If an ideal solution contains 3. 50 mol of a non-volatile solute and 15. 8 mol of solvent, and it has a vapor pressure of 22. 6 torr, what is the vapor pressure of the pure solvent (in torr)?

Answers

Answer 1

The vapour pressure of the solvent is 28.25 torr.

Raoult's law is a physical chemistry relationship with consequences for thermodynamics. The theory, put out by French chemist François-Marie Raoult in 1887, asserts that the partial pressure of each component of an ideal mixture of liquids is equal to the vapor pressure of the pure component (liquid or solid) multiplied by its mole fraction in the mixture. As a result, the mole fraction of the solute in the solution is equal to the relative decrease in vapor pressure of a diluted solution of a nonvolatile solute.

According to Raoult's law, p = p⁰ × x

Where,

p = partial vapour pressure of the solvent

p⁰ = vapour pressure of the solvent

x = mole fraction of solvent

The mole fraction of the pure solvent = 15 .8 /19.3

                                                               = 0.81

Substitute values in the above expression,

p = p⁰ × x

22.6 = p⁰ × 0.8

p⁰ = 28.25 torr

Therefore, the vapour pressure of the solvent is 28.25 torr.

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Related Questions

What is the daughter nucleus (nuclide) produced when 59 co undwegoes positron decay?

Answers

The 59 co is 100 % stable nuclei that's why it will not show  any kind of decay, have not any daughter nucleus.

The process of radioactive decay describes how an unstable atomic nucleus releases energy through radiation. A substance that has unstable nuclei was regarded as radioactive. Alpha, beta, as well as gamma decay, are three of the most poses significant of decay, as well as they all entail the emission of one or maybe more particles.

Every atom strives to have the greatest degree of stability. When the proportion of protons as well as neutrons in the atomic nucleus is out of balance, instability results in radioactive decay. In essence, the nucleus contains too much energy to keep all the nucleons together.

Therefore, the 59 co is 100 % stable nuclei that's why it will not show  any kind of decay, have not any daughter nucleus.

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Draw the structure of the major organic product formed in the reaction of m‑cresol with sodium hydroxide. Ignore counterions.

Answers

The reaction between m-cresol and sodium hydroxide will create sodium m-cresolate and water.

What is organic creation?

The structure of the organic creation (sodium m-cresolate) and the reaction is described in the attached picture.

In the late 1700s and earlier 1800s, organic biological products were isolated by Scheele, and Chevreuil dissolved carboxylic acids from the saponification of fats. Organic chemistry had formed. Lavoisier invented and Berzelius enhanced combustion research for the organic description. Organic Chemistry was first diagnosed as a branch of modern science in the earlier 1800s by Jon Jacob Berzelius. He compartmentalized chemical combinations into two groups-organic and inorganic, representing if they came from minerals or non-living significance.Organic chemistry is important because it is the study of life and all of the chemical responses related to life. Several professions apply an interpretation of organic chemistry, such as doctors, veterinarians, dentists, pharmacologists, chemical makers, and chemists.

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Calculate [hy3−] in a solution prepared by mixing 10. 00 ml of 0. 0305 m voso4, 9. 20 ml of 0. 0305 m edta, and 10. 00 ml of buffer with a ph of 4. 0

Answers

The concentration of [ Hy³] = 4.861 *28⁻²³

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or answer. A focused answer is one which has a exceedingly massive quantity of dissolved solute. A dilute answer is one that has a tremendously small amount of dissolved solute.

Given,

 Molarity of VoSo4 ,M = 0.02M

     Vol of VoSo4 , V = 10 ml

Molarity of EDTA = 0.02 M

vol of EDTA = 9.10 ml = 0.0091 L

& 10 ml of buffer with pH =4

NOW,

     no. of moles of EDTA = molarity * Volume (L)

                                         =  0.02 M * 0.0091 L

                                        = 182 * 10^-6 moles

                                        = 1.82 * 10^-4 moles

Now,

       ∝ Y^3- = [tex]\frac{[Y^3-]}{moles of edta}[/tex]

         [ Y^3-] = ∝ Y^3- * moles of EDTA

Given,

at pH = 4,   ∝ Y^3- = 3*10^-9

    ∴ ∝ Y^3- =  3*10^-9

        [ Y^3-] = 3*10^-9 * 1.82 * 10^-4

                   = 5.46 * 10^-13

Now, K f = [H2Y^2-]/[vo^2+][y3-]

           [vo^2+] = 18.7

[H2Y2-] = K f * [ v o+][Y^2-]

    [H2Y2] = 3.762 * 10^-13

 [ HY^3-] = 4.8 * 10^-23

So, the concentration of the    [ HY^3-] is 4.8 * 10^-23

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When an electron passes through the magnetic field of a horseshoe magnet, the electron's?

Answers

When an electron passes through the magnetic field of a horseshoe magnet, the electron's direction is changed.

Path of an electron in a magnetic field

The force (F) on wire of length L carrying a current I in a magnetic field of strength B is given by the equation:

F = BIL

But Q = It and since Q = e for an electron and v = L/t you can show that :

Magnetic force on an electron = BIL = B[e/t][vt] = Bev where v is the electron velocity

In a magnetic field the force is always at right angles to the motion of the electron (Fleming's left hand rule) and so the resulting path of the electron is circular.

Therefore :

Magnetic force = Bev = mv2/r = centripetal force

v = [Ber]/m

and so you can see from these equations that as the electron slows down the radius of its orbit decreases.

If the electron enters the field at an angle to the field direction the resulting path of the electron (or indeed any charged particle) will be helical. Such motion occurs above the poles of the Earth where charges particles from the Sun spiral through the Earth's field to produce the aurorae.

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The IR spectrum of a solid can be taken by dissolving it to create a solution. An appropriate solvent is?

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The IR spectrum of a solid can be taken by dissolving it to create a solution. An appropriate solvent is carbon tetrachloride as its IR stretches are( only in tne fingerprint region) not visible in the region of infrared.

Non-polar solvents do not show peaks at the region of IR frequency because they do not have dipoles which absorb the infrared light. However, it has been noted that some of these solvent interfere the reaction spectra or absorb within the range of spectra. This property makes them suitable solvents in IR Spectroscopy.

Therefore non-polar solvents such as CCl4 or Carbon disulfide are appropriate for the IR spectrum. They also do not interfere with the halide disks used in the spectrometer, as a solvent like water would.

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What quantity of nag3 was required to reach the equivalence point in the titration?.

Answers

1.0 mL x 0.1 mM quantity of nag3 was required to reach the equivalence point in the titration.

The technique of titration, also known as titrimetry, is used in chemical qualitative analysis to establish the concentration of a certain analyte in a mixture. Titration, commonly known as volumetric analysis, is an essential analytical chemistry technique. However, the two titration types that are most frequently used in quantitative chemical analysis are redox and acid-base titration, titration Procedures, bases and acids are diluted,oxygen-based titrations, and precipitation titrations. Utilize the titration equation. The equation is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base if the titrant and analyte have a mole ratio of 1:1. (Molarity is the measure of a solution's concentration, which is given in moles of solute per liter of solution.)titrations utilizing intricate metrics.

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Answer the following questions in complete sentences.

A. Identify club soda as an element, compound, or mixture.

B. Explain the classification of club soda identified in Part A.

Answers

Answer:

a) club soda is a compound

b) Club soda is a manufactured form of carbonated water, commonly used as a drink mixer. Sodium bicarbonate, potassium sulfate, potassium bicarbonate, potassium citrate, or sodium citrate is artificially added to replicate constituents commonly found in natural mineral waters

the seasonal shifts of earths planetary wind and moisture belts are due to changes in the

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The seasonal shifts of Earth's planetary wind and moisture belts are due to changes in the latitude that receives the sun's vertical rays.

What is the latitude?

The latitude refers to the specific geographic coordinates at some point of the Earth in relation to the Equator line.

Latitude and longitude are geographic coordinates that allow to localize a specific point in the world by using the center of the Earth's planet as point of origin.

The amount of sun rays received by a given latitude largely depends on the season since the Earth's planet has a light inclination that alter this amount of radiation.

In conclusion, the seasonal shifts are due to changes in the latitude that receives the sun's vertical rays.

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Another real-world example of a change is rust. rust is iron(iii) oxide (fe2o3), which results when iron is exposed to oxygen and water. what are some indicators of rusting? check all that apply.

Answers

Rusting of Iron is the formation of rust which is characterized by formation of layer of red colour. Formula of Rust is Ferric Oxide (Fe₂O₃) where iron exhibits oxidation state of +3.

Following are the indicators of rusting:

Colour change to redSolid formationFlaky substances crumbling into powder

Even if the Reddish brown rust is not visible on the iron surface, then also Ferroxyl Indicator turns blue in presence of Iron ions.

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If 160 grams of a 200-gram sample of gold-198 decay in 6.25 days, what is the half-life of gold-198?

Answers

The half-life of gold-198 is 2.77 days

Given:

mass of gold sample = 200-gram

mass of decay sample = 160 grams

time taken to decay = 6.25 days

To Find:

the half-life of gold-198

Solution: The amount of time it takes to disintegrate by half an initial amount. For a given reaction, a reactant's half-life t1/2 is the time it takes for its concentration to reach a value which is the arithmetic mean of its initial and final (equilibrium) value.

Since Au-198 is 200 g originally and it decays to 160 g, so 40g left

the fraction decay is 40/200 = 0.2

the time base is 6.25 days

ln0.2/6.25 = -0.25

k=ln2/half life therefore half-life = ln2/k = ln2/0.25

half life = 2.77 days

So, half life of gold is 2.77 days

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What would cause the equilibrium to shift left in this reaction? co 3h2 ⇌ ch4 h2o

Answers

option (A) Adding heat to the product mixture is the right answer.

As the reactant side has more moles than the product side, the equilibrium of the reaction shifts to the left to decrease pressure by increasing volume.

If the temperature drops, equilibrium also moves to the left.

Given equation is co+ 3h2 ⇌ ch4+ h2o

When heat is added to the product mixture in this situation, equilibrium moves to the left.

What is meant by equilibrium?

A condition where opposing forces or actions are in balance is known as equilibrium.

What two types of equilibrium are there?

Equilibrium is of two types:

homogeneous equilibriumheterogeneous equilibrium

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The materials in the flux covering on an electrode determine the electrical characteristics of the electrode.

a. true
b. false

Answers

Answer:

a. true

Explanation:

It is true that, the materials in the flux covering on an electrode determine the electrical characteristics of the electrode.

The combustion of 1 mole of co according to the reaction co(g) ½o 2 (g) co 2 (g) 67.6 kcal gives off how much heat?

Answers

Heat change at constant volume for the combustion of carbon monoxide = -67.71 Kcal

CO(g) + 1/2O2(g) ⟶ CO2(g)

From the above reaction,

∆ng = nP - nR = 1 - ( 1/2 + 1 )

∆ng = - 1/2

Temperature (T) = 17°C (17+ 273) K = 290K (Given)

Now from first law of thermodynamics,

∆H = ∆E + ∆ng RT

ΔΗ = -67.71 + (-1/2) x 2 x 10^-3 x 290

∆H = -67.71 - 0.29 = -68 Kcal

Hence the heat of reaction at constant pressure will be -68 Kcal

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List the procedural steps, from start to finish, that are required to convert 2‑naphthol and allyl bromide into allyl 2‑naphthyl ether.

Answers

Procedural steps are: - On a small scale, the reaction is carried out by combining the alcohol, the haloalkane, and the phase transfer catalyst in a conical vial. To start the reaction, sodium hydoxide (base) is added. To prevent solvent evaporation, the reaction flask is covered and stirred during the reaction. TLC monitors the reaction's progress to ensure that no time is wasted.To remove any remaining water, the reaction solution is dried over calcium chloride. Column chromatography is used to purify the product, and evaporation is used to collect it.What is Catalysis?

Catalysis is the process of boosting the pace of a chemical reaction by using a catalyst. Catalysts are not consumed in the reaction and so survive it.

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Why are salt and sugar both able to dissolve in water, even though the solutes have different types of chemical bonding?.

Answers

Answer: Everything can dissolve in water because water is considered a universal solvent

Explanation: Liquid water is cooler than solid salt and sugar, allowing them to dissolve easily.

According to the concept of solubility, as water is considered to be a universal solvent salt and sugar both are able to dissolve in water as water is a universal solvent.

What is solubility?

Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.

The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.Concept of solubility is not valid for chemical reactions which are irreversible. The dependency of solubility on various factors is due to interactions between the particles, molecule or ions.

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If the a of a monoprotic weak acid is 2. 6×10−6, what is the ph of a 0. 33 m solution of this acid?

Answers

The pH of the monoprotic weak acid is 2.79.

What are weak acids?

The weak acids are the acids that do not fully dissociate into ions in the solution. Strong acids fully dissociate into ions.

The chemical reaction is HA(aq) ⇄ A⁻(aq) + H⁺(aq).

c (monoprotic acid) = 0.33 M.

Ka = 1.2·10⁻⁶

[A⁻] = [H⁺] = x

[HA] = 0.33 M - x

Ka = [A⁻]·[H⁺] / [HA]

2. 6 × 10⁻⁶ = x² / (0.33 M - x)

Solve quadratic equation: [H⁺] = 0.000524 M.

pH = -log[H⁺]

pH = -log(0.000524 M)

pH = 2.79

Thus,  the pH of the monoprotic weak acid is 2.79

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If 20. 3 grams of an aqueous solution of iron(ii) chloride, fecl2, contains 2. 71 grams of iron(ii) chloride, what is the percentage by mass of iron(ii) chloride in the solution?

Answers

If 20. 3 grams of an aqueous solution of iron(ii) chloride contains 2. 71 grams of iron(ii) chloride, then percentage by mass of  iron(ii) chloride in the solution is 13.34%

Calculation,

Given:

mass of an aqueous solution of iron(ii) chloride = 20. 3 grams

mass of iron(ii) chloride = 2. 71 grams

The percentage by Mass is equal to percentage of mass of solute present in total mass of solution. It is also known as Mass percentage.

percentage by Mass = 100× 2. 71 grams/20. 3 grams = 13.34%

Hence, the percentage by mass of  iron(ii) chloride in the solution is 13.34% .

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Why is the vapor pressure of a warm pale higher than the vapor pressure of a cold lake

Answers

The vapor pressure of a warm pale higher than the vapor pressure of a cold lake because Warm water evaporates more quickly.

Hence, Option B is correct answer.

What is Evaporation ?

The process in which a liquid or solid is converted into vapour is called Evaporation. When water gains the heat energy then it changes in to gas. When the temperature increases it speeds up the rate of evaporation.

The temperature of warm water increases, the kinetic energy of the warm water molecule also increases.

Thus from the above conclusion we can say that The vapour pressure of a warm lake is higher than the vapor pressure of a cold lake because Warm water evaporates more quickly.

Hence, Option B is correct answer.

Disclaimer: The question was given incomplete on the portal. Here is the complete questions.

Question: Why is the vapor pressure of a warm lake higher than the vapor pressure of a cold lake?

A. Warm water has a greater heat of vaporization.

B. Warm water evaporates more quickly.

C. Cool water evaporates more quickly.

D. Cool water has a greater heat of vaporization.

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Butane reacts with oxygen gas to form carbon dioxide and water vapor as shown below:
2C₂H₁o + 130₂-8CO₂ + 10H₂O

a. If 20 g of butane were used in the experiment how many litres of water would be produced at SATP?

b. How many litres of oxygen would be consumed in this experiment?

c. If conditions were converted from SATP to STP, how many litres of water would now be produced?

Answers

A. The volume of water (in litres) produced at SATP is 42.73 L

B. The volume of oxygen consumed in the experiment is 55.55 L

C. If the conditions were converted from SATP to STP, the volume of water (in litres) produced is 38.64 L

How to determine the mole of C₂H₁₀ Mass of C₂H₁₀ = 20 gMolar mass of C₂H₁₀ = (12×4) + (10×1) = 58 g/molMole of C₂H₁₀ = ?

Mole = mass / molar mass

Mole of C₂H₁₀ = 20 / 58

Mole of C₂H₁₀ = 0.3448 mole

A. How to determine the volume of water (in litres) produced at SATP

Balanced equation

2C₄H₁₀ + 13O₂ -> 8CO₂ + 10H₂O

From the balanced equation above,

2 moles of C₄H₁₀ reacted to produce 10 moles of water.

Therefore,

0.3448 mole of C₄H₁₀ will react to produce = (0.3448 × 10) / 2 = 1.724 mole of water

Thus, the volume of water (in litres) produced at SATP can be obtained by using the ideal gas equation as follow:

Number of mole of water (n) = 1.724 molePressure (P) = SATP = 0.987 atm Temperature (T) = SATP = 298 KGas constant (R) = 0.0821 atm.L/Kmol Volume of water produced (V) =?

PV = nRT

Divide both sides by P

V = nRT / P

V = (1.724 × 0.0821 × 298) / 0.987

Volume of water produced at SATP = 42.73 L

B. How to determine the volume of oxygen consumed

Balanced equation

2C₄H₁₀ + 13O₂ -> 8CO₂ + 10H₂O

From the balanced equation above,

2 moles of C₄H₁₀ reacted with 13 moles of O₂

Therefore,

0.3448 mole of C₄H₁₀ will react with = (0.3448 × 13) / 2 = 2.2412 moles of O₂

Thus, the volume of O₂ (in litres) consumed at SATP can be obtained by using the ideal gas equation as follow:

Number of mole of O₂ (n) = 2.2412 molesPressure (P) = SATP = 0.987 atm Temperature (T) = SATP = 298 KGas constant (R) = 0.0821 atm.L/Kmol Volume of O₂ consumed (V) =?

PV = nRT

Divide both sides by P

V = nRT / P

V = (2.2412 × 0.0821 × 298) / 0.987

Volume of O₂ consumed = 55.55 L

C. How to determine the volume of water (in litres) produced at STPNumber of mole of water (n) = 1.724 molePressure (P) = STP = 1 atm Temperature (T) = STP = 273 KGas constant (R) = 0.0821 atm.L/Kmol Volume of water produced (V) =?

PV = nRT

Divide both sides by P

V = nRT / P

V = (1.724 × 0.0821 × 273) / 1

Volume of water produced at STP = 38.64 L

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What is the equilibrium vapor pressure of diethyl ether and ethanol at room temperature (approximately 20 °c)?

Answers

The equilibrium vapour pressure of diethyl ether and ethanol at room temperature or at 20°C is 442mm and 5.95kPa.

What is vapour Pressure

The pressure exerted by gas in equilibrium state with a solid or liquid in container at a given temperature is termed as vapour pressure.

.Factor affecting vapour pressure:-

Surface area:

The surface area of solid of liquid which is in contact with the gas do not much affect the vapour pressure.

Type of molecules:

Greater the intermolecular face small will be smaller will be vapour pressure, if lesser the force then greater will be the vapour pressure.

Temperature:

At high temp.,more molecules has enough energy to escape from the liquid or solide. At lower temp. feuer molecule escape enhance lesser tha vapour pressure.

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What two molecules make up sucrose?

Answers

Answer:

glucose and fructose

Explanation:

Sucrose is a disaccharide (a kind of sugar made of two monosaccharides) made of glucose and fructose

For the reaction: n2(g) 2 o2(g) ⇌ 2 no2(g), kc = 8. 3 × 10-10 at 25°c. what is the concentration of n2 gas at equilibrium when the concentration of no2 is twice the concentration of o2 gas?

Answers

4.8 × 10^9 M  is the concentration of n2 gas at equilibrium when the concentration of no2 is twice the concentration of o2 gas.

In some gas-producing fields, such as those in the US Midwest, North Sea, Eastern Europe, and South East Asia, nitrogen (N2) may naturally present in significant concentrations. Around 15% of the world's non-associated gas deposits have nitrogen content levels that are too high to be considered pipeline-quality gas (usually 3–4 mol%). Because it is an inert gas, nitrogen cannot support burning. Consequently, unstable combustion could result from burning a gas that contains too much nitrogen. The recovery of NGL content will be lowered when high nitrogen gas is treated in a gas plant because nitrogen acts as stripping gas. The compression technology and size of the transmission pipeline will rise with increased nitrogen concentration. High nitrogen levels are undesirable in an LNG plant because they lower the LNG temperature, which increases the energy required to liquefy natural gas and also increases the amount of boil-off gas from the LNG storage tanks.

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Which does not apply to dihydroxyacetone?
a. ketose
b. triose
c. chiral
d. water-soluble

Answers

Answer: C. Chiral

Explanation: In chemistry, a molecule or ion is called chiral if it cannot be superposed on its mirror image by any combination of rotations, translations, and some conformational changes. This geometric property is called chirality.

A beaker contains a mixture of ice and pure liquid water at 0°c. what happens to the temperature of the liquid water as heat is added?

Answers

Answer:

Remains the same

Explanation:

Until the ice is all melted the water should remain at 0° C....

  the ice melting is a constant temp process and absorbs heat as it melts at 0 C

Calculate the standard free-energy change for the reaction at 25 ∘c. refer to the list of standard reduction potentials. 2au3 (aq) 3cr(s)↽−−⇀2au(s) 3cr2 (aq)

Answers

The standard free-energy change for the reaction at 25°C is 92640 KJ.

The change in free energy that happens when a compound is created from its constituent parts in their most thermodynamically stable states under standard-state circumstances is known as the standard-state free energy of creation.

There are 6 electrons transferred. The anode half-reaction produces 6 electrons while the cathode half-reaction uses 6 electrons.

For these types of reactions always write out the half-reactions and the appropriate oxidation numbers.

6 electrons are transferred as Au³+ has an oxidation number of 3+ and Au has an oxidation number of 0. 3 electrons are gained for each Au³+ and there are 2 Au³+ in the equation

                         [tex]2Au^3 (aq) +3cr(s)[/tex] ↽−−⇀ [tex]2Au(s) +3Cr^2[/tex]

Same for Cr to Cr2+ because there are 3 moles of it.

So, n = 6.

     F = 96500 J/(V*mol)

     where  F is faraday's constant.

                 n = moles of electrons are transferred in this reaction.

Standard emf of the cell, E = cathode - anode.

                                             = 1.49 - 1.33

                                             = 0.16

Using the equation,

                                   ΔG = -nFE

                                         = 6 × 96500 × 0.16

                                         = 92640 KJ

Therefore, the standard free-energy change for the reaction at 25°C is 92640 KJ.

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What is the correct chemical name for the following structures pictured below?

Answers

The IUPAC names of the given compounds are 3-methylpentane, 1,3-butadiene, 1,3-dimethylcyclohexane, 2,3,5,5-tetramethyl-1,3-hexadiene, and 2,2-dimethylpentane respectively.

What are the IUPAC nomenclature rules?Find the longest continuous carbon chain. This chain is called a parent chain.Identify all the substituents attached to the parent chain.Number the carbon atoms from the end which gives the substituents the lowest number.If the substituent occurs more than one then the location of each point is given and the number of times the substituent occurs is indicated by a prefix like di, tri, tetra, and so on.Double bonds are always given preference. Give the double bond as low a number as possible.If there are two chains of equal lengths then choose the chain that hasgreatest numbers of side chainschain whose substituents have the lowest numberhaving least branched side chainsA cyclic (ring) hydrocarbon is represented by the prefix cyclo- which appears in front of the base name.

Thus, following the IUPAC nomenclature rules the name of the given compounds are as follows:

3-methylpentane

1,3-butadiene

1,3-dimethylcyclohexane

2,3,5,5-tetramethyl-1,3-hexadiene

and 2,2-dimethylpentane

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When an electron drops from the n= 6 to the n= 3 orbit, light is emitted with a wavelength of

Answers

The wavelength of the electron is 1085nm.

What is the wavelength?

The wavelength refers to the horizontal distance that is covered by a wave. Now we know that according to the Bohr Model of the atom, electrons move from a higher to a lower energy level leading to the emission of a ray of light with a characteristic wavelength.

Now Using the formula;

1/λ = RH (1/n2^2 - 1/n1^2)

Where;

λ = wavelength

n1 = initial energy level

n2 = final energy level

RH = Rydberg's constant

1/λ = 1.097 * 10^7(1/3^2 - 1/6^2)

1/λ =  1.097 * 10^7( 0.111 - 0.027)

λ =  1.085 * 10^-6 m or 1085nm

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Name the following compound: CH₂-C- CH₂-CH₂-CH₂-C - H butanal O2-butanol O propyl hydrogen ether 1-propanone​

Answers

Answer:

butanal

Explanation:

It's not 1-propanone because otherwise you have OH bonded to C not O and H bonded to C separately. 2-butanol means that the O and H would be bonded to a different C atom, and it's not propyl hydrogen ether because the O would be in the chain of bonded Cs.
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Answer:

Butanal

Explanation:

trust

Select true or false: if 2mg(s) o2(g) → 2mgo(s), δh° = –1203. 6 kj/mol, then formg(s) (1/2)o2(g) → mgo(s), the enthalpy change is δh = –601. 8 kj/mol

Answers

According to the given equation ,if 2Mg(s) O2(g) → 2MgO(s), δh° = –1203. 6

k j/m o l, then form g(s) (1/2)O2(g) → Mg O(s), the enthalpy change is δh = –601. 8 k j /m o l, hence the given statement is true.

What do you mean by enthalpy change?

An enthalpy change is roughly equivalent to the energy gained through the production of new chemical bonds in a reaction minus the energy required to break existing chemical bonds.

It describes how a system changes in terms of energy while pressure is constant.

The symbol ΔH stands for enthalpy change. At constant pressure, ΔH is equal to the sum of the system's internal energy and the pressure-volume work it performs on its surroundings.

It  is expressed in units of joules per mole.

If 2Mg(s) O2(g) → 2MgO(s), δh° = –1203. 6

k j/m o l, then form g(s) (1/2)O2(g) → Mg O(s), the enthalpy change is δh = –601. 8 k j /m o l, therefore the above given statement is true.

Learn more about enthalpy change ,here:

https://brainly.com/question/3298339

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When the ph of an aqueous solution is changed from 1 to 2, the concentration of hydronium ions in the solution is.

Answers

Answer:

decreased by a factor of 10

Explanation:

pH is defined in such a way that;

pH= −log10(H)

Where H represents the concentration of Hydronium or Hydrogen ions

Given that pH is changed from 1 to 2,

By rearranging the above formula , we get 10−pH = H

if pH=1,H=10−1=0.1Mif pH=2,H=10−2=0.01M

Therefore,  0.1/0.01 = 10 and 0.1 > 0.01

Hence, the concentration of hydronium ions in the solution is decreased by a factor of 10

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