I don’t understand why I got my answer wrong

Answer:

[tex]\huge\boxed{\sf x < 4}[/tex]

Step-by-step explanation:

-4x + 7 > x - 13

Subtract x to both sides

-4x - x + 7 > -13

-5x + 7 > -13

Subtract 7 to both sides

-5x > -13 - 7

-5x > -20

Divide -5 to both sides

x < -20/-5

[tex]\rule[225]{225}{2}[/tex]

Answer:

[tex]x < \bf 4[/tex]

Step-by-step explanation:

[tex]-4x + 7 > x -13[/tex]

We have to make [tex]x[/tex] the subject of the equation:

• Subtract [tex]x[/tex] from both sides:

[tex]-4x - x + 7 > -13[/tex]

⇒ [tex]-5x + 7 > -13[/tex]

• Now subtract 7 from both sides:

[tex]-5x > -13 - 7[/tex]

⇒ [tex]-5x > -20[/tex]

• Next divide both sides by -5, and remember that dividing an inequality by a negative number reverses the inequality symbol:

[tex]x < \frac{-20}{-5}[/tex]

⇒ [tex]x < \frac{20}{5}[/tex]

⇒ [tex]x < \bf 4[/tex]

Triangle ABC was reflected over the y axis and translated 3 units down to form triangle A'B'C'.

Transformation is the movement of a point from its initial location to a new location. Types of transformations are reflection, translation, rotation and dilation.

Rigid transformation preserves the shape and size of the figure. Reflection, translation, rotation are rigid transformations.

Triangle ABC was reflected over the y axis and translated 3 units down to form triangle A'B'C'.

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Answer:

379.94

Step-by-step explanation:

3.14 x 11^2 =  379.94

The area of the given circle is 95 square ft.

Calculation for the Area of the Circle:

It is given in the diagram that,

The diameter of the circle, d = 11 ft.

Now, we know that the radius of a circle is equal to half of the diameter.

Therefore, radius of the given circle, r = 11/2 ft.

The formula for the area of the circle is given as follows,

A = π × r²

Substituting the values, π = 3.1, and r = 11/2, we get,

A = (3.14) × (11/2)²

A =  (3.14) × 30.25

A = 94.985

A ≈ 95

Hence, the area of the given circle with diameter 11 ft. comes out to be 95 ft².

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Answer:

[tex]x=6[/tex]
[tex]y=\frac{3}{4}[/tex]

Step-by-step explanation:

Given the following question:

[tex]x+4y=9[/tex]
[tex]2x-4y=9[/tex]

To solve using the elimination method we will add the two equations together to find the two individual values.

[tex]x+2x=3x[/tex]
[tex]4y-4y=0[/tex]
[tex]9+9=18[/tex]
[tex]3x=18[/tex]
[tex]\frac{3x}{3} =x[/tex]
[tex]18\div3=6[/tex]
[tex]x=6[/tex]

[tex]x+4y=9[/tex]
Substitute six in for x:
[tex]x=6[/tex]
[tex]6+4y=9[/tex]
Solve for y:
[tex]6-6=0[/tex]
[tex]9-6=3[/tex]
[tex]\frac{4y}{4} =y[/tex]
[tex]3=\frac{3}{4}[/tex]
[tex]y=\frac{3}{4}[/tex]

x is equal to 6, and y is equal to 3/4.

Hope this helps.

Answer:

437.068     28.019

Step-by-step explanation:

Not sure how to explain this one....it is what it is

  7 ones = 7

  3 tens  = 30

  4 hundreds = 400      added = 437

      No tenths = 0

       6 hudredths = .06

       8 thousandths = .008        added to   = 437.068

280 tenths =   280 * 1/10 = 28

  19   thousandths = .019                  summed = 28.019  

The solutions to the equations are x = 7/3 and y = 24/7

Linear equations are equations that have constant average rates of change, slope or gradient

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

4x + 10 = -2x + 4

y - 4(2y - 5) = -4

Considering the first equation

4x + 10 = -2x + 4

Collect the like terms

4x + 2x = 10 + 4

Evaluate the like terms, by adding them

6x = 14

Divide both sides of the equation by 6

x = 7/3

Considering the second equation

y - 4(2y - 5) = -4

Expand the bracket in the above equation

y - 8y + 20 = -4

Collect the like terms

y - 8y = -20 -4

Evaluate the like terms, by adding them

-7y = -24

Divide both sides of the equation by -7

y = 24/7

Hence, the solutions to the equations are x = 7/3 and y = 24/7

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Answer: 80% correct

Step-by-step explanation:

        If Divine got 36 correct and 9 incorrect, then we can find the total number of questions.

                 36 + 9 = 45 questions

        Now, we will divide the number of questions answered correctly by the total number of questions.

                 [tex]\displaystyle \frac{36}{45} =0.8[/tex]

        Lastly, we will multiply it by 100 to find the percentage.

                  0.8 * 100 = 80%

Answer:

80% was correct.

Step-by-step explanation:

The total number of questions is 45 (36 + 9).  The percentage is the part correct over the total.

36/45 = .8.  The answer is given in the decimal form.  To change a decimal to a percent, move the decimal two places to the right.

Answer:

m=-4

y-intercept=8

x-intercept=2

Step-by-step explanation:

Please see attachment.

y-intercept=8

The y-intercept is where the line crosses the y-axis.

x-intercept=2

The x-intercept is where the line crosses the x-axis.

m=-4

If you do not know how to find slope by looking at graph, use slope formula.

(y2-y1)/(x2-x1)

Choose 2 points. You may use the x and y intercepts.

(2,0) and (0,8)

(8-0)/(0-2)=8/-2=-4

Hope this helps!

Answer:

1. (2,2)

2. (-20, -1)

3. (4,3)

Step-by-step explanation:

See attached images

Answer:

The solutions to the sets of equations may be found by either a substitution process or by graphing and looking for the point that the two lines formed by the quations intersect.  Both approaches are described.

The "solution" to these sets of equations is the point at which the two lines intersect each other.

Step-by-step explanation:

1. 3x-y=4 and x+2y=6

x+2y=6

6x-2y=8     We can simply add these two equations since y will            disappear, leaving just x.

7x = 14  [result of addition]

x = 2    [Solve]

Since x = 2,  [Then use the solution for x to find y]

x+2y=6

(2)+2y=6

2y = 4

y = 2

(2,2) is the solution (where the lines intersect).  See attached graph.

2. 2x-y= -39 and x+y= -21

2x-y= -39

x+y= -21               Add the two equations (since the y will be eliminated)

3x = -60

x = -20

Find y:  

x+y= -21

(-20)+y= -21

y = -1

Solution is (-20,-1)

3. 2x+y =11 and 6x-5y =9

2x+y =11

-6x+-3y = -33    [Multiply by -3 and then add to other equation.  This allows us to eliminate x]

6x - 5y =   9

 -8y = - 24

y = 3

2x+y =11

2x+(3) =11

2x = 8

x = 4

Solution is (4,3)

==================

See attached graph for all the graphed solutions.

==================

The substitution process also works if we isolate one of the 2 variables in one equation and then use the resulting value in the second eqaution.  For example, in problem 1:

3x-y=4

x+2y=6

Pick either equation and isolate the x or y.  I'll pick the second equation and isolate for x:

x = 6-2y

Now use this value of x (6-2y) in the other equation:

3x-y=4

3(6-2y)-y=4

18 - 6y - y = 4

-7y = -14

y = 2

Then use y=2 to fiond x, using either equation:

x+2y=6

x+2(2)=6

x = 2

The solution is (2,2).

This same approach can be used on all these problems.  It avoids trying to visualize what can be done to an entire equation to eliminate one of the variables, but it takes a bit more paper.

All solutions are graphed in the attachment.

If the value of determinant a is 3, determinant b is 5 then the value of determinant ab is 15.

Given that the value of determinant a is 3, determinant b is 5.

We are required to find the value of determinant ab.

Determinant of a matrix is the scalar value computed for a given square matrix.It means the matrix which is not square does not have a determinant value.  It is denoted by IAI.

We know that,

IaI*IbI=IabI

So we have to just put the values in the above formula to get the determinant of ab.

IabI=3*5

=15

Hence if the value of determinant a is 3, determinant b is 5 then the value of determinant ab is 15.

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Answer:

  12% loss

Step-by-step explanation:

The selling price is the sum of the cost price and the markup. Here, the markup (profit) is expressed as a percentage of the cost price.

The relation between selling price and cost price is ...

  selling price = cost price + cost price × markup fraction

  selling price = cost price × (1 + markup fraction)

Then the original cost price is ...

  cost price = (selling price) / (1 + markup fraction)

  cost price = #1.35 / (1 +8%) = #1.25

After the change in selling price, we can find the markup fraction (profit rate) to be ...

  1 + markup fraction = (selling price)/(cost price)

  markup fraction = (selling price)/(cost price) -1

  markup fraction = #1.10/1.25 -1 = 0.88 -1 = -0.12

The trader has a 12% loss when selling the oranges at #1.10.

The expression 40 + 30m = c represents the cost of the gym membership for m months option (A) 40 + 30m = c is correct.

It is defined as the combination of constants and variables with mathematical operators.

It is given that:

The local gym is offering this new promotion:

An enrollment fee of $40 and a monthly fee of $30.

Let m be the total number of months

Total monthly fee = 30m

Total cost(including the enrollment fee of $40) = 40 + 30m

Let the total cost is c:

c = 40 + 30m

If in the linear expression, one variable is present, then the bis known as the linear expression in one variable.

Thus, the expression 40 + 30m = c represents the cost of the gym membership for m months option (A) 40 + 30m = c is correct.

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The missing length of given right triangle is equal to 1500.

A triangle is classified as a right triangle when it presents one of your angles equal to 90º.  The greatest side of a right triangle is called hypotenuse. And, the other two sides are called cathetus or legs.

The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean  Theorem.

The Pythagorean Theorem says: [tex]hypotenuse^2=(leg_1)^2+(leg_2)^2[/tex] . And the main trigonometric ratios are: sin (x),  cos (x) and tan (x) , where:

[tex]sin(x)=\frac{opposite\ side}{hypotenuse} \\ \\ cos(x)=\frac{adjacent\ side}{hypotenuse} \\ \\ tan (x)= \frac{opposite\ side}{adjacent\ side}[/tex]

There is another important property, where h²=m*n. See the attached image.

From the previous informations presented, you can solve the given question.

Thus, if h²=m*n. You can write:

h²=900*1600

[tex]h=\sqrt{1440000}\\ \\ h=1200[/tex]

If h=1200, you can find x from Pythagorean  Theorem.

x²=1200²+900²

x²=1440000+810000

x²=2250000

x=[tex]\sqrt{2250000}[/tex]

x=1500

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Answer:

Periodicity of 2cos(3x-2π)=

[tex] \frac{2\pi}{3} [/tex]

Step-by-step explanation:

[tex]periodicity \: of \: 2 \cos(3x - 2\pi) \\ periodicity \: of \: a. \cos(bx + c) + d = \\ \frac{periodicity \: of \: \cos(x) }{|b|} \\ periodicity \: of \: \cos(x) \: is \: 2\pi = \frac{2\pi}{|3|} \\ simplify = \frac{2\pi}{3} [/tex]

Answer:

[tex]\sf Period=\dfrac{2}{3} \pi[/tex]

Step-by-step explanation:

The cosine function is periodic, meaning it repeats forever.

Standard form of a cosine function

f(x) = A cos(B(x + C)) + D

where:

Given function:

y = 2 cos (3x - 2π)

Therefore:

Period of given function:

[tex]\sf \implies Period=\dfrac{2 \pi}{B} = \dfrac{2 \pi}{3}[/tex]

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This is voluntary response bias. The result overestimates true support for firing the coach.

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The degrees of freedom for a chi-square test applied to a cross-tabulation with 5 rows and 2 columns is equal to 6

The given parameters are:

Rows = 5

Column = 2

The degrees of freedom is then calculated as:

df = Rows + Column - 1

Substitute the known values in the above equation

df = 5 + 2 - 1

Evaluate the expression

df = 6

Hence, the degrees of freedom for a chi-square test applied to a cross-tabulation with 5 rows and 2 columns is equal to 6

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Answer:

(x + 6, y + 1)

Step-by-step explanation:

Just look at 1 point of ABCD. For example, look at point D.

Point D must become point F.

When you reflect ABCD over the x-axis, point D will end up at (-1, -2).

Now it has to be translated to (5, -1).

For x to go from -1 to 5, you need to add 6.

For y to go from -2 to -1, you need to add 1.

Answer: (x + 6, y + 1)

Answer:

x = 4

Step-by-step explanation:
1.Distribute

2. Subtract 2 from both sides
3. Simplify
4. Divide both sides by same factor

5. Simplify
x = 4

Answer: 4

Step-by-step explanation:

We have to try getting x by itself to solve for it. Since we have two sides that are equal to each other, we can add, subtract, multiply, and divide anything on both sides to try to isolate x.

[tex]2(x+1)=10[/tex]

We can first divide the left side and the right side by 2. This would remove the 2 being multiplied on the outside.

[tex]\frac{2(x+1)}{2}=\frac{10}{2}\\x+1=10\div 2\\x+1=5[/tex]

Now, we have a + 1 on the left side that we need to remove to get x by itself. If we are adding something, we can remove that by subtracting the same thing. Hence, we can subtract 1 from both sides to remove the + 1.

[tex]x+1=5\\x+1-1=5-1\\x+0=4\\x=4[/tex]

After all that simplifying, we get that x equals 4.

Answer:

I would use equation d

Step-by-step explanation:

because need to find out X which is the second section so you would do 60 subtract 35 which gives 25 so X would be 25 .

I hope this helped . if you need any more help pls ask :)

pls give brainliest if you like my answer :)

Answer:

Below in bold.

Step-by-step explanation:

f(x) = x(18x + 4)

f(x) = 18x^2 + 4x

Antiderivative = 18 * (x^2+1)/(2 + 1) -+4x(1+1) / (1+1) + C

                        =  18x^3 / 3 + 4x^2 / 2 + C

                         = 6x^3 + 2x^2 + C.

Checking by differentiating:

f'(x) = 6*3 x^(3-1) + 2*2x^(2-1)

      =  18x^2 + 4x

      =  x(18 -+4)

Considering the situation described, it can be graphed by the first function.

Cities A, B and C are on a straight line.

Hence, the first graph is the correct one for this problem.

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Answer:

  24 m depth

Step-by-step explanation:

The quadratic function modeling depth will have zeros at x=1 and x=12, the distances in meters from the boat where the diver is at the surface.

The factored form of a quadratic function can be written as ...

  y = a(x -p)(x -q)

where p and q are zeros of the function. The value 'a' is a vertical scale factor.

Here, we are given y=0 at the surface, at points where x=1 and x=12. This means the function can be written as ...

  y = a(x -1)(x -12)

To find the value of 'a', we can use the maximum depth value. That depth will be halfway between the function zeros, at x = (1+12)/2 = 6.5

  -30.25 = a(6.5 -1)(6.5 -12)

  30.25 = 5.5²·a = 30.25a   ⇒   a=1

Then the function modeling the diver's depth in meters is ...

  y = (x -1)(x -12)

And the depth at x=4 will be ...

  y = (4 -1)(4 -12) = 3(-8) = -24 . . . . meters

The diver's depth is 24 meters when she is 4 m away from the boat.

The bags of candy that was sold is 6

The bags of cookies that was sold is 10.

$8.50c + $4.50o = 79 equation 1

o - c = 6

o = 6 + c  equation 2

Where:

Substitute for o in equation 1 using equation 2

$8.50c + $4.50(6 + c) = 79

$8.50c + 27 + 4.50c = 79

$8.50c + 4.50c = 79 - 27

$13c = 52

c = 52 / 13

c = 4

Substitute for c in equation 2

0 = 6 + 4 = 10

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The height of the painting in the scale drawing is 10 centimeters if the height of the real painting is 35 inches given that in a scale drawing of a painting, 2 centimeters represents 7 inches. This can be obtained by using the ratio of scale drawing to the real drawing.

Here in the question it is given that,

Thus we can say that, scale of the painting is 2 cm : 7 in

Ratio of scale drawing and real painting is 2 : 7

⇒ Similarly here height of the painting in the scale drawing to the height of the painting in the real drawing will be in the ratio 2 : 7.

We can say that,

2 cm/7 in = x cm/35 in

where x is the height of the painting in the scale drawing

2 cm × 35 in /7 in = x cm

x = 2 × 5 cm

x = 10 cm

Hence the height of the painting in the scale drawing is 10 centimeters if the height of the real painting is 35 inches given that in a scale drawing of a painting, 2 centimeters represents 7 inches.

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Answer:

0 < x ≤ 10 and 0 < y ≤ 20.

Step-by-step explanation:

I did the test and got it right ma bois.

Answer: Its A

Step-by-step explanation:

The cost of the pecan cheesecake and one apple cheesecake are $11 and $17.

According to the statement

we have given that the Sumalee sold 6 pecan cheesecakes and 12 apple

cheesecakes for a total of $270. Julio sold 12 pecan cheesecakes and 9 apple cheesecakes for a

total of $285.

And we have to find that the cost each of one pecan cheesecake and one apple cheesecake.

So, for this purpose,

Let x be the cost of each pecan cheesecake.

and y be the cost of each one apple cheesecake.

Then The equation become

6x + 12y = 270  -(1)

12x + 9y = 285  -(2)

From elimination method

multiply (1) by 12 and (2) by 6 then

72x + 144y = 3240

72x + 54y = 1710

Now eliminate x from them then the equation become

90y = 1530

here y = 17

then the x become

6x + 12y = 270  

6x + 12(17) = 270  

6x = 270-204

6x = 66

and x become 11.

So, The cost of the pecan cheesecake and one apple cheesecake are $11 and $17.

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P(A and B) expressed in the simplest form is (B) 2/21.

To express P(A and B) in the simplest form:

Therefore, P(A and B) expressed in the simplest form is (B) 2/21.

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The complete question is given below:

A bag contains 4 black tiles, 5 white tiles, and 6 blue tiles. Event A is defined as drawing a black tile from the bag on the first draw, and event B is defined as drawing a white tile on the second draw.

If two tiles are drawn from the bag, one after the other without replacement, what is P(A and B) expressed in the simplest form?

A. 4/45

B. 2/21

C. 4/15

D. 5/14

Step-by-step explanation:

there are 4 suit with 13 cards each

Taking into account the definition of a system of linear equations, 240 stamps are in Will’s collection.

A system of linear equations is a set of two or more equations of the first degree, in which two or more unknowns are related.

Solving a system of equations consists of finding the value of each unknown so that all the equations of the system are satisfied. That is to say, the values ​​of the unknowns must be sought, with which when replacing, they must give the solution proposed in both equations.

In this case, a system of linear equations must be proposed taking into account that:

On the other hand, you know that:

So, the system of equations to be solved is

[tex]\left \{ {{30=\frac{1}{3}C } \atop {W=2(C+30)}} \right.[/tex]

There are several methods to solve a system of equations, it is decided to solve it using the substitution method, which consists of clearing one of the two variables in one of the equations of the system and substituting its value in the other equation.

Solving the first equation:

30= [tex]\frac{1}{3}[/tex]C

30÷[tex]\frac{1}{3}[/tex]= C

90= C

Substituting the value in the second equation:

W= 2(90 + 30)

W= 2×120

W=240

Finally, 240 stamps are in Will’s collection.

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