I need help with this question

For this question, we have the following reaction:

Fe2O3 + 3 CO -> 2 Fe + 3 CO2

For letter D, we have:

10 grams of Fe2O3, molar mass = 159.7g/mol

6 grams of CO, molar mass = 28g/mol

In this case, we need to find which compound is the limiting and which is the excess reactant, and it is important to have in mind the molar ratio concept, which we use the coefficients in front of the compound to determine the ratios, like for Fe2O3 and CO, the molar ratio is 1:3. Now let's check if Fe2O3 is in excess, finding the number of moles first:

159.7g = 1 mol

10g = x moles

x = 0.063 moles of Fe2O3

According to the molar ratio, we need 3 times this value for CO, therefore, 0.063 * 3 = 0.189 moles of CO, now we need to check if this is the amount that we have of CO, or if we have more than that:

28g = 1 mol

6g = x moles

x = 0.214 moles of CO, this means that we have more CO than we actually need, making it the excess reactant and Fe2O3 the limiting reactant

Now to find the mass of Fe, we will be using the number of moles of the reactant, which is Fe2O3, 0.063 moles, and according to the molar ratio, we have twice this value for Fe, therefore, 0.063 * 2 = 0.126 moles of Fe, now using the molar mass of Fe, 55.84g/mol, we can find the final mass:

55.84g = 1 mol

x grams = 0.126 moles of Fe

x = 7.03 grams of Fe are produced, or if it is possible to round up, 7 grams of Fe, this is letter D

E. In this case, we need to see how much CO remains in the reaction, and since we need only 0.189 moles of CO and we actually have 0.214 moles, we have a 0.025 moles leftover, which is, in grams:

28g = 1 mol

x grams = 0.025 moles

x = 0.7 grams of CO remaining, only 5.3 grams will react

F. The percent yield is calculated having the actual yield, given in the question and the theoretical yield, which is the value we found in letter D, the formula for it is:

%yield = (actual yield/theoretical yield)*100

%yield = (6.75g/7.03g)*100

%yield = 0.964*100

The percent yield will be 96.4% for this reaction

ANSWER

The mass of solid dye the student will use to prepare the solution is 178.15 grams

STEP-BY-STEP EXPLANATION:

What to find? The grams of the solid dye

Giving parameters

The mole of red #40 dye = 0.359 M

The molecular mass of red#40 = 496.42g/mol

The grams of the red#40 dye can be calculated by using the below formula

Hence, the mass of solid dye the student will use to prepare the solution is 178.15 grams

0.66 moles of aluminum are needed to react completely with 2 moles of FeO.

Given,

the chemical equation is,

Al(s)+3FeO(s)—>3Fe(s)+Al2O3(s)

1 mole of aluminum is needed to react completely with 3 moles of FeO.

then,

no of moles of aluminum are needed to react completely with 2 moles of FeO = 2/3 = 0.66 moles

Hence, 0.66 moles of aluminum are needed to react completely with 2 moles of FeO.

A chemical element with the symbol Al and atomic number 13 is known as aluminium (or aluminium in American and Canadian English). Aluminum has a density that is around one third that of steel, which is lower than that of most common metals. It has a strong affinity for oxygen, and when exposed to air, creates a protective oxide coating on the surface. Aluminum visually resembles silver due to similarities in colour and light-reflecting properties. It is ductile, soft, and non-magnetic. Aluminum is the twelfth most prevalent element in the universe based on the frequency of its one stable isotope, 27Al, which is also the only stable isotope. Radiodating makes use of 26Al's radioactivity. A chemical element with the symbol Al and atomic number 18 is called aluminium (aluminium in American and Canadian English).

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6.0 % w/v means:

6.0 g of glucose ------ 100 mL of glucose solution (maybe it is diluted in water)

We need to find the volume of the solution.

Procedure:

6.0 g of glucose -------- 100 mL of solution

The true statement about Air is that :

Air is made of tiny particles that move separately from one another.

Gas particles move quickly in all directions and regularly collide with one another and the container's side. The particles gather kinetic energy and accelerate as the temperature rises.

Any physical phenomenon where a quantity is continuously undergoing minor, random fluctuations is referred to as Brownian motion. Robert Brown, a Scottish botanist, who was the first to observe this fluctuation, was honored with its name.

Thus, the tiny particles in the air continues to move.

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Since a mol is always a constant number = 6.022*10^23, to find how many moles there are in 4.5*10^23 molecules of iron we only need to do a simple math:

6.022*10^23 = 1 mol

4.5*10^23 = x moles

x = 0.7 moles

The molar mass of CO = 28.01 g grams are in  1.98x [tex]10^{15}[/tex] molecules of CO is 9.20× [tex]10^{-8}[/tex] g.

Avogadro's number is a proportion that compares atomic molar mass to human physical mass.

The molar mass of CO = 28.01 g

grams are in 1.98x [tex]10^{15}[/tex] molecules of CO

= 28.01x  1.98x [tex]10^{15}[/tex]/ 6.023 x 10²³

=9.20× [tex]10^{-8}[/tex] g.

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Based on the calculations, the pH of this solution is equal to 1.9208.

pH is literally the power of hydrogen ions and it can be defined as a measure of the molar concentration of hydrogen ions in a given solution.

Mathematically, the pH of this solution can be calculated by using this formula;

pH = -log[H⁺]

Where:

H⁺ represents the hydrogen ion concentration of a solution.

Given the following data:

Concentration of hydrogen ion (H⁺) = 1.2 × 10⁻² M.

Substituting the given parameters into the formula, we have;

pH = -log(1.2 × 10⁻²).

pH = -(-1.9208)

pH = 1.9208

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When 26. g of butane is mixed with 168. g of oxygen. Then, the maximum mass of carbon dioxide that could be produced by the chemical reaction is 77.44g.

2Ch3CH₂CH₂CH3 + 13O₂ ------- 8CO₂ + 10H₂O

From the above chemical reaction we get to know that, 2 moles of butane react with 13 moles of oxygen.

1 moles of butane react with 6.5 moles of oxygen to produce 4 moles. of carbon dioxide.

Given,

mass of oxygen = 168 g

Mass of butane = 26g

Molar mass. of oxygen = 32 g

Molar mass of butane = 58 g

We will calculate the number of moles

As we know that,

Mole = given mass/ molar mass

Moles of oxygen = 168/32 = 5.2 mol

Moles of butane = 26/ 58 = 0.44 moles

So, we can say that 0.4 moles of butane react with 6.5 × 0.44 moles of oxygen to produce 4 × 0.44 moles. of carbon dioxide.

Or 0.4 moles of butane react with 2.86 moles of oxygen to produce 1.76 moles of carbon dioxide.

1.6 = mass / molas mass

Molar mass of carbon dioxide = 44

Mass = 1.76 × 44

77.44g

Thus, we calculated that when 26. g of butane is mixed with 168. g of oxygen. Then, the maximum mass of carbon dioxide that could be produced by the chemical reaction is 77.44g.

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The heat change experienced by the calorimeter is 5.1339J.                                                                      

Total mass of solution = 50 + 50 = 100ml

Density = 1 g/ml

mass = 100 gm

Q = (msΔt)solution + (sΔt) mixture

    = (100×4.18×4.71) + (4.70 ×4.71)

   = 1980.78 + 22.137

   =2002.9 J

mole of AgNo₃ = 50×0.360/1000

                          = 0.0018

a mole of Kcl = 50×0.200/1000

                    = 0.010

The limiting reagent in a chemical reaction is a reactant that is definitely eaten up whilst the chemical reaction is completed. the amount of product fashioned is limited via this reagent, for the reason, that response can not hold without it.

The limiting reagent in a chemical reaction is the reactant with a view to be consumed completely. as soon as there is no greater of that reactant, the response can not proceed. Therefore it limits the response from continuing. The extra reagent is the reactant that would maintain reacting if the other had now not been consumed.

The limiting reagent is KCl so, moles of precipitate formed 0.010

ΔH exothermic = - 0,6568/0.01 = -65.68

Hence ΔH ext = - 65.68 kJ/mol

Theoretical moles of precipitate formed = 0.01 moles

Heat change by combustion = 100×4.70×4.18

                                               = 1964.6 J

Heat change experienced by calorimeter is = 4.70 × 1.09

                                                                         = 5.1339J

The heat of solution  = 1964.6 J + 5.1339J

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​104895.10 kilometers need to drive for the lower fuel consumption of the second car to compensate for the higher cost of this car.

For calculating the number of  miles  we need the compare the cost equation of both cars.

Considering x be the number of kilometers, since the mileage of the USA-made car is (22.5 * 1.609) / 3.785 = 19.56-kilo meter per litre, and the cost of petrol  per Litres = 2.05 .

SO for the USA made the pertrol cost is 2.05 / 9.56 = $0.214per km

and for the european made car is  2.05 / 28.5 = $0.071 per km

since the total cost is nothing like the sum of the purchase price and the fuel cost SO,  

for the  USA  made , the total  cost  is  = 85,000  + 0.214x and

for the  eurpoean car is   = 100,000 + 0.071x

By comparing the equation by considering the total cost for a car  to be equal so

85,000  + 0.214x =100,000 + 0.071x

=>100,000- 85,000 = 0.214x- 0.071x

=>15000= 0.143x

=>x=  104895.10

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​

The layer whose temperature drops with the depth is called Thermocline

What is thermocline?

A thermocline is a thin, distinct layer in a large body of fluid (such as water, such as in an ocean or lake; or air, such as an atmosphere), where temperature changes more dramatically with depth than it does in the layers above or below.

A thermocline layer is also called a thermal layer and there are lots of factors responsible for its temperature changes like

• seasonal weather variations,

• latitude

• local environmental conditions, like tides and currents.

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Carbon, hydrogen, nitrogen, oxygen, phosphorus, and sulfur are the strengths of the cell. The first four are the most significant since they are utilized to build the molecules required to create live cells.

The models draw attention to characteristics that are less obvious in actual cells. Color is used by the models to highlight various components. example of a weakness The models are static, but real cells feature moving elements. While the models depict cross-sections in two dimensions, real cells are three dimensional.

The inadequacy of cellular models to accurately represent the function of complicated decision-making by human beings is one of their shortcomings. Although transition rules are handled probabilistically in Markov models and may be affected by temporal lags in cell response, cellular frameworks can be coupled with these models.

Carbon, hydrogen, nitrogen, oxygen, phosphorus, and sulfur are the strengths of the cell. The first four are the most significant since they are utilized to build the molecules required to create live cells.

The complete question is:

What are the strengths and weaknesses of the cell model?

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The first step we have to follow is to balance the given equation, making the number of atoms of each element equal in both sides of the equation.

Now, that the equation is balanced, we can use the stoichiometric ratio of Na2O to NaOH to find the number of moles of NaOH produced from 1.20moles of Na2O:

2.40 moles of NaOH are produced.

The energy diagram given is for endothermic reaction process

This is characterized by the system to require more energy to form products.

In this question, specie A and B are the reactant while C is the product.

What happens in this type of reaction is that for products to be formed, the reaction has to attain activation energy which is used to break bonds and form products and this energy has to be gotten from outside the system in order for the reaction to proceed.

Writing a balanced equation:

Determine the moles of C = mass/ molar mass

mole of C= 2g / 12.01 g = 0.17 mol

mole of oxygen = 15g/ 32g = 0.47 mol

Mole ratio between carbon and carbon dioxide is 1:1. Therefore 0.17 mol Carbon reacts with 0.17 carbon dioxide.

mass of carbon dioxide = moles x molar mass

mass of carbon dioxide = 0.17 x 44.01

mass of carbon dioxide = 7.48 g

Explanation

First, let's list the density of each substance:

vegetable oil - approximately 0.92 g/mL

water - approximately 0.99 g/mL

rubbing alcohol - approximately 0.79 g/mL

So the least dense is rubbing alcohol, then vegetable oil and then water.

Answer: rubbing alcohol < vegetable oil < water.

Answer:

the density is halved

Explanation:

doubling the volume results in the density being halved

ANSWER

The final pressure of the gas is 1350.22 mmHg

STEP-BY-STEP EXPLANATION:

Given information

From the question provided, you were asked to find the final pressure of the gas, hence, we assume that x represents the final pressure of the gas

To find the final pressure of the gas, we need to apply the general gas law

Where,

P1 = initial pressure

V1 = initial volume

T1 = initial temperature

P2 = final pressure

V2 = final volume

T2 = final temperature

The next process is to convert the final and initial temperature from degree Celcius to degree kelvin

The next thing is to substitute the given data into the above formula

Therefore, the final pressure of the gas is 1350.22 mmHg

answer and explanation

the balanced chemical reaction for the formation of nitrogen dioxie is

2NO + O₂ → 2NO₂

and so at STP the number of mols of nitrogen dioxide in 4.50L would be

PV = nRT

n = PV/RT

= (1atmx 4.50L) / (8.314 x 273.15K

= 4.50/2270.97

= 0.00204 mols

0.00204 mols of nitrogen dioxide would have been formed from the reaction.

we know from the balance reaction that 1 mol of oxygen forms 2 mols of nitrogen dioxide and so the mols of oxygen that were present would be

1/2 x0.00204 = 0.00102 mols

we know that 1 mol of a gas occupies a volume of 22.4L at STP and so

0.00102 mols of oxygen would have a volume of

0.0102 mols x 22.4 L/mol

= 0.0228L

0.0228L of oxygen would be needed

Answer:

Explanation:

Here, we want to describe what happens to an aluminum atom when an aluminum ion is formed

The aluminum atom has 3 valence electrons

To form an ion, like other metals, it has to lose these electrons

By losing these electrons, it is able to form an ion

Hence, an aluminum ion is formed when an aluminum atom loses 3 valence electrons

ANSWER

option C

EXPLANATION

A base is a substance that reacts with an acid to produce salt and water only.

A base will also give hydroxide ion (OH-) when dissolved in water

Hence, the only compound that is a base in the given options is Al(OH)3

Therefore, the correct is option C

Answer:

- A carbonyl group has a carbonyl carbon with only O atom while A haldehyd group has acarbonyl carbon with only OH atom.

[tex].[/tex]

Answer:

- A ketone is not oxidised but aldehyde csn be so

In the reaction that is shown in the question;

1) Dichromate ion is reduced while tin II ion is oxidized

2) Fe II is oxidized while  nitrate ion is reduced.

We know that oxidation has to do with the loss of electrons. Thus we say that a specie has been oxidized if the specie looses electrons and we say that a specie has been reduced if the specie gains electrons. The species that is oxidized in a reaction is the oxidizing agent while the specie that is reduced in the reaction is a reducing agent.

Let us note that the procedures of oxidation and reduction does occur at the same time and when this happens, we have a specie whose oxidation number is increased and we say that it has been oxidized while the other specie has received some new electrons and has been said to be reduced.

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ANSWER

The percentage yield of water is 160%

EXPLANATION

Given that;

The mass of water is 144.9 grams

The mass of hydrogen gas is 10.04 grams

Follow the steps below to find the percentage yield of water

Write the balanced equation of the reaction

Step1; Find the number of moles of hydrogen gas using the formula below

Recall, that the molar mass of H2 is 2 g/mol

Step 2; Find the number of moles of water using a stoichiometry ratio

In the reaction, 2 moles H2 give 2 moles H2O

Therefore, the number of moles of H20 is 5.02 moles

Step 3: Find the mass of H2O

The molar mass of water is 18.0 g/mol

Step 4; Find the percentage yield of water

Therefore, the percentage yield of water is 160%

There are eight bonding electrons and one non-bonding pair of electrons across the Se atom. The Lewis structure is, for this reason, a legitimate Lewis structure of SeF4 S e F four can't be drawn without violating the octet policies.

Lewis structures, additionally called Lewis dot formulas, Lewis dot systems, electron dot structures, or Lewis electron dot systems, are diagrams that show the bonding among atoms of a molecule, in addition to the lone pairs of electrons that can exist within the molecule.

The Lewis structures became named after Gilbert N. Lewis, who added it in his 1916 article The Atom and the Molecule. Lewis structures extend the idea of the electron dot diagram by way of including lines between atoms to represent shared pairs in a chemical bond.

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The volume of the air that we require is 18.85 liters air.

The term combustion has to do with a situation where we are burning a substance in oxygen. By implication, combustion is actually a type of oxidation reaction and it does occur with hydrocarbons to produce energy.

The combustion of the butane occurs as follows:

     C₃H₈ + 5O₂  = 4 H₂O + 3CO₂      

MW 44    5x32      4x18    3x44

The number of moles of one gram of butane is; 1/44 = 0.02272 mol propane

The amount of oxygen that is required is;  5 x 0.02272 = 0.1136 mol oxygen

Given that  0.21 is the mol fraction of oxygen in air; 0.1136 / 0.21 = 0.54 mol air is required for the combustion of  propane.

From the ideal gas law;

PV=nRT, or V = nRT/P

The volume in  liters  = 0.54 x 8.314 x 468 / 111457 = 0.0188 m³ = 18.85 liters air.

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Here we have to multiply two values of length, so the result will be a value of surface, that means that the result will have the same unit and squared:

So, the correct answer is 405.3 cm^2.