I want the answer please please

The area of the city block is 13.23 kilometers².

The city block is 3 times as long as it is wide. In this case, the width can be represented by w. The length will be 3w.

Therefore, perimeter will be:

= 2(length + width)

= 2(3w + w) = 16.8

8w = 16.8

Divide

w = 16.8 / 8

w = 2.1

Length = 3w = 3 × 2.1 = 6.3km

The area will be:

= Length × Width

= 6.3 × 2.1

= 13.23km²

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Answer:

The area of the city block is 13.23 kilometers².

Step-by-step explanation:

The dimensions of the cup that minimize the construction cost are 2 x 2 x 5 in

Given:  Capacity = 20 in³, cost of material for the side = 12¢/in² and cost of material for the base = 60¢/in²

In order to calculate the dimension of the cup

Let h and x represent the height and square base respectively

Thus, the capacity (volume) of the pencil cup is can be represented as:

V = x²h     (where V = 20)

20 = x²h

h = 20/x²

At minimum cost, we have:

C(x) = 60x² +  12(4xh)

C(x) = 60x² +  48xh         (put h = 20/x²)

C(x) = 60x² +  48x(20/x²)

C(x) = 60x² +  960/x

Differentiating with respect to x, we have:

C(x) = 120x - 960/x²      (multiply through by x²)

120x³-960 = 0

120x³ = 960

x³ = 960/120

x³ = 8

x = ∛8 = 2 in

For the height:

h = 20/x²

h = 20/2²

h = 20/4 = 5 in

dimensions = 2 x 2 x 5 in

Therefore, the dimensions of the cup that minimize the construction cost are a 2 x 2  square base and  height of 5 in

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Considering the triangle given the variables are calculated to be

x = (5√6)/3

y = (10√6) / 3

Information given in the question

right angle triangle

The unknown variables is calculated using SOH CAH TOA

Definition of variables for the  right angle triangle

hypotenuse = y

opposite = 5√2

adjacent = x

The variable x is solved using tan, TOA, the angle is 60

tan 60 = Opposite / Adjacent

tan 60 = (5√2) / x

x = (5√2) / tan 60

x = (5√6)/3

The variable y is solved using sin, SOH, the angle is 60

sin 60 = Opposite / Hypotenuse

sin 60 = (5√2) / y

y = (5√2) / sin 60

y = (10√6) / 3

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Check the picture below.

[tex]~~~~~~\textit{initial velocity in meters} \\\\ S = -5t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&16\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&16\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases} \\\\\\ 0=-5t^2+16t+16\implies 5t^2-16t-16=0 \\\\\\ (5t+4)(t-4)=0\implies t= \begin{cases} -\frac{4}{5}\\\\ 4 ~~ \textit{\LARGE \checkmark} \end{cases}[/tex]

the equation for meters is usually as you see in the picture but for this exercise it got rounded from -4.9 to -5, which is fine.

let's notice that "t"  has two values, however the seconds cannot be a negative value, so we dismiss that one.

The ball will strike the ground 4 seconds after it is thrown When an object is thrown upward, its height , in meters, is given by the quadratic equation S = -5t² + vt + h

To find the time at which the ball will hit the ground, we need to determine when the height (S) of the ball becomes zero. At that moment, the ball will be at ground level.

The height (S) of the ball is given by the quadratic equation:

S = -5t² + vt + h

where:

S = height of the ball in meters

t = time of flight in seconds

v = initial velocity in meters/second (upward velocity, so it's positive)

h = height above level ground from which the object is thrown

Given that the initial velocity (v) is 16 meters/second, and the height above the ground (h) is 16 meters, we can substitute these values into the equation:

S = -5t² + 16t + 16

Now, to find the time (t) at which the ball hits the ground, we need to solve for t when S = 0:

0 = -5t² + 16t + 16

This is a quadratic equation in standard form (ax² + bx + c = 0), and we can solve it by factoring or using the quadratic formula. In this case, let's use the quadratic formula:

The quadratic formula is given by:

t = (-b ± √(b² - 4ac)) / 2a

In our case, a = -5, b = 16, and c = 16. Plugging these values into the quadratic formula:

t = (-(16) ± √(16² - 4*(-5)16)) / 2(-5)

t = (-16 ± √(256 + 320)) / -10

t = (-16 ± √576) / -10

Now, find the two possible solutions for t:

t₁ = (-16 + √576) / -10

t₁ = (-16 + 24) / -10

t₁ = 8 / -10

t₁ = -0.8 seconds

t₂ = (-16 - √576) / -10

t₂ = (-16 - 24) / -10

t₂ = -40 / -10

t₂ = 4 seconds

We have two solutions for t: t = -0.8 seconds and t = 4 seconds. However, we can disregard the negative value for time, as time cannot be negative in this context.

So, the ball will strike the ground 4 seconds after it is thrown.

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Answer:

P(les than/equal to 3): ½

The corresponding angles form the given figure are ∠1 and ∠5, ∠2 and ∠6, ∠4 and ∠8 and ∠3 and ∠7. Therefore, option D is the correct answer.

From the given figure, we need to identify the corresponding angles.

The corresponding angles definition tells us that when two parallel lines are intersected by a third one, the angles that occupy the same relative position at each intersection are known to be corresponding angles to each other.

From the figure, ∠1 and ∠5, ∠2 and ∠6, ∠4 and ∠8 and ∠3 and ∠7 are the corresponding angles.

The corresponding angles form the given figure are ∠1 and ∠5, ∠2 and ∠6, ∠4 and ∠8 and ∠3 and ∠7. Therefore, option D is the correct answer.

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x = [tex]x^{2}[/tex] - 20  is equivalent to  [tex]x^{2}[/tex] - x - 20 = 0 .

What do you mean by algebraic expression?

Algebraic expressions are mathematical expressions that result when you perform operations such as addition, subtraction, multiplication, and division on variables and constants. Algebraic expressions have different components. Variables, constants, terms, and coefficients in algebraic expressions. A symbol that does not have a fixed value is called a variable.

Given equation:

x = [tex]x^{2}[/tex] - 20

⇒ [tex]x^{2}[/tex] - 20 - x = 0

⇒ [tex]x^{2}[/tex] - x - 20 = 0

Therefore, x = [tex]x^{2}[/tex] - 20  is equivalent to  [tex]x^{2}[/tex] - x - 20 = 0 .

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A)  the domain is:

D: [0, 6]

The range is:

B)  

"The slope is __1/2__ So, the water amount in the rain barrel changes at a rate of __1/2__ inch per day."

"The Y-intercept is __2__ So, the amount of water in the rain barrel before the rain began was __2__ inches."

And the graph can be seen at the end.

Here we have the linear equation:

d(t) = (1/2)*t + 2

This refers to the amount of water in a barrel for six rainy days, where t is the number of days.

So the domain goes between t = 0 and t = 6.

The range will go between:

d(0) = (1/2)*0 + 2 = 2

d(6) = (1/2)*6 + 2 = 3 + 2 = 5

So the domain is:

D: [0, 6]

The range is:

T: [2, 5]

b) The complete sentences are:

"The slope is __1/2__ So, the water amount in the rain barrel changes at a rate of __1/2__ inch per day."

"The Y-intercept is __2__ So, the amount of water in the rain barrel before the rain began was __2__ inches."

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Answer:

3.2 pages per minute

Step-by-step explanation:

Unit Rate: 64 / 20 = 3.2 pages per minute

A unit rate is just a measure of either how fast you can do one of something, or how fast you can do something in one unit of time :)

Answer:

Step-by-step explanation

64 pages ÷ 20 =

20 minutes ÷ 20 =

3.2 pages

1 minute

so she read 3.2 pages per minute

Answer:

y = 2(x - 1)^2 - 9

Step-by-step explanation:

The vertex form of a parabola is y = a(x - h)^2 + k

(h, k) is the vertex, aka (1, -9)

(x, y) is the point that is passed through aka (2, -7)

Using this, we can substitute these values into the equation.

First, let's work with the vertex

We know that h = 1 and k = -9:  y = a(x - 1)^2 - 9

Now, let's substitute in the point that was given: -7 = a(2 - 1)^2 - 9

Now, we can find the a-value by simplifying: -7 = a - 9   -->  a = 2

Finally, we can make the equation by taking our equation that we made with the vertex but just putting the a-value in since we know it.

y = 2(x - 1)^2 - 9 is the equation of the parabola in vertex form

I hope this helps! Let me know if it is wrong

Solving for X the value is = 45, 6

acc to our question-

90/x=90/x+15+1/2

(15-x)90 - 90x/15x-x^2 = 5

x= 45 or 6

hence, for X the value is = 45, 6

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Using the z-score tables, the number of babies that weighed more than 10 pounds is; 43

A probability distribution that can be considered to be symmetric about the mean is the normal distribution, which can often be referred to as the Gaussian distribution. This depicts to us the concept of data being close to the mean occurring more often than data that are considered far from the mean. The normal distribution usually has a bell curve graph.

We are given that;

The total number of babies is 908.

Mean of the normal distribution is 7.2 pounds.

Standard deviation of the normal distribution is 1.5 pounds.

The formula of z score is given by;

z = (x - μ)/σ

where;

x is sample mean

μ is population mean

σ is standard deviation

We are given that;

x = 10

μ = 1.5

σ = 7.2

Thus;

z = (10 - 7.2)/1.5

z = 1.86667

The P-value from Z-Table gives us:

P(x > 10) = 1 - P(x < 10) = 0.030974

The number of babies that weighed more than 10 pounds is;

(0.030974 × 908) ≈ 43

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The equation that shows the relationship between the number of hours Jack's crew works, x, and the total number of yards of pavement laid, y will be;

⇒ y = 40 + 15x

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

Sanjay and his paving crew laid 40 yards of new pavement.

And, They can lay 15 yards of new pavement per hour.

Now,

Let the number of hours Jack's crew works = x

And, The total number of yards of pavement laid = y

Hence, We can formulate;

An equation that shows the relationship between x and y will be;

y = 15x + 40

Thus, The equation that shows the relationship between the number of hours Jack's crew works, x, and the total number of yards of pavement laid, y will be;

⇒ y = 40 + 15x

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According to the following frequency table, the mean of the number points deducted from each student on an economics is 5.1

Frequency table:

Frequency table means the method of organizing raw data in a compact form by displaying a series of scores in ascending or descending order, together with their frequencies—the number of times each score occurs in the respective data set.

Given,

Here we need to determine the mean of the number of points deducted from each student on an economics test given in the follow grouped frequency table.

For the given table of data, the frequency table of the data is attached below.

In order to find the mean of the frequency table we have to use the following values,

The total frequency is 204

And the number of frequency is 40.

So, the mean is

=> 204/40

=> 5.1

Therefore, the mean of the data is 5.1

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The surface area of the cylinder in term of π is 6764πmm^2

A cylinder is a three-dimensional solid that contains two parallel bases connected by a curved surface. The bases are usually circular in shape. The perpendicular distance between the bases is denoted as the height “h” of the cylinder and “r” is the radius of the cylinder.

The total surface area of a cylinder is 2πr(r+h)

Where r is the radius and h is the height of the cylinder

therefore T.S.A= 2×38π(38+51)

T.S.A=76π×89

The total surface area(T.S.A) of the cylinder =6764πmm^2

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₁₁C₈ * ₄C₃ as related to permutations is ₁₁P₈ / 8! * ₄P₃ / 3!

The term combination refers to a method of choosing where order does not matter. an instance forming 3 letter word from ABC. the combination is ₃C₃ = 1

In permutation, order matters hence in choosing or making selection specific order should be followed. an instance here is arranging the 3 letters word from ABC. ₃P₃ = 6

All the items above are different permutations however for combination they are same.

The difference mathematically is dividing by the number of arrangements

₃C₃ = 3! / (3!(3-3)!) = 3! / (3!* 0!) = 3! / 3! = 1

₃P₃ = 3! / (3-3)! = 3! / (0!) = 3! / 1 = 3! = 6

Therefore ₃C₃ = ₃P₃ / 3!

similarly

₁₁C₈ * ₄C₃ = ₁₁P₈ / 8! * ₄P₃ / 3!

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The following relation are said to be the functions:

{(-5, 1), (-2, 0), (-1, 1), (2, 4), (6,3)}

Relation:

Relation in math is a set of ordered pairs defining the relation between two sets.

Given,

Here we have the following relation

{(-5, 1), (-5, 0), (-2, 1), (-1, 4), (6, 2)}

{(-5, 1), (-2, 0), (-2, 2), (3, 4), (6, 2)}

{(-5, 1), (-2, 0), (-1, 1), (2, 4), (6,3)}

{(-5, 3), (-2, 0), (-1, 2), (6, 4), (6,3)}

Now, we need to identify the which relations are the functions.

We know that the function means the relation in math such that each element of the domain is related to a single element in the codomain.

While we check this condition with each relation then we get,

{(-5, 1), (-5, 0), (-2, 1), (-1, 4), (6, 2)}

This one is not a relation because here -5 take two output values.

{(-5, 1), (-2, 0), (-2, 2), (3, 4), (6, 2)}

This one is not a relation because here -2 take two output values.

{(-5, 1), (-2, 0), (-1, 1), (2, 4), (6,3)}

This one is a function because each domain has exactly one co domain

{(-5, 3), (-2, 0), (-1, 2), (6, 4), (6,3)}

This one is not a relation because here -6 take two output values.

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Answer:

Step-by-step explanation:

x²-4x+2=0

x²-4x=-2

x²-4x+4=-2+4

(x-2)²=2

x-2=±√2

x=2±√2

x=2+√2≈2+1.41≈3.41

x=2-√2≈2-1.41≈0.59

so roots lie between 0 and 4.

The Required Factors   (x + 1) (x - 3 ) (x + 2) (x - 2).

Given equation.
x^4 - 2x^3 - 7x^2+8x+12 = 0

Factors : factor is a number that divides another number, leaving no remainder. In other words, if multiplying two whole numbers gives us a product, then the numbers we are multiplying are factors of the product because they are divisible by the product.

polynomial : an expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable

Now, factorize the polynomial of degree 4 as follows.

= (x + 1) (x - 3) (x^2 - 4)

Then, again factorize polynomial of degree 2.

Therefore  (x + 1) (x - 3 ) (x + 2) (x - 2)

This is the required factors.

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The exponential function giving the concentration after t hours is given as follows:

[tex]C(t) = 0.00372(0.9359)^t[/tex]

The standard modelling of an exponential function is presented as follows:

[tex]y = a(b)^x[/tex]

The meaning of the variables of the equation are given as follows:

The initial value of the exponential function is given as follows:

a = 0.00372.

After eight hours, the concentration is given as follows:

C(8) = 0.00219.

Hence the rate of change is obtained as follows:

[tex]C(t) = 0.00372b^t[/tex]

[tex]0.00219 = 0.00372b^8[/tex]

[tex]b^8 = \frac{0.00219}{0.00372}[/tex]

[tex]b = \sqrt[8]{\frac{0.00219}{0.00372}}[/tex]

[tex]b = \left(\frac{0.00219}{0.00372}\right)^{\frac{1}{8}}[/tex]

b = 0.9359.

Hence the equation is:

[tex]C(t) = 0.00372(0.9359)^t[/tex]

The problem is given by the image at the end of the answer, and it asks for the exponential function modelling the situation.

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If the temperatures on Earth continue to increase, the change in the pie graph would be C. Less than 2% of the Earth's water will be in polar ice caps.

The temperature of Earth has risen significantly in the last century as a result of human activity. This had led to the loss of polar ice caps due to them having melted into the oceans from the high temperatures.

This means that if the temperature of the planet should continue to increase, the polar ice caps we have will further be depleted. This would lead to less than 2% of the Earth comprising polar ice caps as is the case now.

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Answer:

27w+2=19w+6

27w+19w=6+2

w(27+19)=8

w(27+19)/27+19=8/27+19

w=8/(27+19)

3-3(9x²+15x-15x+25)-4(6x²+9x-4x+6)

3-27x²-75-24x²-20-24

3-51x²-119

-116-51x²

The width of a rectangle is (7x+y) meters.

What is the area of a rectangle?

A flat surface of a specific shape can be thought of as the area it occupies in space. In terms of the "number of" square units, it is measured (square centimeters, square inches, square feet, etc.) The number of unit squares that can fit inside a rectangle is the area of that shape. The flat surfaces of laptop monitors, chalkboards, canvases, and other objects are a few instances of rectangular shapes.

Area of the rectangle is = (7[tex]x^{2}[/tex]+8xy+[tex]y^{2}[/tex]) square meter

length of the rectangle is = (x+y) meters

we know, the area of the rectangle= length×width

So, the width of the rectangle = (7[tex]x^{2}[/tex]+8xy+[tex]y^{2}[/tex])/(x+y) meters

=(7x+y)(x+y)/(x+y) meters

=(7x+y) meters

Hence, The width of a rectangle is (7x+y) meters.

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Answer:

13

Step-by-step explanation:

56/7 = 8

13 - 5 = 8

15/7 = 13 - 5

The missing number in the expression is 13.

We have,

To find the missing number in the equation 56 / 7 =? - 5, solve for the unknown value.

Unknown value = x

Starting with the equation 56 / 7 = x - 5, simplify the left side:

56 / 7 = x - 5

8 = x - 5

x = 8 + 5

x = 13

Thus,

The missing number in the expression is 13.

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Answer:

$22,106.28

Step-by-step explanation:

[tex]CI=P(1+(\frac{r}{12}) )^{12t}[/tex], where [tex]P[/tex] is the principal, [tex]r[/tex] is the interest rate in decimal form, and [tex]t[/tex] is the time in years.

[tex]CI=\$11000.00(1+(\frac{0.07}{12}) )^{12(10)}[/tex]

[tex]CI=\$22106.28[/tex]

Answer: 9.57

Step-by-step explanation:

do 9 - -0.87 first.

that will give you 9.87

then you subtract 0.3

final answer: 9.57

Answer:

92

Step-by-step explanation:

3+3=6

Zach's investment is $100,000.

A ratio shows us the number of times a number contains another number.

Given that Zach, Kolby, and Peyton are investing a total of $350,000 to open a coffee shop. And their investments are in the ratio 1:2:0.5, respectively.
Therefore, Zach, Kolby, and Peyton's investment can be written as  1x, 2x, and 0.5x, respectively.

Now, the total sum of the investment of the three can be written as,

Zach's investment + Kolby's investment + Peyton's investment = $350,000

1x + 2x + 0.5x = $350,000

3.5x = $350,000

x = $350,000 / 3.5

x = 100,000

Further, Zach's investment can be written as,

Zach's investment = 1x = 1($100,000) = $100,000

Hence, Zach's investment is $100,000.

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Using the t-distribution, it is found that:

a)

b)

The bounds of the confidence interval are given according to the rule presented as follows:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

In which the variables of the equation are listed as follows:

The margin of error of the interval is:

[tex]M = t\frac{s}{\sqrt{n}}[/tex]

Then the interval can be interpreted as the sample mean plus/minus the margin of error.

For the confidence interval in this problem, using a calculator, the parameters are given as follows:

[tex]\mu = 1280.1111, s = 33.5799, n = 9[/tex]

The critical value, using a t-distribution calculator, for a two-tailed 90% confidence interval, with 9 - 1 = 8 df, is t = 1.86.

Then the margin of error of the interval is:

M = 1.86 x 33.5799/sqrt(9) = 21.

Then the bounds of the interval are:

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