Identify the quadratic function(s). (Select all that apply). y(y + 4) - y = 6 (3x + 2) + (6x - 1) = 0 4b(b) = 0 3a - 7 = 2(7a - 3)

Answer:

See below.

Step-by-step explanation:

I'm sure the question is asking to solve for ∠BDC, but we'll solve for all of the angles.

We should note that we have a Given Exterior Angle.

An Exterior Angle is an angle that is formed by extended lines.

An exterior angle is equal to the combined sum of the two nonadjacent, and interior angles.

Using what we learned, ∠BCD and ∠CDB will equal ∠DBE°.

Let's turn this problem into an equation.

60° + ∠BDC = 120°
Subtract 60 from both sides.

∠BDC = 60°.

We can also identify that ∠CBD is a linear pair with ∠DBE.

A Linear Pair is 2 adjacent angles that add up to 180°. Linear Pairs are straight lines with one line intersecting in between.

Meaning that ∠CBD + ∠DBE = 180°.

∠CBD + 120° = 180°.

∠CBD = 60°.

We can identify that this triangle is an Equilateral Triangle. An Equilateral  Triangles is a triangle that has all congruent sides and angles.

Our final answers are;

∠BDC = 60°.

∠CBD = 60°.

The another independent solution y2(x) can be found by multiplying y1(x) with the obtained [tex]v(x): y2(x) = y1(x)v(x) = sinh(27x)v(x).[/tex]

To find another independent solution to the given differential equation, [tex]y(x) + p(x)y'(x) + q(x)y(x) = 0[/tex], with one solution [tex]y1(x) = sinh(27x)[/tex], we can use the formula for finding a second linearly independent solution using the Wronskian.

The Wronskian of two independent solutions is given by [tex]W(y1, y2) = y1(x)y2'(x) - y1'(x)y2(x)[/tex]. Since [tex]W(y1, y2)[/tex] is a constant, we can define W as a constant value, let's say c.

Introduce a new function v(x) such that [tex]y2(x) = y1(x)v(x), so y2(x) = sinh(27x)v(x).[/tex] Compute the derivative of y2(x): [tex]y2'(x) = 27cosh(27x)v(x) + sinh(27x)v'(x)[/tex]. Substitute [tex]y1(x), y1'(x), y2(x), and y2'(x)[/tex]into the Wronskian equation: c = [tex]sinh(27x)[27cosh(27x)v(x) + sinh(27x)v'(x)] - 27cosh(27x)sinh(27x)v(x)[/tex]

Divide by [tex]sin(27x)cos(27x)[/tex] to simplify the equation: c / [tex](27sinh(27x)cosh(27x)) = v(x) + (1/27)v'(x).[/tex] Rearrange the equation to obtain a first-order linear differential equation:  [tex]v'(x) - 27v(x) = 27c / sinh(27x)cosh(27x)[/tex]

Solve the differential equation for[tex]v(x)[/tex] (you can use an integrating factor or another method). Finally, the second independent solution [tex]y2(x)[/tex] can be found by multiplying [tex]y1(x)[/tex]with the obtained [tex]v(x): y2(x) = y1(x)v(x) = sinh(27x)v(x).[/tex]

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Answer:

Step-by-step explanation:

Given: Length of the building = 78 ft

Scale = 1 in : 8 ft

To find: Length of the building in the drawing

Now we have the scale where

8 ft = 1 inch

So using unit rule

1 ft = (1/8) in

So

78 ft = (1/8)(78) in = 9.75 inch

So length of the building in the drawing is 9.75 inch.

The length of the drawing is 9.75 inches.

To calculate the length of the drawing, find out how many inches correspond to 78 feet using the scale provided.

Since the scale is 1in:8ft, this means that 1 inch on the drawing represents 8 feet in real life.

To determine the length of the drawing, divide the length of the building by the scale factor:

Length of drawing = Length of building / Scale factor

Length of drawing = 78 ft / 8

Length of drawing = 9.75 inches

Hence, the drawing is 9.75 inches long.

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a) To find the linear velocity of a point on the tip of one of the blades, we need to use the formula: V = 2πr/T where V is the linear velocity, r is the radius of the circle, and T is the period of rotation. In this case, the radius of the circle is the length of the propeller blades, which is 3 meters, and the period of rotation is the inverse of the frequency of rotation, which is 1/6 minutes. Plugging in the values, we get: V = 2π(3)/(1/6) = 36π meters per minute. To the nearest meter per minute, the linear velocity is approximately 113 meters per minute.

b) To find the arc length and the area of the circular sector, we need to use the formulas: Arc length = θr and Area = (θr^2)/2 where θ is the central angle in radians, and r is the radius of the circle. In this case, the central angle is 25 degrees, which is equivalent to (25π)/180 radians, and the radius of the circle is 12 cm. Plugging in the values, we get: Arc length = ((25π)/180)(12) = (5π)/3 cm and Area = (((25π)/180)(12^2))/2 = (25π)/3 cm^2. Therefore, the arc length is approximately 5.24 cm and the area is approximately 26.18 cm^2.

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the real solutions to this equation are x = 2√2 and x = -2√2.

Solution:

(a) -n + √(6n + 19) = 2

To find the solution algebraically, we need to isolate the radical on one side of the equation and then square both sides to get rid of the radical.

-n = 2 - √(6n + 19)

(-n - 2)^2 = (2 - √(6n + 19))^2

n^2 + 4n + 4 = 4 - 4√(6n + 19) + 6n + 19

n^2 - 2n - 19 = -4√(6n + 19)

(n^2 - 2n - 19)^2 = (-4√(6n + 19))^2

n^4 - 4n^3 - 18n^2 + 76n + 361 = 96n + 304

n^4 - 4n^3 - 114n^2 + 76n + 57 = 0

This is a quartic equation that can be solved using the Rational Root Theorem or by factoring. However, this equation does not have any real solutions. Therefore, there are no real solutions to this equation.

(b) x^4 - 20x^2 + 64 = 0

This equation can be factored as:

(x^2 - 8)^2 = 0

x^2 - 8 = 0

x^2 = 8

x = ±√8

x = ±2√2

Therefore, the real solutions to this equation are x = 2√2 and x = -2√2.

Remember to check your solutions by plugging them back into the original equation and seeing if they make the equation true.

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We can use the properties of logarithms to evaluate each expression. The properties of logarithms include:

1) loga (xy) = loga (x) + loga (y)

2) loga (x/z) = loga (x) - loga (z)

3) loga (x^p) = p loga (x)

4) loga (square root x) = (1/2) loga (x)

Using these properties, we can evaluate each expression as follows:

(a) loga (xy) = loga (x) + loga (y) = 3.1 + 5.8 = 8.9

(b) loga (x/z) = loga (x) - loga (z) = 3.1 - 1.1 = 2

(c) loga (y^7) = 7 loga (y) = 7 * 5.8 = 40.6

(d) loga (square root y) = (1/2) loga (y) = (1/2) * 5.8 = 2.9

Therefore, the answers are:

(a) loga (xy) = 8.9

(b) loga (x/z) = 2

(c) loga (y^7) = 40.6

(d) loga (square root y) = 2.9

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Answer:

Let's first find the volume of the original cuboidal box:

Volume = Length x Width x Height = 3 x 3 x 2 = 18 cubic units

We can then set up an equation to relate the volume of the original box to the volume of the new cuboid:

Volume of new cuboid = Volume of original box

Let's call the length and height of the new cuboid "x" (since we know that the length and height are the same). We know that the width of the new cuboid is 15 units. Therefore, we can write:

Volume of new cuboid = Length x Width x Height = x x 15 x x = 15x^2

Now we can set up the equation:

15x^2 = 18

Dividing both sides of the equation by 15 gives:

x^2 = 18/15

Simplifying the right side of the equation gives:

x^2 = 1.2

Taking the square root of both sides of the equation gives:

x ≈ 1.095

Therefore, the length and height of the new cuboid are approximately 1.095 units.

the value of the expression is 0.

To solve this expression, we can use the PEMDAS order of operations:

since there are no Parentheses and Exponents we move to multiplication and division

-2(-3) + 27 ÷ (-3) + 3 = 6 + (-9) + 3

6 + (-9) + 3 = 0

As a result, the equation has a value of 0.

A mathematical definition of an equation is a claim that two expressions are equal when they are joined by the equals sign ("="). For illustration, 2x - 5 = 13.

Here,

5 and 13 are expressions for 2x.

These two expressions are joined together by the sign "=".

Two expressions are combined in an equation using an equal symbol ("="). The "left-hand side" and "right-hand side" of the equation are the two expressions on either side of the equals sign. Typically, we consider an equation's right side to be zero. As we can balance this by deducting the right-side expression from both sides' expressions, this won't reduce the generality. The two most well-known groups of equations in algebra are linear equations and polynomial equations. P(x) = 0 can be used to represent polynomial equations with a single variable. P is a polynomial, and axe + b = 0 is the standard form for linear equations. Here, are the parameters a and b.

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(a) The area of a triangle can be found using the formula A = (1/2)bh, where b is the base and h is the height. In this case, the base is one of the sides with length 13 or 15, and the height is the altitude with length 12. Using the formula, the area is A = (1/2)(13)(12) = 78 square units.

(b) The area of a triangle can also be found using Heron's formula, which is A = √[s(s-a)(s-b)(s-c)], where s is the semiperimeter of the triangle, and a, b, and c are the lengths of the sides. In this case, s = (10+10+16)/2 = 18, so the area is A = √[18(18-10)(18-10)(18-16)] = 80 square units.

(c) Using Heron's formula again, s = (5+12+13)/2 = 15, so the area is A = √[15(15-5)(15-12)(15-13)] = 30 square units.

(d) The area of an isosceles triangle can be found using the formula A = (1/2)bh, where b is the base and h is the height. In this case, the base is 30 and the height can be found using the Pythagorean theorem, h = √(17^2 - (30/2)^2) = 8. So the area is A = (1/2)(30)(8) = 120 square units.

(e) The area of an isosceles triangle can also be found using the formula A = (1/2)ab sin C, where a and b are the lengths of the two equal sides and C is the vertex angle. In this case, a = b = 20 and C = 68°, so the area is A = (1/2)(20)(20) sin 68° = 190.4 square units.

(f) Using the same formula as in (e), but with a = b = 30 and C = 62°, the area is A = (1/2)(30)(30) sin 62° = 675 square units.

(g) The area of a triangle inscribed in a circle can be found using the formula A = (1/2)ab sin C, where a and b are the lengths of the two sides and C is the angle between them. In this case, one side is a diameter with length 8 (2 times the radius of 4), another side has an unknown length, and the angle between them is 30°. The area is A = (1/2)(8)(b) sin 30° = 2b square units.

(h) The area of a triangle cut off by a line parallel to the base can be found using the formula A = (1/2)bh, where b is the length of the base and h is the height. In this case, the base is 10 and the height is 5 - 6 = -1, so the area is A = (1/2)(10)(-1) = -5 square units.

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Convert the expression as follows:

To Show:-

Answer:-

The ratio given to us is ,

[tex]\implies (y + 2) : ( y + 7) = k : 1 \\[/tex]

In fraction form we can write it as ,

[tex]\implies \dfrac{y+2}{y+7}=\dfrac{k}{1} \\[/tex]

Now solve for y , by cross multiplying,

[tex]\implies 1( y + 2 ) = k( y + 7) \\[/tex]

Simplify the brackets,

[tex]\implies y + 2 = ky + 7k \\[/tex]

Subtract ky on both sides ,

[tex]\implies y - ky + 2 = 7k \\[/tex]

Subtract 2 on both sides,

[tex]\implies y - ky = 7k - 2 \\[/tex]

Take out y as common from LHS ,

[tex]\implies y ( 1 - k ) = 7k - 2 \\[/tex]

Divide both the sides by (1-k) ,

[tex]\implies \underline{\underline{ \green{y =\dfrac{7k-2}{1-k}}}} \\[/tex]

Hence Proved !

and we are done!

To add or subtract the given expressions, we need to combine like terms. Like terms are terms that have the same variable and exponent.

Step 1: Combine like terms for a^(2):
6.9a^(2) + 0 = 6.9a^(2)
Step 2: Combine like terms for b^(2):
-2.3b^(2) + (-2.5b^(2)) = -4.8b^(2)
Step 3: Combine like terms for ab:
2ab + 0 = 2ab
Step 4: Combine like terms for a:
0 + 3.1a = 3.1a
Step 5: Combine like terms for b:
0 + b = b
Step 6: Put all the combined terms together:
6.9a^(2) + (-4.8b^(2)) + 2ab + 3.1a + b
Step 7: Simplify the expression:
6.9a^(2) - 4.8b^(2) + 2ab + 3.1a + b

So the final answer is 6.9a^(2) - 4.8b^(2) + 2ab + 3.1a + b.

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The percent increase in pipe footage sales is approximately 7%.

To find the percent increase in pipe footage sales, use the formula:

[(New Value - Old Value)/Old Value] × 100.

In this case, the new value is the amount of pipe sold in September (2,558 feet) and the old value is the amount of pipe sold in August (2,390 feet). Plugging these values into the formula, we get:

[(2,558 - 2,390)/2,390] × 100 = [168/2,390] × 100 = 0.0703 × 100 = 7.03%

Therefore, the correct answer is 7%, which is option A. The percent increase in pipe footage sales from August to September is 7%.

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Dijkstra's algorithm is a useful tool for finding the length of the shortest path between two vertices in a weighted graph.

To solve this problem, we can start by creating a distinguished vertex set Q that contains all of the vertices in the graph, and assigning a distance of ∞ to each vertex in the set. Then, we can assign the starting vertex, a, a distance of 0.

Next, we can choose the vertex in Q with the shortest distance from the source vertex, a. This vertex is then removed from the set Q, and all of its adjacent vertices are evaluated and added to the set Q if they are not already in it. We then assign each adjacent vertex the distance of the selected vertex, plus the weight of the edge connecting it to the selected vertex.

Finally, we continue this process until the destination vertex, z, is removed from the set Q. At this point, the length of the shortest path between vertices a and z can be found by looking at the distance of the destination vertex.

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The area of the trapezoid is 65.16 metres squared.

The area of a trapezoid can be found as follows:

area of a trapezoid = 1 / 2 (a + b)h

where

Therefore,

a = 5metres

b = 13.1 metres

h = 7.2 metres

Hence,

area of a trapezoid = 1 / 2 (5 + 13.1) 7.2

area of a trapezoid = 1 / 2 (18.1)7.2

area of a trapezoid = 130.32 / 2

Therefore,

area of a trapezoid = 65.16 metres squared

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The formula:

[tex]\huge\begin{array}{ccc}C=2\pi r\end{array}[/tex]

[tex]r[/tex] - radius

We have:

[tex]r=6.5m[/tex]

Substitute:

[tex]C=2\cdot6.5m\cdot\pi=13\pi m[/tex]

Use: [tex]\pi\approx3.14[/tex]

[tex]C\approx13m\cdot3.14=40.82m[/tex]

Answer:40.82 meters

The circumference of the circle.

The formula:

- radius

SOLUTION:

We have:

Substitute:

Use:

Step-by-step explanation:

Give bro above me the good stuff

A is invertible and its inverse is B = (-1/3)(A^3 + 2A - In). To show that A is invertible, we need to find a matrix B such that AB = BA = In, where In is the identity matrix of size

n × n.

First, let's rearrange the given equation:
A – 2A^2 -A^4 + 3In = 0
A^4 + 2A^2 - A + 3In = 0
Next, let's factor out A from the left side of the equation:
A(A^3 + 2A - In) = -3In

Now, let's multiply both sides of the equation by -1/3:
(-1/3)A(A^3 + 2A - In) = In

finally, let's set B = (-1/3)(A^3 + 2A - In):
AB = (-1/3)A(A^3 + 2A - In) = In
Therefore, the inverse of A is B = (-1/3)(A^3 + 2A - In).

To check our answer, we can multiply A and B to see if we get the identity matrix:
AB = A[(-1/3)(A^3 + 2A - In)] = (-1/3)(A^4 + 2A^2 - A) = (-1/3)(0) = In
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The desired solution is to the nearest quarter of a unit, the approximate solution is x=2.25.

A quarter is a fraction that represents one-fourth of a whole number or quantity. It can be written as a ratio, a decimal, or a percentage. A quarter is one of the simplest fractions, and it can be used to divide an object or number into four equal parts. It is also used to calculate percentages and proportions.

A table of values is a great way to approximate a solution to an equation. To approximate a solution to the equation f(x)=g(x) to the nearest quarter of a unit, the table of values must contain the x-values and the corresponding f(x) and g(x) values.

For example, if the equation was f(x)=2x+3 and g(x)=x+2, the table of values would look like this:

x f(x) g(x)

0 3 2

1 5 3

2 7 4

3 9 5

4 11 6

To find the approximate solution to f(x)=g(x), the table must be examined for the first x-value where the f(x) and g(x) values are equal. In this case, the x-value is 2 and the corresponding f(x) and g(x) values are both 7. Since the desired solution is to the nearest quarter of a unit, the approximate solution is x=2.25.

This method of using a table of values to approximate a solution to an equation is very simple and quick. It is a great way to get a rough answer to an equation without having to solve it. It is also a useful tool for double-checking the exact solution to an equation.

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The values of h and k are h=7 and k=46. The equation in the form (x+h)^(2)=k is (x+7)^(2)=46.

To solve the equation x^(2)+14x+3=0 by completing the square method, we need to follow these steps:

1. Rearrange the equation so that the constant term is on the right side: x^(2)+14x=-3

2. Find the value of h by taking half of the coefficient of the x term: h=14/2=7

3. Add the square of h to both sides of the equation: x^(2)+14x+7^(2)=-3+7^(2)

4. Simplify the right side of the equation: x^(2)+14x+49=46

5. Write the left side of the equation in the form (x+h)^(2): (x+7)^(2)=46

Therefore, the values of h and k are h=7 and k=46. The equation in the form (x+h)^(2)=k is (x+7)^(2)=46.

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Answer: The inequality is:

1.2 + m ≤ 5.5

This inequality can be read as "the sum of 1.2 and m is less than or equal to 5.5."

To solve for m, you need to isolate it on one side of the inequality symbol.

1.2 + m ≤ 5.5

Subtract 1.2 from both sides:

m ≤ 5.5 - 1.2

Simplify:

m ≤ 4.3

Therefore, the solution to the inequality is m ≤ 4.3.

Step-by-step explanation:

Coordinates of the vertices of the pre-image are (-4, 4), (-1, 9), and (1, 9).

And the graph is given below.

A transformation of a triangle can refer to any process that changes the size, position, or shape of a triangle.

Translation involves moving the triangle without changing its shape or size. To translate a triangle, you can simply move it in any direction by a certain distance, without rotating or flipping it.

Here we have

From the graph

The coordinates of the triangle are (1, 1) (4, 6), and (6, 3)

Given T < -5, 3 > (x, y)

Hence, the coordinates of the pre-image are

(1, 1) => (1 - 5,  1 + 3)  = (-4, 4)  

(4, 6) => (4 - 5, 6 + 3) = (-1, 9)

(6, 3) => (6 - 5,  3+3) = (1, 6)

Hence,

Coordinates of the vertices of the pre-image are (-4, 4), (-1, 9), and (1, 9).

And the graph is given below.

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[2x^(2) + 7x + 6 = 0] has C. two real solutions

The quadratic equation 2[tex]x^{(2)}[/tex] + 7x + 6 = 0 has two real solutions. To solve, use the Quadratic Formula:

x = [-b ± √([tex]b^{2}[/tex] - 4ac)]/2a  

Where a = 2, b = 7, and c = 6.

So, x = [-7 ± √([tex]7^{2}[/tex]- 4(2)(6))]/2(2)  

x = [-7 ± √(49 - 48)]/4  

x = [-7 ± 1]/4  

x = -3/2 and x = 1/2  


Therefore, the equation has two real solutions: x = -3/2 and x = 1/2.

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Answer: -4

Basically, just plug in m and n as the values you were given:

The discriminant is positive (D = 8), the equation x² - 6x + 7 = 0 has two distinct real solutions, which supports Jason's claim.

The quadratic equation's roots are represented geometrically by the discriminant. The equation has two separate real roots if the discriminant is positive, and as a result, the graph of the quadratic function meets the x-axis twice. The quadratic function's graph crosses the x-axis precisely one time if the discriminant is zero, which indicates that the equation has one real root.

To find the discriminant of the given equation, we can substitute the values of a, b, and c into the formula:

D = (-6)² - 4(1)(7) = 36 - 28 = 8

Since the discriminant is positive (D = 8), the equation x² - 6x + 7 = 0 has two distinct real solutions, which supports Jason's claim.

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The complete question is:

The two real solutions of the equation are:

z=32.5/18 ± √(81+32.5z)/18

The equation 18z2-65z-72=0 can be solved by completing the square. We start by taking half of the coefficient of the squared term and squaring it:

(18/2)2 = (9)2 = 81

We then add 81 to both sides of the equation to complete the square:

18z2-65z-72+81=0+81

18z2-65z+9=81

Now, we take half of the coefficient of the z-term, subtract it from both sides of the equation, and add it in the parentheses:

18z2-(65/2)z+(65/2)z+9=81+(65/2)z

(18z-32.5)2=81+32.5z

We now have a perfect square on the left side, so we can simplify:

(18z-32.5)2=81+32.5z

18z-32.5=±√(81+32.5z)

18z=32.5±√(81+32.5z)

z=32.5/18 ± √(81+32.5z)/18

Therefore, the two real solutions of the equation are:

z=32.5/18 ± √(81+32.5z)/18

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If a rectangular prism has dimensions of 1.5 feet by 3.5 feet by 2 feet, its volume, expressed in cubic feet, is 10.5 cubic feet.

The rectangular prism's measurements are —

3.5 feet in length

1.5 feet wide in Size

Height is two feet.

The volume of the rectangular prism is calculated by multiplying these dimensions collectively.

Volume equals length, width, and height, or 3.5 feet, 1.5 feet, and 2 feet.

= 10.5 cubic feet of volume

Hence, the rectangular prism has a volume of 10.5 cubic feet.

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The volume of the small can is  25.12 inches cube.

Mrs. Roberts' dog, Rover, loves to eat peanuts. A large can of peanuts has a diameter of 4 inches and a height of 6 inches. The small can that she plans to purchase has the same diameter but is 1/3 of the height of the large can.

Therefore, the approximate volume of the small can can be found as follows:

Hence,

volume of the small can = πr²h

where

Therefore,

r = 4 / 2 = 2 inches

h = 1 / 3 (6) = 2 inches

Hence,

volume of the small can = 3.14 × 2² × 2

volume of the small can = 3.14 × 4 × 2

volume of the small can = 3.14 × 8

volume of the small can = 25.12 inches cube

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Yes, the equation y = 3/4(x) represent a proportional relationship because its line passes through the origin.

In Mathematics, a proportional relationship is a type of relationship that produces equivalent ratios and it can be modeled or represented by the following mathematical expression:

y = kx

Where:

Generally speaking, the graph of any proportional relationship such as the linear equation is characterized by a straight line that passes through all the points and the origin, which is denoted by the ordered pair (0, 0).

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If the mean of five scores is 27, then the number 33 must be added to the previous five scores to make the mean of six scores as 28.

It is given that mean of five scores is 27. If the unknown number x is added to the five scores, the new mean becomes 28. To calculate the value of x, the following equations are considered.

Let us say that the five scores are A, B, C, D and E.

∴ Mean of five scores = (A+B+C+D+E)/ 5 = 27

⇒ (A+B+C+D+E) = 27 × 5 = 135

Now, if sixth score x is added, then mean score becomes 28.

⇒ (A+B+C+D+E+x)/ 6 = 28

⇒ (A+B+C+D+E+x) = 28×6 = 168

Putting the value of (A+B+C+D+E) in above equation, we get:

135 + x = 168

x = 168 - 135 = 33

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The value of 8#(8#8) is (A) 1/2

An operation \# for positive real numbers is defined by the equation a#b=ab/a+b. The value of 8#(8#8) is (A) 1/2. To solve, use the equation given:

8#(8#8) = (8*8)/(8+8)

= 64/16

= 1/2

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Answer: Stem-and-leaf plot, because you can see each individual data point.

Step-by-step explanation:im taking the test.

Answer:stem and leaf plot