I NEED HELP SOLVING THESE EQUATIONS PLEASEEE

The minimal sum for the expression using a Karnaugh map is y'z + x'y'z.

To find the minimal sum for the expression using a Karnaugh map, we first need to rewrite the expression in complete sum-of-product form:

yz + xy'z + x'y'z

Now let's create a Karnaugh map for the expression. Since there are three variables (x, y, and z), we'll create an 8-cell Karnaugh map. Next, we'll fill in the map based on the given expression. We'll place 1s in the cells corresponding to the minterms in the expression.

Now we can find groups of adjacent 1s in the Karnaugh map. Let's start with the largest group possible, which is a group of 4 adjacent 1s.

There is no group of 4 adjacent 1s in the map. Next, we'll check for groups of 2 adjacent 1s.There is one group of 2 adjacent 1s in the top right and one in the bottom right. We can combine these two groups to form a single group of 2 adjacent 1s.

The simplified expression can be obtained by finding the minimal sum of products from the groups:

y'z + x'y'z

Therefore, the minimal sum for the expression using a Karnaugh map is y'z + x'y'z.

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The circumference of the circle to the nearest tenth is 18.2 cm.

The circumference is the distance around a circle. We can calculate the circumference using either the diameter or radius of a circle.

Given,

Circumference of the circle:

[tex]=\sf2\pi r[/tex]

[tex]=2\times3.14\times2.9[/tex]

[tex]=6.28\times2.9[/tex]

[tex]\sf = 18.212\thickapprox\bold{18.2 \ cm}[/tex]

Hence, 18.2 cm is the required circumference of the circle rounded to nearest tenth.

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The formula for the circumference of a circle is:

C = 2πr

where C is the circumference, π (pi) is a mathematical constant approximately equal to 3.14, and r is the radius of the circle.

Given a radius of 2.9 inches, we can substitute this value into the formula and calculate the circumference:

C = 2πr

C = 2 × 3.14 × 2.9

C ≈ 18.18

Rounding to the nearest tenth, we get:

C ≈ 18.2

Therefore, the circumference of the circle with a radius of 2.9 inches is approximately 18.2 inches.

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To sketch the resultant force (r), we need to add two or more forces vectorially. We can then calculate the magnitude and angle of the resultant force (r) using trigonometry and the Pythagorean theorem.

Let's assume that we have two forces F1 and F2 acting on the object at different angles.To sketch the resultant force (r), we need to have two or more forces acting on an object.

To determine the resultant force (r), we need to add the two forces vectorially. This means that we need to draw the two forces as vectors, with their tails meeting at the same point. The resultant force (r) will then be the vector that connects the tail of the first force to the head of the second force.Once we have sketched the resultant force (r), we can calculate its magnitude and angle. The magnitude of the resultant force can be calculated using the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In this case, the two sides are the x and y components of the resultant force (r). The x and y components can be calculated using trigonometry, where the angle between the resultant force and the x-axis is known. Once we have calculated the x and y components, we can use the Pythagorean theorem to find the magnitude of the resultant force (r). The angle of the resultant force can be calculated using inverse trigonometric functions, such as the arctan function.

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We can use the properties mentioned above  : Geometry Unit 10: Circles Homework 7. :1. AP = AQ , 2. ∠APO = ∠AQO = 90°

To find the value or measure of the given problem, we must consider the properties of tangent segments and circles.

Recall that tangent segments to a circle from an external point are congruent, meaning they have equal lengths. Additionally, a tangent line forms a right angle (90°) with the radius at the point of tangency.

Now, let's assume we are given a circle with center O and two tangent segments, AP and AQ, from an external point A. Since both segments are tangent to the circle,

Using these properties, we can find the value or measure of the unknown quantities in the problem. Please provide the specific problem details for a more accurate and precise answer.

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To find the area of a region under the standard normal curve, the following information would typically be provided in the question:

1. The specific boundaries or limits of the region: The question should provide the z-scores or values that determine the starting and ending points of the region of interest. For example, it could specify "Find the area under the standard normal curve between z = -1.5 and z = 2.0."

2. The type of region: The question might specify whether the desired area is for a specific tail (e.g., "Find the area to the left of z = 1.8") or for a specific interval (e.g., "Find the area between z = -0.5 and z = 1.2").

3. Clear instructions or context: The question should provide sufficient context or instructions to ensure a clear understanding of what area needs to be found. It could specify a particular percentage or probability associated with the region, or it could relate to a specific problem or scenario where finding the area under the standard normal curve is necessary.

By providing these details, the question enables you to determine the appropriate steps to calculate the area using methods such as z-tables, statistical software, or mathematical formulas.

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Angle A( angle WXY) must be an Blunt angle, the cosine of an blunt angle is negative.          

The angles of triangle WXY must be true, we can  dissect the given side lengths using the Law of Cosines. The Law of Cosines states that in a triangle, the forecourt of one side is equal to the sum of the places of the other two sides minus twice their product, multiplied by the cosine of the included angle.  Let's denote angle WXY as angle A, angle WYX as angle B, and angle XYW as angle C. According to the Law of Cosines, we have  WX2 =  WY2 XY2- 2 * WY * XY * cos( A)  132 =  152 102- 2 * 15 * 10 * cos( A)  169 =  225 100- 300 * cos( A)  69 = -300 * cos( A)  cos( A) = -69/ 300  the cosine of an angle is a value between-1 and 1, we can conclude that-69/ 300 is within this range. thus, angle A( angle WXY) must be an blunt angle. This is because the cosine of an blunt angle is negative.

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The greatest number of bags required to pack the items such that 10 bags remain empty is 2,400 bags.

To find the greatest number of bags required to pack the items such that 10 bags remain empty, we need to determine the number of items in each bag.

Let's assume the number of items in each bag is x.

The total number of bottles of sanitizer is 240, the total number of face shields is 480, and the total number of masks is 600.

We can set up the following equations based on the given information:

Number of bags for sanitizers: 240 / x

Number of bags for face shields: 480 / x

Number of bags for masks: 600 /x

Since the number of bags for each item type must be equal, we can set them equal to each other:

240 / x = 480 / x = 600 / x

To find the greatest number of bags, we need to find the least common multiple (LCM) of the three fractions.

The LCM of 240, 480, and 600 is 2,400.

So, x = 2,400.

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The amount of candy that costs $1. 80 per pound that she will be able to use would be = 107 candies.

The mass of candy that Miss Ann has selected = 80 pounds

The cost of each pound of the candy = $2.40 per pound

The cost of the selected candy by its mass = 80×2.4 = $192

But the amount of candy that cost $1.80 per pound she will be able to make = 192/1.8 = 107 (approximately)

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The greatest Integer that belongs to the interval (-∞, 8) is 7, as it is the largest whole number that is less than 8 within the given interval.

1. The greatest integer that belongs to the interval [-1, 17), we need to determine the largest whole number that is less than or equal to 17. In this case, the interval includes -1 but does not include 17.

The greatest integer in the interval [-1, 17) is 16.

To clarify, the greatest integer that belongs to the interval [-1, 17) is 16 because it is the largest whole number that is less than 17 and also within the specified interval.

2. For the interval (-∞, 8), the range extends from negative infinity to 8, where negative infinity is not an actual number but rather represents the concept of going infinitely in the negative direction. In this interval, we are looking for the largest integer that is less than 8.

The greatest integer in the interval (-∞, 8) is 7.

Since the interval does not include 8 and extends infinitely in the negative direction, the largest integer within this interval is 7.

the greatest integer that belongs to the interval (-∞, 8) is 7, as it is the largest whole number that is less than 8 within the given interval.

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The length of AB is approximately 8.602 units, and the length of A'B' is approximately 7.211 units.

To find the coordinates of A' when the line segment is dilated from the origin by a factor of 2, we can multiply the coordinates of A by 2.

Coordinates of A: (x₁, y₁) = (-2, 3)

Coordinates of A' = (2 * x₁, 2 * y₁) = (2 * (-2), 2 * 3) = (-4, 6)

Therefore, the coordinates of A' are (-4, 6).

To find the coordinates of B, we can observe the graph and read the coordinates directly.

Coordinates of B: (x₂, y₂) = (3, -4)

Therefore, the coordinates of B are (3, -4).

Next, we need to find the length of AB using the distance formula:

Length of AB = √((x₂ - x₁)² + (y₂ - y₁)²)

            = √((3 - (-2))² + (-4 - 3)²)

            = √((3 + 2)² + (-4 - 3)²)

            = √(5² + (-7)²)

            = √(25 + 49)

            = √74

            ≈ 8.602 (rounded to the nearest three decimal places)

Finally, we need to find the length of A'B' using the distance formula:

Length of A'B' = √((x₂' - x₁')² + (y₂' - y₁')²)

              = √((-4 - 0)² + (6 - 0)²)

              = √((-4)² + 6²)

              = √(16 + 36)

              = √52

              ≈ 7.211 (rounded to the nearest three decimal places)

Therefore, the length of AB is approximately 8.602 units, and the length of A'B' is approximately 7.211 units.

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The normal distribution is a specific distribution having a characteristic bell-shaped form.

The specific distribution that has a characteristic bell-shaped form is called the normal distribution. It is a continuous probability distribution that is symmetric around the mean. In a normal distribution, the majority of the data falls close to the mean, with fewer data points found further away from the mean towards the tails.

The normal distribution is important in statistics because many natural phenomena and processes follow this distribution, such as heights and weights of people, IQ scores, and errors in measurements.

The normal distribution has several properties that make it useful in statistical analysis, including the central limit theorem, which states that the sum of many independent and identically distributed random variables tends to follow a normal distribution.

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The equations which represent a linear function are

c) y = -3x - 1

d) y = ( 1/2 ) x

Given data ,

Let the linear equations be represented as A

Now , the value of A is

a)

y = -3x - 1

Now , the equation is of the linear form , where slope m = -3

And , the y-intercept is b = -1

So , it is a linear function

b)

y = ( 1/3 )x

Now , the equation is of the linear form , where slope m = (1/3_

And , the y-intercept is b = 0

So , it is a linear function

Hence , the linear functions are solved

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The Excel command/formula that can be used to find the t-value such that the area under the tio curve to its right is 0.975 is T.INV(0.025;10) and the correct option is b. T.INV(0,025; 10).

T.INV(Probability, Deg_freedom) finds the t-value that is the result of a probability value.

Probability is the area under the curve, and the deg_freedom is the degrees of freedom. When using a one-tailed test, T.INV(0.025,10) function returns the t-value for a probability of 0.025 and degrees of freedom of 10 such that the area under the curve to its right is 0.975.

T.INV is an inbuilt function in excel. The function requires two arguments, one for the probability and the other for the degrees of freedom. The function returns the t-value of a given probability and degrees of freedom.

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In the given problem, we have u = (4, 0, -4) and v = (4, 7, 8). The inner product u, v is defined as 2u1v1 + 3u2v2 + u3v3. To find the values of u, v, u, v, and d(u, v), let's calculate them step by step.

First, let's calculate u, v:

The inner product u, v = 2u1v1 + 3u2v2 + u3v3

      = 2(4)(4) + 3(0)(7) + (-4)(8)

      = 32 + 0 + (-32)

      = 0

Next, let's calculate u:

u = ||u|| = sqrt(u, u)

     =[tex]\sqrt{2u1^2 + 3u2^2 + u3^2}[/tex]

     = [tex]\sqrt{(2(4)^2 + 3(0)^2 + (-4)^2)}[/tex]

     = 4√3

Similarly, let's calculate v:

v = ||v|| = sqrt(v, v)

     = [tex]\sqrt{2v1^2 + 3v2^2 + v3^2}[/tex]

     = [tex]\sqrt{2(4)^2 + 3(7)^2 + (8)^2)}[/tex]

     = 9√3

Finally, let's calculate d(u, v):

d(u, v) = ||u - v|| = sqrt((u - v), (u - v))

               = [tex]\sqrt{(u1 - v1)^2 + (u2 - v2)^2 + (u3 - v3)^2}[/tex]

               = ([tex]\sqrt{(4 - 4)^2 + (0 - 7)^2 + (-4 - 8)^2}[/tex])

               = [tex]\sqrt{193}[/tex]

In summary, u, v = 0, u = 4√3, v = 9√3, and d(u, v) = square root of(193).

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Answer:

h(x) will be continuous on [0,5] when the value of

k= 4

Step-by-step explanation:

For making h(x) continuous we need to ensure that the functions, kx and x+3 should meet at the point x=1.

For continuity, the left-hand limit and the right-hand limit of h(x) to be equal at x = 1.

Left-hand limit:

lim(x→1-) h(x) = lim(x→1-) kx = k(1) = k

Right-hand limit:

lim(x→1+) h(x) = lim(x→1+) (x + 3) = 1 + 3 = 4

The function to be continuous at x = 1, the left-hand limit and right-hand limit must be equal. Therefore, we need k = 4.

Therefore, for h(x) to be continuous on [0, 5], the value of k must be 4.

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Therefore, the value of k that makes h(x) continuous on [0,5] is k = 4

We have been given a piecewise-defined function h(x) that needs to be continuous on [0, 5]. We have to determine the value of k that will make h(x) continuous. Let's begin by checking if the function is continuous at

x = 1. lim h(x)

as x approaches 1 from the left (i.e., from the interval [0,1)) is equal to

h(1-) = k(1) = k. lim h(x)

as x approaches 1 from the right (i.e., from the interval [1,5]) is equal to

h(1+) = 1+3 = 4.

For the function to be continuous at x = 1, h(1-) must be equal to h(1+), i.e., k = 4. Therefore, the value of k that makes h(x) continuous on [0,5] is k = 4. The value of k that makes h(x) continuous on [0,5] is k = 4.

Therefore, the value of k that makes h(x) continuous on [0,5] is k = 4

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The series ∑(n=2)^∞ (1/n²) is convergent.

To determine the convergence or divergence of the series, we can use the p-series test. The p-series test states that if we have a series of the form ∑(n=1)^∞ (1/[tex]n^p[/tex]), then the series converges if p > 1 and diverges if p ≤ 1.

In the given series, we have ∑(n=2)^∞ (1/n²), which can be written as ∑(n=1)^∞ (1/n²) with the first term (1/1²) removed. This series is a specific case of the p-series where p = 2. Since 2 is greater than 1, according to the p-series test, the series converges.

The convergence of the series ∑(n=2)^∞ (1/n²) can also be verified using the integral test. The integral test states that if a function f(x) is continuous, positive, and decreasing on the interval [1, ∞), and if f(n) = a(n), then the series ∑(n=1)^∞ a(n) converges if and only if the improper integral ∫(1 to ∞) f(x) dx converges.

In this case, the function f(x) = 1/x² satisfies the conditions of the integral test. Integrating f(x) over the interval [1, ∞) gives us ∫(1 to ∞) 1/x²dx = [-1/x] from 1 to ∞, which equals 0 - (-1) = 1. Since the integral is finite and positive, the series converges.

Therefore, both the p-series test and the integral test confirm that the series ∑(n=2)^∞ (1/n²) is convergent.

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Answer:

Difference = Surface Area_small - Surface Area_large ≈ 63.72 cm^2 - 85.39 cm^2 ≈ -21.67 cm^2

Step-by-step explanation:

Radius of the larger hollow ball (r_outer) = 3 cm

For the smaller hollow balls, since they are identical, we assume that the outer and inner radii are the same:

Radius of the smaller hollow balls (r_inner) = r_outer/2 = 3 cm / 2 = 1.5 cm

Now, let's calculate the surface area for both cases:

Surface area of the larger hollow ball:

Surface Area_large = 4π(r_outer^2 - r_inner^2)

Surface Area_large = 4π(3^2 - 1.5^2)

Surface Area_large = 4π(9 - 2.25)

Surface Area_large = 4π(6.75)

Surface Area_large ≈ 85.39 cm^2

Surface area of the smaller hollow balls (each):

Surface Area_small = 4π(r_outer^2 - r_inner^2)

Surface Area_small = 4π(1.5^2 - 0.75^2)

Surface Area_small = 4π(2.25 - 0.5625)

Surface Area_small = 4π(1.6875)

Surface Area_small ≈ 21.24 cm^2

Now, let's compare the surface areas:

The total surface area of the three smaller hollow balls = 3 * Surface Area_small ≈ 3 * 21.24 cm^2 ≈ 63.72 cm^2

Therefore, it takes more paint to paint the three smaller hollow balls compared to the larger hollow ball. The difference in surface area is given by:

Difference = Surface Area_small - Surface Area_large ≈ 63.72 cm^2 - 85.39 cm^2 ≈ -21.67 cm^2

The difference is negative because the surface area of the larger hollow ball is greater than the combined surface area of the three smaller hollow balls.

The point C shows the 13 miles in the given graph.

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

Given that On Friday, Leo walked 13 miles.

We have to find the points from A-E which shows this to complete the line graph.

According to the given graph, the point C shows the distance which is 13 miles of friday.

Hence, the point C shows the 13 miles in the given graph.

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Answer:

terms - 4

variables - x,y

coefficients - 5,2,3

constants - 1/2

The distance between each pair of points given on the bottom and right edge is given below.

Using Distance formula

d = √(a-c)² + (b-d)²

1. (8, 0) and (4, 7)

= √(4-8)² + (7-0)²

= √4² +7²

= √65

(2, -6) and (4, -12)

= √(4-2)² + (-12 + 6)²

= √2² + 6²

= √40

= 2√5

2. (-3, 2) and (1, 6)

= √4² + 4²

= 4√2

(-3, 4) and (-6, 6)

= √3² + 2²

= √13

3. (9.5) and (0, -1)

= √9² + 6²

= √117

(3,-6) and(- 7, - 2)

= √4² + 4²

= 4√2

4. (-3.8) and (6,8)

= √3² + 0²

= 3

(8, 7) and (2,9)

= √6² + 2²

= 2√5

5. (10.-8) and (-7.-6)

= √17² + 2²

= √293

(10, - 10) and (2, 6)

= √8² + 16²

= √320

Thus, the edges does not match with the sides given.

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To find the length of the vector x = -4e1 + 5e2 - 4e3 - 5e4 + 4e5 + 2e6, denoted as ||x||, we can use the formula:

||x|| = sqrt((x1)^2 + (x2)^2 + (x3)^2 + (x4)^2 + (x5)^2 + (x6)^2),

where x1, x2, x3, x4, x5, and x6 are the coefficients of the vector x in terms of the standard basis vectors e1, e2, e3, e4, e5, and e6.

Plugging in the values, we have:

||x|| = sqrt((-4)^2 + (5)^2 + (-4)^2 + (-5)^2 + (4)^2 + (2)^2)

Simplifying the equation:

||x|| = sqrt(16 + 25 + 16 + 25 + 16 + 4)

||x|| = sqrt(102)

Therefore, the length of the vector x is sqrt(102).

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Answer:

25) $6.15

26) 300

Step-by-step explanation:

25)

p(k) = 1600/(k + 20)

p(240) = 1600/(240 + 20)

p(240) = 1600/260

p(240) = 6.15

Answer: $6.15

26)

p(k) = 5

p(k) = 1600/(k + 20)

5 = 1600(k + 20)

5(k + 20) = 1600

5k + 100 = 1600

5k = 1500

k = 300

Answer: 300

The Maclaurin polynomials of orders n = 0, 1, 2, 3, and 4 can be obtained by expanding the function around x = 0 using the Taylor series. Here they are:

Order n = 0:

P0(x) = f(0)

Order n = 1:

P1(x) = f(0) + f'(0)x

Order n = 2:

P2(x) = f(0) + f'(0)x + (f''(0)x^2)/2

Order n = 3:

P3(x) = f(0) + f'(0)x + (f''(0)x^2)/2 + (f'''(0)x^3)/6

Order n = 4:

P4(x) = f(0) + f'(0)x + (f''(0)x^2)/2 + (f'''(0)x^3)/6 + (f''''(0)x^4)/24

Note that f'(0) represents the derivative of the function evaluated at x = 0, f''(0) represents the second derivative evaluated at x = 0, and so on.

These polynomials can be used to approximate the function near x = 0. The higher the order of the polynomial, the closer the approximation to the actual function.

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The equation 3(2d-1) - 2d = 4(d-2+5)  Isolate the variable 'd' on one side of the equation ,has no solution.

The equation 3(2d-1) - 2d = 4(d-2+5), we will simplify and

Step 1: Distribute the multiplication on the left side:

6d - 3 - 2d = 4(d - 2 + 5)

Simplifying, we have:

4d - 3 = 4(d + 3)

Step 2: Distribute the multiplication on the right side:

4d - 3 = 4d + 12

Step 3: Move the variables to one side and the constants to the other side:

4d - 4d = 12 + 3

Simplifying, we have:

0 = 15

Step 4: Conclusion:

We have obtained the equation 0 = 15, which is not a true statement. This means that there is no solution to the equation. The original equation is inconsistent and does not have a valid value for 'd' that satisfies the equation

Therefore, the equation 3(2d-1) - 2d = 4(d-2+5) has no solution.

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Answer:

u just have to apply formula for slope i.e tan£= perpendicular height / horizontal length

Main Answer:The approximate probability is 0.033

Supporting Question and Answer:

How do we calculate the expected average and standard deviation for a sample?

To calculate the expected average and standard deviation for a sample, we need to consider the characteristics of the population and the sample size.

Body of the Solution:

a) To find the expected average amount of the waiter's tips, we can use the fact that the mean of the sample means is equal to the population mean. Since the mean of the tips is given as 7 dollars, the expected average amount of his tips is also 7 dollars.

b) The standard deviation for the average amount of the waiter's tips, also known as the standard error of the mean, can be calculated using the formula:

Standard deviation of the sample means

= (Standard deviation of the population) / sqrt(sample size)

In this case, the standard deviation of the population is given as 2 dollars, and the sample size is 30. Plugging these values into the formula, we have:

Standard deviation of the sample means = 2 / sqrt(30) ≈ 0.365

Therefore, the standard deviation for the average amount of the waiter's tips is approximately 0.365 dollars.

c) To find the approximate probability that the average amount of the waiter's tips is less than 6 dollars, we can use the Central Limit Theorem, which states that for a large sample size, the distribution of sample means will be approximately normal regardless of the shape of the population distribution.

Since the sample size is 30, which is considered relatively large, we can approximate the distribution of the sample means to be normal.

To calculate the probability, we need to standardize the value 6 using the formula:

Z = (X - μ) / (σ / sqrt(n))

where X is the value we want to standardize, μ is the population mean, σ is the population standard deviation, and n is the sample size.

Plugging in the values, we have:

Z = (6 - 7) / (2 / sqrt(30)) ≈ -1825

Using a standard normal distribution table or a calculator, we can find the probability associated with this z-score. The approximate probability that the average amount of the waiter's tips is less than 6 dollars is approximately 0.033.

Final Answer:Therefore, the approximate probability is 0.033, accurate to three decimal places.

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The approximate probability is 0.033

To calculate the expected average and standard deviation for a sample, we need to consider the characteristics of the population and the sample size.

a) To find the expected average amount of the waiter's tips, we can use the fact that the mean of the sample means is equal to the population mean. Since the mean of the tips is given as 7 dollars, the expected average amount of his tips is also 7 dollars.

b) The standard deviation for the average amount of the waiter's tips, also known as the standard error of the mean, can be calculated using the formula:

Standard deviation of the sample means

= (Standard deviation of the population) / sqrt(sample size)

In this case, the standard deviation of the population is given as 2 dollars, and the sample size is 30. Plugging these values into the formula, we have:

Standard deviation of the sample means = 2 / sqrt(30) ≈ 0.365

Therefore, the standard deviation for the average amount of the waiter's tips is approximately 0.365 dollars.

c) To find the approximate probability that the average amount of the waiter's tips is less than 6 dollars, we can use the Central Limit Theorem, which states that for a large sample size, the distribution of sample means will be approximately normal regardless of the shape of the population distribution.

Since the sample size is 30, which is considered relatively large, we can approximate the distribution of the sample means to be normal.

To calculate the probability, we need to standardize the value 6 using the formula:

Z = (X - μ) / (σ / sqrt(n))

where X is the value we want to standardize, μ is the population mean, σ is the population standard deviation, and n is the sample size.

Plugging in the values, we have:

Z = (6 - 7) / (2 / sqrt(30)) ≈ -1825

Using a standard normal distribution table or a calculator, we can find the probability associated with this z-score. The approximate probability that the average amount of the waiter's tips is less than 6 dollars is approximately 0.033.

Therefore, the approximate probability is 0.033, accurate to three decimal places.

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The probability that all three students walk to school is 1/496.

Probability is the likelihood of a desired event happening. It is expressed as a number between 0 and 1, where 0 indicates that the event is impossible and 1 indicates that the event is certain.

The probability of an event can be calculated using the following formula:

Probability = Favorable Outcomes / Total Outcomes

total number of students = 32

number of students that walk to school = 5

Selection of three students that walk to school without replacement:

probability of 1st selection = 5/32

probability of 2nd selection = 4/31

probability of 3rd selection = 3/30

probability that all three students walk to school = 5/32 * 4/31 * 3/30 = 1/496

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i) (6, 4) and (6, -2)

j) (-5, 2) and (7.-7) This two distance and midpoint are not pairs of points.

To find the distance and midpoint between each pair of points, we'll use the distance formula and the midpoint formula. The distance formula is given by:

Distance =[tex]sqrt((x2 - x1)^2 + (y2 - y1)^2)[/tex]

And the midpoint formula is given by:

Midpoint = ((x1 + x2)/2, (y1 + y2)/2)

Let's calculate the distance and midpoint for each given pair of points:

a) The distance between (0, 5) and (0, -6) is:

Distance =[tex]√((x2 - x1)^2 + (y2 - y1)^2)[/tex]

= [tex]√((0 - 0)^2 + (-6 - 5)^2)[/tex]

= √(0 + 121)

= √121

= 11

The midpoint between (0, 5) and (0, -6) is:

Midpoint = ((x1 + x2) / 2, (y1 + y2) / 2)

= ((0 + 0) / 2, (5 + -6) / 2)

= (0, -0.5)

b) The distance between (3, 0) and (-4, 0) is:

Distance =[tex]√((x2 - x1)^2 + (y2 - y1)^2)[/tex]

= [tex]√((-4 - 3)^2 + (0 - 0)^2)[/tex]

= [tex]√((-7)^2 + 0)[/tex]

= √49

= 7

The midpoint between (3, 0) and (-4, 0) is:

Midpoint = ((x1 + x2) / 2, (y1 + y2) / 2)

= ((3 + -4) / 2, (0 + 0) / 2)

= (-0.5, 0)

c) The distance between (5, 2) and (7, 6) is:

Distance = [tex]√((x2 - x1)^2 + (y2 - y1)^2)[/tex]

= [tex]√((7 - 5)^2 + (6 - 2)^2)[/tex]

= [tex]√(2^2 + 4^2)[/tex]

= √(4 + 16)

= √20

= 2√5

The midpoint between (5, 2) and (7, 6) is:

Midpoint = ((x1 + x2) / 2, (y1 + y2) / 2)

= ((5 + 7) / 2, (2 + 6) / 2)

= (6, 4)

d) The distance between (-3, 4) and (1, -3) is:

Distance = [tex]√((x2 - x1)^2 + (y2 - y1)^2)[/tex]

= [tex]√((1 - (-3))^2 + (-3 - 4)^2)[/tex]

= [tex]√((1 + 3)^2 + (-7)^2)[/tex]

= [tex]√(4^2 + 49)[/tex]

= √(16 + 49)

= √65

The midpoint between (-3, 4) and (1, -3) is:

Midpoint = ((x1 + x2) / 2, (y1 + y2) / 2)

= ((-3 + 1) / 2, (4 + (-3)) / 2)

= (-1, 0.5)

e) The distance between (6, 4) and (2, 1) is:

Distance = [tex]√((x2 - x1)^2 + (y2 - y1)^2)[/tex]

= [tex]√((2 - 6)^2 + (1 - 4)^2)[/tex]

=[tex]√((-4)^2 + (-3)^2)[/tex]

= √(16 + 9)

= √25

f) (-2, -4) and (3, 8):

Distance =[tex]sqrt((3 - (-2))^2 + (8 - (-4))^2)[/tex] = [tex]sqrt(5^2 + 12^2[/tex]) = sqrt(25 + 144) = sqrt(169) = 13

Midpoint = ((-2 + 3) / 2, (-4 + 8) / 2) = (0.5, 2)

g) (0, 0) and (5, 10):

Distance =[tex]sqrt((5 - 0)^2 + (10 - 0)^2)[/tex]= [tex]sqrt(5^2 + 10^2)[/tex] = sqrt(25 + 100) = sqrt(125) = 5√5

Midpoint = ((0 + 5) / 2, (0 + 10) / 2) = (2.5, 5)

h) Distance: [tex]√((2 - 4)^2 + (1 - 0)^2[/tex]) = [tex]√((-2)^2 + (1)^2)[/tex] = √(4 + 1) = √5

Midpoint: ((2 + 4)/2, (1 + 0)/2) = (6/2, 1/2) = (3, 1/2)

i) (6, 4) and (6, -2)

j) (-5, 2) and (7.-7) This two distance and midpoint are not pairs of points.

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Answer: d O(-6,4)

Step-by-step explanation: