpredictability since work is produced by organized molecular motion.
The overall entropy of a system may only ever increase or stay constant during spontaneous processes, according to the second law of thermodynamics.
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Select all intermolecular forces that contribute to creating a solution of CO₂, in C₆H₆ a. lon-dipole b. London Dispersion c. H-bonding d. Dipole-dipole
a. Dispersion in London b. Dipole-dipole interaction The intermolecular interactions that contribute to the formation of a CO2 solution in C6H6 are as follows: Because CO2 is a non-polar molecule.
this is the sole intermolecular force that exists between CO2 and C6H6. Dipole-dipole interactions: Because CO2 is a polar molecule, it might interact with C6H6 via dipole-dipole interactions if C6H6 was similarly polar. However, because C6H6 is a non-polar molecule, dipole-dipole interactions do not contribute to the formation of a CO2 solution in C6H6 H-bonding: An H-bonding interaction is a sort of dipole-dipole interaction in which a hydrogen atom is connected to a strongly electronegative atom (such as N, O, or F). Because CO2 has no hydrogen atoms, there is no H-bonding between CO2.
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A 4 x 8 ft solar collector has water circulating through it at a rate of 1.0 gal per minute (gpm) while exposed to sunlight with an intensity of 300 BTU/ft2.hr. Fifty percent of that sunlight is captured by the collector and heats the water flowing through it. What would be the temperature rise of the water as it leaves the collector?I have no idea how to do this problem. Could someone please walk me through it? Thanks!
The temperature rise of the water as it leaves the collector is 5.32 °C
The solar collector area=[tex]4\times8=32[/tex]feet
According to the inverse square law of light intensity, the amount of light that an object emits and reflects toward an observer when they are both stationary is inversely proportional to the square of their distance from the object. Imagine being in a station when a train is approaching. The inverse square law is supported by the train's light, which becomes brighter as it draws nearer. The light increases brighter by a factor of one over the square of the distance between the train and the viewer, if the varying light intensity from the train were measured.
Intensity of exposure of sunlight=300[tex]\frac{BTU}{ft^{2}hr }[/tex]
The heat which is getting absorbed by heater per minute= [tex]\frac{exposure\times area}{60}[/tex]
The heat which is getting absorbed by heater per minute=[tex]\frac{300\times32}{60}[/tex]
=160[tex]\frac{BTU}{min}[/tex]
Now, heat get transfer to water,
Q=50% of 160
Q=80[tex]\frac{BTU}{min}[/tex]
The volume that is heated of water = 1[tex]\frac{gallon}{min}[/tex]
Volume=3.79 [tex]\frac{L}{min}[/tex]
Now, to find the mass of water
Heated=volume ×density=3.79×1=3.79[tex]\frac{kg}{min}[/tex]
Heat=8.36[tex]\frac{lb}{min}[/tex]
Heat capacity of water, C= 1[tex]\frac{BTU}{lb}F[/tex]
Let temperature rise be [tex]\triangle A[/tex]
[tex]mc\triangle T=Q[/tex]
[tex]8.36\times1\times \triangle T=80[/tex]
[tex]\triangle T=[/tex]9.57°F
[tex]\triangle T=[/tex]5.32 °C
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What mass of ascorbic in grams is actually used if 4.061 g is weighed out and the assay is 95.7%(w/w)?
The mass of ascorbic in grams is actually when used if the 4.061 g is weighed out and the 95.7 % (w/w) is 3.88 g.
The total mass weighed out = 4.061 g
The w/w % = 95.7 %
The expression for the w/w % is as follows :
w/w % = (mass of ascorbic / total weighed ) × 100 %
95.7 % = (mass of ascorbic / total weighed ) × 100 %
0.957 = mass of ascorbic / 4.061 g
Mass of the ascorbic = 0.957 × 4.061 g
Mass of the ascorbic = 3.88 g
Thus, the mass of ascorbic is 3.88 g.
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11.1) Describe the differences between expendable and permanent molds.
Expendable molds must be formed of expanding mold materials since the mold must flex throughout the cooling process. Molds that are permanent are fixed and do not permit any kind of distortion.
Expendable mold: what is it?For low volume or one-off production, the method of disposable mold casting uses reusable molds to create metal components. Friction, slush, poor, and vacuum casting processes are the four basic categories.
What is the procedure for permanent mold?Using an one reusable mold, permanent mold casting produces a huge number of castings. Simply pour molten into a mold, where it heats up and hardens, is the casting process. The casting is then taken out of the mold, which is then opened and utilized again.
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Is it ever ok to use a micropipette to dispense more liquid than its maximum calibrated volume? Why or why not? Select all that apply.
Is it not ok to use the micropipette to dispense the more liquid than its maximum calibrated volume. The correct option is 2) Not ok to use .
If we use a micropipette to dispense the more liquid than its maximum calibrated volume then it can damage the instrument. So, never use the volume 200 µl - 1000 µl pipette to dispense the volumes below the 200 µl. The micropipette is the essential instrument in the laboratory. That is used to accurately and the precisely transfer the volumes of the liquid in the microliter range.
Thus, it harmful to use the micropipette to dispense the more liquid than its maximum calibrated volume.
This question is incomplete, the complete question is :
Is it ever ok to use a micropipette to dispense more liquid than its maximum calibrated volume? Why or why not? Select all that apply.
1) Ok to use
2) Not ok to use
3) More information required to answer this.
4) Depends on you
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a sample containing of metal pellets is poured into a graduated cylinder initially containing of water, causing the water level in the cylinder to rise to . calculate the density of the metal.
The density of the metal is 1 g/ml.
To calculate the density of the metal, we need to determine the mass and volume of the metal. If the water level in the graduated cylinder rose to 60 ml after adding the metal pellets.
We can assume that the volume of the metal is equal to the volume of water displaced, which is 60 ml. We can then use the equation of density, which is:
density = mass/volume
Since the volume is known (60 ml), to find the mass we can use the conversion factor: 1 ml of water has a mass of 1 g.
So, the mass of the metal is 60 g.
Now we can substitute the mass and volume into the equation for density:
density = 60 g / 60 ml = 1 g/ml
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consider the phase diagram shown here. a sample of the substance in the phase diagram is initially at 120 oc and 925 mmhg. what phase transition occurs first when a substance increases temperature at constant pressure?
The phase transition which occurs when a substance increases temperature at constant pressure is solid to liquid. The correct option is A.
It can be seen in the attached diagram that when the substance is at 120 degrees C and 925 mmHg, it is in the solid phase. Then, if we increase the temperature while keeping the pressure as constant, it will change to the liquid phase.
How do we know on a phase diagram in what phase a substance is?The lines represent the combinations of pressures and temperatures where two phases can exist in equilibrium. In another words, these lines show phase change points. The line divides the solid and gas phases, defines sublimation (solid to gas) and deposition (gas to solid).
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Although part of your question is missing, you might be referring to this full question: Consider the phase diagram shown here. A sample of the substance in the phase diagram is initially at 120 degrees C and 925 mmHg. What phase transition occurs when a substance increases temperature at constant pressure?
a) solid to liquid
b) liquid to gas
c) solid to gas
d) liquid to solid
calculate the expected ph of buffer plus added hcl. show your work for full credit. how much did the value decrease when acid was added
The expected pH of a buffer solution can be calculated using the Henderson-Hasselbalch equation is the initial pH of the buffer is 5.57.
The Henderson-Hasselbalch equation can be used to calculate the predicted pH of a buffer solution: [tex]pH=pKa+log(\frac{A-}{HA})[/tex].
Where pKa is the buffer system's acid dissociation constant, [A-] is the concentration of the base (A-), and [HA] is the concentration of the acid (HA).
Because 5 mL of NaOH reacts with 5 mL of acetic acid.
Acetic acid millimole remaining = 7.5 – 5 = 2.5 Millimole
Sodium acetate millimole = 12 + 5 = 17 millimoles.
[tex]P^H[/tex]=4.74+log [17 millimoles / 30 mL] / [2.5 millimole / 30 mL]
= 4.74 + 0.83
= 5.57
Hence, the buffer system's value decreases when acid was added is 5.57.
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The distance between the centers of two oxygen momecule is 1.21x10-8 cm . what is this distance in nm?needs to be worked out into the boxes
The distance between the centers of the two oxygen molecules is 1.21 x 10⁻⁸ cm is the 1.21 × 10⁻¹nm.
The distance between the centers of two oxygen molecule is as :
= 1.21 x 10⁻⁸ cm
The nm = nanometer
The 1 cm is equals to 10000000 nanometers, the nanometer is used to measure the length in the metric system. The nanometer is the unit that is equals to the one billionth of the meter.
The distance in nanometer is as follows :
The distance , 1.21 x 10⁻⁸ cm = 1.21 x 10⁻⁸ × 10⁷
The distance , 1.21 x 10⁻⁸ cm = 1.21 × 10⁻¹nm.
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A 0.15 M solution of NaOH is used to titrate 200.0 mL of 0.15 M HCN. What is the pH at the equivalence point? (Ka = 4.9 x 10-10; Kb = 2.0 x 10-5)
A 0.15 M solution of the NaOH is used to titrate the 200.0 mL of 0.15 M HCN. The pH at the equivalence point is 9.3.
The molarity of HCN = 0.15 M
The Ka value = 4.9 × 10⁻¹⁰
The pH expression is given as :
pH = pka + log [base] / [acid]
where .
The pka = - log (ka)
pka = - log(4.9 × 10⁻¹⁰)
[base] = 0.15 M
[acid] = 0.15 M
pka = 9.3
pH = 9.3 + log [0.15] / [0.15]
pH = 9.3
Thus, the pH at the equivalence point of the solution is 9.3.
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why does labour create value according to locke?
According to Locke, productive labor is a moral activity because it produces the products needed to maintain human life. As such, it is required that productive labor be a value-creating activity.
Locke claimed that private property rights are inalienable human rights. According to the reasoning, one is entitled to the rewards of their job because they worked hard to earn them. The worker must also have a natural property interest in the material itself because instant production required exclusive ownership. Marx used this theory of value, which holds that the amount of labor in a product determines its worth and that labor has the sole legal claim to production.
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Which Inorganic Substance has a melting point of -101°C and a boiling point of -35°C?
Hydrogen
Chlorine
Hydrogen Sulfide
Hydrogen Chloride
Hydrogen Chloride (HCl) is the inorganic substance that has a melting point of -101°C and a boiling point of -35°C.
Hydrogen Chloride is a colorless and pungent-smelling gas that is highly soluble in water and forms a strong acid when dissolved in water. It is commonly used in a variety of industrial applications, including the production of fertilizers, dyes, and plastics. Its melting and boiling points are relatively low, which allows it to exist as a gas at room temperature, making it easier to handle and transport. However, its corrosiveness and reactivity with many materials means that it must be handled with care and proper safety precautions must be taken when using it.
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circle a represents a unit volume of 100. ml of a solution. which circle (b, c, or d) best represents the unit volume after 300. ml of solvent has been added?
Circle b represents the solution after 300 mL of solvent has been added.
Volume percent = {Volume of solute / volume of solution} x 100
After adding the solution, the volume of solution increases but volume of solute remains the same. For same volume of solute, the volume percent is high for once which has the volume of solution is low.
In 100 mL the visually represented solution has 12 balls for solute. When 300 mL of solution is added to the solute, the total volume is 400 mL volume is increased 4 times. Then 12/4 = 3 is the number of solute present in the circle. Circle b represents the solution.
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ignore this lol
......................................
Answer:
5 points are mine
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which of the following foods contains the lowest amount of sodium? a. one cup of canned vegetable soup b. a medium fresh orange c. a 4-ounce glass of tomato juice d. a hot dog
Medium fresh orange because in a medium fresh orange only contains 0-3 mg sodium (Alternative B).
SodiumSodium is a type of mineral that you can easily find in various foods, especially salt. Salt itself is known as sodium chloride and is the most abundant source of sodium, up to 40% with the remainder consisting of chloride.
People use salt as a flavor enhancer so that food is not bland. Salt also functions as a binder for food components as well as a stabilizer and food preservative.
a. one cup of canned vegetable soup. On average, canned soup has 700 mg of sodium.
b.a medium fresh orange. sodium in a medium fresh orange only contains 0-3 mg of sodium.
c. 4-ounces of 100 percent tomato juice contain about 1200 mg of sodium.
d. hotdogs. a hotdog contains about 1250 mg of sodium.
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Calculate the molarity of 0.75 L of a solution containing 0.93 g of dissolved KCl. Use the calculations of 0.93 g of KCl / molar mass of KCl (from Periodic Table) = moles of KCl. Moles of KCl/0.75 L = molarity of solution
Explanation:
To calculate the molarity of a solution, we need to know the number of moles of solute (in this case, KCl) and the volume of the solution in liters.
First, we need to calculate the number of moles of KCl. We can do this by using the formula: moles of KCl = (mass of KCl in grams) / (molar mass of KCl in grams/mole)
The molar mass of KCl is 74.5513 g/mol, so we can use this to calculate the number of moles of KCl in the solution:
moles of KCl = (0.93 g) / (74.5513 g/mol) = 0.01239 moles
Next, we can use this number of moles to calculate the molarity of the solution. Molarity is defined as moles of solute per liter of solution, so we can use the following formula to calculate the molarity of the solution:
molarity of solution = (moles of KCl) / (volume of solution in liters)
In this case, the volume of the solution is 0.75 L, so we can substitute these values into the formula:
molarity of solution = (0.01239 moles) / (0.75 L) = 0.0165 moles/L or approximately 0.0165 M
Experiment A2b: Bromination of (E)-StilbeneThe product of this reaction contains two stereocenters. Due to the stereospecificity of the bromination and the symmetry of the product, however, only the meso-diastereomer of stilbene dibromide is produced.a) How many possible stereoisomers exist for stilbene dibromide?b) You formed one of the possible stereoisomers as the product of the bromination reaction (see the Reaction Scheme and Question 1). Draw all of the other possible stereoisomers, and label each stereocenter (R or S).c) How are the stereoisomers that you drew in part (b) related to each other?d) How are the stereoisomers that you drew in part (b) related to the product of the reaction shown in the Reaction Scheme?
(a) The chiral carbons in stilbene dibromide total to two. Two additional stereoisomers are enantiomers (b). Both are enantiomers of one another (c) (mirror images) (d) These are diastereomers because they are stereoisomers of one another but not mirror images of one another.
Trans-stilbene is primarily converted to meso-1,2-dibromo-1,2-diphenylethane (also known as meso-stilbene dibromide) by bromination, in accordance with a mechanism involving a cyclic bromonium ion intermediate of a typical electrophilic bromine addition reaction; cis-stilbene results in a racemic mixture of the two enantiomers. An established procedure used as an illustration of an electrophilic addition reaction of alkenes is the reaction of bromine with (E)-stilbene. A double bond anti addition makes the reaction stereospecific. A bromine solution in methylene chloride, which has a relatively high toxicity, is used in the conventional reaction.
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