Answer:
Step-by-step explanation:
LHS a - b = -9 - (-6) = -9 +6 = -3
RHS b-a = -6 - (- 9) = -6 +9 = 3
as LHS not equal to RHS
a-b not equal to b-a
Thus proven
Peter organizes morning hikes for his friends every Saturday. When the hiking trail is 3 km long, 19 friends join him and when the trail is 5 km long, only 7 friends tag along. There exists a linear relationship between the distance of the hiking trail (in km) and the number of friends who tag along. The number of friends depend on the distance of the trail. Determine how many friends will tag along to a hiking trail of 2 km.
Answer:
25
Step-by-step explanation:
x = distance of the hike
y = number of friends coming along
so, we are looking for a linear relationship between these two.
y = ax + b
we need to find the factor a and the constant offset b.
19 = a×3 + b
7 = a×5 + b
7 - b = a×5
a = (7-b)/5
19 = (7-b)×3/5 + b
19 = (21 - 3b)/5 + b
95 = 21 - 3b + 5b
74 = 2b
b = 37
a= (7-37)/5 = -30/5 = -6
so, the relationship is
y = -6x + 37
for 2km hiking
y = -6×2 + 37 = -12 + 37 = 25 friends
What is the slope of (-0,-1) and (3,1)
Answer:
Step-by-step explanation:
(0, -1) & (3 ,1)
[tex]Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{1-[-1]}{3-0}\\\\=\frac{1+1}{3}\\\\=\frac{2}{3}[/tex]
If the current through a circuit is 2 A and the resistance of a light bulb in the circuit is 10 Ohms what is tge voltage difference across the light bulb
Answer:
v = ir
2 times 10 = 20v
Step-by-step explanation:
i think it is the one
Dr. Smith is interested in the relationship between nicotine and hand steadiness. Two groups participated in the experiment. One group smoked 5 cigarettes in an hour, while another group read during the same hour. Participants are then tested on the hand steadiness apparatus (yielding a score with the number of errors made). What is the independent variable
Answer:
Exposure to nicotine is the independent variable
Step-by-step explanation:
An independent variable is a factor that remains unchanged (by other factors in the experiment) throughout the course of an experiment. It can however be manipulated by the researcher. A dependent variable, on the other hand, is the factor being measured that relies on the independent variable. In the case above, exposure to 1 hr of nicotine intake forms the independent variable while the levels of hand steadiness, which will be measured, form the dependent variable.
Help me with moth of these questions please
Answer:
10. CD + DE = CE
11. BC + CE = BE
Step-by-step explanation:
10. CD and DE lie on a straight line, therefore, CD + DE = CE based on the segment addition postulate.
11. BC and CE lie on a straight line, therefore, BC + CE = BE based on the segment addition postulate.
Which terms in the following expression are like terms?
x3 + 5x - 3x + 3y + 4 - 1
3x and 3y
x 3, 3x, and 3y
5x and 3x, and 4 and 1
x 3 and 3x, and 4 and 1
9514 1404 393
Answer:
(c) 5x and 3x, and 4 and 1
Step-by-step explanation:
Like terms have the same variable(s) to the same power(s).
The terms of this expression are ...
x^3: variable x, power 35x: variable x, power 1-3x: variable x, power 13y: variable y, power 14: no variable-1: no variableThe like terms are {5x, -3x}, which have the x-variable to the first power, and {4, -1}, which have no variable.
Determine whether the given functions are linearly dependent or linearly independent on the specified interval. Justify your decision.
The question is incomplete. The complete question is :
Determine whether the given functions are linearly dependent or linearly independent on the specified interval. Justify your decision.
[tex]$\{ x^5, x^5-1,3 \} \text{ on } (- \infty, \infty)$[/tex]
Solution :
Given :
Function : [tex]$\{ x^5, x^5-1,3 \} \text{ on } (- \infty, \infty)$[/tex]
We have to determine whether the given function is linear dependent or linearly independent for the interval [tex]$(-\infty, \infty)$[/tex].
The given function are linearly dependent because for the constants, [tex]c_1[/tex] and [tex]c_2[/tex], the equation is :
[tex]$c_1x^5 + c_23 = x^5-1$[/tex] has the solution [tex]$c_1 = 1$[/tex] and [tex]$c_2 = -\frac{1}{3}$[/tex]
Therefore,
[tex]$1x^5 + \left(-\frac{1}{3}\right)3 = x^5-1$[/tex]
Previous Question Question 17 of 20 Next Question Based on the regression model, the expected daily production volume with 112 factory workers is 118,846 units. The human resource department noted that 123,415 units were produced on the most recent day on which there were 112 factory workers. What is the residual of this data point
Answer:
4,569 units
Step-by-step explanation:
Given :
Measured value = 123,415 units
Expected value = 118,846 units
Residual is the difference between the measured and expected value :
Residual = Measured value - Expected value
Residual = 123,415 units - 118,846 units
Residual = 4,569 units
What does point b represent on the graph ?
Answer:
Step-by-step B represents the $14 John earned in the 2 hours he worked.
explanation:
Jill has 32 crayons. She loses 4 of the crayons. How many are left?
Answer:
the answer here is d
the answer is d
Answer:
28
Step-by-step explanation:
Total number of crayons = 32
Number of crayons lost = 4
Therefore, number of crayons she is left with is : 32 - 4 = 28
Working :
[tex]32\\04 - \\\overline{28}[/tex]
¿Pueden ayudarme por favor?
The 11th term of an arithmetic progression is 14 and the sum of the first 26 terms is 416. Find the first term and the common difference.
Answer:
The first term is 6; the common difference in 0.8.
Step-by-step explanation:
The nth term is:
[tex] a_n = a_1 + (n - 1)d [/tex]
The sum of the first n terms is:
[tex] S_n = \dfrac{n(a_1 + a_n)}{2} [/tex]
[tex] a_{n} = a_1 + (n - 1)d [/tex]
[tex] a_{11} = a_1 + (11-1)d [/tex]
[tex] a_1 + 10d = 14 [/tex] Equation 1
[tex] S_n = \dfrac{n(a_1 + a_n)}{2} [/tex]
[tex] S_{26} = \dfrac{26(a_1 + a_{26})}{2} [/tex]
[tex] \dfrac{26(a_1 + a_1 + 25d}{2} = 416 [/tex]
[tex] \dfrac{52a_1 + 650d)}{2} = 416 [/tex]
[tex] 26a_1 + 325d = 416 [/tex] Equation 2
Equation 1 and Equation 2 form a system of equations in 2 unknowns.
To eliminate a_1, subtract 26 times Eq. 1 from Eq. 2.
[tex] 65d = 52 [/tex]
[tex] d = \dfrac{52}{65} [/tex]
[tex] d = \dfrac{4}{5} = 0.8 [/tex]
[tex] a_1 + 10d = 14 [/tex]
[tex] a_1 + 10 \times 0.8 = 14 [/tex]
[tex] a_1 + 8 = 14 [/tex]
[tex] a_1 = 6 [/tex]
Answer:
The first term is 6; the common difference in 0.8.
A papaya is accidentally dropped from a bridge, which is 30 m above the water. Ignoring air resistance, the papaya's speed just before it hits the water will be __________ m/s.
Answer:
24 .30ms is the answer I think so if the answer is correct plz mark me as brainliest.
The papaya's speed just before it hits the water will be 24.24 m/s.
What is speed?The rate at which objects moves is called speed. It is given by
[tex]s = \frac{d}{t}[/tex]
An object held above the ground has a potential energy related to the height at which it is held,
PE = mgh
If you drop the object, its potential energy will become the kinetic energy of motion:
KE = ½ mv²
½ mv² = mgh
v = √(2gh)
v = √(2*9.8*30)
v = 24.24 m/s
To learn more about Speed here
https://brainly.com/question/7359669
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Two trains leave stations 192 miles apart at the same time and travel toward each other. One train travels at 85 miles per hour while the other travels at 75
miles per hour. How long will it take for the two trains to meet?
Do not do any rounding.
11 hours
Answer:
32 miles per hour
Step-by-step explanation:
x+85+75=192 x+160=192 x=192-160 x=32..
Find the area of the region that is enclosed between the curves y = x2 and
y = x + 6.
Integrate:
[tex]\displaystyle\int_{-2}^3((x+6)-x^2)\,\mathrm dx = \int_{-2}^3(6+x-x^2)\,\mathrm dx[/tex]
[tex]=\left(6x+\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{-2}^3[/tex]
[tex]=\left(18+\dfrac92-9\right) - \left(-12+2+\dfrac83\right)[/tex]
[tex]=\boxed{\dfrac{125}6}[/tex]
The data on the box plot describes the weight of several students in sixth grade. Which of the following statements are true about the data set? Select all that apply.
One-fourth of the students weigh between 90 and 101 pounds.
One-half of the students weigh between 75 and 90 pounds.
The median weight of the sixth graders is 85 pounds.
One-fourth of the students weigh less than 75 pounds.
One-fourth of the students weigh more than 75 pounds.
The total range of weight is 40 pounds.
Answer:
Step-by-step explanation:
B
Please help. I'm stuck on this problem
Answer:
Step-by-step explanation:
[tex]h(t)=-16t^2+96t\\\\h(t)=-t(16t-96)[/tex]
[tex]96=2^5*3\\\\16=2^4\\\\h(t)=-t(2^5*3*t-2^4)=-2^4t(2^1*3*t-1)\\\\h(t)=-16t(6t-1)[/tex]
the b) part is easy do it!
Can someone help me?
Answer:
x = 80
Step-by-step explanation:
3x/2=120°
3x=240°
x=80°
Answered by GAUTHMATH
4b^2+300=0 this is a quadratic equation that I am trying to solve including any solutions with imaginary numbers I will include a picture
Answer:
b= 5i square root of 3
b = -5i square root of 3
Step-by-step explanation:
4b^2+300=0
4b^2 = -300
b^2 = -75
b = square root of -75
b = -75^1/2
^1/2 means square root
b = 25^1/2 * 3^1/2 * i
b= 5i square root of 3
b = -5i square root of 3
A lift in a building starts with 7 passengers and stops at 10 floors.if each passenger is equally likely to get off at any floor and all passengers leave independently.what is the probability that atleast two passengers will get off at the same floor?
Answer:
Correct option is
C
10
5
10P
5
Total ways in which one passenger can stop =10
Total ways in which 5 passengers can stop =10∗10∗10∗10∗10
=10
5
We will select 5 floors from 10 floors and assign each individual to each floor to keep everyone isolated from each other
No. of ways in which no two persons stop at the same floor =10C
5
∗5!
=10P
5
⇒P(E)=10P
5
/10
5
Amy worked 37.5 hours last week.
She is paid £11.50 per hour.
Her total deductions last week were £116.30.
What was Amy’s net pay last week?
£
if 8km=5miles.how many miles are in 56m?
Answer:
89.6 miles
Step-by-step explanation:
[tex]\frac{8}{5}[/tex] = [tex]\frac{x}{56}[/tex]
5x = 448
x=89.6
Step-by-step explanation:
if 8km=5
x =56km
5x=8×56
5x=448
x=89.6 miles
Write each of the following numbers to 3 significant figures in exponential or scientific notation. Write each number with only one non-zero digit before the decimal point.
(i) 5590
(ii) 0.000498
(iii) 135000
(iv) 0.000438
Solution :
The significant figure of a number are defined as the positional notation of that number which are most reliable and are absolutely necessary to represent the quantity of something.
In the context, we have to express the given numbers into three significant figures in the form of scientific notation or in the exponential form :
(i). 5590 ----- [tex]$5.59 \times 10^3$[/tex]
(ii). 0.000498 ----- [tex]$4.98 \times 10^{-4}$[/tex]
(iii) 135000 ----- [tex]$1.35 \times 10^5$[/tex]
(iv) 0.000438 ----- [tex]$4.38 \times 10^{-4}$[/tex]
The frequency distribution below summarizes the home sale prices in the city of Summerhill for the month of June. Determine the lower class limits.
Answer:
79.5, 110.5, 141.5, 172.5, 203.5, 234.5
Step-by-step explanation:
Given
The attached distribution
Required
The lower class limits
To do this, we simply subtract 0.5 from the lower interval
From the attached distribution, the lower intervals are:
80.0, 111.0, 142.0, 173,0 .......
So, the lower class limits are:
[tex]80.0-0.5 = 79.5[/tex]
[tex]111.0-0.5 = 110.5[/tex]
[tex]142.0-0.5 = 141.5[/tex]
[tex]173.0-0.5 = 172.5[/tex]
[tex]204.0-0.5 = 203.5[/tex]
[tex]235.0-0.5 = 234.5[/tex]
Carlos has an aquarium which is 45 cm long, 32 cm wide, and 35 cm high. How much water can the aquarium hold?
Answer:
volume =l×b×h
45cm×32cm×35cm=48,960cm³
Weatherwise magazine is published in association with the American Meteorological Society. Volume 46, Number 6 has a rating system to classify Nor'easter storms that frequently hit New England states and can cause much damage near the ocean coast. A severe storm has an average peak wave height of 16.4 feet for waves hitting the shore. Suppose that a Nor'easter is in progress at the severe storm class rating.
(A) Let us say that we want to set up a statistical test to see if the wave action (i.e., height) is dying down or getting worse. What would be the null hypothesis regarding average wave height?
a) μ < 16.4.
b) μ > 16.4.
c) μ = 16.4.
d) μ ≠ 16.4.
(B) If you wanted to test the hypothesis that the storm is getting worse, what would you use for the alternate hypothesis?
a) μ < 16.4.
b) μ = 16.4.
c) μ ≠ 16.4.
d) μ > 16.4.
(C) If you wanted to test the hypothesis that the waves are dying down, what would you use for the alternate hypothesis?
a) μ < 16.4.
b) μ ≠ 16.4.
c) μ > 16.4.
d) μ = 16.4.
(D) Suppose you do not know if the storm is getting worse or dying out. You just want to test the hypothesis that the average wave height is different (either higher or lower) from the severe storm class rating. What would you use for the alternate hypothesis?
a) μ > 16.4.
b) μ = 16.4.
c) μ ≠ 16.4.
d) μ < 16.4.
(E) For each of the tests in parts (b), (c), and (d), would the area corresponding to the P-value be on the left, on the right, or on both sides of the mean?
a) left; right; both.
b) left; both; right.
c) both; left; right.
d) right; left; both.
Answer:
a) c) μ = 16.4.
b) d) μ > 16.4.
c) a) μ < 16.4.
d) c) μ ≠ 16.4.
e) d) right; left; both.
Step-by-step explanation:
Question a:
Test if it is getting worse, so at the alternative hypothesis we test if the mean is of greater than 16.4 inches, but at the null hypothesis we test if it is still of 16.4 options, so option C.
Question b:
At the alternative hypothesis we test if the mean is of greater than 16.4 inches, as said above, so the answer is given by option d.
Question c:
Dying down, so if the mean is lower than 16.4 inches, so option a.
Question d:
Don't know, so just test if it is different, which includes both lower or greater, so the correct answer is given by option c.
Question e:
Test if more -> right, so on question b) is a right tailed test.
Test if less -> left, so on question c) is a left tailed test.
Different -> both sides, so on question d) it is a two-tailed test.
Thus the correct answer is given by option d.
The amount of tax on a chair was $3.60. The tax rate was 5%. Find the original price of the chair.
Bianca solved the problem below. Find Bianca’s error.
0.05(3.60) = Original price
The original price is $0.18.
9514 1404 393
Answer:
$72.00
Step-by-step explanation:
The relationship between price and tax is ...
tax amount = (tax rate) × (price)
Then the price can be found by dividing by the tax rate:
price = (tax amount)/(tax rate)
price = $3.60 / 0.05 = $72.00
The original price of the chair was $72.00.
__
Bianca apparently did not pay any attention to the way tax is computed. Nor did she check her work. The original price is not a small fraction of the tax. It is the other way around. Bianca used a wrong relationship between tax and price.
The solution to the equation x3 = 125 is: 5 -5 ±5
Answer:
x=5
Step-by-step explanation:
x^3 = 125
Take the cubed root of each side
x^3 ^ (1/3) = 125 ^ (1/3)
x = 5
PLEASE HELP!!! I tried using different formulas, adding, subtracting, dividing, multiplying you name it and I have yet to find the correct answer. How would I should this problem?
Answer:
19.14
Step-by-step explanation:
You have a half circle and a square, look at them separate then add for the area.
Circle
Your radius is half the diameter, so 4/2
Radius = 2
[tex]A = 3.14 * radius\\A = 3.14 * 2\\A = 6.28[/tex]
This is for the entire circle, half of that would be 3.14
Square
[tex]A = 4^{2} \\A = 16[/tex]
Add them both together for a total area of 19.14 square miles
Suppose you have $1750 in your savings account at the end of a certain period of time. You invested $1500 at a 3.72% simple annual interest rate. How long, in years, was your money invested?
Answer:
4.48 years
Step-by-step explanation:
The formula for simple interest is
A = P(1+r*t), with A being the final amount, P being the initial amount, r being the interest rate, and t being the time. Plugging our values in, we get
1750 = 1500(1+0.0372 * t)
Note that 3.72 was translated into 0.0372 as changing percents to decimals requires dividing by 100
Expanding our equation, we get
1750 = 1500 + 55.8 * t
subtract 1500 from both sides to isolate the t and its coefficient
250 = 55.8 * t
divide both sides by 55.8 to get t
t = 4.48
