I need the answers to this question

Step-by-step explanation:

Use this sort of layout, but where x will be an odd number, do not shade it. there should be a pattern of shaded segments followed by unshaded segments repeating

The system of inequalities y < -x+4 and y >-x 2 do not have a solution

Inequalities are expressions that have unequal values when compared or evaluated

The system of inequalities is given as

y < -x+4

y >-x 2

Next, we plot the inequalities on a graphing tool

See attachment for the graph

From the attached graph, the lines of the inequalities do not intersect

This means that the system of inequalities do not have a solution

Hence, the system of inequalities y < -x+4 and y >-x 2 do not have a solution

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Answer:

w = 15 cm

Step-by-step explanation:

We want to find the width, as the area of a rectangle is length (l) * width (w).

Since we know the area and the length, we have 480 = 32w

Isolating w by dividing both sides by 32 gives us w = 15 cm

The limit does not exist. There are infinitely many infinite discontinuities at [tex]x=n\pi[/tex], where [tex]n\in\Bbb N[/tex]. The function oscillates wildly between negative and positive infinity.

Answer:

[tex]\sf 28 \frac{1}{3} \:ft=28.3\:ft\:(nearest\:tenth)[/tex]

Step-by-step explanation:

Given information:

Let x be the unknown length of the other side of Mr Kelly's house.

To solve, set up a ratio with the given information and the defined unknown, then solve for x:

[tex]\textsf{20 ft : 6 strides = x ft : 8.5 strides}[/tex]

[tex]\implies \sf 20:6 = x:8.5[/tex]

[tex]\implies \sf \dfrac{20}{6}=\dfrac{x}{8.5}[/tex]

[tex]\implies \sf x=\dfrac{20 \cdot 8.5}{6}[/tex]

[tex]\implies \sf x=\dfrac{170}{6}[/tex]

[tex]\implies \sf x=28 \frac{1}{3} \:ft[/tex]

[tex]\implies \sf x=28.3\:ft\:(nearest\:tenth)[/tex]

Therefore, the length of the other side of Mr Kelly's house that takes him 8.5 strides to walk is 28.3 ft (nearest tenth).

Let that be x

If a kite is flying 95 ft. off the ground, and its string is pulled taut. The angle of elevation of the kite is 59 degrees. Then the length of the string will be 110.8 ft.

Given information constitutes the following,

The distance of the flying kite from the ground, length AB (refer the figure) = 95 ft.

The angle of elevation of the kite, ∠ACB = 59°

We have to find the length of the string, that is the length AC. For that, we can apply Trigonometry as shown in the next steps of the solution.

In ΔABC, as shown in the attached figure,

sin (∠ACB ) = AB / AC

⇒ sin (59°) = 95 / AC

0.8572 = 95 / AC

AC = 95 / 0.8572

AC = 110.814

AC ≈ 110.8 ft.                [After rounding off to the nearest tenth]

Hence, the length of the string comes out to be 110.8 ft.

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The solution for the simultaneous equations 2x + y - 2z = 12, x + 2y +z =18 and 2x - y + 2z =16 are x = 7, y = 4 and z = 3

Linear equations are equations that have constant average rates of change, slope or gradient

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

2x + y - 2z = 12,

x + 2y +z =18

2x - y + 2z =16

Eliminate y and z in the equations by adding the first and the third equation together

This gives

2x + y - 2z = 12,

+

2x - y + 2z =16

--------------------------

4x = 28

Divide both sides by 4

x = 7

Substitute x = 7 in x + 2y +z =18 and 2x - y + 2z =16

7 + 2y +z =18

2(7) - y + 2z =16

This gives

2y + z = 11

-y + 2z= 2

Multiply -y + 2z= 2 by 2

-2y + 4z= 4

Add -2y + 4z= 4 and 2y + z = 11

5z = 15

Divide by 5

z = 3

Substitute z = 3 in -y + 2z= 2

-y + 2*3= 2

Evaluate

y = 4

Hence, the solution for the simultaneous equations 2x + y - 2z = 12, x + 2y +z =18 and 2x - y + 2z =16 are x = 7, y = 4 and z = 3

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[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

Take HJ = a, GH = b and GJ = c

put the value of a from equation 1 in equation 2

[tex]\qquad❖ \: \sf \:c = (b + 2) + b - 17[/tex]

[tex]\qquad❖ \: \sf \:c = 2b - 15[/tex]

now, put the value of a and c in equation 3

[tex]\qquad❖ \: \sf \:b + 2 + b + 2b - 15 = 73[/tex]

[tex]\qquad❖ \: \sf \:4b - 13 = 73[/tex]

[tex]\qquad❖ \: \sf \:4b = 86[/tex]

[tex]\qquad❖ \: \sf \:b = 21.5 \: \: in[/tex]

Now, we need to find HJ (a)

[tex]\qquad❖ \: \sf \:a = b + 2[/tex]

[tex]\qquad❖ \: \sf \:a = 21.5 + 2[/tex]

[tex]\qquad❖ \: \sf \:23.5 \: \: in[/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

Answer:

23.5 in

Step-by-step explanation:

To find the length of HJ in triangle GHJ, create three equations using the given information, then solve simultaneously.

Equation 1

HJ is two inches longer than GH:

⇒ HJ = GH + 2

Equation 2

GJ is 17 inches shorter than the sum of HJ and GH:

⇒ GJ + 17 = HJ + GH

Equation 3

The perimeter of ΔGHJ is 73 inches:

⇒ HJ + GH + GJ = 73

Substitute Equation 1 into Equation 2 and isolate GJ:

⇒ GJ + 17 = GH + 2 + GH

⇒ GJ + 17 = 2GH + 2

⇒ GJ = 2GH - 15

Substitute Equation 1 into Equation 3 and isolate GJ:

⇒ GH + 2 + GH + GJ = 73

⇒ 2GH + GJ = 71

⇒ GJ = 71 - 2GH

Equate the two equations where GJ is the subject and solve for GH:

⇒ 2GH - 15 = 71 - 2GH

⇒ 4GH = 86

⇒ GH = 21.5

Substitute the found value of GH into Equation 1 and solve for HJ:

⇒ HJ = 21.5 + 2

⇒ HJ = 23.5

The answers to the question are:

1. The letters of the word track can be arranged in 5! ways

These are  5 x 4 x 3 x 2 x1

= 120

2. The way that the student would be able to select 6 out of 10 questions would be by 10C6

= 210 ways

C)This teacher would be able to make the decision of the prices to the students using =20C6= n!(n-r!r!)

= 38760

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Since [tex]a,b,c[/tex] are in geometric progression, if [tex]r[/tex] is the common ratio between consecutive terms, then

[tex]a=a[/tex]

[tex]b = ar[/tex]

[tex]c=ar^2[/tex]

Since [tex]a,b,c[/tex] are also in arithmetic progression, if [tex]d[/tex] is the common difference between consecutive terms, then

[tex]a = a[/tex]

[tex]b = a + d \implies d = b-a[/tex]

[tex]c = b + d = a + 2d \implies c = a + 2(b-a) = 2b-a[/tex]

Given that [tex]abc=27[/tex], we have

[tex]abc = a\cdot ar\cdot ar^2 = (ar)^3 = 27 \implies ar = 3 \implies a = \dfrac3r[/tex]

[tex]b = \dfrac3r \cdot r = 3[/tex]

[tex]c = \dfrac3r \cdot r^2 = 3r[/tex]

It follows that

[tex]c = 2b-a \iff 3r = 6 - \dfrac3r[/tex]

Solve for [tex]r[/tex].

[tex]3r - 6 + \dfrac3r = 0[/tex]

[tex]3r^2 - 6r + 3 = 0[/tex]

[tex]r^2 - 2r + 1 = 0[/tex]

[tex](r-1)^2 = 0[/tex]

[tex]\implies r=1 \implies a=b=c=3[/tex]

so the only possible sequence is {3, 3, 3, …}.

[tex]\frac{7}{4}[/tex] [tex]x\:-\:2\:=\:-5x\:+\:1[/tex]

[tex]\frac{7}{4}[/tex] [tex]x\:-\:2\:=\:-5x\:+\:1[/tex]

[tex]7x\: - \:8 \:=\: -20x\: + \:4 [/tex]

[tex]7x \:- \:8 \:+ \:20x \:= \:4[/tex]

[tex]7x\: + \:20x \:= \:4 \:+ \:8 [/tex]

[tex]27x\: = \:4\: + \:8[/tex]

[tex]x\:= [/tex] [tex]\frac{4}{9}[/tex]

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Answer:

x = 4/9

Step-by-step explanation:

Solve for x

7/4 x -2  = -5x +1

Add 5x to each side

7/4 x -2+5x  = -5x +1+5x

7/4 x  + 5x -2  = 1

Get a common denominator for the x terms

7/4x  +20/4x -2 = 1

Add 2 to each side

27/4 x -2+2 = 1+2

27/4 x = 3

Multiply each side by 4

27/4 x *4 = 3*4

27x = 12

Divide each side by 27

27x/27 = 12/27

x = 12/27

Simplify

x = 4/9

Answer:

for normalian is a function of the form FX is equal to a and x n + a n - 1 x n - 1 + ax2 into X + A1 is equal to A2 is degree per normal highest power of X is

In the derivation of the formula for the volume of a cone, the volume of the cone is calculated to be D. the the sum of the area of the square and the area of the circle from a cross section.

It should be noted that a volume simply means the amount of three dimensional space that's enclosed by a closed surface.

It is typically meaured on cubic units.

In this case, in the derivation of the formula for the volume of a cone, the volume of the cone is calculated to be the the sum of the area of the square and the area of the circle from a cross section.

In conclusion, the correct option is D.

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Answer:

B. It is the ratio of the area of the circle to the area of the square from a cross section.

Step-by-step explanation:

Answer:

18. Sqrt40 goes between 6 and 7.

19. Sqrt83 ~= 9

Step-by-step explanation:

For both of these problems, it's really useful to be very familiar with the perfect squares on the times table. 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225...



On #18, we're looking at the sqrt40. This will be between sqrt36 and sqrt49, because 40 is between 36 and 49. But sqrt36 is 6 and sqrt49 is 7. So sqrt40 is between 6 and 7.

For #19, the sqrt83 is far closer to sqrt81 than it is to sqrt100. Sqrt81 = 9. So sqrt83 is very close to 9, it would round to 9 and not 10.

The simplification of a³ - 1000b³ and 64a³ - 125b³ is (a - 10b) × (a² + 10ab + 100b²) and 4a - 5b) • (16a² + 20ab + 25b²) respectively.

Question 1: a³ - 1000b³

a³ - b³

= (a-b) × (a² +ab +b²)

So,

(a - 10b) × (a² + 10ab + 100b²)

Question 2: 64a³ - 125b³

a³ - b³

= (a-b) × (a² +ab +b²)

So,

(4a - 5b) • (16a² + 20ab + 25b²)

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Answer:

The file contains the solution to the question

The frequency distribution based on the information given is illustrated below.

A frequency distribution table is the

chart that summarizes all the data under two columns - variables/categories, and their frequency.

It should be noted that the distribution table has two or three columns and the first column lists all the outcomes as individual values or in the form of class intervals, depending upon the size of the data set.

Given the above information the frequency distribution table is:

Cost of living Number of states

85.0 - 94.9 9

95.0 - 104.9 5

105.0 - 114.9 0

115.0 - 124.9 2

125.0 - 134.9 2

135.0 - 144.9 1

145.0 - 154.9 1

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The exponential function is illustrated below.

An exponential function has a growth factor or 3.76. What is the percentage growth rate?

The growth factor (b) is given as:

b = 3.76

So, the percentage growth rate (r) is calculated as:

r = b - 1

Substitute known values

r = 3.76 - 1

Evaluate the difference

r = 276%

The way to solve Financial Problems using Sequences & Series will be:

The first salary that Mr James earn is 10000 and there is a yearly increase of 2000. Find his salary in the 5th year. This will be:

= a + (n - 1)d

= 1000 + (5 - 1)2000

= 10000 + (4 × 2000)

= 10000 + 8000.

= 18000

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The length of one of the remaining sides is 34.20 meters.

A trapezoid is a convex quadrilateral. A trapezoid has at least on pair of parallel sides. the parallel sides are called bases while the non parallel sides are called legs

Perimeter of an isosceles trapezoid =  sum of lengths of sides of a trapezoid

length of shorter base + length of longer base + (2 x legs)

108 = 11.5 + 28.1 + (2 x legs)

108 = 39.60 + (2 x legs)

108 - 39.60 =  (2 x legs)

68.40 =  (2 x legs)

leg = 68.40 / 2

= 34.20 meters

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Answer:

229.37, 229.4

Step-by-step explanation:

1. Hundredths
2. Tenths

The intersection of the two intervals in the number line will be = 4, 5,  6,.......+∞ = (-∞,6).

The union of the two intervals = -3, -2, -1, 0, 1, 2, 3, 4, 5,.....,+∞ = (-∞),9)

The given intervals are;

First interval  = (-∞, 6)

Second interval  = (-∞, 9)

Using the number line, we therefore, the first interval includes, -3, -2, -1, 0, 1, 2, 3, 4, 5,.....,+∞

The second interval includes, 4, 5,.....,+∞

Which gives the intersection as 4, 5, 6,7, 8,9......+∞

The union is the interval that combines the two sets of intervals which is given as follows;

The union of the two intervals = -3, -2, -1, 0, 1, 2, 3, 4, 5,.....,+∞

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Due to length restrictions, we kindly invite to check the explanation herein for further details of the hyperbola.

Herein we have an hyperbola whose axis of symmetry is parallel to the y-axis and the major semiaxis length is in the y-direction. By analytical geometry, we know that eccentricities of hyperbolae are greater than 1.

a) The formula for eccentricity is:

e = √(a² + b²) / a      (1)

Where:

If we know that a = 4 and b = 3, then the eccentricity of the hyperbola is:

e = √(4² + 3²) / 4

e = 5 / 4

b) The coordinates of the two vertices of the hyperbola are:

V(x, y) = (h, k ± a)      (2)

Where (h, k) are the coordinates of the center of the hyperbola.

V₁ (x, y) = (0, 4), V₂ (x, y) = (0, - 4)

The coordinates of the foci of the hyperbola are:

F(x, y) = (h, k ± c), where c = √(a² + b²).     (3)

c = √(4² + 3²)

c = 5

F₁ (x, y) = (0, 5), F₂ (x, y) = (0, - 5)

The equations of the asymptotes of the hyperbola are:

y = ± (a / b) · x

y = ± (4 / 3) · x      (4)

And the equations of the directrices of the hyperbola are:

y = k ± (2 · a - c)

y = 0 ± (8 - 5)

y = ± 3     (5)

The graph is presented in the image attached below.

c) The parametric equations for the hyperbola are the following formulae:

y = ± a · cosh t   →   y = ± 4 · cosh t      (6)

x = b · sinh t   →   x = 3 · sinh t     (7)

d) First, we determine the slopes of the two tangent lines by implicit differentiation:

m = (16 · x) / (9 · y)

m = (16 · 2.3) / [9 · (± 4.807)]

m = ± 0.851

Second, we find the intercept of each tangent line:

(x, y) = (2, 4.807)

b = 4.807 - 0.851 · 2

b = 3.105

y = 0.851 · x + 3.105      (8)

(x, y) = (2, - 4.807)

b = - 4.807 - (- 0.851) · 2

b = - 3.105

y = - 0.851 · x - 3.105      (9)

e) The definite integral of the arc length of the hyperbola is presented below:

[tex]s = \int\limits^{2}_{1} {\sqrt{\left(\frac{dx}{dt} \right)^{2}+\left(\frac{dy}{dt} \right)^{2}}} \, dt[/tex]

If we know that dx / dt = a² · sinh² t and dy / dt = b² · cosh² t, then the definite integral for the arc length is:

[tex]s = \int\limits^2_1 {\sqrt{a^{2}\cdot \sinh ^{2}t +b^{2}\cdot \cosh^{2}t}} \, dt[/tex]      (10)

f) We apply the following substitutions on (1): x = r · cos θ, y = r · sin θ. Then, we have the polar form by algebraic handling:

r(θ) = (a · b) / (b² · sin² θ - a² · cos² θ)     (11)

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Option C is correct. The test statistic is not between the critical values, so we reject the null hypothesis. There is sufficient evidence to support a claim of correlation between percentage of vote and income level.

The scatter plot is the plot that is used to show the correlation that is known to exist between the given data sets that is of interests. It helps by showing the existing relationship between the x values and the y values in the question.

When we look at the graph properly, if we are to rule a line we would find out that most of the data points in the equation fall under the line in the data set. This shows that there is high correlation between these two variables.

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Using proportions, it is found that option A gives a figure that is a scale drawing of the same courtyard using the scale 1 centimeter = 3 feet.

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

Researching this problem on the internet, the figure with a scale of 1 cm = 4 feet has the dimensions of:

51 cm, 75 cm, 30 cm and 72cm.

For a scale of 1 centimeter = 3 feet, these measures will be multiplied by 4/3, hence the figure is given in option A, as:

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Answer:

The shortest piece is the first piece and it is 14 cm long.

Step-by-step explanation:

We have three unknowns so we need 3 equations.

Let x = the length of the first piece

Let y = the length of the second piece

Let z = the length of the third piece.

x + y + z = 74            y = 2x          z = y + 4

There are a number of ways to solve this.  I am going to plug in 2x for y into the first and the third equation to get:

x + y + z = 74

x + 2x + z = 74 Combine the x terms

3x + z = 74

Next, I am going to substitute 2x in for y in the third equation above.

z = y + 4

z = 2x + 4  I am going to put both variable on the left side of the equation

z - 2x = 4

I can know take the two bold equations that I have above and solve for the either x or z.  I am going to solve for z.  I need one of the equation to have a z and the other equation to have -z so that they will cancel one another out.  I am going to multiple z - 2x = 4 all the way through by -1 to get:

z - 2x = 4

-1(z - 2x) = 4(-1)

-z +2x = -4  

I am going to rearrange 3x + z = 74 so that the z term is first and add it to -z + 2x = -4

z + 3x = 74

-z + 2x = -4

      5x = 70 divide both sides by 5

x = 14  This is the length of the first piece.

y = 2x

y = 2(14) = 28

y = 28 This is the length of the second piece.

z = y+4

z = 28 + 4 = 32

or

x + y + z = 74

14 + 28 + z = 74

42 + z = 74  Subtract 42 from both sides.

z = 32

Answer:

15u+15x-20

Step-by-step explanation:

* = multiply or times

We have to multiply everything in the parenthesis by -5, meaning:

-5*-3u = 15u

-5*-3x = 15x

-5*4 = -20

Put it all together: 15u+15x-20

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{What is the distributive formula?}[/tex]

[tex]\mathsf{a(b + c)}\\\\\mathsf{= a(b) + a(c)}\\\\\mathsf{= ab + ac}[/tex]

[tex]\large\textbf{Extended distributive property formula:}[/tex]

[tex]\mathsf{a(b + c + d)}\\\\\mathsf{= a(b) + a(c) + a(d)}\\\\\mathsf{= ab + ac + ad}[/tex]

[tex]\huge\textbf{What are we solving for?}[/tex]

[tex]\large\textbf{It seems like you have the extended distributive property}[/tex]

[tex]\mathsf{-5(-3u - 3x + 4)}[/tex]

[tex]\huge\textbf{What are the steps to solving for the}\\\\\huge\textbf{given equation?}[/tex]

[tex]\mathsf{-5(-3u - 3x + 4)}\\\\\mathsf{= -5(-3u) - 5(-3x) - 5(4)}\\\\\mathsf{= 15u + 15x - 20}[/tex]

[tex]\huge\textbf{What is the answer to the equation?}[/tex]

[tex]\huge\boxed{\frak{{= 15\mathsf{u} + 15\mathsf{x} - 20}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

If the length of hypotenuse is 95 m ,perpendicular is 57 m then the length of missing leg is 76m.

Given that the length of hypotenuse is 95 m ,the length of perpendicular is 57 m.

We are required to find the length of base or missing leg.

The given triangle is a right angled triangle. We can easily find out the length of the base of the triangle by using pythagoras theorem.

Pythagoras theorem says that the square of hypotenuse of a right angled triangle is equal to the sum of squares of the base and perpendicular of that triangle.

[tex]H^{2} =P^{2} +B^{2}[/tex]

We have to find the base of the triangle.

B=[tex]\sqrt{H^{2} -P^{2} }[/tex]

=[tex]\sqrt{(95)^{2} -(57)^{2} }[/tex]

=[tex]\sqrt{9025-3249}[/tex]

=[tex]\sqrt{5776}[/tex]

=76 m.

Hence if the length of hypotenuse is 95 m ,perpendicular is 57 m then the length of missing leg is 76m.

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By critically observing the number lines, the intersection of both (-∞, 6) and (-∞, 9) is (6, 9) because this is the point where they overlap. Also, the union of both (-∞, 6) and (-∞, 9) on a number line is (-∞, 9).

A number line can be defined as a type of graph with a graduated straight line which contains both positive and negative numerical values that are placed at equal intervals along its length.

Given the following intervals:

On a number line, the first interval would comprise the following numerical values -∞,..........-6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6.

On a number line, the second interval would comprise the following numerical values -∞,..........-6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.

By critically observing the number lines, we can logically deduce that intersection of both (-∞, 6) and (-∞, 9) is (6, 9) because this is the point where they overlap.

Also, the union of both (-∞, 6) and (-∞, 9) on a number line is (-∞, 9).

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