Answers
9514 1404 393
Answer:
a) yes
b) see attached
c) see discussion
d) neither
e) increasing (2,5); decreasing (-2, 2)
Step-by-step explanation:
a) The graph passes the vertical line test, so is the graph of a function.
__
b) A table of values is attached
__
c) Generally, this sort of function would be defined piecewise:
[tex]\displaystyle f(x)=\begin{cases}-\dfrac{1}{2}x+1&\text{for }-2\le x<2\\2x-4&\text{for }2\le x \le5\end{cases}[/tex]
In the attachment, we have shown the use of the "maximum" function to define it. The effect is the same.
__
d) The function has no symmetry about the origin or the y-axis, so is neither odd nor even.
__
e) The function is increasing where the line has positive slope, on the interval (2, 5). The function is decreasing where the line has negative slope, on the interval (-2, 2).
Related Questions
If f(x) = 4^x-8 and g(x) = 5x+6, find (f + g)(x)
A. (F+g)(x) = -4^x - 5x + 2
B.(F+g)(x) = 4^x + 5x - 2
C.(F+g)(x) = 4^x - 3x + 6
D.(F+g)(x) = 9x - 2
Answers
Hey there!
We are given two functions - one is Exponential while the another one is Linear.
[tex] \large{ \begin{cases} f(x) = {4}^{x} - 8 \\ g(x) = 5x + 6 \end{cases}}[/tex]
1. Operation of Function
(f+g)(x) is a factored form of f(x)+g(x). We can common factor out x. Therefore:[tex] \large{(f + g)(x) = f(x) + g(x)}[/tex]
2. Substitution
Next, we substitute f(x) = 4^x+8 and g(x) = 5x+6.[tex] \large{(f + g)(x) = ( {4}^{x} - 8) + (5x + 6)}[/tex]
3. Evaluate/Simplify
Cancel out the brackets and combine like terms.[tex] \large{(f + g)(x) = {4}^{x} - 8 + 5x + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 8 + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 2}[/tex]
4. Final Answer
(f+g)(x) = 4^x+5x-2Find the area of the figure
Answers
Answer:
24
Step-by-step explanation:
divide the area in 2 regions
4 x 2 = 8 (area of one region)
4 x 4 = 16 (area of second region)
8 + 16 = 24 (sum of areas of the two regions)
If f(x) = 3X + 10x and g(x) = 4x - 2, find (f+g)(x).
O A. 17x - 2
O B. 3* + 6x + 2
O C. 3* - 6x + 2
D. 3X + 14x-2
help!!!
Answers
Simplify this algebraic expression.
y-3/3 +12
O A. y-11
O B. y + 13
O c. y-5
O D. y+ 11
Answers
Answer:
D
Step-by-step explanation:
[tex]y - \frac{3}{3} + 12[/tex]
[tex]y - 1 + 12[/tex]
[tex]y + 11[/tex]
Type your answer
(1 out of 4)
What is the value of the function when x = 3 in the
piecewise function
g(x) =
3x when x > 1
- 2x when x < 1
Answers
Answer:
9
Step-by-step explanation:
Visually demonstrate the decimal .3 in the hundred square below. Explain how you what to shade.
Answers
I will assign a question at around 9:00 today (July 3, 2021) for a huge amount of points. I won’t say where on Brainly. Good luck.
Answers
Answer:
ಠ_ಠ
Step-by-step explanation:
1. Willow Brook National Bank operates a drive-up teller window that allows customers to complete bank transactions without getting out of their cars. On weekday mornings, arrivals to the drive-up teller window occur at random, with an arrival rate of 24 customers per hour or 0.4 customers per minute.
a. What is the mean or expected number of customers that will arrive in a five-minute period?
b. Assume that the Poisson probability distribution can be used to describe the arrival process. Use the arrival rate in part (a) and compute the probabilities that exactly 0, 1, 2, and 3 customers will arrive during a five-minute period.
c. Delays are expected if more than three customers arrive during any five-minute period. What is the probability that delays will occur?
2. In the Willow Brook National Bank waiting line system (see Problem 1), assume that the service times for the drive-up teller follow an exponential probability distribution with a service rate of 36 customers per hour, or 0.6 customers per minute. Use the exponential probability distribution to answer the following questions:
a. What is the probability that the service time is one minute or less?
b. What is the probability that the service time is two minutes or less?
c. What is the probability that the service time is more than two minutes?
Answers
Answer:
1.
a. 2
b. 0.1353 probability that exactly 0 customers will arrive during a five-minute period, 0.2707 that exactly 1 customer will arrive, 0.2707 that exactly 2 customers will arrive and 0.1805 that exactly 3 customers will arrive.
c. 0.1428 = 14.28% probability that delays will occur.
2.
a. 0.4512 = 45.12% probability that the service time is one minute or less.
b. 0.6988 = 69.88% probability that the service time is two minutes or less.
c. 0.3012 = 30.12% probability that the service time is more than two minutes.
Step-by-step explanation:
Poisson distribution:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:
[tex]f(x) = \mu e^{-\mu x}[/tex]
In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.
The probability that x is lower or equal to a is given by:
[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]
Which has the following solution:
[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]
The probability of finding a value higher than x is:
[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]
Question 1:
a. What is the mean or expected number of customers that will arrive in a five-minute period?
0.4 customers per minute, so for 5 minutes:
[tex]\mu = 0.4*5 = 2[/tex]
So 2 is the answer.
Question b:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353[/tex]
[tex]P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707[/tex]
[tex]P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707[/tex]
[tex]P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1805[/tex]
0.1353 probability that exactly 0 customers will arrive during a five-minute period, 0.2707 that exactly 1 customer will arrive, 0.2707 that exactly 2 customers will arrive and 0.1805 that exactly 3 customers will arrive.
Question c:
This is:
[tex]P(X > 3) = 1 - P(X \leq 3)[/tex]
In which:
[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]
The values we have in item b, so:
[tex]P(X \leq 3) = 0.1353 + 0.2707 + 0.2707 + 0.1805 = 0.8572[/tex]
[tex]P(X > 3) = 1 - P(X \leq 3) = 1 - 0.8572 = 0.1428[/tex]
0.1428 = 14.28% probability that delays will occur.
Question 2:
[tex]\mu = 0.6[/tex]
a. What is the probability that the service time is one minute or less?
[tex]P(X \leq 1) = 1 - e^{-0.6} = 0.4512[/tex]
0.4512 = 45.12% probability that the service time is one minute or less.
b. What is the probability that the service time is two minutes or less?
[tex]P(X \leq 2) = 1 - e^{-0.6(2)} = 1 - e^{-1.2} = 0.6988[/tex]
0.6988 = 69.88% probability that the service time is two minutes or less.
c. What is the probability that the service time is more than two minutes?
[tex]P(X > 2) = e^{-1.2} = 0.3012[/tex]
0.3012 = 30.12% probability that the service time is more than two minutes.
The accompanying data represent the homework scores for material for a random sample of students in a college algebra course.
36
47
54
58
60
66
66
68
69
70
72
75
77
77
78
78
78
79
79
79
79
79
80
82
84
85
86
86
86
87
89
89
91
92
92
93
93
94
96
99
(a) Construct a relative frequency distribution with a lower class limit of the first class equal to 30 and a class width of 10.
(b) What is the probability a randomly selected student fails the homework (scores less than 70)? (The standard deviation is 13.64)
Simplify your answer to two decimal places.
Answers
Answer:
[tex]\begin{array}{ccc}{Class} & {Frequency} & {Relative\ Frequency} &{30-39} & {1} & {0.025} & {40-49} & {1} & {0.025} & {50 - 59} & {2} & {0.050} & {60 - 69} & {5} & {0.125} & {70 - 79} & {13} & {0.325} & {80 - 89} & {10} & {0.250} & {90 - 99} & {8} & {0.200} &{Total} & {40} & {1}\ \end{array}[/tex]
[tex]P(x < 70) = 0.225[/tex]
Step-by-step explanation:
Given
[tex]Lower = 30[/tex]
[tex]Width = 10[/tex]
Solving (a): The relative frequency table
First, we construct the frequency table using the given parameters.
[tex]\begin{array}{cc}{Class} & {Frequency} &{30-39} & {1} & {40-49} & {1} & {50 - 59} & {2} & {60 - 69} & {5} & {70 - 79} & {13} & {80 - 89} & {10} & {90 - 99} & {8} & {Total} & {40}\ \end{array}[/tex]
The relative frequency (RF) is calculated as:
[tex]RF = \frac{Frequency}{Total}[/tex]
Using the above formula to calculate the relative frequency, the relative frequency table is:
[tex]\begin{array}{ccc}{Class} & {Frequency} & {Relative\ Frequency} &{30-39} & {1} & {0.025} & {40-49} & {1} & {0.025} & {50 - 59} & {2} & {0.050} & {60 - 69} & {5} & {0.125} & {70 - 79} & {13} & {0.325} & {80 - 89} & {10} & {0.250} & {90 - 99} & {8} & {0.200} &{Total} & {40} & {1}\ \end{array}[/tex]
Solving (b): [tex]P(x < 70)[/tex]
To do this, we add up the relative frequencies of classes less than 70.
i.e.
[tex]P(x < 70) = [30 - 39] + [40 - 49] + [50 - 59] + [60 - 69][/tex]
So, we have:
[tex]P(x < 70) = 0.025 + 0.025 + 0.050 + 0.125[/tex]
[tex]P(x < 70) = 0.225[/tex]
Can you help please fellow people
Answers
Answer:
using 2 below points to draw:
(0, 7)
(3.5, 6)
Step-by-step explanation:
using
Exam V Psych 2317 Name: _____________________________
Attention: Read carefully each sentence and choose the best answer (2 points each)
1) While comparing a sample to a population, which design is appropriate?
A) One sample t test B) Related samples t-test C) Independent samples t-test D) ANOVA
2) While comparing two samples of different individuals, which research design is appropriate?
A) One sample t test B) Related samples t-test C) Independent samples t-test D) ANOVA
3) While comparing the same individuals two times, which research design is appropriate?
A) One sample t test B) Related samples t-test C) Independent samples t-test D) ANOVA
4) While comparing three samples of different individuals with an interest in one variable, which design is appropriate?
Answers
Attention: Read carefully each sentence and choose the best answer (2 points each)
1) While comparing a sample to a population, which design is appropriate?
A) One sample t test B) Related samples t-test C) Independent samples t-test D) ANOVA
2) While comparing two samples of different individuals, which research design is appropriate?
A) One sample t test B) Related samples t-test C) Independent samples t-test D) ANOVA
3) While comparing the same individuals two times, which research design is appropriate?
A) One sample t test B) Related samples t-test C) Independent samples t-test D) ANOVA
4) While comparing three samples of different individuals with an interest in one variable, which design is appropriate?
How many different committees can be formed from 12 teachers and 43 students if the committee consists of 3 teachers and 4 students?
The committee of 7 members can be selected in BLANK
different ways.
Answers
Answer:
27150200Step-by-step explanation:
Combination of 3 teachers out of 12:
12C3 = 12!/9!3! = 10*11*12/2*3 = 220Combination of 4 students out of 43:
43C4 = 43!/39!4! = 40*41*42*43/2*3*4 = 123410Total combinations:
220*123410 = 27150200please solve both i have been struggling
Answers
Answer:
3
Step-by-step explanation:
make a column of x ,f, fx
then write income in x and no.of workers in f
andthen multiply both just like 100*3 ,100*2, 300*p, 400*2,500*1 write its answer fx
add the all fx and use this formula
mean =fx /n
260=adding total of fx divide by 5
Repeat same formula in no 2
Thirty-six percent of customers who purchased products from an e-commerce site had orders exceeding 110. If 17% of customers have orders exceeding 110 and also pay with the e-commerce site's sponsored credit card, determine the probability that a customer whose order exceeds 110 will pay with the sponsored credit card.
Answers
Answer:
The right solution is "0.5".
Step-by-step explanation:
According to the question,
P(pay with the sponsored credit card | order exceeds $110)
= [tex]\frac{P(Pay \ with \ the \ sponsored \ credit\ card\ and\ order\ exceeds\ 110)}{P(order \ exceeds \ 110)}[/tex]
= [tex]\frac{P(A \ and \ B)}{P(A)}[/tex]
By putting the values, we get
= [tex]\frac{0.17}{0.34}[/tex]
= [tex]0.5[/tex]
Thus, the above is the right solution.
prove that
[tex]2 \tan30 \div 1 + tan ^{2} 30 = sin60[/tex]
prove that
.
Answers
Step-by-step explanation:
2tan 30° / 1 + tan² 30° =
2(⅓√3) /1 + (⅓√3)² =
⅔√3 / 1+ ⅓ =
⅔√3 / 4/3 =
2/4 √3 =
½√3 = sin 60° (proven)
halla la suma y el producto de la PG 3,9,27,81,243
Answers
Answer:
huh ano yan huhu paki ayos ng sagot
Step-by-step explanation:
hahahhaa
Moses receives a gift that is wrapped in a cube shaped box. The volume of the box is 1331/8 cubic inches.Find the length of a side of the box
Answers
Answer:
5.5inches
Step-by-step explanation:
1331/8=166.375
then length of a side is = cubic root of 166.375
=³√166.375
5.5
csc(π/2) =__
a.0
b.-1
c.1
d.undefined
Answers
Hi there!
[tex]\large\boxed{C. \text{ } 1}[/tex]
csc (π/2)
π/2 is located at (0, 1)
csc is equal to 1/y, or the reciprocal of the y-value
Therefore:
csc(π/2) = 1/1 = 1. C is the correct answer.
Two competitive brothers, who work in two different industries, were comparing their salaries. Because there is a difference of 4 years in their respective work experience, they decided to compare, not their actual salaries, but to compare their salaries against their company averages to see who is doing better. The following gives the brothers salaries, companies mean, and standard deviation for each company
Brother Salary P sd
Tom 84000 75000 7000
Andy 70578 60000 8200
What is the 2-score of Andy's salary?
a. 1.89
b. 1.89
c. 1.29
d. 0-129
Answers
Answer:
c. 1.29
Step-by-step explanation:
Z-score:
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Andy 70578 60000 8200
This means that [tex]X = 70578, \mu = 60000, \sigma = 8200[/tex]
What is the z-score of Andy's salary?
This is Z, so:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{70578 - 60000}{8200}[/tex]
[tex]Z = 1.29[/tex]
So the correct answer is given by option c.
5.11.
A manufacturing process produces 500 parts per hour. A sample part is selected about every half hour, and after five parts are obtained, the average of these five measurements is plotted on an x control chart.
(a) Is this an appropriate sampling scheme if the assignable cause in the process results in an instantaneous upward shift in the mean that is of very short duration?
(b) If your answer is no, propose an alternative procedure. If your answer is yes, justify.
5.12.
Consider the sampling scheme proposed in Exercise 5.11. Is this scheme appropriate if the assignable cause results in a slow, prolonged upward drift in the mean? If your answer is no, propose an alternative procedure.
Answers
Answer:
Following are the response to the given points:
Step-by-step explanation:
For question 5.11:
For point a:
For all the particular circumstances, it was not an appropriate sampling strategy as each normal distribution acquired is at a minimum of 30(5) = 150 or 2.5 hours for a time. Its point is not absolutely fair if it exhibits any spike change for roughly 10 minutes.
For point b:
The problem would be that the process can transition to an in the state in less than half an hour and return to in the state. Thus, each subgroup is a biased selection of the whole element created over the last [tex]2 \frac{1}{2}[/tex] hours. Another sampling approach is a group.
For question 5.12:
This production method creates 500 pieces each day. A sampling section is selected every half an hour, and the average of five dimensions can be seen in a [tex]\bar{x}[/tex]line graph when 5 parts were achieved.
This is not an appropriate sampling method if the assigned reason leads to a sluggish, prolonged uplift. The difficulty would be that gradual or longer upward drift in the procedure takes or less half an hour then returns to a controlled state. Suppose that a shift of both the detectable size will last hours [tex]2 \frac{1}{2}[/tex] . An alternative type of analysis should be a random sample of five consecutive pieces created every [tex]2 \frac{1}{2}[/tex] hour.
Please help i need answer asap
Answers
Answer:
23
Step-by-step explanation:
f(x) = 1
g(x) = x - 4
Can you evaluate (g•f)(0)? Explain why or why not?
Answers
Answer:
This is a multiplication of functions g and f, and these functions have no restrictions(such as a even root or a fraction), and thus [tex](g \mult f)(0) = g(0)f(0) = -4(1) = -4[/tex]
Step-by-step explanation:
We are given the following functions:
[tex]f(x) = 1[/tex]
[tex]g(x) = x - 4[/tex]
Can you evaluate (g•f)(0)?
This is a multiplication of functions g and f, and these functions have no restrictions(such as a even root or a fraction), and thus [tex](g \mult f)(0) = g(0)f(0) = -4(1) = -4[/tex]
Answer:
To evaluate the composition, you need to find the value of function f first. But, f(0) is 1 over 0, and division by 0 is undefined. Therefore, you cannot find the value of the composition.
You must evaluate the function f first.
Division by 0 is undefined.
The composition cannot be evaluated.
Translate the following into an algebraic expression: If it would take Mark m hours to clean the house alone and with his brother Sam they can clean the house together in t hours. How many hours would it have taken Sam if he was working alone
Answers
The width of a rectangular slab of concrete is 7 m less than the length. The area is 98 m squared. Find the dimensions
Answers
Answer:
Length = 14 m, Width = 7 m
Step-by-step explanation:
Let the length is l and width is b.
Width, b = l-7
Area of the rectangle, A = 98 m²
We know that, the area of a rectangle is as follow :
[tex]A=lb[/tex]
So,
[tex]98=l(l-7)\\\\98=l^2-7l\\\\l^2-7l-98=0\\\\l^2+7l-14l-98=0\\\\l(l+7)-14(l+7)=0\\\\l=14,-7[/tex]
Length can't be negative. So,
Width, b = 14-7 = 7 m
So, the dimensions of the rectangle are 14 m and 7 m respectively.
What piece of information is needed to prove
the triangles are congruent through ASA?
Answers
Answer:
B. <B is congruent to the <Z
OPTION B is the correct answer
will give brainyest (m^2/3 n^-1/3)^6
Answers
Step-by-step explanation:
here is the answer to your question
What is the y-coordinate of the point that divides the
directed line segment from J to k into a ratio of 2:3?
13
12+
11+
10
9
8
7+
v = ( my mom n Ilv2 – va) + ve
O 6
0-5
6+
05
5
07
5
4+
3+
1 27
Mi
Answers
Answer:
5
Step-by-step explanation:
took the test
The coordinates of the point that divides the line segment from J to K into a ratio of 2:3 are P(-5,7), and the y-coordinate is 7, the correct option is D.
What is the ratio?Ratio is described as the comparison of two quantities to determine how many times one obtains the other. The proportion can be expressed as a fraction or as a sign: between two integers.
We are given that;
Ratio= 2:3
Now,
Let the point we are looking for be denoted as P(x,y), and let the ratio be 2:3, which means that the distance from J to P is 2/5 times the distance from J to K.
Using the distance formula, we can find the distance between J and K as:
d = sqrt((x2-x1)^2 + (y2-y1)^2)
= sqrt((-8 - (-3))^2 + (11 - 1)^2)
= sqrt(25 + 100)
= sqrt(125)
The distance from J to P is 2/5 of the total distance, which is:
(2/5)d = (2/5)sqrt(125) = 2sqrt(5)
Using the ratio formula, we get:
x = (3* (-3) + 2 * (-8)) / (3+2) = -5
y = (31 + 211) / (3+2) = 7
Therefore, by the given ratio answer will be 7.
Learn more about the ratio here:
brainly.com/question/13419413
#SPJ7
Barnaby decided to count the number of ducks and geese flying south for the winter. On the first day he counted 175 ducks and 63 geese. By the end of migration, Barnaby had counted 4,725 geese. If the ratio of ducks to geese remained the same (175 to 63), how many ducks did he count?
Answers
Answer:
13,125 ducks
Step-by-step explanation:
The ratio of ducks:geese on the first day was:
175:63
On the last day (end of migration), he counted 4,725 geese.
To find the number of ducks using the same ratio, we are first going to divide 4,725 by 63 to find what number all the ducks and geese multiplied by:
4,725/63 = 75
The geese multiplied by 75. This means the ducks also multiplied by 75:
175*75 = 13,125
Barnaby counted 13,125 ducks.
Hope it helps (●'◡'●)
Round off to the underlined place values. 1 0.5242 2. 2.1616 3. 5.4852 4. 0.5862 5. 5.9658 6. 2.8959 7. 8.2584 8. 8.8956 9. 4.1492 1 5481
Answers
Answer:
wheres the underline pls let me know what is underlined ill answer it on comment
How many degrees are in a quarter circle? 25° 40° 90° 100°
Answers
Explanation:
Answer:
90
Step-by-step explanation:
360 ÷ 4 = 90
