We will have the following:
We know by the laws of reflection that the reflection will be equal to the angle of incidence. Thus, the reflected ray will be 27° from the normal.
Two different objects are moving with different velocities until they strike each other, stick to each other, and begin moving together. If each object’s mass is known and each object’s initial velocity is known, then the final velocity can be predicted using the law of conservation of
Energy
Momentum
Force
Speed
A person starts at a point on a square which has a side of 1.5 metres in the clockwise direction and reaches the same point after time of 4 s . The value of distance is
To find the distance traveled, we just have to add all the side lengths of the square, in other words, the perimeter.
[tex]\begin{gathered} P=1.5m+1.5m+1.5m+1.5m \\ P=6m \end{gathered}[/tex]Therefore, the value of the distance is 6 meters.Two cars have a ‘rear end’ collision. A 120 kg Honda moving at 20 m/s strikes a 100 kg Ford moving at 15 m/s. Their bumpers become locked and they continue to move as one mass. What is their final velocity?
Given
Mass of the Honda car, m=120 kg
Velocity of the Honda car, v=20 m/s
Mass of the Ford, m'=100 kg
Velocity of the Ford , v'=15 m/s
To find
The final velocity.
Explanation
The combined velocity is V
By conservation of momentum,
[tex]\begin{gathered} mv+m^{\prime}v^{\prime}=(m+m^{\prime})V \\ \Rightarrow120\times20+100\times15=(120+100)V \\ \Rightarrow V=17.72\text{ m/s} \end{gathered}[/tex]Conclusion
The combined velocity is 17.72 m/s
The gravitational force between two masses is 36 N. What is the gravitational force if the distance between them is tripled? (G = 6.673 x10 (Power of-11)
If the distance between them is tripled, the gravitational force is F2= 36/9=4N. The force of attraction between any two bodies is proportional to the product of their masses and inversely proportional to the square of their distance.
WHAT IS GRAVITATIONAL FORCE?
It is the force that connects all masses in the universe, particularly the pull of the earth's mass on objects near its surface. It follows the inverse square law. The force of attraction exerted on a body by the earth is known as gravitational force. For example, the leaves and fruits of a tree fall to the ground, water in a river flows down streams, and a ball thrown up travels to a height before returning to the ground are all examples of motion caused by gravitational force.The formula for Gravitational force:
F=G m1*m2/r² ,
G: gravitational constant = 6.67x10⁻¹¹ N*m²/kg²
m1: is the mass of the first object
m2: is the mass of the second object
r: is the distance between the center of the masses of the objects
F∝1/r²
so F1/F2=( r2/r1)².......(1)
Given F1= 36N F2=?
let r1=r, r2= 3r
putting all this value in equation (1)
36/F2= (3r/r)²
⇒F2= 36/9=4N
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A racing car on a flat track travels at 45.0 m/s around a curve with a 55.0 m radius. Find the car’s centripetal acceleration?
Given,
The velocity of the car, v=45.0 m/s
The radius of the circular path, r=55.0 m
The centripetal force is the force directed towards the center that is acting on an object in a circular motion. This is the force that keeps the object in its circular path.
The centripetal acceleration is given by,
[tex]a=\frac{v^2}{r}[/tex]On substituting the known values,
[tex]\begin{gathered} a=\frac{45.0^2}{55.0} \\ =36.82\text{ m/s}^2 \end{gathered}[/tex]Thus, the centripetal acceleration of the car is 36.82 m/s².
The meter bridge shown in the figure is balanced when the slide wire is divided as shown in the figure. Find the value of the resistance X
A 20.0 N block slides over a horizontal table. If it takes 5.0 N to move the block at constant velocity, what is the coefficient of friction?
A. 0.50
B. 4.0
C. 0.10
D. 0.25
A 20.0 N block slides over a horizontal table. If it takes 5.0 N to move the block at a constant velocity, the coefficient of friction is D. 0.25.
Given,
Frictional force (F) is 5.0 N
Normal force (N) is 20.0 N
The coefficient of friction (µ), a numerical value, is obtained by dividing the resistive force of friction (F) by the normal or perpendicular force (N) pushing the objects together.
i.e., µ = F/N
Calculating the coefficient of friction :
The frictional force is equal to and opposing the applied force since the box is traveling at a constant speed.
µ = F / N
µ = 5.0 N / 20.0 N
µ = 1/4 N
µ = 0.25 N
Thus, the coefficient of friction is D. 0.25.
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Wes places red blood cells in a petri dish with pure water and observes them
under a microscope. He drew a model to illustrate his observations.
What is the most likely explanation for Wes's observations?
a. The red blood cells were placed into an isotonic solution. Water moved into
and out of the cells to maintain homeostasis.
b. The red blood cells were placed into an isotonic solution. Water moved into
the cells until the cells burst.
c. The red blood cells were placed in a hypertonic solution. Water moved from
the inside of the cells to the outside of the cells to maintain homeostasis.
d. The red blood cells were placed in a hypotonic solution. Water moved from
the outside of the cells to the inside of the cells until the cells burst.
What space telescope is used to look deep into the universe?
O A.
OB.
O C.
Hubble
Galileo
Penzias
OD. Edwin
Find the currents through the 8 Ω resistor at the instant that the switch is closed.0.545 A0.744 A0.641 A0.926 A
From the figure,
The resistors are in series
Thus the equiva;ent resistance is:
R=14+8=22 ohm
Thus the current through the equivalent resistance is:
[tex]i=\frac{V}{R}=\frac{12^{}}{22}=0.545\text{ A}[/tex]The answer is 0.545 A
The velocity-time table represents the motion of a leftward moving car.
What is the magnitude and direction of the acceleration?
Given velocity-time table represents the motion of a leftward moving car.
Magnitude of acceleration = -4 m/s^2
Direction is Left.
When any object is slowing down then the acceleration is in opposite direction. Then the object will have a negative acceleration.
Deceleration is the opposite of acceleration. The deceleration is calculated by dividing the difference final and initial velocity by the amount of time taken for the drop in velocity. The formula for acceleration with a negative sign is used to identify the deceleration value.
Deceleration = (Final Velocity–Initial Velocity)/Time taken
It is written' –a,' where a is acceleration.
When initial velocity, final velocity and time are given, then Deceleration Formula is given by,
Given in the graph, u= 20m/s and v= 4m/s
t= 4sec
a = (v−u)/t
= (4 -20)/ 4
=- 16/4
a= -4 m/s^2
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Kelley is playing pool and hits the cue into the nine ball, which is directly in the center of the pool table. The nine ball travels a total of 7 meters before stopping, 1 meter to the left of the initial starting point of the nine ball. Which sentence reflects the correct statement regarding distance and displacement when considering the motion of the nine ball?(1 point)
I NEED THE ANSWER NOW. . .I really don't understand displacement
The displacement of the nine balls is 1 m while the distance travelled by the nine balls is 7 m.
What is the displacement of he ball?The displacement of the ball is the change in the position of the ball. Displacement describes the shortest distance between the initial and final position of an object.
Mathematically, the displacement of the nine balls is given as;
Δx = xf - xi
where;
xf is the final position of the objectxi is the initial position of the objectIf the balls travels 1 meter to the left of the initial starting point, then the displacement of the balls is 1 m. The 1 meter is the shift from the initial position.
The distance of the balls is the total path covered by the balls.
distance = 7 m
Thus, the displacement of the nine balls is the change in the position of the balls while the distance of the nine balls is the total path covered.
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Identify the time interval during which the velocity of shuttle bus is zero.
Explanation:
during D and E, so between 13 and 16 (whatever time unit this is - hours, minutes, ... ?).
Answer:
Explanation:
The time interval 13 to 16 seconds
Which of the following is NOT an example of a projectile.
O A tennis ball after it is struck by a tennis racket.
O A rocket that is launched from Earth's surface.
OA snowball rolling downhill.
O A football kicked to the goal post.
Snowball rolling downhill is not an example of a projectile.
What is projectile?
A projectile is any object is thrown into space upon the which the only acting force on is gravity. The primary force of the acting on a projectile is the gravity. This doesn't have necessarily mean that other just forces do not act on it, just that their effect is minimal the compared to gravity.
A projectile is any object that once projected or dropped with the continues in motion by its only own inertia and is influenced by only by the downward force of of gravity. By definition, in a projectile has a single force of that acts upon it - the force of gravity.
Thus this is the reason why snowball rolling downhill is not an example of projectile.
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A cube with an edge of length l = 4 cm is placed in a uniform magnetic field throughout the region that has components Bx = 0 T, By = 4 T and Bz = 3 T. Find the net flux through the cube.Group of answer choices0 Tm20.00640 Tm20.00480 Tm20.120 Tm20.160 Tm2
Given,
Length of the edge, l=4 cm.
The magnetic field components:
[tex]\begin{gathered} B_x=0T \\ B_y=4T \\ B_z=3T \end{gathered}[/tex]To find
The net flux through the cube.
Explanation
Through any closed surface the total magnetic flux is always zero.
Thus the net flux through the cube is zero
Conclusion
The answer is
[tex]0Tm^2[/tex]Newton's 2nd law states that, the acceleration of an object as ______________ is _________________to the magnitude of the __________, in the same ______________ as the net force, and _______________ to the ____________________ of the object.
Answer:
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
Dylan and Sophia are walking along Bluebird Lake on a perfectly calm day. Dylan, determined to impress Sophia by his ability to skip rocks, picks up the flattest rock he can find and gives it a sidearm launch from the edge of the water. The rock acquires a completely horizontal speed of 27.2 m/s from a height of 0.54 meters above the water surface. How far does it go horizontally before it hits the water?
Question 17 options:
0.3 meters
9.1 meters
0.1 meters
14.7 meters
The horizontal distance travelled by the rock before it hits the water is 9.0 m.
What is the time of motion of the rock?The time of motion of the rock is the time taken for the rock to fall from the given height.
h = vt + ¹/₂gt²
where;
h is the height of fallv is the vertical velocity = 0t is the time of motionh = ¹/₂gt²
t = √(2h/g)
t = √(2 x 0.54 / 9.8)
t = 0.33 s
The horizontal distance travelled by the rock before it hits the water is calculated as follows;
X = vt
where;
v is horizontal velocityt is time of motionX = 27.2 m/s x 0.33 s
X = 9.0 m
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Exactly 3.3 s after a projectile is fired into the air from the ground, it is observed to have a velocity v⃗ = (8.6 i^ + 4.7 j^)m/s, where the x axis is horizontal and the y axis is positive upward. aDetermine the horizontal range of the projectile.bDetermine its maximum height above the ground.cDetermine the speed of motion just before the projectile strikes the ground.dDetermine the angle of motion just before the projectile strikes the ground.= ∘ below the horizontal
a. Horizontal range is given by,
[tex]Range=\frac{u^2sin2\theta}{g}[/tex]where u is the initial speed, and theta is the angle of projection,
Now velocity vector as a function of time is given by,
[tex]\vec{v}(t)=(ucos\theta)\hat{i}+(usin\theta-gt)\hat{j}[/tex]Given,
[tex]\begin{gathered} \vec{v}(3.3s)=8.6\text{ }\hat{i}+4.7\text{ }\hat{j} \\ \Rightarrow ucos\theta=8.6,usin\theta-(10)(3.3)=4.7 \\ \Rightarrow ucos\theta=8.6,usin\theta=37.7 \\ Dividing, \\ \Rightarrow tan\theta=\frac{37.7}{8.6}=4.3837 \\ \Rightarrow\theta=77.15\degree \\ Hence \\ ucos77.15\degree=8.6 \\ \Rightarrow u=\frac{8.6}{0.2224}=38.67\text{ m/s} \end{gathered}[/tex]And so, the horizontal range will be,
[tex]Range=\frac{(38.67)^2sin(154.3\degree)}{(10)}=64.85\text{ m}[/tex]b. Maximum height reached by a projectile is given by,
[tex]\begin{gathered} H_{max}=\frac{u^2sin^2\theta}{2g} \\ \Rightarrow H_{max}=\frac{(38.67)^2sin^2(77.15\degree)}{(2)(10)}=71.07\text{ m} \end{gathered}[/tex]c. Now time of flight of the projectile is given by,
[tex]t_{flight}=\frac{2usin\theta}{g}=\frac{(2)(38.67)sin(77.15\degree)}{(10)}=7.54\text{ s}[/tex]this is the time at which the projectile strikes the ground, and so its velocity then would be,
[tex]\begin{gathered} \vec{v}(7.54s)=8.6\text{ }\hat{i}+(37.7-10\times7.54)\hat{j} \\ \Rightarrow\vec{v}(7.54s)=8.6\text{ }\hat{i}-37.7\text{ }\hat{j} \end{gathered}[/tex]As expected the vertical component of velocity has just been flipped, and therefore its speed will be same as its initial speed i.e.
[tex]v_{strikes\text{ }ground}=u=38.67\text{ m/s}[/tex]d. Below the horizontal, let the angle be φ, then
[tex]tan\varphi=-\frac{v_y}{v_x}[/tex]extra -ve sign since its below the horizontal, when the projectile strikes the ground,
[tex]\begin{gathered} v_y=-37.7\text{ m/s} \\ v_x=8.6\text{ m/s} \\ \Rightarrow tan\varphi=-\frac{(-37.7)}{8.6}=\frac{37.7}{8.6}=tan\theta \\ \Rightarrow\varphi=\theta \\ \Rightarrow\varphi=77.15\degree \end{gathered}[/tex]Result: a. 64.85 m, b. 71.05 m, c. 38.67 m/s, d. 77.15°.Find the answer to the problem
In the given diagram,
The first force applied = F1 = 10N
The second force applied = F2 = 6 N
The net force exerted on the box = F = F1 + F2 = 10 + 6 = 16 N
The mass of the box = 10.6 Kg
As per the Newtons second law of motion,
Force = Mass x Acceleration
⇒ Acceleration = Force/Mass
⇒ Acceleration = 16/10.6
⇒ Acceleration = 1.50 m/s^2
Hence the acceleration of the box is 1.5 m/s^2
What is Acceleration?In layman's terms, acceleration is the ability of a vehicle to increase its speed. The rate of change in an object's velocity with respect to time is known as acceleration in mechanics. In vector quantities, accelerations exist (in that they have magnitude and direction). The direction of the net force that is acting on an object determines its acceleration. According to Newton's Second Law, the amount of an item's acceleration results from the interaction of two factors: the mass of the object, which varies depending on the materials from which it is built, and the net balance of all exterior forces acting on the object.To learn more about Acceleration, refer to:
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A 3.5-inch floppy disk in an old computer rotates with a period of 2.00 x 10^-1 s. Calculate the angular speed of the disk, the linear speed (in inches/sec) of a point on the rim of the disk, and the linear speed (in inches/sec) of a point 0.750 inches from the center of the disk. (Hint: a 3.5 inch floppy disk has a 3.50 inch diameter)
We have the next information
T=2.00 x 10^-1 s=0.2s
r=3.5 inch
For the angular speed
[tex]\omega=\frac{2\pi}{T}[/tex]where omega is the angular speed, T is the period
We substitute
[tex]\omega=\frac{2\pi}{0.2}=31.41\text{ rad/s}[/tex]For the linear speed on the rim of the disc, we will use the next formula
[tex]v=\omega\cdot r[/tex]in this case r= 3.5/2=1.75 inch
[tex]v=31.41(1.75)=54.97\text{ }\frac{inches}{\text{sec}}[/tex]Then for the linear speed on the point at 0.750 inches from the center of the disk.
[tex]v=31.41(0.750)=23.56\frac{inches}{\text{sec}}[/tex]ANSWER
ω=31.41 rad/sec
v on the rim= 54.97 inches/sec
v on the point=23.56 inches/sec
A woman pushes a wheelchair up an inclined plane. The effort force is...Select one:a. the weight of the woman. b. the height of the inclined plane. c. the weight of the wheelchair. d. the force applied by the woman.
When a women pushes the wheelchair up an inclined plane, the effort force will be the force applied by the woman.
Thus, the correct option is (d)
A 131 kg electric motorcycle moving at 30 mph accelerates by 0.03 m/s^2 for 60 s in the same direction that it’s moving. What is the average velocity during this period? Answer in km/hr.
We would calculate the distance travelled by the motor by applying one of Newton's formula for calculating motion which is expressed as
s = ut + 1/2at^2
where
s is the distance travelled
u is the initial velocity
t is the time
a is the acceleration
From the information given,
u = 30 mph
We would convert it to m/s
Recall,
1 mile = 1609.344 m
1 hour = 3600 s
Thus,
30mph = (30 x 1609.344)/3600
u = 13.4112 m/s
t = 60 s
a = 0.03m/s^2
Thus,
s = 13.4112 x 60 + 1/2 x 0.03 x 60^2
s = 804.672 + 54
s = 858.672 m
We would convert 858.672 m to km and 60s to hours. It becomes
858.672 m = 858.672/1000 = 0.858672 km
60s = 60/3600 = 1/60 hr
Average velocity = 0.858672 km/(1/60 hr)
Average velocity = 51.5 km/hr
A 2.5 kg ball moving at 4.2m/s collided with a 2.5 kg stationary ball. If the first ball is at rest after the collision what is the velocity of the second ball
We need to apply the conservation of momentum formula
[tex]m1u1+m2u2=m1v1+m2v2[/tex]Where m1 and m2 are the masses, u1 and u2 are the initial velocities of each mass, and v1 and v2 are the final velocities of each mass
we have
m1= 2.5 kg
u1= 4.2 m/s
m2=2.5 kg
u2= 0 m/s
v1=0 m/s
v2=?
we substitute
[tex]2.5(4.2)+2.5(0)=2.5(0_{})+2.5(v_2)[/tex]therefore
[tex]v2=4.2\text{ m/s}[/tex]ANSWER
v2=4.2 m/s
What is the first step in scientific method?
A) Gather information
B) state the problem
C) form a hypothesis
D) perform the experiment
The first step in scientific method is to state the problem. That is option B.
What are scientific methods?The scientific methods are those methods that are used by scientists and researchers to discover answers to specific questions that are being asked and it involves the use of scientific steps and guidelines.
These steps include the following:
State the problem: This is the first step where the problem to be investigated is being defined.Form a hypothesis: This is the step that involves the making of predictions based on the research.Gather information: The data that is related to the problem are being collected.Perform the experiment: Analysis are being carried out on the collected data.Learn more about scientific methods here:
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Which is the best statement of the Law of Conservation of Energy? (1 point)
The amount of energy put out by a simple machine is always less than the amount of energy put into the machine
The amount of energy put into a simple machine should be conserved Item
The amount of energy put out by a simple machine depends on its efficiency
The amount of energy put out by a simple machine must equal the amount of energy put into the machine
The best statement of the Law of Conservation of Energy is option D. The amount of energy put out by a simple machine must equal the amount of energy put into the machine.
The regulation of conservation of energy states that the entire electricity of an isolated system remains steady; it's far stated to be conserved over time.
The law of conservation of power is a physical law that states strength cannot be created or destroyed but can be modified from one form to some other. any other manner of pointing out this regulation of chemistry is to mention the full electricity of a remoted device stays regular or is conserved within a given body of reference.
The law of conservation of energy states that power can neither be created nor destroyed - best converted from one form of energy to some other. this means that a device constantly has an equal quantity of power unless it is added from the out of doors.
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Look at the diagram below.
Encoding technique - Decoding technique
"Written language
Pictures
Billboards
Advertisements
E-mails
Reading
Viewing
Interpreting
The communication process, which involves understanding parts and meanings, consists of eight key elements: Source Message Channel Receiver Feedback Environment Context, and Interference
Common examples of character encoding systems are Morse Code, Bodo Code, American Standard Code ASCII for Information Interchange, and Unicode. The purpose of encoding is to transform data so that it can be properly and safely processed by another type of binary system data transmitted via e-mail or special characters that appear on web pages.
The goal is not to keep information secret, but to make it available for proper consumption. Coding is the process of transforming data into the formats required for various information processing needs, such as compiling and running programs. Coding uses different patterns of voltage or current levels to represent the 1s and 0s of a digital signal on a transmission line. Common types of line coding are unipolar, polar, bipolar, and Manchester.
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The inside of the Earth is hot due to heat left over from when the Earth formed and due to heat generated by the radioactive decay of elements in the Earth's mantle and crust. Heat from these sources flows to the surface at a total rate of of 47 terrawatts. If the Earth were instantly teleported into deep space so that absorption of any outside radiation stopped, what would the equilibrium surface temperature of the Earth be, using e=0.6 for the emissivity, and R = 6400km for the radius? Write the temperature in Kelvin, just the number without units.
The temperature at the earth's surface would be
40.48K
This is further explained below.
What is Stefan Boltzmann's law:?Generally, In accordance with the Stefan-Boltzmann equation, the total radiant heat output that is radiated from a surface is proportional to the fourth power of that surface's absolute temperature.
According to the Stefan-Boltzmann law, the total energy radiated per unit surface area of a black body across all wavelengths per unit of time is directly proportional to the fourth power of the black body's thermodynamic temperature T: j=.
To be more specific, the Stefan-Boltzmann law states that the total energy radiated per unit surface area of a black body across all wavelengths per unit of time is directly proportional to the black
[tex]P=\sigma e AT^4[/tex]
Where P stands for power, e stands for emissivity, A stands for the surface area of the earth, and T stands for the temperature at the surface.
[tex]&P=47 * 10^{12} W, \sigma \\\\=5.67 * 10^{-8} W / m^2 . K^4, e ,[/tex]
=0.6
[tex]\\\\&A=4 \pi R^2 \\\\=4 \pi *\left(6400 * 10^3\right)^2 \\\\[/tex]
=5.147 * 10^{14}m^2
[tex]T=\left(\frac{P}{\sigma e A}\right)^{1 / 4} \\\\=\left(\frac{47 * 10^{12}}{5.67 * 10^{-8} * 0.6 * 5.147 * 10^{14}}\right)^{1 / 4}[/tex]
=40.48K
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Conversion of PE into KE
1. A ball is thrown up with a velocity of 10 m/s. How high will it go? (Solve the problem
without using the equation v2=v0−2gΔy. This equation is true, but here we are trying
use PE and KE). Never mind that you are not told the mass of the ball – it will cancel
out.)
If a ball is thrown up with a velocity of 10 meters per second then it will go up to a height of 5.10 meters.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.
As given in the problem if a ball is thrown up with a velocity of 10 meters per second,
The kinetic energy of the ball is getting converted into the potential energy
mg×h = 1/2×m×v²
v² = (2×g×h)
10² = 2×9.8×h
h = 100 / 19.6
h = 5.10 meters
Thus, If a ball is thrown up with a velocity of 10 meters per second then it will go up to a height of 5.10 meters.
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List three ways that you can use water in each of its states.
A soccer ball kicked with a force of 13.5 N accelerates at 6.5 m/s^2. What is the mass of the ball?
ANSWER:
2.08 kg
STEP-BY-STEP EXPLANATION:
The force is given by the multiplication of the mass and the acceleration, like this:
[tex]\begin{gathered} f=m\cdot a \\ f=13.5\text{ N} \\ a=6.5\frac{m}{s^2} \end{gathered}[/tex]We replace and calculate for m:
[tex]\begin{gathered} 13.5=m\cdot6.5 \\ m=\frac{13.5}{6.5} \\ m=2.08\text{ kg} \end{gathered}[/tex]The mass is 2.08 kg
