we have the following:
[tex]undefined[/tex]Write an absolute value inequality whose solution set is shown by the graphs. Each mark on the graph represents a whole number. (Your answers will have the absolute value symbols, | |.)
To answer this question we will use the following:
[tex]\begin{gathered} |a|\ge b\text{ if and only if} \\ a\ge b\text{ or }a\le-b. \end{gathered}[/tex]Notice that the given set consists of the real numbers that are greater than or equal to 3 or that are less than or equal to -3, the above statement in algebraic notation is:
[tex]x\geq3\text{ or }x\leq-3.[/tex]Using the first equations we get that the given set can be represented by the following absolute value inequality:
[tex]|x|\ge3.[/tex]Answer:
[tex]|x|\ge3.[/tex]Simplify this expression 2x² x x³
[tex]2x^{6}[/tex] is the Simplify of the expression 2x² x x³
[tex]2x^{2} xx^{3} = 2x^{6}[/tex]
what is simplify?
To simplify means to make anything basic or simpler, for example. a: to reduce to the bare minimum. b: to become simpler or broader in scope: It was advised to streamline management processes.
The fundamental guidelines and procedures to simplify any algebraic statement are as follows:
By multiplying factors, remove any grouping symbols like brackets and parenthesis.If the words contain exponents, use the exponent rule to eliminate grouping.Add or subtract like terms to combine them.add the constants togetherWhen you describe a complex mathematical idea to a child in words they can easily understand, you are simplifying. When you eliminate many of the tasks that were keeping you occupied and stressed out, you have simplified.
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4. What value of c would make the function below have two real solutions? y= -3x^2 – 4x+c
The quadratic equation is,
[tex]y=-3x^2-4x+c[/tex]The value of coefficients of square term, x term and constant terms are,
a = -3
b = -4
and c = c.
For two real roots,
[tex]b^2-4ac>0[/tex]Dubstitute the values in the equation to obtain the value of c.
[tex]\begin{gathered} (-4)^2-4\cdot(-3)\cdot(c)>0 \\ 16+12c-16>0-16 \\ \frac{12c}{12}>\frac{-16}{12} \\ c>-1.333 \end{gathered}[/tex]So value of c should be greater than -1.333, and from from the options it can be observed that value more than -1.333 is only c = -1.
So answer is c = -1.
What is the approximate circumference of a circle with a radius of 13 feet?
ANSWER
81.68 ft
EXPLANATION
The circumference of a circle = 2 * pi * r
[tex]\text{circumference = 2 }\Pi\text{ r = 2}\times\frac{22}{7}\times13\text{ = 81.68 ft}[/tex]When 2 triangles are congruent, you can move 1 figure and it fits exactly on the other. Which transformation from Unit 1 would not result in congruent figures?
The non-rigid transformation will not result in congruent figures because they will change the size or shape.
Hence, the answer is dilation because if we dilate the figures they will not be congruent after the transformation.
Solve for x and round to the nearest thousandth
4*x=728
Answer:
182
Step-by-step explanation:
728 divided by 4 is 182.
Hi, can you help me with that please ‘cause I don’t understand what I have to do .
This is a simple question.
The run is related to the x-axis and the rise to the y-axis and the slope is the relation between the two and we can calculate in the following form:
[tex]Slope=\frac{Rise}{Run}=\frac{y_2-y_1_{}}{x_2-x_1}[/tex]To do so, we need to choose 2 different points in the line and calculate. For our explanation, we will choose points (-1,9) and (3,-3). So let's calculate:
[tex]Slope=\frac{Rise}{Run}=\frac{y_2-y_1}{x_2-x_1}=\frac{9-(-3)}{-1-3}=\frac{12}{-4}=-\frac{12}{4}[/tex]And that is our Slope.
Now we can draw it as follows:
And that is our final answer.
If angle T = x degrees and angle V = 3x + 60, then angle V = ___ degrees.
Given data:
The given circle.
The quadrilateral inside the circle is cyclic in nature, the expression for the cyclic quadrilateral is,
[tex]\begin{gathered} \angle V+\angle T=19=180^{\circ} \\ 3x+60+x=180 \\ 4x=120 \\ x=30 \end{gathered}[/tex]The value of angle V is,
[tex]\begin{gathered} \angle V=3(30^{\circ})+60^{\circ} \\ =150^{\circ} \end{gathered}[/tex]Thus, the value of angle V is 150 degrees.
Which equation represents a line that is perpendicular to the graph of y = 2/5x − 1?
The equation of the line y=-5/2x-4 is perpendicular to the given equation of the line.
Given that,
The given equation of the line is y=2/5x-1.
We have to find the equation of the line that is perpendicular to the given equation of the line.
We know Equation of the line formula,
y=mx+c
Here,
m denotes the line's slope, and c the y-intercept.
Take the equation of the line y=2/5x-1
m is 2/5
The perpendicular line is m is -5/2
We get the perpendicular line is y=-5/2x-4.
Therefore, The equation of the line y=-5/2x-4 is perpendicular to the given equation of the line.
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The result of RREF produced the following matrix. What is the solution of the system? Choose the best answer.
Using the augmented matrix, we find that:
The first system has no solutions.
The second system has infinite solutions, given by: (-3t, 0, t).
Augmented Matrix:
An augmented matrix for a system of equations is a matrix of numbers in which each row represents the constants from one equation and each column represents all the coefficients for a single variable.
Given:
The matrix is,
[tex]\begin{bmatrix}1 & 0 & 3&| & 0 \\ 0& 1 & 1 & | & 5 \\0 & 0 & 0 & | & 1\end{bmatrix}[/tex]
Here we need to find the solution of the system.
While we looking at the first system, at the third row of the matrix, the relation is written as,
0t=1
This one is not possible, therefore, there are no solutions for the first system.
Now when we looking at the second system, the third line has the value of,
0t=1
This refers that there are infinite solutions, therefore here t is the free parameter.
From the second line, y = 5.
From the first,
=> x + 3t
=> x = -3t
The solutions are: (-3t, 0, t).
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Convert to an algebraic expression and simplify, if y stands for the unknown number: Sixteen more than five times a number.
Here, we are told y stands for the unknown number: Sixteen more than five times a number.
Converting to an algebraic expression, we have:
16 + 5y
Here, y is the unknown number.
16 + 5y
52
base six
Write the normal number
19770609664 is simple power of 52⁶ .
What is exponent and power?
A base number raised to an exponent is referred to as a power in mathematics, where base number is the factor that is multiplied by itself and exponent is the number of times the same base number is multiplied.Exponents and powers are two techniques for simplification of extremely big or extremely small numbers. As an illustration, we can write 3 x 3 x 3 x 3 as 34, where 4 is the exponent and 3 is the base, if we need to represent it simply. It is claimed that the entire statement 34 has power.= 52⁶
= 52 × 52 × 52 × 52 × 52 × 52
= 19770609664
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10. Find the value of k such that the line through (5, 1) and (k, 7) is parallel to the line
y = 3x.
Answer:
k = 7
Step-by-step explanation:
y = 3x
The slope is 3
Parallel lines have the same slope so a line parallel will have a slope of 3
Using the slope formula
m = (y2-y1)/(x2-x1)
3 = ( 7-1)/(k-5)
3 = 6/(k-5)
Multiply each side by k-5)
3 * (k-5) = 6
Divide each side by 3
k-5 = 6/3
k-5 = 2
Add 5 to each side
k = 7
The following transactions were completed by Winklevoss Inc., whose fiscal year is the calendar year:
Year 1
July 1 Issued $71,900,000 of 20-year, 6% callable bonds dated July 1, Year 1, at a market (effective) rate of 7%, receiving cash of $64,222,669. Interest is payable semiannually on December 31 and June 30.
Oct. 1 Borrowed $420,000 by issuing a six-year, 5% installment note to Nicks Bank. The note requires annual payments of $82,747, with the first payment occurring on September 30, Year 2.
Dec. 31 Accrued $5,250 of interest on the installment note. The interest is payable on the date of the next installment note payment.
31 Paid the semiannual interest on the bonds. The bond discount amortization of $191,933 is combined with the semiannual interest payment.
Year 2
June 30 Paid the semiannual interest on the bonds. The bond discount amortization of $191,933 is combined with the semiannual interest payment.
Sept. 30 Paid the annual payment on the note, which consisted of interest of $21,000 and principal of $61,747.
Dec. 31 Accrued $4,478 of interest on the installment note. The interest is payable on the date of the next installment note payment.
31 Paid the semiannual interest on the bonds. The bond discount amortization of $191,933 is combined with the semiannual interest payment.
Year 3
June 30 Recorded the redemption of the bonds, which were called at 98. The balance in the bond discount account is $6,909,599 after payment of interest and amortization of discount have been recorded. Record the redemption only.
Sept. 30 Paid the second annual payment on the note, which consisted of interest of $17,913 and principal of $64,834.
Required:
1. Journalize the entries to record the foregoing transactions. Round all amounts to the nearest dollar. Refer to the Chart of Accounts for exact wording of account titles.
2. Indicate the amount of the interest expense in (a) Year 1 and (b) Year 2.
3. Determine the carrying amount of the bonds as of December 31, Year 2.
1. The journal entries recording the transactions for Winkelvoss Inc. are as follows:
Journal Entries:Year 1:
July 1: Debit Cash $64,222,669
Debit Bonds Discount $7,677,331
Credit Bonds Payable $71,900,000
Oct. 1: Debit Cash $420,000
Credit Bank Notes Payable $420,000
Dec. 31 Debit Interest Expense $5,250
Credit Installment Note Interest Payable $5,250
Dec. 31 Debit Interest Expense $2,708,433
Credit Cash $2,516,500
Credit Bond Amortization $191,933
Year 2:
June 30 Debit Interest Expense $2,516,500
Credit Cash $2,324,567
Credit Bond Amortization $191,933
Sept. 30 Debit Interest Expense $15,750
Debit Installment Note Interest Payable $5,250
Debit Notes Payable $61,747
Credit Cash $82,747
Dec. 31 Debit Interest Expense $4,478
Credit Installment Note Interest Payable $4,478
Dec. 31 Debit Interest Expense $2,708,433
Credit Cash $2,516,500
Credit Bond Amortization $191,933
Year 3:
June 30 Debit Bonds Payable $64,990,401
Debit Bond Redemption Premium $5,471,599
Credit Cash $70,462,000
Sept. 30 Debit Interest Expense $13,435
Debit Installment Note Interest Payable $4,478
Debit Notes Payable $64,834
Credit Cash $82,747
2. The amounts of the interest expense in Year 1 and Year 2 are as follows:
Year 1 Year 2
Total interest $2,713,683 $2,72,8661
3. The bond's carrying amount as of December 31, Year 2, is $64,798,468.
Transaction Analysis:Year 1:
July 1: Cash $64,222,669 Bonds Discount $7,677,331 Bonds Payable $71,900,000
Oct. 1: Cash $420,000 Bank Notes Payable $420,000
Dec. 31 Interest Expense $5,250 Installment Note Interest Payable $5,250
Dec. 31 Interest Expense $2,708,433 Cash $2,516,500 Bond Amortization $191,933
Year 2:
June 30 Interest Expense $2,516,500 Cash $2,324,567 Bond Amortization $191,933
Sept. 30 Interest Expense $15,750 Installment Note Interest Payable $5,250 Notes Payable $61,747 Cash $82,747
Dec. 31 Interest Expense $4,478 Installment Note Interest Payable $4,478
Dec. 31 Interest Expense $2,708,433 Cash $2,516,500 Bond Amortization $191,933
Year 3:
June 30: Bonds Payable $64,990,401 Bond Redemption Premium $5,471,599 Cash $70,462,000
Sept. 30 Interest Expense $13,435 Installment Note Interest Payable $4,478 Notes Payable $64,834 Cash $82,747
Interest Expenses:Year 1 Year 2
Bonds Payable $2,708,433 $2,708,433
Notes Payable $5,250 $15,750
Notes Payable $4,478
Total interest $2,713,683 $2,72,8661
Carrying amount of the bonds December 31, Year 2:July 1: $64,222,669
Dec. 31 Bond Amortization $191,933
June 30 Bond Amortization $191,933
Dec. 31 Bond Amortization $191,933
Dec. 31 Year 2 Carrying Amont = $64,798,468
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Please help me solve question 5 on my algebra homework
Check the answers below, please
1) Since we have this linear function:
[tex]f(x)=-\frac{1}{3}x-4[/tex]a) We can proceed to state the Domain, the set of inputs for this function as:
[tex]D=(-\infty,\infty)[/tex]Since this Linear function does not have any restraint or discontinuity.
b) The Range, i.e. the set of outputs for this function will be defined for this function as:
[tex]R=(-\infty,\infty)[/tex]c) The Zero, can be found algebraically by plugging f(x)=0
[tex]\begin{gathered} f(x)=-\frac{1}{3}x-4 \\ 0=-\frac{1}{3}x-4 \\ \frac{1}{3}x=-4 \\ x=-12 \end{gathered}[/tex]d) Y-intercept is the point in the y-axis where the line intercepts it. Looking at the rule of the function, we can state the y-intercept as:
[tex]-4[/tex]e) Slope, the measure of how steep a line of a function is, it's always the coefficient of x, in this case:
[tex]m=-\frac{1}{3}[/tex]f) Type of slope. Since the slope is -1/3 , i.e. lesser than 0, then we can classify it as decreasing
g) Evaluating f(3):
[tex]\begin{gathered} f(x)=-\frac{1}{3}x-4 \\ f(3)=-\frac{1}{3}(3)-4 \\ f(3)=-1-4 \\ f(3)=-5 \end{gathered}[/tex]h) The value of x, where f(x)= -4 Similarly to the previous item, we can plug into that f(x)= -4 like this:
[tex]\begin{gathered} f(x)=-\frac{1}{3}x-4 \\ -4=-\frac{1}{3}x-4 \\ -4+4=-\frac{1}{3}x-4+4 \\ -\frac{1}{3}x=0 \\ \mathbf{x=0} \end{gathered}[/tex]i) The graph can be traced having the zero, the y-intercept the type of the slope we can plot this:
5. A. How do we know if an ordered pair is an x-intercept? Explain with specific detail.B. How do we know if an ordered pair is a y-intercept? Explain with specific detail.C. In the table, which order pair is the x-intercept, and which is the y-intercept?х4XNOу-10-24123
a) x-intercept: the y coordinate will be zero while the x coordinate will have a value different from zero.
b) y-intercept: the x coordinate will have a value of zero while the y-coordinate will have a value that is non-zero.
c) The x-intercept: (2, 0)
The y-intercept: (0, 1)
Explanation:5) a) x-intercept is the value of x when the value of y is zero.
To determine if an ordered pair is an x-intercept, the y coordinate will be zero while the x coordinate will have a value different from zero.
b) y-intercept is the value of y when x is equal to zero.
To determine if an ordered pair is a y-intercept, the x coordinate will have a value of zero while the y-coordinate will have a value that is non-zero.
c) To get the x-intercept: From the table, we will check for the of x when the value of y = 0
The value of y = 0 when x = 2
The ordered pair: (x, y)
The x-intercept: (2, 0)
To get the y-intercept: we will check for the value of y when x = 0
The value of x = 0 when y = 1
The ordered pair: (x, y)
The y-intercept: (0, 1)
Can someone help me asap
Answer:
A) 670
B) 192 and 670
C) 670
Answer:
a) 670
b) 192, 670
c) 670
Step-by-step explanation:
670 is divisible by 5 because 670/5=134, also because 670 ends in 0
192 and 670 is divisible by 2 because they both end in even numbers, and also 192/2=96, 670/2=335
670 is divisible by 10 because 670/10=67, and it ends in a 0 as well
John Paul Jones rented a helicopter. There was a one-time charge of $500, plus an hourly rate of $150. His total for the night was $1700. How many hours did he rent the helicopter for?
a. Create an equation that represents the situation
b. Solve the equation
PLEASE I NEED ANSWER FAST
1. The equation that represents the situation is 500 + 150h = 1700
2. The number of hours used to rent the helicopter is 8 hours.
What is an equation?It should be noted that an equation is used to show the relationship between the variables.
In this case, John rented a helicopter, there was a one-time charge of $500, plus an hourly rate of $150 and his total for the night was $1700.
Let the number of hours be represented as h.
The equation will be 500 + 150 × h = 1700
500 + 150h = 1700
The number of hours used will be:
500 + 150h = 1700
Collect like terms
150h = 1700 - 500
150h = 1200
Divide
h = 1200/150
h = 8
The helicopter was for 8 hours.
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The population of the world in 1987 was 5 billion and the annual growth rate was estimated at 2 percent per year. Assuming that the world population follows an exponential growth model, find the projected world population in 1992.
Answer:
5.52 billion
Step-by-step explanation:
2% s .02 in decimal from '87 to '92 is 5 years ( the exponent in the following:
5 (1.02)^5 = 5.52 billion
Answer:
5.52 billion
Step-by-step explanation:
i got this my doing math
Given: 3x + 16 = 4x - 9
Prove: x = 25
Answer:
x=16
Step-by-step explanation:
Simplifying
3x + 16 = 4x
Reorder the terms:
16 + 3x = 4x
Solving
16 + 3x = 4x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-4x' to each side of the equation.
16 + 3x + -4x = 4x + -4x
Combine like terms: 3x + -4x = -1x
16 + -1x = 4x + -4x
Combine like terms: 4x + -4x = 0
16 + -1x = 0
Add '-16' to each side of the equation.
16 + -16 + -1x = 0 + -16
Combine like terms: 16 + -16 = 0
0 + -1x = 0 + -16
-1x = 0 + -16
Combine like terms: 0 + -16 = -16
-1x = -16
Divide each side by '-1'.
x = 16
Simplifying
x = 16
ANSWER PLS QUESTION ATTACHED
A parallelogram is an easy quadrilateral with two pairs of parallel aspects. the other or dealing with facets of a parallelogram are of equal length and the other angles of a parallelogram are of equal measure. Hence, proved p + q = r.
A parallelogram has four sides overall and two pairs of facets that might be parallel. A square is a parallelogram that has four equal sides. the other facets are parallel and all corners of the rectangular shape the right attitude. A rectangle is a parallelogram that has 4 contrary, parallel, congruent aspects.
proving p + q = r;
q = ∠OCD = ∠BAO ( alternate angle)
In Δ AOB
∠OAb + ∠DBA = p + q -------------------(1)
& ∠AOD + ∠BOA = 180° ------------(2)
Also,
∠OAB + ∠OBA + ∠BOA = 180° --------- some of angle in a triangle.
⇒ ( p + q) + (180° - ∠BOA) = 180° --------using 1 & 2
⇒ p + q - r = 0
⇒ p + q = r
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In amelies home town the ratio of cars to people is 4,200 to 5,000. Which of the following equals to this ratio? a)0.21, b) 0.42, c) 0.12, d) 0.84?
The option that is to equal to the ratio, 4,200 to 5,000, is 0.84
What is ratio?
Ratio mean expressing one variable as a fraction of the other variable, in this case, 4,200 is expressed as a fraction of a bigger number which is 5,000, intuitively, the correct answer in this scenario is 0.84 because when viewed in percentage terms, 4000 is 80%,hence, 4,200 is greater than 4000, it would be more 80% which is 84%, without mincing words, the computation can be done as shown below:
ratio 4,200 to 5,000=4,200/5,000
ratio 4,200 to 5,000=0.84
Invariably, as stated earlier, all the options from a-c are incorrect as they are not even up 0.80, which means 0.84 is the most appropriate
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Greatest common factor of 5xy+10xy^2+5x
To find the GCF of an expression, find the greatest number that every term can divide by. One way we can do this is by factoring the expression.
Solving the Question[tex]5xy+10xy^2+5x[/tex]
Here, each term has the variable x. Factor this out by dividing each term by x:
[tex]x(5y+10y^2+5)[/tex]
Now, each term has a factor of 5. Divide each term by 5:
[tex]5x(y+2y^2+1)[/tex]
Now, there are no more common factors between each term.
Therefore, the GCF is 5x.
Answer5x
Convert the following complex number into its polar representation: 3i O A. -3(60597 +isin 37 O COS 2 2 O B. -3(cos+ i sin o) O C. 3(cos+ i sin ) O D. 3c052+isin 8
The correct option is D.
The value of r for the given complex number is calculated below:
[tex]r=\sqrt[]{0^2+3^2}=\sqrt[]{9}=3[/tex]now,
[tex]\tan \theta=\frac{3}{0}=\text{ not defined}[/tex]Since the complex number lies on the positive y-axis.
[tex]\theta=\frac{\pi}{2}[/tex]Therefore, the polar form of the given complex number is
[tex]3(\cos \frac{\pi}{2}+i\sin \frac{\pi}{2})[/tex]Can’t find the correct answer pls help
a)What is the value of y? y= 6
b)The value of RS is 57 and ST is 16.
a) How is the value of y calculated?
From the number line,
RS = 9y +3
ST= 2y + 4
RT = 73
Rewriting as equation,
RT = RS + ST
73 = 9y +3 + 2y + 4
73 = 11y + 7
11 y = 73 - 7
11y = 66
y = 66/11
y = 6
b) What is the value of RS and ST ?
Considering the equation,
RS = 9y + 3
=9(6) +3
=54 +3
RS = 57
Considering the equation,
ST = 2y + 4
=2(6) +4
= 12 +4
ST = 16
What is an equation?
An equation is a mathematical statement that demonstrates the equality of two mathematical expressions. More than one variable may be present in a linear equation. An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for linear equation is a one-degree equation.To learn more about equations , refer:
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4 (-2,6)
B (4,6)
C(-2,3)
D(4,3)
Answer:
answer is c-(2,3)
Step-by-step explanation:
......................m
PLEASE HELP ME I WAS SICK AND I DONT UNDERSTAND.DUE IN 1 HOUR!!!!
Answer:
x = 11
Step-by-step explanation:
(3x + 12) + (7x + 15) = 137 (exterior angle: angle KFG = angle g + angle h)
10x + 27 = 137
10x = 110
x = 11
Look at the equation.
r+ 4 = 32
For which value of r is the equation true?
a. 8
b. 28
C. 36
d. 128
Identify the quadratic function(s). (Select all that apply.) 2b(b - 7) + b = 0 (4a + 2)(2a - 1) + 1 = 0 2y + 2(3y - 5) = 0 8 - 5x = 4(3x - 1)
The quadratic equations are 2b(b - 7) + b = 0 and (4a + 2)(2a - 1) + 1 = 0 .
what is Quadratic Equation?An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax² + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term. First, there must be a term other than zero in the coefficient of x² (a ≠ 0) for an equation to be a quadratic equation. The x² term is written first when constructing a quadratic equation in standard form, then the x term, and finally the constant term.
Given:
a) 2b(b - 7) + b = 0
2b² - 14b + b = 0
2b² - 13b = 0
b) (4a + 2)(2a - 1) + 1 = 0
8a² - 4a + 4a + 1 =0
8a² 1 =0
c) 2y + 2(3y - 5) = 0
2y+ 6y- 10 = 0
8y -10=0
d) 8 - 5x = 4(3x - 1)
8- 5x= 12x- 4
Hence, the quadratic equations are 2b(b - 7) + b = 0 and (4a + 2)(2a - 1) + 1 = 0 .
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What is the reflection image of X? 0 (3,7) O (73) (5,7) (7,5)
ANSWER
(7, 5)
EXPLANATION
We want to find the reflection image of X.
The coordinates of X is (-1, 5).
When reflecting over a vertical axis, the x coordinate changes but the y coordinate does not change.
To reflect a point (x, y) (i.e. to find the new x coordinate) across the line x = a, find the distance between a and x, then add that to a.
That is the new x coordinate.
For the question, a = 3.
Therefore, for X(-1, 5):
[tex]\begin{gathered} a-x=3-(-1)=3+1 \\ a=4 \end{gathered}[/tex]Adding that to a, the new coordinates are:
[tex]\begin{gathered} (4+3,5) \\ (7,5) \end{gathered}[/tex]That is the reflection image of X.
