A subcritical state will result by flattening a critical mass of fissionable material into the shape of a hamburger.
To find the answer, we need to know about the critical mass.
What is critical mass?A material's nuclear characteristics (particularly, its nuclear fission cross-section), density, shape, enrichment, purity, temperature, and environment all affect its critical mass.A mass of fissile material is considered to be in a critical state when a nuclear chain reaction in the mass is self-sustaining and there is no change in power, temperature, or neutron population. At a specific temperature, a mass might be precisely critical. A subcritical state will result by flattening a critical mass of fissionable material into the shape of a hamburger.The cross sections for fission and absorption grow as the relative neutron velocity drops.Thus, we can conclude that, a subcritical state will result by flattening a critical mass of fissionable material into the shape of a hamburger.
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By what age do babies generally develop full sensitivity for taste?
By the age of
babies generally develop full sensitivity for taste.
Answer: 12 to 19 months
Explanation:
If you are operating under basicmed, what is the maximum speed at which you may fly?
Answer:
250 kts
Explanation:
is the flight restriction for BasicMed
Describe how an oil spill could affect the aquaculture and fishing industries.
If the resistance in a circuit connected to a constant current is halved, how is the voltage in the circuit affected?.
The voltage is reduced by a factor of 2.
What is resistance?
Resistance is a proportion of the opposition to flow stream in an electrical circuit. Opposition is estimated in ohms, represented by the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who concentrated on the connection between voltage, current and resistance.The equation to compute the obstruction utilizing Ohm's Law is given as keeps:R = V I.
where,
R is the resistance of the resistor R in ohms (Ω)
V is the voltage drop in the resistor in volts.
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Glycerin at a temperature of 30 degrees celcius flows at a rate of 8×10−6m3/s through a horizontal tube with a 30mm diameter. what is the pressure drop in pascals per 100m?
The pressure drop in pascal is 3.824*10^4 Pascals.
To find the answer, we need to know about the Poiseuille's formula.
How to find the pressure drop in pascal?We have the Poiseuille's formula,[tex]Q=\frac{\pi Pr^4}{8\beta l}[/tex]
where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, [tex]\beta[/tex] is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.
It is given that,[tex]Q=8*10^{-6}m^3/s\\diameter=30mm, thus,\\r=15mm\\l=100m\\\beta =0.95[/tex]
Thus, the pressure drop will be,[tex]P=\frac{8Q\beta l}{\pi r^4} =\frac{8*8*10^{-6}*0.95*100}{3.14*(15*10^{-3})^4} \\\\P=3.824*10^4Pascals.[/tex]
Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4 Pascals.
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A proton moving eastward with a velocity of 5. 0 × 103 m/s enters a magnetic field of 0. 20 t pointing northward. what is the magnitude and direction of the force that acts on the proton?
The magnitude of the force is 1.6*10^-16 N. The direction of force is upward.
The definition of force is the push or pull that causes a massed object to change its velocity. Force is an external agent that has the power to alter a body's resting or moving position. It has a direction and a magnitude. The total amount of forces exerted on an object is referred to as the magnitude of force.
The strength of the force increases when all the force is pulling in the same direction. When force is exerted on an item from different angles, the force's strength reduces. The amount that encapsulates the force's strength is known as its magnitude.
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Knowing that the speed of the flywheel is 300 rpm just before a punching operation, determine the speed immediately after the punching operation?
the speed of flywheel is 300 rpm just before a punching operation,then the speed of the flywheel immediately after the punching operation is 299.93 rpm.
The answer of the above question is as follows:
mass of the flywheel of the punching machine (m) is 300 kg .
radius of gyration of the flywheel is :
[tex]k = 600 mm \times \frac{1m}{100mm} = 6m[/tex]
work to be done against each punching by the wheel (W) is 2500J.
initial angular velocity of the flywheel is:
[tex]w = 300rpm \times \frac{ \frac{\pi}{30} \frac{rad}{s} }{1rpm} = 10 \frac{\pi \: rad}{s} [/tex]
therefore the angular speed of the flywheel immediately after punching is given by
w1 =299.93 rpm
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Disclaimer : the given question is incomplete, thus the complete question is as follows:
Question: The flywheel of a punching machine has a mass of 300 kg mass and a radius of gyration of 600 mm. each punching operation requires 2500 J of work.
(a) knowing that the speed of the flywheel is 300 rpm just before a punching,determine the speed immediately after the punching.
The school is 1 km away from a teacher’s house. A teacher driving to the school has an acceleration of 20 m/s2 . When starting from rest, what would be the distance travelled in 10 seconds? How much more distance does the teacher have to travel to reach the school?
[tex]x = \frac{at {}^{2} }{2} + vt + x(0)[/tex]
[tex]x = \frac{20 \times (10) {}^{2} }{2} + 0 + 0 = \frac{2000}{2} = 1000 \: meters[/tex]
2)0 meters since she has already reached school. Note: 1000 meters = 1 kilometerWhat does friis free space loss (fsl) tell us about unguided transmission attenuation? fsl=(4πd/λ)2
When we consider unguided wireless communications, we must understand the signal attenuation that occurs between transmit and receive antennas.
The information, or message, that we wish to transmit, is modulated onto a frequency carrier, which is then emitted from a transmit antenna in the form of an electromagnetic (EM) wave.
The signal power (watts) received by the antenna is much less than the transmitted power due to attenuation loss. The Friis equation (also known as the Free Space Loss, FSL equation) describes this attenuation loss.Attenuation, as treated in the Friis equation, is the spreading of power over an ever increasing surface area as it propagates away from the transmit antenna.
We can measure how much power resides in a 1 meter2 area as a function of distance from the isotropic antenna.
Power Density, Pd = Pt/(4πd2)
where the (λ/4πd)2 term is sometimes referred to as the path loss or free space loss. The following definitions are assumed:
Pt - The transmitted signal power.
λ - The wavelength of the carrier (i.e., the center frequency of the radiated signal)
d - The distance between the transmitting and receiving antennas.
We can also place the above equation into decibel format:
FSLdB = [FSL] = 20log10(4πd/l) = 20log10(4π) + 20log10(d) - 20log10(l)
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What is the energy (in evev) of a photon of visible light that has a wavelength of 500 nmnm?
_______________
λ=500 nm = 500·10⁻⁹ m
c=3·10⁸ m/s
h=6,63·10⁻³⁴ J·s = 4,14·10⁻¹⁵ eV·s
_______________
E - ?
_______________
[tex]\displaystyle \boldsymbol{E}=h\nu =h \frac{c}{\lambda} =4,14\cdot 10^{-15} \; eV\cdot s\cdot \; \frac{3\cdot 10^8\; m/s}{500\cdot 10^{-9}\; m} =2,484\; eV\approx \boldsymbol{2,5\; eV}[/tex]
How does betelgeuse compare to the other stars in the amount of light it is giving off?
Betelgeuse is the 10th brightest star in the night sky comparing to other stars. And it is the second brightest in Orion's constellation.
Betelgeuse is the tenth brightest star in the night sky and, after Rigel, the second brightest in Orion's constellation. it is a distinctly reddish semiregular variable star with the widest apparent magnitude range of any first-magnitude star, ranging from +0.0 to +1.6. Betelgeuse is the brightest star in the night sky at near - infrared wavelengths. Its Bayer name is Orionis, which is Latinized to alpha Orionis and abbreviated alpha Ori or Ori
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When an objective lens is 20x and the ocular lens is 10x, the total magnification of a specimen will be:_________.
The total magnification will be 200x.
What is Magnification?It quantifies the comparison of the image's size to that of the object's size. In terms of how big or little the picture is produced, it informs us about the image. The height of the picture divided by the height of the object is known as magnification. m=hiho.
Objective lens - An essential component of the microscope's optics is the objective lens. The sample, specimen, or item being examined is situated close to the microscope's objective. It plays a crucial part in imaging since it creates the initial magnified picture of the sample.
Ocular lens - The component of the microscope known as the eyepiece, or ocular lens, is responsible for enlarging the picture created by the objective so that it can be viewed by the human eye.
20x objective lens was used by specimen
10x ocular lens was also used by him.
we have to find the total magnification.
For calculating the total magnification we 'll simply do multiplication
Total Magnification = 20 × 10x
Total Magnification = 200x
So , the total magnification will be 200x .
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Find both the scalar projection compvuand the vector projection projvuof the vectoru=〈1,−1,1〉onto the vectorv=〈1,0,1〉. answer:. . . . . . . . . . . . . . . . . . . .
Its Scalar projection [tex]\sqrt{2}[/tex] and Vector projection 1 (i+0j+k).
How to find scalar projection and vector projection ?We have been given two vectors <1 -1 1> and vector <1 0 1> , we are to find out the scalar and vector projection of vector <1 -1 1> onto vector <1 0 1>
We have vector a = <1 -1 1> and vector b = <1 0 1>
The scalar projection of vector a onto vector b means the magnitude of resolved component of vector a in the direction of vector b and is given by
The scalar projection of vector a onto vector b = [tex]\frac{vector b . vector a}{|vector b| }[/tex]
= [tex]\frac{(1-1+1)(1+0+1)}{\sqrt{1^{2} }+0+1^{2} }[/tex]
=[tex]\frac{1^{2} + 1^{2} }\sqrt{2}[/tex]
= [tex]\sqrt{2}[/tex]
The Vector projection of vector a onto vector b means the resolved component of vector a in the direction of vector b and is given by
The vector projection of vector a onto vector b .
= [tex]\frac{vector b . vector a}{| vector b|^{2} }[/tex] (i+0j+k)
= [tex]\frac{(1-1+1)(1+0+1)}{{1^{2} }+0+1^{2} }[/tex]. (i+0j+k)
= [tex]\frac{1^{2} + 1^{2} }{\sqrt{2} }[/tex] (i+0j+k)
= 1 (i+0j+k).
Thus from the above conclusion we can say that scalar projection scalar projection [tex]\sqrt{2}[/tex] and vector projection 1 (i+0j+k).
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how to calculate that
Explanation:
Acceleration= 15-3/2
=6m/s²
Answer:
acceleration = [tex]\bf 6 m/s^2[/tex]
Explanation:
We can calculate the acceleration of an object using the following formula:
[tex]\boxed{acceleration = \frac{Resulatant \space\ force}{Mass}}[/tex].
The resultant force is the effective force that is being applied to an object. In this case, there is a 15N force to the right, and a 3N force to the left.
∴ Resultant force = 15N - 3N
= 12N
Now we can use the formula for above formula to calculate acceleration:
[tex]acceleration = \frac{12}{2}[/tex]
= [tex]\bf 6 m/s^2[/tex]
A 2. 0 μf and a 4. 0 μf capacitor are connected in series across an 8. 0-v dc source. what is the charge on the 2. 0 μf capacitor?
voltage across 2.0μf capacitor is 5.32v
Given:
C1=2.0μf
C2=4.0μf
since two capacitors are in series there equivalent capacitance will be
[tex] \frac{1}{c} = \frac{1}{c1} + \frac{1}{c2} [/tex]
[tex]c = \frac{c1 \times c2}{c1 + c2} [/tex]
[tex] = \frac{2 \times 4}{2 + 4} [/tex]
=1.33μf
As the capacitance of a capacitor is equal to the ratio of the stored charge to the potential difference across its plates, giving: C = Q/V, thus V = Q/C as Q is constant across all series connected capacitors, therefore the individual voltage drops across each capacitor is determined by its its capacitance value.
Q=CV
given,V=8v
[tex] = 1.33 \times 10 {}^{ - 6} \times 8[/tex]
[tex] = 10.64 \times 10 {}^{ - 6} [/tex]
charge on 2.0μf capacitor is
[tex] \frac{Qeq}{2 \times 10 {}^{ - 6} } [/tex]
[tex] = \frac{10.64 \times 10 {}^{ - 6} }{2 \times 10 {}^{ - 6} } [/tex]
=5.32v
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Compute the torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min.
The torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min will be 389 Nm.
Given
Power = 175kw = 17500 WAngular Speed(ω) = 4300 rev/min = 450 rad/sLet Torque = т
P = т * ω
т = P/ ω
т = 17500 / 450 = 388.88 Nm (approx. 389 Nm)
Hence , the torque developed by an industrial motor whose output is 175 kw at an angular speed of 4300 rev/min will be 389 Nm.
In physics and mechanics, torque is the rotational equivalent of linear force. It is also referred to as the moment, moment of force, rotational force or turning effect, depending on the field of study. It represents the capability of a force to produce change in the rotational motion of the body.
We can define power as the rate of doing work, it is the work done in unit time. The SI unit of power is Watt (W) which is joules per second (J/s). Sometimes the power of motor vehicles and other machines is given in terms of Horsepower (hp), which is approximately equal to 745.7 watts.
Angular speed is the speed of the object in rotational motion.
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Sun has an eective temperature of about 5800 kelvins. What is the peak wavelength emitted by the sun?
By Wien's displacement law we can conclude that, the peak wavelength emitted by the sun for 5800K temperature is 499nm.
To find the answer, we have to know about Wien's distribution law.
How to find the maximum wavelength?The black-body radiation curve for various temperatures will peak at various wavelengths that are inversely proportional to the temperature, according to Wien's displacement law.It is given that, Sun has an active temperature of about 5800 kelvins.Thus, by Wien's distribution law, the maximus wavelength is,[tex]wavelength*T=2.898*10^{-3}mK\\wavelength=\frac{2.898*10^{-3}mK}{5800K}=499nm.[/tex]
Thus, by Wien's displacement law we can conclude that, the peak wavelength emitted by the sun for 5800K temperature is 499nm.
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Class 11
Physics
Motion in a Plane
The unit vectors along the three co-ordinate axes are described as. i > j > k > 1. is D. i = j = k = 1
What is the unit vector along the vector?A vector that has a volume of 1 is a unit vector. It is also known as a direction vector because it is generally used to denote the direction of a vector. The vectors i, j, k, stand the unit vectors along the x-axis, y-axis, and z-axis respectively.
What is the unit vector along y-axis?
There are three essential unit vectors which are commonly employed and these are the vectors in the direction of the x, y and z-axes. The unit vector in the direction of the x-axis is i, the unit vector in the direction of the y-axis is j and the unit vector in the demand of the z-axis is k.
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How much heat in joules will it take to raise the temperature of a 100. 0 g piece of copper from 18°c to 35°c? the specific heat capacity of copper is 0. 385 j ⁄ g · °c
The amount of heat generated is 654.5 joules.
q=mCΔT
Given,
m=100, C=0.385 j ⁄ g · °c, [tex]T_{1} =18^{0}C , T_{2} =35^{0} C[/tex],
q=100*0.385*(35-18)= 654.5 j
HeatHeat is defined as energy that is transferred to or from a thermodynamic system by means other than thermodynamic work or the movement of matter (e.g. conduction, radiation, and friction). Similar to thermodynamic work, heat transfer affects a system's surrounds in addition to the system itself; as a result, it is not a characteristic of the system alone, even while it helps to change the internal energy of the system, which is a property of the system alone. This differs from the common linguistic usage of the word "heat" as a system feature in and of itself. The quantity of energy that is transported as heat in a process is the amount of energy that has been transferred minus any thermodynamic work that has been done and any energy that has been contained in the substance being moved.
How much heat in joules will it take to raise the temperature of a 100. 0 g piece of copper from 18°c to 35°c? the specific heat capacity of copper is 0. 385 j ⁄ g · °c
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Describe the usefulness or inconvenience of frictional force by turning a door knob.
The cylinder is pulled in the direction of the knob's turn. If the knob is not twisted, a latch at the end of the cylinder that extends into a recess in the doorframe stops the door from being opened.
What is Frictional force ?The opposing force that is produced when two surfaces attempt to move in the same direction or in opposite directions is known as frictional force. A frictional force is primarily intended to produce resistance to the mobility of one surface over another.
Between solid surfaces, there is friction that is static, sliding, and rolling. The three types of friction are ranked from strongest to weakest: rolling, sliding, and static. Fluids experience fluid friction, which is liquid or gaseous.Learn more about Frictional force here:
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Which one of the following possesses the highest elasticity? a. Rubber b. Glass c. Copper d. Steel
Answer:
Correct option is D)
Steel
Answer:
Steel gives
Explanation:
Glass: 50−90GPa
Rubber:0.01−0.1GPa
Steel:200GPa
Copper: 117GPa
Suppose a comet orbits the sun on a highly eccentric orbit with an average (semimajor axis) distance of 1 au. how long does it take to complete each orbit, and how do we know?
If a comet were to orbit the sun with a highly eccentric orbit and an average (semimajor axis) distance of 1 au, we might use Kepler's third law of planetary motion to determine that each orbit would take one year to complete.
To find the answer, we need to know about the Kepler's third law of planetary motion.
What is Kepler's third law of planetary motion?The period of a planet's orbit (T) squared is equal to the size of the semi-major axis of the orbit (a) cubed when it is stated in astronomical units because T² ∝ a³ according to Kepler's Third Law. In reality, Kepler's Third Law compares a planet's orbital period and radius to those of other planets.Thus,[tex]a=1AU\\T=(1)^{3/2}=1 year[/tex]
Thus, we can conclude that, If a comet were to orbit the sun with a highly eccentric orbit and an average (semimajor axis) distance of 1 au, we might use Kepler's third law of planetary motion to determine that each orbit would take one year to complete.
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A car coasts 62. 2 meters along a hill that makes a 28. 3° angle with the ground. if the car's mass is 1234 kg, then what is the change in potential energy?
The change in Potential energy is = 662,292.459 J.
How can we calculate the value of change in potential energy?Here, to calculate the potential energy change we use the formula,
[tex]W= F \times d \times cos\theta[/tex]
Or, [tex]W= m\times g \times d \times cos\theta[/tex]
Here we are given,
d= Distance the car makes = 62. 2 m.
[tex]\theta[/tex] = Angle that the car make along the hill = 28. 3°
F= The amount of force affect on the car = [tex]m\times g[/tex] .
m= Mass of the car = 1234 kg.
g= Acceleration of gravity = 9.8 [tex]m/s^2[/tex]
Now we substitute the known values in the above equation,
[tex]W= m\times g \times d \times cos\theta[/tex]
Or, [tex]W= 1234 \times 9.8 \times 62.2 \times cos(28.3)[/tex]
Or, [tex]W= 662,292.459 J[/tex]
From the above calculation we can conclude that the amount of work done on the car is, 662,292.459 J.
We know, from the work energy theorem that,
The change in Potential energy = The work done on the mass.
So, From the above theorem the change in potential energy is 662,292.459 J.
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A process with a negative change in enthalpy and a negative change in entropy will generally be:________
A process with a negative change in enthalpy and a negative change in entropy will generally be: spontaneous.
Gibbs free energy:Since the Gibbs free energy is a parameter that tells us whether a chemical reaction is spontaneous (Gibbs free energy less than 0) or nonspontaneous (Gibbs free energy greater than 0) in this situation, we can describe it mathematically as:
ΔG = ΔH - TΔS
Therefore, any process with a negative change in enthalpy and a positive change in entropy will be spontaneous. If the enthalpy and the entropy are both negative, the subtraction becomes always negative, for which the Gibbs free energy is also negative.
One of the most crucial thermodynamic functions for the characterization of a system is the Gibbs free energy. It influences results like the voltage of an electrochemical cell and the equilibrium constant for a reversible reaction, among others.
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Which has more total enthalpy 3kg of 20% of salt brine at 65 degrees Celsius or 5kg of 20% salt brine at 50 Degrees celsius, assuming 0 enthalpy at 0 degrees celsius? The specific heat capacity of 20% salt brine is 3.56kJ/kg*C
The 3kg of 20% of salt brine at 65 degrees Celsius has more enthalpy than the 5kg of 20% salt brine at 50 Degrees Celsius.
What is enthalpy?Enthalpy is defined as the total heat content of a system. The enthalpy is a measure of the total work which the system can do plus the internal energy of the system.
The enthalpy of the given solutions can be calculated as follows:
Enthalpy = mass * specific heat capacity * temperature change.For the 3kg of 20% of salt brine at 65 degrees;
mass of salt = 3 * 20% = 0.6 kg
specific heat capacity = 3.56kJ/kg*C
temperature change = 65°C
Enthalpy = 0.6 * 3.56 * 65
Enthalpy = 232 kJ
For the 5kg of 20% salt brine at 50 Degrees Celsius;
mass of salt = 5 * 20% = 1 kg
specific heat capacity = 3.56kJ/kg*C
temperature change = 50°C
Enthalpy = 1 * 3.56 * 50
Enthalpy = 178 kJ
Therefore, the 3kg of 20% of salt brine at 65 degrees Celsius has more enthalpy.
In conclusion, the enthalpy or heat content of the solutions depends on the mass and temperature change.
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A particle is moving in a circle of diameter 5. calculate the distance covered and the displacement when it completes 3 revolutions.
Total distance covered is 47.1 m whereas displacement is zero.
Calculation:Given,
Diameter, d = 5 m
No. of revolutions = 3
Radius, r = 5/2 = 2.5 m
To find,
Distance =?
Displacement =?
Distance covered in one revolution = 2πr
Put the values in this,
Distance = 2 × 3.14 × 2.5
= 15.7 m
Total distance covered in 3 revolution = 3 × 31.4
= 47.1 m
Displacement is the change in the position of the object or the distance between the initial and final position.
After 3 revolutions the particle comes back to its initial position. Therefore, the displacement is zero.
Hence, the total distance covered in 3 resolutions is 47.1 m whereas displacement is zero.
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A thin hoop with a radius of 10 cm and a mass of 3.0 kg is rotating about its center with an angular speed of 3.5 rad/s. What is its kinetic energy? group of answer choices
The kinetic energy is 1.8 × 10^ -1 J.
Rolling items each rotate and have linear (or translational) movement. consequently, they've both linear and rotational kinetic power. since the rotational kinetic strength of a rolling object depends at the inertia of the item.
The only kinetic energy involved here is rotational kinetic energy.
Kinetic Energy (Rotational) = 1/2Iω²
I = Moment of Inertia of a thin hoop =(Mass)(Radius)2
Mass = 3.0 kg
Radius = 10 cm = 0.10 m
ω = angular speed = 3.5 rad/s
Kinetic Energy (Rotational) = 1/2 * 3 * 12.25 J.
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The Kinetic energy is of thin hoop can be found out using the formulas of Rotational Kinetic Energy. The Kinetic Energy of the hoop is 18.375J.
Rolling items rotate and have linear or translational movement. consequently, they have both linear and rotational kinetic power. Since the rotational kinetic strength of a rolling object depends on the Inertia of the item.
The only kinetic energy involved here is Rotational Kinetic Energy.
Rotational Kinetic Energy = 1/2Iω²
where, I = Moment of Inertia of a thin hoop =(Mass)(Radius)²
where, Mass of hoop, m = 3.0 kg
Radius of loop, R = 10 cm = 0.10 m
Angular speed, w= 3.5 rad/s
Since, Rotational Kinetic Energy = 1/2 × 3 × 12.25 J.
Rotational Kinetic Energy = 18.375J
Hence, Rotational Kinetic Energy is 18.375J
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If a 3. 0 v potential difference causes a 0. 60 a current to flow through a resistor, its resistance is_________.
The resistance is 5 Ω.
Resistance is a degree of the opposition to present day waft in an electrical circuit. Resistance is measured in ohms, symbolized via the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who studied the connection between voltage, modern-day and resistance.
Ohm's regulation states that the voltage or capacity difference among points is without delay proportional to the modern or energy passing through the resistance, and directly proportional to the resistance of the circuit. The system for Ohm's regulation is V=IR.
Potential difference (V) = 3.0 volt
current (I) = 0.60 ampere
V = IR
Resistance (R) = v/I
= 3/0.60
= 5 Ω
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A 35 μfμf capacitor is connected across an ac generator that produces a peak voltage of 8. 0 vv. the peak current is 0. 50 aa. part a what is the oscillation frequency?
The frequency of the oscillation is (f)= 284.21Hz
How do we calculate the frequency of the oscillation?To calculate the frequency we used the formula,
[tex]f=\frac{\omega}{2\pi }[/tex]
Here , we are given,
I= The peak current across an ac generator = 0.50 A.
V= The peak Voltage across an ac generator = 8.0 V.
C= The capacitance of the capacitor = 35 μf.
We have to find the angular frequency of an ac generator [tex]\omega[/tex].
We know, The maximum charge of the generator is,
[tex]Q=CV[/tex]
Or,[tex]Q=(35\times 10^{-6}) \times 8.0[/tex]
Or, [tex]Q=28\times 10^{-5} C[/tex]
So, The maximum charge of the generator is (Q)= [tex]28\times 10^{-5} C[/tex]
Now, for the angular frequency we can write that,
[tex]I=\omega\times Q[/tex]
Or,[tex]\omega=\frac{I}{Q}[/tex]
Now we put the value of [tex]\omega[/tex] in the first equation , we can find that
[tex]f=\frac{\omega}{2\pi }[/tex]
Or,[tex]f=\frac{1}{2\pi } \times \frac{I}{Q}[/tex] [Note: from above[tex]\omega=\frac{I}{Q}[/tex]]
Or,[tex]f=\frac{1}{2\pi } \times \frac{0.50}{28\times 10^{-5} }[/tex]
Or, [tex]f=284.21 Hz[/tex]
Therefore, from the above calculation we can conclude that the frequency of the oscillation is 284.21 Hz.
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The aspect of lighting that refers to the relative intensity of illumination is called________.
A Final statement or concluding statement
The aspect of lighting that refers to the relative intensity of illumination is called Lightning Quality.
What is Luminous intensity?Based on the luminosity function, luminous intensity is a measure of the wavelength-weighted power emitted by a light source in a specific direction per unit solid angle.
Photometry is the science of measuring visible light as it is experienced by human eyes.
The human eye can only sense light in the visible range and is sensitive to different wavelengths of light within that spectrum.
The eye is most sensitive to greenish-yellow light at 555 nm when it is acclimated for bright settings (photopic vision).
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