I need help pleaseeee

I Need Help Pleaseeee

Answers

Answer 1
Answer is:
9.8df+5.8dg+13.1fg
Assuming you add both numbers together for each side of the triangle.

Related Questions

In a triangle ABC, if a=16m c=14m b=19m. Find the angles​

Answers

Step-by-step explanation:

went to a calculator

it said

Angle ∠A = 55.543°

Angle ∠B = 78.28°

Angle ∠C = 46.177

I do not understand any of this

Answers

Answer:

to get the slope. take the change of y axis value divide by the change of x axis value

Find the equation of a quadratic function in general form whose graph has points: (-2, 3) (0, 3) and (-4,-5).

Try your best to show complete work & explain your strategy.

Answers

Answer:

-x²-2x+3

Step-by-step explanation:

The first thing I noticed is that the first and second point has the same y intercept despite being only 2 x coordiantes away. This must mean that the vertex's x coordiante is probably (-1,4)

Because the vertex is probably (-1,4) the graph must also be concave down because the point (-4,-5) is below it

writing this in vertex form we get

-a(x+1)²+4

Where a is some constant

solve for a by plugging in (0,3)

3= -a(0+1)²+4

3= -a+4

-1= -a

a=1

therefore the equation looks like

-(x+1)²+4

expanding this so that it's in stantard form...

-(x²+x+x+1)+4

-x²-2x+3

which is the final answer

Here are the first five terms of a sequence. 4, 11, 22, 37, 56 Find an expression, in terms of , for the th term of this sequence.

Answers

Answer:

[tex] a_n = 2n^2 + n + 1 [/tex]

Step-by-step explanation:

4, 11, 22, 37, 56

11 - 4 = 7

22 - 11 = 11

37 - 22 = 15

56 - 37 = 19

After the first difference, 11 - 4 = 7, each difference is 4 more than the previous difference.

Difference of differences:

11 - 7 = 4

15 - 11 = 4

19 - 15 = 4

Since we need the difference of differences to find a constant, this must be a second degree function.

[tex] a_1 = 4 = 2^2 + 1(0)[/tex]

[tex] a_2 = 11 = 3^2 + 2 = 3^2 + 2(1) [/tex]

[tex] a_3 = 22 = 4^2 + 6 = 4^2 + 3(2) [/tex]

[tex] a_4 = 37 = 5^2 + 12 = 5^2 + 4(3) [/tex]

[tex]a_5 = 56 = 6^2 + 20 = 6^2 + 5(4)[/tex]

[tex] a_n = (n + 1)^2 + (n)(n - 1) [/tex]

[tex] a_n = (n + 1)^2 + (n)(n - 1) [/tex]

[tex] a_n = n^2 + 2n + 1 + n^2 - n [/tex]

[tex] a_n = 2n^2 + n + 1 [/tex]

What is the volume of the cone to the nearest whole number?

Answers

Answer:

the volume of the cone is 60

Step-by-step explanation:

12×5=60

In the diagram, the length of segment QV is 15 units. What is the length of segment TQ?

Answers

Answer:

14 units is the answer

Step-by-step explanation:

^_^^_^^_^^_^^_^

I need someone to please explain how to turn this into a simplified fraction. (NOTE: please explain!!) __ 3.541 The repeating sign is only above the 41, not the five

Answers

the way to do these recurring decimals is by firstly separating the repeating part or recurring part and then multiply it by some power of 10 so we move it to the left, lemme show

[tex]3.5\overline{41}\implies \cfrac{35.\overline{41}}{10}\qquad \stackrel{\textit{say that the repe}\textit{ating part is }~\hfill }{x = \overline{0.41}\qquad \qquad \textit{so that }35.\overline{41}=35+\overline{0.41}=35+x}[/tex]

now, let's multiply that repeating part by some power of 10 that moves the 41 to the left, well, we have two repeating decimals, 4 and 1, so let's use two zeros, namely 100 or 10², thus

[tex]100\cdot x = 41.\overline{41}\implies 100x - 41+\overline{0.41}\implies 100x = 41+x\implies 99x=41 \\\\\\ \boxed{x =\cfrac{41}{99}}\qquad \qquad \textit{so then we can say that}~~\cfrac{35.\overline{41}}{10}\implies \cfrac{35+\frac{41}{99}}{10} \\\\\\ \cfrac{~~\frac{3506}{99}~~}{10}\implies \cfrac{~~\frac{3506}{99}~~}{\frac{10}{1}}\implies \cfrac{3506}{99}\cdot \cfrac{1}{10}\implies \cfrac{3506}{990}\implies \blacktriangleright \stackrel{\textit{which simplifies to}}{\cfrac{1753}{495}} \blacktriangleleft[/tex]

Write an equation for the quadratic graphed below: x-intercepts: (-1,0) and (4,0); y-intercept: (0,1)

Answers

Answer:

y = (1/4)x² - (5/4)x + 1

Step-by-step explanation:

The x-intercepts of the quadratic equation are simply it's roots.

Thus, we have;

(x + 1) = 0 and (x - 4) = 0

Now, formula for quadratic equation is;

y = ax² + bx + c

Where c is the y intercept.

At y-intercept: (0,1), we have;

At (-1,0), thus;

0 = a(1²) + b(1) + 1

a + b = -1 - - - (1)

At (4,0), thus;

0 = a(4²) + b(4) + 1

16a + 4b = -1

Divide both sides by 4 to get;

4a + b = -1/4 - - - (2)

From eq 1, b = -1 - a

Thus;

4a + (-1 - a) = -1/4

4a - 1 - a = -1/4

3a - 1 = -1/4

3a = 1 - 1/4

3a = 3/4

a = 1/4

b = -1 - 1/4

b = -5/4

Thus;

y = (1/4)x² - (5/4)x + 1

Find the value of cos H rounded to the nearest hundredth, if necessary

Answers

Answer:

0.6

Step-by-step explanation:

cos H = GH/FH

FH^2=20^2+15^2

FH^2=400+225=625

FH=25

cos H= 15/25=3/5=0.6

Answer:  0.6

===========================================================

Explanation:

Before we can apply a trig ratio, we need to find the length of the hypotenuse. Use the pythagorean theorem.

a^2 + b^2 = c^2

c^2 = a^2 + b^2

c = sqrt(a^2 + b^2)

c = sqrt(15^2 + 20^2)

c = 25

The hypotenuse is 25 units long, which is the length of segment FH.

Now we can find the cosine ratio

cos(angle) = adjacent/hypotenuse

cos(H) = GH/FH

cos(H) = 15/25

cos(H) = 3/5

cos(H) = 0.6

Which is expression is equivalent to (x^-4y/x^-9y^5)^-2

Answers

Answer:

[tex]\frac{y^8}{x^{10}}[/tex]

Step-by-step explanation:

Given

[tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex]

Required

The equivalent

Apply law of indices to the inner bracket

[tex](x^{-4--9}y^{1 -5})^{-2}[/tex]

[tex](x^{5}y^{-4})^{-2}[/tex]

Rewrite as:

[tex]\frac{1}{(x^{5}y^{-4})^2}[/tex]

Expand

[tex]\frac{1}{(x^{5*2}y^{-4*2})}[/tex]

[tex]\frac{1}{(x^{10}y^{-8})}[/tex]

Apply law of indices

[tex]\frac{y^8}{x^{10}}[/tex]

Use a trigonometric ratio to find the value of x. Round your answer to the nearest tenth.

Answers

I believe it’s 7 but I don’t think it is

Find the length of side xx in simplest radical form with a rational denominator.

Answers

Answer:

Solution given:

it is a right angled isosceles triangle

so

perpendicular [p]=base[b]=3

hypotenuse [h]=x

we have

by using Pythagoras law

p²+b²=h²

3²+3²=h²

18=h²

h=[tex]\sqrt{18}[/tex]

x=[tex]\bold{3\sqrt{2}}[/tex]

Simplify the radical (180°.

Answers

Answer:

radical is sqrt we find 180 sqrt root

Step-by-step explanation:

first we write sqrt 180

sqrt 180 = ?

we can choose first two letters

18 are two letters

4^2 + 2 = 18

so first + third number choose

4 , 2 are number choose

4 + 2 sqrt (4+2-1)

6 sqrt 5

sqrt 180 = 6sqrt 5

Find the measure of the indicated angle

Answers

I think the answer is 23

Answer:

67°

Step-by-step explanation:

he sum of the first two terms of a G.P is 27 whereas the sum of the second and third term is 54. Find the first term and the common ratio.​

Answers

Answer:

[tex]{ \tt{sum = \frac{a(r {}^{n - 1} )}{n - 1} }} \\ 27 = \frac{a(r {}^{2 - 1} )}{2 - 1} \\ { \bf{27 = ar - - - (i)}} \\ \\ 54 = \frac{a( {r}^{3 - 1} )}{3 - 1} \\ { \bf{108 = a {r}^{2} - - - (ii) }} \\ { \tt{(ii) \div (i) : }} \\ r = \frac{108}{27} \\ { \bf{common \: ratio = 4}} \\ { \bf{first \: term = \frac{27}{4} }}[/tex]

i need help multiplying these radicals:) there’s two: A) and B)

Answers

Answer:

Step-by-step explanation:

Well lets start with

(3*sqrt 2+ 1)(2*sqrt 3-4)

Lets multiply everything in the second parenthesis by 3*sqrt 2

2 sqrt 3 * 3 sqrt 2 =  6 sqrt 6

-4*3 sqrt 2 =  -12 sqrt 2

Now lets multiply everything by 1

1*2 sqrt 3 = 2 sqrt 3

1*-4 = -4

we have

-4  -12 [tex]\sqrt{2}[/tex]  +  6 [tex]\sqrt{6}[/tex]  + 2 [tex]\sqrt{3}[/tex]  as the awnser to problem A

Now lets do problem b

We can start by multiplying everything in the second parenthesis by 2

2*5=10

2*-1 *sqrt 3 = -2 sqrt 3

Now multiply everything in the second parenthesis by 2sqrt3

2sqrt 3 * 5 = 10 sqrt 3

2 sqrt 3 * -1* sqrt3 =  -6

Our final awnser is

10-6 +10 sqrt 3 -2 sqrt 3 ->  4+ 8 [tex]\sqrt{3}[/tex]

The awnser to question B is 4+ 8 [tex]\sqrt{3}[/tex]

pls give brainliest

A bag contains 13 blue marbles, 12 red marbles, 6 yellow marbles, and 8 green marbles. What is the probability of picking a red marble, putting that one back and then picking another red marble?

Answers

Answer:

(12/39) * (12/39) or 16/169

Step-by-step explanation:

How can you represent 1/2 on a 10-by-10 grid?

Answers

Answer:

Represent 1/2 by covering 50 squares.

Step-by-step explanation:

There are 100 squares in a 10-by-10 grid.

1/2 of 100 is 50, so you should cover 50 squares out of 100 squares.

Martin was selling tickets for a basketball game in a high school. He sold 1,250 tickets and the total amount collected for the game was $2,750. The student tickets cost $2 each, and adult tickets cost $3 each. How many student and adult tickets were sold?

Answers

Answer:

x = number of students tickets = 1,000

y = number of adults tickets = 250

Step-by-step explanation:

Let

x = number of students tickets

y = number of adults tickets

x + y = 1,250 (1)

2x + 3y = 2,750 (2)

Multiply (1) by 2

x + y = 1,250 (1) * 2

2x + 2y = 2,500 (3)

2x + 3y = 2,750 (2)

Subtract (3) from (2) to eliminate x

3y - 2y = 2,750 - 2,500

y = 250

Substitute y = 250 into (1)

x + y = 1,250

x + 250 = 1,250

x = 1,250 - 250

x = 1,000

x = number of students tickets = 1,000

y = number of adults tickets = 250

number of ways you can wear 10 outfits to school each day in a 5 day week

Answers

Answer:

1 day=10outfits

5days=10outfits×5

=50outfits

Step-by-step explanation:

hope this is helpful

Based on the calculation, you can wear the 10 outfits in 50 different ways throughout the week.

How to calculate the number of ways

To calculate the number of ways you can wear 10 outfits to school each day in a 5-day week, you need to consider the total number of outfits across all days. Since there are 10 outfits and 5 days, the total number of outfit combinations can be calculated by multiplying the number of outfits per day by the number of days:

10 outfits/day × 5 days = 50 outfit combinations

Therefore, you can wear the 10 outfits in 50 different ways throughout the week.

Learn more about permutations

https://brainly.com/question/4658834

#SPJ2

Dairy cows at large commercial farms often receive injections of bST (Bovine Somatotropin), a hormone used to spur milk production. Bauman et al. (Journal of Dairy Science, 1989) reported that 12 cows given bST produced an average of 28.0 kg/d of milk. Assume that the standart deviation of milk production is 2.25 kg/d. (a) Find a 99% confidence interval for the true mean milk production. Round your answers to two decimal places (e.g. 98.76).

Answers

Answer:

The 99% confidence interval for the true mean milk production is between 26.33 kg/d and 29.67 kg/d.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 2.575\frac{2.25}{\sqrt{12}} = 1.67[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 28 - 1.67 = 26.33 kg/d.

The upper end of the interval is the sample mean added to M. So it is 28 + 1.67 = 29.67 kg/d.

The 99% confidence interval for the true mean milk production is between 26.33 kg/d and 29.67 kg/d.

The owner of a coffee shop compared the amount of hot coffee per day, in fluid ounces, sold and the daily high temp. In degrees f per day, 5.9x+850=

Answers

The question is not complete as the scatter plot is missing.

Thus, I have attached the complete question showing the scatter plot.

Answer:

D: On a day with a high temperature of 0°C, the shop can expect to sell about 850 fluid ounces of hot coffee

Step-by-step explanation:

From the attached image showing the question and scatter plot, we can see that the scatter plot is modeled by the line; y = -5.9x + 850

Where;

x is the high temperature in °F

y is the amount of fluid ounces sold

Let's try x = 0°F

Thus;

y = 0 + 850

y = 850 fluid ounces

Let's try x = 10°F

Thus;

y = -5.9(10) + 850

y = 850 - 59

y = 791

This means for every increase in temperature of 10°F, the amount sold is approximately 60 fluid ounces lesser.

Looking at the options in the attached file, the only correct one that corresponds to our answer is option D where it says;. On a day with a high temperature of 0°C, the shop can expect to sell about 850 fluid ounces of hot coffee

(X, Y) satisfy the equation? JW Is (-94,-5) a solution to the equation y = x + 89? yes no​

Answers

Answer:

si

Step-by-step explanation:

si  :v

Answer:

yes

Step-by-step explanation:

y = x + 89

-5 = -94 + 89

-5 = -5

Determine the area of the triangle.
223.6 square units
248.7 square units
447.1 square units
458.4 square units

Answers

Answer:

223.6 square units. or 223.569 square units

Answer:A

Step-by-step explanation:I took the test

(X^2+3)^2 - (x^2-1)^2

Answers

Answer:

8(X^2+1)

Step-by-step explanation:

(X²+3)²-(X²-1)

(X²+3)(X²+3)-(X²-1)(X²-1)

X⁴+3X²+3X²+9-(X⁴-X²-X²+1)

X⁴+6X²+9-(X⁴-2X²+1)

X⁴+6X²+9-X⁴+2X²-1

8X²+8

Twice a number minus 25 is less than 89. Translate it into an inequality and find the solution

Answers

Answer:

2x-25<89

x<57

Step-by-step explanation:

2x-25<89

2x<89+25

2x<114

Divide by 2...

x<57

Hope this helped! Please mark brainliest :)

Which of the following is an example of an exponential equation?
y=(3x)^2
y=x/2
y=x^4
y=2(3)^x

Answers

Answer:

Option D

Step-by-step explanation:

y = 2(3)^x is the example of exponential equation.

What is the largest prime factor of the factorial 49!?

Answers

Answer:

13

Step-by-step explanation:

i just know

Answer:

,

Step-by-step explanation:

,

The distance traveled (in meters) by a frog is modeled by the equation d=2t where d is the distance traveled in meters and t is the time in minutes. Find the distance traveled in 25 minutes.

Answers

Given,

d = 2t

here, t = 25

Therefore,

d = 2*25

= 50m

4(1\:-\:2b)\:+\:7b\:-\:10
[tex]4(1\:-\:2b)\:+\:7b\:-\:10[/tex]

Answers

Answer:

-6 -b

Step-by-step explanation:

I have attached the explanation above. hopefully this will help you

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