Answer:
Explanation:
1
Locate the parentheses after the chemical formula, whether or not it is within the context of an equation.
2
Identify the parentheses as (s) for solid, (l) for liquid, (g) for gas, or (aq) for aqueous solution. An aqueous solution is a substance dissolved in water.
3
If no parentheses follow the chemical formula, look for key words or phrases. These are especially helpful in the context of chemical reactions. For example, a precipitate is a solid, a combustion reaction produces water and carbon dioxide in their gaseous forms, and in solubility experiments, ions are in aqueous solution.
Urea [(NH2)2CO] is a by-product of protein metabolism, and it can be synthesized in a lab by combining ammonia and carbon dioxide according to the following equation 2NH3(g) + CO2(g) (NH2)2CO(aq) + H2O(l) determine the moles of carbon dioxide required to reaction with 2.50 moles of ammonia.
1.25 moles of [tex]CO_{2}[/tex] are required to react with 2.50 moles of [tex]NH_{3}[/tex].
What are the moles?
Moles are a unit of measurement used in chemistry to express the amount of a substance. One mole of a substance is equal to its molecular weight expressed in grams. In other words, one mole of a substance contains 6.022 x [tex]10^{23}[/tex] individual particles (atoms, molecules, or ions). The number of moles of a substance can be calculated by dividing its mass in grams by its molecular weight or by using the ideal gas law PV=nRT, where n is the number of moles.
The balanced chemical equation is:
[tex]2NH_{3}[/tex](g) + [tex]CO_{2}[/tex](g) → [tex](NH_{2})_{2}CO[/tex](aq) + [tex]H_{2}O[/tex](l)
From the balanced equation, we can see that 1 mole of [tex]CO_{2}[/tex] reacts with 2 moles of [tex]NH_{3}[/tex].
Therefore, to determine the moles of [tex]CO_{2}[/tex] required to react with 2.50 moles of [tex]NH_{3}[/tex], we need to use the mole ratio from the balanced equation:
2 [tex]NH_{3}[/tex] : 1 [tex]CO_{2}[/tex]
2.50 moles [tex]NH_{3}[/tex] * (1 mole [tex]CO_{2}[/tex] / 2 moles [tex]NH_{3}[/tex]) = 1.25 moles [tex]CO_{2}[/tex]
Therefore, 1.25 moles of [tex]CO_{2}[/tex] are required to react with 2.50 moles of [tex]NH_{3}[/tex].
What is molecular weight ?
Molecular weight, also known as molar mass, is the mass of one mole of a substance. It is expressed in units of grams per mole (g/mol). The molecular weight of a compound is determined by adding up the atomic weights of all the atoms in the molecule.
What is substance?
In chemistry, a substance is a form of matter that has constant chemical composition and characteristic properties. It may be an element or a compound made up of two or more elements chemically combined in a fixed proportion. Examples of substances include pure water, carbon dioxide gas, and sodium chloride (table salt).
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A calorimeter was chemically calibrated using the following method.
0.9638 g of solid CaCl2 was dissolved in 100 mL of water.
The dissolution process is described as:
CaCl2(s) →Ca2+(aq)+2Cl−(aq), ΔH = -83 kJ mol-1.
The temperature of the water rose from 21.0 to 22.6 oC.
The calorimeter was then emptied and cleaned and 100 mL of water was placed into the calorimeter again. When 0.0978 mol of concentrated sulfuric acid, H2SO4, was then mixed in the water, the temperature change was 5.0 oC
The calibration factor of the calorimeter to 3 significant figures is J oC-1.
The molar heat of solution of sulfuric acid is kJ mol-1
(write your answer to 1 decimal place)
The molar heat of the solution of sulfuric acid is 21.4 kJ/mol, rounded to 1 decimal place.
let's calculate the heat absorbed by the water when dissolving CaCl2:
n = m/M = 0.9638 g / 110.98 g/mol = 0.00868 mol (moles of CaCl2 dissolved)
q1 = nΔH = (0.00868 mol)(-83 kJ/mol) = -0.722 kJ (heat absorbed by water)
Next, let's calculate the heat released by the sulfuric acid:
n = 0.0978 mol (moles of H2SO4 added)
ΔT = 5.0 oC (temperature change of water)
m = 100 g (mass of water)
q2 = -mcΔT = -(100 g)(4.184 J/g oC)(5.0 oC) = -2092 J = -2.092 kJ (heat released by sulfuric acid)
Now, we can set these two values equal to each other and solve for the calibration factor:
q1 = q2
-0.722 kJ = -2.092 kJ
q = 1.370 kJ (total heat exchanged)
c = q/ΔT = (1.370 kJ)/(1.6 oC) = 0.856 kJ/oC (calibration factor)
Finally, we can calculate the molar heat of the solution of sulfuric acid:
ΔH = -q/n = -(-2.092 kJ)/0.0978 mol = 21.4 kJ/mol (molar heat of solution of sulfuric acid)
Therefore, the molar heat of the solution of sulfuric acid is 21.4 kJ/mol, rounded to 1 decimal place.
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HELPPPP FASTTTTTTT
An inflated balloon is left outside overnight. It has a volume of 1.7 4 L when the temperature is 20.2 degC and the pressure is 1.02 atm. At what temperature will the balloon have a volume of 1.56 L if the pressure falls to 0.980 atm?
What gas law will you use to solve this problem?
options
A. boyles gas law
B. charles gas law
C. Gay lussacs gas law
D. combined gas law
E. ideal gas law
What is your reason for choosing the gas law?
options
A.moles are in the problem
B. there are 2 variables that are changing
C. there are 3 variables that are changing
In this problem, is the volume increasing or decreasing?
What is the unknown that you are solving for?
options.
A.T1
B.T2
What temperature will you use in your calculations?
A. 20.2 degc
B. 273 k
C. 293.2 K
What is the final temperature after the volume and pressure decrease in this problem?
options.
A. 253k
B. 314k
C. 353 K
Explanation:
1.The gas law that we will use to solve this problem is the combined gas law.
2.We will choose the combined gas law because there are three variables that are changing in this problem: volume, pressure, and temperature.
3The volume is decreasing in this problem, from 1.74 L to 1.56 L.
The unknown that we are solving for is T2, the temperature at which the balloon will have a volume of 1.56 L.
4We will use the temperature in Kelvin for our calculations. To convert from Celsius to Kelvin, we add 273.15 to the Celsius temperature. Therefore, the temperature we will use in our calculations is 293.35 K (20.2°C + 273.15).
5To find the final temperature, we can use the combined gas law equation:
(P1 x V1)/T1 = (P2 x V2)/T2
where P1 = 1.02 atm, V1 = 1.74 L, T1 = 293.35 K, P2 = 0.980 atm, and V2 = 1.56 L.
Substituting the values into the equation and solving for T2, we get:
T2 = (P2 x V2 x T1)/(P1 x V1)
= (0.980 atm x 1.56 L x 293.35 K)/(1.02 atm x 1.74 L)
= 268.06 K
Therefore, the final temperature after the volume and pressure decrease is 268.06 K, which is approximately 253 K (option A).
The pH of an aqueous solution is measured as
1.79. Calculate the [H3O
+].
Answer in units of M.
The solution's [H3O+] is 1.27 x 10^(-2) M.
What is pH?The acidity or basicity of an aqueous solution is determined by its pH value. In terms of the concentration of H3O+ ions in the solution, it is the negative logarithm (base 10) of the hydronium ion concentration. The pH scale runs from 0 to 14, with a pH of 7 being regarded as neutral, anything below that as acidic, and anything above that as basic (or alkaline).
How do you determine it?The negative logarithm of the hydronium ion concentration, or [H3O+], is used to calculate the pH of a solution. pH and [H3O+] are mathematically related in the following way:
pH = -log[H3O+].
This equation can be rearranged to give
[H3O+] = 10^ (-pH)
Using the pH value of 1.79 as a replacement, we obtain [H3O+] = 10^ (-1.79)
[H3O+] = 1.27 x 10^(-2) M
As a result, the solution's [H3O+] is 1.27 x 10^ (-2) M.
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The structure illustrated here is
DONE
The structure illustrated here is butanone
What is butanone used for?Butanone, also known as methyl ethyl ketone (MEK), is a solvent that is commonly used in industrial applications such as in the manufacture of plastics, textiles, and paints. It is also used as a solvent in the production of adhesives, and as a cleaning agent for electronic components.
Butanone's importance lies in its versatile properties as a solvent, which make it essential in the production of many consumer goods and industrial products. Its high solvency power and fast evaporation rate make it particularly useful in applications where rapid drying and bonding are required.
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Answer:
The first one is Butanone and the second one is Propenal
Explanation:
Just did it on Edge2023!
he two main processes that occur in the final formation of sedimentary rocks are
Answer: Compaction and Cementation.
Explanation. Compaction occurs when the weight of overlying sediment compresses the sediment grains and reduces the amount of pore space between them, resulting in a more tightly packed sedimentary rock. Cementation occurs when mineral-rich groundwater moves through the pore spaces of the sediment, depositing minerals that bind the sediment grains together and form a solid rock.
How much heat is needed to convert 2.0kg of ice at -15°C to steam at 100°C?
Approximately 6,082,900 J of heat is needed to convert 2.0 kg of ice at -15°C to steam at 100°C.
What is Heat Energy?
Heat energy is a form of energy that is transferred from one object to another as a result of a temperature difference between the two objects. It is the energy that flows from a warmer object to a cooler object until they reach thermal equilibrium, meaning they have the same temperature. Heat energy can be transferred through three mechanisms: conduction, convection, and radiation.
The specific heat capacity of ice is 2090 J/(kg·°C), the latent heat of fusion of ice is 334 kJ/kg, the specific heat capacity of water is 4186 J/(kg·°C), and the latent heat of vaporization of water is 2257 kJ/kg.
Using these values, we can calculate the heat needed for each step as follows:
Heat needed to raise the temperature of ice from -15°C to 0°C:
Q1 = mcΔT = 2.0 kg × 2090 J/(kg·°C) × (0°C - (-15°C)) = 62,700 J
Heat needed to melt the ice:
Q2 = mL = 2.0 kg × 334 kJ/kg = 668,000 J
Heat needed to raise the temperature of water from 0°C to 100°C:
Q3 = mcΔT = 2.0 kg × 4186 J/(kg·°C) × (100°C - 0°C) = 837,200 J
Heat needed to vaporize the water:
Q4 = mL = 2.0 kg × 2257 kJ/kg = 4,514,000 J
The total heat needed to convert 2.0 kg of ice at -15°C to steam at 100°C is the sum of the heat needed for each step:
Total heat = Q1 + Q2 + Q3 + Q4
= 62,700 J + 668,000 J + 837,200 J + 4,514,000 J
= 6,082,900 J
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The EPA is collecting water samples from the Allegheny River and testing for lead ion
concentrations. They are measuring concentrations using an aluminum ion selective
electrode. Al (s) | Al 3+ (?) || Pb2+ (1.4 x 10-6 )| Pb (s). When they put the electrode in the water solution they measure a value of 1.42 V. Write a balanced redox reaction. What is [Al 3+ ] in the water sample? The EPA limit for drinkable water is 0.06 mg/L. Is the water drinkable?
2. I want to chrome plate my wheels on my mustang convertible using a trivalent chromium solution. How many g of chromium will I plate onto my wheels if I pass a current of 4.12 amps for 2.53 hours?
The wheels will have about 0.620 g of chromium plated on them.
Drinkable water is subject to an EPA limit of 0.06 mg/L. Is the water fit to drink?For the measurement using the aluminium ion selective electrode, the balanced redox reaction is 2 Al (s) + 3 Pb2+ (aq) 2 Al3+ (aq) + 3 Pb. (s)
The standard potential of the cell, E°cell, can be calculated using the cell notation as follows:
E'cell is equal to E'cathode minus E'anode.
E°cell = 0 Volts. (-1.66 V)
1.66 V for E°cell.
Ecell, the calculated cell potential, is 1.42 V. The aluminium ion content in the water sample can be determined using the Nernst equation:
Ecell equals (RT/nF) - E°cell. 1.42 V = 1.66 V - (0.0257 V) ln ([Al3+]/(1.4 x 10-6 M)) ln ([Al3+]/[Pb2+])
[Al3+] = 2.84 x 10^-5 M
Calculating in mg/L:
7.68 x 10-7 mg/L = 2.84 x 10-5 M x (1 L/1000 mL) x (26.98 g/1 mol) x (1 mg/1000 g)
The amount of lead ion in the water sample is less than the 0.06 mg/L EPA limit for drinking water. As a result, drinking the water is safe.
Faraday's law can be used to determine how much chromium is plated onto the wheels: moles of e- = (current x time) / (F)
F stands for the Faraday constant, which is 96485 C/mol e-. Because each mole of electrons moves one mole of chromium atoms (Cr3+ + 3e- Cr), it is possible to compute the moles of chromium used in plating.
moles of Cr equal (moles of e-) / 3
Using its molar mass (51.996 g/mol), one can then get the mass of chromium plated:
Cr's mass is equal to its molar mass multiplied by its molecular weight.
Changing the values indicated:
The formula is as follows: moles of e- = (4.12 A x 2.53 h x 3600 s/h) / (96485 C/mol e-) = 0.0357 mol e- moles of Cr = 0.0357 mol e- / 3 = 0.0119 mol Cr mass of Cr = 0.0119 mol Cr x 51.996 g/mol = 0.620 g Cr
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1. a) Compounds A and B have the same molecular formula of C4H10O. Both evolved bubbles of gas when treated with sodium metal. When A is heated with an acidified solution of sodium dichromate, it forms a green solution and Compound G, C4H8O2 whereas the colour of chromic acid was unchanged with B. (i) Draw the structural formula of A, B and G. (ii) Write all the chemical equations involved. (iii) Write the structural formula of the product formed when G reacts with B. State the catalyst used.
(i) The structural formula of A: CH₃CH₂CH₂CHO, B: CH₃CH(OH)CH₂CH₃, G. CH₃CH=CHCOOH. (ii) CH₃CH₂CH₂CHO + H₂Cr₂O₇ + H₂SO₄ → CH₃CH=CHCOOH + Cr₂(SO4)₃ + 7 H₂O (iii) Catalyst used: sulfuric acid (H₂SO4).
What are the compounds with same molecular formula but different structural formula known as?Compounds with the same molecular formula but different structural formula are known as isomers.
(i) Structural formula of A: CH₃CH₂CH₂CHO
Structural formula of B: CH₃CH(OH)CH₂CH₃
Structural formula of G: CH₃CH=CHCOOH
(ii) Equation for the reaction of A with sodium metal:
2 CH₃CH₂CH₂CHO + 2 Na → 2 CH₃CH₂CH₂COONa + H₂↑
Equation for the reaction of B with sodium metal:
CH₃CH(OH)CH₂CH₃ + Na → CH₃CH(OH)CH₂CH₂Na + 1/2 H₂↑
Equation for the reaction of A with acidified sodium dichromate:
CH₃CH₂CH₂CHO + H₂Cr2O₇ + H₂SO₄ → CH₃CH=CHCOOH + Cr₂(SO₄)₃ + 7 H₂O
(iii) The product formed when G reacts with B is an ester, specifically methyl 3-hydroxybutyrate. The reaction is catalyzed by sulfuric acid.
Structural formula of methyl 3-hydroxybutyrate: CH₃COOCH₂CH(OH)CH₂CH₃
Equation for the reaction of G with B:
CH₃CH=CHCOOH + CH₃CH(OH)CH₂CH₃ → CH₃COOCH₂CH(OH)CH₂CH₃
Catalyst used: sulfuric acid (H₂SO₄).
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Consider the reaction shown. What will happen if the pressure of the system is increased for this reaction? 2SO2(g) + O2(g) <--> 2SO3(g)
A: The equilibrium will shift to the left.
B: The equilibrium will be permanently destroyed.
C: The equilibrium will not be affected.
D: The equilibrium will shift to the right.
Answer: The answer to your question is D. Brainliest?
Explanation:
The reaction 2SO2(g) + O2(g) <--> 2SO3(g) involves the formation of sulfur trioxide (SO3) from sulfur dioxide (SO2) and oxygen (O2). According to Le Chatelier's principle, if a system at equilibrium is subjected to a change in temperature, pressure, or concentration, the system will respond by shifting its equilibrium position to counteract the change.
In this case, increasing the pressure of the system will cause the equilibrium to shift in the direction that reduces the total number of moles of gas. This is because increasing the pressure of a gas mixture will favor the reaction that produces fewer moles of gas, as this will reduce the overall pressure.
In the given reaction, the total number of moles of gas on the left side of the equation is 3 (2 moles of SO2 and 1 mole of O2), whereas on the right side, it is 2 (2 moles of SO3). Therefore, the equilibrium will shift to the right to produce more SO3, which will reduce the total number of moles of gas and thus reduce the pressure.
Hence, the correct answer is D: The equilibrium will shift to the right.
If the pressure of the system is increased for the given reaction, according to Le Chatelier's principle, the equilibrium will shift in a direction that partially counteracts the imposed stress.
In this case, the balanced equation shows that the number of moles of gas on the reactant side is equal to the number of moles of gas on the product side. Therefore, changing the pressure will not cause any shift in the equilibrium position.
Hence, the correct answer is C: The equilibrium will not be affected.
If 61.3 g of aspirin (C₉H₈O₄) are produced from 79.8 g of C₇H₆O₃, what is the percent yield from the reaction below?
C₇H₆O₃ (s) + C₄H₆O₃ (l) → C₉H₈O₄ (s) + HC₂H₃O₂ (aq).
52.1% of the aspirin in this process is yielded.
Why is aspirin's percent yield less than 100?The loss of the aspirin in the glassware is the reason why the yield percentage can be less than 100%. Unreacted reactants, which would have an impact on the amount of product (aspirin) created, are still another potential source for a decrease in yield.
79.8 g C₇H₆O₃ x (1 mol C₇H₆O₃ / 122.12 g C₇H₆O₃) = 0.653 mol C₇H₆O₃
The balanced equation also tells us that 1 mole of C₇H₆O₃ produces 1 mole of C₉H₈O₄. So, the theoretical yield of C₉H₈O₄ is:
0.653 mol C₇H₆O₃ x (1 mol C₉H₈O₄ / 1 mol C₇H₆O₃) = 0.653 mol C₉H₈O₄
Now, we can use the molar mass of C₉H₈O₄ to convert moles to grams:
0.653 mol C₉H₈O₄ x (180.16 g C₉H₈O₄ / 1 mol C₉H₈O₄) = 117.6 g C₉H₈O₄ (theoretical yield)
The actual yield is given as 61.3 g.
Now we can calculate the percent yield:
Percent yield = (actual yield / theoretical yield) x 100%
Percent yield = (61.3 g / 117.6 g) x 100%
Percent yield = 52.1%
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Find the molar solubility of SrCO3 in pure water. (Ksp = 5.4 x 10-10).
Answer: 7.35 x 10^-5.
Explanation: Easy. The precipitate equation is SrCO3 --> Sr2+ and Co32-. For every 1 mole of SrCo3, 1 mole of Sr2+ and 1 mole of Co32- is formed. Hence, the equation would be Q = [Sr2+][CO3 2-], where it is 5.4 x. 10 ^-10 = x(x). 5.4 x. 10 ^-10 = x^2. Solve for x. X is 7.35 x 10^-5.
Molar solubility by definition is the number of moles of a solute that can be dissolved per liter of solution before the solution becomes saturated. When Q > Ksp, precipitate forms as it is super saturated, and when Q < Ksp, precipitate would not form. When Q = Ksp, it is at equilibrium.
The solubility of silver dichromate at 15oC is 8.3 x 10-3 g/100mL solution. Calculate its Ksp. (Molar mass of silver dichromate is 323.79 g/mol)
Therefore, the Ksp of silver dichromate at 15oC is [tex]6.83 * 10^-^1^4.[/tex]
What is solubility product constant (Ksp)?The solubility product constant (Ksp) for silver dichromate ([tex]Ag_2Cr_2O_7[/tex]) can be calculated using the solubility information provided.
The balanced equation for the dissolution of silver dichromate is:
Ag2Cr2O7 (s) ⇌ 2 Ag+ (aq) + Cr2O7 2- (aq)
The Ksp expression for this equilibrium is:
Ksp = [Ag+]^2 [Cr2O7 2-]
where [Ag+] is the molar concentration of Ag+ ions in solution and [Cr2O7 2-] is the molar concentration of Cr2O7 2- ions in solution.
To calculate Ksp, we need to determine the molar concentrations of Ag+ and Cr2O7 2- ions in solution. Since the solubility of Ag2Cr2O7 is given in grams per 100 mL of solution, we first need to convert it to molar solubility:
molar solubility =[tex](8.3 * 10^-^3 g/100 mL) / (323.79 g/mol)[/tex] = [tex]2.56 * 10^-^5 M[/tex]
Since each formula unit of Ag2Cr2O7 produces 2 Ag+ ions in solution, the molar concentration of Ag+ ions is:
[Ag+] = 2 x molar solubility =[tex]5.12 * 10^-^5 M[/tex]
Similarly, each formula unit of Ag2Cr2O7 produces 1 Cr2O7 2- ion in solution, so the molar concentration of Cr2O7 2- ions is:
[Cr2O7 2-] = molar solubility =[tex]2.56 * 10^-^5 M[/tex]
Substituting these values into the Ksp expression gives:
[tex]Ksp = [Ag+]^2 [Cr_2O_7 2^-] = (5.12 * 10^-^5)^2 (2.56 * 10^-^5) = 6.83 * 10^-^1^4[/tex]
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How many grams of Al2O3
can form from 37.7 g
of Al
?
4Al(s)+3O2(g)⟶2Al2O3(s)
71.26 g of Al2O3 can form from 37.7 g of Al.
How to determine how many grams of Al2O3 can form from 37.7 g of AlThe balanced chemical equation is:
4Al(s) + 3O2(g) ⟶ 2Al2O3(s)
From the equation, we can see that 4 moles of Al react with 3 moles of O2 to form 2 moles of Al2O3. This means that the mole ratio of Al to Al2O3 is 4:2 or 2:1.
To determine how many grams of Al2O3 can form from 37.7 g of Al, we need to use the mole ratio and the molar mass of Al2O3.
Calculate the number of moles of Al:
molar mass of Al = 26.98 g/mol
moles of Al = mass/molar mass = 37.7 g / 26.98 g/mol = 1.397 mol
Use the mole ratio to determine the number of moles of Al2O3 that can form:
moles of Al2O3 = 1.397 mol Al × (2 mol Al2O3 / 4 mol Al) = 0.6985 mol Al2O3
Calculate the mass of Al2O3 using its molar mass:
molar mass of Al2O3 = 101.96 g/mol
mass of Al2O3 = moles of Al2O3 × molar mass = 0.6985 mol × 101.96 g/mol = 71.26 g
Therefore, 71.26 g of Al2O3 can form from 37.7 g of Al.
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How many litres of H2 gas (at STP) are needed to Completely
react with 5 moles of
0₂
gas?
Answer:
10
Explanation:
got it right on the redt
What does the latent heart of vaporization measure
Latent heat of vaporization measures the amount of heat that is required to change one unit of mass of substance from liquid state to a gaseous state at constant temperature and pressure.
What does latent heart of vaporization measure?Latent heat of vaporization is a physical property of substance, and it measures the amount of heat required to change one unit of mass of substance from liquid to gaseous state at constant temperature and pressure.
Latent heat of vaporization is the amount of energy required to overcome the intermolecular forces holding liquid molecules together and convert the substance from liquid to a gas phase.
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2. Given the unbalanced equation:
Na(s) +
H2O(1) -
NaOH(aq) +
Н.
When this equation is balanced, the reactant Na(s) and the product NaOH(aq) both have coefficients of
1) 1
2) 2
3) 3
4) 4
Answer: 2Na+ 2H2O ------- 2NaoH + H2
Explanation:
Find the molarity of H2C2O4 using mole concept
Answer:
To find the molarity of H2C2O4 (oxalic acid), we need to know the number of moles of H2C2O4 and the volume of the solution in liters.
Let's assume we have 10 grams of H2C2O4 and we dissolve it in enough water to make 1 liter of solution.
The molar mass of H2C2O4 can be calculated by adding the molar masses of the individual atoms:
molar mass of H2C2O4 = 2(1.01) + 2(12.01) + 4(16.00) = 90.04 g/mol
To calculate the number of moles of H2C2O4 in the solution, we divide the mass of H2C2O4 by the molar mass:
moles of H2C2O4 = mass of H2C2O4 / molar mass
moles of H2C2O4 = 10 / 90.04
moles of H2C2O4 = 0.111 mol
Therefore, we have 0.111 moles of H2C2O4 in 1 liter of solution.
The molarity of the solution is defined as the number of moles of solute per liter of solution:
Molarity = moles of solute / volume of solution (in liters)
Molarity = 0.111 mol / 1 L
Molarity = 0.111 M
Therefore, the molarity of the H2C2O4 solution is 0.111 M.
Explanation:
Please explain well! <33
What societal need would wider use of technology for forecasting earthquakes address?
Explanation:
Earthquakes are one of the most devastating natural disasters, causing widespread destruction and loss of life. The ability to predict earthquakes is critical for reducing their impact and ensuring the safety of people in affected regions. Wider use of technology for forecasting earthquakes can address the societal need for improved earthquake prediction and preparedness.One of the key benefits of technology for forecasting earthquakes is the ability to detect seismic activity before an earthquake occurs. This can provide early warning to people in affected areas, allowing them to evacuate or take other safety measures. Additionally, technology can help scientists better understand the patterns and causes of earthquakes, leading to more accurate predictions and a better understanding of earthquake risk.Wider use of technology for forecasting earthquakes can also help with disaster planning and preparedness. By providing more accurate information about earthquake risk, governments and organizations can better prepare for potential disasters, including developing evacuation plans, stockpiling supplies, and preparing emergency response teams.
CONCLUDING
In summary, the societal need for wider use of technology for forecasting earthquakes is significant. Improved earthquake prediction and preparedness can save lives, reduce damage to infrastructure and property, and help communities recover more quickly from disasters. By investing in technology for earthquake forecasting, we can better protect people and communities from the devastating effects of earthquakes.
Which of the following has the largest radius
A. Na
B. Na+
C. K+
D. K
Determine the mass in grams of 5.34 mol vanadium
Therefore, the mass of 5.34 mol of vanadium is approximately 271.758 grams.
What component is the heaviest?The heaviest element currently found in the periodic table, Oganesson, was named after the Russian physicist Yuri Oganessian (SN: 1/21/17, p. 16). It has a massive atomic mass of roughly 300. The synthetic element has only ever been produced in a small number of atoms, each of which lived for less than a millisecond.
The molar mass of vanadium (V) is approximately 50.94 g/mol.
To determine the mass of 5.34 mol of vanadium, we can use the following calculation:
mass = number of moles x molar mass
mass = 5.34 mol x 50.94 g/mol
mass = 271.758 g
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Report the answer to 3 significant figures
The mass of oxygen in the 77.4 g sample of Ni(BrO3)2 is 23.7 g, rounded to 3 significant figures.
What is molar mass?Molar mass is the mass of one mole of a substance, expressed in grams per mole (g/mol). It is calculated by adding up the atomic masses of all the atoms in the molecule. The atomic mass is the mass of one atom of an element, and it is listed on the periodic table.
Equation:To calculate the mass of oxygen in the sample of Ni(BrO3)2, we need to first determine how many moles of Ni(BrO3)2 are in the sample using its molar mass:
molar mass of Ni(BrO3)2 = 2 x molar mass of BrO3 + molar mass of Ni
= 2 x (79.904 + 3 x 15.999) + 58.6934
= 313.5914 g/mol
Number of moles of Ni(BrO3)2 in 77.4 g sample = 77.4 g / 313.5914 g/mol = 0.2468 mol
Each mole of Ni(BrO3)2 contains 6 moles of oxygen atoms, since there are 3 oxygen atoms in each formula unit and Ni(BrO3)2 has a formula weight of 2:
Number of moles of oxygen atoms in 0.2468 mol of Ni(BrO3)2 = 6 x 0.2468 = 1.481 mol
Finally, we can calculate the mass of oxygen in the sample:
Mass of oxygen = number of moles of oxygen atoms x molar mass of oxygen
= 1.481 mol x 15.999 g/mol
= 23.70 g
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A) HOCl(aq) is the molecule that kills bacteria when chlorine is added to water. The wing reaction produces this molecule.
Cl2(g) + H2O(l) + HOCI(aq) + H+ (aq) +CI (aq)
Which statement about this reaction is correct?
A Chlorine is both oxidised and reduced.
B Chlorine is oxidised but not reduced.
C Hydrogen is both oxidised and reduced.
D Hydrogen is oxidised but not reduced.
B) Find the oxidation state of,
i) Each Cr in K:Cr2O
ii) Mn in MnO
iii) C in C:04
C) 20.0cm of an acidified solution containing Fe ions was titrated against KMnO4 solution. 18.0cm of 0.450M KMnO4 was needed. Calculate the concentration of Fe ions in the acidified solution.
Explanation:
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>>HOCl(aq) is the molecule that kills bact
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HOCl(aq) is the molecule that kills bacteria wen chlorine is added to water.
The following reaction produces this molecule
Cl
2
(g)+H
2
O(l)⇌HOCl(aq)+H
+
(aq)+Cl
−
(aq)
Which statement about this reaction is correct?
Hard
Updated on : 2022-09-05
Solution
verified
Verified by Toppr
Correct option is A)
Oxidation and reduction are two types of chemical reactions that often work together. Oxidation and reduction reactions involve an exchange of electrons between reactants.
Reduction and oxidation occur simultaneously in a type of chemical reaction called a reduction-oxidation or redox reaction.
Oxidation Involves Loss of electrons
Reduction Involves Gain of electrons.
As we can see the above case with the chlorine .
hence chlorine is both oxidised and reduced
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A compound with the following composition by mass: 48.0% C, 8.0% H, 28.0% N and 16.0% O.
(a) Determine the empirical formula of this compound.
(b) If this compound has a molar mass of 200 g, what is its molecular formula?
In each case below, indicate the person or group that should have the authority to decide how to resolve
the problem.
A new weapon has been developed that can be made by anyone from materials purchased online.
elected government officials
military leaders
historians
Elected government leaders should have the power to address the issue of a new weapon that can be produced by anybody using materials acquired online. Military leaders can offer guidance, while historians can offer background.
How can you protest about an Indian Army officer?You can initially complain about this to the officer immediately above you. You may also submit a statutory complaint to the Indian government. In this regard, you must have strong evidence, as it is illegal to make untrue accusations against a senior officer.
Who was India's first army commander?After India gained independence from Great Britain, Kodandera Madappa Cariappa, also known by his nick name Kipper, served in the Indian military. He was the first chief of staff of the Indian army.
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Please help with this chemistry question
the cell potential for the given galvanic cell is +3.16 V at 25°C. This means that the reaction is strongly favored to occur spontaneously in the direction written, from left to right.
To calculate the cell potential for the given galvanic cell, we need to use the standard reduction potentials of the two half-reactions involved in the cell reaction. From the table of standard reduction potentials, we can find the following half-reactions:
Al³+ (aq) + 3e⁻ → Al(s) E°red = -1.66 V
Au³+ (aq) + 3e⁻ → Au(s) E°red = +1.50 V
To obtain the overall cell potential, we can use the equation:
E°cell = E°reduction (cathode) - E°reduction (anode)
where the cathode is the half-cell where reduction occurs and the anode is the half-cell where oxidation occurs. In this case, we can see that Au³+ is reduced to Au(s) (cathode) and Al(s) is oxidized to Al³+ (anode).
Therefore, we can calculate the cell potential as follows:
E°cell = E°red (Au³+ → Au) - E°red (Al → Al³+)
= (+1.50 V) - (-1.66 V)
= +3.16 V
Thus, the cell potential for the given galvanic cell is +3.16 V at 25°C. This means that the reaction is strongly favored to occur spontaneously in the direction written, from left to right.
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What is the largest unit of ordinary matter
Answer:
Explanation:
Conversely, the largest (in terms of mass) fundamental particle we know of is a particle called a top quark, measuring a whopping 172.5 billion electron volts, according to Lincoln.
A mass of 6.005 g of carbon (atomic mass 12.010 amu) contains...? ty in advance
The mass of 6.005 g of carbon contains approximately 3.011 x 10²³ carbon atoms.
How much mass do six moles of carbon atoms have?We are aware that a mole is a grouping of 6.022 10²³ atoms. 6.0221023 carbon atoms make up a mole of carbon. As a result, we can estimate that 6.0221023 carbon atoms have a mass of 12 grammes.
There are: atoms of carbon in the sample.
The amount of carbon atoms in the sample may be determined using Avogadro's number (6.022 x 10²³ atoms per mole) and the molar mass of carbon (12.010 g/mol)
Number of moles of carbon = mass of carbon/molar mass of carbon
= 6.005 g / 12.010 g/mol
= 0.500 mol
Number of carbon atoms=number of moles of carbon x Avogadro's number
= 0.500 mol x 6.022 x 10²³ atoms/mol
= 3.011 x 10²³ atoms
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Which of the following is described by the equation H2O(l) + heat  H2O(g)?
The term that is described by the equation H2O(l) + heat H2O(g) is Evaporating.
What is Evaporating?The equation H2O(l) + heat -> H2O(g) represents a physical process in which water in its liquid state (H2O(l)) absorbs heat and turns into its gaseous state (H2O(g)). This process is called "evaporation". Evaporation is a common process in nature where water from oceans, rivers, lakes, and other bodies of water turns into water vapor due to the heat energy from the sun. It is also a widely used process in industries to separate liquids from solutions and to concentrate solutions.
During evaporation, the heat energy absorbed by the liquid water overcomes the intermolecular forces holding the water molecules together, causing them to break apart and escape as water vapor. Thus, the equation H2O(l) + heat -> H2O(g) accurately describes the process of evaporation.
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Which of the following is described by the equation H20(1) + heat → H2O(g)?
A. Freezing
B. Condensing
C. Evaporating
D. Melting -
Which of the following is an example of quantization?

A.
The coach pacing the floor

B.
The movement of basketball players on a court

C.
The distance the ball is passed

D.
The fans sitting in the bleachers
B. The movement of basketball players on a court of the following is an example of quantization
What exactly does quantization mean?
The process of translating continuously infinite values to a more manageable collection of discontinuous finite values is known as quantization. It involves estimating real-world values with a digital representation that places restrictions on a value's precision and range in the context of simulation and embedded computing.
As a general guideline, quantize to the note you've played that is the shortest; for example, if the phrase contains both eighth and quarter notes, use eighth note resolution. Keep in mind that many rhythms may really employ triplets; if things aren't working out, you may try utilising a triplet resolution.
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