Answer:
28.57 Mpc
Explanation:
This question is going to be solved by applying Hubble's Law.
This Hubble's Law is actually an observation in physical cosmology. This observation makes it clear that galaxies are moving away from the Earth, and are doing so at speeds proportional to their distance. This essentially means that the farther they are from the Earth, the faster they are moving away from Earth.
It is represented by this formula
v = H(0)D, where
v = speed
H(0) = Constant of proportionality, or otherwise, Hubble's constant.
D = Distance to a galaxy
Applying the given parameters to the formula, we have
v = H(0).D
D = v / H(0)
D = 2000 / 70
D = 28.57 Mpc
Why does the plant produce more pollen need for fertilization?
The pollen is used as to attract bees and other insects to help fertilize the egg.
Many of the pollen produced never reach eggs cells due to environmental factors.
The plant stores the excess pollen for its next reproduction cycle.
There are many animals that would eat pollen from flowers.
Answer: The main reason the pollen and the extension the process of pollination is so that important is because it means the plants don't have to rely on water to transport the biological components necessary for the fertilization. Inside it and they contain the male portion of DNA needed for the plant reproduction.
Explanation:
The force stretching the D string on a certain guitar is 130 N. The string's linear mass density is 0.006 kg/m. What is the speed of the waves on the string?
Answer:
The value is [tex]v = 147.2 \ m/s[/tex]
Explanation:
From the question we are told that
The force is [tex]F = 130 \ N[/tex]
The linear mass density is [tex]\mu = 0.006 \ kg/m[/tex]
Generally the speed of the wave on the string is mathematically represented as
[tex]v = \sqrt{\frac{F}{\mu } }[/tex]
=> [tex]v = \sqrt{\frac{130}{0.006} }[/tex]
=> [tex]v = 147.2 \ m/s[/tex]
A driveway is illuminated at night by identical lamps at the top of two poles 30 ft high and 40 ft apart. Assuming the lamps radiate equally in all directions, compare the illumi- nance at ground level for points directly under one lamp and midway between them.
Answer:
Step 1 of 3
Step 1 of 3Solution:
Step 1 of 3Solution:Height of two poles is 
Step 1 of 3Solution:Height of two poles is Distance between two poles is 
Step 1 of 3Solution:Height of two poles is Distance between two poles is It is given that there are two identical lamps at the top of two poles which radiate equally in all directions. Thus powers of the two lamps are equal then.
Step 1 of 3Solution:Height of two poles is Distance between two poles is It is given that there are two identical lamps at the top of two poles which radiate equally in all directions. Thus powers of the two lamps are equal then.Now illuminance of two lamps at a point at ground level directly below one lamp is
Step 1 of 3Solution:Height of two poles is Distance between two poles is It is given that there are two identical lamps at the top of two poles which radiate equally in all directions. Thus powers of the two lamps are equal then.Now illuminance of two lamps at a point at ground level directly below one lamp is
Step 1 of 3Solution:Height of two poles is Distance between two poles is It is given that there are two identical lamps at the top of two poles which radiate equally in all directions. Thus powers of the two lamps are equal then.Now illuminance of two lamps at a point at ground level directly below one lamp isNow illuminance of two lamps at a point at ground level which is midways between two poles is
Step 1 of 3Solution:Height of two poles is Distance between two poles is It is given that there are two identical lamps at the top of two poles which radiate equally in all directions. Thus powers of the two lamps are equal then.Now illuminance of two lamps at a point at ground level directly below one lamp isNow illuminance of two lamps at a point at ground level which is midways between two poles is
Illuminance is greater at midpoint of the ground compare to points directly under one lamp.
Given that, height of the two pole is = 30 ft.
Distance between the two pole is = 40 ft.
And, the lamps radiate equally in all directions, so illuminance of two light is same. say, it is I.
The light intensity is inversely proportional to the square of the distance.
So, at a point directly under one lamp, total intensity is = I/30² + I/(30²+40²) = 0.001511 I.
And, at a point midway between them, total intensity is = 2×I/(30²+20²) = 0.001538I.
Hence, at midpoint of the ground, illuminance is greater.
Learn more about illumination here:
https://brainly.com/question/15300512
#SPJ5
Give me a copy and pasted bible lol
Answer:
what
Explanation:
The diagram shows an experiment to find the density of a liquid.
cm
50
cm
50
-40
measuring
cylinder
40
30
-30
-20
- 20
-liquid
-10
balance
10
2009
250 g
What is the density of the liquid?
A 0,5g/cm
B 2.0g/cm
C 8.0g/cm
D
10.0g/cm
Answer:
B - sorry if im wrong
Explanation:
Let's say that the red laser has a wavelength of 650 nm, the distance between the two slits is 28000 nm, and the distance between the double slit and the screen is 2.30 m. What is the distance on the screen between the center of the central maximum (m = 0) and the center of one of the fifth-order maxima?
Answer:
The value is [tex]y = 0.267 \ m[/tex]
Explanation:
From the question we are told that
The wavelength is [tex]\lambda = 650 \ nm = 650 *10^{-9} \ m[/tex]
The distance of separation between the two slit is [tex]d = 28000nm = 28000 *10^{-9} \ m[/tex]
The distance between the slit and the screen is [tex]D = 2.30 \ m[/tex]
Generally the path difference is mathematically represented as
[tex]y = \frac{ m * D * \lambda }{d}[/tex]
Here m is the order of the fringe and the value is m = 5
So
[tex]y = \frac{ 5 * 2.30 * 650 *10^{-9} }{ 28000 *10^{-9}}[/tex]
=> [tex]y = 0.267 \ m[/tex]
consider a solid sphere and a solid disk wiht the same radius and the same mass. explain why the solid disk has a greater moment of inertia than the solid sphere g
Answer:
Moment of inertia of the solid sphere:
I
s
=
2
5
M
R
2
.
.
.
.
.
.
.
.
.
.
.
(
1
)
Is=25MR2...........(1)
Here, the mass of the sphere is
M
M
The action force is the balloon pushing the air out. What is the magnitude of the reaction force of the air pushing on the balloon? N.
Answer:
reaction force is 3N
Explanation:
The question is not complete.
From estudyassistant, I've gathered that the action force pushing the air out of the balloon is -3N.
Now,from Newton's third law of motion, it says, for every action, there is an equal and opposite reaction.
Thus, the reaction force will be equal and opposite in direction to the action force.
Thus, reaction force is 3N
Answer:
3n
Explanation:
edge 2021
A runner increases his velocity from 0 m/s to 20 m/s in 2.0 s. what is his average acceleration?
Answer: 10 m/s²
his average acceleration is a (m/s²).
we have:
a = (20 - 0)/2.0 = 10 (m/s²)
Explanation:
What is the weight of a 20 kg object on earth
The weight of a 20 Kg object is 196 Newton.
What is weight?Weight determines how much gravity is pulling on a body. The weight formula is as follows: w = mg
Since weight is a force, it has the same SI unit as a force, which is the Newton (N). When we look at how weight is expressed, we can see that it depends on both mass and the acceleration caused by gravity; while the mass may not change, the acceleration caused by gravity does.
Given parameter:
Mass of the object, m = 20 Kg.
Acceleration due to gravity, g = 9.8 m/[tex]s^2[/tex].
So, Weight of the object, W= mg
= 20 × 9.8 Newton.
= 196 Newton.
Hence, weight of the given body is 196 Newton.
Learn more about weight here:
https://brainly.com/question/23312072
#SPJ2
Does increasing an object’s mass increase its momentum?
Answer:
Explanation:
If you leave the velocity constant, then if the mass is increased, so is the momentum.
Yes providing the velocity remains constant.
Question 1 options:
steam engines to be used on a small enough scale for personal transportation
steam engines to operate using only hot steam
turbines to convert steam energy into kinetic energy
steam to be used to do work
Answer:
Steam engines to operate using only hot steam
Explanation: i took the quiz
A sound wave has a wavelength of 3.0m. The distance from a compression center to the adjacent rarefaction center is:
Answer:
3 m
Explanation:
It is given that,
The wavelength of a sound wave is 3 m.
We need to find the distance from a compression center to the adjacent rarefaction.
We know that, sound is a longitudinal wave. It travels in the form of compression and rarefaction.
Also, the distance between compression center to the adjacent rarefaction centre is called wave. Hence, the required answer is 3 m.
A piece of wood is floating in a bathtub. A second piece of wood sits on top of the first piece, and does not touch the water. If the top piece is taken off and placed in the water, what happens to the water level in the tub?
A. The water level cannot be determined without additional information.B. The water level remains unchanged.C. The water level rises.D. The water level drops.
Answer:
B
Explanation:
Water level remains unchanged
The first thing to realize is that the buoyancy force is the same as, or equal to the weight of the wood, this same force is also the same as or equal to the weight of the water displaced by the wood. In the two cases, the weight of the wood will be unaffected nonetheless, and thus the water level will remain the same.
Therefore, the answer is B, the water level remains unchanged.
All of the objects in the solar system orbit the...
Answer:
All of the objects in the solar system orbit the
Explanation:
sun
A light string is wrapped around a spool (shape is unknown, thus you do not know moment of inertia I) of radius 0.5 m. A 5.0-kg mass is hung from the string, causing the spool to rotate and the string to unwind. The spool rotates from rest to 10 rad/s in 2 s. Find (a) the angular acceleration of spool, (b) moment of inertia I, and (c) the tension on the string.
Answer:
a) angular acceleration α = 5 rad/sec
b) MOI = 1.25 kgm^2
c) Tention in the string T = 12.5 N
Explanation:
The solution to the question has been provided in the attachment, please refer to that.
2. If I drop a watermelon from the top of one of the tower dorms at CSU, and it takes 3.34 seconds to hit the ground, calculate how tall the building is in meters
Answer:
The building is 54.66 m tall
Explanation:
Free Fall
It occurs when an object falls under the sole influence of gravity and do not encounter air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.8 m/s^2[/tex].
The distance traveled by a dropped object at time t is:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
The watermelon is dropped from a tower dorm and takes t=3.34 seconds to hit the ground.
The distance traveled in that time is the height of the building:
[tex]\displaystyle h=\frac{9.8*3.34^2}{2}[/tex]
h = 54.66 m
The building is 54.66 m tall
Calculate the aceleration of a vehicle if the initial velocity (Vi) is 20 m/s and acelerates to 40 m/s (V) in 3,8 s. (t).
Hello!!
For calculate the aceleration of the vehicle let's applicate formula:
[tex]\boxed{V=V_i + a*t}[/tex]
[tex]\textbf{Being:}[/tex]
[tex]\sqrt{}[/tex] V = Final velocity = 40 m/s
[tex]\sqrt{}[/tex] Vi = Initial velocity = 20 m/s
[tex]\sqrt{}[/tex] a = Aceleration = ?
[tex]\sqrt{}[/tex] t = Time = 3,8 su
⇒ [tex]\text{Then let's \textbf{replace it according} we information:}[/tex]
[tex]40 \ m / s = 20 \ m / s + a * 3,8 s[/tex]
⇒ [tex]\text{We clear the "a"}[/tex]
[tex]a = \dfrac{40 \ m /s - 20 \ m / s }{3,8 \ s}[/tex]
⇒ [tex]\text{Let's resolve it: }[/tex]
[tex]a = 5,263 \ m / s[/tex]
[tex]\textbf{Result:}\\\text{The aceleration is of \textbf{5,263 m/s}}^{2}[/tex]
Answer:
Huh? What do u say!
Explanation:
Water of density of 1.0 g/cm^3. What is the mass of 10.0 cm^3 of water?
Hellou n-n
For this applicate the formula:
m = ρV
Replacing according formula:
m = 1 g/cm³ * 10 cm³
Resolving:
m = 10 g
The mass of that water is 10 grams
When an object gives off sound the energy of the air ______ (decreases, increases, or stays the same)
Answer:
Increases.
Explanation:
Hello!
In this case, when objects give off, we can realize that the solid molecules undergo a phase transition to vapor; such is the case of volatile solids such as naphthalene, benzoic acid and those types of organic molecules.
In such way, since the air is now composed by a vapor and the air itself, if such process is able to give off sound as well, we are going to notice the energy of air increases because such waves are able to excite both air and the vapor molecules, even the solid is not given off as a vapor but as sound only.
Best regards!
When you irradiate a metal with light of wavelength 417 nm in an investigation of the photoelectric effect, you discover that a potential difference of 1.15 V is needed to reduce the current to zero. What is the energy of a photon of this light in electron volts
Answer:
E = 4.76 eV
Explanation:
It is given that,
Wavelength = 417 nm
Potential difference = 1.15 V
We need to find the energy of a photon of this light in electron volts. The energy of a photon is given by :
[tex]E=\dfrac{hc}{\lambda}[/tex]
Where
h is Planck's constant, c is speed of light
[tex]E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{417\times 10^{-9}}\\\\=4.76\times 10^{-19}\ J[/tex]
We know that, [tex]1\ eV=1.6\times 10^{-19}\ J[/tex]
or
E = 4.76 eV
So, the energy of a photon is 4.76 eV.
object x and y fall from a same height and object x is heavier than y which object would fall faster qnd y
Answer: They’d fall at the same speed, because air resistance is the only thing that makes an object fall faster than another. There’s a video somewhere on the internet of a bowling ball and a feather falling at the same speed in a vacuum, if you look for it. Hope this helps!
A 105 kg crate initially at rest on a horizontal floor requires a 705 N horizontal force
to set it in motion. Once the crate is in motion, it requires a 595 N horizontal force
to keep it moving at a constant velocity. Find the coefficient of static friction and the
coefficient of kinetic friction between the floor and the crate.
Answer:
μs = 0.68
μk = 0.577
Explanation:
In order to solve this problem, we must remember that the normal force on a body that rests on a horizontal surface is equal to the weight of a body but in the opposite direction.
[tex]W=N\\N=m*g\\N=105*9.81\\N=1030.05[N][/tex]
The friction force is defined as the product of the coefficient of friction by the normal force.
Now when the body is in motion we have that the coefficient of friction is the dynamic one.
595 = μk*N
μk = 595/1030.05
μk = 0.577
Now to start moving it requires a force of 705 [N].
705 = μs*N
μs = 705/1030.05
μs = 0.68
A spring with spring constant 200N/m is compressed by 4cm by applying a force. What is the applied force
Answer:
396 needa bigger clue like a graph
Explanation:
Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m . If the track is completely flat and the race car is traveling at a constant 30.5 m/s (about 68 mph ) around the turn.
Required:
a. What is the race car's centripetal (radial) acceleration?
b. What is the force responsible for the centripetal acceleration in this case?
Complete Question
Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m . If the track is completely flat and the race car is traveling at a constant 30.5 m/s (about 68 mph ) around the turn.
Required:
a. What is the race car's centripetal (radial) acceleration?
b. What is the force responsible for the centripetal acceleration in this case?
O normal
O gravity
O friction
O weight
Answer:
question a
[tex]a = 16.32 \ m/s^2[/tex]
question b
correct option is option 3
Explanation:
From the question we are told that
The radius is [tex]r = 57.0 \ m \[/tex]
The constant speed at which the race car is travelling is [tex]v = 30 .5 \ m/s[/tex]
Generally from the question we are told that the track is completely flat so the only force pulling the car to the middle is the frictional force hence the centripetal force is due to the frictional force
Generally the centripetal acceleration is mathematically represented as
[tex]a = \frac{v^2}{r}[/tex]
=> [tex]a = \frac{30.5^2}{ 57}[/tex]
=> [tex]a = 16.32 \ m/s^2[/tex]
What is the wavelength of a radiowave that has a frequency of 9.650 x10^7 Hz (cycles per second)?h = 6.6261 x10^-34 J/sc = 2.998 x10^8 m/s
Hello!!
For this, we only need frequency and speed, so for calculate we applicate formula:
[tex]\boxed{\lambda = V/f}[/tex]
[tex]\textbf{Being:}[/tex]
[tex]\sqrt{}[/tex] [tex]\lambda = Wavelength = \ ?[/tex]
[tex]\sqrt{}[/tex] [tex]V = Velocity = 2.998*10^{8} \ m/s[/tex]
[tex]\sqrt{}[/tex] [tex]f = Frequency = 9,650*10^{7} \ Hz[/tex]
[tex]\text{Then let's \textbf{replace it according} we information:}[/tex]
[tex]\lambda = 2,998*10^{8} \ m /s / 9,650*10^{7} \ Hz[/tex]
[tex]\lambda = 3.106 \ m[/tex]
[tex]\textbf{Result:}\\\text{The wavelength of the radiowave is \textbf{3.106 meters}}[/tex]
The wavelength of the radiowave with a frequency of 9.650 × 10⁷ and 2.998 × 10⁸ wave speed is 3.10m.
What is Radiowave?Radio waves are the waves which have the longest wavelength in the electromagnetic spectrum. These waves are a type of electromagnetic radiations and these have a frequency which range from as high as 300 GHz to as low as 3 kHz though somewhere it is defined to be above 3 GHz as for the microwaves.
Wavelength of the radiowave can be calculated by the formula:
λ = V/f
where, λ = wavelength of light,
V = wave speed,
f = frequency of light.
λ = (2.998 × 10⁸) / 9.650 × 10⁷
λ = 0.310 × 10
λ = 3.10m
Therefore, the wavelength of the radio waves is 3.10 meters.
Learn more about Radio waves here:
https://brainly.com/question/21995826
#SPJ5
7.33 moles of a diatomic gas are at a temperature of 44.4 C. What is the internal energy of the gas? (Unit = J)
Answer: 4187.7
Explanation:
To estimate the change in internal energy of the gas we need to understand the work done in growth and the amount of heat transfer.
The internal energy of the gas is 4189.6 J.
How to estimate the internal energy of the gas?
To estimate the work done we require the volume change. So we begin with the analysis of volume change. Consider the gas to be ideal.
Change in volume, ∆V= n R( [tex]T_{2} - T_{1}[/tex])/ P
∆V = 7.33 mol [tex]*[/tex] 0.082 L atm [tex]K^{-1}[/tex][tex]mol^{-1 }[/tex] [tex]*[/tex] 27.5 K/ 1 atm
∆V = 16.53 L
Work done in expansion, W = - P [tex]*[/tex] ∆V
= - 1 atm [tex]*[/tex] 16.53 L
= - 16.53 L atm
= -16.53 L atm [tex]*[/tex] (8.314 J/0.082 L atm)
= - 1676 J( 0.082 L atm = 8.314 J)
Heat transfer, [tex]Q = n* Cp*(T_{2} - T_{1} )[/tex]
= 7.33 mol [tex]*[/tex] 3.5 [tex]*[/tex] 8.314 J [tex]K^{-1[/tex] [tex]mol^{-1[/tex] [tex]*[/tex] 27.5 K
= 5865.6J
( Note: Cp = 3.5 [tex]*[/tex] R, the gas exists diatomic)
From the first law of thermodynamics,
∆E = Q + W
= 5865.6J - 1676 J
= 4189.6 J
Therefore, the internal energy of the gas is 4189.6 J.
To learn more first law of thermodynamics about refer to:
https://brainly.com/question/19863474
#SPJ2
A man weighing 980 n on earth
Answer:
91.84kg
Explanation:
A person standing a straight horizontal walkway. the moving walkway is moving with a constant speed of 2m/s due east. Use your forces and force diagrams to solve for the net force
Answer:
net force is 35
Explanation:
If a 500-mL glass beaker is filled to the brim with methanol at a temperature of 5.00ºC, how much will overflow when its temperature reaches 22.0ºC?
(Suppose the coefficient of volume expansion for methanol is 1200x10^(-6) 1/ºCRequired to answer. Single choice.
(1 Point)
Answer:
10.2 mL.
Explanation:
From the question given above, the following data were obtained:
Original Volume (V₁) at temperature θ₁ = 500 mL
Initial temperature (θ₁) = 5 °C
Final temperature (θ₂) = 22 °C
coefficient of volume expansion (γ) = 1200×10¯⁶ / °C
Rise in volume (ΔV) =?
Next, we shall determine the volume (V₂) of the methanol at 22 °C. This can be obtained as follow:
Original Volume (V₁) at temperature θ₁ = 500 mL
Initial temperature (θ₁) = 5 °C
Final temperature (θ₂) = 22 °C
coefficient of volume expansion (γ) = 1200×10¯⁶ / °C
Volume 2 (V₂) at temperature θ₂ =?
γ = V₂ – V₁ / V₁ (θ₂ – θ₁)
1200×10¯⁶ = V₂ – 500 / 500 (22 – 5)
1200×10¯⁶ = V₂ – 500 / 500 × 17
1200×10¯⁶ = V₂ – 500 / 8500
Cross multiply
V₂ – 500 = 1200×10¯⁶ × 8500
V₂ – 500 = 10.2
Collect like terms
V₂ = 10.2 + 500
V₂ = 510.2 mL
Thus, the volume of the methanol at 22 °C is 510.2 mL
Finally, we shall determine the rise in volume of methanol as illustrated below:
Original Volume (V₁) at temperature θ₁ = 500 mL
Volume (V₂) at temperature θ₂ = 510.2 mL
Rise in volume (ΔV) =?
ΔV = V₂ – V₁
ΔV = 510.2 – 500
ΔV = 10.2 mL
Thus, 10.2 mL of the methanol will overflow when the temperature reaches 22 °C.
