If an object is dropped how long will it take to attain a velocity of 127.4 m/s

The engine weighs four times as much as a freight car. Therefore, the final velocity following connection is 4 km/h.

v′=m1v1+m2v2m1+m2 m1 is the weight of item 1, v1 is indeed the velocity of the object of item 1, m2 is indeed the mass of argument 2, and v2 is the starting velocity of instrument 2 wherein v' is the final speed of a two objects after they travel as one mass after the collision.

The velocity of the special properties in a head-on object with a projectile that is significantly more massive than target the projectile's speed before and after the contact will be roughly equal, and the projectile's speed will practically remain unaltered.

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1) Statements best describes the electric field in the region between the spheres  field points radially outward.

2) Statements best describes the electric field in the region outside the red sphere The field is zero.

For positive charge, E field lines are projecting outward of positive charge.

For negative charge, E field lines are projecting inward of negative charge.

Then, between the spheres,

because of q, E field lines are projecting outward of q and inward of- q;

and because of- q, E filed lines are projecting outward of q and inward of- q

So, The field points radially outward

2) C still, net charge inside the gaussian face is zero, If we draw a gaussian face outside the spheres.

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The speeds of the object at the various positions are :

The formula to determine the velocity or speed is given below:

velocity or speed = √(2s * F/m)

where:

The speeds of the object at the various points are given below:

At x = A: force = 9 N; s = 6 m

speed = √(2 * 6 * 9 / 38)

speed = 2.06 m/s

At x = B; Force = 9 N; s = 12 m

speed = √(2 * 12 * 9 / 38)

speed = 2.38 m/s

At x = C; Force = 0 N; s = 18 m

speed = √(2 * 12 * 0 / 38)

speed = 0 m/s

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Acceleration 1 - constant acceleration. Acceleration 2 - varied acceleration. The correct option is D.

Acceleration of any object is defined as the variation in the speed of the object with the variation of time. Acceleration is a vector term and to define it we require both the magnitude and the direction. The unit of acceleration can be m / sec², miles / sec², etc.

In a velocity-time graph, the acceleration corresponds to the slope of the curve.

In fact, acceleration is defined as the ratio between the change in velocity and the time interval:

a = Δv / Δt

However, in a velocity-time graph, corresponds to the y-variable increment (), while corresponds to the x-variable increment (). (). As a result, acceleration can also be expressed as,

a = Δy / Δx

For object 1, the slope is constant: this means that the acceleration is constant.

For object 2, the slope varies: this means that the acceleration varies as well.

The missing graph is attached with the answer below.

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Answer:

their speed maybe cause of the ups and downs

(a) The potential energy of the tank of water with respect to the floor is 294,000 J.

(b) The potential energy of the tank of water with respect to the basement is 392,000 J.

The potential energy of the tank of water with respect to the floor can be calculated as follows:

Potential energy = mgh

where;

We can first find the mass of the water using the density of water, which is approximately 1000 kg/m³:

Mass of water = density x volume

Mass of water = 1000 kg/m³ x 2500 L

Mass of water = 2500 kg

Now we can calculate the potential energy:

Potential energy = 2500 kg x 9.8 m/s² x 12.0 m

Potential energy = 294,000 J

The potential energy of the tank of water with respect to the basement can be calculated in a similar way. We can first calculate the height of the tank with respect to the basement:

Height of tank with respect to basement = 12.0 m + 4.0 m

Height of tank with respect to basement = 16.0 m

Now we can calculate the potential energy using the same formula as before:

Potential energy = 2500 kg x 9.8 m/s² x 16.0 m

Potential energy = 392,000 J

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Its vertical acceleration is equal to -g, while the horizontal component of its velocity is unchanged.

This is due to the projectile's dual components of vertical and horizontal velocities. But when the item moves, its vertical component of velocity changes but its horizontal component does not.

The projectile's horizontal component of velocity remains constant, therefore it only has a vertical component of acceleration and no horizontal component. The horizontal component of velocity remains unchanged as a result.

Since the only vertical force acting on the object is the weight, the vertical component of acceleration is equal to -g.

Therefore, the vertical component of its acceleration is equal to -g, while the horizontal component of its velocity remains constant.

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Answer:

The potential difference across the battery can be calculated using the equation:

Potential difference (V) = Energy supplied (J) / Charge (C)

Energy supplied during each second = 2.3 coulombs * 4.2 J/C = 9.66 J

Therefore, the potential difference across the battery would be:

Potential difference (V) = 9.66 J / 2.3 C = 4.2 V

So the potential difference across the battery is 4.2 volts.

Answer:

Explanation:

Here is a step by step explanation of how to solve the problem:

Break the initial velocity into x and y components. The velocity of the Pokéball can be broken down into two components: the horizontal component (vix) and the vertical component (viy). The horizontal component remains constant throughout the motion and has a value of vix = vcosθ, where v is the magnitude of the velocity and θ is the angle of launch. The vertical component changes due to the acceleration of gravity and has a value of viy = vsinθ - gt, where t is time.

Solve for the time of flight. We want to find the time it takes for the Pokéball to reach its maximum height, so we need to set viy = 0 and solve for t:

0 = vsinθ - gt

gt = vsinθ

t = vsinθ / g

Calculate the maximum height. The maximum height is reached when the vertical component of velocity is equal to zero, so we can use the equation:

h = viy^2 / (2g)

h = (vsinθ)^2 / (2g)

Calculate the range. The range is the horizontal distance traveled by the Pokéball during its flight, and it can be found using the equation:

x = vix * t

x = vcosθ * (vsinθ / g)

Draw a well labeled diagram of the physical situation. Draw the coordinate axes, showing the directions, and label the initial velocity as a vector. Show the trajectory of the Pokéball, including the point where it reaches its maximum height, and label the acceleration due to gravity.

(a) The particle is instantaneously at rest at time, t = 3/2 seconds.

(b)  The displacement of the particle is 54 meters from the fixed point O at t = 6 seconds.

(c) The total distance travelled by the particle during the first 6 seconds of its motion is 52 meters.

To find the time when the particle is instantaneously at rest, we need to find the time when its velocity is zero. The velocity of the particle can be found by taking the derivative of its displacement with respect to time, which gives us the velocity function, v(t) = d(x)/dt.

Taking the derivative of x = (t — 1)^3 -2t^2 +1 with respect to time t, we get:

v(t) = 3(t - 1)^2 - 4t

To find when the velocity is zero, we set v(t) = 0 and solve for t:

0 = 3(t - 1)^2 - 4t

3(t - 1)^2 = 4t

t = (3(t - 1)^2)/4

t = (3(t - 1)^2)/4

Solving this equation, we find t = 3/2 seconds. So, the particle is instantaneously at rest at t = 3/2 seconds.

To find the displacement of the particle from O when t=6 s, we simply substitute t = 6 into the displacement function:

x = (6 - 1)^3 - 2 * 6^2 + 1

x = 125 - 72 + 1

x = 54 meters

To find the total distance travelled during the first 6 seconds of its motion, we need to find the definite integral of the velocity function over the interval [0, 6].

x(t) = ∫v(t) dt

x(t) = ∫(3(t - 1)^2 - 4t) dt

x(t) = (t - 1)^3 - 2t^2 + C

where C is the constant of integration. We can determine the value of C by using the initial condition that x(0) = 0:

0 = 0 - 2 * 0^2 + C

C = 0

So, x(t) = (t - 1)^3 - 2t^2.

Finally, to find the total distance travelled during the first 6 seconds of its motion, we evaluate the definite integral of x(t) from 0 to 6:

d = x(6) - x(0)

d = [(6 - 1)^3 - 2 * 6^2] - [(0 - 1)^3 - 2 * 0^2]

d = 125 - 72 - 1

d = 52 meters

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The statement that describes the relationship between atoms and conductivity is as follows: Atoms with a full valence shell make good conductors (option C).

Conductivity is the ability of a material to conduct electricity, heat, fluid or sound.

Conductivity is determined by the types of atoms in a material (the number of protons in each atom's nucleus determines its chemical identity) and how the atoms are linked together with one another.

The atoms which have fewer electronic shells have, the lower the electrical conductivity it has and vice versa.

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Conductors and Insulators Quick Check

100% true

C. The electrons in copper (Cu) are loosely bound to the nucleus.

A. An electrical current that flows in one direction.

A. aluminum (Al)

B. Opposite charges attract one another.

C. Atoms with a nearly empty valence shell make good conductors.

C.

A.

A.

B.

C.

The correct answer is : Planet X, because the sun pulls it with a greater force

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Answer: A A A !!!!  

Explanation: just did the test, got it right thx thx!!!

The resistance (slope of a curve) is about 490 so when bulb is lit. According to this model, the resistance was inversely proportional to temperature for materials (such this tungsten filament).200 ohms

The datasheet for such LED will include this information as well as the forward dc voltage. LEDs typically demand 10 to 20mA. For instance, a 9V battery powered ultra-bright blue LED has a forwards voltage or 3.2V and a typical current is 20mA. Thus, the resistor must be 290 ohms and as close to that value as is feasible.

Due to their relatively high resistance, alkaline, carbon-zinc, and the majority of primary batteries can only be used in low-current devices like flashlights, remotes, portable entertainment systems, and kitchen clocks. The resistance gets worse when these batteries run out of power.

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The minimum initial speed of the proton needed to pass through the square of charges is 5.09 x 10^6 m/s.

Charge is a fundamental physical property of matter that describes the degree to which it interacts with electromagnetic fields. It is an intrinsic property of subatomic particles, such as protons and electrons, that gives rise to electric and magnetic forces.

The basic unit of charge is the Coulomb (C), named after the French physicist Charles-Augustin de Coulomb, who first quantified the electric force between charged objects. A single proton or electron has a charge of approximately 1.6 x 10^-19 Coulombs.

Electric charge is conserved, which means that the total amount of charge in a closed system remains constant over time. Charges can be positive, negative, or neutral, and like charges repel each other, while opposite charges attract each other.

Charge is an important property in many areas of physics, including electromagnetism, quantum mechanics, and particle physics. It is also a crucial concept in many practical applications, such as electronics, power generation, and communication systems.

We can solve this problem using the principle of conservation of energy. The initial kinetic energy of the proton must be equal to the work done by the electrostatic force of the charged spheres on the proton as it passes through the square.

The electrostatic force between two charges q1 and q2 separated by a distance r is given by Coulomb's law:

[tex]F = k * q1 * q2 / r^2[/tex]

where k is the Coulomb constant, which has a value of

[tex]8.99 x 10^9 N m^2 / C^2.[/tex]

Since the four spheres are identical and equally spaced, the electrostatic force on the proton due to each sphere will have the same magnitude and direction. We can calculate the force on the proton due to one sphere and multiply by 4 to get the total force:

[tex]F = 4 * k * q * q_p / r^2[/tex]

where q is the charge on each sphere (+15 nC), q_p is the charge on the proton (-1.6 x 10^-19 C), and r is the distance from the center of the square to the proton's initial position (which we will assume is the same as the distance from the center of the square to the closest sphere, which is sqrt[tex](2)/2 * 0.02 m = 0.0141 m).[/tex]

The work done by the electrostatic force as the proton passes through the square is:

W = F * d

where d is the length of the square (2 cm = 0.02 m).

Equating the initial kinetic energy of the proton to the work done by the electrostatic force, we get:

[tex](1/2) * m * v_i^2 = 4 * k * q * q_p * d / r^2[/tex]

where m is the mass of the proton (1.67 x 10^-27 kg) and v_i is the initial speed of the proton.

Solving for v_i, we get:

[tex]v_i = sqrt(8 * k * q * q_p * d / (m * r^2))[/tex]

Plugging in the values, we get:

[tex]v_i = sqrt(8 * 8.99 x 10^9 N m^2 / C^2 * 15 x 10^-9 C * 1.6 x 10^-19 C * 0.02 m / (1.67 x 10^-27 kg * (0.0141 m)^2))v_i = 5.09 x 10^6 m/s[/tex]

Therefore, the minimum initial speed of the proton needed to pass through the square of charges is [tex]5.09 x 10^6 m/s.[/tex]

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Here, when , the reaction quotient is less than the equilibrium constant, then, the reaction will move to the right. In the first set up, the reaction quotient is less than Keq. Then, the reaction moves to right.

The reaction quotient of a reaction is the ratio of molar concentration of the product to the molar concentration of the reactants.

In the first setup.

Keq = 6.16 x 10⁻³

Q = [0.0064]²/[0.098] = 4.18 × 10⁻⁴

Q<K⇒The reaction moved to the right (products)

Setup 2 :

Q = [0.0304]²/[0.150]

   = 6.16 x 10⁻³

Q=K⇒the system at equilibrium

Setup 3 :

Q =  [0.230]²/[0.420]

   = 0.126

Q>K⇒The reaction moved to the left (reactants)

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Answer: products, equilibrium, reactants

Explanation:

its right on edge 2023

Answer:

bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

Explanation:

The man has at most 3.55 s to get out of the way.

Kinematics can be defined as a subfield of physics developed in classical mechanics that describes the motion of points, bodies and systems of bodies without considering the forces that cause them to move.

We can solve this problem using kinematic equations.

First, we can find the time it takes for the block to fall from a height of 84.9 m using the formula:

y = 1/2 * g * t^2

where

Rearranging this equation, we get:

t = sqrt(2y/g) = sqrt(2 * 84.9 m / 9.81 m/s^2) = 4.09 s (to two significant figures)

So the block will hit the ground after 4.09 s of falling.

Next, we can find the time it takes for the block to fall from a height of 16.6 m using the same formula:

t = sqrt(2y/g) = sqrt(2 * 16.6 m / 9.81 m/s^2) = 1.41 s (to two significant figures)

So the block will take 1.41 s to fall from a height of 16.6 m to the ground.

The man has to get out of the way before the block falls the remaining distance of (84.9 - 16.6) = 68.3 m. We can find the time it takes for the block to fall this distance using the same formula:

t = sqrt(2y/g) = sqrt(2 * 68.3 m / 9.81 m/s^2) = 3.55 s (to two significant figures)

Therefore, the man has at most 3.55 s to get out of the way.

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If a radio station broadcasts at 9.23 x 10⁷Hz and the velocity of the waves is 3  x 10⁸m/s, the wavelength of these waves is 3.25m.

According to the question,

Frequency of the FM radio = 9.23 x 10⁷Hz

Velocity of the waves = 3  x 10⁸m/s

The wavelength of the wave =?

To find the wavelength of the wave, we conclude the velocity equation;

Velocity = frequency x wavelength.

Since to find unknown is the wavelength, we have to solve for it:

       3  x 10⁸  = 9.23 x 10⁷ x wavelength

      wavelength =    3  x 10⁸/ 9.23 x 10⁷

      wavelength = 3.25m

Therefore, the wavelength of these waves is 3.25m.

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The displacement of the Usain Bolt will be 100 m if ran a straight path. (There is need to specify the shape of the track, did he return to the initial position?)

Displacement is a vector quantity that measures the overall change in position of an object, from its initial position to its final position.

It is defined as the straight-line distance between the initial and final positions, along with the direction from the initial to the final position.

Δx = x₂ - x₁

where;

Δx =  100 m - 0 m

Δx = 100 m

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Heat will naturally flow from an object at 40°C to an object at 20°C.

Heat is described as the energy that is transferred from one body to another as the result of a difference in temperature.

Heat will naturally flow from an object at a higher temperature to an object at a lower temperature. So in the above scenario,  heat will naturally flow from an object at 40°C to an object at 20°C.

In conclusion, the basic concept of thermodynamics states that heat will flow spontaneously from a higher-temperature body to a lower-temperature body in order to equalize the temperatures of the two bodies.

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The magnitude of the charges must be 1.67 x 10⁻⁵ C in order for the force exerted by them to be comparable to the weight of a 50 kilogram individual.

The force of attraction between two point charges Q1 and Q2 separated by a distance r is given by Coulomb's law:

[tex]F = k * (Q1 * Q2) / r^2[/tex]

here,

k is Coulomb constant, value is [tex]9.0 * 10^9 Nm^2/C^2[/tex].

To find the magnitude of the charges such that the force between them equals the weight of a 50 kg person, we need to set the force equal to the weight of the person:

F = m * g

here,

m is mass of the person and

g is the acceleration gravity, value [tex]9.81 m/s^2[/tex].

Reserving values:-

[tex]m * g = k * (Q1 * Q2) / r^2[/tex]

We know that Q1 and Q2 are equal, so we can write Q1 = Q2 = Q. Reserving equation above:-

[tex]m * g = k * Q^2 / r^2[/tex]

Solving for Q:-

[tex]Q = \sqrt{[(m * g * r^2) / k]}[/tex]

Reserving values:-

[tex]Q = \sqrt{x} \sqrt{[(50 kg * 9.81 m/s^2 * (1.0 m)^2) / (9.0 x 10^9 Nm^2/C^2)]}[/tex]

Simplifying and evaluating:-

[tex]Q = 1.67 * 10^-^5 C[/tex]

Therefore, the magnitude of each of the charges should be approximately [tex]1.67 * 10^-^5 C[/tex].

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The distance between the two charges is approximately 0.0134 meters.

The Coulomb force between two point charges is given by Coulomb's Law,

[tex]F = \dfrac{k Q_1 Q_2}{r^2}[/tex]

where k is Coulomb's constant, Q1 and Q2 are the magnitudes of the two charges, and r is the distance between them.

Q1 = +8 x 10^-6C, Q2 = -5 x 10^-6C, and F = 0.2 N.

k = 9 x 10^9 N m^2/C^2.

Substituting these values into Coulomb's Law,

[tex]0.2 N = \dfrac{9 \times 10^9 \times 8 \times 10^{-6} \times -5 \times 10^{-6}}{ r^2}[/tex]

Multiplying both sides by r^2, we get:

r^2 = (3.6 x 10^-5 N) / 0.2

r^2 = 1.8 x 10^-4 m^2

r ≈ 0.0134 m

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The correct answers to the blanks are 1. UP ,2. UP and 3. ZERO

When the cart is initially given a push up the ramp, the direction of the acceleration of the cart is up the ramp. This is because the net force acting on the cart is directed up the ramp, in the same direction as the component of the gravitational force that is parallel to the ramp. As a result, the cart accelerates up the ramp in the same direction as the net force.

When the cart turns around and begins moving down the ramp, the direction of the acceleration of the cart is still up the ramp. This is because the component of the gravitational force that is parallel to the ramp is still directed down the ramp, but the net force acting on the cart is directed up the ramp due to the normal force exerted by the ramp on the cart. As a result, the cart accelerates down the ramp in the opposite direction to the net force, which is up the ramp.

            At the highest point that the cart reaches on the ramp, when the cart momentarily comes to rest, the magnitude of the acceleration of the cart is zero. This is because at this point, the cart is at the highest point on the ramp and has stopped moving. As a result, the velocity of the cart is zero, and therefore the acceleration of the cart is also zero.

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A concrete floor surface will produce a coefficient for traditional footwear that is high enough (between 0.55 and 70) to eliminate the foreseeable risk of slipping.

The ratio between the perpendicular force pushing the objects together and the frictional resistive force is known as the coefficient of friction.

The formula for the friction coefficient is = F N, where is the friction coefficient, is the frictional force, and is the normal force.

A numerical value known as the coefficient of friction (fr) is created by dividing the resistive force of friction (Fr), which pushes the objects together, by the normal or perpendicular force (N), which pushes them apart. It is represented by the formula below: fr = Fr/N.

X= 25 m

u = 10m/s

m = 20kg

F= uN

N= mg

[tex]a = \frac{uN}{m} = \frac{umg}{m}[/tex]

a= ug

[tex]v^{2} =u^{2} - 2ax[/tex]

[tex]o= (10)^2 - 2ug (25)[/tex]

[tex]50 ug = (10)^2 = 100[/tex]

[tex]u = \frac{2}{g} = \frac{2}{10} = 0.2[/tex]

Therefore, 0.2 is the coefficient of friction between the box and floor.

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The energy of a wave is proportional to the square of its amplitude. Doubling the amplitude of a wave quadruples its energy.

Therefore, if the original wave on the small lake had an amplitude of 0.1 meters and a certain amount of energy, doubling its amplitude to 0.2 meters would increase its energy by a factor of 4. In other words, the energy of the wave would become 4 times greater than its original value.

The largest deviation a wave can make from its equilibrium position is referred to as its amplitude. In plainer terms, it refers to the height of a wave, or the distance between the highest point (the wave's crest) and the lowest point (its trough).

A wave's energy, or the entire amount of work that the wave may exert on its surroundings, is measured by the amplitude of the wave. The wave carries more energy the larger its amplitude.

The term "amplitude" is frequently used to describe a variety of waves, such as sound, light, and water waves. It is typically expressed as a "A" sign and is measured in units of measurement like meters or feet.

To calculate the energy of the wave by doubling its height:

(Energy after / Energy before) = (Amplitude after)^2 / (Amplitude before)^2

Substituting the given values, we get:

(Energy after / Energy before) = (0.2)^2 / (0.1)^2 = 4

This means that the energy of the wave after doubling its amplitude would be four times the energy of the original wave.

So, if the original wave had an energy of E, the energy of the wave after doubling its amplitude would be 4E.

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The reading on the spring scale will depend on the acceleration of the elevator and the direction of that acceleration.

If the elevator is traveling downward but slowing down (i.e., accelerating in the upward direction), the scale will read less than the woman's normal weight of 125 lb. This is because the upward acceleration of the elevator reduces the effective weight of the woman, making her appear lighter on the scale. To determine the reading on the scale, you would need to know the acceleration of the elevator at that particular moment. If the elevator is slowing down at a rate of, say,[tex]2 m/s^2,[/tex]then the scale would read:

Weight = mass x acceleration due to gravity

Weight =[tex]56.7 kg x (9.81 m/s^2 - 2 m/s^2)[/tex]

Weight =[tex]56.7 kg x 7.81 m/s^2[/tex]

Weight = [tex]442.5 N[/tex]

Converting this to pounds, the reading on the scale would be approximately:

Weight = [tex]442.5 N x (1 lb / 4.448 N)[/tex]

Weight[tex]≈ 99.4 lb[/tex]

So, the scale would read approximately 99.4 lb, which is less than the woman's normal weight of 125 lb.

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Answer:

a bus triveling north at 25m/s

D. Multiplying mass by velocity.

The momentum of an object is a measure of its motion and is defined as the product of its mass and velocity. It is a vector quantity, meaning it has both magnitude and direction.

The formula for momentum is given by p = mv, where p is the momentum, m is the mass of the object, and v is its velocity. So, the momentum of an object can be calculated by multiplying its mass by its velocity.

Option A is incorrect because momentum is not simply the product of mass and acceleration. Option B is incorrect because force is not directly related to momentum. Option C is incorrect because dividing mass by velocity does not give momentum, it gives the velocity of the object.

The potential difference across the battery is 4.2 volts.

What is  potential difference?

Potential difference is described as the amount of work energy required to move an electric charge from one point to another.

The unit of potential difference is the volt.

The potential difference across the battery is  calculated using the equation:

V = W / Q

Workdone  = Q * Vbattery = 2.3 C * 4.2 J/C = 9.66 J

Therefore, the voltage across the battery can be calculated as:

V = W / Q = 9.66 J / 2.3 C = 4.2 V

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