If a 1.45 M solution has 2.43 g HCl dissolved, what is the volume of solution? (Change g HCl into mol using molar mass)

Answer:D all of these

Explanation:

I just did it and that’s the correct answer

Answer:

[tex]\large \boxed{0.64 \, \%}[/tex]

Explanation:

Assume you are using 1 L of water.

Then you are washing 4 L of salty oil.

1. Calculate the mass of the salty oil

Assume the oil has a density of 0.86 g/mL.

[tex]\text{Mass of oil} = \text{4000 mL} \times \dfrac{\text{0.86 g}}{\text{1 mL}} = \text{3440 g}[/tex]

2. Calculate the mass of salt in the salty oil

[tex]\text{Mass of salt} = \text{3440 g} \times \dfrac{\text{5 g salt}}{\text{100 g oil}} = \text{172 g salt}[/tex]

3. Calculate the mass of salt in the spent water

[tex]\text{Mass of salt} = \text{1000 g water} \times \dfrac{\text{15 g salt}}{\text{100 g water}} = \text{150 g salt}[/tex]

4. Mass of salt remaining in washed oil

Mass = 172 g - 150 g = 22 g  

5. Concentration of salt in washed oil

[tex]\text{Concentration} = \dfrac{\text{22 g}}{\text{3440 g}} \times 100 \, \% = \mathbf{0.64 \, \%}\\\\\text{The concentration of salt in the washed oil is $\large \boxed{\mathbf{0.64 \, \%}}$}[/tex]

Sublevel 2s and 2p contains the valence electrons for nitrogen.

Answer:

400 kPa

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

Answer:

400 kPa

The answer is right since its from ck12

hEy!!!

Chlorine(CL) is the symbol for the entity that has 17 protons,20 neutrons and 18 electrons.

Hope it will be helpful to you...

Answer:chlorine

Explanation:

Answer:

[tex]\boxed{\text{0.25 \% H, 43.96 \% O, 4.75 \% F, 20.22 \% Al, 21.05 \% Si, 9.77 \% K}}[/tex]

Explanation:

The oxide formula is (KF)₂(Al₂O₃)₂(SiO₂)(H₂O).

Rewrite it as a molecular formula — H₂O₂₂F₂Al₆Si₆K₂

The formula for the mass percent of an element is

[tex]\text{Mass \%} = \dfrac{\text{mass of element}}{\text{mass of compound}} \times 100 \, \%[/tex]

We can set up a table to calculate the percent of each element.

[tex]\begin{array}{rrrrr}\textbf{Atom} & \textbf{No.} &\textbf{MM/u} & \textbf{Mass/u} & \mathbf{\%} \\\text{H} & 2& 1.01 & 2.02& 0.25 \\\text{O} &22 & 16.00 & 351.98 & 43.96 \\\text{F} & 2 & 19.00 & 38.00 & 4.75 \\\text{Al} & 6 & 26.98 & 161.89 & 20.22 \\\text{Si} & 6 & 28.08 & 168.51 & 21.05 \\\text{K} & 2 & 39.10 & 78.20 & 9.77 \\& & \text{TOTAL =} & \mathbf{800.60} & \mathbf{100.00} \\\end{array}\\[/tex]

[tex]\text{The percent composition of muscovite mica is}\\ \boxed{\textbf{0.25 \% H, 43.96 \% O, 4.75 \% F, 20.22 \% Al, 21.05 \% Si, 9.77 \% K}}[/tex]

Answer:

wHeRe ArE tHe StAtEmEnTs mAn

Answer:

Explanation:

Mg + 2HCl = Mg Cl₂ + H₂

.594 g = .594 / 24.3

= .02444 mole

Heat evolved = msΔ T , m is mass of water ( solvant ) , s is specific heat of water , Δ T is rise in temperature

= 100 x 4.2 x ( 41.83 - 25 )

= 7068.6 J

.02444 mole  of Mg evolves 7068.6 J of heat

1 mole of Mg evolves 7068.6 /.02444 J

= 289222.6 J

= 289 kJ .

Molar heat enthalpy = 289 kJ .

Answer:

0.200 M NaOH: 13.3 mL of the concentrated solution and complete to 20.0mL

0.150 M NaOH: 10.0 mL of the concentrated solution and complete to 20.0mL

0.100 M NaOH: 6.67 mL of the concentrated solution and complete to 20.0mL

0.050 M NaOH: 3.33 mL of the concentrated solution and complete to 20.0mL

0.025 M NaOH: 1.67 mL of the concentrated solution and complete to 20.0mL

Explanation:

It is possible to prepare a solution from a more concentrated one. In the problem, the concentrated solution is 0.300M NaOH. Thus, to prepare 20.0mL of each of the solutions you will need:

0.200 M NaOH: 20.0mL × (0.200M / 0.300M) = 13.3 mL of the concentrated solution and complete to 20.0mL

The ratio between the concentrated solution and the solution you want to prepare is called "dilution factor"

0.150 M NaOH: 20.0mL × (0.150M / 0.300M) = 10.0 mL of the concentrated solution and complete to 20.0mL

0.100 M NaOH: 20.0mL × (0.100M / 0.300M) = 6.67 mL of the concentrated solution and complete to 20.0mL

0.050 M NaOH: 20.0mL × (0.050M / 0.300M) = 3.33 mL of the concentrated solution and complete to 20.0mL

0.025 M NaOH: 20.0mL × (0.025M / 0.300M) = 1.67 mL of the concentrated solution and complete to 20.0mL

Answer:

0.10 amps

Explanation:

Answer:

1) Rate = K [ClO⁻]²

2) Rate = K [C6H5N2Cl]

3) - Double the concentration of H3PO4.

- Double the concentration of I⁻

4) Check Explanation

Explanation:

A reaction's rate law is written as a product of the reaction's rate constant, k, and the concentration of the respective reactant(s) raised to the power of the order of reaction.

The order of a reaction with respect to a reactant is the power that the concentration of that specific reactant has in the rate law. It shows how dependent on each reactant , the rate of the reaction.

1) 3ClO⁻ (aq) → ClO³⁻ (aq) + 2 Cl⁻ (aq)

Doubling the concentration of ClO⁻ quadruples the initial rate of formation of ClO³⁻. What is the rate expression for the reaction?

Rate = k [ClO⁻]ⁿ

When [ClO⁻] is doubled, Rate is quadrupled, this shows that the reaction is second order with respect to the only reactant.

Rate = K [ClO⁻]²

2. The reaction

C6H5N2Cl (aq) + H2O (l) → C6H5OH (aq) + N2 (g) + HCl (aq) is first order in C6H5N2Cl and zero order in H2O. What is the rate expression?

Normally, the rate of reaction is equal to the rate constant multiplied by the each reactant's concentration raised ti the power of the order, so,

Rate = K [C6H5N2Cl]¹ [H2O]

Rate = K [C6H5N2Cl]

3. For the reaction

H3PO4 (aq) + 3I⁻ (aq) + 2H + (aq) → H3PO3(aq) + I³⁻(aq) + H2O

(l) the rate expression under certain conditions is R = k[H3PO4][I⁻][H⁺]² . What method(s) could be used if you want to double the reaction rate?

Rate = k[H3PO4][I⁻][H⁺]²

Indicating a first order relationship between the rate and the concentration of H3PO4 & I⁻ and second order with respect to H⁺.

So, any attempt to double the rate of reaction will entail a direct doubling of the one of the reactants with a first order relationship with the rate of reaction.

4. What is the overall order of reaction for each of the following.

a) R = k[NO2]² b) R = k c) R = k[H2][Br2] ½ d) Rate = k[NO]² [O2]

Note that overall order of a reaction is the sum of all the orders of the reactants that appear in the rate law.

a) R = k[NO2]²

Overall order is obviously 2.

b) R = k

Overall order is evidently 0.

c) R = k [H2] [Br2]^ ½

Overall order = 1 + ½ = (3/2)

d) Rate = k[NO]2 [O2]

Overall order = 2 + 1 = 3

Hope this Helps!!!

Answer:

CH4 and CH3 CH2 CH2 CH3

Explanation:

Answer:

CH4 and CH3CH2CH2CH3

Explanation:

its right on edg

Due to prokaryote

Explanation:

Answer:

see explanation

Explanation:

Pure water (H₂O) at 25°C follows an autoionization mechanism. That is, water reacts with itself to yield Hydronium Ions (H₃O⁺) and Hydroxide Ions (OH⁻) according to the following proton transfer mechanism.

2H₂O(l) ⇄ H₃O⁺(aq) + OH⁻(aq) => H₂O(I) ⇄ H⁺(aq) + OH⁻(aq) as a shorthand form of the process primarily for convenience. The H⁺ ion is a proton and would not be found in solution as an independent free form particle, but the shorthand format is generally accepted in the chemical community because of it's ease of application.

Other related facts of water ionization include...

At 25°C/1atm => the molar concentrations of  [H⁺(aq)]  = 1 x 10⁻⁷M and [OH⁻(aq)] = 1 x 10⁻⁷M

Applying to the equilibrium ionization expression for water ...

                H₂O(I) ⇄    H⁺(aq)      +      OH⁻(aq)

C(eq):          ∞*         1 x 10⁻⁷M          1 x 10⁻⁷M

*The molar concentration of water is considered to be infinite [∞] as compared to concentration values of H⁺(aq) and OH⁻(aq) and is for practical purposes assumed to be constant. This leads to the classic Ionization Product constant expression for water (Kw = [H⁺(aq)][OH⁻(aq)].

The value for Kw at 25°C/1atm is then ...

Kw =  [H⁺(aq)][OH⁻(aq)] = (1 x 10⁻⁷M)(1 x 10⁻⁷M) = 1 x 10⁻¹⁴M² (units are typically dropped and Kw listed simply as 1 x 10⁻¹⁴.

With this, the terms acidity, neutral and alkaline acid base systems are defined and related to pH. That is, if ...

[H⁺(aq)] > [OH⁻(aq)] => Acidic System => pH < 7

[H⁺(aq)] = [OH⁻(aq)] => Neutral System => pH = 7

[H⁺(aq)] < [OH⁻(aq)] => Alkaline System => pH < 7

pH = -log[H⁺]  and pOH = -log[OH⁻] and pH + pOH = 14.

Answer:

THE NUMBER OF MOLES OF HELIUM NEEDED TO FILL A BALLOON AT A VOLUME OF 4.9 L AT 296 K AND 0.78 atm IS 0.00338 moles.

Explanation:

The number of moles is calculated using

PV = nRT

P = Pressure = 0.78 atm

V = volume = 4.9 L

R = gas constant = 0.082 Latm/molK

T = temperature = 296 K

n= number of moles

Substituting theses values and sloving for n, we obtain;

n = PV / RT

n = 0.78 * 4.9 / 0.082 * 296

n = 3.822 / 24.272

n = 0.00338 moles.

So therefore, the number of moles is 0.00338 moles.

Answer:

The number of moles of helium needed is 0.157 moles helium

Explanation:

Step 1: Data given

Volume of the balloon = 4.9 L

Temperature= 296 K

Pressure = 0.78 atm

Step 2: Calculate moles of helium gas

p*V = n*R*T

⇒with p = the pressure = 0.78 atm

⇒with V = the volume = 4.9 L

⇒with n = the number of moles of the helium gas = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol* K

with T = the temperature = 296 K

n = (p*V) / (R*T)

n = (0.78 atm* 4.9 L) / (0.08206 L*atm/mol*K * 296 K)

n = 0.157 moles of helium

The number of moles of helium needed is 0.157 moles helium

Answer:

400 mL

Explanation:

Boyle's Law: [tex]P_1*V_1 = P_2*V_2[/tex]

Let x = the resulting volume

350 (200) = 700 (x)

x = 400 mL

Answer:

1/2 of the Pi

Explanation:

PV = nRT

we are going to assume the only things changing are pressure and number of mols, so we change the formula and substitute the variables to make it what we are looking for

[tex]\frac{Pi}{ni} = \frac{Pf}{nf}[/tex]

then we will assume Pi as 1 as it is not given, so we can state it easier

[tex]\frac{1atm}{10mol} = \frac{xatm}{5mol}[/tex]

then either cross multiply or just work it out to be

[tex]\frac{1}{2}[/tex] which we can say as "half of the initial pressure" as no number is given for initial pressure

Answer:

0.517

Explanation:

HCN + NaOH → NaCN + H2O [balanced as written]

(35.4 mL) x (0.268 M NaOH) x (1 mol HCN / 1 mol NaOH) / (18.35 mL HCN) = 0.517 M HCN

Answer: 0.517

Explanation:

Answer:

A niche is more than a physical place; it's a species' role in a specific place and it can change from habitat to habitat.                  

Explanation:

Niche: In biology, the term "niche" is described as a process through which different organisms tends to fit-in into a specific ecosystem or an ecological community. However, a niche is considered as the "evolutionary result" of a specific species behavioral, morphological, and physiological adaptations associated with its surroundings.

Habitat: In biology, the term "habitat" is described as an environmental or ecological area that is being inhabited by a specific species of plants, animals, or other organisms.

Therefore, a niche is entirely different from a habitat because an organism's niche tends to explain every different aspect of its life whereas its habitat explains the place it lives.

Explanation:

MnO4−+ SO32− → Mn2++ SO42−

Splitting into half equations;

MnO4−  → Mn2+

SO32− → SO42−

Balancing the electrons;

2 MnO4−  + 10 e- → 2Mn2+

5SO32− → 5SO42− + 10 e-

In an acidic medium, it becomes;

2 MnO4−  +  8 H+ → 2 Mn2+ + 4 H2O

5 SO32−  + H2O → 5 SO42−  +  2 H+

Final equation is;

2 MnO4- + 5 SO32- + 6 H+ → 2 (Mn)2+ + 5 SO42- + 3 H2O

Coefficient of H+ = 6

Coefficient of H2O = 3

Coefficient of MnO4- = 2

Coefficient of SO32- = 5

Coefficient of (Mn)2+- = 2

Coefficient of SO42- = 5

Answer:

[tex]5SO_3^{2-}+2MnO_4^{-}+6H^+ \rightarrow 5SO_4^{2-}+ 2Mn^{2+}+3H_2O[/tex]

Explanation:

Hello,

In this case, given the reaction:

[tex]MnO_4^{-}+ SO_3^{2-} \rightarrow Mn^{2+}+ SO_4^{2-}[/tex]

We first identify the oxidation state of both manganese and sulfur at each side:

[tex]Mn^{7+}O_4^{-}+ S^{4+}O_3^{2-} \rightarrow Mn^{2+}+ S^{6+}O_4^{2-}[/tex]

So we have the oxidation and reduction half-reactions below, including the addition of water and hydronium as it is in acidic media:

[tex]S^{4+}O_3^{2-}+H_2O \rightarrow S^{6+}O_4^{2-}+2H^++2e^-[/tex]

[tex]Mn^{7+}O_4^{-}+8H^++5e^- \rightarrow Mn^{2+}+4H_2O[/tex]

Next, we exchange the transferred electrons:

[tex]5*(S^{4+}O_3^{2-}+H_2O \rightarrow S^{6+}O_4^{2-}+2H^++2e^-)\\2*(Mn^{7+}O_4^{-}+8H^++5e^- \rightarrow Mn^{2+}+4H_2O)\\\\5S^{4+}O_3^{2-}+5H_2O \rightarrow 5S^{6+}O_4^{2-}+10H^++10e^-\\2Mn^{7+}O_4^{-}+16H^++10e^- \rightarrow 2Mn^{2+}+8H_2O[/tex]

Then we add the resulting half-reactions and simplify the transferred electrons:

[tex]5S^{4+}O_3^{2-}+5H_2O+2Mn^{7+}O_4^{-}+16H^+ \rightarrow 5S^{6+}O_4^{2-}+10H^++ 2Mn^{2+}+8H_2O[/tex]

We rearrange the terms in order to simplify water and hydronium molecules:

[tex]5S^{4+}O_3^{2-}+2Mn^{7+}O_4^{-}+16H^+-10H^+ \rightarrow 5S^{6+}O_4^{2-}+ 2Mn^{2+}+8H_2O-5H_2O\\\\5S^{4+}O_3^{2-}+2Mn^{7+}O_4^{-}+6H^+ \rightarrow 5S^{6+}O_4^{2-}+ 2Mn^{2+}+3H_2O[/tex]

Finally we write the balanced reaction in acidic media:

[tex]5SO_3^{2-}+2MnO_4^{-}+6H^+ \rightarrow 5SO_4^{2-}+ 2Mn^{2+}+3H_2O[/tex]

Best regards.

Answer:

gas

Explanation:

If you put gas in anything, it will occupy shape and volume.

Liquid only occupies shape of the container, whereas, solid doesn't occupy shape or volume because it maintains a fixed volume and shape.

Answer:

The reaction involves two steps and occurs fastest with tertiary alkyl halides

Explanation:

To solve such this we must know the concept of nucleophilic substitution reaction. The reaction involves two steps and occurs fastest with tertiary alkyl halides. Therefore, the correct option is option A.

Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.

The characteristics of SN1 mechanism:

SN1 reaction is a nucleophilic substitution reaction.

Leaving group, a nucleophile, electrophile and a solvent are present

Two types of enantiomers can be formed in the reaction depending on the preference of the nucleophile.

The first step is the slowest because a bond is being broken.

SN1 reaction involves two steps and occurs fastest with tertiary alkyl halides

Therefore, the correct option is option A.

Learn more about the chemical reactions, here:

https://brainly.com/question/3461108

#SPJ6

Answer:

b. a.

Explanation:

Answer:

Endothermic. The energy is flowing into the molecules causing them to break apart and the ice pop change state.

Answer:

Yes, an autumn day isn’t cold enough to keep an ice pop at freezing temperatures.

Answer:

Molecules in the hot water bottle are

moving faster than molecules in the skin.

Explanation:

Answer:

The first one "Molecules in the hot water bottle are

moving faster than molecules in the skin.''

Explanation:

Answer:

See explaination

Explanation:

1. The addition of group 3A elements to group 4A semiconductors decreases the conductivity of the group 4A semiconductors: Wrong

The addition of 3A group elements inreases the conductivity and make them extrinsic semiconductors( p-type)

2. The conductivity of semiconductors can be increased by the doping process.: Correct

3.As the temperature increases, the conductivity of semiconductors decreases.. wrong

As the temperature increases, the conductivity of semiconductors increases.

4. The addition of group 5A elements to group 4A semiconductors increases the conductivity of the group 4A semiconductors: Correct : They will create n-type semicoductor.

5.Holes are charge carriers in p-type semiconductors: Correct

6. Electrons are charge carriers in n-type semiconductors: Correct

Answer:

1a. Both sides of the decay reaction have the same charge.

b. The number of nucleons on both sides are the same.

2. The binding energy of one mole of the atom is 17.172 × [tex]10^{16}[/tex] J.

Explanation:

1a. Considering the two sides of the decay reaction and with respect to the law of conservation of charge, it can be observed that both sides have the same charge. Charge can not be created or destroyed in the process.

b. The number of nucleons on both sides are equal. No nucleon is created or destroyed in the process.

2. Binding energy is the minimum energy required to separate an atom into its nucleons. From Einstein's energy equation;

             E = Δm[tex]c^{2}[/tex]

Where E is the binding energy of the atom, Δm is the mass defect and c is the speed of light.

Given that: Δm = 1.908 g/mol and c = 3 × [tex]10^{8}[/tex]. So that:

           E = 1.908 × [tex](3*10^{8}) ^{2}[/tex]

              = 1.908 × 9 × [tex]10^{16}[/tex]

              = 17.172 × [tex]10^{16}[/tex] J

The binding energy of one mole of the atom is 17.172 × [tex]10^{16}[/tex] J.

Answer:

octet rule

Explanation:

It refers to the tendency of atoms to prefer to have eight electrons in the valence shell.