I need help with my math!!!!!!!

the answer is in the picture

Answer:

4

Step-by-step explanation:

[tex] \frac{p - 1}{p} = 4[/tex]

Solve for p.

The numerator. difference has to be 4 times the answer of the denomiator.

So we can say

[tex]p - 1 = 4p[/tex]

Solve for p

[tex] - 1 = 3p[/tex]

[tex]p = - \frac{1}{3} [/tex]

Now plug this in for the other formula.

[tex]( \frac{ - \frac{1}{3} +1}{ \frac{1}{3} } ) {}^{2} = 2 {}^{2} = 4[/tex]

So

Answer:

I am in 5 classso i did not known answer

Answer:

a.) 5¹⁰

b.) 6¹⁷

Step-by-step explanation:

a.) 5⁸ × 25

Write 25 in the exponential form with the base of 5.

To calculate product use exponent rule

b.) 6¹⁵ × 36

Similarly, 6¹⁵ × 36

Write 25 in the exponential form with the base of 6.

To calculate product use exponent rule.

Answer:

[tex] \displaystyle {5}^{10} [/tex]

[tex] \displaystyle {6}^{17} [/tex]

Step-by-step explanation:

we want to rewrite the following expression as an exponent

[tex] \displaystyle {5}^{8} \times {25}[/tex]

remember that 25 is the square of 5 therefore

[tex] \displaystyle {5}^{8} \times {5}^{2} [/tex]

recall that,

[tex] \displaystyle {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]

with that law we obtain:

[tex] \displaystyle {5}^{8 + 2} [/tex]

simplify addition:

[tex] \displaystyle {5}^{10} [/tex]

likewise Question-1 36 is the square of 6 Thus,

[tex] \displaystyle {6}^{15} \times {6}^{2} [/tex]

similarly apply law of exponent:

[tex] \displaystyle {6}^{15 + 2} [/tex]

simplify addition:

[tex] \displaystyle {6}^{17} [/tex]

hence,

we have written the expression as an exponent

Given:

The matrix is:

[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

To show:

[tex](A^{-1})^{-1}=A[/tex]

Solution:

If a matrix is:

[tex]M=\begin{bmatrix}a&b\\c&d\end{bmatrix}[/tex]

Then,

[tex]M^{-1}=\dfrac{1}{ad-bc}\begin{bmatrix}d&-b\\-c&a\end{bmatrix}[/tex]

We have,

[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

Using the above formula, we get

[tex]A^{-1}=\dfrac{1}{(\cos x)(\cos x)-(-\sin x)(\sin x)}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\dfrac{1}{1}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

Now, the inverse of [tex]A^{-1}[/tex] is:

[tex](A^{-1})^{-1}=\dfrac{1}{(\cos x)(\cos x)-(\sin x)(-\sin x)}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

[tex](A^{-1})^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

[tex](A^{-1})^{-1}=\dfrac{1}{1}A[/tex]

[tex](A^{-1})^{-1}=A[/tex]

Hence proved.

Answer:

f(x) = [tex]\sqrt{x+5}[/tex] : All real numbers greater than/equal to 5

Explanation: you can't square root negative numbers, and any number less than 5 would give us negative.

f(x) = [tex]\frac{7}{x-8}[/tex] : All real numbers except 8

Explanation: You can't divide by 0, and if we included 8 in the number set, we would get this: [tex]\frac{7}{8-8} =\frac{7}{0}[/tex] (this is impossible).

f(x) = [tex]\sqrt{2}[/tex] : All positive real numbers and 0

Explanation: Again, you can't square root negative numbers.

f(x) = 8x : All real numbers

Not much to explain for this one, any real number makes this equation true.

Answer:

solution

here,

Step-by-step explanation:

f={(2,1/2), ( 3, 1/3) , (4, 1/4)}

Range = { / (\ frac 12\) , \ (\ frac 13\) ,

\( \ frac 14\ )}

Inverse function ( f-^1 ) = {( 1/2, 2) ,( 1/3 ,3) , 1/4, 4 )} is the required answer

Answer:

your y-intercept is 5 and your slope is 1 hope this helps with translating into the form you want

Step-by-step explanation:

Answer:

Step-by-step explanation:

cos x=sinx

divide by cos x

1=tan x

tan x=1

[tex]tan x=1=tan \frac{\pi }{4}=tan (n\pi +\frac{\pi }{4})\\x=n\pi +\frac{\pi }{4} ,\\where~n~is~an~integer.[/tex]

Step-by-step explanation:

Hello,

Let's say a the  first term and r the ratio  of the G.P.

[tex]u_1=a=81\\u_2=a*r\\u_3=a*r^2\\u_4=a*r^3\\\\\dfrac{u_4}{u_1} =\dfrac{a*r^3}{a} =r^3=\dfrac{24}{81} =\dfrac{8}{27} \\\\r=\sqrt[3]{\dfrac{8}{27} } \\\\\boxed{r=\dfrac{2}{3}}\\[/tex]

Answer:

44

Step-by-step explanation:

* means multiply

put 8 where the x is

6 * 8 - 4

48 - 4

44

Answer:

Step-by-step explanation:

radius of base=8/2=4 ft

l²=4²+9²=16+81=97

l=√97 ft

Answer:

x = 70     y = 140

Step-by-step explanation:

Apologies if I get any names of vocabulary terms wrong, I never pay much attention to the names.

The central angle measure of an arc is the same as the arc's measure. In this case, y is the central angle and 140 is the arc's measure, so y = 140.

The inscribed angle measure of an arc is 1/2 the arc's measure. An inscribed angle lies on the circle. So 140/2 = 70 = x.

Answer:

3

Step-by-step explanation:

Answer:

1344.

Step-by-step explanation :

.

The speed of the jet will be 166.4. If the jet fly for 12 hours, then the distance cover will be 1996.8.

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

Speed = Distance/Time

A jet travels 832 km in 5 hours.

Then the speed of the jet will be

Speed = 832 / 5

Speed = 166.4 km per hours

If the jet fly for 12 hours, then the distance cover will be

Distance = Speed x Time

Distance = 166.4 x 12

Distance = 1996.8 km

More about the speed link is given below.

https://brainly.com/question/7359669

#SPJ2

Answer:

Yes by AAA

Step-by-step explanation:

Angle A is the same for both triangles. Angle D is congruent to Angle A since BC and DE are parallel lines and same with angle E. So by AAA the triangles are similar

Answer:

D

Step-by-step explanation:

First find h(3)

2(3)-2= 4

then find g(4)

4³-5= 59

Your answer is 2.98004491789381.

Answer:

The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Step-by-step explanation:

We are given that

Mean, [tex]\mu=8.04 g[/tex]

Standard deviation, [tex]\sigma=0.08g[/tex]

We have to find the two weights that separate the top 3% and the bottom 3%.

Let x be the weight of  machine components

[tex]P(X<x_1)=0.03, P(X>x_2)=0.03[/tex]

[tex]P(X<x_1)=P(Z<\frac{x_1-8.04}{0.08})[/tex]

=0.03

From z- table we get

[tex]P(Z<-1.88)=0.03, P(Z>1.88)=0.03[/tex]

Therefore, we get

[tex]\frac{x_1-8.04}{0.08}=-1.88[/tex]

[tex]x_1-8.04=-1.88\times 0.08[/tex]

[tex]x_1=-1.88\times 0.08+8.04[/tex]

[tex]x_1=7.8896[/tex]

[tex]\frac{x_2-8.04}{0.08}=1.88[/tex]

[tex]x_2=1.88\times 0.08+8.04[/tex]

[tex]x_2=8.1904[/tex]

Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Hi there!  

»»————-　★　————-««

I believe your answer is:  

520 students.

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

60% of the 1300 students passed. This means that 40% of the students failed.

⸻⸻⸻⸻

[tex]1300 * 0.4= 520[/tex]

⸻⸻⸻⸻

520 students failed school.

⸻⸻⸻⸻

[tex]\boxed{\text{Another way to find this...}}\\\\\text{Take 60}\% \text{ of 1300:}\\\\1300 * 0.6 = 780\\\\\text{780 students passed school.}\\\\\text{Subtract 780 from 1300:}\\\\1300 - 780 = \boxed{520}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

Missing angle A = 56.1° (approximately)

Step-by-step explanation:

<A = arcsin(a×sin(C)/c)

= arcsin(5×sin 95/6)

= 56.1154084° ≈ 56.1°

Answered by GAUTHMATH

ST = ST (Common)

RT = TQ (Given)

∠ RTS = ∠ SQT (Both 90°)

So, ∆ RTS ≅ ∆ QTS (By SAS congruency rule)

So, RS = QS (By C.P.C.T.)

=> 2x + 8 = 8x - 4

=> 8 + 4 = 8x - 2x

=> 12 = 6x

=> 12/6 = x

=> 2 = x

SR = 2x + 8 (Given)

=> SR = 2(2) + 8 (Putting the value of x)

=> SR = 4 + 8

=> SR = 12

Answer:

Step-by-step explanation:

Answer: 21, 28

Step-by-step explanation:

Use the Pythagorean Theorem [tex]a^{2}+b^{2}=c^{2}[/tex]:

Substitute in the values & solve:

[tex]x^{2}+(x+7)^{2}=35^{2}\\x^{2}+x^{2}+14x+49=1225\\2x^{2}+14x+49-1225=0\\2x^{2}+14x-1176=0\\2(x^{2}+7x-588)=0\\2(x + 28)(x - 21)=0\\x_{1}=-28, x_{2}=21[/tex]

-28 is not a possible solution since you can't have negative inches...

============================================================

Explanation:

I'm assuming that segments AD and CD are tangents to the circle.

We'll need to add a point E at the center of the circle. Inscribed angle ABC subtends the minor arc AC, and this minor arc has the central angle AEC.

By the inscribed angle theorem, inscribed angle ABC = 50 doubles to 2*50 = 100 which is the measure of arc AC and also central angle AEC.

----------------------------

Focus on quadrilateral DAEC. In other words, ignore point B and any segments connected to this point.

Since AD and CD are tangents, this makes the radii EA and EC to be perpendicular to the tangent segments. So angles A and C are 90 degrees each for quadrilateral DAEC.

We just found angle AEC = 100 at the conclusion of the last section. So this is angle E of quadrilateral DAEC.

---------------------------

Here's what we have so far for quadrilateral DAEC

Now we'll use the idea that all four angles of any quadrilateral always add to 360 degrees

A+E+C+D = 360

90+100+90+D = 360

D+280 = 360

D = 360-280

D = 80

Or a shortcut you can take is to realize that angles E and D are supplementary

E+D = 180

100+D = 180

D = 180-100

D = 80

This only works if AD and CD are tangents.

Side note: you can use the hypotenuse leg (HL) theorem to prove that triangle EAD is congruent to triangle ECD; consequently it means that AD = CD.

Answer:Vertex at (3, -2)

Step-by-step explanation:

Answer

Step-by-step explanation:

y = -2x + 0

Therefore; y = -2x

Answer:

50 km/hr

Step-by-step explanation:

speed = x + 75

distance = 250km

time = 2

250 = (x + 75) * 2

125 = x + 75

x = 50

Answer:

C) 3 times the sq root of 3

Step-by-step explanation:

In a right angle triangle, the COS is definned as the ajacent side over the hypotenuse. So

COS 60 = JK/JL

COS 60 = JK/(6*sq root 3)

.5 = JK/(6*3**1/2)

JK = .5 *(6*3**1/2)

JK = 3*3**1/2

Answer: 70

Step-by-step explanation:

We are required to calculate the total distance Cecilia travelled in 5 days

The total distance Cecilia travelled for 5 days is 99 kilometers

Day 1 = 27 kilometers

Day 2 to day 5 = 2/3 of 27

= 2/3 × 27

= 2 × 9

= 18 kilometers each day

Total distance = day 1 + day 2 + day 3 + day 4 + day 5

= (27 + 18 + 18 + 18 + 18) kilometers

= 99 kilometers

Therefore, the total distance Cecilia travelled for 5 days = 99 kilometers

Read more:

https://brainly.com/question/17207658