I NEED HELP ASAP PLEASE

Answer:

_

3.126

Step-by-step explanation:

Bar notation is a way in Mathematics to write decimal number that are repetiting or infinite.

Bar notation symbol is – is placed above the first decimal number that repeats itself. It is easier than writing the same repeating number and over again. It tells us that this particular number with the bar over it, is repeated continuously till infinity

From the above question, we were asked to write 3.126666666666... using Bar notation

_

3.126666666666... = 3.126

The bar is placed over the digit 6

Answer:

-2a - 3

Step-by-step explanation:

bº equals 1 due to the zero exponent.

Thus, -2a-3 bº simplifies to -2a - 3.

Answer:

−2/a^3  

Step-by-step explanation:

Answer:

choice 1,2,4,5 from top to bottom

Step-by-step explanation:

1:the points given are in the line where both planes intersect

2:point H is not on any plane

3:in the diagram point F is on plane R so false

4:if you connect the points given they will intersect so not collinear

5:the points F and G are on the plane R

6:so F is on plane R but H is not on any do false

Answer:

when each side length of a cube increases by 1 unit, the volume increases by 3x² + 3x + 1 (units)³

Step-by-step explanation:

Let the initial length of the sides of the cube = x unit

when the length of the cube = x ;  volume of the cube = length × breadth × height = x × x × x = x³ (unit)³

when the length increased by 1 unit,

new length = (x + 1) unit

New volume = (x + 1) × (x + 1) × (x + 1)

multiplying the first two brackets

New volume = (x² + 2x + 1 ) (x + 1)

espanding the brackets

New volume = x³ + 2x² + x + x² + 2x + 1

New volume = x³ + 3x² + 3x + 1 (unit)³

Change in volume:

(New volume) - (old volume)

(x³ + 3x² + 3x + 1) - (x³)

x³ + 3x² + 3x + 1 - x³

collecting like terms:

(x³ - x³) + 3x² + 3x + 1

0 + 3x² + 3x + 1

change in volume = 3x² + 3x + 1

Therefore, when each side length of a cube increases by 1 unit, the volume increases by 3x² + 3x + 1 (units)³

Answer:

  linear with a common first difference of 2

Step-by-step explanation:

On the face of it, you can reject answers that ascribe a common ratio to a linear or quadratic function. (A common ratio is characteristic of an exponential function.)

You can also reject the answer that ascribes a common first difference to a quadratic function. (A quadratic function has a common second difference.)

After you reject the nonsense answers, there is only one remaining choice. It is also the correct one:

  linear with a common first difference of 2

_____

The ratio of change in y to change in x is ...

  (0 -(-2))/(-2 -(-3)) = 2

  (4 -0)/(0 -(-2)) = 2

  (12 -4)/(4 -0) = 2

That is, y increases by 2 when x increases by 1. The common first difference is 2.

Answer:

x = 12

Step-by-step explanation:

3(x–6)=18

x-6 = 18:3

x-6 = 6

x = 6+6

x = 12

Answer:

x=12

Step-by-step explanation:

Answer:

1 dz  to make 12 muffins

1 7/24 dz to make 15.5 muffins

Step-by-step explanation:

How many dozen (dz) eggs are needed to make 12 muffins?

See answer options, we are looking for an option with dz indicated along with the number:

The correct option is:

So 1 dozen of eggs required for 12 muffins, that is 12 eggs for 12 muffins or 1 egg for 1 muffin or 1/12 dz per muffin

To get 15.5 muffins:

Or in dozens:

Answer:

A. 0,2,0,2

Step-by-step explanation:

Firstly, Insert 1-4 into [tex]u^n=1+(-1)^n[/tex]

[tex]u^1=1+(-1)^1\\1+(-1)1=0\\\\\\\\u^2=1+(-1)^2\\\\1+1=2\\\\\\u^3=1+(-1)^3\\\\1+(-1)^3=0\\\\\\\\u^4=1+(-1)^4\\\\1+(-1)^4=2\\[/tex]

Simple explanation, for the first number.

-1+1=0

For the second number we are saying, -1*-1=1

and then 1+1=2

For the third number we are saying, -1*-1*-1=-1

-1+1=0

For the fourth number we are saying, -1*-1*-1*-1=1

1+1=2

true false false true...is the quick answer

Remember that negatives are always less than positive numbers.

Answer:

x = -6,3,15,-12; y = 11,5,-3,15

Step-by-step explanation:

Domain is the x value, so plugged in the x values into the equation and got the y values or range.

Answer:

 x:  y:

-6  11

3       5

15 -3

-12    15

Answer:

let x be y

NOW,

X+6Y=6

Y+6Y=6

7Y=6

Y=0.87

Answer:

4.25, 4.5, 4.75, 5.00, 5.25, 5.5, 5.75, 6.00

Step-by-step explanation:

it is an arithmetic sequence with common difference 0.25

Answer:

you could stand at 5.0 ft and still be completely in the shadow of the tree

Step-by-step explanation:

From the diagram attached below;

We consider;

[tex]\overline {BC}[/tex] to be the height of the tree and [tex]\overline {DE}[/tex] to be the height of how tall you could be and still be completely in the shadow of the tree.

∠D = ∠B = 90°

Also;

ΔEAD = ΔBAC   (similar triangles)

Therefore, their sides will also be proportional

i.e

[tex]\dfrac{\overline {DE}}{ \overline {BC}}= \dfrac{\overline{AD}}{ \overline{AC}}[/tex]

[tex]\dfrac{x}{ 45}= \dfrac{225-220}{225}[/tex]

[tex]\dfrac{x}{ 45}= \dfrac{25}{225}[/tex]

By cross multiply

225x = 45 × 25

[tex]x = \dfrac{45 \times 25}{225}[/tex]

[tex]x = \dfrac{1125}{225}[/tex]

x = 5.0 ft

Therefore, you could stand at 5.0 ft and still be completely in the shadow of the tree

Answer:

Hey there!

True. You use individuals rules, pieces of evidence, and experimentally found ideas that can be combined to form a general mathematical statement.

Let me know if this helps :)

Answer:

  an isosceles right triangle

Step-by-step explanation:

The square of the length of a side can be found from the distance formula:

  d^2 = (x2-x1)^2 +(y2-y1)^2

The square of the length of WX is ...

  WX^2 = (-3-(-10))^2 +(-1-4)^2 = 49+25 = 74

The square of the length of XY is ...

  XY^2 = (-5-(-3))^2 +(11-(-1))^2 = 4 +144 = 148

The square of the length of YW is ...

  YW^2 = (-10-(-5))^2 +(4 -11)^2 = 25 +49 = 74

The sum of the squares of the short sides is equal to the square of the long side, so this is a right triangle. The squares of the short sides are equal, so this is an isosceles right triangle.

Answer:

We conclude that prenatal cocaine exposure is associated with lower scores of four-year-old children on the test of object assembly.

Step-by-step explanation:

We are given that the 190 children born to cocaine users had a mean of 7.3 and a standard deviation of 3.0 The 186 children not exposed to cocaine had a mean score of 8.2 with a standard deviation of 3.0.

Let [tex]\mu_1[/tex] = population mean score for children born to cocaine users.

[tex]\mu_2[/tex] = population mean score for children not exposed to cocaine.

So, Null Hypothesis, : = 490      {means that the prenatal cocaine exposure is not associated with lower scores of four-year-old children on the test of object assembly}

Alternate Hypothesis, : 490     {means that the prenatal cocaine exposure is associated with lower scores of four-year-old children on the test of object assembly}

The test statistics that will be used here is Two-sample t-test statistics because we don't know about population standard deviations;

                               T.S.  =  [tex]\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex]  ~ [tex]t__n_1_+_n_2_-_2[/tex]

where, [tex]\bar X_1[/tex] = sample mean score of children born to cocaine users = 7.3

[tex]\bar X_2[/tex] = sample mean score of children not exposed to cocaine = 8.2

[tex]s_1[/tex] = sample standard deviation for children born to cocaine users = 3

[tex]s_2[/tex] = sample standard deviation for children not exposed to cocaine = 3

[tex]n_1[/tex] = sample of children born to cocaine users = 190

[tex]n_2[/tex] = sample of children not exposed to cocaine = 186

Also, [tex]s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }[/tex]  = [tex]\sqrt{\frac{(190-1)\times 3^{2}+(186-1)\times 3^{2} }{190+186-2} }[/tex] = 3

So, the test statistics =   ~

                                     =  -2.908

The value of t-test statistics is -2.908.

Now, at a 0.05 level of significance, the t table gives a critical value of -1.645 at 374 degrees of freedom for the left-tailed test.

Since the value of our test statistics is less than the critical value of t as -2.908 < -1.645, so we have sufficient evidence to reject our null hypothesis as the test statistics will fall in the rejection region.

Therefore, we conclude that prenatal cocaine exposure is associated with lower scores of four-year-old children on the test of object assembly.

In the null hypothesis, a test always forecasts no effect, while the alternate theory states the research expectation impact, and calculation as follows:

Calculating the pooled estimator of [tex]\sigma^2[/tex], denoted by [tex]S^2_p[/tex], is defined by

[tex]\to \bold{S^2_p= \frac{(n_1 - 1) S^2_1+ (n_2 - 1)S^2_2}{n_1 + n_2 - 2}}[/tex]

Null hypothesis:

[tex]\to H_0 : \mu_1 - \mu_2 = \Delta_0\\[/tex]

Test statistic:

[tex]\to T_0=\frac{\bar{X_1}- \bar{X_2} -\Delta_0}{S_p \sqrt{\frac{1}{n_1}+\frac{1}{n_2}}} \\\\[/tex]

Alternative Hypothesis:

[tex]H_1 : \mu_1 -\mu_2 \neq \Delta_0\\\\ H_1 : \mu_1 -\mu_2 > \Delta_0\\\\H_1 : \mu_1 -\mu_2 < \Delta_0\\\\[/tex]

Rejection Criterion

[tex]t_0 > t_{\frac{\alpha}{2} , n_1+n_2 -2}\ \ \ or\ \ \ t_0 < - t_{\frac{\alpha}{2} , n_1+n_2 -2} \\\\t_o > t_{\alpha , n_1+n_2 -2} \\\\t_o > -t_{\alpha , n_1+n_2 -2}[/tex]

Given value:

[tex]\to S_p=9\\\\\to \Delta_0=0\\\\\to t_0=-\frac{0.9}{3(\sqrt{(\frac{1}{190}+\frac{1}{186})})}=-2.9\\\\\to t_{0.05,374}=1.645\\\\[/tex]

here

[tex]\to t_0 < -t_{0.05,374}[/tex]

hence rejecting the [tex]H_0[/tex]

Since there should be enough evidence that prenatal cocaine exposure is linked to inferior item assembly scores in 4-year-olds.

Find out more about the alternative hypothesis here:

brainly.com/question/18831983

=========================================

Explanation:

Subtracting a negative is the same as adding. Example: 2-(-3) = 2+3 = 5.

So (x+y)-(-z) is the same as x+y+z. We can group up terms inside parenthesis and it won't change the result. Meaning that x+y+z is the same as any of the following below

We could also swap the order of either x, y or z, and still have the same result.

Answer:

219.80 feet

Step-by-step explanation:

Tan 20= 80/b

Tan 20= 0.363970234266

(0.363970234266)b=80

b= 219.80 feet

The distance between the sculpture and the bottom of the building is required.

The distance between the building and sculpture is 219.80 feet.

[tex]\theta[/tex] = Angle of depression = Angle of elevation = [tex]20^{\circ}[/tex]

p = Height of building = 80 feet

b = Required length

From the trigonometric ratios we have

[tex]\tan\theta=\dfrac{p}{b}\\\Rightarrow b=\dfrac{p}{\tan\theta}\\\Rightarrow b=\dfrac{80}{\tan 20}\\\Rightarrow b=219.80\ \text{feet}[/tex]

Learn more about trigonometry:

https://brainly.com/question/23899312

Answer:

bgd=cgd+cgb

agf=cgd

50=cgd

cgd=50

bgd=90

so cgd=50

bgc=40

bgd=90

Answer:

C  90-degrees

Step-by-step explanation:

Using alternate interior angles, you can say m<CGD = 50 degrees.

From here, using the fact that line BE is a bisector of line CF, we know that the sum of degrees of the line BE would be 180 degrees.

So we can say m<EGD + m<CGD + m<BGC = 180.  Plug in our known values.

90 + 50 + m<BGC = 180

m<BGC = 40

And we can see that m<BGD = m<BGC + m<CGD

Thus, m<BGD = 40 + 50 = 90.

So the m<BGD = 90 degrees.

Cheers.

Answer:

a = 9

Step-by-step explanation:

3a - 27 = 0

3a = 27

a = 27/3

a = 9

3*9  -  27 = 0

27 - 27 = 0

Answer:

a = 9

Step-by-step explanation:

3a-27=0

Add 27 to each side

3a = 27

Divide by 3

3a/3 = 27/3

a = 9

Answer:

[tex]\boxed{345,600 mL}[/tex]

Step-by-step explanation:

Hey there!

Well first we need to find the amount of seconds in a day,

24hrs in a day * 60 min in an hour

= 1440 minutes in a day

1440 min • 60 secs in a minute

= 86,400 seconds in a day

So now we do 2*86400 = 172800

172800 mL in a day

172800 * 2

= 345600 mL in 2 days

Hope this helps :)

Answer:

4.5

Step-by-step explanation:

2/8=x/18

Answer:

4.5 cups

Step-by-step explanation:

first you set up the problem like servings/cups. This would look like 8/2. Then you add the 18 servings and make it a cross multiplication problem. The expression would look like 8/2=18/x. You cross multiply and get 8x=36. Divide by 8 and get x=4.5 cups.

Answer:

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

Area of rectangle = l × w

where

l is the length

w is the width

From the question

The length is twice its width is written as

l = 2w

Substitute this into the formula for finding the area of the rectangle

Area = 200 yd²

200 = 2w²

Divide both sides by 2

w² = 100

Find the square root of both sides

width = 10cm

Substitute this value into l = 2w

That's

l = 2(10)

length = 20cm

Perimeter of the rectangle is

2(20) + 2(10)

= 40 + 20

Hope this helps you

Answer:

Determination of the least cost of fence enclosure:

= cost of heavy-duty one side of the length plus cost of remaining three sides of the fence

= $416 ($360 + $56)

= $416

Step-by-step explanation:

Rectangular Fence Area = 320 square yard

Since fence is rectangular, the two sides are length and width

Length of rectangular is always greater than the width

Length cannot be 20 yard with width as 16 yard

Therefore, length = 40 yard and width = 8 yard.

Proof: Area of a rectangular = 40 x 8 = 320 square yard

Since, parameter = 2 (Length + Width)

= 2 x (40 + 8)

= 96 yards

Therefore, along one side with heavy-duty material is one length side of the fence = 40 yard

Cost of the one length with heavy-duty material = 40 x $9 = $360

Remaining three sides = 96 - 40 = 56 yard

Cost of remaining three sides = 56 x $1 = $56

Total cost of fencing = $416 ($360 + $56)

The correct question is;

Calculate the derivative of the function. Then find the value of the derivative as specified:

f(x) = 5x + 9; f '(2)

A) f'(x) = 0; f'(2) = 0

B) f'(x) = 9; f '(2) = 9

C)f'(x) = 5; f'(2) = 5

D) f '(x) = 5x; f '(2) = 10

Answer:

Option C: f'(x) = 5 and f '(2) = 5

Step-by-step explanation:

We want to find the derivative of f(x) = 5x + 9.

Now, the derivative with respect to x will be;

f'(x) = 5

Now,we also want to find out f'(2)

This means we are to put 2 for x in the derivative function.

In the derivative function, we don't have x as we have just 5.

Thus,f'(2) = 5

Answer:

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

Step-by-step explanation:

Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.

In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.

Answer:

150

Step-by-step explanation:

70% of 500 people are adults and the remainder are children.

There are 150 children

Answer:

D. E(y) = ?0 + ?1x1 + ?2x12 + ?3x2 + ?4x1x2 + ?5x12x2

Step-by-step explanation:

Quantitative variables are measured in terms of numbers, and figures. Independent variables are those which are reason for change in other variables. Dummy variables are numerical that represents categorical data. The range of these variables is small and they can take on only two quantitative values.

Answer:

Section I test scores are more dispersed that that of section II.

Step-by-step explanation:

Consider the data collected from the arithmetic test given to two sections of a school.

Section I: Mean = 45, Standard  Deviation = 6.5

Section II: Mean = 45,  Standard deviation = 3.1

The mean of both the sections are same, i.e. 45.

So there is no comparison that can be made from the center of the distribution.

The standard  deviation for section I is 6.5 and the standard  deviation for section II is 3.1.

The standard deviation is a measure of dispersion, i.e. it tells us how dispersed the data is from the mean or how much variability is present in the data.

The standard  deviation for section I is higher than that of section II.

So, this implies that section I test scores are more dispersed that that of section II.