Answer: 1. Analyse the question.
2. Define your argument.
3. Use evidence, reasoning and scholarship.
4. Organised a coherent essay.
5. Write clearly.
6.Cite sources and evidence.
-------------------------------------------------------------------------------------------------------------To Start Writing A Essay-
Begin with what you are ready to write—a plan, a few sentences or bullet points. Start with the body and work paragraph by paragraph. Write the introduction and conclusion after the body. Once you know what your essay is about, then write the introduction and conclusion.
--------------------------------------------------------------------------------------------------------What are the five steps to writing an essay?
The Writing Process | 5 Steps with Examples & Tips
Step 1: Pre-writing. Before you start writing, you need to decide exactly what you'll write about and do the necessary research.
Step 2: Planning and outlining.
Step 3: Writing a first draft.
Step 4: Redrafting and revising.
Step 5: Editing and proofreading.
-------------------------------------------------------------------------------------------------------------How a proper essay should look?
A basic essay consists of three main parts: introduction, body, and conclusion. Following this format will help you write and organize an essay. However, flexibility is important. While keeping this basic essay format in mind, let the topic and specific assignment guide the writing and organization.
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What not to do when writing an essay?
1. Fail to address the question's topic in your introduction. ...
2. Stray from the focus of the question (especially in the conclusion) ...
3. Insert quotes without introducing them or relating them back to the topic. ...
4. Fail to provide references. ...
5.Use informal language, colloquialisms, or overuse rhetorical questions.
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How long should an essay be?
Essay length guidelines
Type of essay Average word count range
High school essay 300–1000 words
College admission essay 200–650 words
Undergraduate college essay 1500–5000 words
Graduate school admission essay 500–1000 words
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How do I start my introduction?
How to Write a Good Introduction
1. Keep your first sentence short.
2. Don't repeat the title.
3. Keep the introduction brief.
4. Use the word “you” at least once.
5. Dedicate 1-2 sentences to articulating what the article covers.
6. Dedicate 1-2 sentences to explaining why the article is important.
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What is a good introduction for a paragraph?
An introduction should include three things: a hook to interest the reader, some background on the topic so the reader can understand it, and a thesis statement that clearly and quickly summarizes your main point.
A ship has a speed in still water of 10 ms¹ and is pointed in the direction N 30°E, but there is a current of speed 2 ms-¹ flowing towards the direction SE. By applying the Cosine or Sine Rule, find the resultant velocity of the ship, in terms of its speed and a bearing. Give your answers correct to one decimal place.
Answer:
Hope this helped ^^
Explanation:
To find the resultant velocity of the ship, we can use vector addition by considering the ship's velocity in still water and the velocity of the current separately.
Let's denote the ship's velocity in still water as Vship = 10 m/s, and the velocity of the current as Vcurrent = 2 m/s.
To find the resultant velocity, we can break down the ship's velocity and the current's velocity into their horizontal (East/West) and vertical (North/South) components.
The horizontal component of the ship's velocity (Vship_h) can be calculated using the cosine rule:
Vship_h = Vship * cos(30°)
Vship_h = 10 * cos(30°) = 10 * (√3 / 2) ≈ 8.7 m/s
The vertical component of the ship's velocity (Vship_v) can be calculated using the sine rule:
Vship_v = Vship * sin(30°)
Vship_v = 10 * sin(30°) = 10 * (1 / 2) = 5 m/s
Now, since the current is flowing towards the direction SE (southeast), which is 45° from the East direction, we can break down the current's velocity into its horizontal and vertical components.
The horizontal component of the current's velocity (Vcurrent_h) can be calculated using the cosine rule:
Vcurrent_h = Vcurrent * cos(45°)
Vcurrent_h = 2 * cos(45°) = 2 * (√2 / 2) = √2 m/s
The vertical component of the current's velocity (Vcurrent_v) can be calculated using the sine rule:
Vcurrent_v = Vcurrent * sin(45°)
Vcurrent_v = 2 * sin(45°) = 2 * (√2 / 2) = √2 m/s
Now, we can find the resultant horizontal velocity (Vresultant_h) by adding the horizontal components of the ship's velocity and the current's velocity:
Vresultant_h = Vship_h + Vcurrent_h
Vresultant_h = 8.7 + √2 ≈ 10.1 m/s
Similarly, we can find the resultant vertical velocity (Vresultant_v) by adding the vertical components of the ship's velocity and the current's velocity:
Vresultant_v = Vship_v + Vcurrent_v
Vresultant_v = 5 + √2 ≈ 6.4 m/s
Finally, we can calculate the magnitude of the resultant velocity (Vresultant) using the Pythagorean theorem:
Vresultant = √(Vresultant_h² + Vresultant_v²)
Vresultant = √(10.1² + 6.4²) ≈ 11.9 m/s
The bearing of the resultant velocity can be calculated using the inverse tangent (tan⁻¹) of the vertical component divided by the horizontal component:
Bearing = tan⁻¹(Vresultant_v / Vresultant_h)
Bearing = tan⁻¹(6.4 / 10.1) ≈ 33.7°
Therefore, the resultant velocity of the ship, in terms of its speed and bearing, is approximately 11.9 m/s at a bearing of 33.7°.
