How would you compare dissolving and dispersing waste materials?Dissolving them means flushing them with water; dispersing them means breaking them downDissolving them means breaking them down; dispersing them means recycling themDissolving them means breaking them down; dispersing them means spreading them outDispersing them means cleansing them; dissolving them means flushing them with water

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Answer 1

Dissolving and dispersing are two different approaches to waste disposal. Dissolving is the method of separating and breaking down solid waste materials into smaller particles by using a solvent such as water.

Dispersing involves distributing and breaking up the waste into smaller pieces in order to make it more manageable to dispose of.

Dissolving means breaking them down; dispersing means spreading them out is the right choice.In conclusion, dissolving and dispersing waste materials have different methods. Dissolving refers to the separation and breaking down of solid waste materials into smaller particles by utilizing a solvent such as water.

Dispersing, on the other hand, involves distributing and breaking up waste into smaller pieces to make it more manageable to dispose of.

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Related Questions

Question 1: For the reduction of iron oxide (FeO) by carbon reductant at 950°C to form pure iron and carbon dioxide (CO2) gas leaving the reactor at 950°C. a) Give the balanced chemical reaction

Answers

The balanced chemical reaction for the reduction of iron oxide (FeO) by carbon reductant to form pure iron and carbon dioxide (CO2) gas at 950°C can be represented as follows: FeO + C -> Fe + CO2

In the given reaction, iron oxide (FeO) reacts with carbon (C) to produce pure iron (Fe) and carbon dioxide (CO2). The reaction equation is balanced by ensuring that the same number of atoms of each element is present on both sides of the equation.

The balanced equation indicates that one mole of FeO reacts with one mole of carbon to yield one mole of Fe and one mole of CO2. This balanced equation accurately represents the stoichiometry of the reaction, showing the conversion of reactants to products.

It's important to note that the reaction is taking place at a temperature of 950°C, which indicates the operating condition of the process.

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Clausius inequality is only applicable to reversible
processes.

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The Clausius inequality is a thermodynamic concept that applies specifically to reversible processes. It states that the integral of heat transfer divided by temperature for a closed system undergoing a cycle is less than or equal to zero.

The Clausius inequality is a fundamental principle in thermodynamics that helps us understand the direction and limits of heat transfer in systems. It is derived from the second law of thermodynamics, which states that heat cannot spontaneously flow from a colder body to a hotter body.

The inequality states that for a closed system undergoing a cycle, the integral of heat transfer (Q) divided by temperature (T) over the entire cycle is less than or equal to zero. Mathematically, it can be represented as ∮(dQ/T) ≤ 0, where ∮ denotes integration over a closed path.

This inequality holds true for reversible processes, which are idealized processes that can be reversed without causing any change in the surroundings. In reversible processes, the system is always in equilibrium with its surroundings, ensuring that heat transfer occurs infinitesimally slowly and in a reversible manner.

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Report the enthalphy of formation for each of the reactions that are used to synthesise urea in the two-step synthesis starting with ammonia and carbon dioxide. Explain which step determines the rate of urea production.

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In the two-step synthesis of urea starting with ammonia and carbon dioxide, the enthalpy of formation for each reaction is needed. The rate of urea production is determined by the step with the highest activation energy, which limits the overall reaction rate.

The two-step synthesis of urea involves the following reactions:

1. Formation of ammonium carbamate:

NH₃ + CO₂ → NH₂COONH₄

2. Decomposition of ammonium carbamate to form urea:

NH₂COONH₄ → H₂NCONH₂ + H₂O

To determine the enthalpy of formation for each reaction, the enthalpies of the reactants and products need to be known. These values can be obtained from thermodynamic databases or calculated using bond energies.

The rate of urea production is determined by the step with the highest activation energy, which is the energy barrier that must be overcome for the reaction to proceed. In this case, the decomposition of ammonium carbamate to form urea is often the rate-determining step.

NH₂COONH₄ → H₂NCONH₂ + H₂O

This is because the decomposition reaction requires breaking the bonds in ammonium carbamate, which can be relatively energy-intensive. The formation of ammonium carbamate, on the other hand, is usually a faster process.

By understanding the enthalpies of formation and identifying the rate-determining step, researchers can optimize the reaction conditions and catalysts to improve the overall production rate of urea.

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It has been found that by doubling the initial concentration of
a certain reactant, the rate of reaction becomes four times
greater. Determine the order of reaction with respect to the
reactant.

Answers

The order of reaction with respect to the reactant is 2. This means that the rate of the reaction is proportional to the square of the concentration of the reactant.

The order of a reaction is the relationship between the rate of the reaction and the concentration of each reactant raised to a power. The reaction order can be determined by using the initial rate method or by the integrated rate laws method. In this particular question, it has been found that the rate of reaction becomes four times greater when the initial concentration of a reactant is doubled.

This information can be used to determine the order of reaction with respect to the reactant.First, we need to use the rate equation, which is expressed as:

rate = k[A]^x[B]^ywhere k is the rate constant, [A] and [B] are the concentrations of the reactants, and x and y are the orders of reaction with respect to A and B, respectively.From the given information, we can say that:when [A] is doubled, the rate becomes 4 times greater.

This can be expressed mathematically as[tex]:(k[2A]^x[B]^y) = 4(k[A]^x[B]^y)[/tex]By dividing both sides by k[A]^x[B]^y, we get: (2^x) = 4x = 2

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83. Calculate mass (in grams) of sodium in 8.5 g of each sodium- containing food additive. a. NaCl (table salt) b. Na3PO4 (sodium phosphate) c. NaC H3O2 (sodium benzoate) d. Na,C,H,O, (sodium hydrogen citrate)

Answers

The mass of sodium in each sodium-containing food additive is:

a. NaCl (table salt): 3.36 g

b. Na₃PO₄ (sodium phosphate): 1.19 g

c. NaC₇H₅O₂ (sodium benzoate): 1.35 g

d. Na₃C₆H₅O₇ (sodium hydrogen citrate): 0.66 g

a. NaCl (table salt):

The molar mass of NaCl is 22.99 g/mol (sodium) + 35.45 g/mol (chlorine) = 58.44 g/mol.

To calculate the mass of sodium in NaCl, we need to determine the ratio of sodium to the total molar mass of NaCl:

Mass of sodium = (22.99 g/mol / 58.44 g/mol) × 8.5 g = 3.36 g

b. Na₃PO₄ (sodium phosphate):

The molar mass of Na₃PO₄ is 22.99 g/mol (sodium) × 3 + 30.97 g/mol (phosphorus) + 16.00 g/mol (oxygen) × 4 = 163.94 g/mol.

To calculate the mass of sodium in Na₃PO₄, we need to determine the ratio of sodium to the total molar mass of Na₃PO₄:

Mass of sodium = (22.99 g/mol / 163.94 g/mol) × 8.5 g = 1.19 g

c. NaC₇H₅O₂ (sodium benzoate):

The molar mass of NaC₇H₅O₂ is 22.99 g/mol (sodium) + 12.01 g/mol (carbon) × 7 + 1.01 g/mol (hydrogen) × 5 + 16.00 g/mol (oxygen) × 2 = 144.11 g/mol.

To calculate the mass of sodium in NaC₇H₅O₂, we need to determine the ratio of sodium to the total molar mass of NaC₇H₅O₂:

Mass of sodium = (22.99 g/mol / 144.11 g/mol) × 8.5 g = 1.35 g

d. Na₃C₆H₅O₇ (sodium hydrogen citrate):

The molar mass of Na₃C₆H₅O₇ is 22.99 g/mol (sodium) × 3 + 12.01 g/mol (carbon) × 6 + 1.01 g/mol (hydrogen) × 5 + 16.00 g/mol (oxygen) × 7 = 294.10 g/mol.

To calculate the mass of sodium in Na₃C₆H₅O₇, we need to determine the ratio of sodium to the total molar mass of Na₃C₆H₅O₇:

Mass of sodium = (22.99 g/mol / 294.10 g/mol) × 8.5 g = 0.66 g

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Consider the following experimental observations and measurements concerning transition metal complexes. Briefly explain each one in terms of an atomic/molecular picture of the species involved, using diagrams where appropriate and, if applicable, comment on the role of the d electrons assumed to reside on the metal ion in determining the observed properties. (a) A 0.100M aqueous solution of MnCl2 appears colourless to the eye, but a spectrophotometer reveals some extremely weak absorbance features in the visible region. (b) A 0.100M aqueous solution of Co(NO3)2 has a pale pinkish-purple colour. When conc. HCl is added, the solution goes an intense royal blue. (c) The measured magnetic susceptibility of solid K3[Fe(CN)6] corresponds to a magnetic moment per iron atom of about 1.8μB (where μB is the Bohr magneton). (d) A 0.100M aqueous solution of FeCl3 is made up. When tested with a pH meter, the pH of the solution is about 3.0. (e) The molecular salt [Co(NH3)4Cl2]NO3 can be crystallised in two different coloured forms with different physical properties such as melting points.

Answers

(a) A 0.100M aqueous solution of MnCl2 appears colorless to the eye, but a spectrophotometer reveals some extremely weak absorbance features in the visible region. The transition metal ions Mn2+ possess partially filled d-orbitals, which can undergo electron transition to higher energy levels in the visible region. However, the electron transitions are limited in Mn2+, resulting in weak visible absorbance features. Aqueous solutions of Mn2+ are pale pink, and in dilute solutions, the color may not be noticeable.

Therefore, solutions of Mn2+ may appear colorless to the eye, while a spectrophotometer can still detect the presence of extremely weak absorbance features in the visible region, indicating the existence of the Mn2+ transition metal ion.(b) A 0.100M aqueous solution of Co(NO3)2 has a pale pinkish-purple color. When conc. HCl is added, the solution goes an intense royal blue.When conc. HCl is added to the Co2+ solution, the hydrochloric acid donates chloride ions (Cl-), resulting in the formation of the complex [CoCl4]2-. The complex ion [CoCl4]2- exhibits a more intense blue color than the pale pinkish-purple color of Co2+. Cobalt (II) nitrate, Co(NO3)2, aqueous solutions are pale pink in color. However, when the solution is treated with concentrated HCl, the solution changes to a much more intense blue color. This is due to the formation of the complex [CoCl4]2-.(c) The measured magnetic susceptibility of solid K3[Fe(CN)6] corresponds to a magnetic moment per iron atom of about 1.8μB (where μB is the Bohr magneton).The magnetic moment per iron atom in solid K3[Fe(CN)6] can be attributed to the existence of unpaired electrons in the Fe2+ ion's d-orbitals. The magnetic moment is a measure of the magnetism of the species under the influence of a magnetic field.

K3[Fe(CN)6], Fe2+ is a transition metal ion that possesses partially filled d-orbitals. Due to this, it may experience unpaired electrons that may result in a magnetic moment. The magnetic susceptibility of solid K3[Fe(CN)6] corresponds to a magnetic moment per iron atom of about 1.8μB, which is higher than the spin-only value of 1.73μB for Fe2+ with five unpaired d-electrons.(d) A 0.100M aqueous solution of FeCl3 is made up. When tested with a pH meter, the pH of the solution is about 3.0.Main answerAqueous solutions of FeCl3 can be acidic due to hydrolysis reactions. In the presence of water, Fe3+ undergoes hydrolysis to form [Fe(H2O)5(OH)]2+ and [Fe(H2O)4(OH)2]+. These hydrolysis reactions result in the formation of H+ ions, which lowers the pH of the solution. pH of an aqueous solution of FeCl3 is around 3.0 when tested with a pH meter. This is because Fe3+ undergoes hydrolysis to produce [Fe(H2O)5(OH)]2+ and [Fe(H2O)4(OH)2]+ ions in the presence of water, resulting in the formation of H+ ions and thus making the solution acidic.(e) The molecular salt [Co(NH3)4Cl2]NO3 can be crystallized in two different colored forms with different physical properties such as melting points.B The two different colored forms of [Co(NH3)4Cl2]NO3 can be explained by the presence of different crystal structures. The crystal structure of the compound affects its physical properties, such as melting points.molecular salt [Co(NH3)4Cl2]NO3 can be crystallized in two different colored forms with different physical properties such as melting points. The two different colored forms of [Co(NH3)4Cl2]NO3 can be explained by the presence of different crystal structures. The crystal structure of the compound affects its physical properties, such as melting points.

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what volume, in milliliters, of 0.470 m ca(oh)2 is needed to completely neutralize 201 ml of a 0.360 m hi solution

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To determine the volume of 0.470 M Ca(OH)2 solution needed to neutralize 201 mL of a 0.360 M HI solution, we can use the concept of stoichiometry and the balanced chemical equation between Ca(OH)2 and HI.

The balanced chemical equation is:

2 HI(aq) + Ca(OH)2(aq) → CaI2(aq) + 2 H2O(l)

According to the equation, 2 moles of HI react with 1 mole of Ca(OH)2. Therefore, we can establish the following ratio:

0.360 moles HI : 0.470 moles Ca(OH)2

To find the volume of the Ca(OH)2 solution, we need to calculate the moles of Ca(OH)2 required to react completely with 0.360 moles of HI:

Moles of Ca(OH)2 = 0.470 moles Ca(OH)2 / 2 moles HI * 0.360 moles HI

                = 0.0846 moles Ca(OH)2

Now, we can use the molarity and moles of Ca(OH)2 to find the volume of the solution:

Volume of Ca(OH)2 solution = Moles of Ca(OH)2 / Molarity of Ca(OH)2

                         = 0.0846 moles / 0.470 M

                         = 0.180 L

                         = 180 mL

Therefore, 180 mL of the 0.470 M Ca(OH)2 solution is needed to completely neutralize 201 mL of the 0.360 M HI solution.

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Extent of the reaction affects a. None of the above/below b. The enthalpy change in the reactor only c. The enthalpy change in the reactor and The heat of reaction d. The heat of reaction only

Answers

Extent of the reaction affects the enthalpy change in the reactor and The heat of reaction. Option c. is the correct answer. The extent of the reaction is the measure of how much of the reactants get consumed or how much of the products are produced.

The heat of reaction, on the other hand, is the change in enthalpy during a chemical reaction. For an exothermic reaction, the heat of reaction is negative, whereas, for an endothermic reaction, it is positive. The enthalpy change in the reactor is affected by the extent of the reaction. If the reaction goes to completion, the enthalpy change in the reactor is at its maximum value. On the other hand, if the reaction is incomplete, then the enthalpy change is lesser than the maximum value. The heat of reaction is only affected by the extent of the reaction and not by any other factor. Therefore, the extent of the reaction affects the enthalpy change in the reactor and The heat of reaction.

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Valence bond theory predicts that xenon will use _____ hybrid orbitals in XeOF4.
a.sp
b.sp2
c.sp3
d.sp3d
e.sp3d2

Answers

Answer:

d. sp3d hybrid orbitals in XeOF4.

Explanation:

In XeOF4, xenon is bonded to one oxygen atom (O) and four fluorine atoms (F). The central xenon atom has an expanded octet, meaning it utilizes hybrid orbitals beyond the typical sp3 hybridization.

The oxygen atom contributes two electron pairs, while each fluorine atom contributes one electron pair. In order to accommodate these electron pairs and form bonds, xenon undergoes sp3d hybridization, resulting in five hybrid orbitals.

A liquid phase reaction A→B is carrie out in batch CSTR at 77oC. The feed rate of A is 10 mol/min, concentration is 2 mol/m3. What is the volume of CSTR if the conversation is 75% and activation energy is 50.2KJ/min at 25OC and the rate constant is 0.3 min−1 A.1 B.2 C.5 D.3

Answers

The volume of the CSTR (Continuous Stirred-Tank Reactor) is approximately 2 m³.

To determine the volume of the CSTR (Continuous Stirred-Tank Reactor) for the given conditions, we need to apply the design equation for a batch CSTR and take into account the conversion, feed rate, concentration, activation energy, and rate constant.

The design equation for a batch CSTR is given as:

V = (F₀ * (1-X)) / (-rA)

where:

V is the volume of the CSTR (in m³),

F₀ is the feed rate of A (in mol/min),

X is the conversion (as a fraction),

rA is the rate of reaction of A (in mol/(min·m³)).

To calculate the rate of reaction (rA), we can use the Arrhenius equation:

rA = k * C * exp(-Ea / (RT))

where:

k is the rate constant (in min⁻¹),

C is the concentration of A (in mol/m³),

Ea is the activation energy (in KJ/min),

R is the ideal gas constant (8.314 J/(mol·K)),

T is the temperature (in K).

Given:

Feed rate of A (F₀) = 10 mol/min,

Concentration of A (C) = 2 mol/m³,

Conversion (X) = 75% = 0.75,

Activation energy (Ea) = 50.2 KJ/min,

Rate constant (k) = 0.3 min⁻¹,

Temperature (T) = 25°C = (25 + 273.15) K.

First, we need to convert the activation energy to the appropriate units:

Ea = 50.2 KJ/min * (60 s/min) / (1000 J/KJ) = 3.012 KJ/s.

Substituting the given values into the equations, we can calculate the volume of the CSTR:

rA = 0.3 min⁻¹ * 2 mol/m³ * exp(-3.012 KJ/s / (8.314 J/(mol·K) * (25 + 273.15) K))

Now we can calculate the volume of the CSTR using the design equation:

V = (10 mol/min * (1 - 0.75)) / (-rA)

Performing the calculations, we find that the volume of the CSTR is approximately 2 m³.

Therefore, the correct answer is B.2.

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the silver-ion concentration in a saturated solution of silver(i) sulfate is 2.9 × 10–2 m. what is ksp for silver(i) sulfate?

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Ksp for the silver(i) sulfate is Ksp = 9.43 × 10–5 m3. Ksp is the solubility product of a substance, which is a chemical constant used to indicate the maximum concentration of a solute that may be dissolved in a solvent before precipitating.

The solubility of the salt in the solution at a given temperature can be calculated using the Ksp value. It's a product of the concentrations of the ions in a saturated solution of the substance. The expression for the Ksp of silver sulfate is given below:

Ag2SO4(s) ↔ 2Ag+(aq) + SO42-(aq). The molar solubility of the salt can be calculated using the silver ion concentration as follows:

Ag2SO4(s) ↔ 2Ag+(aq) + SO42-(aq).

The initial molar concentration of Ag+ is two times greater than the molar solubility of Ag2SO4, thus Ag+ concentration is

2 × 2.9 × 10–2 m

= 5.8 × 10–2 m.

The Ksp for the silver(i) sulfate is obtained by the expression:

Ksp = [Ag+]2[SO42-]

Ksp = (5.8 × 10–2)2(2.9 × 10–2)

Ksp = 9.43 × 10–5 m3

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In the instruction MOV AX, 100[BP][SI], which segment register
can be used to form the source operand address?
What is the relationship between three unsigned numbers
X=1001001B, Y=120Q, Z=5EH?

Answers

The segment register that can be used to form the source operand address in the instruction MOV AX, 100[BP][SI] is DS (Data Segment).

Without knowing the base for Y, it is not possible to establish a direct relationship between the three unsigned numbers X=1001001B, Y=120Q, and Z=5EH.

In the instruction MOV AX, 100[BP][SI], the segment register that can be used to form the source operand address is DS (Data Segment). The DS register holds the segment base address, which is added to the effective address to calculate the physical address of the source or destination data.

Regarding the relationship between the three unsigned numbers X=1001001B, Y=120Q, Z=5EH:

X=1001001B: This is a binary number represented in base 2. It has a value of 73 in decimal notation (base 10). The subscript "B" indicates that the number is in binary format.

Y=120Q: This number is represented using an unknown base, denoted by the subscript "Q." Without knowing the base, it's not possible to determine the exact value of Y or establish a relationship with the other numbers.

Z=5EH: This number is represented in hexadecimal notation (base 16). It has a value of 94 in decimal notation (base 10). The subscript "E" indicates that the number is in hexadecimal format.

Without knowing the base for Y, it is not possible to establish a direct relationship between X, Y, and Z.

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Following the question above, write charge balance equation for a 0.001 M solution of hydrofluoric acid (don't forget water's dissociation into H* and OH ions) Charge Balance: [ ___ ] = [ ___ ] + [ ___ ]
a. OH*:F: OH-
b. H+: F: 2OH-
c. 1:1:1 d. +:-:-

Answers

The charge balance equation for a 0.001 M solution of hydrofluoric acid is: [H+] = [F-] + [OH-].

When hydrofluoric acid (HF) is dissolved in water, it undergoes dissociation into its ions, H+ and F-. Additionally, water itself undergoes auto-ionization to produce H+ and OH- ions.

Therefore, to write the charge balance equation, we need to consider the concentrations of these ions.

In a 0.001 M solution of hydrofluoric acid, the concentration of H+ ions is equal to 0.001 M. Since HF is a weak acid, it only partially dissociates in water, so the concentration of F- ions is also 0.001 M.

For water's auto-ionization, we assume it to be at 25°C. At this temperature, the concentration of H+ ions from water's dissociation is extremely small and can be neglected. Therefore, we only consider the concentration of OH- ions, which is also negligible in this case.

Combining these considerations, the charge balance equation becomes: [H+] = [F-] + [OH-]. This equation ensures that the charges on the left-hand side (H+) are balanced by the charges on the right-hand side (F- and OH-).

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1. There is a 2. Pressure is only a function direction, and not of the transverse coc Op/Oy=0. dominant effects of pressure and viscous forces. 3. Inertial and gravitational terms are negligible in comparison with the two 4. There is no flow in the direction, normal to the plane of the diagram. This is a poor assumption in some cases, not considered here, in which there is a continuous leakage of makeup lubricant along the direction of the shaft ( a corresponding injection of lubricant in the vicinity of the bearing surface).

Answers

The statements highlight the directional dependency of pressure, the significance of pressure and viscous forces, the negligible contributions of inertia and gravity, and the assumption of no flow in the normal direction (except in cases of lubricant leakage).

The given statements are related to a specific context, possibly discussing fluid dynamics or mechanics. Let's break them down and summarize the key points:

1. Pressure is only dependent on direction, not on the transverse component (Op/Oy = 0). This suggests that pressure variations occur primarily along a particular direction and are unaffected by transverse components.

2. The dominant effects in the system are pressure and viscous forces. Other factors like inertia and gravity can be considered negligible compared to these two forces.

3. Flow in the direction normal to the diagram plane is assumed to be absent. However, this assumption may not hold in cases where there is continuous leakage of lubricant in the direction of the shaft, which would require considering lubricant injection near the bearing surface.

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State which of the following statements are true: a) When two metals, e.g. Zn and Cd, are connected and placed in a solution containing both metal ions, the metal with the lower standard potential would corrode. b) Conversely, the metal with the higher potential would be deposited. c) The cell and cell reaction are written in opposite orders, for instance, for the cell Fe/Fe2+(aq)/Cu2+(aq)/Cu, the reaction is Fe2+ +Cu→Cu2+ +Fe d) The cell potential is obtained by subtracting the electrode potential of the right-hand electrode from the left-hand electrode.

Answers

Answer:

A

Explanation:

True: When two metals are connected and placed in a solution containing both metal ions, the metal with the lower standard potential (more negative standard reduction potential) would tend to corrode or undergo oxidation.

ch3ch2ch3, ch3ch2f, ch3ch2oh a. which is expected to have the lowest vapor pressure?

Answers

CH3CH2OH is expected to have the lowest vapor pressure. Vapor pressure is the pressure created by a vapor in a thermodynamic equilibrium with its condensed phases, at a given temperature in a closed system.

It is a measure of how easily a liquid will evaporate and form a gas. Liquids with a higher vapor pressure at a given temperature evaporate more quickly than liquids with a lower vapor pressure at the same temperature. The liquid with the lowest vapor pressure is the liquid that evaporates the slowest at a given temperature.  

The order of vapor pressure from lowest to highest will be:
CH3CH2OH < CH3CH2F < CH3CH2CH3. The reason is that intermolecular forces increase as polarity increases. CH3CH2OH is the most polar among the three due to the presence of hydrogen bonding, which is a strong intermolecular force. In comparison, CH3CH2F has only dipole-dipole interactions and CH3CH2CH3 has only van der Waals forces. Hydrogen bonding causes the molecules to stick together more tightly than dipole-dipole interactions, which causes the vapor pressure of CH3CH2OH to be lower than that of CH3CH2F.

Therefore, CH3CH2OH is expected to have the lowest vapor pressure.

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Assume that you are a newly employed Chemical Engineer who has been requested by your Process Manager to design a multicomponent distillation. (a) State the number of fractionators that are required to separate five components (b) Define the following terms with respect to multicomponent distillation systems: fractional recovery, key components, non-key components, distributed components and undistributed components

Answers

(a) To separate five components in a multicomponent distillation, only one fractionator is required.

(b) In multicomponent distillation systems:

Fractional recovery refers to the fraction of a component that is recovered as a product from the distillation process.Key components are the main components of interest that are selectively separated and recovered in a multicomponent distillation.Non-key components are the remaining components that are not the primary focus of separation but are present in the feed mixture.Distributed components are those components that are evenly distributed between the distillate and bottoms streams in a multicomponent distillation.Undistributed components are the components that remain unseparated and appear in both the distillate and bottoms streams.

In multicomponent distillation, the number of fractionators required depends on the complexity of the mixture and the desired separation objectives. However, for separating five components, a single fractionator can be used. This is because a fractionator, also known as a distillation column, is designed to perform multiple separation stages within a single unit.

Fractional recovery is a crucial parameter in multicomponent distillation. It represents the efficiency of separation and is defined as the ratio of the amount of a specific component recovered in the distillate or bottoms to the total amount of that component in the feed mixture.

Key components are the components that are of primary interest and are selectively separated and recovered. These are usually the high-value components or those with specific purity requirements.

Non-key components, on the other hand, are the components that are not the primary focus of separation. They may have lower value or do not require high purity. These components are typically present in the feed mixture but are not selectively separated.

Distributed components are the components that distribute themselves between the distillate and bottoms streams in a multicomponent distillation. They undergo partial separation and are present in both product streams.

Undistributed components, as the name suggests, remain unseparated and appear in both the distillate and bottoms streams. These components are challenging to separate due to their similar properties or azeotropic behavior.

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Part 1 (1 point) See Periodic Table OS Achemist makes up a solution by dissolving 33.0 g of Mg(NO3)2 in enough water to produce a final solution volume of 207 mL. To calculate the molarity of the solution, what additional information is needed? Choose one: the mass of the water added the volume of water used O the molar mass of Mg(NO3)2 the density of the Mg(NO3)2 Part 2 (1 point) See Hint Calculate the number of moles of Mg(NO3)2 used to make up this solution 33.0 g of Mg(NO3)2 is equivalent to mol Mg(NO3)2

Answers

The number of moles of Mg(NO3)2 used is approximately 0.222 moles.

To calculate the molarity of the solution, we need the molar mass of Mg(NO3)2. The molar mass of Mg(NO3)2 can be calculated by summing the atomic masses of magnesium (Mg), nitrogen (N), and oxygen (O) in the compound.

Mg(NO3)2:

Molar mass of Mg = 24.31 g/mol

Molar mass of N = 14.01 g/mol

Molar mass of O = 16.00 g/mol

Molar mass of Mg(NO3)2 = (24.31 g/mol) + 2 * (14.01 g/mol) + 6 * (16.00 g/mol)

= 24.31 g/mol + 28.02 g/mol + 96.00 g/mol

= 148.33 g/mol

Now, we can calculate the moles of Mg(NO3)2 used in the solution. Given that the mass of Mg(NO3)2 is 33.0 g:

moles = mass / molar mass

moles = 33.0 g / 148.33 g/mol

moles ≈ 0.222 moles

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Which ion will be attracted to a magnetic field?
A) C ^ 2+
B) O ^ 2-
C) F+
D) Be
E) All of the above

Answers

The ion that will be attracted to a magnetic field is A) C^2+ (carbon cation).

The attraction of an ion to a magnetic field depends on the presence of unpaired electrons. Unpaired electrons possess a magnetic moment and can align with an external magnetic field, resulting in attraction.

Among the given options, only the carbon cation (C^2+) has unpaired electrons. Carbon normally has 4 valence electrons, but when it loses two electrons to form the C^2+ cation, it retains two unpaired electrons in its outermost energy level. These unpaired electrons give carbon cations a magnetic moment, allowing them to be attracted to a magnetic field.

The other options do not possess unpaired electrons. O^2- (oxygen anion) has gained two electrons to achieve a stable electronic configuration, resulting in a filled outermost energy level with no unpaired electrons. F+ (fluorine cation) and Be (beryllium) do not have any unpaired electrons either.

Among the given options, only the carbon cation (C^2+) will be attracted to a magnetic field due to the presence of unpaired electrons. The other ions, including O^2-, F+, and Be, do not possess unpaired electrons and will not exhibit magnetic attraction.

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Which salt is NOT derived from a strong acid and a strong soluble base?
LiClO4
MgCl2
CsBr
Ba(NO3)2
Which of the following is an acidic salt?
CH3NH3NO3
H3PO4
KMnO4

Answers

The salt that is NOT derived from a strong acid and a strong soluble base is: Ba(NO₃)₂

The substance that is not an acidic salt is: CH₃NH₃NO₃

What is an acidic salt?

An acidic salt is a type of salt that produces an acidic compound or element after it has been dissolved in a solvent. An acidic salt in the list of options provided is CH₃NH₃NO₃.

This compound is formed from methylamine, a weak acid, and nitric acid, a strong acid. Also, barium nitrite is formed from a strong base and weak acid.

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Which of the following metals WILL NOT corrode when acid rain falls on the metal? Assume oxygen is also present, as we're on planet Earth a.Magnesium b. Aluminum c. Lithium d.Silver Iron e. Lead f.All of the above

Answers

Out of the given options, silver will not corrode when acid rain falls on the metal. Silver is considered to be a noble metal that is resistant to corrosion by most acids, including sulfuric acid (H2SO4) and hydrochloric acid (HCl).

Silver is highly resistant to corrosion in the atmosphere and water, making it an excellent material for jewelry, silverware, and coinage. However, it can tarnish if exposed to hydrogen sulfide or sulfur in the air. Therefore, option (d) silver is the correct answer. As we know, Acid rain is caused by the burning of fossil fuels, including coal and oil, which release large amounts of sulfur dioxide and nitrogen oxides into the air.

When these substances combine with water vapor, they form sulfuric acid and nitric acid, respectively, which fall back to the earth as acid rain. When acid rain falls on metals such as iron, steel, copper, zinc, and aluminum, they can corrode and weaken, eventually causing structural damage and failure. Magnesium, aluminum, and lithium are highly reactive metals that are prone to corrosion when exposed to acid rain. Iron and lead are also highly reactive and will corrode when exposed to acid rain. Hence, the correct answer is (d) silver.

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What is the exact aim of polarization in corrosion ?
i understood if we use weight loss method for corrosion rate we can trace corrosion rate by weight loss by direct measurement with specified time.
but for polarization dose it control corrosion rate or measure corrosion rate?

Answers

The exact aim of polarization in corrosion is to measure the corrosion rate of the material in question. while the weight loss method is a direct measurement technique, polarization is a technique used to both measure and control the corrosion rate of a material.

However, unlike the weight loss method, which is used to calculate the corrosion rate directly, polarization is used to control the corrosion rate. Therefore, it can be said that polarization is a technique used to both measure and control the corrosion rate of a material.

The weight loss method directly measures the corrosion rate by calculating the difference in weight of a metal sample before and after exposure to a corrosive environment. On the other hand, polarization is used to measure and control the corrosion rate of a material. In polarization, a current is passed through the metal sample, which creates a potential difference between the anodic and cathodic areas. This results in the formation of a protective film on the surface of the metal, which slows down the rate of corrosion.

By controlling the potential difference, it is possible to control the corrosion rate of the material. This is especially useful in industrial settings where materials are exposed to harsh environments. By controlling the corrosion rate, the lifespan of the materials can be extended, leading to significant cost savings for industries. Therefore, while the weight loss method is a direct measurement technique, polarization is a technique used to both measure and control the corrosion rate of a material.

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It is very difficult to measure the enthalpy change of methane produced from the reaction between carbon and hydrogen.
C(s)+2H2( g)→CH4( g)……..... 1 However, the enthalpy change can be obtained algebraically using the following equations:
H2( g)+1/2O2( g)→H2O(I)…...Eq.2ΔHro=−393.5 kJ C(s)+O2( g)→CO2( g)……Eq.3Δfr∘=−285.8 kJ CH4( g)+2O2( g)→CO2( g)+2H2O (I) ….….Eq.4ΔHr∘=−890.3 kJ Identify the enthalpy change for the first reaction. - ΔHra= Standard heat of reaction

Answers

The enthalpy change (ΔHra) for the reaction between carbon and hydrogen to produce methane ([tex]CH_4[/tex]) can be obtained algebraically using the given equations and Hess's Law. By manipulating and combining the equations, the enthalpy change of -103.3 kJ is determined by subtracting twice the enthalpy change of water formation from the enthalpy change of [tex]CO_2[/tex] formation.

To determine the enthalpy change of the first reaction (ΔHra), we can use a combination of the given equations and the concept of Hess's Law.

Hess's Law states that the overall enthalpy change of a reaction is independent of the pathway taken and depends only on the initial and final states.

We need to manipulate the given equations to obtain the desired reaction, which is the first equation (Eq. 1: C(s) + 2[tex]H_2[/tex](g) → [tex]CH_4[/tex](g)).

By rearranging equations, we can create the desired reaction while ensuring the stoichiometric coefficients and reactants/products match:

1/2 Eq. 2: [tex]H_2[/tex](g) + 1/2 [tex]O_2[/tex](g) → [tex]H_2O[/tex](l) (divided by 2)

Eq. 3: C(s) + [tex]O_2[/tex](g) → [tex]CO_2[/tex](g) (multiplied by 2 and flipped)

Adding these equations together, we get:

1/2 Eq. 2 + Eq. 3: [tex]H_2[/tex](g) + C(s) + [tex]O_2[/tex](g) → [tex]H_2O[/tex](l) + [tex]CO_2[/tex](g)

Now, we can cancel out [tex]H_2O[/tex](l) on both sides by subtracting Eq. 2:

Eq. 4: [tex]CH_4[/tex](g) + 2[tex]O_2[/tex](g) → [tex]CO_2[/tex](g) + 2[tex]H_2O[/tex](l)

The enthalpy change of Eq. 4 (ΔHr∘ = -890.3 kJ) represents the desired reaction plus the enthalpy change of the formation of water.

Since we only want the enthalpy change of the first reaction, we need to subtract the enthalpy change of the formation of water.

ΔHra = ΔHr∘ - 2(ΔHro)

ΔHra = -890.3 kJ - 2(-393.5 kJ)

ΔHra = -890.3 kJ + 787 kJ

ΔHra = -103.3 kJ

Therefore, the enthalpy change for the first reaction (ΔHra) is -103.3 kJ.

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The normal boiling point of n-Buthane is at 272.66 K. Calculate
the fugacity of n-Buthane at 150 bars and the same temperature.

Answers

Once the converged value of V is obtained,

fugacity = φ × P

Where φ is the fugacity coefficient.

To calculate the fugacity of n-Butane at 150 bars and the same temperature as its normal boiling point (272.66 K), we need to use an appropriate equation of state. In this case, we can use the Peng-Robinson equation of state.

The Peng-Robinson equation of state is given by:

P = (RT / (V - b)) - (a / (V(V + b) + b(V - b)))

Where:

P is the pressure (in this case, 150 bars)

R is the gas constant (0.08314 bar·L/(mol·K))

T is the temperature (272.66 K)

V is the molar volume

a and b are parameters specific to the gas (n-Butane)

To calculate the fugacity, we need to solve for the molar volume (V) in the Peng-Robinson equation of state. However, it's important to note that this is an iterative process and requires an initial guess for the molar volume.

Let's assume an initial molar volume value of V = 1 L/mol. We can then iterate using the Peng-Robinson equation of state until we reach a converged value for V.

Here's the step-by-step calculation:

Convert the pressure from bars to Pascal:

P = 150 × 1e5 Pa

Calculate the value of a and b for n-Butane using the Peng-Robinson parameters:

For n-Butane:

a = 0.2136 × (R² × Tc² / Pc)

b = 0.0778 ×(R × Tc / Pc)

Where Tc is the critical temperature of n-Butane (about 425.2 K) and Pc is the critical pressure (about 37.96 bar).

Use the initial molar volume (V = 1 L/mol) and iterate using the Peng-Robinson equation of state until convergence is achieved. Repeat the calculation until the change in molar volume is negligible.

Once the converged value of V is obtained, calculate the fugacity using the following equation:

fugacity = φ × P

Where φ is the fugacity coefficient.

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Nitrogen oxide is one of the pollutants in automobile exhaust and can react with oxygen to form 10³ litter/mol.s (1.4 x 109 ppm2/min). Calculate the half-life of 3000 ppm NO. (Assume excess 2NO2. At 298 °K, rate constant k = 14.8 x of oxygen is consumed therefore rate of reaction depends solely on NO)

Answers

The half-life of 3000 ppm NO is 4.87 × 10⁻⁸ s.

Nitrogen oxide is one of the pollutants in automobile exhaust and can react with oxygen to form 10³ litter/mol.s (1.4 x 109 ppm2/min).

Calculate the half-life of 3000 ppm NO. (Assume excess 2NO2. At 298 °K, rate constant k = 14.8 x of oxygen is consumed therefore the rate of reaction depends solely on NO).

We need to determine the half-life of 3000 ppm NO.

Let's recall the half-life equation,

t1/2 = (0.693 / k) × (1 / [A]t - 1 / [A]0)

Here, k = 14.8 × 10³ L/mol·sAt 298 °K,

the rate of reaction depends solely on NO.

Therefore, [A]0 = 3000 ppm = 3000/10⁶ = 0.003 mol/L.

Since 2NO2 is in excess, the rate of the reaction depends on the concentration of NO, and hence

[A]t = 0.5

[A]0 = 0.5 × 0.003

= 0.0015 mol/L.

Now we can substitute all the values in the half-life equation, t1/2

= (0.693 / 14.8 × 10³ L/mol·s) × (1 / 0.0015 mol/L - 1 / 0.003 mol/L)t1/2

= (0.693 / 14.8 × 10³ L/mol·s) × (1 / 0.0015 - 1 / 0.003) mol/Lt1/2

= (0.693 / 14.8 × 10³ L/mol·s) × (666.67) mol/Lt1/2

= (0.693 / 14.8 × 10³ L/mol·s) × 666.67 mol/Lt1/2 = 3.25 × 10⁻⁵ s / 666.67t1/2

= 4.87 × 10⁻⁸ s

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Q4 This question relates the combustion reactions of acetylene, hydrogen and ethane. (a) Express the stoichiometric ecpigtions for the combustion reactions of acetylene, hydrogen and ethane with their respective standard heats of combustion obtained from physical property table. (b) Verify the standard heat of combustion of acetylene in Q4(a) by using heat of formation method. (c) The equation below shows the acerylene hydrogenation reaction: C2H2(g)+2H2(g)→C2H6(g) (i) Compute the standard heat of acetylcne hydrogenation reaction using tabulated heats of formation and heats of combustion. (ii) Verify the answer in Q4(e)(1) by using Hess's Law.

Answers

Stoichiometric equations for the combustion reactions ΔHf° (C2H2) = (2 x (-393.5)) + (-285.8) - (-1299.5) = +226.7 kJ mol-1(c) Acetylene hydrogenation reaction

Acetylene combustion reaction:C2H2 (g) + (5/2) O2 (g) → 2 CO2 (g) + H2O (l) ΔHc° = -1299.5 kJ mol-1 Hydrogen combustion reaction:2H2 (g) + O2 (g) → 2 H2O (l) ΔHc° = - 483.7 kJ mol-1Ethane combustion reaction:C2H6 (g) + (7/2) O2 (g) → 2 CO2 (g) + 3 H2O (l) ΔHc° = - 1560 kJ mol-1(b) Heat of formation method for verifying the standard heat of combustion of acetylene: The standard heat of combustion of acetylene from the heat of formation method is:ΔHc° (C2H2) = 2 ΔHf° (CO2) + ΔHf° (H2O) - 2 ΔHf° (C2H2) = -1299.5 kJ mol-1ΔHf° (CO2) = -393.5 kJ mol-1ΔHf° (H2O) = -285.8 kJ mol-1.

For verifying the answer in Q4(e)(1) using Hess's Law, we need to convert acetylene hydrogenation reaction into a combination of other reactions:Reaction 1:C2H2 (g) + (2.5) O2 (g) → 2 CO2 (g) + H2O (l) ΔH1 = -1299.5 kJ mol-1Reaction 2:2 CO2 (g) + 2.5 H2 (g) → C2H6 (g) + 5 O2 (g) ΔH2 = +1560 kJ mol-1After multiplying and adding the above equations, we get the required reaction as:C2H2 (g) + 2 H2 (g) → C2H6 (g) ΔH = -396.1 kJ mol-1.

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In a co-current flow heat exchanger, what describes best about the characteristic of the temperature? A. Exit fluid for both cold stream and hot stream become close to each other B. Cold fluid exit the heat exchanger at higher temperature C. Hot fluid exit the heat exchanger at lower temperature D. Heat from the hot fluid transferred to the cold fluid inside the heat exchanger

Answers

D. Heat from the hot fluid transferred to the cold fluid inside the heat exchanger.

In a co-current flow heat exchanger, the hot fluid enters at a higher temperature and transfers heat to the cold fluid as they flow in the same direction. As they move through the heat exchanger, heat is exchanged between the two fluids, resulting in a temperature change. The hot fluid loses heat and exits at a lower temperature, while the cold fluid gains heat and exits at a higher temperature. The characteristic of heat transfer is such that heat is transferred from the hot fluid to the cold fluid, allowing for energy exchange between the two fluids.

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What is the total number of valence electrons in the Lewis structure of XeF2? electrons 2 Draw a Lewis structure for XeF2.

Answers

The total number of valence electrons in the Lewis structure of XeF2 can be determined by adding up the valence electrons of xenon (Xe) and fluorine (F) atoms.

Xenon is in Group 18 of the periodic table, so it has 8 valence electrons.

Fluorine is in Group 17, so each fluorine atom contributes 7 valence electrons.

Total valence electrons in XeF2 = Valence electrons of Xe + Valence electrons of F atoms

                                = 8 + 2(7)

                                = 8 + 14

                                = 22

Therefore, there are 22 valence electrons in the Lewis structure of XeF2.

To draw the Lewis structure of XeF2:

1. Place the xenon atom (Xe) in the center.

2. Connect the xenon atom to two fluorine atoms (F) with single bonds.

3. Distribute the remaining valence electrons around the atoms to satisfy the octet rule (except for xenon, which can exceed the octet rule).

4. Place lone pairs on the fluorine atoms as needed to complete their octets.

5. Check that the total number of valence electrons matches the calculated value (22 in this case).

The resulting Lewis structure of XeF2 should show xenon in the center bonded to two fluorine atoms, with the remaining valence electrons distributed as lone pairs or bonding pairs around the atoms.

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l am working on alcohol( Ethanol) cell. I need to
know the best method for making ethanol cell,
what ethanols cell are? working principle,
chemistry, reactions, feasibility, life, economics,
abd comparison with other cells?

Answers

ethanol cells are fuel cells that produce electrical energy using ethanol as fuel. Ethanol cells have become the focal point of the scientific and technological fields, such as bioengineering, materials science, and nanotechnology.

Ethanols cells are fuel cells that generate electric power by converting ethanol (C2H5OH) and oxygen (O2) into carbon dioxide (CO2) and water (H2O).Ethanol (C2H5OH) is a colorless, flammable liquid. It is used in a variety of applications, including food, medical, and fuel. Ethanol has a high energy density, which makes it an ideal fuel for fuel cells. The use of ethanol in fuel cells is a significant breakthrough in renewable energy technology. Ethanol is a renewable energy source that is derived from biomass.

Ethanol can be produced from a variety of sources, including sugar cane, corn, and other plants. The use of ethanol as a fuel source is environmentally friendly and has a minimal impact on the environment. The working principle of ethanol cells is similar to that of other fuel cells. The electrochemical reaction takes place in the presence of a catalyst. In an ethanol cell, ethanol is oxidized at the anode, producing carbon dioxide, water, and electrons. At the cathode, oxygen is reduced, producing water and accepting electrons. The overall reaction is: C2H5OH + 3O2 → 2CO2 + 3H2O The feasibility of ethanol cells depends on a variety of factors, including the availability of ethanol, the cost of production, and the efficiency of the cell. Ethanol cells have a long life span and are relatively low maintenance. The economics of ethanol cells is dependent on the cost of production and the market demand. Ethanol cells are compared to other fuel cells based on their efficiency, cost, and environmental impact. Overall, ethanol cells are a promising technology for the generation of renewable energy.

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Liquid methanol goes through a change from state 1 (27 0C, 1 bar, 1.4 cm3 /g) to state 2 (T 0C, P bar and V cm3 /g). Given the values for T=17, P=0.8 and V=1.395 and also given that the isothermal compressibility is 47 x 10-6 /bar, determine methanol’s volume expansivity. Provide any necessary derivation(s) and assumptions in your solution.

Answers

The volume expansivity of methanol is approximately 0.1356 cm³/(g∙°C∙bar).

To calculate the volume expansivity (α), we will substitute the given values into the equation:

α = -1/V1 × (∂V/∂T)P × (∂T/∂P)V

Given values:

T1 = 27°C

T2 = 0°C

P1 = 1 bar

P2 = 0.8 bar

V1 = 1.4 cm³/g

V2 = 1.395 cm³/g

(∂V/∂T)P = R/V1 = 0.0821 L∙atm/(mol∙K) / 1.4 cm³/g

First, let's calculate the change in temperature and pressure:

ΔT = T2 - T1 = 0°C - 27°C = -27°C

ΔP = P2 - P1 = 0.8 bar - 1 bar = -0.2 bar

Now, we can calculate the volume expansivity (α):

α = -1/V1 × (∂V/∂T)P × (∂T/∂P)V

= -1/1.4 × (0.0821 L∙atm/(mol∙K) / 1.4 cm³/g) × (-27°C / -0.2 bar)

= 0.1356 cm³/(g∙°C∙bar)

Therefore, the volume expansivity of methanol is approximately 0.1356 cm³/(g∙°C∙bar).

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Then moving average list is calculated by initially taking the average of the first k obse a process has 3 steps, what is the reliability of the system if the reliability of each step is as follows: 0.90, 0.92, 0.92 (e) A plasma consisting of a 50-50 D-T mixture of total density n=10 nuclei per unit volume has a break even temperature of 4 keV. What is the fusion power per unit volume, PF, produced at a temperature of 10 keV? [Assume that P = Kn1/T (2/3) exp(-200/T(1/3)) where K is a constant and that the power radiated by Bremsstrahlung is given by P=1.7810nT W m where the temperature T is in units of eV in both the above formulae.] [5] 23. In a semiconductor a filled dopant level is located close to the bottom of the conductance band. What is the type of conductivity? Encircle the right answer. [1p] A. p-type B. n-type 24. Which of these elements act as donors, which as acceptors for silicon: B, As, Al, In, Sb? [1p] Donors: .. Acceptors: ...25. Where is (as a rule) the mobility of ions larger? Encircle the right answer. [1p] A. In solids B. In liquids 1) Subnetting ExerciseThe organization you work for has several departments. There is a lot of unnecessary traffic flowing between the Human Resources, Accounting, and Marketing departments. Each department has 10 to 15 computers running within it. Your task is to implement subnetting so that each of the three departments computers are placed on separate subnets, thus reducing overall traffic, as well as securing the connections between the departments. In this scenario you will use the 192.168.100.0 network. The current subnet mask is 255.255.255.0. You will need to modify this. Plan the network so that there are eight subnets in total. Specify which subnet ID each department uses and what the usable ranges of IP addresses for those subnets are. Your answers may vary from the example solution. Define the term Green Data Centre. You are assigned to design a Green Data Centre. Describe the measures that you would take to ensure that the Data Centre satisfies the environmental sustainability criteria, such as in terms of the energy consumption, GHG emission, cooling need, distance to the energy source, etc. Assess the viability of the green data centre in terms of the metric Power Usage Effectiveness (PUE). Question 14 6 pts An ice dancer with her arms stretched out starts into a spin with an angular velocity of 2.8 rad/s Her moment of inertia with her arms stretched out is 2.49kg m2. What is the difference in her rotational kinetic energy when she pulls in her arms to make her moment of inertia 1.44 kg m?? (Answer in ))