Identify the type of compound that would have the following properties?

Conducts electricity when melted or dissolved in water.
High Melting Point
Usually a Solid
Group of answer choices

A. Ionic

B. Metallic

C. Covalent

D. Molecular

a) physical property

b) chemical change

c) chemical change

d) chemical property

e) physical change

f) physical property

g) physical change

h) physical change

a) Ethanol has a density of 0.697 g/mL shows physical property, b) The solution turns blue upon mixing water and food coloring shows chemical change, c) Wood burns in an oven shows chemical change, d) Methyl alcohol is highly flammable shows chemical property, e) Ice melts in a beaker shows physical change, f) Methyl ethanoate smells like apples shows physical property, g) A car crashes into a wall shows physical change and h) Sugar dissolves in water shows physical change.

A physical change is a transition that modifies a substance's physical characteristics without changing its chemical makeup or identity. The substance's molecules don't change during a physical change; only their arrangement or state does. On the other hand, a chemical change entails the creation of new compounds with chemical properties that differ from the original ones. A entirely new substance is produced as a result of a chemical reaction in which the links between atoms or molecules are broken and new bonds are established.

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Answer:

D.) reducing agent

Explanation:

Oxidized chemicals gain electrons. In order to gain these electrons, another chemical must lose electrons. So, the chemical (which will be oxidized) acts as a reducing agent, causing the other chemical to be reduced and lose electrons.

Answer:

Silver

Explanation:

What mass of copper was discharge at the cathode in a cell

Answer:

0.645 L

Explanation:

To find the volume, you need to (1) convert grams to moles (using the molar mass) and then (2) calculate the volume (using the molarity ratio). The final answer should have 3 sig figs to match the sig figs of the given values.

(Step 1)

Molar Mass (KOH): 39.098 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (KOH): 56.104 g/mol

19.9 grams KOH              1 mole
--------------------------  x  -----------------------  =  0.355 moles KOH
                                     56.014 grams

(Step 2)

Molarity = moles / volume                            <----- Molarity ratio

0.550 M = 0.355 moles / volume                 <----- Insert values

(0.550 M) x volume = 0.355 moles              <----- Multiply both sides by volume

volume = 0.645 L                                          <----- Divide both sides by 0.550

Sorry for the sloppy writing I tried my best.

If you can't read the words in my photo it says

Evaporation

condensation precipitation and runoff

definition of these words

evaporation: The process of turning liquid into vapor

Condensation:water which collects as droplets on a cold surface when humid air is in contact with

Precipitation: the action or process of precipitating a substance from a solution

runoff: liquid, especially water or rainwater, that flows off or drains away

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Answer:

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Answer:

17.3 g Cr

Explanation:

To find the mass of chromium, you need to (1) convert moles Si to moles Cr (using the mole-to-mole ratio from equation coefficients) and then (2) convert moles Cr to grams Cr (using the atomic mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (0.250).

3 Si + 2 Cr₂O₃ ---> 4 Cr + 3 SiO₂
^                              ^

Atomic Mass (Cr): 51.996 g/mol

0.250 moles Si           4 moles Cr            51.996 g
-------------------------  x  --------------------  x  -------------------  =  17.3 g Cr
                                     3 moles Si              1 mole

Answer:

B.) 129.9 grams

Explanation:

To find the mass, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

The specific heat of copper is 0.385 J/g°C. Knowing this, you can plug the given values into the equation and simplify to isolate "m".

Q = mcΔT                                                            <----- Equation

5000 J = m(0.385 J/g°C)(200 °C - 100 °C)        <----- Insert values

5000 J = m(0.385 J/g°C)(100)                            <----- Subtract

5000 J = m(38.5)                                                <----- Multiply 0.385 and 100

129.9 = m                                                             <----- Divide both sides by 38.5

The first step in clearing a clogged ballpoint pen is to exert additional pressure when scrawling and drawing vertical lines on paper. If this approach doesn't work, dip the pen's tiny tip in rubbing alcohol. [Only the tidbit] Any dried-up or hardened ink on the tip will dissolve with this.

The equation for the autoionization of water is-

NH3 + H2O → NH4+ + OH− (H2O acts as an acid)

HCl + H2O → H3O+ + Cl− (H2O acts as a base)

Autoionization of water, the autoionization constant Kw, and the relationship between [H⁺] and [OH⁻] in aqueous solutions.

Water can undergo autoionization to form and ions.

The expression for the autoionization constant is

[tex]The expression for the autoionization constant isK_\text{w}=[\text{H}_3\text{O}^+][\text{OH}^-]\quad\quad\text{(Eq. 1)}K w​ =[H 3​ O + ][OH − ][/tex]

In this way the autoionization of water,

NH3 + H2O → NH4+ + OH− (H2O acts as an acid)

HCl + H2O → H3O+ + Cl− (H2O acts as a base) is given.

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Answer:

d

Explanation:

The + charge of the proton and the - charge of the electron create a electrostic force of attraction ( opposites attract)

Answer:

13.0 L

Explanation:

To find the volume, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (kPa)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (8.314 kPa*L/mol*K)

-----> T = temperature (K)

After converting the temperature from Celsius to Kelvin, you can plug the given values into the equation and simplify to find "V". The final answer should have 3 sig figs to match the sig figs of the given values.

P = 855 kPa                                  R = 8.314 kPa*L/mol*K

V = ? L                                           T = 26.0 °C + 273.15 = 299.15 K

n = 4.47 moles

PV = nRT

(855 kPa)V = (4.47 moles)(8.314 kPa*L/mol*K)(299.15 K)

(855 kPa)V = 11117.48496

V =  13.0 L

Answer:

Having a specific set of possible values

Answer:

15 is not a correct scientific measurement.

Explanation:

Is this helpful for You

Considering the definition of percentage by mass and density, the percentage by mass of a NaCl solution is 53.917%.

The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

[tex]percentage by mass= \frac{mass of solute}{mass of solution}x100[/tex]

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

[tex]density=\frac{mass}{volume}[/tex]

In this case, you know:

Replacing in the definition of density, you get the mass of water:

[tex]1 \frac{g}{mL} =\frac{mass of water}{50 mL}[/tex]

Solving:

mass of water= 1 [tex]\frac{g}{mL}[/tex]× 50 mL

mass of water= 50 grams

Then, you get that the mass of solution is calculated as:

mass of solution= mass of solute + mass of water

mass of solution= 58.5 grams + 50 grams

mass of solution= 108.5 grams

So, the percentage by mass is calculated as:

[tex]percentage by mass= \frac{58.5 grams}{108.5 grams}x100[/tex]

percentage by mass= 53.917%

Finally, the percentage by mass of a NaCl solution is 53.917%.

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[tex] \quad \quad\quad\huge \tt{ANSWER}[/tex]

Hydrocarbons are organic compounds which made up of only carbon and hydrogen.

[tex] \pink{ \star}[/tex]Carbon - ( C )

[tex] \pink{ \star}[/tex]Hydrogen - ( H )

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

[tex] \red{✿}[/tex] Type of Hydrocarbon :

[tex] \purple{\mathfrak{llXecretll}}[/tex]

The acid dissociation constant(Ka) is 0.0095

The reaction for this dissociation of acid is

HSO4 ⇄H+ + SO4 -2

The dissociation constant can be determined from the following expression

[tex]Ka= \frac{[H+] [SO4]-2}{[HSO4}[/tex]  

[H+] = 10-PH

       = 10-1.35

[H+]  = 0.0447

[H+] = 0.0447 mol / L

From equation, [H+] = [SO4-2] = 0.0447 mol / L

[SO4-2] = 0.0447 mol / L

From the values of [H+], [SO4-2] and [HSO4] Ka can be calculated as follows,

Ka = 0.0447 * 0.0447 / 0.200

     = 0.0019 / 0.200

     = 0.0095

Hence the value of the acid dissociation constant (Ka) for the given reaction is  0.0095

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Answer:

1.25 M

Explanation:

In this case, the solute is C₆H₁₂O₆ and the solvent is H₂O.To find the molarity, you need to (1) convert the mass C₆H₁₂O₆ to moles (via molar mass), then (2) convert grams H₂O to liters H₂O, and then (3) calculate the molarity.

(Step 1)

Molar Mass (C₆H₁₂O₆): 6(12.011 g/mol) + 12(1.008 g/mol) + 6(15.998 g/mol)

Molar Mass (C₆H₁₂O₆): 180.15 g/mol

18.0 g C₆H₁₂O₆           1 mole
------------------------  x  -----------------  =  0.0999 moles C₆H₁₂O₆
                                   180.15 g

(Step 2)

1,000 grams = 1 L

80.0 g H₂O                1 L
--------------------  x  -------------------  =  0.0800 L H₂O
                                 1,000 g

(Step 3)

Molarity = moles solute / volume solvent (L)

Molarity = 0.0999 moles / 0.0800 L

Molarity = 1.25 M

C. The heat released when the aluminum is cooled from 70°C to 50°C is -180 J.

Specific heat capacity is the quantity of heat needed to raise the temperature per unit mass.

The heat released when the aluminum is cooled from 70°C to 50°C is calculated as follows;

Q = mcΔθ

where;

Q = (10)(0.9)(50 - 70)

Q = -180 J

Thus, the heat released when the aluminum is cooled from 70°C to 50°C is -180 J.

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The three disadvantages of hard water are:

1. Hard water is unsuitable for washing because soap does not readily create a lather in it.

2. Soap may react and produce, wasting the soap.

3. Due to the development of calcium and magnesium carbonates, tea kettles will get furred.

Water that contains a lot of minerals is referred to as hard water. In limestone, chalk, or gypsum deposits, which are mostly composed of calcium and magnesium carbonates, bicarbonates, and sulphates, hard water is created as a result of percolation. A moderate health advantage from drinking hard water is possible. In industrial settings where water hardness is regulated to prevent expensive breakdowns in boilers, cooling towers, and other water-handling equipment, it can present serious issues. Hard water is frequently detected in home settings by the build-up of lime scale in kettles and water heaters as well as by the absence of foam when soap is agitated in water. Wherever there is a worry about water hardness, water softening is frequently employed to lessen the negative impacts of hard water.

write three disadvantages of hard water.​

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Answer:

65.0 K

Explanation:

To find the temperature, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (pKa)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (8.31 L*kPa/mol*K)

-----> T = temperature (K)

You can plug the given values into the equation and simplify to find the temperature.

P = 202.65 pKa                          R = 8.31 L*kPa/mol*K

V = 2.0 L                                     T = ? K

n = 0.75 moles

PV = nRT

(202.65 pKa)(2.0 L) = (0.75 moles)(8.31 L*kPa/mol*K)T

405.3 = (6.2325)T

65.0 K = T

Answer:

5.5 grams

Explanation:

To find how much of the isotope remains, you need to use the half-life equation:

[tex]N(t) = N_0(\frac{1}{2})^\frac{t}{h}[/tex]

In this equation,

-----> N(t) = remaining mass (g)

-----> N₀ = initial mass (g)

-----> t = time (hrs)

-----> h = half-life (hrs)

You can find the remaining mass by plugging the given values into the equation and solving.

N(t) = ? g                          t = 30 hrs

N₀ = 22 g                         h = 15 hrs

[tex]N(t) = N_0(\frac{1}{2})^\frac{t}{h}[/tex]                                         <----- Half-life equation

[tex]N(30) = (22)(\frac{1}{2})^\frac{30}{15}[/tex]                                    <----- Insert values

[tex]N(30) = (22)(\frac{1}{2})^2[/tex]                                      <----- Simplify exponent

[tex]N(30) = (22)(0.25)[/tex]                                   <----- Solve [tex](\frac{1}{2} )^2[/tex]

[tex]N(30) = 5.5[/tex]                                              <----- Multiply 22 and 0.25

The heat needed is (-) 14760 Joules because the ice is cooling.

The term heat refers to a form of energy that can be observed as a result of temperature difference between two bodies. We can recall that heat always flows from the hotter to the cooler body.

Given that the heat added to a substance can be calculated by the use of H = mcdT

Where;

H = heat

m = mass

c = specific heat capacity

T = temperature change

Hence;

H = 150 g * 2.03 Jg∘C * (-63 - (-15))

H =  (-) 14760 J

Hence the heat needed is (-) 14760 Joules because the ice is cooling.

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22.37 g of chromium(II) nitrate, must be dissolved to prepare 500. mL of a 0.188 M aqueous solution of the salt.

According to the definition, the molar concentration of a substance in a solution is the ratio of the number of the moles to the volume of the solution:

c=n/V.

The number of the moles is related to the mass with the molar mass:

n=m/M;

m=n·M.

Thus, given the volume of the solution of chromium(II) nitrate, its concentration and molar mass is 238.011 g/mol we can calculate the mass of chromium(II) nitrate needed for the preparation :

∴   Cr(NO₃)₃ = cVM

                 = 0.188 M × 0.5 L × 238.011 g/mol

                 = 22.37 g

Therefore, 22.37 g of chromium(II) nitrate, must be dissolved to prepare 500. mL of a 0.188 M aqueous solution of the salt.

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B. At the equivalence point of a titration of the [H+] concentration is equal to 7.

The equivalence point of a titration is a point in titration at which the amount of titrant added is just enough to completely neutralize the analyte solution.

At the equivalence point in an acid-base titration, moles of base equals moles of acid and the solution only contains salt and water.

At the equivalence point, equal amounts of H+ and OH- ions combines as shown below;

H⁺ + OH⁻  → H₂O

The pH of resulting solution is 7.0 (neutral).

Thus, the pH at the equivalence point for this titration will always be 7.0.

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The answer is calcium.

Calcium has the largest atomic radius.