If an event has a 55% chance of happening in one trial, how do I determine the chances of it happening more than once in 4 trials?

Answers

Answer 1

The chances of it happening more than once in 4 trials is 13%

How to determine the number

From the information given, we have can deduce that;

Probability of 1 trial = 55%

= 55/ 100

Find the ratio

= 0. 55

We are to find the probability of it happening more than once in 4 different trials

If the probability of it happening in one trial is 555 which equals 0. 55

Then the probability of it happening in 1 in 4 trials is given as;

P(1/4 trials) = 1/ 4 × 55%

P(1/4 trials) = 1/ 4 × 0. 55

Put in decimal form

P(1/4 trials) = 0. 25 × 0. 55

P(1/4 trials) = 0. 138

But we have to know the percentage

= 0. 138 × 100

Multiply the values, we have

= 13. 8 %

Thus, the chances of it happening more than once in 4 trials is 13%

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Related Questions

There are 12 different cookies on a plate. Aiden will choose 3 of these cookies to pack in his lunch. How many different groups of cookies can he choose from 12?
A) 220
B) 320
C) 420
D) 440
I know the correct answer is A) 220, but I am not sure why?

Answers

The number of different groups of cookies he can choose from the 12 cookies is 220

How to determine the number of different groups of cookies he can choose from the 12 cookies?

The given parameters are:

Number of cookies, n = 12

Selected cookies, r = 3

The number of different groups of cookies he can choose from the 12 cookies is calculated as:

Numbers = 12C3

The combination formula is represented as:

nCr = n!/(n - r)!r!

Substitute the known values in the above equation

Numbers = 12!/(12 - 3)!3!

Evaluate the difference in the above equation

Numbers = 12!/9!3!

Expand the above equation

Numbers = 12*11*10*9!/9!3!

Evaluate the quotient

Numbers = 12*11*10/3!

Expand the above equation

Numbers = 12*11*10/3*2*1

Evaluate the products

Numbers = 1320/6

Evaluate the quotients

Numbers = 220

Hence, the number of different groups of cookies he can choose from the 12 cookies is 220

So, the complete parameters are:

Number of cookies, n = 12

Selected cookies, r = 3

Number of selection = 220

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61% of owned dogs in the United States are spayed or neutered. Round your answers to four decimal places. If 46 owned dogs are randomly selected, find the probability that

a. Exactly 29 of them are spayed or neutered.

b. At most 29 of them are spayed or neutered.

c. At least 28 of them are spayed or neutered.

d. Between 28 and 32 (including 28 and 32) of them are spayed or neutered.

A good calculator is found at: Stattrek Binomial Calculator Round answers to at least 4 decimal places.

Answers

Using the binomial distribution, the probability that:

(a) Exactly 29 of them are spayed or neutered, that is, P(X = 29) = 0.1163.

(b)  At most 29 of them are spayed or neutered, that is, P(X ≤ 29) = 0.6648.

(c)  At least 28 of them are spayed or neutered, that is, P(X ≥ 28) = 0.5714.

(d) Between 28 and 32 (including 28 and 32) of them are spayed or neutered, that is, P(28 ≤ X ≤ 32) = 0.48345.

A binomial distribution, with a success rate of p on each trial, gives us the probability of x number of success in n number of trials, using the formula:

P(X = x) nCx.pˣ.qⁿ⁻ˣ, where q = 1 - p.

In the question, we are informed that 61% of owned dogs in the United States are spayed or neutered, and are given that 46 owned dogs are randomly selected.

This can be seen as a binomial probability distribution, with n = 46, and p = 61% = 0.61, q = 1 - p = 1 - 0.61 = 0.39.

(a) We are asked for the probability of exactly 29 of them being spayed or neutered.

Thus, x = 29, and we need to find P(X = 29).

Using the given calculator, P(X = 29) = 0.1163.

(b) We are asked for the probability of at most 29 of them being spayed or neutered.

Thus, we need to find P(X ≤ 29).

Using the given calculator, P(X ≤ 29) = 0.6648.

(c) We are asked for the probability of at least 28 of them being spayed or neutered.

Thus, we need to find P(X ≥ 28).

Using the given calculator, P(X ≥ 28) = 0.5714.

(d) We are asked for the probability between 28 and 32 of them are spayed or neutered.

Thus, we need to find P(28 ≤ X ≤ 32), which can be shown as;

P(28 ≤ X ≤ 32) = P(X ≤ 32) - P(X < 28).

Using the given calculator, P(X ≤ 32) = 0.91209.

Using the given calculator, P(X < 28) = 0.42864.

Thus, P(28 ≤ X ≤ 32) = P(X ≤ 32) - P(X < 28) = 0.91209 - 0.42864 = 0.48345.

Thus, using the binomial distribution, the probability that:

(a) Exactly 29 of them are spayed or neutered, that is, P(X = 29) = 0.1163.

(b)  At most 29 of them are spayed or neutered, that is, P(X ≤ 29) = 0.6648.

(c)  At least 28 of them are spayed or neutered, that is, P(X ≥ 28) = 0.5714.

(d) Between 28 and 32 (including 28 and 32) of them are spayed or neutered, that is, P(28 ≤ X ≤ 32) = 0.48345.

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Question Content Area
Service Department Charges and Activity Bases

Middler Corporation, a manufacturer of electronics and communications systems, uses a service department charge system to charge profit centers with Computing and Communications Services (CCS) service department costs. The following table identifies an abbreviated list of service categories and activity bases used by the CCS department. The table also includes some assumed cost and activity base quantity information for each service for October.

CCS Service
Category
Activity Base
Budgeted Cost Budgeted Activity
Base Quantity
Help desk Number of calls $160,000 3,200
Network center Number of devices monitored 735,000 9,800
Electronic mail Number of user accounts 100,000 10,000
Smartphone support Number of smartphones issued 124,600 8,900
One of the profit centers for Middler Corporation is the Communication Systems (COMM) sector. Assume the following information for the COMM sector:

• The sector has 5,200 employees, of whom 25% are office employees.

• All the office employees have been issued a smartphone, and 96% of them have a computer on the network.

• One hundred percent of the employees with a computer also have an e-mail account.

• The average number of help desk calls for October was 1.5 calls per individual with a computer.

• There are 600 additional printers, servers, and peripherals on the network beyond the personal computers.

a. Determine the service charge rate for the four CCS service categories for October.

CCS Service Category Service Charge Rate
Help desk $fill in the blank 1

Per call
Network center $fill in the blank 3

Per device monitored
Electronic mail $fill in the blank 5

Per user or e-mail account
Smartphone support $fill in the blank 7

Per smartphone issued
b. Determine the charges to the COMM sector for the four CCS service categories for October.

October charges to the COMM sector
Help desk charge $fill in the blank 9
Network center charge $fill in the blank 10
Electronic mail charge $fill in the blank 11
Smartphone support charge $fill in the blank 12
Feedback Area
Feedback
a. Divide the budgeted cost by the budgeted activity base quantity for each category.

b. Determine the Help desk charge by multiplying the rate from (a) by the number of employees times the percentage of office employees times the percentage with a computer times the number of calls. Follow a similar process for each of the other three categories.

Learning Objective 3.

Answers

The service charge rate are: Help desks $50 per call, Network center $75 per device monitored, Electronic mail $10 per user or per e-mail account, Local voice support $14 per phone extension.

Service charge rate

a. Service charge rate

Service charge rate=Budgeted cost/ Budgeted activity base quantity

Help desks:

Service charge rate=$160,000/3,200 calls

Service charge rate=$50 per call

Network center:

Service charge rate=$735,000/9,800 devices

Service charge rate=$75 per device monitored

Electronic mail:

Service charge rate=$100,000/10,000 accounts

Service charge rate=$10 per user or per e-mail account

Local voice support:

Service charge rate=$124,600/8,900 phone extensions

Service charge rate=$14 per phone extension

b.  Help desk charge

Help desk charge =(Number of employees times × Percentage of office employees× Percentage with a computer ×Number of calls)× Service charge rate

Help desk charge:

(5,200 employee×25%×96%×1.5)× $50 per call

=$93,600

Network center charge:

[(5,200 employee×25%×96%)+ 600]× $75 per device

=$138,600

Electronic mail:

(5,200 employee×25%×96%×100)×$10 per user or per e-mail account

=$12,480

Local voice support:

(5,200 employee×25%)× $14 per phone extension

=$18,200

Therefore the service charge rate are: Help desks $50 per call, Network center $75 per device monitored, Electronic mail $10 per user or per e-mail account, Local voice support $14 per phone extension.

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Factor x² - 4x + 5.
Prime
O(x + 5)(x - 1)
O(x - 5)(x - 1)
(x+5)(x + 1)

Answers

Answer:

(x-5)(x+1)

Step-by-step explanation:

x² - 4x + 5 = (x-5)(x+1)

Sierra buys lunch in the cafeteria everyday. Lunch costs $2.00 each day, how much did she spend after 5 days.

Answers

Answer:

$2.00 each day so $2.00 x 5 = $10

The graph below shows the value of Edna's profits f(t), in dollars, after t months: graph of quadratic function f of t having x intercepts at 6, 0 and 18, 0, vertex at 12, negative 36, and passes through point 21, 41.25 What is the closest approximate average rate of change for Edna's profits from the 18th month to the 21st month?

Answers

The closest approximate average rate of change for Edna's profits from the 18th month to the 21st month is 14

How to determine the average rate of change?

From the question, we have the following ordered pairs

x intercepts = (6,0) and (18, 0)

Vertex = (12, -36)

Points (21, 41.25)

The closest approximate average rate of change for Edna's profits from the 18th month to the 21st month is the calculated using

m = [f(21) - f(18)]/[21 - 18]

This becomes

m = [f(21) - f(18)]/3

Substitute the known values in the above equation

m = [41.25 - 0]/3

Evaluate the difference

m = 41.25/3

Evaluate the quotient

m = 13.75

Approximate

m=14

Hence, the closest approximate average rate of change for Edna's profits from the 18th month to the 21st month is 14

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Complete question

The graph below shows the value of Edna's profits f(t), in dollars, after t months:

What is the closest approximate average rate of change for Edna's profits from the 18th month to the 21st month?

See attachment for graph

what is the measure of angle B from the right triangle below ?

Answers

Answer:

d

Step-by-step explanation:

using the cosine ratio in the right triangle

cos B = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{2}{10}[/tex] , then

B = [tex]cos^{-1}[/tex] ( [tex]\frac{2}{10}[/tex] ) ≈ 78.46° ( to 2 dec. places )

Someone please help with this question asap!

Answers

Answer:

Side b is the longest because the longer side always lie opposite the bigger angle. Angle B is the biggest angle, and since side b is opposite angle B, side b is the longest.

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

The side opposite to the largest angle is the longest side of a triangle.

[tex] \qquad \large \sf {Conclusion} : [/tex]

hence, we can conclude that the longest side is b

( since it's opposite angle is the largest, i.e 91° )

30 points!
based off of the chart,

- what is the probability of mint chocolate chip or female
- what is the probability of cookie and cream and vanilla

Answers

Using the probability concept, we have that:

There is a 0.6286 = 62.86% probability that a randomly selected person is female or prefers mint chocolate chip.There is a 0.3714 = 37.14% probability that a randomly selected person prefers cookie and cream or vanilla.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, there are 35 people, out of which 17 are female and 5 are male that prefer mint chocolate chip, hence:

p = (17 + 5)/35 = 22/35 = 0.6286.

There is a 0.6286 = 62.86% probability that a randomly selected person is female or prefers mint chocolate chip.

Out of the same 35 people, 11 people prefer cookie and cream and 2 people prefer vanilla, hence:

p = (11 + 2)/35 = 13/35 = 0.3714

There is a 0.3714 = 37.14% probability that a randomly selected person prefers cookie and cream or vanilla.

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Complete the equivalent fraction 3/5 = ?/10

Answers

Answer:

Step-by-step explanation:

3/5 = x/10

5x = 30

x = 6

6/10

Hey there!

Original equation:

3/5 = ?/10

Convert to:

3/5 = x/10

Cross multiply the numbers:

3 * 10 = 5 * x

Simplify it:

3 * 10 = 5 * x

30 = 5x

5x = 30


Divide 5 to both sides:

5x/5 = 30/5


Simplify it:

x = 30/5

x = 6


Therefore, your mystery number should be: 6


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

Find the solution of the system of equations
shown on the graph.

Answers

Answer: (0,6)

Step-by-step explanation:

The solution is where the graphs intersect.

Can you get out of jail within 3 days or 7 days or at least 2 weeks or are they just lying about being in jail to begin with?

Answers

Answer:

you better give me brainliest

Step-by-step explanation:

i think they are lying about being in jail

what is the difference between d and 7?

Answers

Answer:

d - 7

Step-by-step explanation:

The word "difference" tells us that we will be using subtraction. Also, subtraction is not the same if you reverse the terms like, x - 2 and 2 - x are not the same. In your question it say "d and 7" so that's the order we use in the algebraic expression.

What is the simplified form of i^86?
A. 1
B. i
C. -1
D. -i

Answers

A is the answer because it’s the simplified form of i^86

4899 x 67 show your work​

Answers

Answer:

328,233

Step-by-step explanation:

Use the algorithm method.

4 8 9 9

×     6 7

3 6 6 6

3 4 2 9 3

2 5 5 5  

2 9 3 9 4 0

1  1 1  

3 2 8 2 3 3

328,233

simplify (-243)^-3/5

Answers

The expression, [tex](-243)^{-3/5}[/tex] on simplification using the laws of the exponent can be written as - (1/27).

Exponents are of the form aˣ, read as " a to the power x", function as a multiplied by itself x number of times, and are used in a numerical and algebraic expression.

To simplify these expressions, we use the following laws of the exponents:

[tex]1. a^m.a^n = a^{m + n}\\2.\frac{a^m}{a^n} = a^{m-n}\\ 3. (a^m)^n = a^{mn}\\4. a^{-m} = \frac{1}{a^m}\\5. a^0 = 1[/tex]

In the question, we are asked to simplify the expression, [tex](-243)^{-3/5}[/tex].

The expression can be solved using the laws of exponent as follows:

[tex](-243)^{-3/5}\\[/tex]

= [tex]((-3)^5)^{-3/5}[/tex]

= [tex](-3)^{-3}[/tex] {Using the law of exponent: [tex](a^m)^n = a^{mn}[/tex]}

= [tex]\frac{1}{-3^3}[/tex] {Using the law of exponent: [tex]a^{-m} = \frac{1}{a^m}[/tex]}

= 1/(-27)

= - (1/27).

Thus, the expression, [tex](-243)^{-3/5}[/tex] on simplification using the laws of exponent can be written as - (1/27).

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Middler Corporation, a manufacturer of electronics and communications systems, uses a service department charge system to charge profit centers with Computing and Communications Services (CCS) service department costs. The following table identifies an abbreviated list of service categories and activity bases used by the CCS department. The table also includes some assumed cost and activity base quantity information for each service for October.

CCS Service
Category
Activity Base
Budgeted Cost Budgeted Activity
Base Quantity
Help desk Number of calls $160,000 3,200
Network center Number of devices monitored 735,000 9,800
Electronic mail Number of user accounts 100,000 10,000
Smartphone support Number of smartphones issued 124,600 8,900
One of the profit centers for Middler Corporation is the Communication Systems (COMM) sector. Assume the following information for the COMM sector:

• The sector has 5,200 employees, of whom 25% are office employees.

• All the office employees have been issued a smartphone, and 96% of them have a computer on the network.

• One hundred percent of the employees with a computer also have an e-mail account.

• The average number of help desk calls for October was 1.5 calls per individual with a computer.

• There are 600 additional printers, servers, and peripherals on the network beyond the personal computers.

a. Determine the service charge rate for the four CCS service categories for October.

CCS Service Category Service Charge Rate
Help desk $fill in the blank 1

Per call
Network center $fill in the blank 3

Per device monitored
Electronic mail $fill in the blank 5

Per user or e-mail account
Smartphone support $fill in the blank 7

Per smartphone issued

Answers

The answers to the service charge rate are:

50751014

How to determine the service charge rate for the month of October

This is the number of calls for the help desk

160000/3200 = 50per call

For the network center

735000/9800

= 75 per device that was monitored

For the Electronic mail

100000/10000 =

10 for the mail account

For local voice support

124600/8900

= 14 per phone extension

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(a) Descriptive form: The set of natural numbers greater than or equal to 6.

(b) Roster form: (5, 7, 9, 11)

Answers

The set of natural numbers greater than or equal to 6 will be 6, 7, 8, 9, 10, ....

How to illustrate the information?

It should be noted that the first information is about the set of natural numbers greater than or equal to 6. Therefore, they will be 6 and above.

It should be noted that the descriptive form simply states in words the elements that are in a set. It is the verbal description of the elements in the set. It is the determination of the elements that belong to a set and those that doesn't.

Also, the way that a set is described is known as the roster form. In this case, the contents of a set can be described by listing the elements that are in the set which are separated by a comma inside the bracket.

Also, the roster form: (5, 7, 9, 11) indicates odd natural numbers. The numbers that are given are odd.

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The question is in the picture

Answers

Answer:

16

Step-by-step explanation:

18,903

One hundred dollars less
than twice last year's
income?

Answers

Answer:

2y - 100

Step-by-step explanation:

Last year's income = y

2y-100

How many three-digit positive integers have three different digits and at least one prime digit?

Answers

The number of three-digit positive integers that have three different digits and at least one prime digit are 7960.

What are prime numbers?

The definition of a prime number is a natural number larger than 1 that is not the sum of two lesser natural numbers. A composite number is any natural number that is more than 1 but not a prime.

The only two components in prime numbers are 1 and the number itself.

Any whole number greater than one is a prime number.

It has exactly two factors—1 and the actual number.

There is just one 2-digit even prime number.

Every pair of prime numbers is always a co-prime.

The product of prime numbers can be used to represent any number.

Three-digit positive integers that have three different digits and at least one prime digit = 3!*4!*10*9 = 7960

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Captain's Autos sells 22 used cars on
Monday, and 18 cars on Tuesday. This was
25% of the number of sales for the week.
How many cars did they sell altogether that
week

Answers

Answer:

160

Step-by-step explanation:

22 + 18 = 25 percent

40 = 25 percent

100 / 25 = 4

40 x 4 = 160.

Find the area of the trapezoid

Answers

Answer:

[tex]52\sqrt{3}[/tex]

Step-by-step explanation:

[tex]\frac{1}{2}(11+15)(4\sqrt{3})=52\sqrt{3}[/tex]

a train started from Howrah to Allahabad and another train started from Allahabad for Howrah at the same time. The two trains reached their destinations in 9 hours

Answers

The speed ratio of the two trains is 4:3, that is, for every 4 hours that one train is delayed, the other is delayed 3.

How to find the speed ratio of the trains?

To find the speed ratio of the trains we must do the following operation:

V1 = [tex]\frac{x}{t} = \frac{l - x }{9}[/tex]V1 = [tex]\frac{x}{l - x} = \frac{t}{9}[/tex]

T = [tex]\frac{t}{9} = \frac{16}{t}[/tex]

V2 = [tex]\frac{x}{t} = \frac{x}{12}[/tex]

V1 : V2 = [tex]\frac{x}{12}[/tex]:[tex]\frac{x}{16}[/tex]

Note: This question is incomplete because there is some information missing. Here is the complete information in:

A train started from Howrah for Allahabad another train started from Allahabad for Howrah at the same time. The two trains reached their destinations in 9hours and 16 hours respectively after they meet each other. Find the ratio of speed of the two trains.​

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Hello guys, can you please help my son!!

Answers

Based on the fact that there is no country which had won more than 900 silver medals, set E using the roster method would be E = {  }.

How is set E denoted?

Set E is meant to include the set of countries who have attained more than 900 silver medals in the Olympic games.

The highest number of silver medals attained is that of the United States which is 860 silver medals.

This means that no single country has attained more than 900 silver medals.

Set E would therefore be null. Using the roster method, the way to show set E would be:

E = {  }

In conclusion, set E is E = {  }.

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The question is below ​

Answers

The events E1 and E2 are not independent events.

How to determine if the events are independent?

The two events are given as:

E1 and E2 such that

P(E1) = 0.27, P(E2) = 0.40 and P(E1 U E2) = 0.58.

The two events E1 and E2 are independent if the following equation is true

P(E1 and E2) = P(E1) * P(E2)

Where

P(E1 and E2) = P(E1) + P(E2) - P(E1 U E2)

Substitute the known values in the above equation

P(E1 and E2) = 0.27 + 0.40 - 0.58

Evaluate the sum in the above equation

P(E1 and E2) = 0.67 - 0.58

Evaluate the difference in the above equation

P(E1 and E2) = 0.09

Substitute P(E1 and E2) = 0.09 in P(E1 and E2) = P(E1) * P(E2)

P(E1) * P(E2) = 0.09

Substitute P(E1) = 0.27 and P(E2) = 0.40 in the above equation

0.27 * 0.40 = 0.09

Evaluate the product

0.108 = 0.09

The above is false because 0.108 and 0.09 are not equal

Hence, the events E1 and E2 are not independent events.

Independent Events A and B

How to solve for x

We  have:

P(A) = x

P(B) = x + 0.2

P(A n B) = 0.15

For independent events, we have:

P(A) * P(B) = P(A n B)

So, we have:

x * (x + 0.2) = 0.15

Expand

x^2 + 0.2x - 0.15 = 0

Using  a graphing calculator, we have:

x = 0.3

Hence, the value of x is 0.3

The value of P(A U B)

This is calculated using

P(A U B) = P(A) + P(B) - P(A n B)

Substitute the known values in the above equation

P(A U B) = x + x + 0.2 - 0.15

Evaluate the like terms

P(A U B) = 2x + 0.05

Substitute 0.3 for x

P(A U B) = 2 * 0.3 + 0.05

Evaluate

P(A U B) = 0.65

Hence, the value of P(A U B) is 0.65

The value of P(A' U B')

This is calculated using

P(A' U B') = P(A') + P(B') - P(A' n B')

Where

P(A') = 1 - x

P(B') = 1 - x - 0.2 = 0.8 - x

P(A' n B') = P(A') * P(B')

P(A' n B') = (1 - x) * (0.8 - x)

Substitute the known values in the equation P(A' U B') = P(A') + P(B') - P(A' n B')

P(A' U B') = (1 - x) + (0.8 - x) - (1 - x) * (0.8 - x)

Substitute 0.3 for x

P(A' U B') = (1 - 0.3) + (0.8 - 0.3) - (1 - 0.3) * (0.8 - 0.3)

Evaluate

P(A' U B') = 0.85

Hence, the value of P(A' U B') is 0.85

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Match each statement (term) with its value in relation to 0 (definition).

Match Term Definition
A building is 37 feet tall. A) –13.7
The scuba diver was 37 feet below sea level. B) 2.5
The basement is 13.7 feet below ground. C) −37
Oliver owes his sister $25. D) 37
Erica jumped 2.5 feet above the ground. E) –25

Answers

The statements with their correct matches in relation to 0 are:

A building is 37 feet tall - 37The scuba diver was 37 feet below sea level = −37The basement is 13.7 feet below ground = –13.7Oliver owes his sister $25 = -25Erica jumped 2.5 feet above the ground = 2.5

What are the values in relation to 0?

When a building is 37 feet tall, it means that if 0 feet was the ground level, the building would be 37 higher than 0. This is the same for the basement which will be -13.7 in relation to a ground level of 0.

Erica jumping 2.5 feet above the ground is 2.5 in relation to 0feet and the scuba driver is -37 by the same relation to 0 feet.

Oliver owes his sister $25 which means that in relation to a state of no debt or $0, Oliver is -25 deep in debt.

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X=y
Y=x
Is this is inverse equation

Answers

The inverse equation of x = y is y = x

What are inverse equations?

Inverse equations are the opposite of an original equation

How to determine the inverse equation?

The equation is given as

x = y

Swap the positions of x and y in the above equation

y = x

This means that the inverse equation of x = y is y = x

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A private jet flies the same distance in 8 hours that a commercial jet flies in 7 hours. If the speed of the commercial jet was 144mph less than 2 times the speed of the private jet, find the speed of each jet.

Answers

Solving a system of equations, we can see that:

Speed of the private jet: 168 mi/hSpeed of the commercial jet: 192mi/h

How to find the speeds of each jet?

Let's define the variables:

P = speed of the private jet.C = speed of the commercial jet.

With the given information, we can write:

P*8h = D

C*7h = D

C = 2*P - 144mi/h

So we have a system of 3 equations, where D is the distance in the problem.

With the first and second equations we can write:

P*8h = D = C*7h

Isolating P, we get:

P = C*(7/8)

Now we can replace that in the last equation:

C = 2*P - 144mi/h

C = 2*C*(7/8) - 144mi/h

And now we can solve that for C.

C - 2*(7/8)*C = - 144mi/h

C*(1 - 14/8) = -144mi/h

C*(8/8 - 14/8) = - 144mi/h

C*(6/8) = 144mi/h

C = (8/6)*144mi/h = 192mi/h

Now that we know the speed of the commercial jet, we can find the speed of the private jet.

P = C*(7/8) = 192mi/h*(7/8) = 168 mi/h

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a linear equation is an equation whose graph is a straight lina

Answers

The statement that a linear equation is an equation whose graph is a straight line is True.

What is a linear equation?

A  linear equation can be defined as an algebraic equation with each term having an exponent and the graphing of the equation results in a straight line.

From the definition, it can be deduced that the statement is True.

Thus, the statement that a linear equation is an equation whose graph is a straight line is True.

The complete question is:

True or false

A linear equation is an equation whose graph is a straight line.

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