In each of the following cases, work is done as follows:
What is work?
Work is a term used in physics to describe the transfer of energy from one system to another. Work is done when a force is applied to an object, causing it to move a certain distance in the direction of the force.
a) A physics student works tirelessly on this homework assignment: No work is done in this scenario as work is defined as the transfer of energy from one system to another. Writing a homework assignment does not involve the transfer of energy from one system to another.
b) An elevator takes you from the 1st to the 3rd floor of Suncoast, and returns to the 1st floor: Work is done in this scenario as the elevator moves against the force of gravity, lifting the people and its own weight from the 1st to the 3rd floor, and then back to the 1st floor.
c) A link pulls a block 10 m across the floor of a temple at constant speed: Work is done in this scenario as the link exerts a force on the block, causing it to move in the direction of the force, covering a distance of 10 m.
d) A guy pushes the wall with all his strength: No work is done in this scenario as work is defined as the transfer of energy from one system to another. Pushing the wall does not result in the transfer of energy from one system to another, and the wall does not move.
e) A student picks up a textbook from the ground: Work is done in this scenario as the student lifts the textbook against the force of gravity, causing the textbook to gain potential energy.
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describe the relationship between frequency and energy as you move through all parts of the electromagnetic spectrum.
In electromagnetic spectrum, the frequency and energy of electromagnetic waves increase.
The electromagnetic spectrum includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. At the lowest end of the spectrum, radio waves have low frequency and low energy, while at the highest end, gamma rays have high frequency and high energy.
The relationship between frequency and energy can be described by the equation E = hf, where E is energy, h is Planck's constant, and f is frequency. As frequency increases, energy increases proportionally, and this relationship is consistent throughout the electromagnetic spectrum.
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The probability of fusion occurring is greatly enhanced when appropriate nuclei are brought close together, but mutual Coulomb repulsion must be overcome. This can be done using the kinetic energy of hightemperature gas ions or by accelerating the nuclei toward one another. (a) Calculate the potential energy of two singly charged nuclei separated by 1.00 x 10^-12. (b) At what temperature will atoms of a gas have an average kinetic energy equal to this needed electrical potential energy?
Electric potential energy = 8.99 x 10^-3 J and the temperature T = 2.01 x 10^7 K
What is the potential energy between two singly charged nuclei separated by a distance of 1.00 x 10^-12 m? Use Coulomb's constant (k= 8.99 x 10^9 N m^2/C^2) and assume the charges of the nuclei are +1. ?
where k is Coulomb's constant (k = 8.99 x 10^9 N m^2/C^2), q1 and q2 are the charges of the two nuclei (each with a charge of +1 since they are singly charged), and r is the separation distance between the nuclei (1.00 x 10^-12 m).
(a) The potential energy of two singly charged nuclei separated by a distance of 1.00 x 10^-12 m can be calculated using the Coulomb potential energy equation:
Electric potential energy = (k * q1 * q2) / r
where k is Coulomb's constant (k = 8.99 x 10^9 N m^2/C^2), q1 and q2 are the charges of the two nuclei (each with a charge of +1 since they are singly charged), and r is the separation distance between the nuclei (1.00 x 10^-12 m).
Plugging in the values, we get:
Electric potential energy = (8.99 x 10^9 N m^2/C^2) * (+1 C) * (+1 C) / (1.00 x 10^-12 m)
Electric potential energy = 8.99 x 10^-3 J
Therefore, the potential energy of two singly charged nuclei separated by a distance of 1.00 x 10^-12 m is 8.99 x 10^-3 J.
(b) We can use the average kinetic energy equation to find the temperature at which atoms of a gas will have an average kinetic energy equal to the electrical potential energy calculated in part (a):
(1/2)mv^2 = (3/2)kT
where m is the mass of a gas atom, v is the root-mean-square velocity of the atoms, k is Boltzmann's constant (k = 1.38 x 10^-23 J/K), and T is the temperature.
To solve for T, we can rearrange the equation:
T = (1/3)mv^2 / k
The mass of a gas atom can be approximated using the molar mass of the gas and Avogadro's number. Let's assume we are considering helium gas, which has a molar mass of approximately 4.00 g/mol. This is equivalent to approximately 6.64 x 10^-27 kg per helium atom.
The root-mean-square velocity of gas atoms can be found using the equation:
v = sqrt((3kT) / m)
We want to find the temperature at which the average kinetic energy of helium gas atoms is equal to the electrical potential energy calculated in part (a), so we can set (1/2)mv^2 equal to 8.99 x 10^-3 J:
(1/2)mv^2 = 8.99 x 10^-3 J
Substituting in the values for m and v, we get:
(1/2) * (6.64 x 10^-27 kg) * [(sqrt((3kT) / m))^2] = 8.99 x 10^-3 J
Simplifying, we get:
sqrt(3kT / m) = sqrt(2 * 8.99 x 10^-3 J / 6.64 x 10^-27 kg)
sqrt(3kT / m) = 2427.5 m/s
Squaring both sides, we get:
3kT / m = (2427.5 m/s)^2
Solving for T, we get:
T = (m / 3k) * (2427.5 m/s)^2
Substituting in the values for m and k, we get:
T = (6.64 x 10^-27 kg / (3 * 1.38 x 10^-23 J/K)) * (2427.5 m/s)^2
T = 2.01 x 10^7 K
therefore the temperature was found to be about T = 2.01 x 10^7 K
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After which action would the concentration of a solution remain constant?(1 point)
removing solution from the container
adding water to the solution
evaporating water from the container
adding solute to the solution
Answer:
The action that would cause the concentration of a solution to remain constant is removing solution from the container.
What is concentration of a solution?
The concentration of a solution is the measure of the amount of solid particles (solute) that has been dissolved in the given amount of a solvent.
Adding water to a solution will dilute the solution, hence changes the concentration of the solution.
Also, adding solute will change the concentration of the solution.
Thus, the action that would cause the concentration of a solution to remain constant is removing solution from the container.
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PLS ANSWERRR What are the main differences between the carbon flows 300 years ago and today?
The main differences between the carbon flow 300 years ago and today are the amount of carbon dioxide released into the atmosphere and the sources of those emissions.
300 years ago, the majority of carbon emissions came from natural sources, such as volcanic eruptions and forest fires. However, today, the majority of carbon emissions come from human activities, such as burning fossil fuels for energy and deforestation for agriculture and urbanization. Additionally, the amount of carbon dioxide released into the atmosphere has greatly increased in the past 300 years due to the industrialization of society and the increase in the human population. This has led to an increase in greenhouse gases in the atmosphere and has contributed to climate change.
In summary, the main differences between the carbon flow 300 years ago and today are the sources of emissions and the amount of carbon dioxide released into the atmosphere.
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light is traveling from plastic into air. at the interface some of the light is reflected. how does the reflected wave compare to the incident wave?
When light travels from plastic into the air, some of the light is reflected at the interface between the two media. The reflected wave is characterized by a few key differences compared to the incident wave.
Firstly, the reflected wave is inverted with respect to the incident wave, meaning that it is flipped upside down.
Furthermore, the abundance of the reflected wave is by and large more modest than that of the occurrence wave.
This is because some of the energy of the wave is absorbed or scattered as it interacts with the interface between the plastic and air.
Lastly, the reflected wave is shifted in phase compared to the incident wave. The amount of phase shift depends on the angle of incidence and the refractive indices of the two media.
In summary, the reflected wave that occurs when light travels from plastic into the air is inverted, has a smaller amplitude, and is shifted in phase compared to the incident wave.
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a 70.0 kg person rides in an elevator while standing on a scale. the elevator is traveling downward and speeding up at a rate of 2.50 m/s2 . the reading on the scale is closest to
Reading on the scale will be closest to 861.7 N which can be calculated using Newton's 2nd Law of Motion.
The reading on the scale will depend on the force acting on the person in the elevator. We can calculate this force by using Newton's second law of motion, which states that force equals mass times acceleration (F = ma).
In this case, the force acting on the person is the sum of their weight (mg) and the force due to the acceleration of the elevator (ma). The direction of the acceleration is downward, so we can take it as negative. Net force:
Fnet = mg - ma
where m is the mass of the person, g is the acceleration due to gravity (9.81 m/s^2), and a is the acceleration of the elevator (-2.50 m/s^2).
Substituting the given values, we have:
Fnet = (70.0 kg)(9.81 m/s^2) - (70.0 kg)(-2.50 m/s^2)
Fnet = 686.7 N + 175 N
Fnet = 861.7 N
Therefore, the reading on the scale will be closest to 861.7 N. Note that this is greater than the person's weight (686.7 N) because the elevator is accelerating downward, creating an additional force on the person.
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a smooth metal plate with a surface area of 380 cm2 is traveling in water at a velocity of 6.3 m/s, with the flow parallel to the long dimension of the surface. if the reynolds number at the trailing edge of the plate is 950,000, what is the friction drag acting on the surface of the plate?
The friction drag acting on the surface of the plate is approximately 0.074 N.
The friction drag acting on the surface of the plate can be calculated using the following formula:
[tex]$F_D = \frac{1}{2} \rho V^2C_D A$[/tex]
where \rho is the density of water,
V is the velocity of the plate relative to the water,
C_D is the drag coefficient, and
A is the surface area of the plate.
To determine the drag coefficient C_D.
We need to know the Reynolds number of the flow.
For a flat plate, the drag coefficient can be estimated using the following formula for laminar flow:
[tex]$C_D = \frac{1.328}{\sqrt{Re_x}}$[/tex]
where Re_x is the Reynolds number based on the distance from the leading edge of the plate to the point of interest (in this case, the trailing edge).
For turbulent flow, we can use the following formula for the drag coefficient:
[tex]$C_D = \frac{0.074}{Rex^{1/5}}[/tex]
The critical Reynolds number for a flat plate is around 5,000, above which the flow is typically turbulent.
In this case, the Reynolds number of 950,000 indicates that the flow is definitely turbulent.
To calculate the drag coefficient, we need to use the turbulent flow formula:
[tex]$C_D = \frac{0.074}{Rex^{1/5}}[/tex]
[tex]= \frac{0.074}{(380 \times 6.3 / \nu)^{1/5}}[/tex]
where nu is the kinematic viscosity of water at the given temperature.
Assuming a temperature of 25°C, the kinematic viscosity of water is approximate nu = 8.85* [tex]10^{-7}[/tex] [tex]m^2\\[/tex]/s.
Plugging in the values, we get:
[tex]C_D = \frac{0.074}{(380 \times 6.3 / 8.85 \times )^{1/5}}[/tex] approx 0.0093
Finally, we can calculate the friction drag:
[tex]F_D = \frac{1}{2} \rho V^2 C_D A\\ = \frac{1}{2} \times 1000 \times 6.3^2 \times 0.0093 \times 0.0038\\ \approx. 0.074N[/tex]
Therefore, the friction drag acting on the surface of the plate is approximately 0.074 N.
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what is the maximum speed vmax that the cylinder can move along its circular path without slipping off the turntable? express your answer numerically in meters per second to two significant figures.
The centripetal force causes angular or circular motion by pulling or pushing an item in the direction of the centre of a circle as it moves.
What is the main role of centripetal force?Rotating is the process of an object moving in a circular path. The centripetal force exerts a push perpendicular to the velocity of the item in the direction of the curve's centre. The object's velocity changes direction due to the centripetal force, even while its speed is unaltered.
Work can only be done by the force component that is acting in the direction of motion. Without such a component, the centripetal force is incapable of doing work.
[tex]F_c =F_f[/tex]
[tex]mv2/r = \mu mg[/tex]
Vmax = √(μgr)
Vmax =√(0.08×9.81×0.15)
Vmax [tex]=0.343m/s[/tex]
Therefore, 0.343 m/s Maximum speed occurs when centripetal force equal to frictional force.
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The above question is incomplete. The complete question is given below:
A small metal cylinder rests on a circular turntable that is rotating at a constant speed, as illustrated in the diagram (Figure 1) . The small metal cylinder has a mass of 0.20 kg , the coefficient of static friction between the cylinder and the turntable is 0.080, and the cylinder is located 0.15m from the center of the turntable. Take the magnitude of the acceleration due to gravity to be 9.81m/s^2 .
What is the maximum speed Vmax that the cylinder can move along its circular path without slipping off the turntable?
two children with masses of 22 kg and 38 kg are sitting on a balanced seesaw. if the heavier child is sitting 0.45 m from the center, at what distance from the center is the lighter child sitting?
A seesaw is one type of lever, and it features a long beam attached to a pivot known as the fulcrum. The beam drops to the ground as soon as you sit on one side of it and put weight on one of its ends.
is the distance from the center is the lighter child sitting.
What is the balanced seesaw?The seesaw maintains its balance if the total torques that drive it to revolve in one direction—clockwise—equal the total torques that cause it to rotate in the opposite—counterclockwise. For an object at rest with no net forces acting on it, this is analogous to Newton's First Law.
This is due to the weight of your body being pulled downward by the force of gravity as well as the beam.
Two children with masses of 22 kg and 38 kg are sitting on a balanced seesaw, the heavier child is sitting 0.45 m,
the force by both, as shown below,
the distance as the seesaw is in equilibrium,
Therefore, is the distance from the center is the lighter child sitting.
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Rolling railroad car a collides inelastically with railroad car b of the same mass, which is initially at rest. If the two cars stick together after the collision, how does their speed after the collision compare with the initial speed of car a ?
The final velocity of the two cars after they stick together is half the initial velocity of car a. In other words, their speed after the collision is half the initial speed of car a.
In an inelastic collision, the two objects stick together after the collision and move together with a common final velocity. In this case, the rolling railroad car a collides inelastically with railroad car b of the same mass, which is initially at rest.
Let's assume that the initial velocity of car a is v and the mass of each car is m. Since car b is initially at rest, its initial velocity is 0.
Using the law of conservation of momentum, we can write:
(momentum before collision) = (momentum after collision)
mv + 0 = (m + m)vf
where vf is the final velocity of the two cars after they stick together.
Simplifying the equation, we get:
vf = v/2
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a 1000-kg car experiences a net force of 9500 n while slowing down from 30 m/s to how far does it travel while slowing down?
By using the kinematic equation that relates the distance traveled by an object to its initial velocity, final velocity, acceleration, and time the car travels a distance of 450 meters while slowing down from 30 m/s.
What is a kinematic equation?A kinematic equation is a mathematical equation that relates the motion of an object to its position, velocity, acceleration, and time. These equations are derived from the principles of classical mechanics and are used to describe the motion of objects in a variety of physical contexts.
The most commonly used kinematic equations are those that describe the motion of an object with constant acceleration, which can be derived from the equations of motion of a particle under constant acceleration. These equations are:
v_f = v_i + at (the equation that relates the final velocity v_f, the initial velocity v_i, the acceleration a, and the time t)d = v_i*t + (1/2)at^2 (the equation that relates the displacement d, the initial velocity v_i, the acceleration a, and the time t)v_f^2 = v_i^2 + 2ad (the equation that relates the final velocity v_f, the initial velocity v_i, the acceleration a, and the displacement d)To calculate the distance covered by the car while slowing down:
Using Kinematic equation,
d = (v_f^2 - v_i^2 ) / (2a)
where:
d is the distance traveled
v_i is the initial velocity
v_f is the final velocity
a is the acceleration
In this case, the car is slowing down, so the acceleration is negative. We can calculate the acceleration using Newton's second law:
F_net = ma
where F_net is the net force, m is the mass of the car, and a is the acceleration. Solving for a, we get:
a = F_net / m = 9500 N / 1000 kg = 9.5 m/s^2 (in the opposite direction of the initial motion)
Now we can substitute the values into the kinematic equation:
d = (v_f^2 - v_i^2) / (2a) = (0 m/s - 30 m/s)^2 / (2(-9.5 m/s^2)) = 450 m
Therefore, the car travels a distance of 450 meters while slowing down from 30 m/s.
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1. find the distance between a 0.300 kg billiard ball and a 0.400 kg billiard ball if the magnitude of the gravitational force between them is 8.92 x 10-11 n.
The distance between two pool balls are separated by 0.0424 m.
By gravitational force, what do you mean?The gravitational pull draws any two mass-containing things together. It mentions the gravitational force. The force will always be applied along the line joining the two masses in the direction of the other mass, according to the formula F=Gm1m2r2.
The following formula can be used to determine the gravitational force between two objects:
F = G * (m1 * m2) / r²
where F is the gravitational force's strength, G is the gravitational constant (6.67 x 10-11 N×m2/kg), m1 and m2 are the objects' masses, and r is the separation between them.
To determine the separation between the two pool cues To account for r, we can rearrange this expression as follows:
Represents the objects' masses, while r denotes the separation between their mass centres.
Rearranging this formula to solve for r will allow us to get the distance between the two pool balls:
r = √(G × m1 × m2 / F)
Substituting the given values, we get:
r = √(6.67 x 10⁻¹¹ N*m²/kg² × 0.300 kg × 0.400 kg / 8.92 x 10⁻¹¹ N)
r = 0.0424 m
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Help now please! I don't really understand the question and would be very grateful for some clarification.
El Toro is the third tallest wooden roller coaster in the world. It has a drop of 55 meters. One empty cart has a mass of 958 kg and 511,000 J of kinetic energy when it reaches the base level of the track. How much energy is converted into heat when the cart is at the base level of the track? Show your work.
The amount of energy converted into heat when the cart is at the base level of the track is approximately 7490 J.
What is kinetic energy?The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it.
Kinetic energy:
E = mgh
E = (958 kg) x (9.81 m/[tex]s^2[/tex]) x (55 m) = 5.26 x [tex]10^5[/tex] J
E = KE + Q
KE is the kinetic energy of the cart and Q is the energy converted into heat. Substituting the given value for the kinetic energy, we get:
5.26 x [tex]10^5[/tex] J = 511,000 J + Q
Solving for Q, we get:
Q = 5.26 x [tex]10^5[/tex] J - 511,000 J = 7490 J
Thus, 7490 J energy is converted into heat.
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suppose that the cable from a to b must exert a 8500 n horizontal force on the car to hold it in place. determine the car's weight and also mass in kg
The car's weight and mass in kg if cable from a to b must exert a 8500 n horizontal force on the car to hold it in place is 14722N and 1502.24 kg.
Believe or not, weight is the force that the earth Earth is acting on you. The gravitational acceleration which is multiplied to the mass is deduced by using the equation of Newton's law of solemnity similar that one mass is the mass of the earth Earth.
The free body diagram is shown to the right
Applying the equilibrium equation
[tex]\sum F_s = T- Nsin30\degree = 0\\\\\sumF = Ncos30 - mg = 0\\[/tex]
Setting T = 8500N and solving the equation we get,
N = 17000N
mg = 14722 N
So weight = 14722 N
and mass = 14722/g = 14722/9.8 = 1502.24 kg
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assume that the particle in the picture is a proton. if an electron is projected at point 1 with the same velocity v, it will not follow the same path as the proton, unless the magnetic field is adjusted. explain how the magnitude and direction of the field must be changed.
Since the electron has a smaller mass than the proton, it will experience a larger deflection due to the same magnetic field. Increasing the magnitude of the field compensates for this and ensures that the electron follows a circular path with the same radius as the proton.
Reversing the direction of the magnetic field is necessary because the Lorentz force on the electron is in the opposite direction to that on the proton due to its negative charge. By changing the direction of the field, the force on the electron will be in the same direction as the force on the proton, allowing it to follow the same circular path.
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The table above shows the data that Mendel collected about the offspring of
his second set of crosses. What is the median of the number of trials he
performed?
The table above shows the data that Mendel collected about the offspring of his second set of crosses therefore the median of the number of trials he performed is 1,181 and is therefore denoted as option A.
What is Median?This is referred to as the middle number in a sorted, ascending or descending list of numbers.
In this scenario there were five trials which are 1064, 7324, 8003, 1181 and 929. When it is arranged in an ascending order we have:
929 , 1064 , 1181 , 7324 , 8003
Therefore the median number is 1181.
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(ii) Atmospheric pressure on that day is 1.0 x 10^5Pa
Calculate the total pressure at the bottom of the pond
Answer:
Explanation:Force applied by atmosphere = atmospheric pressure × ares of table
F=P×A
F=1.013×[tex]10^{5}[/tex] ×(2×1)=2.026×[tex]10^{5}[/tex]N
a parallel-plate capacitor has 2.00-cm2 plates that are separated by 5.00 mm with air between them. (a) if a 12.0-v battery is connected to this capacitor, how much energy does it store? (b) if a dielectric with a constant of 2.56 were inserted between the plates with the battery attached, what would the energy stored become? (c) repeat (b) for the case where the battery had been disconnected before dielectric insertion.
a) The energy stored in the capacitor is 5.10 × 10⁻¹⁰ J.
b) The energy stored in the capacitor with the dielectric inserted is 1.04 × 10⁻⁹ J.
c) The energy stored in the capacitor with the dielectric inserted and the battery disconnected is 2.14 × 10⁻¹⁰ J.
The energy stored in a parallel-plate capacitor is given by the formula:
U = [tex]\frac{1}{2}CV^2[/tex]
where U is the energy stored, C is the capacitance, and V is the voltage across the capacitor.
(a) The capacitance of a parallel-plate capacitor is given by the formula:
C = [tex]\frac{\epsilon_0A}{d}[/tex]
where [tex]\epsilon_0[/tex] is the permittivity of free space, A is the area of the plates, and d is the distance between them.
Substituting the given values, we have:
C =[tex]\frac{(8.85 \times 10^{-12} \textrm{ F/m})(2.00 \times 10^{-4} \textrm{ m}^2)}{5.00 \times 10^{-3} \textrm{ m}} = 7.08 \times 10^{-12} \textrm{ F}[/tex]
The voltage across the capacitor is given by the battery voltage, which is 12.0 V. Substituting these values into the formula for energy, we have:
U = [tex]\frac{1}{2}(7.08 \times 10^{-12} \textrm{ F})(12.0 \textrm{ V})^2 = 5.10 \times 10^{-10} \textrm{ J}[/tex]
(b) When a dielectric is inserted between the plates, the capacitance increases. The new capacitance is given by the formula:
[tex]C' = \kappa C[/tex]
where [tex]\kappa[/tex] is the dielectric constant of the material.
Substituting the given values, we have:
[tex]C' = (2.56)(7.08 \times 10^{-12} \textrm{ F}) = 1.82 \times 10^{-11} \textrm{ F}[/tex]
The voltage across the capacitor remains the same, so the energy stored in the capacitor becomes:
[tex]U' = \frac{1}{2}(1.82 \times 10^{-11} \textrm{ F})(12.0 \textrm{ V})^2 = 1.04 \times 10^{-9} \textrm{ J}[/tex]
(c) If the battery is disconnected before the dielectric is inserted, the charge on the plates remains the same. However, the voltage across the capacitor decreases due to the increased capacitance. The new voltage is given by the formula:
[tex]V' = \frac{V}{\kappa}[/tex]
Substituting the given values, we have:
[tex]V' = \frac{12.0 \textrm{ V}}{2.56} = 4.69 \textrm{ V}[/tex]
The energy stored in the capacitor becomes:
[tex]U' = \frac{1}{2}(1.82 \times 10^{-11} \textrm{ F})(4.69 \textrm{ V})^2 = 2.14 \times 10^{-10} \textrm{ J}[/tex]
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Water is pumped from a large reservoir to a point 20 m higher than the reservoir.
Calculate the pump head if 0.01 m3/s flows through a 0.15 m diameter pipe and the
total frictional head loss is given to be 35^2/2g?
The pump head is -42.065 m
Since the pump head is negative, the pump is unable to push the water to the height of 20 m, and additional work must be done to overcome the frictional losses in the pipe.
How The Pump Head Calculation Was DoneThe pump head is equal to the total head minus the frictional head loss. The total head can be calculated as follows:
h_total = h_static + h_dynamic
where h_static is the static head, which is equal to the difference in height between the reservoir and the point 20 m higher, and h_dynamic is the dynamic head, which is a measure of the pressure generated by the flow of water.
h_static = 20 m
To calculate the dynamic head, we need to first calculate the velocity of the water in the pipe. We can use the equation of continuity, which states that the flow rate through a pipe must remain constant along its length.
Q = A * v
where Q is the flow rate (0.01 m^3/s), A is the cross-sectional area of the pipe (pi * (d/2)^2), and v is the velocity of the water.
A = pi * (0.15/2)^2 = 0.00176 m^2
v = Q / A = 0.01 / 0.00176 = 5.68 m/s
Next, we can calculate the dynamic head using the Bernoulli equation:
h_dynamic = (v^2) / (2g)
where g is the acceleration due to gravity (9.8 m/s^2).
h_dynamic = (5.68^2) / (2 * 9.8) = 16.06 m
Finally, we can calculate the total head:
h_total = h_static + h_dynamic
= 20 + 16.06
= 36.06 m
The pump head is then:
h_pump = h_total - h_friction
= 36.06 - (35^2) / (2 * 9.8)
= 36.06 - 78.125
= -42.065 m
Since the pump head is negative, it means that the pump is unable to lift the water to the desired height of 20 m, and additional work must be done to overcome the frictional losses in the pipe.
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the work done to compress a gas is 74 j. as a result, 26 j of heat is given by the system to the surroundings. what is the change in the internal energy of the gas?
The change in the internal energy of the gas is 100 J and this calculation assumes that the system is closed and no other forms of energy are involved.
The change in the internal energy of a system can be calculated using the First Law of Thermodynamics: ΔU = Q - W where ΔU is the change in internal energy of the system, Q is the heat added to the system, and W is the work done by the system. In this case, the work is done on the system (compressing the gas), so W is negative.
Given that the work done to compress the gas is 74 J and 26 J of heat is given by the system to the surroundings, we can substitute these values into the equation to get:
ΔU = Q - W
ΔU = 26 J - (-74 J)
ΔU = 26 J + 74 J
ΔU = 100 J
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one light-minute is the distance that light travels in one minute. how far is this, in kilometers? (recall that the speed of light is 300,000 km/s.)
One light-minute is approximately 18 million kilometers.
One light-minute is the distance that light travels in one minute, at the speed of light, which is approximately 300,000 km/s. we can simply multiply the speed of light by the number of seconds in one minute:
1 light-minute = 60 seconds x 300,000 km/s
1 light-minute = 18,000,000 km
Therefore, one light-minute is approximately 18 million kilometers.
Light is an electromagnetic wave that travels through space at a constant speed of approximately 300,000 km/s. This means that in one second, light can travel a distance of 300,000 kilometers.
300,000 km/s x 60 seconds = 18,000,000 km
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a hamster runs at a speed of 13 centimeters per second in a wheel of radius 14 centimeters. a) what is the angular velocity of the wheel? (in radians/sec) incorrect radians/sec correctradians/sec no decimals allowed. b) how fast will the wheel spin in revolutions per minute? incorrect rev/min correctrev/min no decimals allowed.
The angular velocity of the wheel is 0.9286 radians/sec and the number of revolutions per minute is 8.84 rpm
The angular velocity of the wheel in radians per second is given by the formula:
ω = v/r where ω is the angular velocity in radians per second, v is the linear velocity in cm/s, and r is the radius of the wheel in cm.
Therefore, the angular velocity of the wheel is:
ω = 13 cm/s / 14 cm = 0.9286 radians/sec
To calculate the revolutions per minute (rpm), we use the formula:
rpm = ω * 60 / (2π)
where 2π is the number of radians in a full revolution.
Therefore, the wheel will spin at a rate of:
rpm = 0.9286 radians/sec * 60 / (2π) = 8.84 rpm
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When a car’s velocity is positive and its acceleration is also positive what is happening to the car’s overall motion?
When a car's velocity is positive and its acceleration is also positive, the car's overall motion is speeding up in a forward direction.
Velocity is the measure of an object's speed in a specific direction, while acceleration is the measure of how quickly an object's velocity changes over time. So, if both the velocity and acceleration are positive, the car's speed is increasing in the forward direction. This means that the car is moving faster and faster in a forward direction.
Likewise, it can be said that the automobile develops an accelerated movement.
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If two objects have different temperatures, in which direction will heat move? When will the heat stop moving?
Answer: When there are two objects of different temps, the heat will always move from the higher temp to the lower temp. The energy will stop moving when there is equilibrium, when both objects are at the same temperatures.
shows four equipotential surfaces. the positively charged particle located at point a can move to points b, c, or d by the paths indicated. along which path is the greatest work done on the particle by the electric field?
The depicted paths allow the positively charged particle at point a to travel to places b, c, or d. The electric field has the most influence over the particle along path a to b.
A charged particle is a particle that has an electric charge. The charge can be either positive or negative, and the unit of charge is the Coulomb. Charged particles can be found in nature and in man-made environments. For example, the nucleus of an atom contains positively charged protons, and electrons are negatively charged particles that orbit the nucleus. Other examples of charged particles include ions, which are atoms or molecules that have gained or lost one or more electrons, and free electrons, which are electrons that are not bound to an atom or molecule. Charged particles interact with electric and magnetic fields, and these interactions are fundamental to many areas of physics and engineering.
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The complete question is:
(Figure 1) shows four equipotential surfaces. The positively charged particle located at Point a can move to Points b, c, or d by the paths indicated. Along which path is the greatest work done on the particle by the electric field?
- Path a to b
- Path a to c
- The work done is equal along all three paths.
- Path a to d
what is the minimum possible diameter of the spot on the wall, defined as the diameter of the circle where the intensity is zero? (a) 2.03e-03 m
The minimum possible diameter of the spot on the wall is approximately 3.05e-4 mm or 2.03e-3 m.
The minimum possible diameter of the spot on the wall, also known as the diffraction spot or Airy disk, can be calculated using the formula:
d = 2.44 * λ * L / D
where λ is the wavelength of the light, L is the distance between the aperture and the wall, and D is the diameter of the aperture.
In this case, we are not given the wavelength or distance L, but we are given the diameter of the aperture, which is 0.4 mm or 4e-4 m. We can assume a typical visible light wavelength of 500 nm or 5e-7 m and a distance L of 1 m for this calculation.
d = 2.44 * 5e-7 m * 1 m / 4e-4 m
d = 3.05e-7 m or 3.05e-4 mm
Therefore, the minimum possible diameter of the spot on the wall is approximately 3.05e-4 mm or 2.03e-3 m.
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assume the speed of sound is 340 m/s and the two loudspeakers emit a tone with a frequency of 680 hz. find the minimum distance that the observer has to travel in the x direction (moving toward one speaker and away from the other) to hear the smallest possible sound intensity.
The minimum distance that the observer has to travel in the x direction to hear the smallest possible sound intensity is 0.25 meters.
The distance between adjacent minima is given by,
d = (λ/2) × (D/d)
where λ is the wavelength, D is the distance between the speakers, and d is the distance between the observer and nearest speaker.
The wavelength of the sound is given by,
λ = v/f
where v is the speed of sound and f is the frequency of the sound. Substituting the given values,
λ = 340/680 = 0.5 m
Distance between adjacent minima to solve for d,
d = λ/2 × (D/d)
d^2 = (λ×D)/2
d = sqrt(λ×D/2)
To find the minimum distance, minimize d. This occurs when d is equal to half the wavelength of the sound. Thus,
d = λ/2 = 0.25 m
Solve for D,
D = λ * (d/(λ/2))
D = 2d = 0.5 m
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a child holds a ball of mass m a distance h above the ground. in which system(s) is the force of gravity on the ball an internal force to the system?
The system in which the force of gravity on the ball an internal force to the system is Option B. system of the earth and the ball together.
Every object that has mass exerts a gravitational pull or force on every other mass. The strength of this pull depends on the millions of objects at play. graveness keeps the globes in route around the sun and the moon around the Earth. Hence, we define graveness as graveness is a force that attracts a body towards the centre of the earth or any other physical body having mass.
Originally, the direct instigation of the" ball earth" system is zero. So, according to the conservation of direct instigation, final direct instigation of the system must also be zero. therefore, if the ball moves overhead with some haste, the earth moves in downcast direction so as to conserve the instigation. Hence, the ball and the earth moves down from each other.
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Complete question:
A child holds a ball of mass m a distance h above the ground. In which system(s) is the force of gravity on the ball an internal force to the system? The system of just the ball.
The system of the earth and the ball together.
The system of the earth, the ball, and the child's hand.
The system of the earth, the ball, and the entire child.
23) if two equal charges, each of 1 c, were separated in air by a distance of 1 km, what would be the force between them?
So the force between the two charges would be 8.99 x 10^3 newtons.
define force ?
Force is a physical quantity that describes the interaction between objects or systems, causing a change in motion or deformation. It is typically measured in newtons (N) and is represented as a vector quantity with both magnitude and direction.
The force between two charges can be calculated using Coulomb's law:
F = kq1q2 / r^2
where k is Coulomb's constant (k = 8.99 x 10^9 N m^2/C^2), q1 and q2 are the charges of the two objects, and r is the distance between them.
In this case, q1 = q2 = 1 C, and r = 1 km = 1000 m. Plugging these values into the equation, we get:
F = (8.99 x 10^9 N m^2/C^2) * (1 C) * (1 C) / (1000 m)^2
= 8.99 x 10^3 N
So the force between the two charges would be 8.99 x 10^3 newtons.
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you measured the length, diameter and mass of two different cylinders. in both cases, you found that the length had 3 significant figures and that length was the measurement with the fewest number of significant digits. if you found the weight densities to be 38123 n/m3 and 38091 n/m3 and you round these values to the correct number of significant figures, can you conclude the two cylinders are made of the same material (do they have the same weight density)?
Weight Density 1 = 38107 N/m³
Weight Density 2 = 38107 N/m³
The formula for volume of cylinder is:
V = πr²l
where,
V = Volume
r = radius
l = length of cylinder
So, if length has the 3 significant figures which is least in all values, Then the volume must also be in 3 significant figures. The formula for weight density is:
Weight Density = Weight/Volume
Here, the volume has the least significant figures of 3, therefore, the weight densities must also have 3 significant figures:
Weight Density 1 = 38123 N/m³
Weight Density 1 = 38124 N/m³
Weight Density 1 = 38107 N/m³
Weight Density 2 = 38123 N/m³
Weight Density 2 = 38124 N/m³
Weight Density 2 = 38107 N/m³
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