Identify the compound that would have the highest osmotic pressure when dissolved in water. nacl k2so4 mgcl2 fecl3 mgso4

It take a larger partial pressure difference for oxygen to dissolve in plasma vs carbon dioxide because of its much higher solubility in plasma.

Partial pressure is defined as the pressure of anyone gas that arises in the container with more than one gas and each gas exert pressure. Partial pressure is calculated only for gases which is exist in the same volume.

Oxygen dissolve in plasma because oxygen exerts a certain amount of partial pressure. Plasma cannot carry much oxygen because of its solubility.

Thus from the above conclusion we can say that It take a larger partial pressure difference for oxygen to dissolve in plasma vs carbon dioxide because of its much higher solubility in plasma.

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0.6 mol / L is the molarity of a solution prepared by dissolving 36. 0 g of NaOH in enough water to make 1. 50 l of solution.

The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another term for molarity.

The ratio employed to indicate the solution's concentration is called its molarity. Understanding a solution's molarity is important since it allows you to determine the actual concentration as well as whether the solution is diluted or concentrated.

Amount of NaOH = 36. 0 g

Amount of water = 1. 50 L

1 mol of NaOH = 40 g,

Moles of NaOH = 36. 0 / 40 g = 0.9 mol NaOH

Molarity of a solution = moles of solute / Liters of solution

Molarity of a solution = 0.9 / 1.50

Molarity of a solution = 0.6 mol / L

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Typically, amides will hydrolyze under milder conditions than esters.

So, second option is correct one.

In acidic medium, amide interact with the water molecules to give a carboxylic aid and salt of ammonia or amine salt whereas in a basic medium, amides interacts with water molecules to give carboxylic aid and salt of ammonia or amine salt. An amides will hydrolyze under milder conditions because amide is least reactive than ester. The electronegativiy of nitrogen is less than oxygen. So, nitrogen transfer more electron cloud than oxygen towards carbonyl carbon. So, carbonyl group of amide hydrolysis in milder condition than ester.

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When a 45-minute road trip a vehicle emitted 16.7 g of nitrogen dioxide (NO₂) from its exhaust then the mass of nitrogen atoms in this amount of NO₂ would be 5.082 grams.

The chemical compound is a combination of two or more either similar or dissimilar chemical elements.

for example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom

The molecular mass of any compound is calculated by the sum of the mass of the individual atom

As given in the problem In a 45-minute road trip a vehicle emitted 16.7 g of nitrogen dioxide (NO₂) from its exhaust

The molecular mass of the NO₂ is the sum of the mass of the nitrogen atom and the oxygen atom.

The mass of the single nitrogen atom is 14, while the mass of the single oxygen atom is 16

the molecular mass of NO₂= mass of the N atom+2×(mass of O atom)

                                     = 14 + 2×16

                                     =46

As 46 grams of NO₂ contain 14 grams of Nitrogen

then 1 gram of NO₂ would  contain 14/46  grams of Nitrogen

then 16.7 grams of NO₂ would  contain (14/46×16.7)  grams of Nitrogen

The mass of a nitrogen atom in 16.7 grams of NO₂ would be 5.082 grams

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Answer:

Explanation to the following:

Na -k pumps couple atp hydrolysis with the transport of Na and k.

Both ions are used for active transport.

d. K+ and Na+ both diffuse into the cell along their concentration gradients and drive the transport of glucose.

Na/K pump is a pump located on the plasma membrane which uses ATP to move 3 Na ions out the cell and brings in 2 K ions into the cell. It is an example of primary active transport. As a consequence, concentration of Na is higher outside the cell, while K concentration is higher inside the cell.

Glucose is transported in the cell against its gradient, together with Na ions (symport) which move down their concentration gradient.

This is an example of secondary active transport because it uses the energy from the primary active transport to move other substances such as glucose against their own gradients.

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The resistance of the heating element is 21.61 Ω

Given

The power dissipated = 1500 W

Voltage = 180 V

We know that

Power = Voltage * Current

⇒ Power / Voltage = Current

⇒ 1500 W/180 V = Current

⇒ 8.33 A = Current

In order to calculate the resistance of the heating element. We Have to apply the formula

Power = (Current)^2 * Resistance

⇒ Resistance = Power / (Current)^2

⇒ Resistance = 1500 W/ (8.33) ^2

⇒ Resistance = 21.61 Ω

Hence the resistance of the heating element is 21.61 Ω

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The coefficient of performance (cop) of a refrigerator is defined as the ratio of " the work necessary to heat or cool something usefully."

The usable heating or cooling delivered to work required ratio, also known as the coefficient of performance, or COP, of a heat pump, refrigerator, as well as air conditioning system. Higher efficiency, less energy (power) usage, and thus reduced operational costs are all related to higher COPs.

Coefficient of performance formula:

[tex]K = Q_{H} / W_{in}[/tex]

where, K = Coefficient of performance, [tex]Q_{H}[/tex] = heat of pumps output, [tex]W_{in}[/tex] = work required by the system.

It is refrigeration's coefficient of performance (COP) will always be greater than 1.

Therefore, the coefficient of performance (cop) of a refrigerator is defined as the ratio of " the work necessary to heat or cool something usefully."

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Molality of ethylene glycol, C₂H₄(OH)₂, in a solution prepared from 2. 331×10³ g of ethylene glycol and 2.00×10³ g of water, H₂O is 47.6m

Ethylene Glycol is known as C₂H₄(OH)₂. It is added in water to prepare an Antifreeze solution.

Given,  

Mass of Ethylene Glycol = 2.331 × 10³ g = 2.331kg

Mass of Water = 2.00 × 10³ g

Since, Ethylene Glycol is in excess. Hence, it acts as a solvent and water acts as a solute.

We know, Molar Mass of Water = 18g

Hence, Moles of  Water = Given mass of water / Molar Mass of Water

⇒             Moles of  Water = 2000 / 18

⇒            Moles of  Water = 111.1

Molality is defined as the moles of solute present in a given solvent in kg.

∴ Molality = Moles of  Solute / Mass of Solvent (in kg)

Molality = Moles of  Water / Mass of Ethylene Glycol

⇒ Molality = 111.1 / 2.331

⇒ Molality = 47.6m

Molality of ethylene glycol, C₂H₄(OH)₂, in a solution prepared from 2. 331×10³ g of ethylene glycol and 2.00×10³ g of water, H₂O is 47.6m

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Answer:

3.3 x 10⁻¹⁷ Hz    

Explanation:

To find the frequency, you can use the following equation:

E = h / f

In this equation,

-----> E = energy (J)

-----> h = Planck's Constant (6.626 x 10⁻³⁴ J*s)

-----> f = frequency (Hz)

You can plug the given values into the equation and simplify to find the frequency. This equation will require a little bit of rearranging.

E = h / f                                                        <----- Given equation

(2.0 x 10⁻¹⁷ J) = (6.626 x 10⁻³⁴ J*s) / f         <----- Insert values

(2.0 x 10⁻¹⁷ J) x f = (6.626 x 10⁻³⁴ J*s)        <----- Multiply both sides by f

f = 3.3 x 10⁻¹⁷ Hz                                        <----- Divide both sides by 2.0 x 10⁻¹⁷

The frequency of an x-ray wave with an energy of 2.0 x 10^-17 J is 3.3 x 10⁻¹⁷ Hz.

The term frequency is defined as the number of waves that pass a fixed point in unit time. Frequency is measured in hertz which is equal to one event per second.

Frequency also describes the number of cycles undergoes during one unit of time by a body in periodic motion.

Calculating the frequency, you can use the following equation:

E = h / f

Where,

E = energy (J)

h = Planck's Constant (6.626 x 10⁻³⁴ J*s)

f = frequency (Hz)

Insert his values in the given equation

(2.0 x 10⁻¹⁷ J) = (6.626 x 10⁻³⁴ J × s) / f        

(2.0 x 10⁻¹⁷ J) x f = (6.626 x 10⁻³⁴ J × s)        

f = 3.3 x 10⁻¹⁷ Hz                

Thus, The frequency of an x-ray wave with an energy of 2.0 x 10^-17 J is 3.3 x 10⁻¹⁷ Hz.

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Pt195 having 78 atomic number is the daughter nucleus produced when Au195 undergoes electron capture.

An unstable isotopes can undergoes radioactive decay to form a more stable isotopes . Initial isotopes is called parent nuclide and the resultant isotopes from radioactive decay is called the daughter nuclide There are several radioactive decay like alpha decay , beta decay  , gamma decay , electron capture etc .

In electron capture , the atom have only one less which is daughter isotopes than electron than atomic number of parent isotopes.

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The  Cm of the Microsand concentration in the tanks when expressed in grams of Microsand per liter (g/L) is known to be 3.8 g/L.

This is known to be a kind of  aggregate, that is said to be exempted from clay and shale and it is one that can rightly fine to pass via a No. 100 (that is 150 µm) sieve.

Note that from the question:

The Average of six samples = 30mg/L.

Then one need to Multiply:

30 by 300gpm x 1 Train x 1700 ( this is the use of the bulk density conversion factor).

Then one need to also Divide by (4000 gpm x 2000 mL) =  1.8 g/L.

Lastly you then multiply by 2,

1.8 g/L x 2  = 3.8 g/L.

Therefore, looking at the solution above, the Cm of the Microsand concentration in the tanks  is seen to be 3.8 g/L.

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Answer:

136 g Al₂O₃

Explanation:

Assuming you do not need to find the limiting reactant, to find the mass of Al₂O₃, you need to (1) convert grams O₂ to moles O₂ (via molar mass), then (2) convert moles O₂ to moles Al₂O₃ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles Al₂O₃ to grams Al₂O₃ (via molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (64.0 g).

Molar Mass (O₂): 32 g/mol

Molar Mass (Al₂O₃): 102 g/mol

4 Al + 3 O₂ -----> 2 Al₂O₃

64.0 g O₂           1 mole           2 moles Al₂O₃            102 g
-----------------  x  --------------  x  ------------------------  x   -------------  =  136 g Al₂O₃
                             32 g               3 moles O₂             1 mole

Answer:

Explanation:

Based of the fact that you were given 2 masses I would assume this to be a limiting reagent question. However amount on the left side both equal 2. Ignoring limiting reagents and focusing on just O2 the steps would be:

1. Make sure the equation is balanced ( already given)

2- Use given values to find the mols of O2 (mass/molar mass)

3. Mols are conserved but due to the coefficients the molar value from O2 must be divided by three and multiplied by 2 to ensure proper ratios

4. Using that amount the mass can derived using amount/molar mass

5. Use proper significant digits and units(3 in this case)

A pure element unbound or in a diatomic state, such as cl2, always has an oxidation number of 0 (zero).

In a neutral substance with atoms of only one element, the oxidation number of an atom is zero. As a result, the oxidation number of the atoms in O2, O3, P4, S8, and aluminum metal is 0. The oxidation numbers for an element in its normal state will be zero. O2 and Cl2 are diatomic gas molecules that occur naturally, thus when they are in that state, they have an oxidation state of zero. Metals like zinc will also have an oxidation number of zero if they are in their natural solid state.

O2 and Cl2 are neutral diatomic, hence they will always have a zero oxidation state. It is impossible for one oxygen atom to have a negative 2 charge while the other has a positive 2. The oxidation states should be 0 if the elements are solids, liquids, or any type of diatomic molecule.

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option (d) 0 is the right option.

A pure element unbound or in a diatomic state, such as cl2, always has an oxidation number of 0.

An unbound or diatomic pure element, like cl2, always has an oxidation number of 0 (zero).

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Answer:

An increase in the intensity of sounds or fire issuing from a relief valve.

Propane serves as the propellant in all aerosols. R-12, a Freon that was the previous propellant, has been outlawed because it harms the ozone layer above the poles. Propane and R-12 share the same pressure-temperature characteristics.

Propane's boiling point is quite low. It desires a boil-off at ambient temperature. And it continues to do so until the pressure inside a closed container rises to roughly 150 psi (give or take depending on temperature), at which time the boiling point is raised high enough to cause the substance to stop boiling.

"Contents Under Pressure" is exactly what the notice indicates. Paint, hairspray, lubricant, wasp and hornet spray, among other liquids, can be found within an aerosol can, which is a pressure vessel. By inspecting the bottom, you may determine whether a vessel is a pressure vessel. If it is dished in like a bowl, it has the same pressure-holding end as a huge propane tank, with the exception that the curve on the latter has an outward orientation. On aerosol canisters, it is inward because they must sit upright for ease. A circular bottom just cannot accomplish that. But the top resembles an outer hemisphere more or less.

Thank you,

Eddie

Answer:

Red

Explanation:

Red color is evidenced when thymol blue indicator is in a solution having a pH of 11. A pH of 11 means that the solution is basic or alkaline. Therefore, the indicator turns red, indicating that the solution is alkaline.

When thymol blue indicator is in a acidic solution, the indicator remains blue.

The half-life of sr-89 will be 51 days.

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A glow stick will glow longer at lower temperatures than at room temperature, one can infer from the observation. Temperature and reaction time are the test variables.

We notice in this reaction that a glow stick stored in the freezer lights for a longer period of time than a glow stick stored at normal temperature. This implies that temperature affects how long a response lasts.

The most straightforward explanation for this observation is that glow sticks glow longer in colder temperatures than they do at room temperature; as a result, glow sticks kept in the freezer are observed to glow longer than glow sticks kept at room temperature.

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The radius of a sodium atom is determined as 2.145 x 10⁻⁸ cm.

Body-centered cubic (BCC) is the name given to a type of atom arrangement found in nature.

A body-centered cubic unit cell structure consists of atoms arranged in a cube where each corner of the cube shares an atom and with one atom positioned at the center.

The volume of the sodium atom is calculated as follows;

V = ZM/Nρ

where;

V = (2 x 23) / (6.023 x 10²³ x 0.968)

V = 7.89 x 10⁻²³ cm³

a = (V)^¹/₃

a = (7.89 x 10⁻²³ cm³)^¹/₃

a = 4.29 x 10⁻⁸ cm

r = a/2

r = ( 4.29 x 10⁻⁸ cm) / 2

r = 2.145 x 10⁻⁸ cm

Thus, the radius of a sodium atom is determined as 2.145 x 10⁻⁸ cm.

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The volume occupied by 22. 0 g of helium gas at 26. 0 ° C and 1. 20 atm of pressure is 112.37 L .

Calculation ,

According to ideal gas equation ,

PV = nRT        ....(i)

where P is the pressure = 1. 20 atm

V is the volume of the helium gas = ?

R is the universal gas constant = 0.082 atm L /K mol

T is the temperature of the gas =  26. 0 ° C = 299 K

n is the number of moles

Number of miles (n)  = given mass/ molar mass =22 g/4 = 5.5 moles

By putting the value of pressure , volume , temperature and  universal gas constant  in equation ( i) we get

1. 20 atm ×V = 5.5 moles × 0.082×299

V = 5.5 moles × 0.082×299/1. 20 atm = 112.37 L

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By generating a rate law is complicated when the rate-determining step is preceded by 'a' is a Equilibrium reaction.

The rate law shows about the rate of chemical reaction depends on reactant concentration.

According to rate law, the rate of reaction is directly proportional to the concentration of reaction which is raised to a stiochiometric coefficient which is determined experimentally.

Thus, from above we concluded that if the preceding reaction is an equilibrium, that compromises the simplicity of writing the rate law from the stiochiometry of the rate determining step will be used up in the reverse reaction of the equilibrium.

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The relationship between the light emitted by an atom and the energies of the electrons in the atom is that the energy emitted by an atom is equal to the difference between the energy of two orbitals.

According to Bohr's model:

In Bohr's theory, the electron can jump from a lower energy level to a higher energy level, and when the energy is removed electron comes back to the initial energy level. Bohr proposed the energy and radii of an electron in the atom are quantized.

Energy between the orbits is given by,

∆E = E -E°

where ∆E = difference between the energy of orbital.

E = initial energy

E° = final energy.

Thus, we concluded that the energies of electron in the atom is equal difference between the energy of two orbitals.

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Answer:

D. carbohydrate, blue-purple

Explanation:

Carbohydrates are one of many types of macronutrients found in certain foods and drink. For example, sugars, starches, and fibers are carbohydrates.

When starch is present, using an iodine solution will turn it blue-black or purple. If starch is NOT present, it will stay orange or yellow. The reason starch reacts with iodine is due to the amylose present in starch. Iodine is not soluble in water, so it's dissolved along with potassium iodide that forms a triiodide molecule. That then enters the helical structure of amylose and changes its color.

For calculating mean value, add up all of the values then divide by the number of them. 815/9 is about 90.6

The mean refers to the average of a set of values. The mean can be computed in a number of ways, including the simple arithmetic mean (add up the numbers and divide the total by the number of observations), the geometric mean, and the harmonic mean.

Moreover, the mean can be used to represent the typical value and therefore serves as a yardstick for all observations. For example, if we would like to know how many hours on average an employee spends at training in a year, we can find the mean training hours of a group of employees.

Hence, the mean can be calculated only for numeric variables, no matter if they are discrete or continuous. It's obtained by simply dividing the sum of all values in a data set by the number of values.

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4 ml stock is needed for the standard of 1 mg/ml creatinine if a 4.0 mg/dl creatinine standard is needed to prepare 100 ml of the working standard.

Your muscles produce creatinine as a waste product during routine, everyday action. In a typical state, your kidneys remove creatinine from your blood and excrete it in urine. Creatinine can accumulate in the blood and less creatinine will be excreted in the urine if there is an issue with your kidneys.

A high amount of creatinine in the blood or urine may indicate that the kidneys are not doing a good job of filtering the blood. Although high creatinine levels do not pose a life-threatening hazard, they may be a sign of a major health problem, such as chronic renal disease.

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Answer:

0.453 moles

Explanation:

The Ideal Gas Law equation looks like this:

PV = nRT

In this formula,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

To find the amount of moles of gas, you can plug the given values into the equation and then simplify.

P = 2.7 atm                                 R = 0.08206 atm*L/mol*K

V = 4.2 L                                     T = 305 K

n = ? moles

PV = nRT

(2.7 atm)(4.2 L) = n(0.08206 atm*L/mol*K)(305 K)

11.34 = n(25.0283)

0.453 = n

climate

Changes in the composition of the atmosphere have caused gradual changes in earth's climate throughout history, causing changes in plant and animal life that contributed to mass extinctions.

The following are some of the reasons:

heat

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Answer:

C. C-14 decays but C-12 stays the same after death.

Explanation:

C-12 is stable and won't change.  C-14 is slightly radioactive.  It decays over time to C12.  A living plant or animal has a fairly constant C14/C12 ratio during it's lifetime.  Sources of food have a fairly consistent C-14/C-12 ratio.  Once it dies, the C-14 is no longer replenished, so the ratio of C-14 to C-12 drops over time, giving paleontologists the ability to carbon-date the sample.  The less C-14, the older the sample.