how to solve this? help ​

The total work done of 0.018 joules is needed to move the charges apart and double the distance between them.

We have two electric charges q(A) = 1μc and q(B) = -2μc kept at a distance 0.5 meter apart.

We have to calculate  much work is needed to move the charges apart and double the distance between them.

The potential energy of the system of two charges separated by a distance is given by -

[tex]U = \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}[/tex]

In order to solve this question, it is important to remember the work - energy theorem which states -

"The change in the energy of the body is equal to work done on it"

Hence, using this work -energy theorem in the question given to us we get -

[tex]U_{f} -U_{i} =W_{net}[/tex]

In our case -

[tex]U_{f} = \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{2r}\\\\U_{i} = \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}\\\\W=\frac{1}{4\pi\epsilon_{o} } \frac{qQ}{2r} - \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}\\\\W = \frac{qQ}{4\pi\epsilon_{o}r} (\frac{1}{2} -1)\\\\W = 9\times 10^{9}\times \frac{1 \times 10^{-6} \times 2\times10^{-6} }{0.5} \times \frac{-1}{2}[/tex]

W = 0.018 joules

Hence, the total work done should be 0.018 joules.

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~400 nm to ~700 nm are the wavelengths of electromagnetic wave in free space.

What are the wavelengths of electromagnetic wave in free space?

Electromagnetic waves are categorized on the basis of their frequency f, which is equivalent to wavelength λ = c/f. Visible light has a wavelength that ranges from ~400 nm to ~700 nm. Violet light has a wavelength of ~400 nm, and having a frequency of ~7.5*1014 Hz.

So we can conclude that: ~400 nm to ~700 nm are the wavelengths of electromagnetic wave in free space.

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The wavelengths of the light are 4.3 * 10^-12 m and 0.2 m respectively.

The term wavelength has to do with the horizontal distance that is covered by a wave. We know that a long wavelength implies that the wave is able to travel a long distance from one point to another.

Given that;

c = λf

c = speed of light

λ = wavelength of ight

f = frequency of light

Thus;

λ = 3 * 10^8/ 7.00 x 10^19

λ = 4.3 * 10^-12 m

λ = 3 * 10^8/1.50 x 10^9

λ = 2 * 10^-1 or 0.2 m

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Missing parts:

What are the wavelengths of electromagnetic wave in free space that have the following frequencies? (a) 7.00 x 10^19 Hz______ pm (b) 1.50 x 10^9 Hz__________ cm

[tex]\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}[/tex]

Apply the Conservation of Linear Momentum:

[tex]\longrightarrow \sf{m_1 u_1 +1 + m_2 u_2 = m_1v_1 + m_2v_2}[/tex]

[tex]\longrightarrow \sf{(7 \cdot 4) + (1 \cdot 0) = (7 \cdot 3) + 1v_2}[/tex]

Solving further:

[tex]\longrightarrow \sf{28+0 = 21+ v_2}[/tex]

[tex]\longrightarrow \sf{28 = 21+ v_2}[/tex]

[tex]\longrightarrow \sf{v_2= 28- 21}[/tex]

▪ [tex]\longrightarrow \sf{v_2= 7 \dfrac{m}{s} }[/tex]

[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]

[tex] \boxed{\bm{v_2= 7 \dfrac{m}{s}}}[/tex]

A low partial pressure of oxygen promotes hemoglobin binding to carbon dioxide. This is an example of the  Haldane effect

The less saturated hemoglobin is and the lower the partial pressure of oxygen in the blood is, the more readily hemoglobin binds to carbon dioxide. This is an example of the Haldane effect.

The Haldane effect is a property of hemoglobin first described by John Scott Haldane, within which oxygenation of blood in the lungs displaces carbon dioxide from hemoglobin, increasing the removal of carbon dioxide. Consequently, oxygenated blood has a reduced affinity for carbon dioxide.

The Haldane effect is a property of hemoglobin first described by John Scott Haldane, within which oxygenation of blood in the lungs displaces carbon dioxide from hemoglobin, increasing the removal of carbon dioxide. Consequently, oxygenated blood has a reduced affinity for carbon dioxide.

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Answer:

ΔV=Vi + Vf

           2

ΔV= 11m/s + 19m/s

                 2

ΔV= 15m/s

Explanation:

The cannonball will travel 311.8 m  horizontally. Among the given options, 310 m is the correct answer.

What is a Projectile ?

A projectile is any object like stone, ball or javelin that take a trajectory path when thrown into the air.

The following parameters are given from the question

Resolve the initial velocity into horizontal and vertical components. That is,

To calculate the range that is, the horizontal distance, will can first calculate the total time take by the ball to reach the ground.

Total time T = 2usinФ / g

Substitute all the parameters

T = (2 x 60sin30) / 10

T = (2 x 30) / 10

T = 60 / 10

T = 6 s

The horizontal distance R = ucosФ x T

R = 60 x cos 30 x 6

R = 311.77 m

Therefore, the cannonball will travel 312 m approximately horizontally.

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The power expended is calculated as 91,100 W.

We know that the acceleration can be obtained by the use of the equation;

v = u + at

v = final velocity

u = initial velocity

t = time

a = acceleration

a= v - u/t

a =  27 - 0/ 5.2 = 5.2 m/s^2

Thus;

v^2 = u^2 + 2as

but u= 0 m/s

v^2 = 2as

s =  v^2/2a

s = (27)^2/2 * 5.2

s = 70 m

Now;

Work done =  1300 kg * 5.2 m/s^2 * 70 m = 473200 J

Power = 473200 J/5.2 seconds

Power =  91,100 W

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The amount of heat required to raise the temperature is 706.05J.

To find the answer, we need to know more about the specific heat capacity.

                                 Q=msΔT

                 [tex]m=2.50g=2.50*10^{-3}kg\\s=0.523 J/gK=\frac{0.523}{10^{-3}} J/kgK=523J/kgK\\T_1=65^0C=338K\\T_2=600^0C=873K\\[/tex]

            [tex]Q=2.5*10^{-3}*523*(873-333)=706.05 J[/tex]

Thus, we can conclude that, the amount of heat required to raise the temperature is 706.05J.

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Answer:

.513 Ω

Explanation:

The current through the 20 Ω load can be found to be

  (12-.3) v / 20 Ω  = .585 A

This current also flows through the internal resistance and produces the .3 v drop across this resistor

V/I  = R

.3 v / .585 A = .513 Ω  internal resistance

Hi, your answer is below.

Time dilation is usually defined as the slowing of the passage of time experienced by objects in motion relative to an observer; measurable only a relativistic speeds.  Because time moves at various rates for the two of them depending on their relative velocities and/or proximity to things of considerable mass, if two persons (or objects) are moving relative to one another, they will age at separate rates. They will age differently from one another over time since their two timepieces will really tick at separate speeds. If they cross paths again later, they will both have aged differently, which may be determined by using their own timepieces, presuming they each had one. Einstein's Special and General Relativity equations, which have undergone extensive testing over the past 115 years and have never been shown to falter, regulate this "time dilation." The general relativity theory of Einstein, which states that a huge body's gravity warps space-time around it, causes time to move more quickly or more slowly depending on how far away the mass is from the observer, is what causes this so-called "time-dilation" phenomenon.

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565.2 lbs pressure can apply to a plunger.

It is given that,

The air supplied to a diaphragm is 20 psig.

Diameter is 6

Then r=3

We know that,

Area=

πr²

=(3.14×3²)

= 28.26

The formula is (3.14 ×radius of diaphragm squared) ×psig.

=( 28.26 ×20)

= 565.2 lbs of pressure.

Hence, the pressure is  565.2 lbs.

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When a proton slows from 0. 8c up to 0. 6c, it’s kinetic energy decreases by what factor of 1/4.

Kinetic energy of a proton having a charge Q and Voltage V is given by:

Kinetic energy = Q×V

Where, Q is the charge

            V is the Voltage

Kinetic energy is directly proportional to the charge on a proton.

Let the kinetic energy of proton having charge 0.8C be KE₁ and kinetic energy of proton having charge 0.6C be KE₂

Hence KE₁ = 0.8 × V

KE₂ = 0.6 × V

Now, KE₁ / KE₂ = 0.8 V / 0.6 V

⇒          KE₁ / KE₂ = 4 / 3

⇒         KE₂ / KE₁ = 3/4

⇒         KE₂ = 3/4 times KE₁

Hence, the final kinetic energy becomes 3/4 times the initial kinetic energy.

The kinetic energy decreases by a factor of:

Change = KE₁ - KE₂

Change = KE₁ - 3/4KE₁

Change = 1/4 KE₁

Hence, the kinetic energy decreases by a factor of 1/4

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Electric utility power blackouts will result in short electric power outages for the organization.

When the electrical power network, often known as the electrical grid, is down, there are power outages. Power outages can have a variety of causes, but they always tend to affect entire regions or cities rather than simply a single residence. For example, the Northeast blackout of 2003 left 50 million people without power from New York to Canada’s capital Ottawa.  

A place experiences a blackout when all power is lost. Power outages of this kind generally affect a sizable population over perhaps extraordinarily broad areas. Blackouts are particularly difficult to quickly fix because they typically result from significant damage to electrical generation facilities (such as structural damage from violent wind storms or lightning strikes). As a result, these types of outages can, in the worst-case scenarios, last for several weeks.

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The energy of the red light emitted by a neon atom is 2.827*10^-19J

Light produces photons which might be small packets of power. as the atoms of an object are heated, it results within the manufacturing of photons. The electrons locate pleasure from the warmth and produce extra energy. This power emits inside the shape of a photon, and extra photons are released because the cloth becomes hotter.

The SI unit of wavelength is metre typically denoted as m. at the same time as measuring wavelength the multiples or fractions of a metre is also used. extensively, exponential powers of 10 are used while wavelengths are of a huge property. while there are shorter wavelengths they're expressed as negative exponential.

c=3*10^8 h=6.626*10^-34

wavelength= 703.2*10^-9m

E=2.827*10^-19J

Hence energy of the red light is 2.827*10^-19J.

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Building a telescope that detects radio waves must be built with a very large dish since radio waves have very large wavelengths is regarded as a true statement and is denoted as option A.

This is defined as the distance between two successive crests or troughs of a wave.

Radio waves have the longest wavelength in the electromagnetic spectrum which is therefore the reason why a very large dish is built to detect it.

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The speed of one rocket relative to the other is 8.5 cc.

Let s be the frame at rest relative to the earth. Let the spaceship moving to the left with respect to the earth at speed [tex]v[/tex] be the particle in the terminology. Then the velocity of the spaceship relative to each other is simply the velocity of the second spaceship.

That for speeds small compared with the speed of light the relativistic velocity addition law gives the usual Newtonian result, whereas for speed near c the result is not what has been expected classically.

[tex]v' = 0.96cc\\\\v= 0.84cc\\\\\\v' = \frac{v+V}{1+ \frac{vV}{c^2} } \\\\v' = \frac{v+V}{ \frac{c^2+ vV}{c^2} }\\\\v' = \frac{(v+V) c^2} {c^2+ vV}\\\\\\v'c^2 + c^2v = V (c^2 - v'v)\\\\V = \frac{v'c^2+c^2v}{c^2 - v'v} \\ \\ = \frac{0.96 * 9* 10 ^1^6 + 0.84*9*10^1^6}{9*10^1^6 - 0.96 * 0.84} \\\\ =\frac{16.2}{1.9}\\ \\= 8.5 cc[/tex]

Therefore, the speed of one rocket relative to the other is 8.5 cc.

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The hydroxide ion concentration in a solution is 3.31*10^-8M.

To find the answer, we have to know more concentration of solution.

                     [tex]pH=-log[H_3O^+][/tex]

                   [tex][H_3O^+]=-10^{pH}=10^{-6.25}=5.6*10^{-7}M[/tex]

                        [tex]K_w=[H_3O^+][OH^-]\\Where,\\K_w=10^{-14}[/tex]

                         [tex][OH^-]=\frac{K_w}{[H_3O^+]} =\frac{10^{-14}}{10^{-6.52}}\\\\[/tex]

                           [tex][OH^-]=3.31*10^{-8}M[/tex]

Thus, we can conclude that, the hydroxide ion concentration in a solution is 3.31*10^-8M.

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The cost of operating the iron is $2186.49.

To find the answer, we have to know about the power.

              [tex]cost=power(kW)*t(hours)*(price/ kWh)[/tex]

                        [tex]P=IV=5.2*240=1248W[/tex]

                     [tex]t=2*365*24hours=17520hours.[/tex]

                  [tex]cost=1248*10^{-3}*17520*0.10} =\$2186.49[/tex]

Thus, we can conclude that the cost of operating the iron is $2186.49.

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A drift velocity in physics is the average speed that charged particles—like electrons—achieve within a material as a result of an electric field. An electron will typically move randomly across a conductor at the Fermi velocity, producing an average velocity of zero. Applying an electric field causes a little net flow in one direction to be added to this random motion; this is the drift.

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Drift velocity

it is a average speed of the particle reached in a random motion

The distance should be increased by 0.4 mm.

Lens formula is used here.

For a spherical mirror, the focal length, image distance, and object distance are all related by the lens equation, often known as the lens formula.

It is given by,

[tex]\frac{1}{f} = \frac{1}{v} -\frac{1}{u}[/tex]

where,

f = focal length

u = distance of the object

v = distance of the image formed

Given,

f = 40 mm

u = 4 m = 4000 mm

v =?

Using the lens formula,

[tex]\frac{1}{f} = \frac{1}{v} -\frac{1}{u}[/tex]

[tex]\frac{1}{40} = \frac{1}{v} -\frac{1}{4000}\\[/tex]

[tex]\frac{1}{v} = \frac{1}{40} + \frac{1}{4000}[/tex]

v = 39.6 mm

Change in distance = 40 - 39.6

                                 = 0.4 mm

Hence, the distance should be increased by 0.4 mm.

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0.4 mm

The distance should be increased by 0.4 mm.

We use lens formula here,

[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{v}[/tex] - [tex]\frac{1}{u}[/tex]

where,

f =  focal length

u = distance of the object

v = distance of the image formed

Given that,

f = 40 mm

u = 4 m = 4000 mm

v = ?

Using the lens formula, we get:

[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{v}[/tex] - [tex]\frac{1}{u}[/tex]

[tex]\frac{1}{40}[/tex] = [tex]\frac{1}{v}[/tex] - [tex]\frac{1}{4000}[/tex]

[tex]\frac{1}{v}[/tex] = [tex]\frac{1}{40}[/tex] + [tex]\frac{1}{4000}[/tex]

v = 39.6 mm

Change in the distance = 40 - 39.6

                                        = 0.4 mm

Therefore, the distance has to be increased by 0.4 mm

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Vmax = 1.258 m/s

Maximum velocity of any point on the string is 1.258 m/s.

Maximum velocity is given by,

Vmax = Aω

where,

V = velocity

A = amplitude

ω = angular displacement

ω is given by,

ω = 2[tex]\pi[/tex]f

where f = frequency

ω = 2[tex]\pi[/tex]f

   = 2*3.147*100

   = 629.4 rad

A = amplitude = 2mm

Vmax = Aω

         = 2 ×[tex]10^{-3}[/tex] × 629.4

         = 1.258 m/s

Maximum velocity = Vmax =  1.258 m/s

Maximum velocity of any point on the string is 1.258 m/s.

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The area of a second piston that exerts a force of 24,000 N is 0.04 [tex]m^{2}[/tex].

Gravitational force is measured in newtons. Utilizing the physics formula pressure = force/area, you can compute pressure if you know the value of a force. Both pounds per square inch (psi) and newtons per square meter (N/m2) are acceptable units of measurement for this pressure.

Given force 1 =  12,000 N

The pressure which has produced a force of 12,000 N at the piston 1 = Force/ area

= 12,000N / 0.020 [tex]m^{2}[/tex]

= 6,00,000 N/[tex]m^{2}[/tex]

Now force at piston 1 must be equal to force at piston 2. thus, force at piston 2 is given by:

Force at piston 2 = pressure × area

24,000 N = 6,00,000 × area

area = 0.04 [tex]m^{2}[/tex]

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The work done by the unstretched spring is 5 J.

Hooke's law states that the extension of a given material is directly proportional to the force applied as log as the elastic limit is not exceeded. Thus we have to know that; F = Ke

F = force applied

K = force constant

e = extension

Using the graph;

K = F/e

F = 200N

e = 5 cm or 5 * 10^-2 m

K = 200N/ 5 * 10^-2 m

K = 4000 N/m

Now;

Work = 1/2Ke^2

Work = 0.5 *  4000 N/m * (5 * 10^-2 m)^2

Work = 5 J

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A lorenz curve represents the cumulative percentage of total income received along the horizontal axis and the cumulative share of population along the vertical axis.

The distribution of the cumulative percent of occurrences by the cumulative percent of population is shown graphically by the Lorenz Curve. By expanding the neighbourhood income quintile group, the horizontal axis (x-axis) of the curve shows the cumulative percent of persons in the population, and the vertical axis (y-axis) shows the cumulative percent of events in the population.

The Lorenz curve can be described as the proportion of the population that the neighbourhood income quintile represents holding the proportion of population events.

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The volume of a unit cell is 4.3 × 10⁻¹⁰ pm³.

We need to start with the features of a face-centered cubic system in order to be able to determine the edge length of the unit cell.

As we know, a face-centered cubic system is characterized by a unit cell that has a total of 14 lattice points.

Now, these lattice points will contain

Assume that r is the edge length of the unit cell and that r is the radius of an iron atom. You'll see that we can represent x in terms of the cell's diagonal, d, using Pythagoras' Theorem.

        [tex]d^2 = x^2+ x^2[/tex]

        [tex]d^2=2x^2[/tex]

The cell's diagonal will be equal to one radius from the atom in the top corner, two from the atom in the face, and one from the atom in the lower corner.

[tex]d= r+2r+r = 4r[/tex]

This means that we have,

[tex](4r)^2=2x^2[/tex]

[tex]16.r^2 = 2x^2 \\x=\sqrt{8r^2}[/tex]

This is equivalent to

[tex]x=2\sqrt{2} r = 2\sqrt{2} .124= 350.7 pm[/tex]

So, the edge length of the unit cell is equal to 350.7 pm.

The volume of a unit cell. As we know, the volume of a cube is given by the formula

V = [tex]l[/tex] × [tex]l[/tex] × [tex]l[/tex]

[tex]l[/tex] = the edge length of the cube

Volume = (350.7)³ pm³

            = 4.3 × 10⁻¹⁰ pm³

            = 4.3e-30 cm³

Therefore, the volume of the unit cell is 4.3 × 10⁻¹⁰ pm³.

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When testing for friction loss coefficients, departments that use a pitot tube should use Smooth bore nozzle

The pitot tube is a simple and convenient instrument to measure the difference between static, total and dynamic pressure (or head) .

It is a device used to measure velocity in pipe, wide tunnel, aero planes , etc. Pitot tube is completely based on its principle that if the velocity of flow at any point becomes Zero. A pressure measuring instrument used to measure fluid flow speed, especially used to determine the airspeed of an aircraft

Smooth bore nozzles also use the lowest engine pump pressures, allowing for maximum reach. Smooth bore nozzles are often referred to as solid bore nozzles because they produce a solid stream to provide maximum reach and penetration to the seat of the fire.

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The frequency of a photon is  1.06 * [tex]10^{18}[/tex] Hz.

The mass of a neutron is:

m = 1.67 * [tex]10^{-27}[/tex] kg

Since we know its speed, we can calculate the neutron's momentum:

p = mv = (1.67 * [tex]10^{-27}[/tex] kg)(1400 m/s) = 2.34 * [tex]10^{-24}[/tex] kg m /s

The problem says the photon has the same momentum of the neutron, p.  The photon momentum is given by

                                               p = h / λ              

where h is the Planck constant, and  λ  is the photon wavelength. If we re-arrange the equation and we use the momentum we found before, we can calculate the photon's wavelength:

p = h / λ =  [6.6 * [tex]10^{-34}[/tex] J/s]  /  [2.34 * [tex]10^{-24}[/tex] kg m /s ]

             = 2.82 * [tex]10^{-10}[/tex] m

And since we know the photon travels at speed of light c, we can now calculate the photon frequency:

f = c /  λ  =  [3 * [tex]10^{8}[/tex] m/s] / [ 2.82 * [tex]10^{-10}[/tex] m ]

              = 1.06 * [tex]10^{18}[/tex] Hz.

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Convex lens  had the largest overall magnification .

In optics, It is a quantification of comparing the size of the image with respect to the size of the object. It gives us information about the image in terms of how large or small is the image formed. Magnification is defined as the ratio of the height of image to the height of object.

The convex lens has the largest overall magnification. To get maximum magnification by convex lens object must be placed between center of curvature and pole of the lens .

Magnifying glasses make objects appear larger because their convex lenses (convex means curved outward) refract or bend light rays, so that they converge or come together.

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The probability that she makes 6 of them is 0.242

Simply put, the probability is the likelihood that something will occur. When we don't know how an event will turn out, we can discuss the likelihood or likelihood of several outcomes. Statistics is the study of events that follow a probability distribution.

A basketball player has a probability = 0. 603

The player shoots 10 free throws.

Let x be a random variable that represents the number of free throws made by a basketball player.

x ≈ Binomial (n,p)

p = 0.603

n= 10

P(x=k) = [tex]_nC_k p^k (1-p)^{n-k}[/tex]

P(6)    [tex]= _1_0C_6 (0.603)^6 (1-0.603)^{10-6}[/tex]

           [tex]=210 (0.048) (0.397)^4[/tex]

           [tex]=210 (0.048)(0.024)[/tex]

           [tex]= 0.242[/tex]

Therefore, the probability that she makes 6 of them is 0.242

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The angle of refraction is a. 15°

Snell's law is described as “The ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, for the light of a given colour and for the given team of media”.

By Snell's law:

η = sin i / sin r. i = 25, η = 1.6

1.6 = sin25° / sin r

sin r = sin25° / 1.6

= 0.4226/1.6= 0.2641

calculating

r = sin⁻¹( 0.2641 )

sin−1(0.264) is ≈ 15.3075

the angle of refraction is a. 15°

So the angle associated with the incidence and refraction can have a relation to the refractive index of the two mediums. Snell's First Law: It states that the incident ray, the refracted ray and the standard lie on the same plane.

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