A. The total force acting on the plane during take-off is 563,140 N. This is calculated by multiplying the thrust of each engine (281,570 N) by the number of engines (2).
What is engine?An engine is an mechanical device that converts energy into useful work, typically in the form of rotational force. Engines are used in a variety of applications, from cars and airplanes to power plants and generators.
b. The acceleration the plane experiences during take-off can be calculated using Newton's Second Law of Motion, which states that Force = Mass x Acceleration. Therefore, the acceleration is 563,140 N / 369,000 kg = 1.53 m/s2.
c. To calculate the time it takes the plane to reach take-off speeds, we can use the kinematic equation for average acceleration, which states that the time taken is equal to the change in velocity (76 m/s) divided by the acceleration (1.53 m/s2). Therefore, the time taken is 49.8 seconds.
d. Using the kinematic equation for displacement, we can calculate the displacement the plane covers during take-off. This equation states that displacement is equal to the initial velocity (0 m/s) multiplied by the time taken (49.8 seconds) plus one-half of the acceleration (1.53 m/s2) multiplied by the time taken squared (49.8 seconds x 49.8 seconds). Therefore, the displacement is 3,814.7 m.
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an inquisitive physics student and mountian climber climbs a 41.9 m cliff that overhangs a calm pool of water. he throws two stones vertically downward, 1.45 s apart and observes that they cause a single splash. the first stone has an initial velocity of 2 m/s. how long after release of the first stone do the two stones hit the water?
An inquisitive physics student and mountain climber climbs a 41.9 m cliff that overhangs a calm pool of water. It takes 2.996 seconds for the stone to hit the water.
We set [tex]y_i = 0[/tex] at the top of the cliff, and find the time interval required for the first stone to reach the water using the particle under the constant acceleration model:
[tex]y_f = y_i + v_{yi}t+ \frac{1}{2} a_yt^2[/tex]
OR
[tex]y_f -y_i - v_{yi}t- \frac{1}{2} a_yt^2 = 0[/tex]
OR
[tex]- \frac{1}{2} a_yt^2 - v_{yi}t+y_f-y_i=0[/tex]
If we take the direction downward to be negative,
[tex]y_f = -41.9 m, v_{yi} = -2 m/s, a_y = 9.8 m/s^2[/tex]
Substituting these values into the equation, we find
4.9t² + 2t - 50 = 0
The quadratic formula is now what we use. Since the stone is thrown into the pool, time must be positive, and the physical situation can only be described by the positive root:
[tex]t = \frac{-2 \pm\sqrt{2^2 - 4(4.9)(-41.9)} }{2(4.9)}[/tex]
⇒ t = 2.996 sec
Therefore, it takes 2.996 seconds for the stone to hit the water.
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give two reasons why transformers are an important part of the power distribution grid.
Transformers are an important part of the power distribution grid for two main reasons i.e. (1) Voltage regulation (2) Power transmission
(1) Voltage Regulation: Transformers are used to change the voltage level of electricity from the high voltage generated at power plants to a lower voltage level suitable for safe and efficient distribution to homes and businesses. This helps to regulate the voltage and prevent damage to electrical equipment and power outages.
(2) Power Transmission: Transformers also play a crucial role in transmitting electrical power over long distances. High voltage transmission reduces energy losses due to resistance in the transmission lines, making it more cost-effective to transmit power over large distances. Transformers are used at various points along the transmission line to step down the voltage to the required level for distribution to end-users.
In summary, transformers play a key role in maintaining the stability and efficiency of the power grid, enabling the safe and efficient transmission and distribution of electricity.
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An inventor claims to have developed an engine that during a certain time interval takes in 110 MJ of heat at 415 K, rejects 50 MJ of heat at 212 K while manages to do 16.7 kW of work. Do you agree with the inventors's claim?
The claim is observed to be wrong from the calculations done regarding the efficiency of the engine.
Heat Q₁ is given as 110 × 10⁶ J
Heat Q₂ is given as 50 × 10⁶ J
Temperature T₁ is given as 415 K.
Temperature T₂ is given as 212 K.
Work done is said to be 16.7 kW hours.
So, W = 16.7 × 10³ W (3600 sec) = 16.7 × 3600× 10³ W
η₁ = W/Q₁ = (16.7 × 3600× 10³)/(110 × 10⁶) = 0.5465 = 54.65%
Efficiency of the Carnot engine = 1 - T₂/T₁ = 1 - 212/415 = 0.5 = 50%
So, the claim is observed to be wrong.
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si crystalizes into a diamond crystal structure with lattice constant a = 0.543\: nma=0.543nm. calculate the atomic density in units of cm^{-3}cm −3 . values within 5rror will be considered correct.
Si crystalizes into a diamond crystal structure with lattice constant a = 0.543nm, the atomic density is 2330kg/m^3
Given the lattice constant of Si crystal (a) = 0.543nm = 0.543 x 10^-9m
Since Silicon has diamond cubic structure, its unit cell contains 8 atoms.
The molar mass of silicon is = 28g/mol
The mass of electron is = 1.6 x 10^-24
The mass of silicon crystal = density x volume
The mass = 8 x 28 x 1.6 x 10^-27 = 3.73 x 10^-25kg
Density of crystal lattice = mass / volume
Volume of silicon crystal = (5.43 x 10^-10)^3 = 1.6 x 10^-28m^3
Thus the density = 3.73 x 10^-25/ 1.6 x 10^-28 = 2330kg/m^3
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The only force acting on a 2.0 kg body as it moves along a positive x axis has an x component F x =−6x N, with x in meters. The velocity at x=3.0 m is 8.0 m/s. (a) What is the velocity of the body at x=4.0 m? (b) At what positive value of x will the body have a velocity of 5.0 m/s?
Answer:
Explanation:
The force is acting in the negative direction, causing the 2 kg body to slow down.
First find the acceleration (a), which will be negative:
a = F/m = -6N / 2 kg = -3 m/s²
a) Use this kinematics equation to find the v at x=4 m
v² = v₀² + 2aΔx
Δx = 4m - 3m = 1m
v² = (8 m/s)² + 2(-3 m/s²)(1 m)
v² = 64 m²/s² - 6 m²/s² = 58 m²/s²
v = √58 = 7.6 m/s
b) (5 m/s)² = (7.6 m/s)² + 2(-3 m/s²)Δx
Δx = -32.8/-6 = 5.47 m
4 m + 5.47 m = 9.46 m
This means the 2 kg body will have slowed down to 5 m/s when it is at x = 9.46 m
The velocity of the body at x=4.0 m is 7.6 m/s and At 9.46 m of x will the body have a velocity of 5.0 m/s.
The 2-kilogramme body is slowing down because the force is acting in a negative direction.
The acceleration (a) will be negative, therefore find it first:
F/m = -6N/kg = -3 m/s2 (a) To determine the v at x=4 m, use this kinematics equation.
v2 = v02 + 2ax, where x = 4m - 3m = 1m and v2 = 8 m/s.
² + 2(-3 m/s²)(1 m) (1 m)
58 m2/s2 v2 = 64 m2/s2 - 6 m2/s2
(5 m/s) v = 58 = 7.6 m/s
v² = (7.6 m/s)
v² + 2(-3 m/s²)
Δx \sΔx = -32.8/-6 = 5.47 m
4 m + 5.47 m = 9.46 m
This indicates that when the 2 kilogramme body reaches x = 9.46 m, its speed will have dropped to 5 m/s.
The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.
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which term describe dthe umber of pulses that are used to determine the velocity along a color line of sight
The term packet size, or ensemble length, describes the number of pulses used to interrogate a color line of sight
What does the number of packets in color Doppler relate to?The number of pulses needed to query a color line of sight is referred to as packet size or ensemble length. The dwell time is the period of sampling along each line of sight, which is equal to the product of the inverse of the pulse repetition frequency (PRF) and the packet size.
The number of pulses broadcast in the same direction is referred to as the ‘packet size,' and it must contain at least three pulses for velocity measurement. The beam is guided to the next color scan line after acquiring data for one color scan line.
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a 10.0-μf capacitor, a 50.0-μf capacitor, and a 100-μf capacitor are connected in series across a 9.00-v battery. what is the equivalent capacitance equiv of the combination?
The total of the capacitances has an inverse relationship with the equivalent capacitance in series. About 1.6 F is the equivalent capacitance of 10.0 F, 50.0 F, and 100 F.
The reciprocal of the sum of the reciprocals of the capacitors in a series connection yields the equivalent capacitance (C equiv). In this situation, 1/C equiv = 1/10.0 F + 1/50.0 F + 1/100 F may be used to compute C equiv. We arrive at C equiv = 13.04 F after solving for C equiv. This indicates that the total equivalent capacitance of the three capacitors—10.0 F, 50.0 F, and 100 F—is 13.04 F. The overall charge stored in the combination is equal to the sum of the charges stored in each individual capacitor, and the voltage across each capacitor will be proportional to its capacitance.
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pls help documents are attached
Answer: do you need a essay for it? also i need a close up!!
Explanation:
a certain power supply provides a continuous 2 w to a load. it is operating at 60% efficiency. in a 24 h period, how many kilowatt-hours does the power supply use?
In a 24-hour period, the power supply uses 0.08 kilowatt-hours.
The power supply is operating at 60% efficiency, which means 60% of the power it consumes is delivered to the load as useful power, while the remaining 40% is lost as heat or other forms of waste.
Since the power supply delivers a continuous 2 W to the load, it must consume:
2 W / 0.6 = 3.33 W
To find the energy consumption in kilowatt-hours, we need to multiply the power consumption by the number of hours in a day and then divide by 1000 to convert from watts to kilowatts:
3.33 W * 24 hours / 1000 = 0.08 kWh
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in physics class, tara discovers that the behavior of electrical power, x, in a particular circuit can be represented by the function:
If the behavior of electric power is represented by the equation f(x) = x² + 2x + 7 = 0, then the value of x will be (-1 + i√6) & (-1 - i√6).
The behavior of electric power, x, in a circuit is represented by the quadratic equation:
f(x) = x² + 2x + 7
if f(x) = 0
x² + 2x + 7
Here the value of a = 1, b = 2, c = 7
To find the value of x, we use the formula, x = (-b ± √(b² - 4ac))/2a
x = (-2 ± √(2²- 4 × 1 × 7))/(2 × 1)
x = (-2 ± √(4 - 28))/2
x = (-2 ± √-24)/2
x = (-2 ± √(-6×4)/2
x = (-2 ± 2√-6)/2
x = (-1 ± √-6)
x = (-1 + √-6) & (-1 - √-6)
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--The given question is incomplete, the complete question is:
"in physics class, tara discovers that the behavior of electrical power, x, in a particular circuit can be represented by the function f(x) = x² + 2x + 7. If f(x) = 0, solve the equation and express your answer in the simplest (a + ib) form."--
mr kim is driving in his tesla at a velocity of 20m/s. he then slams the accelerator and hots a velocity of 80m/s. by what factor has mr. kim and his tesla changed their kinetic energy? Can someone please help me w this question?
The change in their Kinetic energy by the factor of 3000m
It is given that
Initial velocity of Tesla (u) = 20m/s
Final velocity of Tesla (v) = 80m/s
We have to find change in Kinetic energy
Kinetic energy is the energy an object has because of its motion. If we want to accelerate an object, then we must apply a force. Applying a force requires us to do work. After work has been done, energy has been transferred to the object, and the object will be moving with a new constant speed
It is given by the formula
∆KE = 1/2mv^2 - 1/2mu^2
KE(i) = 1/2m(20)^2 = 200m J
KE(f) = 1/2m(80)^2 = 3200m J
∆KE = 3200m - 200m = 3000m J
Hence, change in their Kinetic energy by the factor of 3000m
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a tuning fork vibrates with a frequency of 220 hertz. you strike the tuning fork with a force that produces a maximum pressure of 3 pascals. write and graph a sine model that gives the pressure p as a function of the time t. what is the period of the sound wave?
The sine model that gives the pressure (p) as a function of time(t) is p(t) = Psin(2πft + Ф), and the time period of the sound wave is 0.004545 seconds.
The pressure at a point in space due to a vibrating tuning fork can be modeled as a sinusoidal wave:
p(t) = Psin(2πft + Ф)
Where P is the amplitude (3 Pa in this case), f is the frequency (220 Hz), t is time, and Ф is the phase angle.
The period of the wave, T, is given by:
T = 1 / f = 1 / 220 Hz = 0.004545 seconds
So, the graph of the pressure p(t) would be a sinusoidal wave with a period of 0.004545 seconds and an amplitude of 3 Pa.
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Suppose you were given the statement "All points on a rigid object have the same angular acceleration and angular speed." a. How could you use the bugs in Ladybug Revolution to test this idea?b. Is the angular displacement also the same or does it differ? Explain your reasoning
The following propositions are true with regard to an object's points rotating around a fixed point. They all rotate at the same pace. All of them experience the same angular acceleration
The angular speed for a circular motion about a particular point is equal at all locations along the circular path and is calculated as;
Where
α=ω÷t
The number of rotations about a fixed point is N.
The time of motion is T.
As a result, the position of an item spinning around a fixed point has no bearing on its angular speed.
The specified same angular acceleration is
Each object in the circular path will move at a different tangential speed and acceleration depending on its position.
We may therefore draw the conclusion that the claims that are true for all points in the object spinning about a fixed point are that they all have the same angular acceleration and angular speed.
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Standing waves are produced on a string that is held fixed at both ends. The tension in the string is kept constant. (a) For the second overtone standing wave the node-to-node distance is 8.00 cm. What is the length of the string? (b) What is the node-to-node distance for the fourth harmonic standing wave?
The required length of the string is 0.24 m and the node-to-node distance for the fourth harmonic standing wave is 0.06 m.
The relation for the wavelength of n th harmonic λₙ = 2L/n
where,
λₙ = 2 dₙ with dₙ being node-node distance of n th harmonic
Distance dₙ = 8 cm = 8 × 10⁻² m = 0.08 m
a) The second overtone is the second harmonic from the principle one so n = 3. If we use that in the above equation we get that,
2 dₙ = 2L/n
2 × 0.08 = 2L/3
3× 0.08 = L
L = 0.24 m
b) By employing above's considerations, the node to node distance of the fourth harmonic is obtained as
d₄ = λ₄/2 = (2 ×0.24)/(2× 4) = 0.06 m
Thus, the length of the string is 0.24 m and the node-to-node distance for the fourth harmonic standing wave is 0.06 m.
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2) the earth is 1.49x1011 m from the sun. if the earth requires 365.25 days to go once around the sun, what is the centripetal force on the earth
The centripetal force on the earth is 352.8x 10^20N if the earth is 1.49x10^11 m from the sun and requires 365.25 days to go once around the sun.
Given the distance of earth from sun is (r) = 1.49x10^11 m
Number of days the earth requires to complete one revolution (T) = 365.25
The mass of the earth (m) = 5.98x10^24 kg
We know the centripetal force = Fc = mrω^2 where ω is the angular velocity of earth to travel around the sun.
Also we know that ω = 2π/T where T is the time required for the Earth to complete one revolution around the Sun.
Fc = m x r x (2π/T)^2
T = 365.25days x 24 hrs x 60 min x 60 s
Fc = (5.98x10^24 x 1.49x10^11 x 4π^2) / (365.25 x 24 x 60 x 60)^2
Fc = 351.4 x 10^35/(31557600)^2
Fc = 111.35 x 10^28/31557600
Fc = 352.8x 10^20N
Hence the centripetal force on the earth is 352.8x 10^20N.
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if the airtrack is sloped at an angle of 4 degress, what should be the acceleration of a cart down the airtrack?
The acceleration of a cart down the air track is 0.68 m/s^2.
The acceleration of a cart down an air track that is sloped at an angle of 4 degrees can be calculated using the formula:
a = g * sin(θ)
where
"a" is the acceleration
"g" is the acceleration due to gravity (9.8 m/s^2 on the surface of the Earth)
"θ" is the angle of the slope in radians.
Converting the angle from degrees to radians, we get:
θ = 4° * (π / 180°) = 0.0698 radians
Plugging the values into the formula, we get:
a = 9.8 m/s^2 * sin(0.0698 radians) = 0.68 m/s^2
So, the acceleration of the cart down the air track would be approximately 0.68 m/s^2.
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A student is performing an activity in which two balls are pushed on a surface, and the times it takes for the balls to come to rest are recorded. What question can be best tested by the activity? How does force affect the motion of the object? What is the relationship between force and mass? How does a change in mass affect the motion of an object? What is the effect of a change of force on how fast an object moves?
The question can be best tested by the activity is: What is the coefficient of kinetic friction of the surface?
The frictional force resists the motion of the objects.
The force and mass are directly proportional to each other.
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
If the mass increases, resisting frictional force also increases.
As the force is resistive in nature, if force increases, object's motion decreases.
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each of the following is a form of energy except one, which one is the exception?
a. heat
b. water
c. light
d. x-radiation
b. water
Heat is a form of energy that is transferred from one body to another as a result of a difference in temperature. This transfer of thermal energy can occur through conduction, convection, and radiation. Correct option is A.
Water, on the other hand, is not a form of energy, but it is a crucial component in many energy-producing processes. For example, water is used in hydropower generation to generate electricity.
Light is a form of electromagnetic radiation that is visible to the human eye. Light energy travels in waves and can be harnessed for various purposes, such as lighting and solar power generation.
X-radiation, also known as X-rays, is a form of high-energy electromagnetic radiation. X-rays are used in medical imaging to produce images of bones and other internal structures of the body. X-rays are also used in scientific research and in industrial applications, such as material testing and inspection.
In conclusion, heat, light, and x-radiation are all forms of energy, while water is not a form of energy, but it is a necessary component in many energy-producing processes.
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jack and jill exercise in a 25.0 m long swimming pool. jack swims 9 lengths of the pool in 142.5 s (2 min and 22.5 s) , whereas jill, the faster swimmer, covers 10 lengths in the same time interval. find the average velocity and average speed of each swimmer.
The Jack and Jill exercise is a swimming exercise that involves two swimmers swimming in a pool.
Find the average velocity and average speed of each swimmer?Jack:
Velocity = 25.0 m/142.5 s = 0.175 m/s
Speed = 9 lengths x 25.0 m/142.5 s = 2.125 m/s
Jill:
Velocity = 25.0 m/142.5 s = 0.175 m/s
Speed = 10 lengths x 25.0 m/142.5 s = 2.375 m/s
In this exercise, Jack and Jill each swim a certain number of lengths of a swimming pool in a given time interval. In this case, Jack swam 9 lengths of a 25.0 m long pool in 142.5 s (2 min and 22.5s) and Jill covered 10 lengths in the same time interval.To find the average velocity and average speed of each swimmer, we will need to calculate the distance each swimmer covered and the time each swimmer took to cover the distance. Jack swam 9 lengths of 25.0 m, which is 225.0 m. Jill swam 10 lengths of 25.0 m, which is 250.0 m. Both Jack and Jill covered the distance in 142.5 s (2 min and 22.5 s). The average velocity of Jack is the distance he covered divided by the time to cover the distance. Therefore, Jack's average velocity is 225.0 m divided by 142.5 s, or 1.57 m/s. Jill's average velocity is 250.0 m divided by 142.5 s, or 1.75 m/s.To learn more about The average velocity refer to:
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one of the vertical circular rides in fisics fantasy land has a radius of 35.0 m. you are sitting in a car that is just cresting the top of the ride. how fast must the car be moving in order that you momentarily lift off your seat and feel weightless?
The car must be moving at 28.75 m/s in order for a person to momentarily lift off their seat and feel weightless.
What is car?A car is a wheeled motor vehicle used for transportation. Most definitions of cars say that they typically run on roads, have seating for one to eight people, and mainly transport people rather than goods. Cars are also known as motor vehicles, automobiles, or vehicles and are typically powered by internal combustion engines fueled by diesel and gasoline.
The speed necessary for a person to momentarily feel weightless on a circular ride is known as their "escape velocity". It is calculated using the equation v = √(2gr) where v is the escape velocity, g is the acceleration due to gravity, and r is the radius of the ride.
In this case, the escape velocity would be calculated as v = √(2*9.8*35) = 28.75 m/s. Therefore, the car must be moving at 28.75 m/s in order for a person to momentarily lift off their seat and feel weightless.
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show how to wire the 74ls293 as a mod-14, mod-60, counter with a 10-khz clock input.
To wire a 74LS293 as a mod-14, mod-60 counter with a 10-kHz clock input, connect the clock input to the CK input of one of the 74LS 293, connect the Q output of that 74LS 293 to the clock input of the next 74LS 293, connect the Q3 and Q0 outputs of the first 74LS 293 to the clear and enable inputs, respectively, of the second 74LS 293, and connect the Q0-Q3 outputs of the second 74LS 293 to the outputs of the counter.
The 74LS 293 is a dual 4-bit binary counter that can be used to count up to 15. To wire a 74LS 293 as a mod-14, mod-60 counter, the following steps can be followed:
Connect the 10-kHz clock input to the CK input of one of the 74LS 293 chips. This will provide the clock input to the first 74LS 293.
Connect the Q output of the first 74LS 293 to the clock input of the second 74LS 293. This will provide the output of the first 74LS 293 as the clock input to the second 74LS 293.
Connect the Q3 output of the first 74LS 293 to the clear (CLR) input of the second 74LS 293. This will allow the second 74LS 293 to be reset back to zero when the count in the first 74LS 293 reaches 14.
Connect the Q0 output of the first 74LS 293 to the enable (EN) input of the second 74LS 293. This will allow the second 74LS 293 to count only when the count in the first 74LS 293 is less than 14.
Connect the Q0-Q3 outputs of the second 74LS 293 to the outputs of the counter. These outputs will represent the count from 0 to 15 (or mod-16) in binary form.
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here's another please help me :(
The three different types of matter are solid, liquid, and gas. By examining the configuration of their particles, we can understand why they have various properties.
What are the five states of matter?States of matter are the divisions of matter based on the physical characteristics they reflect. They can be separated into five different states of matter: solid, liquid, gas, plasma, and bose-einstein condensate.The three different types of matter are solid, liquid, and gas. By examining the configuration of their particles, we can understand why they have various properties.A substance can exist in three different states, solid, liquid, and gaseous. Any change in a material's state of matter without a change in its chemical makeup is referred to as a physical transition.The complete question is,
How many states of matter are there?
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when naming an ionic compound, the is always named first. to name the anion, the root of the nonmetal name is added to the suffix - . the anion o2– is therefore named .
The cation is always named first. to name the anion, the root of the nonmetal name is added to the suffix - . the anion o2– is therefore named as oxide.
In naming ionic compounds, the cation is always named first, followed by the anion. The cation is named as a metal element, while the anion is named by taking the root of the nonmetal element and adding the suffix "-ide".
For example, the anion O2– is formed by combining two oxygen atoms, resulting in a negative charge. To name this anion, the root of the nonmetal name (oxygen) is added to the suffix "-ide", giving the name "oxide".
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a railroad car of mass 2.00 x 10 4 kg moving at 3.00 m/s collides and couples with two coupled railroad cars, each of the same mass as the single car and moving in the same direction at 1.20 m/s. what is the speed of the three coupled cars after the collision? (1.8 m/s)
The speed of the three coupled cars after the collision is 1.8m/s.
The mass of the railroad car is given to be 2 x 10⁴ kg and moving with 3m/s speed.
The railroad car collides and coupled with to coupled railroad cars that has the same mass as that of a single car and they are moving in the same direction with a speed of 1.2m/s.
As we know that the linear momentum will be conserved, so, we can write,
Initial Momentum = final momentum
(2 x 10⁴ x 3) + (2 x 2 x 10⁴ x 1.2) = (3 x 2 x 10⁴)V
V is the final speed of the coupled railroad cars.
V = 5.4/3
V = 1.8 m/s
So, the speed of the coupled railroad cars is 1.8m/s.
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Which part of an extension ladder locks the fly section into position?
Choose matching definition
1 6 feet
2. Spur plates
3. Rung locks
4. 75 degrees
When using an extension ladder, it is important to know which part is responsible for locking the fly section into position. The part responsible for this is called the rung lock so option 3 is correct.
Rung locks are the components located at the top of the ladder that secure the fly section in place. When the rung locks are engaged, the fly section is locked into the desired position. Extension ladders are typically at an angle of 75 degrees when in use, and the rung locks help to keep the ladder in place at this angle. Additionally, spur plates are attached to the base of the ladder and help to increase stability and grip on the surface below. The size of the extension ladder can vary, but most are around 6 feet in length.
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19. (ii) an 88-g arrow is fired from a bow whose string exerts an average force of 110 n on the arrow over a distance of 78 cm. what is the speed of the arrow as it leaves the bow?
The speed of the arrow that has a mass of 88 g is 13.96 m/s
The mass of the arrow = 88 g
The force exerted by the string on the arrow = 110 N
The length of the arrow = 78 cm
The speed of the arrow can be found using the formula,
F = mv² / 2d
where F is the force exerted by the string on the arrow
m is the mass of the arrow
v is the speed of the arrow
d is the length of the arrow
Let us rearrange the equation,
v² = 2Fd / m
Let us substitute the known values in the above equation, we get
v² = 2 x110 x 78 x 10⁻² / 0.88
= 17160 x 10⁻² / 0.88
= 19500 x 10⁻²
= 195
v = √195
= 13.96 m/s
Therefore, the speed of the arrow = 13.96 m/s
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which electromagnetic wave can travel the farthest distances because it has a wavelength range of greater than 1x10-1 meters? a) Gamma ray b) Radio wave c) Microwave d) X-ray
The correct option is (b) i.e. radio wave, electromagnetic wave can travel the farthest distances because it has a wavelength range of greater than 1x10-1 meters.
Radio wave have the longest wavelength range (greater than 1x10-1 meters) among all the electromagnetic waves, so they can travel the farthest distances.
Radio waves have a wavelength range that can be as long as several kilometers, which makes them suitable for long-distance communication. They can travel through the atmosphere, around the Earth's curvature, and even through solid objects like buildings, making them ideal for broadcast and communication purposes.
Gamma rays, X-rays, and microwaves, on the other hand, have much shorter wavelengths, making them less suitable for long-distance travel. Gamma rays have the shortest wavelength range and are highly energetic and penetrate through materials, making them useful for imaging and radiation therapy. X-rays have a slightly longer wavelength range and are used for medical imaging. Microwaves have a slightly longer wavelength range compared to X-rays and are used for communication, radar, and cooking.
Therefore, radio waves are the electromagnetic waves that can travel the farthest distances because they have a wavelength range that is greater than 1x10-1 meters.
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do you feel yourself thrown to either side when you negotiate a curve that is ideally banked for your car's speed? what is the direction of the force exerted on you by the car seat?
The feeling of being thrown to either side while negotiating a curve is due to the centrifugal force, and the direction of this force is outwards the center of the curve.
When we negotiate a circular curve we experience a force due to the circular motion. This force is called centrifugal force. The direction of working of this force is away from the center of curve. Centrifugal force experienced by an object is equal to:
F = mv²/R
Where m is the mass of the object, v is the velocity of the object on the curve path, and R is the radius of the circular curve.
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at which numbered point or points is the object moving the fastest? check all that apply. at which numbered point or points is the object moving the fastest?check all that apply. point 1 point 2 point 3 point 4 point 5 point 6
The object is moving the fastest at points 1, 3, 5, and 6.
To determine which numbered points the object is moving the fastest, you can look at the position-versus-time graph for the moving object. At points 1, 3, 5, and 6, the object is moving the fastest.
This is because the slope of the graph is at its steepest at these points, indicating an increase in speed. Additionally, the curvature of the graph changes from a concave shape to a convex shape at these points, which is another sign of increasing speed.
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Calculate the gravitational force between 2 small objects each with a mass of 200kg that are 2 meters apart from each other
Answer: Approximately 2.67 x 10^-2 N
The gravitational force between two objects can be calculated using the formula:
F = G * (m1 * m2) / r^2
where F is the force, G is the gravitational constant (approximately 6.67 x 10^-11 N*(m^2)/(kg^2)), m1 and m2 are the masses of the two objects, and r is the distance between their centers.
In this case, we have m1 = 200 kg, m2 = 200 kg, and r = 2 meters. Plugging these values into the formula gives:
F = 6.67 x 10^-11 N*(m^2)/(kg^2) * (200 kg) * (200 kg) / (2 m)^2
F = 6.67 x 10^-11 N*(m^2)/(kg^2) * 40000 kg^2 / 4 m^2
F = 6.67 x 10^-11 * 10000 N
F = 0.667 * 10^-6 N
So the gravitational force between the two objects is approximately 0.667 micronewtons (0.667 * 10^-6 N).